Answer:
A.
Explanation:
Find the hot resistance of a light bulb rated 70W, 120V.
Answer:
The hot resistance of a light bulb is 205.714 ohms.
Explanation:
Hot resistance can be found by using Ohm's Law and definition of power, whose expression as a function of power and voltage is:
[tex]R = \frac{V^{2}}{\dot W}[/tex]
Where:
[tex]\dot W[/tex] - Power, measured in Watts.
[tex]V[/tex] - Voltage, measured in Volts.
[tex]R[/tex] - Resistance, measured in Ohms.
Given that [tex]V = 120\,V[/tex] and [tex]\dot W = 70\,W[/tex], we find that hot resistance is:
[tex]R = \frac{(120\,V)^{2}}{70\,W}[/tex]
[tex]R = 205.714\,\Omega[/tex]
The hot resistance of a light bulb is 205.714 ohms.
Which sentence best compares LCDs with CRTs
Answer:
LCDs consume less power than CRTs
Explanation:
The sentence that best compares LCDs with CRTs is that "LCDs consume less power than CRTs".
Recently, in many homes and offices, cathode ray tube (CRT) monitors are being replaced by liquid crystal display (LCD) monitors. There are some benefits that LCD panels offer over CRT monitors. Some of them are:
LCD monitors don't usually take up much space. They take less space than CRT monitors. Also, LCDs consume less power than CRT monitors. Which means that CRTs consume more power than LCDs. LCD monitors gives a much brighter image than CRT monitors .
When under a deep vacuum the motor winding of a hermetic refrigeration compressor: ______.
a. will be damaged if energized.
b. must be kept warm to operate properly.
c. will be protected by its insulation.
Answer:
a. will be damaged if energized
Explanation:
A hermetic compressor needs a coolant to prevent overheating of the motor. The cooling of the compressor depends on the flow of the refrigerant through the compressor hence when under a deep vacuum, the motor winding of a hermetic compressor can overheat.
A crankcase heater is used to prevent the mixing of refrigerant and oil at low temperatures. The mixing of refrigerant and oil can cause oil foaming in the vacuum. When under a deep vacuum, the motor winding of a hermetic compressor can overheat if the crankcase heater is energized.
Q.4 In a reheat Rankine-cycle power plant, a concentrator solar plant (CSP) system gives steam at 5 MPa and 4000C. After expansion in the high-pressure turbine to 600 kPa, the steam is reheated again to 4000C and expands again in the low-pressure turbine to a pressure of 10 kPa in a dry, saturated steam condition. If the steam leaves the condenser as a saturated liquid and the pump and high-pressure turbine efficiency is 85%, determine the efficiency of a low-pressure turbine, the work output of the two turbines, the work input to the pump per unit mass of the fluid, the heat added by the CSP system, and the cycle efficiency. If the solar radiation is 900 W/m2 and the CSP system operates at 40% efficiency, how many square meters of collectors are required if the steam flow rate is 1 kg/s.
Answer:
Efficiency of low pressure Turbine ( [tex]n_{lp}[/tex] ) = 82.9%
Square meters ( Area of collectors ) = 9705.2 m^2
Explanation:
Given data :
T1 = 400⁰c
p1 = 5 Mpa
p2 = 600 kpa
p3 = 600 kpa
p4 = 10 kpa
high pressure turbine efficiency = 85%
solar radiation = 900 w/m^2
Csp efficiency = 40%
A) calculate the efficiency of a low-pressure turbine
E ) Determine the area of the collectors
attached below is a detailed solution of the given problem
How to find the voltage(B Aab) in series parallel circuit?
Answer:
Vab ≈ 3.426 V
Explanation:
First of all, it is convenient to find the equivalent parallel resistance of R5 and R6. That will be ...
R56 = (R5)(R6)/(R5 +R6) = (1000)(1500)/(1000 +1500) = 600
Then we can call V1 the voltage at the top of R2. The voltage at Va is a divider from V1:
Va = V1·(R4/(R3+R4)) = V1(560/1030) ≈ 0.543689V1
The voltage at Vb is also a divider from V1:
Vb = V1·(R7+R8)/(R2 +R56 +R7 +R8) = V1(780/1710) ≈ 0.456140V1
The parallel branches containing Va and Vb have an effective resistance of ...
(1030)(1710)/(1030+1710) = 642.81
That forms a divider with R1 to give V1:
V1 = (100 V)642.81/(1000 +642.81) ≈ 39.1287 V
The difference Va-Vb is ...
Vab = (39.1287 V)(0.543689 -0.456140) ≈ 3.426 V
_____
We have done this using parallel resistance and voltage divider calculations. You can also do it using node voltage equations. Using the same definition for V1 as above, we have ...
(Vs -V1)/R1 +(Vb -V1)/(R56+R2) +(Va-V1)/R3 = 0
(V1 -Vb)/(R56 +R2) -Vb/(R7+R8) = 0
(V1 -Va)/R3 -Va/R4 = 0
The solution of interest is the value of Vab, shown in the attachment. It computes as 154200/45013 V ≈ 3.42568 V.
According to the article "Edward R. Murrow: Inventing Broadcast Journalism," how did Murrow perceive the threat of Adolf Hitler?
a. Murrow was cautious towards Hitler, unwilling to ruffle the "powers that be."
b. Murrow did not know Hitler personally, and refused to comment on his politics.
c. Murrow downplayed Hitler's threat, reasoning that Germany was 4,000 miles away
d. To Murrow, Hitler was a threat to all of civilization
Answer:
d. To Murrow, Hitler was a threat to all of civilization
Explanation:
For Murrow, Hitler's rise was a serious problem and a major threat to the entire civilization. For this reason, he believed that covering news about Hitler's advance and the battles of Nazi Germany was essential, even if the American population did not see Hitler as a threat and the European population, believed that these reprotations were only a way to denigrate the image of the continent to the world.
For Murrow reporting on Hitler's actions was as important as reporting on natural disasters.
If the driver gear has 10 teeth and is moving at 10 RPMs (revolutions per minute), at what speed would the driven gear move if it has 20 teeth?
Answer:
5 rpm
Explanation:
Each turn of the driver gear moves 10 teeth past the point of engagement with the driven gear. That is half of the 20 teeth on the driven gear, so it makes 1/2 turn for each turn of the driver.
In 1 minute, the driver makes 10 turns, so the driven gear makes 5 turns. Its speed is 5 rpm.
simple power system consists of a dc generator connected to a load center via a transmission line. The load power is 100 kW. The transmission line is 100 km copper wire of 3 cm diameter. If the voltage at the load side is 400 V, compute the following: a. Voltage drop across the line Vline b. Voltage at the source side Vsource c. Percentage of the voltage drop Vline /Vsource d. Line losses e. Power delivered by the source f. System efficiency
Answer:
A. ) 591.7 v
B.) 991.7v
C.) 59.7%
D.) 47.9 Kw
E.) 247925 W
F.) 59.7 %
Explanation:
Given that a simple power system consists of a dc generator connected to a load center via a transmission line. The load power is 100 kW. The transmission line is 100 km copper wire of 3 cm diameter. If the voltage at the load side is 400 V,
Let first calculate the resistance in the wire.
The resistivity (rho) of a copper wire is 1.673×10^-8 ohm metres
Resistance R =( L× rho)/A
Where Area = πr^2 = π × 0.015^2
Area = 0.00071 m^2
R = (100000 × 1.673×10^-8) / 0.00071
Resistance in wire = 2.367 ohms
Then let calculate the resistance in the load.
Also, since Power P = V^2 /R
Make R the subject of formula
R = V^2/ P
R = 400^2/100000
Resistance in load = 1.6 Ohms
Current l = V / R
I = 400/1.6 = 250 Ampere
a.) Voltage drop across the line V line will be achieved by using Ohms law.
V = I R
V = 250 × 2.367
V = 591.7 v
B.) Voltage at the source side Vsource will be
V = V line + V load
V = 400 + 591.7
V = 991.7 v
C.) Percentage of the voltage drop Vline /Vsource
591.7/991.7 × 100 = 59.7%
D.) Line losses
P = I V
P = 250 × 591.7
P = 147925 W
Power loss = 147925 - 100000
Power loss = 47,925 W
Power loss = 47.9 Kw
E.) Power delivered by the source
P = IV
P = 250 × 991.7 = 247925 W
F.) System efficiency
Efficiency = power line / power source × 100
Efficiency = 147925 / 247925 × 100
Efficiency = 59.7 %
In this exercise we have to use the circuit knowledge of an electrical system and calculate the characteristics so we have to:
A. ) 591.7 v
B.) 991.7v
C.) 59.7%
D.) 47.9 Kw
E.) 247925 W
F.) 59.7 %
Organizing the information given in the statement we have that:
power is 100 kW.line is 100 km 3 cm diametervoltage at the load side is 400 VThe resistivity is 1.673×10^-8 ohm metresCalculating the resistivity we find that:
[tex]R =( L* \rho)/A\\A= \pi r^2 = 0.00071 m^2\\R = (100000 * 1.673*10^{-8}) / 0.00071\\R = 2.367 ohms[/tex]
Then it becomes simpler to calculate the power and current, we have:
[tex]P = V^2 /R= 1.6 Ohms\\l = V / R = 250 Ampere[/tex]A) With the above information, we can calculate the voltage as:
[tex]V = I R\\V = 250 * 2.367\\V = 591.7 v[/tex]
B) Now calculating the source voltage, we find that:
[tex]V = V line + V load\\V = 400 + 591.7\\V = 991.7 v[/tex]
C.) The percentage will be calculated as the division of the two previous values, like:
[tex]591.7/991.7 * 100 = 59.7\%[/tex]
D.) Like any imperfect circuit, losses occur, so the loss will be calculated as:
[tex]Power loss = 147925 - 100000\\Power loss = 47,925 W\\Power loss = 47.9 Kw[/tex]
E.) Power delivered by the source, can be:
[tex]P = IV\\P = 250 * 991.7 = 247925 W[/tex]
F.) System efficiency, will be:
[tex]Efficiency = power line / power source *100\\Efficiency = 147925 / 247925 * 100\\Efficiency = 59.7 \%[/tex]
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which option identifies the AFNR pathway in the following scenarios? Jalal works for a prestigious golf course that hosts an annual PGA Tour event. His employers depend on him to use cutting-edge science and technology to prepare the course and maintain it with the utmost care.
A. Agricultural System
B. Plant System
C. Biotechnology System
D. Natural Resource System
Answer: C. Biotechnology system
Explanation:
Please help I need by today !!
What is the purpose of an engineering notebook ?
What is the purpose of a portfolio?
Consider a 1.5-m-high and 2.4-m-wide double-pane window consisting of two 3-mm-thick layers of glass (k = 0.78 W/m⋅K) separated by a 12-mm-wide stagnant airspace (k = 0.026 W/m⋅K). Determine the steady rate of heat transfer through this double-pane window and the temperature of its inner surface for a day during which the room is maintained at 20°C while the temperature of the outdoors is −5°C. Take the convection heat transfer coefficients on the inner and outer surfaces of the window to be h1 = 10 W/m2⋅K and h2 = 25 W/m2⋅K, respectively, and disregard any heat transfer by radiation.
Answer:
The answer is below
Explanation:
Given:
kg (glass) = 0.78 W/m⋅K, ka (air) = 0.026 W/m⋅K, h1 = 10 W/m2⋅K, h2 = 25 W/m2⋅K, glass length = Lg = 3 mm = 0.003 m, Lo = 3 mm = 0.003 m, La = 12 mm = 0.012 Height = 1.5 m, width = 2.4 m, room temperature = T = 20°C. Therefore:
Total resistance per unit area is given as:
[tex]R"=\frac{1}{h_1}+\frac{L_g}{k_g}+\frac{L_a}{k_a} +\frac{L_o}{k_g}+\frac{1}{h_2} \\\\R"=\frac{1}{10}+\frac{0.003}{0.78}+\frac{0.012}{0.026} +\frac{0.003}{0.78}+\frac{1}{25} \\\\R"=0.1+0.00385+0.46154+0.00385+0.04\\\\R"=0.60924\ K.m^2/W[/tex]
Area = A = height * width = 1.5 m × 2.4 m = 3.6 m²
The change in temperature = ΔT = 20 °C - (-5 °C) = 25 °C
The rate of heat loss is given as:
[tex]\dot {Q}=A*\frac{\Delta T}{R"}= 3.6*\frac{25}{0.60924}\\ \\\dot {Q}=147.73\ W[/tex]
The inner surface temperature (Ti) is given as:
[tex]T_i=T-\frac{\dot {Q}}{A} *\frac{1}{h_1}\\ \\T_i=20-\frac{147.73}{3.6}*\frac{1}{10}=15.9\ ^oC[/tex]
The current through a 10-mH inductor is 10e−t∕2 A. Find the voltage and the power at t = 8 s.
Answer:
voltage = -0.01116V
power = -0.0249W
Explanation:
The voltage v(t) across an inductor is given by;
v(t) = L[tex]\frac{di(t)}{dt}[/tex] -----------(i)
Where;
L = inductance of the inductor
i(t) = current through the inductor at a given time
t = time for the flow of current
From the question:
i(t) = [tex]10e^{-t/2}[/tex]A
L = 10mH = 10 x 10⁻³H
Substitute these values into equation (i) as follows;
v(t) = [tex](10*10^{-3})\frac{d(10e^{-t/2})}{dt}[/tex]
Solve the differential
v(t) = [tex](10*10^{-3})\frac{-1*10}{2} (e^{-t/2})[/tex]
v(t) = -0.05 [tex]e^{-t/2}[/tex]
At t = 8s
v(t) = v(8) = -0.05 [tex]e^{-8/2}[/tex]
v(t) = v(8) = -0.05 [tex]e^{-4}[/tex]
v(t) = -0.05 x 0.223
v(t) = -0.01116V
(b) To get the power, we use the following relation:
p(t) = i(t) x v(t)
Power at t = 8
p(8) = i(8) x v(8)
i(8) = i(t = 8) = [tex]10e^{-8/2}[/tex]
i(8) = [tex]10e^{-4}[/tex]
i(8) = 10 x 0.223
i(8) = 2.23
Therefore,
p(8) = 2.23 x -0.01116
p(8) = -0.0249W
Answer:
The voltage is - 0.9158 mV
The power is - 0.1677 mW
Explanation:
Given;
current through the inductor, i(t) = [tex]10e^{-t/2}[/tex] -----equation (1)
inductance, L = 10 mH
given time, t = 8 s
The voltage across the inductor is given by;
[tex]V_L = L\frac{di}{dt} \\\\V_L = (10 *10^{-3})\frac{d}{dt} (10e^{-t/2})\\\\V_L = (10 *10^{-3})\frac{10}{-2}(e^{-t/2})\\\\ V_L = -0.05e^{-t/2} \ ----equation (2)[/tex]
when t = 8 s, the voltage will be ;
[tex]V_L = -0.05 e^{-t/2}\\\\V_L = -0.05 e^{-8/2}\\\\V_L = -0.05 e^{-4}\\\\V_L = -9.158 *10^{-4} \ V\\\\V_L = -0.9158 \ mV[/tex]
Power is given by;
P = I V
When t = 8, the current "I" is given by;
[tex]i(t) = 10e^{-t/2}\\\\i(8) = 10e^{-8/2}\\\\I = 10e^{-4}\\\\I = 0.1832 \ A[/tex]
P = 0.1832 x (-9.158 x 10⁻⁴)
P = -1.677 x 10⁻⁴ W
P = -0.1677 mW
In python code write a program that prompts the user to input two POSITIVE numbers — a dividend (numerator) and a divisor (denominator). Your program should then divide the numerator by the denominator, and display the quotient followed by the remainder.
Answer:
The python code for the given problem is written in explanation section.
Explanation:
The code for the given situation, in Python, can be written as follows:
x = int(input("Enter a positive number for dividend: "))
y = int(input("Enter a positive number for divisor: "))
quotient = x//y
remainder = x%y
print("The Quotient of the given calculation is:",quotient)
print("The Remainder of the given calculation is:",remainder)
An engineer is interested in the relative strength of machine parts made of two different metals. She measures the force required to break 200 parts made out of plastic, and 200 parts made out of aluminum. After conducting her measurements, she learned that a small number of the plastic parts may have had cracks in them before testing, which would have caused them to break at ridiculously low force levels. (There was no possibility of cracked aluminum parts.) Given the uncertainty about the number of cracked parts in her sample, what measure of central tendency would probably be the best to provide a fair comparison between the relative strengths of the two materials
Answer:
Median
Explanation:
Since the engineer is interested in the relative strength of machine parts made of two different metals. And after conducting her measurements, she learned that a small number of the plastic parts may have had cracks in them before testing, which would have caused them to break at ridiculously low force levels. Whereas, there was no possibility of cracked aluminum parts.
This small crack in the plastic part will affect the mean (average) value if it is used as a central tendency for comparison. This same thing will affect the mode and the range of the value of strength.
The best measure of central of tendency to use is median since the affected cracked part in the plastic is minimal.
Two points along a wire are labeled Xand Y. The current is measured to be iXY= –3A.The reference direction of iXY is defined by double-subscript notation. a. In which direction are electrons flowing? From X to Y, or from Y to X? b. How much charge (in coulombs) passes through a cross section of the wire in 5 seconds?
Answer:
a. From Y to X
b. q = 15 C
Explanation:
a.
When current is denoted by double subscript, it is interpreted as traveling from 1st subscript to the second, when the value of current is positive. On the other hand, if the value of current is negative, then it means that the current is traveling from 2nd subscript to the 1st subscript. Since, the value of current is negative in the given question, therefore, it means that the current is traveling from 2nd subscript to the 1st subscript. Hence the direction of current or the flow of electrons is:
From Y to X
b.
Using the following formula of current:
I = q/t
where,
I = Current (Absolute Value) = 3 A
q = amount of charge = ?
t = time taken = 5 s
Therefore,
3 A = q/5 s
q = (3 A)(5 s)
q = 15 C
A wastewater is to be disinfected using ultraviolet (UV) light. Batch experiments find that the bacterial concentration decays under UV light with first-order kinetics, with a half of the initial bacteria killed after 6.2 minutes of illumination. You need to design a reactor than can kill 99% of bacteria in a stream having a flow rate of 140, 000 gal/d. Assume that regardless of the reactor type it will be possible to have UV illumination conditions identical to those of the batch experiment. a. Based on the batch experiments, what is the first-order rate constant k for bacterial inactivation
Answer:
k = 0.1118 per min
Explanation:
Assume;
Initial number of bacteria = N0
Number of bacteria IN 'T' time = Nt
So,
[tex]Nt=N0e^{-kt}\\\\in\ 6.2 min\\\\\\frac{N0}{2}= N0e^{-k(6.2)}\\\\ln\frac{1}{2} = -k[6.2][/tex]
k = 0.1118 per min
Eleanore Rigby picks up the rice in the church after the wedding. Why she might she do this?
Explanation:
It gives her a sense of purpose.
A construction manager is looking for workers to build a series of walkways within a large garden apartment. What type of workmen should the manager employ?
Answer:
construction workers
Explanation:
A construction worker is usually someone with the technical skills and abilities needed to manually construct physical infrastructures.
Since a walkway is an infrastructure, hiring skilled construction workers should perform the project of building the series of walkways within the large garden apartment.
1. The only purpose of a personal fall arrest system is to
A) Keep workers from falling
B) Hoist materials
C) Avoid having to use a
net
D)All of the above
✅C) Avoid having to use a net ✅
IamSugarBee
does anyone know how i can make my LED lights be sticky again? they keep falling :/
Which unit is used, when specifying a vehicle's height, length and width?
Meters
Millimeters
Kilometres
Centimeters
Answer:
Centimeters
Explanation:
The interactive activities in this course
A. will be tested in lesson quizzes but not the final exam
B. will be tested in the final exam but not the lesson quizzes
C. will be scored by your instructor
D. will not be score
The interactive activities for the course will be scored by the instructor.
Interactive activities
Interactive classroom activities are defined as the activities or interactive sessions which is a two way communications or discussions where the students involved also participate in discussions and interacts with the teacher or the instructor.
In some school curriculars, the interactive activities are scored and in some it is not scored.For the particular course, the interactive sessions will be scored by the instructor.
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A high-speed steel tool is used to turn a steel work part with length = 350 mm and diameter = 70 mm. The parameters in the Taylor equation are n = 0.13 and C = 75 (m/min) for a feed of 0.4 mm/rev. The operator and machine tool rate = $36.00/hr, and the tooling cost per cutting edge = $4.25. It takes 5.0 min to load and unload the work part and 4.0 min to change tools. Determine the cutting speed for minimum cost.
Answer:
42.85 m/min
Explanation:
To save cost, the tools should not be changed frequently if the tool cost or tool change time is high
[tex]The\ operator\ and\ machine\ tool\ rate =C_o=\$36/hr=\frac{\$36}{1\ hr*\frac{60\ min}{1\ hr} } =\$0.6/min[/tex]
The tooling cost per cutting edge = [tex]C_t[/tex] = $4.25
n = 0.13, C=75 (m/min), tool change time = [tex]t_t=4\ min[/tex]
Therefore the cutting speed for minimum cost is given as:
[tex]v_{max}=\frac{C}{[\frac{C_o}{(\frac{1}{n}-1 )(C_o*t_t+c_t)} ]^n} \\\\Substituting:\\\\v_{max}=75{[\frac{0.6}{(\frac{1}{0.13}-1 )(0.6*4+4.25)} ]^{0.13}} \\\\v_{max}=42.85\ m/min[/tex]
he following is true for a Function Generator (select all that apply): Select one or more: a. It produces a variety of patterns of voltage in adjustable range of frequencies and amplitudes. b. Its main use is to provide input signals to circuits to test the response to known signals. c. It can deliver the set voltage level of the signal waveform to any load connected to its outputs without any attenuation. d. It can measure peak to peak voltage of sine waves. e. Some of common useful signal it can generate include sine, square, pulse, triangular, sawtooth waveforms.
Answer:
A,C and E
Explanation:
It should be understood that a function generator can be explained as a piece of electronic test equipment or software which is used in generating different types of electrical waveforms over a wide range of frequencies. It should be noted that some of the examples of waveforms produced by the function generator are the sine wave, square wave, triangular wave and sawtooth shapes.
Therefore, the reason why of picking the options as highlighted above.
The minimum fresh air requirement of a residential building is specified to be 0.35 air changes per hour (ASHRAE, Standard 62, 1989). That is, 35 percent of the entire air contained in a residence should be replaced by fresh outdoor air every hour. If the ventilation requirement of a 2.7-m-high, 200-m2 residence is to be met entirely by a fan, determine the flow capacity in L/min of the fan
Answer:
3150 L/min
Explanation:
The volume of the room is the product of the height of the room and its area. It is given as:
Volume (V) = height (h) × Area (A)
V = h × A
Height = 2.7 m, Area = 200 m². Hence:
V = h × A = 2.7 × 200 = 540 m³
The flow capacity ([tex]\dot {V}[/tex]) is given by
[tex]\dot {V}=ACH*Volume\ of\ room[/tex]
ACH = air changes per hour = 0.35
[tex]\dot {V}=ACH*Volume\ of\ room\\\\\dot {V}=0.35*540\\\\\dot {V}=189\ m^3/h[/tex]
But 1 m³ = 1000 L, 1 hr = 60 min
[tex]\dot{V}=189\ m^3/h=\frac{189\ m^3*\frac{1000\ L}{1\ m^3} }{1\ h*\frac{60\ min}{1\ h} } =3150\ L/min\\\\\dot{V}=3150 \ L/min[/tex]
A 55-μF capacitor has energy ω (t) = 10 cos2 377t J and consider a positive v(t). Determine the current through the capacitor.
Given :
Capacitor , C = 55 μF .
Energy is given by :
[tex]\omega(t)=10cos^2 (377t)\ J[/tex] .
To Find :
The current through the capacitor.
Solution :
Energy in capacitor is given by :
[tex]\omega=\dfrac{Cv^2}{2}\\\\v=\sqrt{\dfrac{2\omega}{C}}\\\\v=\sqrt{\dfrac{2\times 10cos^2 (377t)}{55\times 10^{-6}}}\\\\v=cos(337t)\sqrt{\dfrac{2\times 10}{55\times 10^{-6}}}\\\\v=603.02\ cos( 337t)[/tex]
Now , current i is given by :
[tex]i=C\dfrac{dv}{dt}\\\\i=C\dfrac{d[603.02cos(337t)]}{dt}\\\\i=-55\times 10^{-6}\times 603.03\times 337\times sin(337t)\\\\i=-11.18\ sin(337t)[/tex]
( differentiation of cos x is - sin x )
Therefore , the current through the capacitor is -11.18 sin ( 377t).
Hence , this is the required solution .
A part has been tested to have Sut = 530 MPa, f = 0.9, and a fully corrected Se = 210 MPa. The design requirements call for the part to be loaded at three different fully-reversed loads and cycled at each one for a set number of cycles. First, it will be loaded at ±350 MPa for 5,000 cycles. Then, it will be loaded at ±260 MPa for 50,000 cycles. Finally, it will be loaded at ±225 MPa until it fails. How many cycles do we expect the part to last at the final loading? Use Miner's method. :g
Answer:
126984 cycles
Explanation:
Given data :
Sut = 530 MPa
f = 0.9
fully corrected Se = 210 MPa
using Miner's method attached below is the detailed solution of the given problem
when loaded with ± 225 MPa the number of cycles before it fails will be
≈ 126984
3. Jack & Jill went up the hill to fetch a pail of water. At the well, Jill used a force
of 20.0 N to turn the crank handle of radius 0.400 m to rotate the axle of radius
0.100 m, so she could raise the 60.0 N bucket of water. A) What is the ideal
mechanical advantage of the wheel? B) What is the actual mechanical advantage
of the wheel? C) What is the efficiency of the wheel?
The ideal mechanical advantage, actual mechanical advantage and efficiency of the wheel are respectively; 4, 3 and 75%
What is the mechanical advantage?
We are given;
Radius of crank handle; r_c = 0.4 m
Radius of axle; r_a = 0.1 m
Load = 60 N
Effort = 20 N
A) Formula for ideal mechanical advantage is;
IMA = 2πr_c/2πr_a
IMA = 0.4/0.1
IMA = 4
B) Actual mechanical advantage is;
AMA = 60/20
AMA = 3
C) Efficiency is gotten from the formula;
Efficiency = AMA/IMA * 100%
Efficiency = (3/4) * 100%
Efficiency = 75%
Read more about Mechanical Advantage at; https://brainly.com/question/18345299
when were dresses made
Answer:
The world's oldest dress called the Tarkhan Dress is at 5,100 to 5,500 years of age.
Does that help? Or do you need something else? I can change my answer if this is not what you need! :D
Explanation:
Mild neurotoxins can cause which of these physical effects?