I think i know how to do this but i keep getting them wrong lol help

Using a system of equations, it is found that there were a total of 825,000 Arabic speakers, and the diagram is completed as follows:

A system of equations is when multiple variables are related, and equations are built to find the values of each variable, according to the relations given in the problem.

For this problem, the variables are given as follows, considering the situation described:

There were 639,000 French Creole speakers, hence:

f = 639,000.

There were 186,000 more Arabic speakers than French Creole speakers, hence:

a = 186,000 + f = 186,000 + 639,000 = 825,000.

There were a total of 825,000 Arabic speakers, and the diagram is completed as follows:

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Answer:

[tex]4x^2+2x+1[/tex]

Step-by-step explanation:

[tex]f(x)=4x^2+5\\g(x)=2x-4\\\\f(x)+g(x)=(4x^2+5)+(2x-4)\\\\4x^2+5+2x-4\\\\4x^2+2x+1[/tex]

Using the distance formula, the distance between the pair of points A(0,0) and B(15,20) is 25 units

Given,

The points = A(0,0) and B(15,20)

We know the distance formula = [tex]\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }[/tex]

Substitute the values in the equation

The distance = [tex]\sqrt{(15-0)^{2}-(20-0)^{2} }[/tex]

[tex]=\sqrt{15^{2}+20^{2} } \\=\sqrt{225+400}\\ =\sqrt{625}[/tex]

=25 units

Hence, using the distance formula, the distance between the pair of points A(0,0) and B(15,20) is 25 units.

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Answer:Your answer would be x=1/10

Step-by-step explanation:

Using system of three equations, the equation of the circle that contains the points (0 , 0), (6 , 8), and (7 , 7) is (x - 3)^2 + (y - 4)^2 = 25.

The standard form of the equation of  circle is given by (x - h)^2 + (y - k)^2 = r^2, where (h , k) is the location of the center and r is the radius of the circle.

Substituting the values of the x and y coordinates of each point to the standard form of the equation of a circle, the three system of equations are:

(x - h)^2 + (y - k)^2 = r^2

(0 , 0) : (0 - h)^2 + (0 - k)^2 = r^2

(6 , 8) : (6 - h)^2 + (8 - k)^2 = r^2

(7 , 7) : (7 - h)^2 + (7 - k)^2 = r^2

Expanding these equations,

(0 , 0) : h^2 + k^2 = r^2     (equation 1)

(6 , 8) : 36 - 12h + h^2 + 64 - 16k + k^2 = r^2     (equation 2)

(7 , 7) : 49 - 14h + h^2 + 49 - 14k + k^2 = r^2     (equation 3)

Subtracting equation 1 from equation 2 and 3.

36 - 12h + h^2 + 64 - 16k + k^2 = r^2

-                (h^2 +                 k^2 = r^2)

36 - 12h           + 64 - 16k           = 0

100 - 12h - 16k = 0

12h + 16k = 100

Dividing both sides by 4,

3h + 4k = 25     (equation 4)

49 - 14h + h^2 + 49 - 14k + k^2 = r^2

-                (h^2 +                 k^2 = r^2)

49 - 14h            + 49 - 14k          = 0

98 - 14h - 14k = 0

14h - 14k = 98

h + k = 4     (equation 5)

h = 7 - k

Substitute h = 7 - k to equation 4 and solve for k.

3h + 4k = 25     (equation 4)

3(7 - k) + 4k = 25

21 - 3k + 4k = 25

k = 25 - 21

k = 4

Substitute the value of k to equation 5 and solve for h.

h = 7 - k     (equation 5)

h = 7 - 4

h = 3

Substitute the value of h and k to equation 1 and solve for r.

h^2 + k^2 = r^2     (equation 1)

3^2 + 4^2 = r^2

9 + 16 = r^2

r^2 = 25

r = 5

Hence, the equation of the circle that contains the points (0 , 0), (6 , 8), and (7 , 7) is (x - 3)^2 + (y - 4)^2 = 25.

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The value of the function  (f + g)(−8) (f + g)(−8) for f (x) = x + 3 and g (x) = x² - 2 is 3249.

We are given the functions:

f(x) = x + 3

g(x) = x² − 2

Now,

(f + g) (−8) × (f + g)(−8)

= [ (f + g) (−8) ]²

Substituting the values of the functions, we get that:

=(x + 3 + x² - 2)² ,   where x = -8

= ( -8 + 3 + 64 - 2 )²

= ( -5 + 62)²

= (57) ²

= 3249

So, the value of the function  (f + g)(−8) (f + g)(−8) for f (x) = x + 3 and g (x) = x² - 2 is 3249.

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Kittens without black markings to kittens with black markings: 2:5

Kittens without black markings to total kittens: 2:7

Kittens with black markings to total kittens: 5:7

The equation of the line, with slope equal to 0 and passing through the point located at (4 , -2), is y = -2.

The equation of a line can be expressed in three different forms: standard form, slope-intercept form, and point-slope form.

The standard form of an equation of a line is expressed as ax + by = c, where a and b, if all possible must be integers, are the coefficients of variable x and y, respectively, and c is a constant. Meanwhile, slope-intercept form is given by the formula y = mx + b, where m is the slope of the line and b is the y- intercept. On the other hand, given the slope m and a point on the line (x , y), we can express the equation in point-slope form, (y - y1) = m(x - x1).

Using the point slope form, plug in the values to set up the equation.

(y - y1) = m(x - x1)

where m = 0 and (x1 , y1) = (4 , -2)

(y - -2) = 0(x - 4)

(y + 2) = 0

y = -2

In slope-intercept form, the equation of the line is:

(y + 2) = 0

y = -2

In standard form, the equation of the line is:

y = -2

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Answer:

[tex]{ \tt{f•g(x) = 4(2x + 5) {}^{2} }} \\ = { \tt{4(4 {x}^{2} + 20x + 25)}} \\ = { \tt{ {8x}^{2} + 80x + 100}} \\ \\ { \tt{f•g( - 3) = 8 {( - 3)}^{2} + 80( - 3) + 100 }} \\ { \tt{f•g( - 3) = 72 - 240 + 100}} \\ { \tt{f•g( - 3) = - 68}} \\ \\ \\ { \tt{g•f(x) = 2( {4x}^{2}) + 5 }} \\ { \tt{ = {8x}^{2} + 5 }} \\ { \tt{g•f( - 3) = 8 {( - 3)}^{2} + 5}} \\ { \tt{g•f( - 3) = 77}}[/tex]

Domain - { 3, 11, 121, 34 , 23 , } is domain of  each relation is a function.

What is domain and range ?

How are the domain and range determined?

  Domain - { 3, 11, 121, 34 , 23 , }

 Range  -  { 9, 21 , 34 , 1 , 45 }

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Answer:

It's B

Step-by-step explanation:

Step-by-step explanation:

[tex]\displaystyle\\12-15x > 22\\12-15x+15x > 22+15x\\12 > 22+15x\\12-22 > 22+15x-22\\-10 > 15x\\Divide\ both\ parts\ of \ the \ equation\ by\ 15:\\-\frac{10}{15} > x\\\\-\frac{5*2}{5*3} > x\\\\-\frac{2}{3} > x \\\\Thus,\\\\x < \frac{-2}{3}[/tex]

Answer: A

[tex]\displaystyle\\4\leq 3x+10 < 19\\\\4-10\leq 3x+10-10 < 19-10\\\\-6\leq 3x < 9\\\\Divide\ the\ inequality\ by \ 3:\\\\-2\leq x < 3\\\\Answer:\ -2\leq x < 3[/tex]

Answer:

1.76.

Step-by-step explanation:

1.32 ÷ 12 = 0.11

16 x 0.11 = 1.76.

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The midpoint is at ([tex]-\sqrt{3} , 3 ,3\sqrt{2}[/tex])

In the given statement is

To find the midpoint of the line segment joining the pair of points

B(√3, 2,2√2) and C(-2√3, 4,4√2)

Midpoint:

The coordinates of the midpoint of a line segment are the average of the coordinates of the end points.

m = (A +B)/2

If we are given three points and we wish to find the midpoint of those points, we need to use the midpoint formula m =([tex]\frac{x_{1}+x_{2} }{2} , \frac{y_{1}+y_{2} }{2} , \frac{z_{1}+z_{2} }{2} ,[/tex] )

where:

(x1 , y1 ,z1) are the coordinates of the first point:

(x2 , y2 , z2) are the coordinates of the second point:

Now, We are given the three points B(√3, 2,2√2) and C(-2√3, 4,4√2)

Solving for the midpoint , we have,

m = ([tex]\frac{\sqrt{3}+(-2\sqrt{3} ) }{2}, \ \frac{2+4}{2}, \frac{2\sqrt{2} +4\sqrt{2} }{2}[/tex])

m = [tex]\frac{-2\sqrt{3} }{2} ,\frac{6}{2},\frac{6\sqrt{2} }{2}[/tex]

m = ([tex]-\sqrt{3} , 3 ,3\sqrt{2}[/tex])

Therefore, the midpoint is at( [tex]-\sqrt{3} , 3 ,3\sqrt{2}[/tex])

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The lowest possible integer value of x is 3 such that (x ≥ 3).

For the given question;

The area of rectangle A is bigger than the area of rectangle B.

The sides of the rectangle A are 2x-3 and 5 cm.

Area = length×breadth

Area A = (2x - 3)(5)

Area A = 10x - 15

The sides of the rectangle B are x = 2 and 3 cm.

Area = length×breadth

Area B = (x + 2)3

Area B = 3x + 6

As area B > area B

Then,

10x - 15 ≥  3x + 6

Solving the inequality;

10x - 3x ≥ 6 + 15

7x ≥ 21

x ≥ 3

Thus, the minimum value of the x is 3 to make the area A bigger than Area B.

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The measures of the sides of ΔXYZ are XY = 9.1, YZ = 11.4, XZ =  8. and the triangle XYZ must be an acute triangle

In this questions we have been given the the coordinates of the triangle XYZ.

X(-4, -2), Y(-3, 7), Z(4, -2)

We need to find  the measures of the sides of ΔXYZ .

We find the the measures of the sides using distance formula.

XY = √[(7 + 2)² + (-3 + 4)²]

XY = √[9² + 1²]

XY = √(81 + 1)

XY = √(82)

XY = 9.1

Now side YZ

YZ = √[(-2 - 7)² + (4 + 3)²]

YZ = √[(-9)² + (7)²]

YZ = √81 + 49

YZ = √130

YZ = 11.4

And the length of side XZ would be,

XZ = √[(-2 + 2)² + (4 + 4)²]

XZ = √0 + 8²

XZ = 8

We find the sum of the squares of the two smaller sides, and compare the sum to the square of the largest side.

the sum of the squares of the two smaller sides is,

= 8² + 9.1²

= 64 + 82.81

= 146.81

= 12.12²

And 11.4² = 129.96

Since the sum of the squares of the two smaller sides is greater than the square of the largest side, the triangle must be an acute triangle.

Therefore, the measures of the sides of ΔXYZ are XY = 9.1, YZ = 11.4, XZ =  8. and the triangle XYZ must be an acute triangle

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Answer:

a

Step-by-step explanation:

i ink

The positive interval is (0,2) and the negative range is calculated as (-4,0) and (2,4).

A graph is used to show the relationship between variables on a coordinate plane.

The domain of the function is [-4,4].

The zeros are: -2,0 and 2.

The positive interval is between (0,2).

The range of negative values is (-4,0) to (2,4). This is the set of x values in the graph. The graph demonstrates that the x value is between -4 and 4.

Thus, the domain is [-4,4]. The zeros of the function: Where it crosses the x- axis. The graph touches the x-axis when it is at -2,0 and 2. As a result, the function has the following zeros:-2,0 and 2.

Positive interval:

On the graph, positive values range from x = 0 to x = 2.

Consequently, the positive interval is (0,2).

Negative duration:

This is the x values when the function gives a negative result.

The graph shows negative values from x = -4 to x = 0, then from x = 2 to x = 4.

The negative range is therefore (-4,0) and (2,4).

Hence, the positive interval is (0,2) and the negative range is (-4,0) and (2,4).

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The two consecutive odd integers are less than 76 is the numbers are 37 and 39.

Any integer's reverse and sum are both equal to zero.

A positive sum results from adding two positive numbers, whereas a negative sum results from adding two negative integers.

Take the absolute value of each integer, then subtraction, to obtain the total of a positive and a negative integer.

Let two consecutive odd numbers be x and x+2

According to question

⇒ x........... equation (1)

⇒ x+2........equation (2)

by adding equation 1 and 2

⇒ x+x+2=76

⇒ 2x+2=76

⇒ 2x=76-2

⇒ 2x=74    

⇒  x=74/2

⇒ x=37

We apply the value of x=37 in equation (2)

⇒ x+2

⇒ 37+2

⇒ 39

so, the numbers are 37 and 39.

Therefore, the two consecutive odd integers are less than 76 is the numbers are 37 and 39

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The given lograthimic expression  log₃ y + 4 log₃ t can be written as log₃(yt^4).

According to the given question.

We have an logarithmic expression

log₃ y + 4 log₃ t

As we know that, a logarithmic expression is an expression that involves the logarithm of an expression containing a variable.

Also according to the product  and power rule we know that

log(mn) = logm + logn

Thereofore, the given lograthimic expression  log₃ y + 4 log₃ t can be written as

log₃ y + 4 log₃ t

= log₃ y + log₃ t ^4

= log₃(yt^4)

Hence, the given lograthimic expression  log₃ y + 4 log₃ t can be written as log₃(yt^4).

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The number of apples Chee bought is 2, and the number of peaches she bought is 8

From the question, we are to determine the number of apples, x, and the number of peaches, y, that Chee bought

From the given information,

She bought $6 worth of apples and peaches

and

Each apple costs $1 and each peach costs $0.50

Then, we can write that

$1 × x + $0.50 × y = $6

x + 0.50y = 6

Also,

She bought 4 times as many peaches as apples

That is,

y = 4x

Now, we will solve the system of equations graphically

x + 0.50y = 6

y = 4x

From the graph, the solution to the system of equations is x = 2, y = 8.

Hence, the number of apples Chee bought is 2, and the number of peaches she bought is 8

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The solution using the square root property for given complex numbers would be x = 10i where i is an imaginary number.

A complex number is a combination of real values and imaginary values. It is denoted by z = a + ib,

where a, and b are real numbers and i is an imaginary number.

We have been given the equation of complex numbers x² = -100

Using the square roots property to solve the above equation

⇒ x² = -100

⇒ x = √-100

⇒ x = √(-1×10×10)

∵ i² = - 1 or i = √-1

Here i is an imaginary number.

⇒ x = 10(√-1)

⇒ x = 10i

Therefore, the solution of given complex numbers would be x = 10i where i is an imaginary number.

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Answer: If you're solving for the substitution method then your answer would be (1,3)

Step-by-step explanation:

Answer:

x = -4/5

y = 9/5

Step-by-step explanation:

-3y + 2x = -7

8x - 3y = -1

make one of the equations y=....

-3y + 2x = -7

-3y = -7 - 2x

  y = (-7 - 2x)/3

now put (-7 - 2x)/3 where y is in the other equation

8x - 3y = -1

8x - 3((-7 - 2x)/3) = -1

8x - 1*(-7 - 2x) = -1

8x + 7 + 2x = -1

solve for x

8x + 7 + 2x = -1

8x+2x = -8

10x = -8

x = -8/10

x = -4/5

now put -8/10 in one of the equations to get what y is

-3y + 2x = -7

-3y + 2(-8/10) = -7

-3y - 16/10 = -7

-3y = -7 + 16/10

-3y = -70/10 + 16/10

-3y = -54/10

y = -54/10 * -1/3

y = 18/10

y = 9/5

Answer: A

Step-by-step explanation: took the quiz got it right

The cost of 8 oranges is $7.52

The first step is to find the cost of one orange

6 oranges cost 5.65

1 orange= 5.64/6

= 0.94

Therefore the cost of 8 oranges can be calculated as follows

= 0.94×8

= 7.52

Hence 8 oranges cost $7.52

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The equation of the line in slope-intercept form with a slope of -3/8 and y-intercept of (0 , 12) is y = (-3/8)x + 12.

The equation of a line can be expressed in three different forms: standard form, slope-intercept form, and point-slope form.

The slope-intercept form of the equation of a line is given by the formula:

y = mx + b

where m is the slope of the line

b is the y- intercept

Given that the slope of the line is -3/8 and the y-intercept is (0 , 12), write the equation of the line by simply plugging in its values.

y = mx + b

y = (-3/8)x + 12

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According to the question, determine whether the given sequence converges or diverges.

The given sequence is: [tex]a(n) = \frac{9+3n^{2} }{n+8n^{2} }[/tex]

Taking limits tends to infinity on both sides. And dividing numerator and denominator by [tex]n^{2}[/tex]

Therefore, the final term can be re-written as: [tex]a(n) = \frac{9+3n^{2} }{n+8n^{2} } = \frac{3}{8}[/tex].

Hence, the given sequence converges and the limit is [tex]\frac{3}{8}[/tex].

What converges and diverges in limits?

When the limits of the sequence exist and have finite value that means the sequence is a convergent sequence. The calculated value is a real number. And the tem divergence means limits do not exist.

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