i.
Determine the rms current of the periodic function.
ii. When a 100-ohm resistor is connected in this periodic
function, what will be the average power?

Answers

Answer 1

Given: The periodic function is  v(t) = 40sin(100πt) + 60cos(100πt) RMS Current of the periodic functionThe RMS current of the periodic function is given by the formula:  

[tex]Irms=√((I1² +I2² +....+ In² )/ n )[/tex]where I1, I2, .....In are the instantaneous currents at the time t1, t2, ......tn respectively. And n is the number of instantaneous currents.The current in the circuit can be calculated using Ohm’s Law.[tex]i(t) = v(t) / R = v(t) / 100 1 = 40sin(100πt) / 100 = 0.4sin(100πt)I2 = 60cos(100πt) / 100 = 0.6cos(100πt)[/tex]Therefore, [tex]Irms = √[(0.4)² + (0.6)²]/√2= 0.7071 or 0.71 A[/tex] (approx) When a 100-ohm resistor is connected in this periodic function,

We know that Average power = (Irms)²RThe value of Irms is 0.71 A and the value of resistance R is 100 Ohm.Average power = (0.71)² x 100= 50.41 W (approx)Therefore, the average power in the given periodic function is 50.41 W (approx).

To know more about function visit :

https://brainly.com/question/30721594

#SPJ11


Related Questions

6. [5 points] During an adiabatic expansion the temperature of 0.450 mol of argon (Ar) drops from 50 °C to 10 °C. By treating the argon as an ideal gas, (a) Draw a pV-diagram for this process (supply sufficient information in the diagram). (b) How much is the work done by the gas? (c) What is the change in internal energy of the gas? Is it increased or decreased?

Answers

(a) The pV-diagram would show a decrease in pressure and an increase in volume.

(b) The work done by the gas can be calculated using the area under the pV-curve.

(c) The change in internal energy is equal to the negative of the work done by the gas.

(a) The pV-diagram for the adiabatic expansion of 0.450 mol of argon from 50 °C to 10 °C would show a decrease in pressure and an increase in volume. In an adiabatic process, there is no heat exchange with the surroundings. As the gas expands, it does work against an external pressure, resulting in a decrease in pressure and an increase in volume. The pV-diagram would depict an upward-sloping curve, representing the expansion. The initial state would be represented by a point on the diagram, corresponding to the initial temperature and volume, while the final state would be represented by another point, reflecting the final temperature and volume.

(b) The work done by the gas can be calculated by finding the area under the pV-curve on the diagram. In an adiabatic process, the magnitude of the work done is given by the equation: Work = (P2V2 - P1V1) / (γ - 1). Here, P1 and V1 represent the initial pressure and volume, P2 and V2 represent the final pressure and volume, and γ is the heat capacity ratio for the gas. To determine the exact work done, we would need the specific value of γ for argon.

(c) The change in internal energy of the gas can be determined using the First Law of Thermodynamics. The equation ΔU = Q - W relates the change in internal energy (ΔU) to the heat added to the system (Q) and the work done by the system (W). In an adiabatic process, where there is no heat exchange (Q = 0), the change in internal energy is equal to the negative of the work done by the gas. Therefore, as the gas expands adiabatically, the work done by the gas will result in a decrease in internal energy.

Learn more about Gas

brainly.com/question/14812509

#SPJ11

In the laboratory, the helium atom has an emission line at 587.60 nm. A nebula (a region of ionized gas) is observed in space, and this heliumemission line is observed at 587.82 nm. What is velocity of this nebula towards or away from the Sun? Use a negative number for the velocity if the nebula and the Sun are moving towards each other and a positive number if the nebula and the Sun are moving away from each other. Your velocity should be in units of km/s (kilometers/second).

Answers

The velocity of the nebula towards or away from the Sun can be determined by calculating the difference in wavelength between the observed helium emission line in the nebula and the laboratory wavelength, using the formula for Doppler shift.

The Doppler shift formula, Δλ/λ = v/c, relates the change in wavelength (Δλ) to the velocity (v) of an object relative to an observer, where λ represents the laboratory wavelength and c is the speed of light. In this case, the observed helium emission line in the nebula is at 587.82 nm, while the laboratory wavelength is 587.60 nm.

By plugging these values into the formula and solving for v, we can find the velocity of the nebula. The velocity will be negative if the nebula and the Sun are moving towards each other and positive if they are moving away from each other. The resulting velocity will be in units of km/s (kilometers/second).

learn more about atom click here;

brainly.com/question/1566330

#SPJ11

Question 6 of 15 < > 0.1/1 View Policies Show Attempt History Current Attempt in Progress Your answer is partially correct. When the displacement in SHM is equal to 1/5 of the amplitude Xm, what fraction of the total energy is (a) kinetic energy and (b) potential energy? (c) At what displacement, in terms of the amplitude, is the energy of the system half kinetic energy and half potential energy? (Give the ratio of the answer to the amplitude) (a) Number i 24/25 ! Units No units (b) Number i 1/25 ! Units No units (c) Number i 1/2 ! Units No units 'amplitude Question 8 of 15 < > 0.38 / 1 III : View Policies Show Attempt History Current Attempt in Progress Your answer is partially correct. The balance wheel of a watch oscillates with angular amplitude 0.591 rad and period 0.14 s. Find (a) the maximum angular speed of the wheel, (b) the angular speed of the wheel at displacement 0.591/2 rad, and (c) the magnitude of the angular acceleration at displacement 0.59x/4 rad. (a) Number 83.2 Units rad/s (b) Number i -72.0 Units rad/s (c) Number i -933 Units rad/s^2 V

Answers

Question 6 a) 24/25 of the total energy is kinetic energy. (b) 1/25 of the total energy is potential energy. (c) The displacement at which the energy is half kinetic and half potential is given by Amplitude/√2.

Question 8 a) Maximum angular speed of the wheel is 28.27 rad/s.(b) Angular speed of the wheel at displacement 0.591/2 rad is 1.99 rad/s.(c) The magnitude of the angular acceleration at displacement 0.59x/4 rad is -8.17 × 10³ rad/s².

Question 6

Part (a) Kinetic energy is given by 1/2 mv²

where m is the mass of the system and v is the velocity. The total energy of the system is the sum of the kinetic and potential energy. Here, we are given the displacement in terms of the amplitude, so we can write the displacement as x = Xm/5 where Xm is the amplitude.

Using the equations for displacement and velocity in SHM, we get:x = Xm/5 = Xm cos(ωt)

∴ cos(ωt) = 1/5ω = ±ω0√24/25

where ω0 is the angular frequency at amplitude Xm, which is given by ω0 = 2π/T where T is the time period of oscillation.

At x = Xm/5, the kinetic energy is given by:

K.E. = 1/2 mω0²Xm²(24/25) × (1/25)

= 24/625 of the total energy

Part (b) At the same point, the potential energy is given by:

P.E. = 1/2 kx² = 1/2 k(Xm/5)² = 1/50 kXm²where k is the spring constant of the system. Therefore, the potential energy is given by:

P.E. = (1 - 24/625) = 601/625 of the total energy

Part (c) Let x = X/√2 be the displacement at which the energy of the system is half kinetic and half potential. At this point, the kinetic energy is given by:

K.E. = 1/2 mω0²(Xm²/2) = 1/4 mω0²Xm²

Similarly, the potential energy is given by:

P.E. = 1/2 k(Xm²/2)² = 1/8 kXm²

Therefore, we have:1/4 mω0²Xm² = 1/8 kXm²∴ Xm = √(2m/k)The displacement at which the energy is half kinetic and half potential is given by:

X/√2 = √(2m/k) × 1/√2

= √(m/k)

= Amplitude/√2

Question 8

Part (a) The maximum angular speed of the wheel is given by:

ωmax = ±√(2π/T)² - (π/τ)²= ±4π/T = ±28.27 rad/s

Part (b)The angular speed of the wheel at displacement 0.591/2 rad is given by:

v = ω0 √(Xm² - x²)

where x = 0.591/2, Xm = 0.591 rad and ω0 = 2π/T.

Therefore:

v = ω0 √(Xm² - x²) = 1.99 rad/s

Part (c)The magnitude of the angular acceleration at displacement 0.59x/4 rad is given by:

a = -ω² x

where x = 0.59x/4, Xm = 0.591 rad, and ω0 = 2π/T.

Therefore:a = -ω² x = -8.17 × 10³ rad/s²

To learn more about  angular speed:

https://brainly.com/question/6860269

#SPJ11

A two-wire transmission line carries equal and opposite direct current I in each wire. The first wire, with a current I in the positive z direction is located at -D/2 and the second wire, with a current I in the negative z direction is located at +D/2. The current distribution is uniform in each wire. Draw this scenario.

a) Express the magnetic flux density on the x-axis anywhere between the two conductors (y = 0, -D/2 + a < x < D/2 - a)
b) Find the magnetic flux for a surface on the x-z plane where (y = 0, -D/2 + a < x < D/2 - a, -l/2 < z < l/2)
c) Determine the inductance per unit length for this two-wire transmission line.

Answers

a) The magnetic flux density on the x-axis between the two conductors (y = 0, -D/2 + a < x < D/2 - a) can be expressed as follows:

B = μ_0I/4π(y+D/2) - μ_0I/4π(y-D/2)

It can be rewritten as

B = μ_0I/4π [1/(y+D/2) - 1/(y-D/2)]

We know that the magnetic field at any point around a current-carrying conductor is directly proportional to the current and inversely proportional to the distance between the point and the wire. Therefore, the magnetic field in the x-direction between the two conductors can be expressed as above.

b) The magnetic flux on the x-z plane, where (y = 0, -D/2 + a < x < D/2 - a, -l/2 < z < l/2) is given by the equation

ϕ = ∫B.ds,

where the surface integral is taken over the closed surface of the rectangle whose four corners are at (-a, -l/2, -D/2), (a, -l/2, -D/2), (a, l/2, -D/2), and (-a, l/2, -D/2), and which lies in the x-z plane. Here, the direction of ds is perpendicular to the plane of the rectangle and is given by the right-hand rule. This integral can be evaluated using the magnetic flux density expression found in part (a) as follows:

ϕ = ∫B.ds= μ_0I/4π ∫[(1/(y+D/2) - 1/(y-D/2))dx]dz

= μ_0Ia ln [(l/2+D/2-a)/(l/2-D/2+a)]

We know that magnetic flux is defined as the product of magnetic field and the area perpendicular to it. Therefore, the flux on the x-z plane can be found by integrating the magnetic flux density over the surface of the rectangle as described above.

c) The inductance per unit length of the two-wire transmission line is given by the equation

L/l = μ_0/π ln (D/a),

where L is the inductance, l is the length of the transmission line, D is the distance between the wires, and a is the radius of each wire. Here, we assume that the wires have the same radius and are uniformly spaced. Substituting the values of the parameters given in the problem, we get:

L/l = μ_0/π ln (D/a)

= 4π x 10^-7/π ln (D/a)

= 4 x 10^-7 ln (D/a) H/m

We know that inductance is directly proportional to the permeability of the medium and the square of the distance between the conductors and inversely proportional to the natural logarithm of the ratio of the distance between the conductors and their radius. Therefore, we can use the equation above to find the inductance per unit length of the transmission line.

Learn more about magnetic flux density: https://brainly.com/question/28499883

#SPJ11

Find Ia​ in the circuit in Fig. P5.18, using superposition.

Answers

The superposition current (Ia) in the circuit is 3.56 A.

The superposition theorem is used to calculate currents and voltages in complex circuits that have multiple sources. This theorem assumes that a circuit has more than one source of voltage or current. A superposition is then calculated by turning off one source and solving for the other. This process is repeated until the total circuit current is found.

The following are the steps involved in calculating the superposition current (Ia) of the circuit shown in Fig. P5.18:

(i) Switch off the current source (4 A) in the circuit and connect the two ends of the current source with a short circuit (zero ohms).

(ii) Compute the resistance seen by the 10 V voltage source to determine the voltage contributed by the 10 V voltage source. Using the voltage divider rule, calculate the voltage drop across 6 ohms, which is equal to 6/(2+6) × 10 = 6.67 V. Hence the voltage of the 10 V source will be 10 - 6.67 = 3.33 V.

(iii) Find the total current Ia using Ohm's law. That is, Ia = 3.33/6 = 0.56 A.

(iv) Now switch off the voltage source (10 V) in the circuit and connect its ends with a short circuit (zero ohms).

(v) Calculate the resistance seen by the current source (4 A) to determine the current contributed by the 4 A current source. The resistance seen by the current source is equal to 2+6 = 8 ohms. Hence the current of the 4 A source will be 4 × 6/8 = 3 A.

(vi) Calculate the total current Ia using Ohm's law. That is, Ia = 3 + 0.56 = 3.56 A.

Therefore, Ia is equal to 3.56 A.

Learn more about superposition

https://brainly.com/question/33182470

#SPJ11

A single-stage, single-acting air compressor has a swept volume of 0.007634 m². Atmospheric air at 101.3 kPa and 20°C is drawn into the compressor and is discharged at 680 kPa. Assume the index of compression and re-expansion is n- 1.30. Determine the induced volume per stroke, Vin" x 10-3 m³. 6.364 6.438 6.651 3.185

Answers

The induced volume per stroke (Vin) of the given air compressor is 6.438 x 10^-3 m³. Therefore, the correct option is 6.438.  Answer: 6.438.

Given Data:Swept Volume (Vs)

= 0.007634 m²P1 (inlet pressure)

= 101.3 kPaT1 (inlet temperature)

= 20°CP2 (outlet pressure)

= 680 kPank (Index of Compression)

= n

= 1.30We know that the formula for the volume of the air delivered per stroke (Vin) is:Vin

= Vs / (1/n) [(P2/P1)n-1]Since, the Index of Compression and Re-expansion is n

= 1.30, thus putting the values in the above formula, we get:Vin

= 0.007634 / (1/1.30) [(680/101.3)1.3-1]Vin

= 6.438 x 10^-3 m³. The induced volume per stroke (Vin) of the given air compressor is 6.438 x 10^-3 m³. Therefore, the correct option is 6.438.  Answer: 6.438.

To know more about compressor visit:

https://brainly.com/question/31672001

#SPJ11

Two charges Q1 = -5 μC and Q2 = +5 μC are located on the y-axis at y1 = -9 cm and y2 = +9 cm respectively. A third charge Q3 = +40 μC is added on the y-axis so that the electric field at the origin is equal to zero. What is the position of Q3?
a. y3 = -40 cm
b. y3 = +9 cm
c. y3 = -18 cm
d. y3 = -20 cm
e. y3 = +18 cm

Answers

The position of Q3 on the y-axis, such that the electric field at the origin is zero, is y3 = 0 cm.

None of the given options (a, b, c, d, e) match the correct answer.

To find the position of Q3 on the y-axis such that the electric field at the origin is zero, we need to consider the contributions of the electric fields created by each charge.

The electric field due to a point charge is given by:

E = k * (Q / r^2)

where:

E is the electric field

k is the electrostatic constant (k = 9 × 10^9 N m^2/C^2)

Q is the charge

r is the distance from the charge to the point where the electric field is being calculated.

Since the electric field at the origin is zero, the contributions from Q1, Q2, and Q3 should cancel each other out.

Let's calculate the electric field due to each charge at the origin:

Electric field due to Q1:

E1 = k * (Q1 / r1^2)

E1 = k * (-5 μC / (-0.09 m)^2)

E1 = k * (-5 × 10^(-6) C / 0.0081 m)

E1 = -k * 617.28 C / m^2

Electric field due to Q2:

E2 = k * (Q2 / r2^2)

E2 = k * (5 μC / (0.09 m)^2)

E2 = k * (5 × 10^(-6) C / 0.0081 m)

E2 = k * 617.28 C / m^2

Electric field due to Q3:

E3 = k * (Q3 / r3^2)

E3 = k * (40 μC / y3^2)

Since the electric field is zero at the origin, we have the following equation:

0 = E1 + E2 + E3

0 = -k * 617.28 C / m^2 + k * 617.28 C / m^2 + k * (40 μC / y3^2)

Simplifying the equation:

0 = k * (40 μC / y3^2)

Since k and Q3 are constants, we can equate the remaining terms to zero:

0 = 40 μC / y3^2

Solving for y3:

y3^2 = 40 μC / 0

y3^2 = 0

Taking the square root of both sides:

y3 = 0

Therefore, the position of Q3 on the y-axis, such that the electric field at the origin is zero, is y3 = 0 cm.

None of the given options (a, b, c, d, e) match the correct answer.

To learn more about, electric field, click here, https://brainly.com/question/30544719

#SPJ11

Question Four (a) Show that for a horizontal pin-ended strut compressed by a load P and supporting a uniformly distributed load of magnitude wN/m along its complete length, the Maximum deflection is given by; W 1 nl Sec 8 max - (-)-] P n = P Where EI And I is the Second Moment of Area of the strut cross-section about a horizontal axis through the centre of gravity while E is the Modulus of Elasticity of the strut. (b) A horizontal strut 4.2m long has a hollow circular section of outside diameter 100mm and inside diameter 82mm . The strut supports an axial compressive load of magnitude 140kN together with a uniformly distributed load of magnitude 3.6kN / m over its entire length.

Answers

The deflection of the horizontal strut that is 4.2m long and has a hollow circular section of outside diameter 100mm and inside diameter 82mm when it supports an axial compressive load of magnitude 140kN together with a uniformly distributed load of magnitude 3.6kN/m over its entire length is `9.72 x 10⁻³ m`.

The area of the cross-section of the strut is given by;` [tex]A = pi/4 (d_0^2 - d_1^2)`[/tex]

= `[tex]pi/4 (0.1^2-0.82^2)`[/tex]

= `5.58 x 10⁻ m²³

`From the area of the cross-section, the second moment of area can be calculated;`

[tex]I = (pi/64) (d_0^4 - d_1^4)`[/tex]

=`(π/64) (0.1⁴ - 0.082⁴)`

= `6.42 x 10⁻⁷ m⁴

To find the deflection of the strut, the following formula can be used;`[tex]w1 nl Sec 8 max - (-)-] Pn = P[/tex]

`Firstly, the value of `8_max` needs to be determined. Since the strut is pin-ended, the maximum deflection occurs at the centre of the strut. By considering only the uniformly distributed load acting on the strut, the formula for the maximum deflection can be derived;`[tex]delta_max = 5 w l^4 / (384 E I)`[/tex]

=`5 (3.6 x 10³) (4.2)⁴ / (384 x 200 x 10⁹ x 6.42 x 10⁻⁷)`

= `9.72 x 10⁻³ m`

Therefore, the deflection of the strut is given by the following formula;`

delta = delta_max (P / n) / (P / n)`

=`delta_max`

=`9.72 x 10⁻³

Hence, the deflection of the horizontal strut that is 4.2m long and has a hollow circular section of outside diameter 100mm and inside diameter 82mm when it supports an axial compressive load of magnitude 140kN together with a uniformly distributed load of magnitude 3.6kN/m over its entire length is `9.72 x 10⁻³ m`.

To know more about deflection, refer

https://brainly.com/question/1581319

#SPJ11

3. Find I1, using KVL,KCL, Wye Delta.

Answers

In order to find I1 using KVL (Kirchhoff's Voltage Law), KCL (Kirchhoff's Current Law), and Wye-Delta, follow the steps mentioned below:Step 1: Considering KVL in the loop where I1 flows: V1 = I1 × (R1 + R2 + R3)Step 2: Applying KCL at node A: I2 = I1/2 + I3

Step 3: Expressing I2 in terms of I1 and I3: I2 = 2I1 - I3Step 4: Substituting the above expression of I2 in KCL equation: 2I1 - I3 = I1/2 + I3=> 4I1 = 5I3 => I3 = 4I1/5Step 5: Converting the resistors from Y configuration to Δ configuration:R1 = R3 = 20 Ω, R2 = 40 ΩR12 = (R1 × R2)/(R1 + R2) = (20 × 40)/(20 + 40) = 13.33 ΩR23 = (R2 × R3)/(R2 + R3) = (40 × 20)/(40 + 20) = 26.67 ΩR31 = (R3 × R1)/(R3 + R1) = (20 × 20)/(20 + 20) = 10 ΩStep 6: Writing the equation for the Δ configuration using Ohm's law: V3 = I3 × R23 and V2 = I2 × R12Step 7: Expressing I3 in terms of I1: V3 = 4I1/5 × 26.67 Ω = 21.34 I1V2 = (2I1 - 4I1/5) × 13.33 Ω = 8.9 I1Step 8: Using KVL in the outer loop: V1 = V3 + V2V1 = 21.34 I1 + 8.9 I1V1 = 30.24 I1I1 = V1/30.24 ΩTherefore, the expression for I1 obtained using KVL, KCL, and Wye-Delta is I1 = V1/30.24 Ω.

To know more about order visit:

https://brainly.com/question/32646415

#SPJ11

In an AC circuit a sinusoidal voltage with peak amplitude of 250 volts is applied to a resistance with a value of 250 Ω. What is the value of the power dissipated in the resistor?

Answers

The answer is 125 W.In an AC circuit, a sinusoidal voltage with peak amplitude of 250 volts is applied to a resistance with a value of 250 Ω.

The value of the power dissipated in the resistor is 250 W when the rms voltage is equal to the peak voltage divided by the square root of 2. This can be calculated using the formula P = V^2/R where V is the rms voltage and R is the resistance value.

In this case, the peak voltage is 250 volts, so the rms voltage can be calculated as follows:Vrms = Vp/√2 = 250/√2 ≈ 176.78 volts Substituting these values into the formula for power, we get:P = V^2/R = (176.78)^2/250 = 125 W Therefore, the value of the power dissipated in the resistor is 125 W.

To know more about resistance visit:-

https://brainly.com/question/14547003

#SPJ11

21. [0/5 Points] DETAILS The 1 kg standard body is accelerated by only F₁ = (6.0 N) ↑ + (7.0 N) ĵ and F₂ = (-5.0 N)i + (−3.0 N) ĵ. 1 2 (a) What is the net force in unit-vector notation? F net PREVIOUS ANSWERS X Submit Answer HRW10 5.P.097. N (b) What is the magnitude and direction of the net force? magnitude XN direction ° counterclockwise from the +x-axis (c) What is the magnitude and direction of the acceleration? magnitude m/s² direction counterclockwise from the +x-axis

Answers

The net force in unit-vector notation can be calculated as follows;

[tex]F_net = F_1 + F_2 = (6.0 N) ↑ + (7.0 N) ĵ + (-5.0 N)i + (−3.0 N) ĵ= (-5.0 N)i + (4.0 N) ĵ[/tex]

The magnitude and direction of the net force can be calculated as;

[tex]|F_net| = √((-5.0)^2 + 4.0^2)|F_net| = 6.4 Ntanθ = 4.0 / 5.0θ = tan⁻¹(4.0/(-5.0))θ = -38.7°[/tex]

The magnitude of the net force is 6.4 N, and the direction of the net force is 38.7 degrees counterclockwise from the +x-axis.

The magnitude and direction of the acceleration can be calculated as follows;

[tex]a = F_net / m = (-5.0 N)i + (4.0 N) ĵ / 1 kga = (-5.0 m/s²)i + (4.0 m/s²) ĵ|a| = √((-5.0)^2 + 4.0^2)|a| = 6.4 m/s²tanθ = 4.0 / 5.0θ = tan⁻¹(4.0/(-5.0))θ = -38.7°[/tex]

The magnitude of the acceleration is 6.4 m/s², and the direction of the acceleration is 38.7 degrees counterclockwise from the +x-axis.

To know more about force visit:

https://brainly.com/question/30507236

#SPJ11

The paper clips are made from a magnetic material write down
the name of one magnet material

Answers

One magnetic material used to make paper clips is iron. Its ferromagnetic properties enable paper clips to exhibit magnetic attraction and efficiently serve their purpose of holding papers together.

Iron is a magnetic material that exhibits ferromagnetism, which is the ability to become permanently magnetized when exposed to a magnetic field. Due to its magnetic properties, iron is widely used in the manufacturing of various magnetic products, including paper clips.Iron possesses a high magnetic susceptibility, meaning it readily responds to magnetic fields and can be easily magnetized. When an external magnetic field is applied to iron, the domains within the material align, resulting in a magnetized state. This property allows paper clips made of iron to attract and hold other magnetic objects.The use of iron in paper clips is advantageous because it provides a strong magnetic force, ensuring that the paper clips securely hold documents together. Additionally, iron is readily available, cost-effective, and easily fabricated into the desired shape, making it a practical choice for manufacturing paper clips.It is worth noting that while iron is commonly used, other magnetic materials such as nickel, cobalt, and some alloys can also be used in the production of paper clips. However, iron remains one of the most widely used magnetic materials due to its effectiveness and availability.

For more such questions on magnetic material, click on:

https://brainly.com/question/10394567

#SPJ8

a lightbulb with a resistance of 2.9 ohms is operated using a 1.5-volt battery. at what rate is electrical energy transformed in the lightbulb? * 10 points 0.78 w 0.52 w 6.5 w 4.4 w

Answers

The electrical energy is transformed in the lightbulb at the rate of 0.78 W.

Given, Resistance of the light bulb, R = 2.9 ohms, Voltage of the battery, V = 1.5 V

Now we know that the power dissipated by the light bulb can be calculated by using the formula;

P = V²/R

Substituting the values we get;

P = (1.5 V)² / 2.9 Ω

= 0.78 W

Therefore, the electrical energy is transformed in the lightbulb at the rate of 0.78 W.

The formula for Power is given as:

P = VI where P is power, V is the voltage, I is the current

Substituting the values we get;

P = V²/RP

= (1.5 V)² / 2.9 Ω

P = 2.25 / 2.9P

= 0.78 W

Therefore, the electrical energy is transformed in the lightbulb at the rate of 0.78 W.

Learn more about electrical energy here:

https://brainly.com/question/1580875

#SPJ11

It is given that the word line of a DRAM is asserted causing the pass transistor to open up. You notice that this leads to dissipation of charge over the digit line causing voltage change in the capacitor. In the given context, which of these parameters will affect the final charge on the capacitor? 1. Capacitance of the word line 2. Capacitance of the DRAM cell capacitor 3. Capacitance of the digit line

Answers

In the given context, the final charge on the capacitor in a DRAM cell will be affected by the capacitance of the DRAM cell capacitor (option 2).

The capacitance of the word line (option 1) and the capacitance of the digit line (option 3) will not directly affect the final charge on the capacitor.

In the given context, the final charge on the capacitor in a DRAM cell is primarily affected by the capacitance of the DRAM cell capacitor (option 2). The DRAM cell capacitor stores the charge and represents the main component responsible for holding the information in the memory cell.

When the word line of a DRAM cell is asserted, the pass transistor opens up, allowing the charge stored in the capacitor to be transferred to the digit line. However, during this process, there may be some dissipation of charge over the digit line, causing a voltage change.

While the capacitance of the word line (option 1) and the capacitance of the digit line (option 3) do play a role in the overall operation of the DRAM cell, they primarily affect the speed and efficiency of charge transfer and signal propagation. They do not directly impact the final charge stored in the capacitor itself.

Therefore, in the given context, the capacitance of the DRAM cell capacitor (option 2) is the parameter that most directly affects the final charge on the capacitor.

To know more about capacitor refer here

https://brainly.com/question/31627158#

#SPJ11

There was 1 kg of steam at the temperature T_{g} = 473.16K in a calorimeter. Piece of ice with m = 1 kg at the temperature T_{g} = 223.16 K was added in the calorimeter. What kind of substance (steam, ice or water) will be in the calorimeter? What will be the final temperature of it. T,?

Answers

The substance in the calorimeter will be water, and the final temperature will be 273.16 K.

When the steam at temperature Tg = 473.16 K and the ice at temperature Tg = 223.16 K are mixed in the calorimeter, heat transfer occurs between the two substances until thermal equilibrium is reached. The steam, being at a higher temperature, will lose heat and condense into water, while the ice will gain heat and melt into water. Since the calorimeter is closed and no substances are added or removed, the final substance in the calorimeter can only be water.

During the heat transfer process, the heat lost by the steam is equal to the heat gained by the ice. This can be calculated using the principle of energy conservation, known as the heat equation:

[tex]m1 * c1 * (T - T1) = m2 * c2 * (T2 - T)[/tex]

Here, m1 and m2 are the masses of the steam and ice respectively, c1 and c2 are the specific heat capacities of steam and ice, T1 and T2 are the initial temperatures of the steam and ice, and T is the final temperature of the water in the calorimeter.

By substituting the given values into the equation and solving for T, we can find the final temperature. However, it is important to note that the specific heat capacity of water is different from that of steam and ice. Therefore, additional calculations would be required to account for the specific heat capacity of water and obtain a precise final temperature.

Learn more about calorimeter

brainly.com/question/28034251

#SPJ11




Part A For SHM along a horizontal axis, when x is most positive then O ay is most positive O ay is zero and increasing ay is zero and decreasing az is most negative Submit Request Answer

Answers

4. ay is zero and decreasing: This states that the acceleration in the y-direction (ay) is initially positive but decreasing over time. The object is moving towards the equilibrium position, and the acceleration is diminishing in the positive y-direction.

For simple harmonic motion (SHM) along a horizontal axis, the given statements can be understood as follows:

1. When x is most positive: This refers to the position of the object in the positive direction of the axis, reaching the maximum displacement. At this point, the acceleration in the y-direction (ay) is zero, and the object is momentarily at rest.

2. O ay is most positive: This means that the acceleration in the y-direction (ay) reaches its maximum positive value. It implies that the object is experiencing the maximum acceleration in the positive y-direction.

3. O ay is zero and increasing: This indicates that the acceleration in the y-direction (ay) is initially zero but is increasing over time. The object is moving away from the equilibrium position, and the acceleration is building up in the positive y-direction.

to know more about acceleration visit:

brainly.com/question/30762941

#SPJ11

Q3 The charge entering the positive terminal of an element is
given by the expression q(t) = -8 e^(-3t) mC. The power delivered
to the element is p(t) = 1.7e^(-2t) W. How much energy delivered to
the

Answers

The charge entering the positive terminal of an element is given by the expression, q(t) = -8 e^(-3t) m C. The power delivered to the element is p(t) = 1.7e^(-2t) W. Therefore, the amount of energy delivered to the element is 0.725 J.

To find the amount of energy delivered to the element, we need to integrate the power function with respect to time.  Mathematically, the energy delivered to the element is given by;

E(t)

= ∫p(t)dt

We are required to find the energy delivered over a certain period of time, let's say from

t = 0 to

t = 4 seconds.

So, E(t)

= ∫(0 to 4s) p(t)dt

= ∫(0 to 4s) 1.7e^(-2t)dt

Using integration by substitution,

let u = -2t,  then du/dt

= -2, and dt

= -du/2.

Substituting these values in the equation above, we have:

E(t)

= ∫(0 to 4s) 1.7e^(u) (-du/2)

= [tex]-0.85∫(0 to 4s) e^(u) du=-0.85[e^(u)](0 to 4s)=-0.85[e^(-8) - e^(0)]J[/tex]

= 0.725 J

Therefore, the amount of energy delivered to the element is 0.725 J.

To know more about charge visit :

https://brainly.com/question/13871705

#SPJ11

Simple Rotational Variables Problem Points:40 The angular position of a point on the rim of a rotating wheel is given by 0 = 2.0t + 5.0t² + 1.4t³, where 0 is in radians if t is given in seconds. What is the angular speed at t = 2.0 s? Submit Answer What is the Tries 0/40 angular speed at t = 5.0 s? Submit Answer Tries 0/40 What is the average angular acceleration for the time interval that begins at t = Submit Answer Tries 0/40 What is the instantaneous acceleration at t = 5.0 s? Submit Answer Tries 0/40 2.0 s and ends at t = 5.0 s? OneDrive Screenshot saved

Answers

The angular position of a point on the rim of a rotating wheel is 24.8 rad/s. The angular speed at t = 5.0 s is 142.0 rad/s, The average angular acceleration for the time interval that begins at t = 2.0 s and ends at t  is 39.07 rad/s². the instantaneous acceleration at t s is 52.0 rad/s².

1. The formula for angular speed is given as follows;

ω = dθ/dt

Where,ω is the angular speedθ is the angle in radians measured from a reference line and t is the time in seconds

Given, θ = 2.0t + 5.0t² + 1.4t³

Differentiating θ w.r.t t we get,

ω = dθ/dt = 2.0 + 10.0t + 4.2t²

At t = 2.0 s, ω = 2.0 + 10.0(2.0) + 4.2(2.0)² = 24.8 rad/s

Therefore, the angular speed at t = 2.0 s is 24.8 rad/s.

2. At t = 5.0 s, ω = 2.0 + 10.0(5.0) + 4.2(5.0)² = 142.0 rad/s

Therefore, the angular speed at t = 5.0 s is 142.0 rad/s

Angular acceleration,

α = dω/dt

Instantaneous acceleration, a = rα

Where r is the radius of the wheel.

3. Let ω₁ be the angular speed at t = 2.0 s, and let ω₂ be the angular speed at t = 5.0 s.

Average angular acceleration, α_avg = (ω₂ - ω₁)/Δt

Where, Δt = t₂ - t₁ = 5.0 - 2.0 = 3.0 s

From the above calculations,ω₁ = 24.8 rad/s andω₂ = 142.0 rad/s

Therefore,α_avg = (142.0 - 24.8)/3.0 = 39.07 rad/s²

Therefore, the average angular acceleration for the time interval that begins at t = 2.0 s and ends at t = 5.0 s is 39.07 rad/s².

4. instantaneous acceleration, a = rα

Where r is the radius of the wheel and

α = dω/dtAt t = 5.0 s, ω = 2.0 + 10.0(5.0) + 4.2(5.0)² = 142.0 rad/s

Differentiating ω w.r.t t,α = dω/dt = 10.0 + 8.4t

Therefore, at t = 5.0 s, α = 10.0 + 8.4(5.0) = 52.0 rad/s²

Therefore, the instantaneous acceleration at t = 5.0 s is 52.0 rad/s².

To learn more about angular acceleration:

https://brainly.com/question/31991521

#SPJ11

Which of the following processes lead to the appearance of a magnetic field? 1) The movement of charged particles; 2) electrification of bodies; 3) the change in time of the electric field; 4) the flow of current through the conductor; 5) the movement of material bodies.

Answers

The movement of charged particles leads to the appearance of a magnetic field. The correct answer is option 1)

When a charged particle moves, it creates a magnetic field around it. This happens because the moving charges create a current, which produces a magnetic field. The strength and direction of the magnetic field depend on the speed and direction of the particle's movement. If the charges move in a straight line, the magnetic field will be perpendicular to the direction of motion.

However, if the charges move in a circular path, the magnetic field will be circular as well. The flow of current through a conductor also creates a magnetic field around it, as it involves the movement of charged particles. However, the other processes listed do not lead to the appearance of a magnetic field. Electrification of bodies involves the buildup of static charges, but does not produce a magnetic field. The change in time of the electric field is related to electromagnetic waves, but does not create a magnetic field. Finally, the movement of material bodies also does not produce a magnetic field.

Learn more about static charges here:

https://brainly.com/question/508980

#SPJ11

Which vector is the sum of the vectors shown below?

A.
B.
C.
D.

Answers

The arrow C is the best vector diagram representing the sum of the vectors.

option C.

What is the sum of two vectors?

The sum of two vectors is a new vector that results from adding the corresponding components of the original vectors.

That is, to add two vectors, they must have the same number of components and be of the same dimension.

Based on the triangle method of vector addition, the result or sum of two vectors is obtained by drawing the vectors head to tail.

From the diagram, the vectors are drawn heat to tail, and the resultant vector must also start from the head of the last vector ending with its head pointing downwards.

Hence arrow C is the best vector diagram representing the sum of the vectors.

Learn more about sum of vectors here: https://brainly.com/question/2927458

#SPJ1


please solve this~
d²y 5. Show that y(x, t) = ym exp(i(kx ± wt)) is a solution of the wave equation dx² where vw/k. (10 pts) 1 d²y v² dt2¹

Answers

`y(x, t) = ym exp(i(kx ± wt))` is a solution of the wave equation where `v = w/k`.

Given the wave equation: `d²y/dx² = (1/v²) d²y/dt²`, it is required to show that `y(x, t) = ym exp(i(kx ± wt))` is a solution of the wave equation, where `v = w/k`.

The given function is `y(x, t) = ym exp(i(kx ± wt))`

Differentiating twice with respect to x we get:

`d²y/dx² = -k² ym exp(i(kx ± wt))`

Differentiating twice with respect to t we get:

`d²y/dt² = -w² ym exp(i(kx ± wt))`

Now, substituting the above derivatives in the wave equation, we get:`

d²y/dx² = (1/v²) d²y/dt²`⇒ `-k² ym exp(i(kx ± wt))

= (1/v²) (-w² ym exp(i(kx ± wt)))`

⇒ `k² = (w²/v²)`

⇒ `v = w/k`

Hence, `y(x, t) = ym exp(i(kx ± wt))` is a solution of the wave equation where `v = w/k`. Therefore, the above-mentioned equation satisfies the wave equation.

To learn more about  wave equation:

https://brainly.com/question/32018564

#SPJ11

You can sometimes find deep red crystal vase in antique stores, called uranium glass because their color was produced by doing the glass with a look up the role of and their half lives, and calculate the activity in Ba) of such a vese assuming it has 2.16 of uranium in R. Neglect the activity of any daughter is (Consider und in your calculation 1193.011 X B

Answers

The formula for calculating the activity of a radioactive substance is:A = λNwhere A is the activity, λ is the decay constant, and N is the number of radioactive nuclei.According to the problem statement, the vase contains 2.16 grams of uranium.

To calculate the number of radioactive nuclei, we need to use the following formula:N = nN/AMwhere N is Avogadro's number (6.022 × 1023), n is the number of atoms, A is the atomic weight, and M is the molar mass.To calculate the number of atoms, we need to use the following formula:n = m/Mwhere m is the mass (2.16 g) and M is the molar mass of uranium (238.02891 g/mol).Substituting the values, we get:n = 2.16/238.02891n = 0.009091767 mol.

To calculate the number of radioactive nuclei:N = (0.009091767 mol × 6.022 × 1023)/238.02891N = 2.293 × 1020 radioactive nucleiTo calculate the decay constant, we need to use the following formula:λ = ln(2)/thalfwhere ln is the natural logarithm and thalf is the half-life of uranium. The half-life of uranium is 4.5 × 109 years. Substituting the values, we get:λ = ln(2)/(4.5 × 109 years)λ = 1.541 × 10-10 /yearTo calculate the activity, we need to use the formula:A = λNSubstituting the values, we get:A = (1.541 × 10-10 /year) × (2.293 × 1020 radioactive nuclei)A = 3.53 × 1010 BqTherefore, the activity of the vase is 3.53 × 1010 Bq.

To know more about uranium visit:

https://brainly.com/question/24285205

#SPJ11


PLEASE SOLVE.
Question 11 If gasoline has a density of 0.680 g/cm3, what is the volume of 5,075 g of gasoline?

Answers

the volume of 5,075 g of gasoline is approximately 7,467.65 milliliters.

To find the volume of gasoline, we can use the formula:

Volume = Mass / Density

Given:

Mass of gasoline = 5,075 g

Density of gasoline = 0.680 g/cm³

Plugging in the values into the formula:

Volume = 5,075 g / 0.680 g/cm³

Now, we need to make sure the units are consistent. The density is given in grams per cubic centimeter (g/cm³), so we need to convert the mass to grams.

Since 1 cm³ = 1 mL, we can say that 1 g/cm³ = 1 g/mL. Therefore, the volume will be in milliliters (mL).

Volume = 5,075 g / 0.680 g/mL

Now, let's calculate the volume:

Volume = 7,467.65 mL

To know more about gasoline visit:

brainly.com/question/14588017

#SPJ11

Suppose a small box of mass m is attached by a thin wire which goes through the top of a cone (angle θ with respect to the horizontal). A second mass M is attached to the end of the string (see Figure. The box slides without friction on the cone surface, moving in a circle or radius R. Write the equations you would need to find the speed v as the box moves in this circle. You do not need to combine or simplify or solve these equations.

Answers

1.mg = Tsinθ,2. Tcosθ = mv^2/R , 3. v 4. T = Mg + mgcosθ These equations can be used to determine the speed v of the box as it moves in the circle on the cone surface.

To find the speed v of the box as it moves in a circle on the cone surface, we can consider the forces acting on the box and apply Newton's laws of motion.

Let's analyze the forces acting on the box:

Tension force (T): The tension force in the string pulling the box towards the center of the circle.

Gravitational force (mg): The weight of the box acting vertically downwards.

Normal force (N): The normal force exerted by the cone surface on the box perpendicular to the surface.

We can decompose the gravitational force into two components:

mgcosθ: The component of gravitational force parallel to the cone surface.

mgsinθ: The component of gravitational force perpendicular to the cone surface.

Considering the circular motion, there are two acceleration components:

Centripetal acceleration (ac): The acceleration directed towards the center of the circle.

Tangential acceleration (at): The acceleration along the tangent to the circle.

Now, we can write the equations of motion for the box:

In the vertical direction:

Sum of forces in the vertical direction = ma (acceleration in the vertical direction is zero)

N - mgcosθ = 0 (Equation 1)

In the horizontal direction:

Sum of forces in the horizontal direction = ma (acceleration in the horizontal direction is the centripetal acceleration ac)

T - mgsinθ = mac (Equation 2)

Tangential acceleration:

The tangential acceleration is related to the angular speed (ω) and the radius (R) of the circle:

at = R * dω/dt = R * α (where α is the angular acceleration)

Angular acceleration:

The angular acceleration can be related to the tangential acceleration:

α = at / R

Relationship between tangential acceleration and centripetal acceleration:

Since ac = R * α, we have:

ac = at / R

Velocity:

The velocity v can be related to the angular speed ω and the radius R:

v = R * ω

These equations represent the forces and motion of the box as it moves in a circle on the cone surface. They can be used to analyze and solve for the speed v by combining and simplifying them.

To learn more about  surface

https://brainly.com/question/31205886

#SPJ11

A 3-phase induction motor has a 4-pole star-connected stator winding and runs on a 220V, 50Hz supply. The rotor resistance is 0.1Ω per phase and rotor resistance is 0.9Ω. The ratio of stator to rotor turns is 1.75. The full-load slip is 5%. Calculate (i) the full-load torque (ii) the maximum torque (iii) the speed at maximum torque.

Answers

the full-load torque of the motor is 8.11 Nm, the maximum torque is 8.77 Nm, and the speed at maximum torque is 1413 rpm.

Given data:

Stator winding of the induction motor is star connected

No. of poles, P = 4 Supply voltage, V = 220V Frequency of supply, f = 50 Hz

Rotor resistance/phase, R₂' = 0.1 Ω

Rotor reactance/phase, X₂' = 0.9 Ω

Stator turns/rotor turn, N₁/N₂ = 1.75Full load slip, s = 5% = 0.05(i) Full Load Torque:

Starting torque of 3-phase induction motor is given by,

Tst = (3V² / 2πf) * (R₂' / (R₂'² + X₂'²)) * (s / (N₁ / N₂))

Substituting values, Tst = (3 x 220² / 2 x 3.14 x 50) x (0.1 / (0.1² + 0.9²)) x (0.05 / 1.75) = 8.11 Nm

(ii) Maximum Torque:

At the point of maximum torque, the rotor resistance should be equal to the rotor reactance.

R₂' = X₂'

Then the total rotor impedance will be equal to the rotor resistance.

R₂ = R₂' = X₂' = 0.9 ΩAt the maximum torque, the slip is, s_max = (R₂' / (R₂' + R₂)) * (N₁ / N₂)

s_max = (0.1 / (0.1 + 0.9)) * (1 / 1.75)

s_max = 0.0514 or 5.14%(iii) Speed at Maximum Torque:

The speed at maximum torque can be calculated as, N_max = (1 - s_max) * (f * 60 / P)

N_max = (1 - 0.0514) * (50 x 60 / 4) = 1413 rpm

Hence, the full-load torque of the motor is 8.11 Nm, the maximum torque is 8.77 Nm, and the speed at maximum torque is 1413 rpm.

learn more about torque here

https://brainly.com/question/17512177

#SPJ11

3. [-/10 Points] A chemical reaction transfers 6250 J of thermal energy into 11.0 moles of an ideal gas while the system expands by 2.00 x 10-² HINT (a) Find the change in the internal energy (in )). J (b) Calculate the change in temperature of the gas (in K). K Need Help? Road It 4. [-/10 Points] A gas is compressed at a constant pressure of 0.800 atm from 9.00 L to 2.00 L. In the process, 420 J of energy leaves the gas by heat. (a) What is the work done on the gas? 3 (b) What is the change in its internal energy? Need Help? Read It Watch It 3 m at a constant pressure of 1.25 x 10° Pa.

Answers

(a) The change in internal energy of the gas is -6250 J.

(b) The change in temperature of the gas is -568.18 K.

(a) To find the change in internal energy, we can use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system. In this case, the chemical reaction transfers 6250 J of thermal energy into the gas, so the heat added to the system is 6250 J.

Since the system expands, no work is done on the surroundings, so the work done by the system is 0 J. Therefore, the change in internal energy is equal to the heat added, which is -6250 J.

(b) To calculate the change in temperature, we can use the ideal gas law, which states that the pressure times the volume of a gas is equal to the number of moles of the gas times the gas constant times the temperature. We can rearrange this equation to solve for the change in temperature. Given that the pressure is constant, we have:

P1 * V1 = n * R * T1

P2 * V2 = n * R * T2

Dividing the second equation by the first equation, we get:

(P2 * V2) / (P1 * V1) = T2 / T1

Plugging in the given values, we have:

(0.800 atm * 2.00 L) / (1.25 x 10⁵ Pa * 9.00 L) = T2 / T1

Solving for T2, we find:

T2 = (0.800 atm * 2.00 L * T1) / (1.25 x 10⁵ Pa * 9.00 L)

Substituting the given value of T1, we can calculate T2, which is approximately -568.18 K.

Learn more about Temperature

brainly.com/question/7510619

#SPJ11

Find the voltage gain of the amplifier in Figure 1 by
measuring the peak amplitude of the input and output
voltages. Calculate the voltage gain as the ratio between
them.

Answers

Voltage gain is an essential concept of electronic circuit amplifiers. It is defined as the ratio of the amplifier's output voltage to its input voltage. It is an important parameter of the amplifier, which specifies how much the amplifier can amplify the input signal's voltage level to produce the output signal. It is measured in decibels (dB) or as a ratio.

The voltage gain of the amplifier in Figure 1 can be determined by measuring the peak amplitude of the input and output voltages. The voltage gain can be calculated by the 'between the output voltage and the input voltage.

The voltage gain formula is given as,

Voltage Gain = Output Voltage/Input Voltage

To calculate the voltage gain, let us first measure the peak amplitude of the input and output voltages. Let us assume that the peak amplitude of the input voltage is 2V, and the peak amplitude of the output voltage is 12V.

The voltage gain of the amplifier can be calculated using the above formula,

Voltage Gain = 12V/2V

Voltage Gain = 6

Therefore, the voltage gain of the amplifier in Figure 1 is 6.

To know more about circuit visit-

https://brainly.com/question/12608516

#SPJ11

Calculate the current produced if a 12-volt battery supplies 6 watts of power

Answers

The current produced by a 12-volt battery supplying 6 watts of power is 0.5 amperes.

To calculate the current produced by a 12-volt battery supplying 6 watts of power, we can use the formula:

current = power / voltage

Substituting the given values:

current = 6 watts / 12 volts

Simplifying the expression:

current = 0.5 amperes

Therefore, the current produced by the battery is 0.5 amperes.

Learn more:

About calculate here:

https://brainly.com/question/12633131

#SPJ11

The current produced by a 12-volt battery supplying 6 watts of power is 0.5 amperes.

To calculate the current produced by a 12-volt battery supplying 6 watts of power, you can use Ohm's Law, which states that the current (I) is equal to the power (P) divided by the voltage (V):

I = P / V

Substituting the given values:

P = 6 watts

V = 12 volts

I = 6 watts / 12 volts

I = 0.5 amperes (A)

Therefore, the current produced by the 12-volt battery supplying 6 watts of power is 0.5 amperes.

To know more about Ohm's Law refer here

https://brainly.com/question/1247379#

#SPJ11

A 76 kg window cleaner uses a 9.5 kg ladder that is 6.8 m long. He places one end on the ground 4.4 m from a wall, rests the upper end against a cracked window, and climbs the ladder. He is 5.4 m up along the ladder when the window breaks. Neglect friction between the ladder and window and assume that the base of the ladder does not slip. When the window is on the verge of breaking, what are (a)the magnitude of the force on the window from the ladder, (b) the magnitude of the force on the ladder from the ground, and (c) the angle (relative to the horizontal) of that force on the ladder?

Answers

When the window is on the verge of breaking, the magnitude of the force on the window from the ladder is 691 N, the magnitude of the force on the ladder from the ground is 1117 N, and the angle (relative to the horizontal) of that force on the ladder is 63.5°.

Given,

The mass of the window cleaner = 76 kg

The mass of the ladder = 9.5 kg

The length of the ladder = 6.8 m

The distance between the wall and the ladder = 4.4 m

The height at which the window cleaner is when the window breaks = is 5.4 m

Assumptions made:

The base of the ladder does not slip. Neglect friction between the ladder and window.

Part (a):

The magnitude of the force on the window from the ladder

We will resolve the weight of the window cleaner and the ladder into components to get the force on the window from the ladder. Draw a free-body diagram of the window cleaner and the ladder. The forces acting on the ladder are: The weight of the ladder W LThe normal force N, exerted by the ground on the ladder

The force F, exerted by the wall on the ladder

The forces acting on the window cleaner are:

The weight of the window cleaner W C

The force exerted by the ladder on the window cleaner F CW L = 9.5 × 9.8 = 93.1 NW C = 76 × 9.8 = 745 N

The ladder is in equilibrium in the horizontal direction. Thus,

F = 0

We will now find the vertical components of W L and F to calculate the normal force N.

The angle made by the ladder with the horizontal is tan⁻¹(5.4/4.4) = 51.3°

The vertical component of W L = 93.1 × cos 51.3° = 60 N

The vertical component of F = F × sin 51.3°N = N + 60N = 0 + 60N = 60 N

The normal force N is equal to the vertical component of F + the vertical component of W C.N = 60 + 745 = 805 N

The force exerted by the ladder on the window cleaner F C = 745 N

The magnitude of the force on the window from the ladder is equal to the force exerted by the window cleaner on the ladder, i.e., 745 N.

Part (b): Magnitude of the force on the ladder from the ground

Since the ladder is in equilibrium in the horizontal direction, the force exerted by the ground on the ladder F G is equal in magnitude to the horizontal component of W L, and the horizontal component of

F.F G = W L × sin 51.3°F G

= 93.1 × sin 51.3°

= 70 N

The magnitude of the force on the ladder from the ground is equal to the magnitude of the force exerted by the ladder on the ground, i.e., 70 N.

Part (c): Angle (relative to the horizontal) of the force on the ladder

Draw the free-body diagram of the ladder once again. The forces acting on the ladder are:

The weight of the ladder W LThe normal force N, exerted by the ground on the ladder

The force F, exerted by the wall on the ladder

The force exerted by the ground on the ladder F G

We know that the ladder is in equilibrium in the horizontal direction. Thus, F G + F = 0⇒ F = -70 N

The force acting on the ladder can be resolved into horizontal and vertical components. The horizontal component of F is 0. The vertical component of F is

F sin θ = N - W L sin 51.3°

F sin θ = 0 - 93.1 × sin 51.3°

F sin θ = - 70

sin θ = -70/-691

sin θ = 0.101θ = sin⁻¹0.101 = 5.76°

Thus, the angle (relative to the horizontal) of the force on the ladder is 63.5°.

To learn more about distance:

https://brainly.com/question/26550516

#SPJ11

1.2 A 7,5 kW, 230 V-shunt motor has a full-load speed of 1 200 r/min. The resistance of the armature and field circuits are 0, 3 ohm and 180 ohms, respectively. The full-load efficiency of the motor is 86 per cent. Ignore the effect of armature reaction. Calculate the following: 1.2.1 The speed at which the motor will run on no-load, if the total no- load input is 600 W (9) 1.2.2 a The value of a resistance to be added in the armature circuit to reduce the speed to 1 000 r/min when giving full-load torque. Assume that the flux is proportional to the field current (5) [18]

Answers

The speed at which the motor will run on no-load can be determined by using the concept of the motor's input and output power.
Given:
Full-load power (output power) = 7.5 kW
Full-load efficiency = 86% = 0.86
Total no-load input power = 600 W
First, we can calculate the full-load input power using the efficiency formula:
Full-load input power = Full-load power / Full-load efficiency
Full-load input power = 7.5 kW / 0.86 = 8.72 kW

Now, we can determine the ratio of the no-load input power to the full-load input power:
Power ratio = Total no-load input power / Full-load input power
Power ratio = 600 W / 8.72 kW = 0.0688
Since power is directly proportional to the speed of the motor, we ca
calculate the speed on no-load using the power ratio
No-load speed = Full-load speed * √(Power ratio)
No-load speed = 1,200 r/min * √(0.0688) ≈ 292.78 r/min
Therefore, the motor will run at approximately 292.78 r/min on no-load.
1.2.2 To reduce the speed to 1,000 r/min when giving full-load torque, we need to add a resistance in the armature circuit. The speed of the motor is inversely proportional to the armature circuit resistance.
Given:
Full-load speed = 1,200 r/min
Target speed = 1,000 r/min
Using the speed ratio formula:
Speed ratio = Full-load speed / Target speed
Speed ratio = 1,200 r/min / 1,000 r/min = 1.2
Since the speed is inversely proportional to the resistance, we can calculate the resistance ratio:
Resistance ratio = 1 / Speed ratio
Resistance ratio = 1 / 1.2 ≈ 0.833
Now, we can calculate the required resistance to be added in the armature circuit:
Required resistance = Armature circuit resistance * Resistance ratio
Required resistance = 0.3 ohm * 0.833 ≈ 0.25 ohm
Therefore, a resistance of approximately 0.25 ohm needs to be added in the armature circuit to reduce the speed to 1,000 r/min when giving full-load torque, assuming the flux is proportional to the field current.

To learn more about, Speed, click here, https://brainly.com/question/28224010

#SPJ11

Other Questions
Step 1: Create the following files Employee1.txt andEmployee2.txt using "," (comma) as delimiter :Employee1.txt Employee2.txt333, John 123, Sales, 5000456, Mathew 333, Analyst, 4000779, Smith one of the best tax advantaged ways to save for retirement if you are in your 20s and your employer does not offer a retirement plan is to: group of answer choices Beginning at the lumen, the sequence of layers of the digestive tract wall is A. submucosa, mucosa, serous membrane, muscularis. B. muscularis, lamina propria, submucosa, mucosa. C. mucosa, submucosa, muscularis, serosa. D. peritoneum, submucosa, mucosa, lamina propria. E. submucosa, mucosa, adventitia, muscularis. construct a parallelogram in which the adjacent sides are 4cm and 3cm and included angles is 60 degree the least squares method for determining the best fit minimizes Based on the article, what does art history mean to you? Why does it matter?Watch the famous "Museum scene" from the film Black Panther with Newark native actor Michael B. Jordan. What do you think of this scene? Based on the Guardian article linked below, what role do you think museums like the British Museum play in commodifying art historically? Some scholars and lawyers have claimed that museums like the British Museum are guilty of looting and profiting by displaying goods stolen from former colonies. After reading the Guardian article and watching the Black Panther clip, discuss whether you agree or disagree. Who do you think should control historical works of art? What about the workers who created these works? information about ingredients, hazards and sage work practices of cement and concrete products can be found Conical Pendulum Puntos:5 onsider the depicted conical pendulum: a mass m on the end of a string of length L, which is fixed to the celling. Given the proper push, this pendulum can swing with an angular velocity in a circle at an angle with respect to the vertical, maintaining the same height, throughout its motion. Different positions of the mass are indicated by North, West, South, East (N, W, S, E). What is the net force on the mass when it is in the North position, expressed in terms of the sum of all forces acting on the mass? Use "g" for the gravitational acceleration, "a" for the angle ,T for the tension on the string, and "o" for the angular velocity w. F x= iF ix=F y= iF iy=F z= iF iz=Tries 2/10 Intentos Anteriores What is the net force on the mass when it is in the North position, expressed in terms of the centripetal force? F x=ma x=F y=ma y=F z=ma z=1Based on Tries 0/10what is the tension on the cable in terms of the angle a ? T()= Tries 0/10 What is the anqular velocity squared in terms of the angle ? 2()= Tries 0/10 If the mass is 10.2ka. the angle 39 degrees, and the length of the cable 2 meters, what is the linear speed of the ball? Tries 0/10 In JavaProgram 2: Make a simple program that counts infected computers on a computer network. The iirus spreads through the network, and every computer that is connected to an infected, computer is infected. Assume Nile.com began June with 14 units of inventory that cost a total of $210. During June, Nile.com purchased and sold goods as follows:June 8 - Purchase 42 units at $16June 14 - Sale 35 units at $32June 22 - Purchase 28 units at $18June 27 - Sale 42 units at $32Suppose Nile.com used the weighted-average inventory costing method and the perpetual inventory system. Compute the weighted-average unit cost of the company's inventory on hand on June 8. Round the weighted-average unit cost to the nearest cent.A) $17.00B) $15.50C) $15.75D) Cannot be determinedDo not copy from Chegg and give complete answer with explanation indefinite integral using the substitutionx=2tan(). (Use c for the constant or integration.2x4+x2dxLARCALC128.4.014.MIFind the indefinite integral by using the substitutionx=2tan(). (Use C for the constant of integration.)(4+x2)22x2dx what is the key question behind civil rights protection? ObjectivesExplain the significance of motivation in influencing organizational behaviour.Employ needs and process theories to stimulate employee performance.BackgroundMotivational theories seek to explain how employers can garner the most productivity from their workforce. Businesses will try to assess their corporate cultures, and attempt to develop strategies for motivation that will be meaningful. The strategies used may vary from extrinsic (financial, compensation, etc.) to intrinsic (promotion of feelings of self-worth, etc.). As a member of the workforce, it is important for you to understand what motivates you. Describe two features found in an erosional beach, includingtheir appearance and formation. Describe two features found in adepositional beach, including their appearance and formation. Nameone pla If you have been around the HR profession for a while, perhaps you have noticed that we are seeing a lot more people with the title of Chief HR Officer (CHRO) than ever before. I was curious to better understand what was driving this and launched a research project to examine this phenomenon. Could it be that HR finally has a seat at the strategic decisionmaking table in the organisation - or is this just a cool title? Do CEOs now finally recognise the value of HR Management? Are these CHROs making an impact? And what does all this mean for future CHROs ? The profession has come a long way and CEOs are looking for help with human capital now more than ever - it is a good time to be in HR! Considering the above, critically discuss the importance of HR having "a seat at the strategic decision-making table in the organisation." a) Give an algebraic equation for the zenith angle of an astronomical object like the sun, in terms of its equatorial coordinates, its hour angle and the latitude of the observer. Define all symbols that you use.b) The giant elliptical galaxy M87 is centred at RA=12h30m49.4234s, Dec=+12d23m28.044s (equinox J2000 coordinates). Hence work out how far south in latitude the centre of M87 can be observed. Give three reasons why we would not choose to observe M87 from such a location.c) The Isaac Newton Telescope is located at longitude = 17 52' 39.5" west and latitude = 28 45' 43.4" north. Evaluate, with reasoning, what time of year the galaxy M87 is highest in the sky at local midnight. What is its zenith angle, when observed from the INT at that time? Consider the following system.A panel of solar cellsa)Describe the RELEVANT energy levels in one of its functions and its quantum origins. Your responses should be elaborate but punctual, as soon as possible.b) What considerations are necessary to describe the system you chose using partition functions? 10 x 32.8 ft wall is composed from a. 8 in Brick, fired clay b. 1.5 in air gap with 0 and 10 F mean temperature and temperature difference respectively c. Concrete block, Lightweight aggregate., 16-17 lb, 85-87 lb/ft d. Gypsum or plaster board e. Still out door air f. Still indoor air The wall has / in double glaze 20 X 8 in window without thermal break and 80 x 32 x 1 3/4 in Solid core flush door (none storming) Find the overall heat transfer coefficient (U) for the combination considering parallel heat transfer mood. Find the critical points of the function (x,y)=x2+y2+4x8y+5.f(x,y)=x2+y2+4x8y+5. List your answers as points in the form (,)(a,b). a key organizational requirement for participation in decision making includes: