If 19.4 mL of a Ca(OH)₂ solution are needed to neutralize 31.5 mL of 0.1 M HC₂H302 solution, what is the concentration (molarity) of the
Ca(OH)₂ solution?
Select one:
O a. 0.009 M
O b. 1.6 M
OC 0.08 M
O d. 0.1 M

Answers

Answer 1

The concentration (molarity) of the Ca(OH)₂ solution needed to neutralize 31.5 mL of 0.1 M HC₂H302 solution is 0.162M (option D).

How to calculate molarity?

The molarity of a solution can be calculated using the following formula:

CaVa = CbVb

Where;

Ca = concentration of acidCb = concentration of baseVa = volume of acidVb = volume of base

31.5 × 0.1 = 19.4 × Cb

3.15 = 19.4Cb

Cb = 0.162M

Therefore, the concentration (molarity) of the Ca(OH)₂ solution needed to neutralize 31.5 mL of 0.1 M HC₂H302 solution is 0.162M.

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Related Questions

An atom is determined to contain 13 protons 10 electrons and 12 neutrons what are the mass number and charge of this atom or ion
Mass number 24 charge +2
Mass number 22 charge neutral
Mass number 34 charge -2
Mass number 34 charge +2

Answers

The mass number and charge of this atom or ion is 24  and charge +2

What is mass number ?

The mass number is equals to the total number of protons and neutrons in a nucleus.

In the give question, The number of neutrons is a distractor.

Only the number of electrons versus the number of protons determines ionic charge. The charge of the ion is +2

Hence, The mass number and charge of this atom or ion is 24  and charge +2

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What is the word equation for atoms of magnesium reacting with molecules of oxygen to produce magnesium oxide?

Answers

Answer:

The "word equation" is Magnesium + Dioxygen → Magnesium Oxide

Explanation: This is also the same as Mg + O₂ → MgO.

Grams in 1.083e+24
Molecules Na BR


Please help explain why

Answers

Answer:

185 gms o NaBr

Explanation:

Na Br  mole weight = 22.989 +79.904 = 102.893  gm/mole

1.083 x 10^24  molecules / 6.022 x 10^23 molecules / mole = 1.798 moles

102.893  *  1.798 = 185 gms

Convert from moles to particles 6.02x1023 particles 1 mole Question 2. 2.7 moles of lithium Question 3. 1.8 moles of sodium chloride​

Answers

Considering the definition of Avogadro's number:

the number of molecules of lithium is 1.62621×10²⁴ molecules.the number of molecules of sodium chloride is 1.08414×10²⁴ molecules.

Definition of Avogadro's number

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

Amount of molecules in this case

You can apply the following rule of three, considering the Avogadro's number:  If 1 mole of lithium contains 6.023×10²³ molecules, 2.7 moles of lithium contains how many molecules?

amount of molecules of lithium= (6.023×10²³ molecules × 2.7 moles)÷1 mole

amount of molecules of lithium=1.62621×10²⁴ molecules

Finally, the number of molecules of lithium is 1.62621×10²⁴ molecules.

On the other hand you can apply the following rule of three, considering the Avogadro's number:  If 1 mole of sodium chloride​ contains 6.023×10²³ molecules, 1.8 moles of  sodium chloride​ contains how many molecules?

amount of molecules of sodium chloride= (6.023×10²³ molecules × 1.8 moles)÷1 mole

amount of molecules of sodium chloride=1.08414 ×10²⁴ molecules

Finally, the number of molecules of sodium chloride is 1.08414×10²⁴ molecules.

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What is the name of this compound ​

Answers

Hydrobrome Aicd

I think so...

Answer:

[tex]\fbox {1,2-di bromo pentane}[/tex]

Explanation:

⇒ Bromine atoms present on 1st and 2nd Carbon atoms

⇒ 5 carbon atoms

⇒ Only single bonds

Hence, the IUPAC name will be :

1,2-dibromopentane

How can you use quantitative chemistry and reaction dynamics to explain and optimize industrial processes and reactions that happen in everyday life?

Answers

The quantitative chemistry is helps in measuring the quantity of chemicals or chemical agents of food while making some dish or cleaning agent. It also helps in determining the quantity of macromolecules in the body, like protein, lipid, etc.

What is quantitative chemistry?

Quantitative chemistry is a branch which tells the quantity  of substances, chemicals. The mass, volume etc. It also helps in determining the molecules and toxic level in the body.

Thus, the quantitative chemistry is helps in measuring the quantity of chemicals or chemical agents of food while making some dish or cleaning agent. It also helps in determining the quantity of macromolecules in the body, like protein, lipid, etc.

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Ordinary water boils at 100°C. Can it be made to boil at 95°C or 105°C.​

Answers

It can be done. Normally the boiling point of water is 100°C. It will boil at temperature greater than 100°C more quickly. Water can be boiled at 95°C but for that the atmospheric pressure of the water should be decreased which will decrease the boiling point of water.

Concept :

To boil water at 95°C, decrease the atmospheric pressure.

At 105°C, the water will be boiling quickly than normal at 100°C.

The best way is add alcohol .

The common way is that decrease the atmospheric pressure .

This will work as per Boyles law ,and boiling point can be decreased.

but it has few restrictions

You can't decrease pressure simply at normal conditionsFor decreasing pressure you have to go hill tops .

Hence there is a spare way

Add alcohol

General alcohols like ethanol,butanol can decrease the boiling point of water

Part 1. A chemist reacted 15.0 liters of F2 gas with NaCl in the laboratory to form Cl2 and NaF. Use the ideal gas law equation to determine the mass of NaCl that reacted with F2 at 280. K and 1.50 atm.


F2 + 2NaCl → Cl2 + 2NaF


Part 2. Explain how you would determine the mass of sodium chloride that can react with the same volume of fluorine gas at STP.


explain please (for 40 pts)

Answers

Answer:

113 g NaCl

Explanation:

The Ideal Gas Law equation is:

PV = nRT

In this equation,

    > P = pressure (atm)

    > V = volume (L)

    > n = number of moles

    > R = 8.314 (constant)

    > T = temperature (K)

The given values all have to due with the conditions fo F₂. You have been given values for all of the variables but moles F₂. Therefore, to find moles F₂, plug each of the values into the Ideal Gas Law equation and simplify.

(1.50 atm)(15.0 L) = n(8.314)(280. K)

2250 = n(2327.92)

0.967 moles F₂ = n

Using the Ideal Gas Law, we determined that the moles of F₂ is 0.967 moles. Now, to find the mass of NaCl that can react with F₂, you need to (1) convert moles F₂ to moles NaCl (via the mole-to-mole ratio using the reaction coefficients) and then (2) convert moles NaCl to grams NaCl (via molar mass from periodic table). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units (the desired unit should be in the numerator).

1 F₂ + 2 NaCl ---> Cl₂ + 2NaF

Molar Mass (NaCl): 22.99 g/mol + 35.45 g/mol

Molar Mass (NaCl): 58.44 g/mol

0.967 moles F₂        2 moles NaCl             58.44 g
----------------------  x  -----------------------  x  -----------------------  =  113 g NaCl
                                     1 mole F₂              1 mole NaCl

What is the chemical formula for acetic acid?

Answers

CH3COOH

Explanation:

hope I helped

if you get the answer right mark me as brainlyst

is Zinc + Hydrogen Chloride a chem. change why or why not

Answers

Answer:

When zinc reacts with hydrochloric acid, the reaction bubbles vigorously as hydrogen gas is produced. The production of a gas is also an indication that a chemical reaction is occurring.

Explanation:

Describe graham's law.

hydrogen chloride gas (hcl) diffuses 1.8 times faster than an unknown gas. determine the molar mass of the unknown gas. show your work or explain your answer, giving specific values used to determine the answer.

Answers

The molar mass of gas is 6.48 g/mol

What is the statement of Graham's law?

Graham's law of diffusion states that the rate of diffusion of a gas is inversely proportional to the density of the gas.

The molar mass of Hydrogen gas = 2

R2/R1 = 1.8

Molar mass of gas = 2 × 1.8 × 1.8

Molar mass of gas = 6.48 g/mol

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