I will give brainliest answer

Answer:

7.5000

Step-by-step explanation:

Answer:

1.6

Step-by-step explanation:

1.2, 1.8, 1.6, 1.4, 1.4, 2.2's mean rounded to the nearest tenth is 1.6

Answer:

I'm not completely sure about the first one, but #8 is 0.0419, and #9 is 30500.

Answer:

£2112

Step-by-step explanation:

To find Gavin's share, sum the parts of the ratio, 4 + 1 = 5 parts

Divide the win by 5 to find the value of one part of the ratio.

£8800 ÷ 5 = £1760 ← value of 1 part of ratio, thus

4 parts = 4 × £1760 = £7040 ← Gavin's share

Now repeat the process with the ratio for his family

1 + 6 + 3 = 10 parts

£7040 ÷ 10 = £704 ← value of 1 part of the ratio, thus

6 × £704 = £4224 ← wife's share

3 × £704 = £2112 ← son's share

Difference = £4224 - £2112 = £2112

Thus his wife gets £2112 more than the son

Answer:

part A 2.6+1.7+9.8-4.2=9.9

part B 6.7-9.9+22-28.46=9.66

Step-by-step explanation:

Part A

First find the square root.

the square root of 7 is 2.6

the square root of 3 is 1.7

the square root of 98 is 9.8

the square root of 18 is 4.2

Then: add and subtract them

2.6+1.7+9.8-4.2=9.9

Part B

I don't know how to explain the next part so I will just give you the answer

6.7-9.9+22-28.46=9.66

I hoped this helped

Answer:

t is between 0.47 seconds and 4.02 seconds

Step-by-step explanation:

Given

[tex]Inequality: -4.9t^2+22t+0.75>10[/tex]

Required

Determine the values of t

[tex]-4.9t^2+22t+0.75>10[/tex]

Subtract 10 from both sides

[tex]-4.9t^2+22t+0.75 - 10 >10 - 10[/tex]

[tex]-4.9t^2+22t-9.25 >0[/tex]

Multiply through y -1

[tex]4.9t^2-22t+9.25 <0[/tex]

Solve t using quadratic formula:

[tex]t = \frac{-b \±\sqrt{b^2 - 4ac}}{2a}[/tex]

Where

[tex]a = 4.9[/tex]

[tex]b = -22[/tex]

[tex]c = 9.25[/tex]

So, we have:

[tex]t = \frac{-(-22) \±\sqrt{(-22)^2 - 4*4.9*9.25}}{2 * 4.9}[/tex]

[tex]t = \frac{22 \±\sqrt{484 - 181.3}}{9.8}[/tex]

[tex]t = \frac{22 \±\sqrt{302.7}}{9.8}[/tex]

[tex]t = \frac{22 \±17.40}{9.8}[/tex]

Split the equation

[tex]t = \frac{22 + 17.40}{9.8}[/tex] or [tex]t = \frac{22 - 17.40}{9.8}[/tex]

[tex]t = \frac{39.4}{9.8}[/tex] or [tex]t = \frac{4.6}{9.8}[/tex]

[tex]t = \frac{39.4}{9.8}[/tex] or [tex]t = \frac{4.6}{9.8}[/tex]

[tex]t = 4.02[/tex] or [tex]t = 0.47[/tex]

Hence; the range is

[tex]0.47 < t <4.02[/tex]

Answer: simple random sampling

Step-by-step explanation:

From the question, we are informed that a research team conducts a survey to determine the area of land used for farming in Iowa and that the team randomly selects house addresses and sends the survey by mail.

The type of sampling method which the research team is using market is the simple random sampling method. A simple random sampling is a subset of a larger set whereby all the participants have an equal and fair chance of being selected in the survey participation.

Answer:

none of these have the solution of x = -4

Step-by-step explanation:

1 . 3x + 6 - 2x = -2 .    (combine like terms)

x + 6 = -2  (isolate the variable)

  -6     -6

x = -8    *x doesn't equal - 4*

2.  2(2 - 4) = 16    (distributive property)

2 - 8 = 16

-6 = 16

since theres no x in the equation its not a possible answer .

3 .  (x + 6) 3 = - 6  

this one also isn't a proper equation to find x

4.    -x + 4 = 3   (isolate the variable)

           -4    -4

-x = -1

/x .   /x

x= -1  

Answer:

13

Step-by-step explanation:

Answer:D y=94x

Step-by-step explanation:

First dive y and x

Then you multiply the next x and the number that you got.

ALSO I GOT IT RIGHT

D. y = 94x. will be the equation that can be used to model the relationship between x and y.

Any mathematical statement that includes numbers, variables, and an arithmetic operation between them is known as an expression or algebraic expression. In the phrase 4m + 5, for instance, the terms 4m and 5 are separated from the variable m by the arithmetic sign +.

Given, a table is attached below.

Since The data in the table is showing the proportionality feature.

the property of having suitable proportions in terms of size, number, degree, harshness, etc. If a defensive action against an unfair attack results in destruction that contravenes the proportionality criterion, it may even go far beyond a justifiable defense.

Thus,

The ratio of distance and time for the cheetah = 470/5 or 940/10 or 1410/15

Since the time is denoted by "x" (in seconds) and distance is denoted by "y".

So,

y/x  = 470/5

y = 94x

therefore, the equation that can be used to model the relationship between x and y will be  D. y = 94x.

Learn more about algebraic Expression here:

https://brainly.com/question/953809

#SPJ6

Answer:

A. Move 5 units down, then 7 units to the right.

Step-by-step explanation:

Answer: 3x=-3 soooooo x= -1

Step-by-step explanation:

lmk for more info

Answer:

x=17

Step-by-step explanation:

Hope this helps

Hey there! I'm happy to help!

Step 2 is incorrect. She added 4 and 2 first, but you are supposed to multiply and divide first. Then she multiplied 6 and 6, which is 36. Then she divided 36 and 2, which is 18, and then she subtracted 7, giving her 11. Step 2 is what threw the whole thing off.

Here is what Sandy should have done.

STEP 1: 6·4+2÷2-7

STEP 2: 24+1-7

STEP 3: 25-7

STEP 4: 18

I hope that this helps! Have a wonderful day! :D

Steps to solve:

6 * 4 + 2 / 2 - 7

~Multiply

24 + 2 / 2 - 7

~Divide

24 + 1 - 7

~Add

25 - 7

~Subtract

18

In step one, she added instead of multiplied which caused her to get the wrong answer.

Best of Luck!

Answer:

Albert invested 21,000 and John invested 49,000 :)

Answer:

Step-by-step explanation:

The number of "ratio units" in their investment ratio is 3+7 = 10. Albert's investment was 3/10 of the total, so was $21,000. John invested the remaining amount, $49,000.

Albert invested $21,000; John invested $49,000.

Answer:

Step-by-step explanation:

-5x + y = -2………… Equation 1

-3x + 6y = -12 ………… Equation 2

Using substitution

Make y the subject in equation 1 and substitute it into equation 2 and solve for x

That's

y = 5x - 2

We have

- 3x + 6( 5x - 2) = - 12

- 3x + 30x - 12 = - 12

27x = - 12 + 12

27x = 0

Divide both sides by 27

x = 0

Substitute x = 0 into y = 5x - 2

We have

y = 5(0) - 2

y = - 2

So the solutions are

Hope this helps you

Step-by-step explanation:

1) angle 2 and 4

2)angle 2 and 3

3)angle 1 and 4

Hope it helps

Answer:15

Step-by-step explanation:

Answer:

interest = Amount-Principal= 2160-2000=160

Rate = Interest*100/(P*T)= 160*100/(2000*2)=4%

Step-by-step explanation:

Answer:

The correct option is c: 1.5 cm.

Step-by-step explanation:

The amplitude of the motion can be calculated using the following equation:

[tex] A = \frac{v}{\omega} [/tex]

Where:

A: is the amplitude

v: is the speed = 15 cm/s

ω: is the angular speed

First, we need to find the angular speed:

[tex] \omega = \frac{2\pi}{T} [/tex]

Where:

T is the period = 628 ms

[tex] \omega = \frac{2\pi}{T} = \frac{2\pi}{0.628 s} = 10.01 rad/s [/tex]

Now we can find the amplitude:

[tex] A = \frac{v}{\omega} = \frac{15 cm/s}{10.01 s} = 1.5 cm [/tex]

Therefore, the correct option is c: 1.5 cm.

I hope it helps you!                          

Answer: -5*10^0

               -6*10^0

                6*10^0

                -4*10^0

I hope this helped there's also standard calculators so don't waste your points .

Problem 9

List any three points that are on the same straight line.

So for example, you could say A, P and B. Or you could say C, P, and D. A third one you could do is J, D and K.

==============================

Problem 10

Now we're listing any three points that aren't on the same straight line.

One example of such triple is A, P and D. Another example is K, D, and C. There are many others as well.

==============================

Problem 11

List any four points that are in the same plane. So you'll pick four points from the set {A, B, C, D, P} to answer this question as these five points are all in the shaded plane R.

==============================

Problem 12

Pick any four points such that they do not all exist in the same plane. It doesn't matter which points you pick as long as J or K are one of the points selected. This is because neither J nor K are in the plane R.

===============================

Problem 13

Line JK intersects CD at point D. The other line that crosses CD is line AB.

Line AB is in plane R, while line JK intersects the plane at point D only.

===============================

Problem 14

Intersecting line JK and plane R results in point D. This is where the line and plane meet, as mentioned in the previous problem.

If you were asked to intersect line AB and plane R, then you would get line AB as a result. All of line AB is inside the plane.

Answer:

3/3 12/15 divided 3/3 = 4/3

Answer: Matherens has the better price

Step-by-step explanation:

To find the better price, all we have to do is divide the price by the number of pounds to find how much one pound is for each store.

Matherens: 1.98 ÷ 3 = 0.66

That means 1 pound of bananas at Matherens is 66 cents.

Winn Dixie: 2.97 ÷ 4 = 0.74

That means 1 pound of bananas at Winn Dixie is 74 cents.

This means that Matherens is charging less per pound of banana.

Answer:

67.31

Step-by-step explanation:

ahhshshshahaha

Answer:

The answer is 67.31

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

AOB + BOC = AOC

AOC = 90 since  the lines are perpendicular

6x-12 + 3x+30 = 90

Combine like terms

9x + 18 = 90

Subtract 18 from each side

9x+18-18 = 90-18

9x = 72

divide by 9

9x/9 = 72/9

x = 8

AOB = 6x - 12

         = 6*8 - 12

          = 48 -12

        = 36

Answer:

AOB = 36

Step-by-step explanation:

OA is perpendicular to OC

AOB + BOC = 90 ------------equation

where:

AOB = 6x - 12

BOC = 3x + 30

plugin values into the eq.

6x - 12 + 3x + 30 = 90

6x + 3x + 30 - 12 = 90

9x + 18 = 90

9x = 90 - 18

9x = 72

x = 72/9

x = 8

plugin values to AOB = 6x - 12

AOB = 6x - 12

AOB = 6(8) - 12

AOB = 36

Answer:

The value is  [tex]p- value  = 0.041815[/tex]

Step-by-step explanation:

From the question we are told that

  The  population mean is [tex]\mu  =  40 \ hours[/tex]

  The  sample size is  [tex]n  =  18[/tex]

    The  sample mean is  [tex]\= x =  37.8 \ hours[/tex]

   The standard deviation is  [tex]\sigma  = 5.4\ hours[/tex]

The null hypothesis is  [tex]H_o  :  \mu =  \ge 40[/tex]

The alternative hypothesis is  [tex]H_a  :  \mu < 40 \ hour s[/tex]

Generally the test statistic is mathematically evaluated as

       [tex]t=  \frac{\= x - \mu}{ \frac{\sigma}{ \sqrt{n} } }[/tex]

      [tex]t=  \frac{37.8 - 40}{ \frac{5.4}{ \sqrt{18 } }[/tex]

      [tex]t=  -1.73[/tex]

From the z - table the p-value is obtained and the value is  

      [tex]p- value  =  P(Z <  -1.73)[/tex]

        [tex]p- value  = 0.041815[/tex]

To test DullCo's hypothesis, the p-value is 0.041815 and this can be determined by using the given data.

Given :

The following steps can be used in order to determine the p-value for DullCo's hypothesis:

Step 1 - The formula for t-statistics can be used in order to determine the p-value for DullCo's hypothesis.

Step 2 - The formula for t-statistics is given below:

[tex]t = \dfrac{\bar{x}-\mu}{\dfrac{\sigma}{\sqrt{n} }}[/tex]

where the sample size is 'n', the standard deviation is [tex]\sigma[/tex], and the mean is [tex]\mu[/tex].

Step 3 - Now, substitute the values of [tex]\sigma[/tex], [tex]\mu[/tex], [tex]\bar{x}[/tex], and n in the above formula.

[tex]t = \dfrac{37.8-40}{\dfrac{5.4}{\sqrt{18} }}[/tex]

Step 4 - SImplify the above expression.

[tex]t = \dfrac{-2.2}{1.2727}[/tex]

[tex]t = -1.73[/tex]

Step 5 - Now, with the help of the z-table the p-value is:

[tex]\rm p-value = P(Z<-1.73)[/tex]

[tex]\rm p-value = 0.041815[/tex]

To test DullCo's hypothesis, the p-value is 0.041815.

For more information, refer to the link given below:

https://brainly.com/question/14723549

Answer:

the probability that system’s failure is due to the radio = [tex]\dfrac{1}{3}[/tex]

Step-by-step explanation:

From the question given;

Let the mean lifetime of the radio  [tex]\dfrac{1}{\lambda_1} = 1000[/tex] and the mean lifetime of the speaker [tex]\dfrac{1}{\lambda_2} = 500[/tex]

we can re-write both expressions as:

[tex]\lambda_1= \dfrac{1}{1000}[/tex]  and [tex]\lambda_2= \dfrac{1}{500}[/tex]

Let consider [tex]X_1 \ and \ X_2[/tex] to be the variables which are independent to the exponentially distributed mean of [tex]\dfrac{1}{\lambda _1} \ and \ \dfrac{1}{\lambda _2}[/tex]

∴

[tex]P(X_1< X_2) = \int ^{\infty}_{0} \ P (X_1<X_2|X_1 =x) \lambda_1 e^{-\lambda_1 \ x} \ dx[/tex]

[tex]P(X_1< X_2) = \int ^{\infty}_{0} \ P (X_1<X_2) \lambda_1 e^{-\lambda_1 \ x} \ dx[/tex]

[tex]P(X_1< X_2) = \int ^{\infty}_{0} \ e^{-\lambda_2 \ x} \lambda _1 \ e^{-\lambda_1 \ x} \ dx[/tex]

[tex]P(X_1< X_2) = \int ^{\infty}_{0} \lambda _1 \ e^{(-\lambda_1 +\lambda_2)} \ dx[/tex]

[tex]P(X_1< X_2) = \dfrac{\lambda_1}{\lambda_1 + \lambda_2}[/tex]

replace the values now; we have:

[tex]P(X_1< X_2) = \dfrac{\dfrac{1}{1000} }{\dfrac{1}{1000} + \dfrac{1}{500}}[/tex]

[tex]P(X_1< X_2) = \dfrac{\dfrac{1}{1000} }{\dfrac{1+2}{1000} }[/tex]

[tex]P(X_1< X_2) = \dfrac{\dfrac{1}{1000} }{\dfrac{3}{1000} }[/tex]

[tex]P(X_1< X_2) = {\dfrac{1}{1000} } \times {\dfrac{1000}{3}[/tex]

[tex]P(X_1< X_2) = {\dfrac{1}{3} }[/tex]

Thus, the probability that system’s failure is due to the radio = [tex]\dfrac{1}{3}[/tex]