Answer:
9m/s
Explanation:
Speed = Distance ÷ Time
Distance=270meters
Time =30 seconds
270m
30s
=9m/s
you know the drill. i need help
Answer:
Доброе утро, ответ 5+5="4
Explanation:
If a vehicle is traveling 13 m/s, what is its velocity in miles per hour? (0.62 miles = 1.00 km)
The vehicle that is traveling at a 13 m/s has a velocity expressed in miles per hour of: 29.016 miles/h
To solve this problem the we have to do the conversion of units with the given information.
Information about the problem:
v = 13 m/sv = expressed in (miles/h) = ?0.62 miles = 1.00 kmBy converting the velocity units from (m/s) to miles per hour (miles/h) we have:
v = 13 m/s * 1 km/1000 m * 0.62 miles/ 1 km * 3600 s/1 h
v = 29.016 miles/h
What is unit conversion?It is the transformation of a value expressed in one unit of measurement into an equivalent value expressed in another unit of measurement of the same nature.
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A stone thrown horizontally from a cliff with an initial speed of 10 m/s hits the bottom of the cliff in 4.3 s. what is the height of the cliff?
The height of the cliff is [tex]$90.69 \mathrm{~m}$[/tex]
The initial speed of the stone vi = 10m/s
The stone is also moving downward vertically under the effect of the gravitational acceleration [tex]$g=9.81 \mathrm{m} / \mathrm{s}^2$[/tex]
Thus, the stone will have two velocity components while moving. One component is the horizontal speed which will be constant during motion and the other component is the vertical speed which will increase under the effect of gravitational acceleration.
Hence, the final vertical speed when the stone hits the ground is
[tex]$$\begin{aligned}&V_y=V_{y o}+g t \\&V_y=0+9.81(4.3)=42.183 \mathrm{~m} / \mathrm{s}\end{aligned}$$[/tex]
The height of the cliff where the stone is thrown is
[tex]$$\begin{aligned}&h=\frac{\left(V_y\right)^2-\left(V_{y o}\right)^2}{2 g} \\&h=\frac{42.183^2-(0)^2}{2(9.81)} \\&h=90.69 \mathrm{~m}\end{aligned}$$[/tex]
So, the height of the cliff is [tex]$90.69 \mathrm{~m}$[/tex]
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pls pls pls Help! this is hard!
Answer:
a phase change occurs when the pressure on the system changes. during pressure change on the system changes the object is going through the phase change of melted then solid, melting, liquid, and then vaporization. sense it is going from a solid state to a melting state. the particles are Freezing: liquid to solid. Melting: solid to liquid. Condensation: gas to liquid. Vaporization: liquid to gas. Sublimation: solid to gas. Deposition: gas to solid. during the a phase change the energy of the particles are The energy that is changing during a phase change is potential energy. During a phase change, the heat added increases or released decreases will allow the molecules to move apart or come together. a phrase change occurs because a phase change is when matter changes to from one state to another example: solid to liquid. another reason why a phase change occurs is because water is a substance that has many interesting properties that influence its phase changes. Most people learn from an early age that water melts from ice to liquid at 0°C, and boils from a liquid to a gas at 100°C but this isn't true in all circumstances. The pressure affects these transition points, so for water, the boiling point actually decreases as the pressure decreases.
________________________________________________________
Have a good day!
-Asher
A student pushes down with a force of 2 N on the plunger of syringe A. Syringe B
has a plunger with an area that is 3 times the area of plunger A. What is the force
produced by plunger B?
Answer:
SYRINGE B PLUNGER FORCE=3*2=6
Force produced by plunger B is 6 Newtons
A car starts from rest and travels 243 m in 7.86 s with constant acceleration. what is its velocity when it crosses the finish line?
The car that starts from rest and travels 243 m in 7.86 s with constant acceleration has a velocity when it crosses the finish line of: 61.82 m/s
The formulas and procedures we will use to solve this exercise are:
a = 2 * [x - (vi * t)] / t²vf = vi + (a * t)Where:
x = distancet = timevi = initial velocitya = accelerationvf = final velocityInformation about the problem:
vi = 0 m/sx = 243 mt = 7.86 sa=?vf=?Applying the acceleration formula we have:
a = 2 * [x - (vi * t)] / t²
a = 2 * [243 m - (0 m/s * 7.86 s)] / (7.86 s)²
a = 2 * [243 m - (0 m)] / 61.779 s²
a = 2 * [243 m] / 61.779 s²
a = 486 m/ 61.779 s²
a = 7.866 m/s²
Applying the final velocity formula we have:
vf = vi + (a * t)
vf = 0 m/s + (7.866 m/s² *7.86 s)
vf = 0 m/s + 61.82 m/s
vf = 61.82 m/s
What is acceleration?It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
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Calculate the radius of a tantalum (ta) atom, given that ta has a bcc crystal structure, a density of 16.6 g/cm3 , and an atomic weight of 180.9 g/mol.
Based on the calculations, the radius of a tantalum (Ta) atom is equal to 0.143 nm.
Given the following data:
Density of tantalum (Ta) = 16.6 g/cm³.
Atomic weight of tantalum (Ta) = 180.9 g/mol.
What is density?Density can be defined as a ratio of mass to the volume of a physical object such as a tennis ball. Mathematically, the density of a physical object can be calculated by using this formula:
Density = Mass/Volume
For the mass of this unit cell, we have:
Mass = 2 atoms/unit-cell × 180.9 g/mol × 1 mol /6.022 x 10²³ atoms/mol
Mass = 6.01 x 10⁻²² g/unit-cell
Next, we would determine the volume and edge length of the cube:
Volume, V = 6.01 x 10⁻²²/16.6
Volume, V = 3.62 x 10⁻²³ cm³
For the edge length, we have:
V = a³
a = ∛V
a = ∛3.62 x 10⁻²³ cm
Edge length, a = 3.31 x 10⁻⁸ cm
Mathematically, the edge length of a body-centered cubic unit cell is given by this formula:
a = 4r/√3
r = a × √3/4
r = 3.31 x 10⁻⁸ × √3/4
Radius, r = 1.43 × 10⁻⁸ cm
Lastly, we would convert the value in cm to nm:
Radius, r = 1.43 × 10⁻⁸ × 1/100 × 1 × 10⁹
Radius, r = 0.143 nm.
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A 50-kg stunt diver is falling at a speed of 20 m/s. When she is stopped by sinking into a cushion, the cushion exerts an average force of 2500 n on her. Approximately how much time did it take her to stop moving once she hit the cushion?.
The approximately time that takes to stop the stunt driver once she hit the cushion is: 0.4 s
To solve this exercise, the formulas and procedures to be applied are:
F = m * at = (vf – vi) / aWhere:
m = massF = Forcea = accelerationt= timevf= final velocityvi = initial velocityInformation about the problem:
m = 50 kgvi = 20 m/sF= -2500 NVf = 0 m/s1 N = kg * m/s²a= ?t =?Applying the force formula and isolating the acceleration, we get:
F = m * a
a = F/m
a = -2500 N /50kg
a = -2500 kg * m/s² / 50 kg
a = -50 m/s²
Applying the time formula we get:
t = (vf – vi) / a
t = (0 m/s – 20 m/s) / 50 m/s²
t = (– 20 m/s) / -50 m/s²
t = 0.4 s
What is force?It is the physical magnitude that expresses the effort necessary to move the mass of one kilogram with an acceleration of one meter per second squared, this is expressed in units of the international system in Newton.
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A 10-foot-tall ladder rests against an 8-foot wall. the wall and ground form a 90-degree angle. how many feet away from the wall is the bottom of the ladder?
[tex]\frac{-2}{15} \\radians per secondExplanation:Denoting the distance in feet between the wall and the base of the ladder by x and the angle in radians between the ladder and the ground by y, it is notedcos(y)=x/10which impliesy=arccos(x/10)Denoting time in seconds by t, it is further noted that[/tex]
[tex]\frac{dy}{dt}= \frac{dy}{dx}\frac{dx}{dt} (chain rule)\\ Noting (using standard table of derivatives for convenience)\\\frac{dy}{dx} = -\frac{0.1}{\sqrt{1-0.01x^{2} } } \\\frac{dx}{dt} =0.8 f/sec\\so,\\\frac{dy}{dt}(8)=\frac{dy}{dx}\frac{dx}{dt} = -\frac{0.08}{\sqrt{1-0.01(64)} } \\ = -\frac{0..8}{\sqrt{0.36} } =\frac{8}{60} = \frac{-2}{15 } radian/sec[/tex]
what is radian ?The radian is a term of angular measurement established so that an arc with an arc length of 1 is produced by an angle over one radian area enclosed from the center of a unit circle.
Due to the fact that a whole angle is 2pi radians, there are 360 ° per 2pi radians, or 180 ° or 57.29577951 degrees per radian. Similar to this, a straight angle has a radius of pi and a right angle has a radius of pi/2.The SI defines the radian as a dimensionless unit having the value 1 rad. As a result, its sign is frequently omitted, particularly in mathematical writing.When measuring angles, the radian is frequently employed in physics. For instance, angular velocity is frequently expressed in terms of radians per second (rad/s). The reciprocal of one revolution per second is two radians per second.
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A car accelerates from rest at a rate of 2.0 m/s^2 [n]. what is the displacment of the car at t=15s?
By using uniform motion, the car displacement is 225 meters.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
a = 2 m/s²
vo = 0 m/s
t = 15 s
Use the third equation to calculate the displacement
s = vo . t + 1/2 . a . t²
s = 0 . 15 + 1/2 . 2 . 15²
s = 0 + 225
s = 225 m
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An object moves in the eastward direction at constant speed. A net force directed northward acts on the object for a certain time interval. Then the net force drops to zero. Which one of the following statements is necessarily correct?.
You need to analyse what is possible and get the answer.
Since this question does not include numerical data, a precise answer is not possible but does not refrain someone from giving you guidance to tackle the question.You may follow those to get the answer.The object could have remained in the eastward motion if the northward force never acted upon it (this idea is grabbed from Newton's first law).Northward is perpendicular to Westward so the force is initially acted the same way on the object and it causes the object to enter into a circular motion.But with time, the force is not acted upon the object perpendicularly so that the object does not follow a circular motion and rather it follows a projectile.This situation can be thought of as a parachuter jumping out with zero initial verticle velocity. He initially possesses only the horizontal speed and then follows a projectile under the influence of gravitational force which is similar to the Northward force here.Once the net force is gone according to Newton's first law again, it continues to move in the direction that it was just before the loss of the net force.Its net speed behaves the same as that of a projectile and you may refer to the figure attached to visualize the situation.#SPJ4
What is the difference between the solar system, the galaxy, and the universe? (select all that apply.)
The difference between the solar system, the galaxy, and the universe is as follows:
A solar system consists of a star and objects that are affected by its gravity revolve around it. The objects that revolve around the star are planets, moons, asteroids, and comets. Take an example of our solar system, the Sun is the star, and all the planets including Earth and moons are revolving around it.
A Galaxy consists of billions of stars and Solar systems. Despite billions of stars, most of a galaxy is empty. This tells a lot about the size of a galaxy. The galaxy that we are in is known as Milky Way.
The universe is all matter and space that there is. It consists of all the galaxies, the solar systems, and everything known to mankind.
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What is the change in area ( in cm^2) of a 60.0cm by 150cm automobile windshield when tem change 0 to 36?
The given coefficient of linear expansion of glass is [tex]9 \times 10^{-6}[/tex]/°C.
change in area =[tex]a_1[/tex][tex]\times[/tex]β[tex]\times[/tex]ΔT
where β=2α
so,
[tex]60\times 150\times2\times9\times10^{-6}\times36 = 5.832cm^{2}[/tex]
Coefficient of thermal expansion is the measurement of change in volume or length in relationship to change in temperatureLinear expansion depends on the change in temp, the original length, and the coefficient of thermal expansionFormula for linear expansion ΔL = αLΔCcoefficient of linear expansion units in one divided by Celsius degree, is materially dependentSpecific heat for every substance has a different capacity for storing energyFormula for specific heat is heat in joules divided by the quantity mass times the change in temp ( can be neg) ( C=Q/MT)To know more about linear expansion visit : https://brainly.com/question/27955197
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What type of laboratory glassware is used when the accuracy and precision of volume is critical to quantitative analysis?
It is frequently necessary to produce volume measurements in quantitative chemistry with an error of 0.1%, or one part per thousand.
Utilizing volumetric glassware with a known capacity down to a few hundredths of a milliliter, or approximately 0.01 mL, is required for this.
Which kind of glass would be appropriate for a crucial measurement?Five different types of glassware, including graduated cylinders, beakers, volumetric pipets, burets, and volumetric flasks, are frequently used to measure out precise volumes.
The most exact glassware are volumetric pipets, flasks, and burets; the glassware manufacturers calibrate these to a high degree of accuracy.
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A potato gun fires a potato straight up with an initial velocity of 16 m/s. How high will it rise?
The maximum height to which the potato will rise is 13.06 m
Data obtained from the questionFrom the question given above, the folloing data were obtained:
Initial velocity (u) = 16 m/sFinal velocity (v) = 0 m/s (at maximum height) Acceleration due to gravity (g) = 9.8 m/s²Maximum height (h) =? How to determine the maximum heightThe maximum height can be obtaibed as illustarted below
v² = u² – 2gh (since the ball is going against gravity)
0² = 16² – (2 × 9.8 × h)
0 = 256 – 19.6h
Collect like terms
0 – 256 = –19.6h
–256 = –19.6h
Divide both side by –19.6
h = –256 / –19.6
h = 13.06 m
Thus, the potato will rise to a height of 13.06 m
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20. What is the final velocity of a snowball dropped from a cliff in the Rocky Mts. that falls
for 17s?4pts
Variable
The final velocity of a snowball dropped from a cliff in the Rocky Mts. that falls for 17s is 166.6 m/s
When a body is dropped from a height, its initial velocity is 0. A body executing free fall moves with constant acceleration i.e acceleration due to gravity
Given data -
time = t= 17 secSnowball is dropped so u ( initial velocity ) = 0 and a = g ( acceleration due to gravity ) under free fallFinal velocity = v = ?By using 1st equation of motion:
v = u + at
Equation of motion under gravity :
v = u + gt ( g = 9.8 m/s² )
= 0 + 9.8 × 17
= 166.6 m/s
Thus we can conclude that the final velocity of a snowball dropped from the cliff is 166.6 m/s
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The notion that every stimulus pattern is seen in such a way that the resulting structure is as simple as possible is called the law of.
The notion that every stimulus pattern is seen in such a way that the resulting structure is as simple as possible is called the law of pragnanz
The law of prägnanz is also known as the law of simplicity or the law of good figure . This law states that when presented with a group of ambiguous or complicated objects, your brain will simplify them as much as possible. When presented with the Olympic logo, for example, you see overlapping circles rather than a jumble of curved, connected lines.
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Identify the types of lineages and clans that Diana is observing.
Diana is a postgraduate student in anthropology, and she is studying the descent system followed by a tribe in Africa. She observed that
✓lineage as the children used to choose to claim inheritance from either of their parents. The tribe
the tribe had a
was arranged in the form of a
where people claimed relationship to an ancestor through a series of male links.
Answer:
Collateral
Explanation:
A more reasonable maximum acceleration for varying pavement conditions is 5.0 m/s2 . under these conditions, what is the maximum speed at which a car can negotiate a flat curve with radius 205 m ?
The maximum speed at which a car can negotiate a flat curve with radius 205m at maximum acceleration of 5.0m/s2 is 32m/s.
Given data
Radius of curve = 205m
Speed (v) =?
Acceleration (a) = 5.0m/s2
The expression for the centripetal force acting on the car
F_c=(mv^2)/r
The expression for the force acting on the car.
F=ma
Equating the force acting on the car to centripetal force,
F_c=F
(mv^2)/r= ma
Making v the subject of the equation above
v=√ar
Putting the values of a and r into the expression above
v=√(5×205)
v=√1025
v=32.02 m/s
Approximately,
v=32 m/s
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Nitrogen is heated to 500 k in a vessel of constant volume. if it enters the vessel at 50 atm and 330 k, what pressure would it exert at the working temperature if it behaved as a perfect gas?
By ideal gas approximation, the final pressure is 75.76 atm.
We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation
P . V = n . R . T
where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.
From the question above, we know that
P1 = 50 atm
T1 = 330 K
T2 = 500 K
When the initial and final volume is the same, we can use the ratio of pressure and temperature as
P1 / P2 = T1 / T2
50 / P2 = 330 / 500
P2 = 50 x 500 / 330
P2 = 75.76 atm
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A piano string having a mass per unit length equal to 5.20 10-3 kg/m is under a tension of 1 250 n. find the speed with which a wave travels on this string.
A piano string having a mass per unit length equal to 5.20 10^-3 kg/m is under a tension of 1 250 n, then speed with which the wave travels is 490.29 m/sec
Speed of waveWavelength x Frequency equals speed. When the wavelength and frequency values are known, this equation can be used to determine the wave speed.
If the wave speed and the other value are known, the equation for wave speed can be written to solve for wavelength or frequency. Unit = meters/second
The distance a wave shape travels divided by the time it takes to cover that distance is its velocity. Also known as wave velocity V. Symbol meters/second are the units (ms-1).
The speed of the wave's doubles when the frequency of a wave source is doubled.
V= sqrt T/u = sqrt [1250/5.20 x 10^-3]
= 490.29 m/sec
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At some instant the velocity components of an electron moving between two charged parallel plates are?
The velocity components of an electron moving between two charged parallel plates are[tex]v_y + Eed/m_ex v_x[/tex].
Any vector's magnitude, represented by its unit and pointing in the direction of the vector, is its length. As a result, the acceleration's magnitude is equal to the length of the acceleration vector and it is pointed in the same direction.
let the magnitude charge of the electron =[tex]e = 1.6 \times10^{-19} C[/tex]
me= mass of electron = 9.11 x 10^-31
force on the electron = Ee
Magnitude of acceleration [tex]a= Ee/m_e[/tex]
In x direction there is no field --> no force---> no acceleration
[tex]d = v_xt[/tex]
[tex]t = d/v_x[/tex]
the y-component of electron's velocity when its x coordinate has changed by a distance [tex]d v_y' = v_y + at = v_y + Eed/m_ex v_x[/tex]
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__________ receptors detect presence of acids in substances, whereas __________ receptors detect sodium in substances. a. sour . . . salt b. sweet . . . bitter c. bitter . . . salt d. sweet . . . sour please select the best answer from the choices provided a b c d
The correct option is A.
Sour receptors help in the detection of the presence of acids in substances, whereas salt receptors help in the detection of sodium in substances.
A sour type of taste is considered as a quality of primary task that makes an innate rejection type of response in humans as well as in many other animals. Generally, Acidic stimuli are certain unique sources of a sour taste as whenever a rejection response might serve a discouragement of ingestion of foods which is spoiled by microorganisms that produce acids. The mechanisms by which an acid excites receptor cells of taste (TRCs) are actually complicated by the variability of wide species and are within species that are apparently different kinds of mechanisms for the case of strong and weak acids in substances.
The presence of epithelial sodium channels mediates the mechanism of salt taste. Usually, these receptors are open, and whenever foods are ingested with a high concentration of salt, sodium starts to flow into the cell which causes depolarization. This change occuring in the membrane potential then opens to voltage-gated sodium as well as calcium channels. The calcium influx is in an increased state that causes releasing of serotonin which is filled by vesicles. The serotonin aids in the acting of afferent taste as by axon which causes depolarization and action potentials.
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.+a+boost+chopper+is+powered+by+a+12-v+dc+power+supply.+what+is+the+output+voltage+range+of+this+chopper+if+the+duty+cycle+can+vary+between+20+and+95%?
A boost chopper is powered by a 12-V DC power supply.
The output voltage range of this chopper if the duty cycle vary between 20 and 95% will be 15 - 240V
How to calculate the output voltage?
Output voltage can be calculated by the following formula:
[tex]V_0=\frac{V_i}{1-D}[/tex]
Here,
[tex]V_i[/tex] is the initial power supply.
D = Duty cycle
Calculating output voltage for 20%
[tex]V_0=\frac{12}{1-0.20} \\V_0=-\frac{12}{0.8} \\V_0=15[/tex]
Calculating output voltage for 95%
[tex]V_0=\frac{12}{1-0.95} \\V_0=-\frac{12}{0.05} \\V_0=240[/tex]
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Which object weighs approximately 1 newton?
1. dime
2.paper clip
3.physics student
4.golf cart
Answer:
None of the choices is appropriate.
Explanation:
A low hydrostatic pressure combined with a high oncotic pressure will result in:________
A low hydrostatic pressure combined with high oncotic pressure will result in fluid overload.
Hydrostatic Pressure is a specified pressure that refers to a particular force that is exerted by the fluid present inside the blood capillaries as it is running against the capillary wall. Oncotic Pressure is also a type of pressure that refers to the force which is exerted by albumin as well as other proteins existing in the same blood vessel.
Osmotic agents are involved in the process of increasing oncotic pressure existing in the blood. This results in the pulling of water from tissues which helps in increasing the volume of the blood more acutely. Then the increased blood volume will result in inhibition of renin release as it increases renal blood flow.
During a situation of prolonged water restriction or when it is after water loss due to sweat condition, the blood concentration will increase so that its oncotic pressure will also increase. Since this pressure is opposing the Glomerular filter rate, dehydration results in reducing the GFR due to the reduction taking place in net driving force. Thus fluid overload will be caused by a low hydrostatic pressure combined with high oncotic pressure.
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A car accelerates from to at a rate of how far does the car travel while accelerating?
The car will travel 69.3m while accelerating, using the equation of motion.
Using the equation of motion:
[tex]v^{2}- u^{2} = 2as[/tex]
[tex]s = \frac{v^{2}-u^{2} }{2a}[/tex]
where, s = displacement
u = initial velocity
v = final velocity
a = acceleration
Plugging in the values we get,
[tex]s = \frac{21^{2} - 5^{2} }{2*3.0}[/tex]
s = 69.3meters
Therefore, the car will travel 69.3m while accelerating, using the equation of motion.
The complete question is: A car accelerates from 5.0 m/s to 21 m/s at a constant rate of 3.0 m/s2, How far does it travel while accelerating?
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A tennis ball is thrown vertically
upward with an initial velocity of +9.0
m/s.
a) What will the ball's speed be
when it returns to its starting
point?
b) How long will the ball take to
reach the starting point?
c) How high will the ball go?
a) The velocity when it return to the ground is 9 m/s
b) The total time taken is 1.84 s
c) The highest distance covered is 4.2 m
What is the speed?We have to know that when an object has been projected upwards or downwards that the movement of the objects could be described by the use of the equations of motion under gravity. In that case we have to look at that tennis ball is thrown vertically upward with an initial velocity of +9.0
m/s as an object that is undergoing motion under gravity.
We now have;
The time taken for the ball to reach the starting point;
v = u - gt
At the maximum height the ball is stationary thus v = 0 m/s
t =u/g
t = 9.0 m/s / 9.8 m/s^2
t = 0.92 s
Given that the ball went up and came down the time taken to return to starting point = 2(0.92) = 1.84 s
The highest distance covered by the ball is obtained from;
h = ut - 1/2gt^2
h = 9 * 0.92 - (0.5 * 9.8 * (0.92)^2)
h = 8.3 - 4.1
h = 4.2 m
The highest distance covered is 4.2 m
The balls speed when it returns;
Recall that it now falls from a height thus u = 0 m/s
v = u + gt
v = gt
v = 9.8 * 0.92
v = 9 m/s
The velocity when it return to the ground is 9 m/s
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A motorcycle can accelerate from rest to 100 km/h in only 4.80 s. how far does it travel in that time? (in m)
By using uniform motion, the distance is 66.64 meters.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
vo = 0 m/s
vt = 100 km/h = 100000/3600 m/s = 27.78 m/s
t = 4.8 s
Calculate the acceleration
vt = vo + a . t
27.78 = 0 + a . 4.8
4.8a = 27.78
a = 27.78 / 4.8
a = 5.79 m/s²
Find the distance
vt² = vo² + 2a . s
27.78² = 0² + 2 . 5.79 . s
11.58s = 771.73
s = 66.64 m
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An object has a mass of 65 g and a volume of 9 cm3.
What is the object's density?
1. 0.13 g/cm3
2. 74 g/cm3
3. 7.2 g/cm3
4. 585 g/cm3
