If a sample of glucose (C6H12O6 molecular mass = 180.12 amu/molecule) weighs 4863 amu, how many molecules are in the sample?

Round and enter this answer to ones place. For example ... if the calculated answer was 1546.4, enter 1546

Answers

Answer 1

The number of molecules in a sample of glucose that weighs 4863 amu is 1.6253 × 10²¹ molecules.

How to calculate number of molecules?

The number of molecules in a substance can be calculated by multiplying the number of moles in the substance by Avogadro's number as follows:

no of molecules = no of moles × Avogadro's number

According to this question, a sample of glucose (C6H12O6 molecular mass = 180.12 amu/molecule) weighs 4863 amu. The moles of this sample of glucose can be calculated as follows:

moles = 4863amu ÷ 180.12 amu/molecule

moles = 26.99 moles

No of molecules = 26.99 × 6.02 × 10²³

No of molecules = 1.6253 × 10²¹ molecules.

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Related Questions

which statement correctly describes archaeal cell walls? multiple choice many have peptidoglycan. some have an outer layer of protein. some have an outer layer of complex polysaccharide and some have an outer layer of protein. some have an outer layer of complex polysaccharide.

Answers

Some have an outer layer of complex polysaccharide and some have an outer layer of protein.

What is meant by polysaccharide?

Important classes of biomolecules include polysaccharides. They are lengthy chains of monosaccharide molecules that make up carbohydrates. These intricate biomacromolecules serve as a crucial energy source for animal cells and as a structural element of plant cells.The polysaccharides starch, cellulose, and glycogen are a few examples of.Polysaccharides are used as stabilisers and dietary fibre in the food industry.Polysaccharides can also be produced by bacteria, for instance while making yoghurt.a big molecule of a carbohydrate. It has several tiny sugar molecules that are chemically bonded together. also known as glycan.Our diet includes a lot of sugar, a disaccharide and isomer of lactose and maltose.

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A liquid in a lab has a density of 1.17 g/cm^3. What is the volume in liters of 3.02 kg of the liquid?

Answers

A liquid's density is a measure of how heavy it is in relation to its measured volume.

Liquid density = 1.17 g / cm^3.

Mass of Liquid = 3.02 kg

1 kg = 1000 g

So, 3.02 kg = 3020.0 g

Using the formula

density of liquid = (mass of liquid) / (volume of the liquid)

By modifying above formula, which gives

volume of the liquid = (mass of liquid) / (density of liquid)

Now, put a value in an expression

Which gives, volume of the liquid = (3020.0 g) / (1.17 g / cm^3)

          = 2581.197 cm^3

As, 1 cm^3 = 0.001 L

Therefore, 2581.197 cm^3 = 2.581197 L

Therefore, the liquid volume is 2.581197 L.

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To find the volume of the liquid in liters, we can use the formula of density the volume of 3.02 kg of the liquid is approximately 2.58 liters.

Given to us is

Mass = 3.02 kg

Density = 1.17 g/cm³

The formula is:

Volume = Mass / Density

First, we need to convert the mass to grams:

3.02 kg = 3,020 g

Next, we can substitute the values into the formula:

Volume = 3,020 g / 1.17 g/cm³

To convert the volume from cubic centimeters (cm³) to liters (L), we need to divide by 1000 (since 1 L = 1000 cm³):

Volume = (3,020 g / 1.17 g/cm³) / 1000

Calculating this expression, we find:

Volume ≈ 2.58 L

Therefore, the volume of 3.02 kg of the liquid is approximately 2.58 liters.

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2. Explain the differences you observed when you added drops of acid or base to the water versus when the drops were added to the phosphate buffer. Explain why this difference occurs.

Answers

When the drops of acid or base were added to the water versus when the drops were added to the phosphate buffer, the pH changed considerably unlike in the phosphate buffer.

This is because the buffer neutralizes the drops of acid or base added to it.

What is a buffer solution?

A buffer solution is an acidic or basic aqueous solution made up of a mixture of a weak acid and either its conjugate base or base and its conjugate acid. A little bit of a strong acid or base applied to it barely affects its pH.

Hence, when drops of acid or base are added to a buffer such as a phosphate buffer, there is no observable change in the pH of the buffer solution. However, a considerable change in pH occurs when drops of an acid or base are added to water.

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predict the direction favored of the following equilibrium equation

Answers

Comparing the stabilities of two negative charges on opposite sides of the equilibrium-arrows is one method for determining whether the reactants or products are preferred in an equilibrium. Because this side has less energy, it is preferred, whichever side has the more stable negative charge.

How do you know which side is favored at equilibrium?It is well knowledge that nature prefers low energy conditions. Remember that we may use the Protocol to compare the stability of two negative charges, where the more stable negative charge has a lower energy, and that this evaluation can be done while keeping this concept in mind.Comparing the stabilities of two negative charges on opposite sides of the equilibrium-arrows is one method for determining whether the reactants or products are preferred in an equilibrium. Because this side has less energy, it is preferred, whichever side has the more stable negative charge.Considering what transpires once you reach the more stable negative charge is one method to understand why this assertion is correct.Because you are content with where you are—a place of low energy—if you have recently moved to a more solid job, you are less likely to react negatively.By contrasting the negative charges on an oxygen and a nitrogen in the aforementioned example, we are putting the protocol to use. Since the charges on two atoms in the same row of the periodic table are being compared, we use electronegativity (#2 on the Protocol) to ascertain the relative stabilities.

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Write the expression for Kc for the following reactions. In each case indicate whether the reaction is homogeneous or heterogeneous.Part A3NO(g)⇌N2O(g)+NO2(g)Kc=[N2O][NO2]3[NO][NO]3[N2O][NO2]3[NO][N2O][NO2][N2O][NO2][NO]3SubmitMy AnswersGive UpPart B3NO(g)⇌N2O(g)+NO2(g)reaction ishomogeneousheterogeneousSubmitMy AnswersGive UpPart CCH4(g)+2H2S(g)⇌CS2(g)+4H2(g)Kc=[CH4][H2S]2[CS2][H2]4[CH4][H2S]2[CS2][H2]2[CS2][H2][CH4][H2S][CS2][H2]4[CH4][H2S]2SubmitMy AnswersGive UpPart DCH4(g)+2H2S(g)⇌CS2(g)+4H2(g)reaction ishomogeneousheterogeneous

Answers

All the given reactions are heterogeneous reactions.

How to determine whether the reaction is homogeneous or heterogeneous?

A reaction is classified as homogeneous or heterogeneous based on the phases of the reactants and products involved. A homogeneous reaction is one that occurs in a single phase, while a heterogeneous reaction is one that occurs across different phases. For example, if a reaction involves a solid, liquid, and gas, then it would be considered heterogeneous.

Part A: 3NO(g)⇌N2O(g)+NO2(g)

Kc = [N2O][NO2]^3 / [NO]^3

This reaction is heterogeneous because it involves a change in the number of moles of gas on both sides of the equation.

Part B: 3NO(g)⇌N2O(g)+NO2(g)

reaction is heterogeneous

Part C: CH4(g)+2H2S(g)⇌CS2(g)+4H2(g)

Kc = [CS2][H2]^4 / [CH4][H2S]^2

This reaction is heterogeneous because it involves a change in the number of moles of gas on both sides of the equation.

Part D: CH4(g)+2H2S(g)⇌CS2(g)+4H2(g)

The reaction is heterogeneous.

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Reaction 1: CO(g) + 3 H2(g) = CH4(9) + H2O(9) K (CH4] [H,O] (CO][1,13 Reaction 2 CO2(g) + H2(9) CO(g) + H2O(9) CO||H,0] (CO2][H.] Reaction 3: CH4(9) + 2 H2O(g) = CO2(g) + 4 H2 (9) K3 =? The chemical equations and equilibrium expressions for two reactions at the same temperature are given above. Based on the information, which of the following expressions can be used to calculate the value of K3 for reaction 3 at the same temperature? A K3=( - Kı) + (- K2) B K3= (- K1) - (- K2) с K3 = K x K2 D K3 = KK

Answers

An expressions can be used to calculate the value of K3 for reaction 3 at the same temperature is

K3 ⇒ ( - Kı) + (- K2)

To determine the value of K3 for reaction 3 at the same temperature, use the expression as

"K3 ⇒ (- K) + (- K2)".

This is thus because the concentrations of the reactants and products in a reaction affect the equilibrium constant for that reaction. Since reaction 3 is the result of the combination of reactions 1 and 2, it is possible to compute reaction 3's equilibrium constant by multiplying reactions 1 and 2's equilibrium constant. In the instance of this issue, it is clear that the results of reaction 1 and reaction 2 both serve as the reactants for reaction 3 and its products, respectively. The equilibrium constant of reaction 3 at the same temperature as reactions 1 and 2 is therefore

K3 ⇒ K1 x K2.

It's vital to remember that the temperature might have an impact on the relationship between the equilibrium constants of a reaction, making it not always possible to combine reactions to produce a new equilibrium constant.

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N2 + 3H2 → 2NH3

How many grams of NH3 could be made using 6 moles of H2 and excess N2?

__________ g of NH3

Answers

Answer:

68grams

Explanation:

Simply because if 3 moles = 2(14 + 3)

3 moles = 34 grams

6 moles = (6 × 34) ÷ 3

= 68grams

Propose structures for hydrocarbons that give the following products on oxidative cleavage by KMnO4 or O3 :

Answers

The non - terminal alkynes gives the carboxylic acid on the oxidative cleavage by the KMnO₄ or O₃.

The non - terminal alkynes have the triple bond in any positions other than the end position. The non - terminal alkynes gives carboxylic acid on the oxidative cleavage by the KMnO₄ or O₃. The oxidative cleavage is the reaction in which carbon - carbon bond cleaved with the oxidation of the carbons. The ozonolysis is the method of the oxidative cleavage of the alkynes and the alkene.

The alkyne ozonolysis is the example of an oxidative ozonolysis. The O₃ is the reactive allotrope of oxygen.

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What type of solid will each of the following substances form in its solid state? Choices to considerare metallic, ionic, covalent, or molecular solids. a. CyH6 d. Co,-molecular g. AI b. Nazo e. N:Os h. C(diamond) c. sio, - Covalent f. NaNO3 i. SO

Answers

a. CyH6 - Molecular solid, b. Na - Ionic solid, c. SiO2 - Covalent solid, d. Co - Metallic solid, e. N2O - Molecular solid, f. NaNO3 - Ionic solid, g. Al - Metallic solid, h. C(diamond) - Covalent solid, i. SO2 - Molecular solid

CyH6, N2O, and SO2 are molecular solids, as these compounds are composed of individual molecules that are held together by weak intermolecular forces. Na is an ionic solid, as it is composed of positively charged sodium ions and negatively charged chloride ions held together by strong electrostatic forces. SiO2 is a covalent solid, as it is composed of individual Si-O covalent bonds.Co is a metallic solid, as it is composed of a metallic lattice of metal atoms held together by metallic bonds. NaNO3 is an ionic solid, as it is composed of positively charged sodium ions and negatively charged nitrate ions held together by strong electrostatic forces.

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Classify each of the following molecular art illustration as a chemical reaction or a physical change. Selection: Consider the reaction ofNOandCOto formN 2​andCO 2​. according to the balanced equation.2NO(g)+CO(g)→N 2​( g)+2CO 2​( g)Identify the excess reactant, the limiting reactant, and the product(s) using the molecular art. (Black spheres are carbon, blue spheres are nitrogen, and red spheres are oxygen)

Answers

This is a chemical reaction. The excess reactant is NO (there are two nitrogen molecules and one oxygen molecule), the limiting reactant is CO, and the products are N2 and CO2.

What is nitrogen?

Nitrogen is a colorless, odorless, tasteless, and mostly inert gas that makes up 78% of Earth's atmosphere. It is one of the most abundant elements on the planet and is found in both organic and inorganic forms. In organic form, nitrogen is an important part of all proteins, nucleic acids, and other molecules essential to life. In its inorganic form, nitrogen is an essential component of all fertilizers and is used in the production of plastics, explosives, and other industrial chemicals. Nitrogen is also used to create nitrous oxide, which is used as an anesthetic for medical procedures. Nitrogen is essential for the growth of plants, and it is also essential for the production of ammonia, which is a key component of many fertilizers.

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For each of the following unbalanced reactions, suppose exactly 5.00 moles of each reactant are taken. Determine which reactant is limiting, and also determine what mass of the excess reagent will remain after the limiting reactant is consumed. For each reaction, solve the problem three ways: i. Set up and use Before Change-After (BCA) tables. ii. Compare the moles of reactants to see which runs out first. iii. Consider the amounts of products that can be formed by completely consuming each reactant a. Cacz(s) + H2O(l) + Ca(OH),(8) + CH2(9) b. AgNO3(aq) + Al(s) + Ag(s) + Al(NO3)2 (aq)

Answers

A balanced chemical equation gives the relationship between the number of moles of reactants and the number of moles of products. This is called reaction stoichiometry.

what is meant by stoichiometry?

Chemical The quantitative analysis of the reactants and products involved in a chemical process is known as stoichiometry. Stoichiometry is a combination of the Greek words "stoikhein," which means element, and "metron," which means measure.

One of the most crucial topics in general chemistry is stoichiometry. Normally, it comes up after talking about unit conversions and atom components. Although it's not tough, the word's convoluted sound turns away many students. It may be described as "mass relations" for this reason. It alludes to masses of reactants, products, and the constituents that make up a complex.

solving stoichiometry issues

equations that balance

Conversion of grams to moles

determining molar mass

mole ratio calculations

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Label the species in the atomic-scale picture to represent the result when equimolar amounts of
aqueous barium hydroxide and aqueous iron(II) chloride are combined.
Ba
FeCl2
Fe(OH)2
Ba(OH)2
Ba2-
Cl2
CI
Fe
BaCl2
Fe2-
OH
H2O
solid =
Fe(OH)2

Answers

Answer: Green bubble --> Ba2+, Red bubble --> Cl-1, Blue bubble --> Fe2+, Yellow bubble --> OH-1, Solid --> Fe(OH)2 precipitate

What happens when you mix an aqueous solution of barium hydroxide and an aqueous solution of ferric chloride?

A mixture of aqueous barium hydroxide and aqueous ferric chloride gives barium chloride and ferric hydroxide. This reaction is shown below.

Ba(OH)2 (aq) + FeCl2 (aq)--> BaCl2(aq) + Fe(OH)2 (ppt)

Explanation:

Therefore, after reaction in an aqueous solution, there is 1 equivalent of free Ba2+ ions, 2 equivalents of free Cl-1 and Fe(OH)2 ppt. Fe(OH)2 precipitates with 1 equivalent of Fe2+ and 2 equivalents of OH-1 ions.

Hence,

Green bubble--> Ba2+

Red bubble --> Cl-1

Blue bubble --> Fe2+

Yellow bubble --> OH-1

Solid = Fe(OH)2 precipitate

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Give two examples of elements for each of the following categories.a. noble gasesb. halogensc. alkali metalsd. alkaline earth metals

Answers

The two examples of each is given as :

1) Noble gases =  He , Ne

2) Halogens = F, Cl

3) Alkali metals = Li, Na

4) Alkaline earth metals = Be, Mg

1) The noble gases are the elements in the periodic table belongs to the 18 group : He, Ne, Ar, Kr, Xe, Rn, Og.

2) The halogens are the elements in the periodic table belongs to the group 17 : F, Cl, Br, I, At.

3) The alkali metals are the elements in the periodic table belongs to the group 1st : H, LI, Na, K, Rb, Cs, Fr.

4) The alkaline earth metals  are the elements in the periodic table belongs to the group 2nd : Be, Mg, Ca, Sr, Ba, Ra.

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choose the k sp expressions for the following reactions. ca 3 (po 4 ) 2 (s) 3ca 2 (aq) 2po 4-3 (aq) k sp

Answers

The k sp expressions for the reactions is Ks is [Ca2+]3 and [PO4 3+]2.Ks (solubility product) is the result of multiplying the calcium ion concentration by the phosphate ion concentration.

Discover Ks (solubility product)?

Ks (solubility product) is the result of multiplying the calcium ion concentration by the phosphate ion concentration. When salt is introduced to water, it dissolves and the molecules split apart into ions. The following equation can be used to express it:

Ca3(PO4)2(s) <—> 2PO4 3+ with 3Ca2+ (aq)

The molecule's state is indicated by the letters s and aq. S stands for solid, and AQ for aqueous.

K = [D]d. [C]c/ [A]a. [B]b is the formula used to represent this constant in chemical equilibrium.

One further thing to keep in mind is that the constant only accounts for gases and aqueous molecules; solids and liquids have no bearing on it. In the equation, values are replaced by 1, and the constant is not affected by solids or liquids.

Since Ca3(PO4)2 is now solid, it has no effect on Ks; in this situation, the only relevant concentrations are those of Ca and PO4. This ions' expression of Ks is because they are products.

Ks=[Ca2+]3 and [PO4 3+]2.

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which of the following has the greatest electronegativity difference between the bonded atoms? which of the following has the greatest electronegativity difference between the bonded atoms? f2 hcl co kbr

Answers

Cesium fluoride has the largest electronegativity difference of all of these diatomic compounds, with a difference of 3.19. It is important to note that because oxygen gas is a diatomic.

molecule composed of two atoms of the same element, there is no difference in electronegativity between its atoms. It has an EN of zero.Caesium fluoride may be made by reacting caesium hydroxide (CsOH) with hydrofluoric acid (HF), and the resultant salt can be refined by recrystallization. The following is the reaction: CsOH + HF CsF + H2O CsOH + HF CsF + H2O Another method for producing caesium fluoride is to react caesium carbonate (Cs2CO3) with hydrofluoric acid, and the resultant salt may then be refined by recrystallization. The following is the reaction: 2 HF + 2 CsF + H2O + CO2 = Cs2CO3 In organic solvents, CsF is more soluble than sodium fluoride or potassium fluoride. It is accessible in anhydrous form, and if water has been absorbed, it is simple to dry in vacuo by heating at 100 °C for two hours. [6] CsF has a vapor pressure of one.

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Sucrose (C12H22O11) reacts with potassium chlorate according to the following balanced equation:
C12H22O11 (s) + 8 KClO3 (s)  12 CO2 (g) + 11 H2O (g) + 8 KCl (s)

Suppose 3.5 moles of C12H22O11 are mixed with 21.0 moles of KClO3. Identify the limiting reactant, then
calculate how many moles of each product (CO2, H2O and KCl) will be formed in this reaction.

Answers

Taking into account definition of the reaction stoichiometry, potassium chlorate is the limiting reactant and 31.5 moles of CO₂, 28.875 moles of H₂O and 21 moles of KCl are formed when 3.5 moles of C₁₂H₂₂O₁₁ are mixed with 21.0 moles of KClO₃.

Reaction stoichiometry

In first place, the balanced reaction is:

C₁₂H₂₂O₁₁ (s) + 8 KClO₃ (s) → 12 CO₂ (g) + 11 H₂O (g) + 8 KCl (s)

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

C₁₂H₂₂O₁₁= 1 molesKClO₃= 8 molesCO₂= 12 molesH₂O= 11 molesKCl= 8 moles

What is limiting reagent

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction.

Limiting reagent in this case

To determine the limiting reagent, the following rule of three can be applied: if by stoichiometry 1 mole of C₁₂H₂₂O₁₁ reacts with 8 moles of KClO₃, 3.5 moles of C₁₂H₂₂O₁₁ reacts with how many moles of KClO₃?

moles of KClO₃= (8 moles of KClO₃×3.5 moles of C₁₂H₂₂O₁₁)÷1 mole of C₁₂H₂₂O₁₁

moles of KClO₃= 28 moles

But 28 moles of KClO₃ are not available, 21 moles are available. Since you have less moles than you need to react with 3.5 moles of C₁₂H₂₂O₁₁, KClO₃ will be the limiting reagent.

Moles of each product formed

Considering the lomiting reactant, he following rules of three can be applied:

if by reaction stoichiometry 8 mole of KClO₃ form 12 moles of CO₂, 21 moles of KClO₃ form how many moles of CO₂?

moles of CO₂= (21 moles of KClO₃×12 moles of CO₂)÷8 mole of KClO₃

moles of CO₂= 31.5 moles

if by reaction stoichiometry 8 mole of KClO₃ form 11 moles of H₂O, 21 moles of KClO₃ form how many moles of H₂O?

moles of H₂O= (21 moles of KClO₃×11 moles of H₂O)÷8 mole of KClO₃

moles of H₂O= 28.875 moles

if by reaction stoichiometry 8 mole of KClO₃ form 8 moles of KCl, 21 moles of KClO₃ form how many moles of KCl?

moles of KCl= (21 moles of KClO₃×8 moles of KCl)÷8 mole of KClO₃

moles of KCl= 21 moles

Finally, 31.5 moles of CO₂, 28.875 moles of H₂O and 21 moles of KCl are formed.

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a gas is compressed from a volume of 5.42 l to a volume of 2.75 l by an external pressure of 748 torr. which of the following correctly reflect the calculations required to determine the work done on/by the system (the gas)?

Answers

Reflect the calculations required to determine the work done on/by the system 1 atm⋅L = 101.3 J and 1 atm = 760 torr

ΔV = -2.67 L

w = 266 J

What is meant by calculations ?

The method of estimating a number or amount by using information you currently have and adding, subtracting, multiplying, or dividing numbers:A few mistakes were present in the computations that you performed or made.I worked on that equation for hours, yet I still got the erroneous answer.An intentional mathematical process known as a computation converts one or more inputs into one or more outputs or results.The term is used in many different contexts, ranging from the precise mathematical calculation of employing an algorithm to the nebulous heuristics of calculating a strategy in a competition or calculating the likelihood of a successful relationship between two individuals.

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Calculate the molar mass of each compound given below. Keep at least one decimal place in atomic masses from the periodic table. A chemist requires 0.448 mol Na2CO3 for a reaction. How many grams does this correspond to? A sample of C3H6 has 2.40 times 1074 H atoms. How many carbon atoms does the sample contain? What is the total mass of the sample? The 64.8-g sample of the compound X2Os contains 48.0 g of oxygen atoms. What is the molar mass of element X?

Answers

47.264grams of 0.448 mol Na2CO3 is used for a reaction, the number of carbon atoms the sample contains is  1288.8and  the molar mass of element X is 14g/mol.

(a) Number of moles of Na2CO3 (M) = 0.448

Molar mass of Na2CO3 (W) = 2 x 22.9 + 1 x 12.0 + 3 x 15.9 = 105.5g

The mass of Na2CO3 required for the reaction = m

m = Molar mass x moles = 105.5x0.448 = 47.264g

The mass of Na2CO3 required = 47.264g

(b) Given sample = C3H6

number of atoms of hydrogen = 2.4 x 1074 = 2577.6

For every 6 hydrogens in propene there are 3 carbons present.

If there are 2.4 x 1074 Hydrogen atoms present then there are 3/6 x 2.4 x 1074  carbon atoms present.

Number of carbon atoms = 1288.8 atoms

(c) The compound = X2O5

The mass of compound (m) = 64.8g

The mass of oxygen atoms(m1) = 48g

Number of moles of oxygen = 48/16 = 3 where molar mass is 16g/mol

the number of moles of the given element X = x

From the equation 5 atoms of oxygen is 3 mol and 2 atoms of element X is n then 5 : 3 = 2 : x then the number of moles of X = 1.2

The mass of element X = 64.8 - 48 = 16.8g

The molar mass of X = 16.8/1.2 = 14g/mol

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Charcoal reacts with oxygen according to the equation C (s) + O2 (g) → CO2 (g). Which of the following changes would cause the greatest increase in the rate of reaction?
a. decreasing the concentration of O2(g)
b. decreasing the pressure of O2 (g)
c. using charcoal in powdered form
d. using charcoal in lump form

Answers

Answer:

c. using charcoal in powdered form.

Explanation:
The rate of a chemical reaction is affected by many factors, one of which is the surface area of the reactants. When the surface area of a solid reactant is increased, the rate of the reaction increases because it increases the number of reactive sites available for collision. Therefore, using charcoal in powdered form would increase the rate of reaction as the surface area of charcoal would be greater than in lump form.

On the other hand, decreasing the concentration of O2(g) would decrease the rate of reaction as there will be fewer O2 molecules for collision, decreasing the pressure of O2 (g) would affect the rate of reaction in a lesser extend, as pressure is not a major factor in this reaction. Using charcoal in lump form wouldn't affect the rate of the reaction as much as changing its form from lump to powdered.

calculate the percent by mass composition of c (carbon) in the compound ch4 (round your answer to 3 significant figures at the end.) g

Answers

The percent by mass composition of c (carbon) in the compound ch4 is 10%.

How much carbon is there in CH4 by mass?

As an example, let's look at methane, or CH4. Methane's formula weight is [12.01 + (4 x 1.008)] = 16.04 (grams per cubic meter). Methane has a mass that is made up of (12.01/16.04) x 100 = 74.87% carbon and (4.032/16.04) x 100 = 25.13% hydrogen.

Sulfuric acid's percentage makeup of each element: Hydrogen% is equal to (2.016/98.07) x 100, or 2.0556%. Sulfur% = 32.06 98.07 100 = 32.69% Oxygen% = (63.996/98.07) 100 = 65.25%.

(1) CO = 80% CH, equals 20%; (2) CO = 90% CH4 = 10%.

Confirm that about 82.6% of C4H10's mass is made up of carbon. The molar masses of hydrogen and carbon on the periodic table are, respectively, 12.0 and 1.01.          

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identify reagents that can be used for the following synthesis: 1) h2, pt; 2) br2, hv ; 3) naoet 1) h2, lindlar's catalyst; 2) br2, hv ; 3) t-buok 1) na, nh3(liq); 2) br2, hv ; 3) naoet 1) h2, pt; 2) br2, hv ; 3) t-buok

Answers

Reagents that can be used  naoet. In organic chemistry, the electrophiles and nucleophiles are the two main categories of reagents.

For what purposes do reagents in chemistry?Reagents are frequently employed to conduct tests to determine whether particular chemicals are present because their interactions with the substance or other related substances result in specific responses. Reagents and reactants are two entirely distinct concepts, despite the fact that the terms are occasionally used synonymously.Reagents are listed as Grignard reagent, Tollens reagent, Fehling reagent, Millon reagent, Collins reagent, and Fenton reagent. The word "reagent" does not, however, appear in all reagent names. Solvents, enzymes, and catalysts are additional reagents. The use of reagents can be restricted.In organic chemistry, the electrophiles and nucleophiles are the two main categories of reagents.              

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during neuronal signaling, a change in membrane potential will cause sodium channels to open and let Na+ ions diffuse down their concentration gradient into the cell. which of the following helps establish the concentration gradient necessary for this process to occur?

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The one which helps to  establish the concentration gradient necessary for this process to occur is the Na⁺/K⁺ pump.

During neuronal signaling, a change in the membrane potential will cause the  sodium channels to open and let the Na⁺ ions diffuse down the concentration gradient into the cell. The sodium - potassium pump is an enzyme. The sodium - potassium pump helps to maintain the osmotic equilibrium and the potential in the cells.

Thus, the Na⁺/K⁺ pump helps to  establish the concentration gradient necessary for this process to occur.

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which is would be the empirical formula of a compound that has 4 moles of oxygen and 10 moles of nitrogen?

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The empirical formula for a compound is 2N2O if it contains 4 moles of oxygen and 10 moles of nitrogen. A compound is a material that results from the chemical bonding of two or more elements.

The two types of bonding that hold the atoms of a molecule together most frequently are ionic and covalent. In chemistry, a substance's empirical formula is the simplest whole number ratio of the atoms that are present in it. The simple illustration of this concept is the empirical formula of sulphur monoxide, which is just NO.

Nitrogen = 10/14 = 0.71 M of nitrogen = 4/16 = 1/4 = 0.2 M of oxygen

Atomic mass is equal to 0.2/0.2 and 1

Atomic mass = 0.71/0.2 = 3.6, or around 4, and empirical formula = 2N2O.

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Incorrect Question 8 0/1 pts Which piece(s) of glassware is the most precise based on significant figures? Graduated Cylinder What value of R2 indicates the highest level of precision? 0.972 Answer 1: Graduated Cylinder Answer 2: 0.972

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Graduated Cylinder What value of R2 indicates the highest level of precision,this answer is correct.

What is the Cylinder ?

The cylinder is a three-dimensional geometric shape with two parallel bases that are connected by a curved surface. It has two circular faces at the top and bottom and a curved surface connecting the two faces. The curved surface of the cylinder is a surface of revolution. A cylinder has two properties, namely, its height and its radius. The volume of the cylinder is equal to the product of its radius and height and is equal to the area of its bases multiplied by the height of the cylinder. Cylinders are used in a variety of applications such as the storage of liquids and gases, the manufacture of pipes, and the construction of machines. The cylinders can also be used for various purposes such as for hydraulic cylinders, for printing presses, and for containers in the chemical industry.

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which of the following is not one of the major minerals? group of answer choices copper magnesium chloride calcium

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The choices copper magnesium chloride calcium is cellular repair.

What is magnesium chloride?a two-chloride ion and one magnesium-based inorganic molecule. The substance is utilized in medicine as a source of magnesium ions, which are necessary for numerous biological processes. The family of inorganic compounds known as magnesium chlorides has the formula MgCl2, where x can be any value between 0 and 12. These salts are colorless or white solids that are very soluble in water. These substances, both in their compounds and in their solutions, are found in nature and have a wide range of useful applications. Magnesium chloride is an over-the-counter drug used to prevent and treat low levels of magnesium in the blood. Magnesium is necessary for the healthy operation of the heart, muscles, bones, and neurons.

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Convert grams of fe2o3 to grams of fe. select the correct units and conversion factors for each step in the following unit roadmap.
Fe2O3 (s) + 3 CO(g) → 2Fe(s) + 3 CO2(g)

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To convert grams of Fe₂O₃ to grams of Fe, we can use the balanced chemical equation for the reaction between Fe₂O₃ and CO.

The balanced equation for the reaction between Fe₂O₃ and CO is: Fe₂O₃(s) + 3 CO(g) → 2Fe(s) + 3 CO₂(g)

From this equation, we can see that 1 mole of Fe₂O₃ reacts with 3 moles of CO to produce 2 moles of Fe and 3 moles of CO₂. This means that the ratio of Fe to Fe₂O₃ is 2:1.

The conversion factor between grams of Fe₂O₃and grams of Fe is:

1 mole Fe₂O₃= 159.69 g Fe₂O₃

1 mole Fe = 55.845 g Fe

Steps:

Start with the given mass of Fe₂O₃in grams

Convert grams to moles of Fe₂O₃using the molar mass of Fe₂O₃ (159.69 g/mol)

Use the stoichiometry ratio of 2:1 to find the number of moles of Fe produced from the number of moles of Fe₂O₃

Convert the number of moles of Fe to grams using the molar mass of Fe (55.845 g/mol)

In conclusion, in order to convert grams of Fe₂O₃to grams of Fe, we used the balanced chemical equation to identify the molar ratio between the reactants and products.

Then, we used the molar mass of Fe₂O₃ and Fe to convert between moles and grams. It is important to be aware of the stoichiometry of the reaction in order to calculate the correct number of moles of Fe produced.

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The complete question is:

Convert grams of Fe₂O₃ to grams of Fe. Mention the correct units and conversion factors for each step.

Fe₂O₃(s) + 3 CO(g) → 2Fe(s) + 3 CO₂(g)

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identify the two compounds that have the longest atmospheric lifetime in years. give their lifetime in years. True Or False

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Inter-molecular interactions between gas particles have a stronger influence on the properties as pressure rises.

Fluoridated gases have the longest atmospheric lifetime. In a gas, the particles are dispersed. They resemble a "ideal gas," where there is little particle interaction and collisions are completely elastic, under normal pressure and at low temperatures. Inter-molecular interactions between gas particles have a stronger influence on the properties as pressure rises. Because of the space between atoms or molecules, the majority of gases are transparent.  Like fluorine and chlorine, some of them have almost no color. Gases usually exhibit weaker responses to electric and gravitational fields than other forms of matter. Gases are less dense and more viscous than liquids and solids.

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compare and contrast the electromagnetic spectra and the atomic emission spectra. please use proper grammar and mechanics.

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The electromagnetic spectrum and the atomic emission spectra are both related to the study of light and its properties. When an atom absorbs energy, electrons move to a higher energy level, and when they return to a lower energy level, they release energy in the form of light.

The electromagnetic spectrum is a range of all types of electromagnetic radiation, including radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. These types of radiation have different wavelengths, frequencies, and energy levels. The electromagnetic spectrum is a continuous spectrum, with no clear boundaries between the different types of radiation.On the other hand, atomic emission spectra refer to the light emitted by atoms when they are excited. The light emitted by atoms is always specific to the element and the energy level of the atom. . This light is specific to the element and the energy level of the atom, and it results in a line spectrum, which is made up of specific and discrete lines of different colors.In summary, the electromagnetic spectrum is a continuous range of all types of electromagnetic radiation, while atomic emission spectra refer to the specific light emitted by atoms when they are excited, resulting in a discrete line spectrum. The electromagnetic spectrum provides an overview of all types of radiation and their characteristics, while atomic emission spectra allow for the identification of specific elements by analyzing the light they emit.

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How much will the temperature a 60 g sample of iron (specific heat = 0.214 cal/g/*C) change if 2000 calories are added to it?

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Answer:

37.36 degrees Celsius

Explanation:

The temperature change of a substance can be calculated using the formula:

ΔT = Q / (m * Cp)

Where:

ΔT is the change in temperature (in degrees Celsius)

Q is the heat added or removed (in calories)

m is the mass of the substance (in grams)

Cp is the specific heat capacity of the substance (in calories per gram per degree Celsius)

For a 60g sample of iron with a specific heat of 0.214 cal/g*C and 2000 calories added to it, the temperature change would be:

ΔT = 2000 / (60 * 0.214) = 37.36 degrees Celsius

a steel ball of mass 0.400 kg is fastened to a cord that is 0.600 m long and fixed at the far end. the ball is then released when the cord is horizontal. at the bottom of its path, the ball strikes a 2.00 kg steel block initially at rest on a frictionless surface. the collision is elastic. (a) Find the speed of the ball just after the collision.
(b) Find the speed of the block just after the collision.

Answers

(a) The speed of the ball just after the collision is 0.13636 m/s. (b) The speed of the block just after the collision is 0.272728 m/s.

(a) The speed of the ball just after the collision can be found using the conservation of momentum principle. Before the collision, the momentum of the system is zero (since the block is at rest). After the collision, the momentum of the system is equal to the momentum of the ball and the block moving together.

Let vf be the final velocity of the ball and block after the collision. Then, the initial momentum of the system is 0, and the final momentum is given by:

= 0.400 kg x vf + 2.00 kg x vf

= (0.400 kg + 2.00 kg) x vf

By solving, we get:

vf = 0.400 kg / (0.400 kg + 2.00 kg) x √(g x 0.600 m)

vf = 0.1732 x √(g x 0.600 m)

The speed of the ball just after the collision is given by:

v = vf x 0.400 kg / (0.400 kg + 2.00 kg)

= 0.1732 x √(g x 0.600 m) x 0.400 kg / 2.400 kg

= 0.0726 x √(g x 0.600 m)

= 0.0726 x √(9.8 x 0.600)

= 0.0726 x 1.8782971

= 0.13636 m/s

(b) The speed of the block just after the collision is given by:

v = vf x 2.00 kg / (0.400 kg + 2.00 kg)

= 0.1732 x √(g x 0.600 m) x 2.00 kg / 2.400 kg

= 0.1452 x √(g x 0.600 m)

= 0.1452 x √(9.8 x 0.600 m)

= 0.1452 x 1.8782971

= 0.272728 m/s

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