Answer:
[tex]s=253.6524712 \approx 253.7[/tex]
Explanation:
From the question we are told that
Initial speed[tex]v=8ft/s[/tex]
Final speed [tex]v=128ft/s[/tex]
Generally the Newtons equation of motion is mathematically represented by
[tex]V_f^2-V_0^2=2as[/tex]
with
Therefore
[tex]a=g=>9.81m/s^2\\a=32.17ft/s^2[/tex]
Therefore
[tex]128^2-8^2=2*(32.17)*s[/tex]
[tex]16320=2*(32.17)*s[/tex]
[tex]s=\frac{16320}{2*(32.17)}[/tex]
[tex]s=253.6524712 \approx 253.7[/tex]
The picture below shows a man in Varanasi, India, resting on a bed of nails. Which principle about impact force
allows him to do this without getting hurt, and why
Answer:
Since there are hundreds of nails, instead of puncturing your skin the nails actually support you.
Explanation:
If you step on the point of a nail, your foot exerts a tremendous amount of pressure on the nail's tiny point. As a result, the point can go straight through your foot. But a bed of nails has lots of points that are close together -- there's a lot of surface area for the body to cover. Hundreds of nails support the weight of your body instead of just one. Typically, your body doesn't exert enough pressure on any one nail for it to break the skin. You can even place a second bed on top of you and break a cinderblock on it. The resulting force is distributed over all of the nails, so you shouldn't be injured.
The impact force will be less because of the pressure is equally distributed over the body of man. The nails will not puncture his skin.
What is pressure?The pressure of any object is given by the force acting per unit area. When the contact area is less, the object will penetrate.
If one steps on the point of a nail, his foot exerts a tremendous amount of pressure on the nail's contact point. As a result, it will penetrate into the foot. In case of a bed of nails, many nail points placed close together. The surface area for the body to make contact is increased.
Then, hundreds of nails now will support the weight of his body.
Thus, the impact force will be less because of the pressure is equally distributed over the body of man. The nails will not puncture his skin.
Learn more about pressure.
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A student in a lab experiment jumps upward off a common bathroom scale as the lab partner records the scale reading. What does the lab partner observe during the instant the student pushes off?
The scale reading will remain unchanged during the entire time the student is in contact with the scale.
The scale reading will increase momentarily then will decrease as the student is moving upward from the scale.
The scale reading will increase during the entire time the student is in contact with the scale.
The scale reading will decrease momentarily then will increase as the student is moving upward from the scale.
Answer:
B: The scale reading will increase momentarily then will decrease as the student is moving upward from the scale
Explanation:
The way weighing scale works is that when you climb on it, it will take your weight reading but when you are moving off the top of it, the reading slowly approaches 0 until you are completely off it.
Thus, the lab partner will observe that the reading will increase for a while and then gradually decrease to zero as the student moves upwards off the scale.
The correct answer is (B)The scale reading will increase momentarily then will decrease as the student is moving upward from the scale.
According to the third law of motion, every action has an equal and opposite reaction. In order to jump, the student will apply force to the bathroom scale in downward direction and there will be an equal force exerted by the bathroom scale upwards on the student which helps him jump.
So when the student applies downward force on the scale in order to jump, the scale reading will increase momentarily and then will decrease as the student moves upwards.
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without calculation explain why the vertical component of velocity v h changes from 3.5 m/s at A to 0 m/s at B
Answer:
due to gravity.
Explanation:
.............
A flat, rigid object oscillates as a physical pendulum in simple harmonic motion with a frequency f. The mass of the pendulum is m, and the pivot point is a distance d from the center of mass. What is the moment of inertia of the pendulum about its pivot point
Answer:
I = mgd/4π²f²
Explanation:
The period of the physical pendulum T = 1/f where f = frequency,
T = 1/f = 2π√(I/mgd) where I = moment of inertia of the physical pendulum, m =mass of pendulum, g = acceleration due to gravity and d = distance of center of mass of pendulum from pivot point.
1/f = 2π√(I/mgd)
dividing both sides by 2π, we have
1/2πf = √(I/mgd)
squaring both sides, we have
(1/2πf) = [√(I/mgd)]²
1/4π²f² = I/mgd
multiplying both sides by mgd, we have
I = mgd/4π²f²
QUESTION 1
A box, initially at rest, has 33.3 N of force exerted on it for 2.35 s. If the box has a mass of 7.33 kg, what was its velocity at this time?
Answer:
Velocity of the box: 10.67 m/s
Explanation:
Recall that impulse is defined as the force applied times the time the force is in action. Then we can obtained the value of the impulse given to the box as:
Impulse = F * time = 33.3 N * 2.35 s = 78.225 kg m/s
then we use the momentum of the box at that precise time to find its velocity recalling that :
Momentum = mass * velocity
Then
78.225 kg m/s = 7.33 kg * v
v = 78.225/7.33 m/s = 10.67 m/s
To ____________________ something is to slowly mix in a bit of _____________ ___________________ with eggs or cream to raise the temperature slowly. This prevents the cream from curdling (turning lumpy and gross) or the eggs from scrambling in your sauce.
Answer:
temper; hot sauce
Explanation:
The context clue here is "raise the temperature slowly" gives a quick clue to temper (as a verb). The 4th definition of temper (as a verb) is "to bring to a suitable state by mixing or adding a usually liquid ingredient." Knowning, this leads to the second blank being hot sauce, as that's a liquid.
If the engine of a car is replaced by one that doubles the amount of net force, the car's acceleration will ___.
Answer:
Double
Explanation:
Newton's second law of motion states that the acceleration of an object is directly proportional to and acts in the same direction as the net force acting on the object. The second law of motion can be represented by the equation:
F ∝ a;
F = ma
where m is the mass which is the constant of proportionality, F is the net force and a is the acceleration of the object.
Hence for a car with a constant mass, if the engine is replace with one that doubles the net force, the acceleration of the car would also double.
Why do the balls react differently when you drop them together?
a machine has an efficiency of 70 percent, how much work does the machine do when 20000 j of work is done on it a. 14000 b. 20600 c. 1400000 or c. 2860000
Answer:
a. 14000
Explanation:
Given parameters:
Efficiency of the machine = 70%
Work done on machine = 20000J
Unknown:
Work done by machine = ?
Solution:
Efficiency of a machine is determined by;
Efficiency = [tex]\frac{Work done by machine}{Work done on machine} x 100[/tex]
70 = [tex]\frac{Work done by machine}{20000}[/tex] x 100
70 = [tex]\frac{work done by machine}{200}[/tex]
Work done by machine = 70 x 200 = 14000J
A billiard ball is moving in the x-direction at 30.0 cm/s and strikes another billiard ball moving in the y-direction at 40.0 cm/s. As a result of the collision, the first ball moves at 50.0 cm/s, and the second ball stops. In what final direction does the first ball move?
Answer:
53.13 °
Explanation:
In order to do this, we just need to apply the following:
tanα = Dy/Dx
Where:
Vy: speed of the ball in the y axis.
Vx: speed of the ball in the x axis.
At this point we do not need the speed of the first ball after the collision because in that moment is already heading in the direction that we are looking for. Therefore, we just need to use the innitial data to calculate the direction which the first ball will go.
According to this, then:
tanα = (40/30)
tanα = 1.3333
α = tan⁻¹(1.3333)
α = 53.13°This means that the final direction of the first ball is 53.13° and in the x axis because the starting momentum of this ball in the x axis has not dissapeared.
Hope this helps
What are two ways engineers use their understanding of KE and PE to make their designs better / Safer?
Answer:
Follows are the solution to this question:
Explanation:
Energy shifts at such a rollercoaster ride many times throughout a ride from possibility to dramatic power. Kinetic energy is the energy the object provides for its movement. The coaster machine is traditionally lifted by a rope from the very first hill. It gains energy stored because as vehicles move up.
OR
we can say that whenever anyone travels through an amusement park ride often recognized as a ring road, energy transfers from the opportunity to kinetic energy, because of the layout of the curves as well as the slope, and it is replicated few more occasions during the ride.
Kinetic energy seems to be used in motion.
Its amusement ride vehicles were usually climbed back by a rope from the very first hill, but as the other vehicles move along that route, they acquire potential power.
A source of frequency f sends waves of wavelength λ traveling with speed v in some medium. If the frequency is changed from f to 2f, then the new wavelength and new speed are (respectively): Question 1 options:
Answer:
Explanation:
The speed will remain unchanged because speed does not depend upon frequency .
So new speed = v
wavelength x frequency = speed
For frequency = 2 f
wavelength = speed / frequency
= v / 2f
So new wavelength = v / 2f .
1. The new wavelength is equal to [tex]\frac{\lambda}{2}[/tex].
2. The new speed is equal to v.
Given the following data:
Wavelength = λSpeed = vInitial frequency = fFinal frequency = 2fTo determine the new wavelength and new speed are:
Mathematically, the speed of a waveform is calculated by using the formula;
[tex]v = \lambda f[/tex]
Where:
[tex]\lambda[/tex] is the wavelength of a wave.v is the speed of a wave.f is the frequency of a wave.Ideally, the speed of a wave doesn't change when the frequency provided they are both in the same medium.
However, the wavelength would change when frequency changes.
Therefore, the new speed = v.
For new wavelength:
[tex]v = \lambda f=\frac{\lambda}{2} (2f)[/tex]
New wavelength = [tex]\frac{\lambda}{2}[/tex]
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Coulomb's Law: Coulomb's law is F = k (q1xq2)/ r^2 where k = 9 x 10^9 C^2/m^2. a) Sketch the charges and use Coulomb's law to determine the electric force between two charged particles where q1 = -5 x 10^-3 C and q2 = -1 x 10^-3 C. Q1 and Q2 are separated by a distance of 0.25 m. b) Determine whether the electric force attractive or repulsive and explain your answer?
Answer:
a) F = 7.20 10⁵ N, b) the force between charges is repulsive.
Explanation:
For this exercise we calculate the electric forces given by Coulomb's law
[tex]F = k \frac{q_{1} q_{2} }{r^{2} }[/tex]
where in this case they indicate that q1 = 5 103 C and q2 = 1 103 C and the distance between them r = 0.25 m
let's calculate
F = [tex]9 10^{9} \ \frac{5 \ 10^{-3} \ \ 1 \ 10^{-3} }{0.25^{2} }[/tex]
F = 7.20 10⁵ N
b) when electric charges have the same sign they repel and when they have the opposite sign they attract.
In this case, charge 1 is negative and charge 2 is negative, therefore, since they both have the same sign, the force between charges is repulsive.
A force acts on a body of mass 13 kg initially at rest. The force
acts for 10 seconds, and once it quits, the body covers 60 min
the next 6 seconds. Find the force that acted on the body.
Answer:
Force that acted on the body was F = 13 N
Explanation:
If once accelerated, the body covers 60 meters in 6 seconds, then its velocity is 60/6 m/s = 10 m/s
When the force was acting (for 10 seconds) the object accelerated from rest (initial velocity vi = 0) to 10 m/s (its final velocity). therefore we can use the kinematic equation for the velocity in an accelerated motion given by:
[tex]v_f=v_i+a*t[/tex]
which in our case becomes;
[tex]10\,m/s=0+a*(10\,s)[/tex]
and we can solve for the acceleration as:
a = 10/10 m/s^2 = 1 m/s^2
Therefore the force acting on the body, based on Newton's 2nd Law expression: F = m * a is:
F = 13 kg * 1 m/s^2 = 13 N
A 5 kg rock falls from an 8 m high cliff. What is the speed of the rock when it hits the ground?
Answer:
3k mph
Explanation:
don't take my answer it is wrong
PLEASE HELP 100 POINTS
The graph shows the force applied to an object over a displacement of 4 meters. What is the total work done on the object over the 4 meter displacement?
Answer:
okay, So Um,
Explanation:
BTW, There are only 50 points, brainly subtracts half of the points
A 5.0 kg object suspended on a spring oscillates such that its position x as a function of time t is given by the equation x (t ) = A cos(ωt ), where A = 0.80 m and ω = 2.0 s-1 . What is the magnitude of the maximum net force on the object during the motion?
Answer:
The magnitude of the maximum net force on the object during the motion is 16 newtons.
Explanation:
The position of the mass, measured in meters, within the mass-spring system is:
[tex]x(t) = A\cdot \cos \left(\omega\cdot t \right)[/tex] (1)
Where:
[tex]A[/tex] - Amplitude, measured in meters.
[tex]t[/tex] - Time, measured in seconds.
[tex]\omega[/tex] - Angular frequency, measured in radians per second.
The acceleration function ([tex]\ddot {x} (t)[/tex]), measured in meters per square second, is obtained by deriving twice (1) in time:
[tex]\dot {x} (t) = -\omega\cdot A\cdot \sin (\omega\cdot t)[/tex]
[tex]\ddot {x} (t) = -\omega^{2}\cdot A\cdot \cos (\omega\cdot t)[/tex] (2)
And the maximum acceleration ([tex]a_{max}[/tex]), measured in meters per square second, experimented by the mass is:
[tex]a_{max} = \omega^{2}\cdot A[/tex] (3)
And the maximum net force ([tex]F[/tex]), measured in newtons, is:
[tex]F = m\cdot a_{max}[/tex] (4)
If we know that [tex]\omega = 2\,\frac{rad}{s}[/tex], [tex]A = 0.80\,m[/tex] and [tex]m = 5\,kg[/tex], then the maximum net force on the object during the motion is:
[tex]a_{max} = \left(2\,\frac{rad}{s} \right)^{2}\cdot (0.80\,m)[/tex]
[tex]a_{max} = 3.2\,\frac{m}{s^{2}}[/tex]
[tex]F = (5\,kg)\cdot \left(3.2\,\frac{m}{s^{2}} \right)[/tex]
[tex]F = 16\,N[/tex]
The magnitude of the maximum net force on the object during the motion is 16 newtons.
The magnitude of the maximum net force on the object during the motion will be 16 newtons.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration. Its unit is Newton.
The given data in the problem is;
m is the mass of 5.0 of object kg
x (t ) = A cos(ωt ),
A is the amplitude= 0.80 m
ω is the frequency= 2.0 s-1 .
F is the magnitude of the maximum net force=?
The position of the mass is given by the equation;
[tex]x(t)= A cos( \omega t)[/tex]]
[tex]\em \dot x= - \omega A sin(\omega t) \\\\ \dot \dot x = - \omega ^2 A cos (\omega t)[/tex]
The maximum acceleration is found as;
[tex]\rm a_{max} = \omega ^2 A \\\\ \rm a_{max} = (2) ^2 \times 0.80 \\\\ \rm a_{max} =3.2 \m/sec^2[/tex]
The value of net force is found as;
[tex]\rm F= m a_{max} \\\\ \rm F= 5 \times 3.2 \\\\\ \rm F=16\ N \\[/tex]
Hence the magnitude of the maximum net force on the object during the motion will be 16 newtons.
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what's the size of our Galaxy
Answer:
Stellar disk: 185 ± 15 kly (kilo Langley/year)
Dark matter halo: 1.9 ± 0.4 Mly (mega light year) (580 ± 120 kpc)
Explanation:
The Milky Way galaxy contains the sun and the planets orbiting around it. This galaxy also contains up to 400 billion stars. The stellar disk of this galaxy is between 170,000 to 200,000 light years which is equal to a diameter of 52 - 61 kiloparsec.
Its thickness is measured at 0.3kpc which is also equal to 1000 light years. Its mass is 890 billion to 1.54 trillion times the mass of the sun. Its size is second to that of the Andromeda galaxy.
Which techniques can scientists use to determine the characteristics of Earth's layers? Select the two correct answers.
conduct experiments about how minerals change under high pressure
study how seismic waves travel through different layers
examine the behavior of minerals at extremely low temperatures
use X-rays to obtain a view of Earth's interior layers
drill deep mines to obtain samples from Earth's mantle and core
Answer:
1 and 3
Explanation:
Scientists can use the following techniques to determine the characteristics of Earth's layers: a) conduct experiments on how minerals change under high pressure; and b) investigate how seismic waves travel through different layers.
Characteristics of Earth's layersMechanically and chemically, the Earth is divided into two categories. The lithosphere, asthenosphere, mesospheric mantle, outer core, and inner core are mechanically separated. However, chemically, which is the more popular of the two, it can be divided into the crust, mantle, and core - which can be further subdivided into outer core and inner core. The outer core is liquid, the inner core is solid, and the mantle is solid/plastic. This is due to the relative melting points of the different layers, as well as the increase in temperature and pressure as depth increases. Because they are cool enough, nickel-iron alloys and silicates are solid at the surface.To learn more about Earth's layers refer :
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A tennis ball moves 16 meters northward, then 22 meters southward, then 12 meters northward, and finally 32 meters southward.
Determine the magnitude of the distance the object traveled
Answer:
26 m southwards.
Explanation:
From a North, East, South, West coordinate plane, moving northwards implies positive distance. While moving southwards implies negative distance.
Thus;
It moves 16 meters northward; d = 16 m
It now moves 22 meters southward; d = -22 m
It moves 12 meters northward; d = 12 m
It moves 32 meters southward; d = -32 m
Thus, total magnitude = 16 - 22 + 12 - 32 = -26 m
Thus, the object travels 26 m southwards.
Burning can be:
controlled for useful work
stopped for use work
wasted for useful work
Answer:
Controlled for useful work
Explanation:
Here we want to select the option that best describes what burning can be used for
Generally, when we talk about something being burnt, we are referring to the fact that we have the thing being on fire.
So basically, when something is on fire, we can say it is burning. We can harness the burning strength of a particular material or substance to do useful work.
For example, in a fire place in our homes, the burning of wood pieces can be used to heat up our homes. It is this same wood burning that has devastating effects in the bushes which in fact when left uncontrolled can cause degrees of catastrophic damages.
But, by taking the pieces and placing in a fire place in our homes, we have successfully controlled its bad effect and use it to do the useful work of heating up the environment
Two resistors are connected in parallel to a 12 V battery. The potential difference across one of the resistors is 12 v . Calculate the potential difference across the other resistor
Answer:
See the explanation below.
Explanation:
We have to take into account that the potential difference is equal to the voltage, and this is measured between two points as the resistors are connected in parallel to the voltage source, the resistors will have the same voltage.
For ease, we will take the attached image of resistors connected in parallel.
As both resistors at their ends share the A & B connection points, these are at a voltage of 12V
An object accelerates 3.0 m/s2 when a force of 6.8 newtons is applied to it. What is the mass of the object?
Find the electron and hole mobilities, and the resistivity of intrinsic silicon at 300K. Is intrinsic silicon a semiconductor
Answer:
Resistivity = 231.481 K Ohm
Yes, Intrinsic Silicon is the semiconductor.
Explanation:
Solution:
At 300K:
Let suppose mobility of electron in intrinsic semiconductor = [tex]M_{e}[/tex]
Mobility of electron in intrinsic semiconductor is:
[tex]M_{e}[/tex] = 1300 [tex]cm^{2}[/tex]/volt.sec
Let suppose mobility of hole in intrinsic semiconductor = [tex]M_{h}[/tex]
[tex]M_{h}[/tex] = 500 [tex]cm^{2}[/tex]/volt.sec
We know that, intrinsic silicon semiconductor has equal number of holes and electrons. So,
At 300 K
Intrinsic Carrier Concentration = 1.5 x [tex]10^{10}[/tex]/[tex]cm^{3}[/tex] = C
And,
Conductivity of intrinsic Silicon is:
σ = C x ([tex]M_{h}[/tex] + [tex]M_{e}[/tex]) e
e = 1.6 x [tex]10^{-19}[/tex] C
So, plugging in the values, we get:
σ = C x ([tex]M_{h}[/tex] + [tex]M_{e}[/tex]) e
σ = 1.5 x [tex]10^{10}[/tex] x (500 + 1300) x 1.6 x [tex]10^{-19}[/tex]
σ = 4.32 x [tex]10^{-6}[/tex]
So, now we can find the resistivity.
Resistivity = 1/σ
Resistivity = 1/ 4.32 x [tex]10^{-6}[/tex]
Resistivity = 231.481 K Ohm
Yes, Intrinsic Silicon is the semiconductor.
An object moves along the x-axis. Its position is given by the equation y( X = 4t^2 - 41t+ 78 \). Find the position of the
object when it changes direction
The object changes direction when its velocity changes sign. You can get the velocity function by differentiating the position function with respect to time t :
x(t) = 4t ² - 41t + 78
→ v(t) = dx(t)/dt = 8t - 41
Solve v(t) = 0:
8t - 41 = 0
8t = 41
t = 41/8 = 5.125
Just to confirm that the velocity indeed changes sign:
• Pick any time before this one to check the sign of v :
v (0) = 8•0 - 41 = -41 < 0
• Pick any time after and check the sign again:
v (6) = 8•6 - 41 = 7 > 0
Now just find the position at this time:
x (5.125) = -433/16 = -27.0625
which means the object is 27.0625 units on the negative x-axis.
You can also do this without calculus by completing the square in the position function:
4t ² - 41t + 78 = 4 (t ² - 41/4 t ) + 78
… = 4 (t ² - 2• 41/8 t + (41/8)² - (41/8)²) + 78
… = 4 (t ² - 2• 41/8 t + (41/8)²) - 4•1681/64 + 78
… = 4 (t - 41/8)² - 433/16
which describes a parabola that opens upward. When t = 41/8 = 5.125, the quadratic term vanishes and the turning point of the parabola occurs at a position of -433/16 units.
A woman of mass 50 kg is swimming with a velocity of 1.6 m/s. If she stops stroking and glides to a stop in the water, what is the impulse of the force that stops her?
Answer:
Impulse of force = -80 Ns
Explanation:
Given the following data;
Mass = 50kg
Initial velocity = 1.6m/s
Since she glides to a stop, her final velocity equals to zero (0).
Now, we would find the change in velocity.
[tex] Change \; in \; velocity = final \; velocity - initial \; velocity [/tex]
Substituting into the equation above;
Change in velocity = 0 - 1.6 = 1.6m/s
[tex] Impulse \; of \; force = mass * change \; in \; velocity [/tex]
Substituting into the equation, we have;
[tex] Impulse \; of \; force = 50 * -1.6[/tex]
Impulse of force = -80 Ns
Therefore, the impulse of the force that stops her is -80 Newton-seconds and it has a negative value because it is working in an opposite direction, thus, bringing her to a stop.
If the mass of the moon is ...
a. ... increased by a factor of 2, then the F . is
by a factor of
b. ... increased by a factor of 3, then the F., is
by a factor of
C. ... decreased by a factor of 4, then the F... is
by a factor of
d. Discuss some evidence (data values) and reasoning in which you explain the
logic behind your answers to parts a-c.
The ball of a ballpoint pen is 0.5 mm in diameter and has an ASTM grain size of 12. How many grainsare there in the ball
Answer:
the number of grains in the ball is 274,848
Explanation:
Given that;
diameter = 0.5 mm
so radius r = 0.25 mm
first we determine the volume of the ball using the following equation;
V = 4/3×πr³
we substitute
V = 4/3×π(0.25)³
V = 0.06544 mm³
Now form table 1.1 "Grain sizes" a metal with grain size number of 12 has about 4,200,000 grains/mm³
so;
Number of grains N = 0.06544 × 4,200,000
N = 274,848 grains
Therefore, the number of grains in the ball is 274,848
(I am doing a lab called, Density of solids and I need help with this question) (I am in HS and I picked Physics because I thought it was short for Physical Science )
4. Locate the data and observations collected in your lab guide. What are the key results? How would you best summarize the data to relate your findings?
Answer: Location the data and observations collected in your lab guide
Explanation:
Kraig pulls a box to the right at an angle of 40 degrees to the horizontal with a force of 30 Newtons. If Kraig pulls the box a distance of 20 meters, determine the work done by Kraig.
Answer:
459.6J
Explanation:
Given parameters:
Angle of pull = 40°
Force applied = 30N
Distance moved = 20m
Unknown:
Work done by Kraig = ?
Solution:
To solve this problem;
Work done = F x dcosФ
d is the distance
F is the force
Ф is the angle given
Work done = 30 x 20cos40° = 459.6J