If a person weighs 600 N on Earth, they would weigh less on a planet with a larger radius. The weight of an object is determined by the force of gravity acting on it, and the force of gravity is directly proportional to the mass of the object and inversely proportional to the square of the distance between the object and the center of the planet. As the radius of the planet increases, the distance between the object and the center of the planet increases, which would decrease the force of gravity acting on the object and therefore decrease the object's weight.
It's worth mentioning that the mass of the person would be the same, so their weight would change due to the gravitational force.
Calculate the pressure of the air when the volume is reduced to 0.42 L at the same temperature. When the equation for the line representing the relationship between Volume (L) vs. (1/pressure) is y
The pressure when the volume is reduced to 0.42 L is (y - b) ÷ m.
What is pressure?Pressure is the force per unit area applied to a surface or object. In the physical sciences, pressure is a measure of the force exerted on a surface by a fluid, such as a gas or liquid. Pressure is the result of the weight of the fluid pushing down on a surface. In physics, pressure is often expressed as the ratio of force to area. Pressure is typically measured in units of pascals (Pa) or pounds per square inch (psi). Pressure can also be measured in atmospheres (atm), bars, or torr.
The equation for the line representing the relationship between Volume (L) and (1/pressure) is y = mx + b, where m is the slope and b is the y-intercept.
Since we know the Volume (L) is 0.42, we can use this value to solve for the pressure.
Using the equation, we can calculate the pressure by solving for x:
x = (y - b) ÷ m
Therefore, the pressure when the volume is reduced to 0.42 L is (y - b) ÷ m.
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One million electrons travel between two points in a circuit. The total energy gained by the electrons is 1.6 × 10−10 J. What is the potential difference between the two points?
A. 1.6 x 10^-16 V
B. 1.6 x 10^-4 V
C. 1.0 x 10^3 V
D. 1.0 x 10^9 V
The potential difference between the two points is B. 1.6 x 10⁻⁴
The potential difference, also known as voltage, is the energy per unit charge that is transferred between two points in a circuit. We can use the formula:
V = E / Q
where V is the potential difference, E is the energy, and Q is the charge.
In this problem, we are given that the total energy gained by the electrons is 1.6 x 1010 J and the charge is Q = 1 x 10⁶ electrons. So, we can plug in these values into the formula:
V = 1.6 x 10-10 J / (1 x 10⁶) = 1.6 x 10⁻⁴ V
Therefore, the potential difference between the two points is 1.6 x 10⁻⁴ V.
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if the temperature outside is 100 f, what is that temperature in celsius?
100.00 °F to Celsius would be 37.78 °C
So sorry but I need help ;(
Gwen is completing a physics investigation involving the speeds of toy cars on a track. Two cars are going to be released from the top of a ramp and timed until they reach the bottom. Before her investigation, Gwen comes up with a hypothesis. She states that toy car A will be faster than toy car B. She runs three trials of her investigation and records her data.
After Gwen’s experiment, she finds that toy car B was faster than toy car A. How should she proceed with her investigation?
A. Gwen should stop her investigation because her hypothesis was supported by her findings.
B. Gwen's hypothesis is invaluable because it was incorrect. She should completely discard her original hypothesis and investigation, starting again from scratch.
C. Gwen's hypothesis is valuable even though it was incorrect. She should rethink her original hypothesis, or design a new way to test her original hypothesis.
D. Gwen should assume that she made an error in her original experiment, because a hypothesis cannot be wrong.
Answer: I think it is (C.
Explanation: (C. is more realistic because that is something i would do.
A spring has a length of 0.180 m when a 0.300 kg mass hangs from it, and a length of 0.750 m when a 2.10 kg mass hangs from it. (a) What is the force constant (in N/m) of the spring? N/m (b) What is the unloaded length (in m) of the spring?
The force constant of the spring is 30.6N and the unloaded length of the spring is 0.57m.
The force constant (k) of the spring is calculated by the equation
k = (mass× gravity) / (change in length).
In this question, the mass is the difference between the two masses (2.10 kg - 0.300 kg = 1.800 kg),
And the change in length is the difference between the two lengths (0.750 m - 0.180 m = 0.570 m).
Therefore, the force constant of the spring is
(1.800 kg × 9.8 m/s²) / (0.570 m) = 30.6 N/m.
The unloaded length of the spring is determined by subtracting the length of the spring when the 0.300 kg mass hangs from it (0.180 m) from the length of the spring when the 2.10 kg mass hangs from it (0.750 m). Therefore, the unloaded length of the spring is
0.750 m - 0.180 m = 0.570 m.
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what is the velocity (in cm/s) of an object which moves 44 m in 2 s?
The velocity (in cm/s) of an object which moves 44 m in 2 s is 220 cm/s.
As per the given data:
Distance given as 44 m.
Time gives as 2s.
Velocity is to be calculated.
Conversion to distance from m to cm.
1m=100 cm
44m=4400 cm
The formula for velocity is:
Velocity = Distance / Time
Velocity = 4400 / 2
=220 cm/s
The velocity of the object is 220 cm/s.
Velocity is a vector expression of the displacement that an object or particle undergoes with respect to time . The standard unit of velocity magnitude (also known as speed ) is the meter per second (m/s). Alternatively, the centimeter per second (cm/s) can be used to express velocity magnitude.
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A student is twirling a rubber stopper in a vertical circle of radius 0.95 m. If the rubber stopper has a mass of 50 grams and the student is able to control the speed so that it is a constant 3.5 m/s at all points on the circle:
If the rubber stopper has a mass of 50 grams and the student is able to control the speed so that it is a constant 3.5 m/s at all points on the circle, then he will use the string half as the length of the original string.
A student is twirling a rubber stopper in a vertical circle of radius 0.95 m. If the rubber stopper has a mass of 50 grams and the student is able to control the speed so that it is a constant 3.5 m/s at all points on the circle. A physics student is performing a lab in which she twirls a rubber stopper at the end of a string around in a circle at nearly constant speed and tries to determine its acceleration. by the given primary information we can firmly conclude that if the rubber stopper has a mass of 50 grams and the student is able to control the speed so that it is a constant 3.5 m/s at all points on the circle, then he will use the string half as the length of the original string.
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the goose has a mass of 21.3 lb (pounds) and is flying at 8.00 miles/h (miles per hour). what is the kinetic energy of the goose in joules?
The goose weighs 21.3 pounds and travels at an average speed of 8 miles per hour (miles per hour). The goose's kinetic energy in joules is 61.86 kg m2/sec2.
Given,
Kinetic energy (K.E)=1/2mv²
where m=mass in kg,velocity =v m/sec
From data m=21.3lb
but 21.3lb =454g; 1000g=1kg
21.3lb×454g/1lb×(kg/1000g)=9.6702 kg
velocity=8.00 miles/h
1mile=1.61km; 1hour=60min =60×60 sec
8.00miles/hour ×(1 hour/60×60sec)×(1.61 km/1mile)×1000m/1km
v=3.577 m/sec
Kinetic energy (K.E)=1/2mv²
=1/2(9.67)(3.577 m/sec)²
=61.86 kg m²/sec²
∴KE=61.86 Joule
kinetic energy of the goose=61.86J
Kinetic energy is the type of energy that an object or particle possesses as a result of its motion. When work is performed on an object by applying a net force, the object accelerates and gains kinetic energy. Kinetic energy is a property of a moving object or particle that is affected by both its motion and mass. Translation (or movement along a path from one location to another), rotation about an axis, vibration, or any combination of motions are all possible.
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identify the conditions necessary for an object to be in rotational equilibrium. i. angular acceleration is zero ii. net torque is zero iii. angular acceleration is a maximum iv. net force is zero group of answer choices ii and iv only iii and iv only i and ii only ii and iii only
Rotational equilibrium is the condition of motion where there is no angular acceleration. Since the torque is what causes the movement's acceleration, there is no total torque in the rotational equilibrium.
What prerequisites must exist for an item to be in rotational and linear equilibrium?An object must satisfy two requirements of equilibrium in order to maintain static equilibrium. First, there must be no net force acting on the item. Second, there must be no net torque pulling on the object.
What is the prerequisite for rotational equilibrium, according to Chegg?If a body meets the requirements below, it is said to be in rotational equilibrium: The forces operate within the same plane, cross at a common element, and finally, act within the same plane.
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When you catch a water balloon, it's best to start with your hand in motion, moving with the balloon, and then gradually slow it to rest. Why is this approach desirable?
This strategy is preferable since you need to apply force because of water balloon does indeed have a lot of motion. To bring its balloon to rest, you must apply a force over a period of time.
Motion? What do you mean?The physics term for a body's position nor orientation changing over time. Translation is defined as movement along this line or a curve. Rotation is a motion that modifies a body's orientation.
To let the balloon to settle after some time, according to Δp = fΔtΔp→F→Δt
In contrast to if the balloon just smacked against a hand that was immobile, you may bring the inflatable to rest by moving your hand as the balloon does. You may place the balloon on top of something bigger. The force could be less. The effort can be reduced while still causing its same acceleration change and preventing the balloon from breaking.
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If a person whirls an object horizontally in a counter clockwise direction and the string breaks at point P as shown, what path will the rock follow?
If a person whirls an object horizontally in a counter-clockwise direction and the string breaks at point P, the rock will follow a path that is determined by the combination of its initial horizontal velocity and its vertical velocity due to gravity.
Without additional information about the object's initial velocity and the distance from the point of release to the ground, it is difficult to determine the exact path that the rock will follow. However, it is likely that the rock will follow a curved path, where gravity causes the rock to fall vertically downward while the horizontal velocity causes it to continue moving horizontally. This path is known as a parabolic path or a projectile motion.
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why does a canvas tent leak when touched when it's raining
You double the partial pressure of a gas over a liquid at constant temperature. Which of these statements is then true?.
"The correct statement is There are twice as many gas molecules in the liquid."
Henry's Law states that the partial pressure of a gas above a solution is precisely proportional to the mass of the gas that will dissolve into the solution.
Mathematically, C = kH × P
where, kH is Henry's constant
P = Partial pressure
Because the relationship between concentration and gas partial pressure is straightforward. Therefore, the number of molecules in the liquid will increase as partial pressure increases.
So, we can conclude that the statement there are twice as many gas molecules in the liquid, is true.
The given question is incomplete. The complete question contains options. They are 'a. The Henry’s Law constant is decreased by half. b. There are half as many gas molecules in the liquid. c. There is no change in the number of gas molecules in the liquid. d. The Henry’s Law constant is doubled. e. There are twice as many gas molecules in the liquid.'
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Sam tried tying toys to his toy parachute. He discovered that differences in size, shape, and material affected
A: Friction
B: Motion
C: Direction
D: Drag
Sam tried tying toys to his toy parachute. He discovered that differences in size, shape, and material affected Drag , option D.
How does Drag affect gravity?Changes in acceleration are caused by resistance and friction. The heavier piece was slowed down by air resistance also known as drag. Drag is the force that opposes the motion of an object through a fluid.
The parachute works by creating drag, slowing the descent of the objects attached to it. The size, shape, and material of the toys that Sam tied to the parachute would affect the amount of drag created, which in turn would affect the motion of the toys as they descended.
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A metal bar is in the xy-plane with one end of the bar at the origin. A force F = (7.25 N)i + (-3.03 N)j is applied to the bar at the point x = 2.76 m, y = 3.05 m.
a. What is the position vector r for the point where the force is applied?
b. What are the magnitude of the torque with respect to the origin produced by F?
c. What is the direction of the torque with respect to the origin produced by F?
The position vector is 2.76i+3.05j, the magnitude of the torque is 20.0055 N*m, and the direction of the torque is perpendicular to the plane.
What is force?A force is an influence that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force.
a. The position vector for the point where the force is applied is given by the coordinates of the point in the xy-plane. In this case, the point is at (2.76 m, 3.05 m), so the position vector is:
r = 2.76i + 3.05j
b. The torque with respect to the origin produced by F is given by the cross product of the position vector and the force vector. The magnitude of the torque is given by the formula:
τ = r x F
τ = (2.76i + 3.05j) x (7.25i - 3.03j)
τ = ((3.05)(-3.03) - (2.76)(7.25))i + ((2.76)(-3.03) - (3.05)(7.25))j
τ =20.0055 N*m
c. The direction of the torque with respect to the origin is given by the cross product of the position vector and the force vector, the direction is perpendicular to the plane formed by the position vector and the force vector. The direction of the torque is out of the plane in a direction perpendicular to the plane.
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The Washington Monument is 169 meters tall.
A worker assigned to the restoration of the Washington Monument is checking the condition of the stone at the very top of the monument. A nickel with a mass of 0.005 kg is in her shirt pocket.
Q: If the nickel accidentally falls out of her pocket, what will happen to the gravitational potential energy (GPE) of the nickel as it falls to the ground?
The gravitational potential energy (GPE) of the nickel will increase as it falls to the ground due to the force of gravity acting on it.
When an object falls, it gains kinetic energy, which is the energy of motion. As an object falls, it gains kinetic energy at the expense of its potential energy.
The amount of GPE gained will be equal to the mass of the nickel multiplied by the acceleration due to gravity and the change in height from the worker's pocket to the ground. Specifically, the change in GPE = 0.005 kg [tex]* 9.8 m/s^2 * 169[/tex]* m. As the nickel falls it will accelerate and its kinetic energy will increase as well. The nickel will convert the potential energy into kinetic energy and also will gain velocity as it falls, reaching a terminal velocity.
When the nickel reaches the ground, all of its potential energy will have been converted into kinetic energy.
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leaving the distance between the 99 kg and the 404 kg masses fixed, at what distance from the 404 kg mass (other than infinitely remote ones) does the 27.9 kg mass experience a net force of zero? answer in units of m.
The 27.9 kg mass experience a net force of zero. Gravitational equilibrium occurs when the gravitational force on an object is equal to zero.
How is equilibrium impacted by gravity?Tilting an object will increase the height of its center of gravity when it is in a stable balance. When tilted, an item in unstable equilibrium will have a lower center of gravity. Finally, for objects in neutral equilibrium, the center of gravity will stay at the same height when pushed.
How can we determined this?To find the distance at which the 27.9 kg mass experiences a net force of zero, we need to calculate the gravitational force acting on it due to the other two masses. The gravitational force between two masses m1 and m2 at distance r is given by F = Gm1m2/r^2, where G is the gravitational constant.
First, we know that the distance between the 99 kg and 404 kg masses is fixed. Let's call this distance d.
Now we can set the gravitational force acting on the 27.9 kg mass due to the 99 kg mass and the 404 kg mass equal to zero and solve for r:
0 = G*(27.9 kg)(99 kg)/r^2 + G(27.9 kg)*(404 kg)/(d-r)^2
Solving for r, we get:
r = d * sqrt(404/(404+99))
Substituting d value will give the distance at which the 27.9 kg mass experiences a net force of zero in units of m.
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what would be true of a thermometer that always reads three degrees lower than the actual temperature?
A thermometer which always reads three degrees lower than the actual temperature is reliable but it is not valid. Thus, the correct option is E.
How does the thermometer works?A thermometer is generally made up of a small, hollow glass tube. At the bottom of this tube is present a bulb, which holds a liquid such as the alcohol or mercury element. When there is an increase in the heat, the liquid present inside the bulb expands, pushing up into the tube of the thermometer. On the other hand, a decrease in heat lets the liquid contract, moving down the tube of the thermometer.
A thermometer works on the principle which states that solids and liquids tend to expand with temperature. This changes in mercury is studied on a temperature scale.
A thermometer which always reads three degrees lower than the actual temperature can be reliable but it is not valid at all.
Therefore, the correct option is E.
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Your question is incomplete, most probably the complete question is:
What would be true of a thermometer that always reads three degrees lower than the actual temperature?
a. It is valid but not reliable
b. It is both reliable and valid
c. It is neither reliable nor valid
d. It is not valid, but you cannot determine if it is reliable from the information given
e. It is reliable but not valid
a spider is crawling at 630 ft/hr. the room is 15 ft wide. How long does it take the spider to travel
The time taken for the spider crawling at 630 ft/hr to travel through the 15 ft wide room is 42 hours
How do I determine the time taken for the spider to travel?From the formula of speed, we can obtain a formula for calculating time as illustrated below:
Speed = Distance / time
Cross multiply
Speed × time = Distance
Divide both sides by speed
Time = Distance / speed
Using the above formula, we can obtain the time taken from the spider to travel through the room. Details as follow:
Speed of spider = 630 ft/hrDistance travel = 15 ftTime taken to travel =?Time = Distance / speed
Time = 630 / 15
Time = 42 hours
From the calculation made above, we can conclude that the time taken is 42 hours
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A planet P revolves around the Sun in a circular orbit, with the Sun at the center, which is coplanar with and concentric to the circular orbit of Earth E around the Sun. P and E revolve in the same direction. The times required for the revolution of P and E around the Sun are TP and TE. Let Ts be the time required for P to make one revolution around the Sun relative to E: show that l/Ts = 1/TE - 1/Tp, Assume Tp; > TE.
When Ts is the time required for P to make one revolution around the Sun relative to E and Tp, Te are the times required for the revolution of P and E around the Sun, the relation between them is 1/Ts = 1/Te - 1/ Tp.
Substitute θe = ωe Ts and θp = ωp Ts in the equation θe = θp + 2 π
ωe Ts = 2 π + ωp Ts ---(1)
Substitute ωp = 2 π/ Tp and ωe = 2 π/Te
Placing above equations in (1), we have,
(2 π/Te) Ts = 2 π + (2 π/ Tp) Ts
On re-arranging, we have,
2 π/Te - 2 π/ Tp = 2 π/Ts
Eliminating 2 π in all the terms, we get,
1/Te - 1/ Tp = 1/Ts
Thus, the relation 1/Ts = 1/Te - 1/ Tp is proved.
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a person pushes a 10 kg box from rest and accelerates it to a speed of 2.3 m/s with a constant force. if the box is pushed for a time of 4.8 s, what is the force exerted by the person?
The average force exerted by the person is 4.8 N (23 N / 4.8 s).
What is force?Force is an interaction between two or more objects that can cause a change in the motion, shape, or energy of one or both of the objects. Force can be classified into two categories: contact forces and non-contact forces. Examples of contact forces include friction, tension, and normal force. Examples of non-contact forces include gravity, magnetism, and electrostatic forces. Force is measured using the SI unit called the newton (N).
The force exerted by the person is equal to the mass of the box multiplied by the acceleration. Since the mass of the box is 10 kg and the acceleration is 2.3 m/s, the force exerted by the person is 23 N (10 kg × 2.3 m/s). This force was applied over a time of 4.8 s, so the average force exerted by the person is 4.8 N (23 N / 4.8 s).
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A cell membrane has a resistance and a capacitance and thus a characteristic time constant.
What is the time constant of a 9.0-nm-thick membrane surrounding a 0.040-mm-diameter spherical cell? Assume the resistivity of the cell membrane as 3.6×107 ??m and the dielectric constant is approximately 9.0.
The membrane's time constant is 2.87 ms. The resistance and capacitance of RC circuits are used to calculate the time constant. The time constant's value is determined in milliseconds.
How can the time constant be determined?The time constant is calculated using the equation,
T = R*C in seconds.
Describe the time constant.In physics and engineering, the parameter that specifies how a first-order, linear time-invariant (LTI) system reacts to a step input is known as the time constant, which is typically symbolized by the Greek letter tau. The time constant is the main property of a first-order LTI system.
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Squid rely on jet propulsion when a rapid escape is necessary. A 1.5 kg squid at rest pulls 0.10 kg of water into its mantle, then ejects this water at a remarkable 45 m/s. Right after this ejection, how fast is the squid moving?
After the water is ejected, the squid's final speed is 3 m/s in the opposite direction.
What is the straightforward meaning of velocity?The dislocation that such an object a particle experiences in respect to time is expressed vectorially as pace. The meter a second (m/s) is the accepted unit measure velocity profile (also known as speed). The unidirectional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity.
mass m₁ = 1.5 kg
initial velocity, u₁ = 0
mass of water, m₂ = 0.1 kg
initial velocity , u₂ = 0
final velocity , v₂ = 45 m/s
conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
1.5(0) + 0.1(0) = 1.5v₁ + 45(0.1)
0 = 1.5v₁ + 4.5
1.5v₁ = -4.5
v1 = (-4.5)/1.5
v1 = -3 m/s
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a small vibrating object s moves across the surface of a ripple tank producing the wave fronts shown above. the wave fronts move with speed v. the object is traveling in what direction and with what speed relative to the speed of the wave fronts produced?
The wave fronts seen above are the result of a small vibrating moving object across a ripple tank's surface. The surface waves move quickly in contrast to the Doppler effect. The item is travelling right, which has compressed the waves at the right.
What is the Doppler effect in plain English?Doppler Effect is the term used to describe the shift in wave frequency caused by the relative motion of an incident wave and its observer.
What makes the Doppler effect effective?One of the most typical examples is the sound of an ambulance or fire engine's siren. You may have observed that the pitch of a siren decreases sharply as it passes you at a high rate of speed. The siren initially approaches you while the pitch is louder.
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A sample of an unknown material weighs 290 N in air and 190N when immersed in alcohol of specific gravity 0.700.
(a) What is the volume of the material?
m3
(b) What is the density of the material?
kg/m3
The volume of the material is 27.14 m³ and the density of the material is 1.02 kg/m³.
The sample of the unknown material as a weight of 290 Newton in the air and when it is must in alcohol of specific gravity 0.70 it has a weight of 190 Newton.
We know,
B = VpG
B is buoyancy that will be 190N,
V is volume of material,
p is the density of alcohol,
G is the acceleration due to gravity,
Putting values,
190 = V(0.7)(10)
V = 27.14 m³
The volume of the material is 27.14 m³.
Now, we know,
Density = Mass/volume
Density = W/Vg
Putting values,
Density = 290/27.14×10
Density = 1.02 kg/m³.
So, the density of material is 1.02 kg/m³.
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(q020) the conventional system of signs that indicate relative durations of long and short sounds is called
The term "musical notation" refers to the widespread symbology used to indicate how far apart long and short sounds should be from one another.
What is fundamental musical notation?a collection of visual instructions for performing music, a visual representation of a heard or imagined musical sound, or musical notation. It usually takes the form of writing or printing and is a deliberate, comparatively time-consuming activity. One of two purposes—as a memory aid or for communication—causes its use.
What are the twelve notes in music?Typically, Western music employs 12 notes: C, D, E, F, G, A, B, plus five flats and comparable sharps in between: C sharp/D flat (they are the same note, simply referred to differently depending on the context).
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a 60.0 kg skier is at the top of a slope 10.0 m above the ground. what is her gravitational potential energy of the skier-earth system?
A 60.0 kg skier is at the top of a slope 10.0 m above the ground. The gravitational potential energy of the skier-earth system is 5880J.
Given,
m=60 kg
h=10m
g=9.8
P.E=mgh
=60*10*9.8
=5880J
William Rankine, a Scottish engineer, and physicist from the nineteenth century coined the term potential energy. Potential energy is classified into several types, each of which is associated with a specific type of force.
Because of its position, an object, as we know, can store energy. When a bow and arrow are drawn, some energy is stored in the bow, which is responsible for the kinetic energy gained when the bow is released.
Similarly, when a spring is displaced from its equilibrium position, it gains energy, which we see as stress in our hands when we stretch it. Potential energy is a type of energy that is created as a result of an alteration.
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during tug of war team adoes 2.20 10^5* J of work in pulling team b 8.00 m. what combined force was team a exerting
Answer:
27,500 N
Explanation:
W = Fd
F = W/d = (2.2x10⁵J)/(8 m ) = 27,500 N
An object is 1.0 cm tall and its erect image is 3.0 cm tall. What is the exact magnification?
An object is 1.0 cm tall and its erect image is 3.0 cm tall, the exact magnification is 3.
What is magnification?Magnification measures how much the image is enlarged compared to the actual object. Magnification measures how many distinct structures can be seen in an image. Calculating magnification is as simple as dividing the eyepiece's magnification by the objective lens's.
By dividing the image height, it is possible to calculate the precise magnification of the objects. We determine it by dividing the size of the erect image by the size of the object. By dividing 3.0 cm by 1.0 cm from the above information, we can determine the precise magnification. So, the response would be 3.
exact magnification = image height/object's height
exact magnification = 3/1
exact magnification = 3.
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± A Superball Collides Inelastically with a Table
As shown in the figure (Figure 1) , a superball with mass m equal to 50 grams is dropped from a height of hi=1.5m . It collides with a table, then bounces up to a height of hf=1.0m . The duration of the collision (the time during which the superball is in contact with the table) is tc=15ms . In this problem, take the positive y direction to be upward, and use g=9.8m/s2 for the magnitude of the acceleration due to gravity. Neglect air resistance.
Part A Find the y component of the momentum, pbefore,y, of the ball immediately before the collision. Express your answer numerically, to two significant figures.
Part B Find the y component of the momentum of the ball immediately after the collision, that is, just as it is leaving the table. Express your answer numerically, to two significant figures.
Part C Find Jy, the y component of the impulse imparted to the ball during the collision. Express your answer numerically, to two significant figures.
Part D Find the y component of the time-averaged force Favg,y, in newtons, that the table exerts on the ball. Express your answer numerically, to two significant figures.
Part E Find Kafter−Kbefore, the change in the kinetic energy of the ball during the collision, in joules. Express your answer numerically, to two significant figures.
Please show your work in detail, I'm posting because I need to know how to get to the answer, I'm studying for an exam.
Part A
The momentum of the ball right before the collision is given by the equation
$p_{before,y} = mv_{before,y}$
But we know the initial velocity of the ball before the collision is just the velocity due to gravity, which is given by
$v_{before,y} = gt_0$
where $t_0$ is the time taken for the ball to fall from the initial height to the table.
This is given by
$t_0 = \sqrt{\frac{2h_i}{g}}$
Substituting this into the equation for the momentum gives
$p_{before,y} = mg\sqrt{\frac{2h_i}{g}}$
The final answer is
$p_{before,y} = m\sqrt{2gh_i} \approx 88.5 \,\text{kg m/s}$
Part B
The momentum of the ball right after the collision is given by the equation
$p_{after,y} = mv_{after,y}$
But we know the final velocity of the ball after the collision is just the velocity due to gravity, which is given by
$v_{after,y} = gt_f$
where $t_f$ is the time taken for the ball to fall from the final height to the table.
This is given by
$t_f = \sqrt{\frac{2h_f}{g}}$
Substituting this into the equation for the momentum gives
$p_{after,y} = mg\sqrt{\frac{2h_f}{g}}$
The final answer is
$p_{after,y} = m\sqrt{2gh_f} \approx 73.6 \,\text{kg m/s}$
Part C
The impulse imparted to the ball during the collision is given by
$J_y = p_{after,y} - p_{before,y}$
Substituting the values from Parts A and B gives
$J_y = 73.6 \,\text{kg m/s} - 88.5 \,\text{kg m/s} \approx -14.9 \,\text{kg m/s}$
Part D
The average force exerted on the ball during the collision is given by
$F_{avg,y} = \frac{J_y}{t_c}$
Substituting the value from Part C gives
$F_{avg,y} = \frac{-14.9 \,\text{kg m/s}}{15 \,\text{ms}} \approx -0.99 \,\text{N}$
Part E
The change in kinetic energy of the ball during the collision is given by
$K_{after} - K_{before} = \frac{p_{after,y}^2 - p_{before,y}^2}{2m}$
Substituting the values from Parts A and B gives
$K_{after} - K_{before} = \frac{73.6^2 - 88.5^2}{2 \cdot 50} \approx -3.3 \,\text{J}$
What is kinetic energy?
Kinetic energy is the energy of a moving object, equal to the work done to accelerate the object from rest to its current velocity. It is dependent on the object's mass and velocity.
To learn more about kinetic energy
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