If a transformer doubles its input voltage, what is the current in the secondary coil if the primary coil is 10 A.

Answers

Answer 1

Answer:

20Amp

Explanation:

Using the transformer formula

Vs/Vp = Ns/Np = Ip/Is

Vs/Vp = Ip/Is

Vp is the primary voltage = input voltage

Vs is the secondary voltage = output voltage

Ip is the current in the primary coil

Is is the amount of current in the secondary coil.

If the transformer doubles its input voltage Vp, its output voltage Vs will be

decreased by 2 but the output current will be doubled

Given the input current Ip = 10A, the current in the secondary coil (output current) will be doubled i.e Is = 2(10) = 20A

Answer 2

The current in the secondary coil be "50 A". To understand the calculation, check below.

Current and Voltage

According to the question,

Current in primary coil, [tex]I_{in}[/tex] = 10 A

We know the relation,

Power = [tex]V_{in} I_{in}[/tex] = [tex]V_{out} I_{out}[/tex]

then,

→ [tex]V_{in} I_{in}[/tex] = [tex]V_{out} I_{out}[/tex]

By substituting the values,

   [tex]V_{in}[/tex] × 10 = 2 [tex]V_{in} I_{out}[/tex]

By applying cross-multiplication,

           10 = 2 [tex]I_{out}[/tex]

         [tex]I_{out}[/tex] = [tex]\frac{10}{2}[/tex]

                = 5 A

Thus the response above is correct.

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Related Questions

state the principle of conservation of energy​

Answers

Answer:

Principal of Conservation of Energy states that " Energy is neither created nor destroyed. However, It is just converted to other forms of energy"

Assume that a machine puts out 8000 joules of work when the user puts in 10,000 joules of work. What is the efficiency of the machine?

Answers

Answer:

80 Percent

Explanation:

E=energy output/energy input×100

E=8000/10000×100

E=0.8×100

E=80 percent.

Mark brianliest if my answer suit your question

If the machine put, in 8000 J, and the user puts 10,000 J of work then the efficiency of the machine will be equal to 80%.

What is Work?

Work is a physics term used to describe the transfer of energy that takes place when an object changes above a distance because of an external force, at least some of which is given in the vector of the dislocation. The element of the force acting all along the path multiplied by the length of the path can be used to calculate work if the force is constant.

Mathematically, this idea is expressed as W = fd, where W is the effort and f is the force multiplied by d, the distance. Work is completed whenever the force is applied at an angle with about the displacement.

As per the data provided in the question,

Total input energy = 10,000 J

Total output energy = 8,000 J

Then, the efficiency (η) of the machine will be,

η = (output energy/input energy) × 100

η = 8000/10000 × 100

η = 80%.

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The ________ of a particle for a given ‘Interval of time’ is defined as the ratio of total distance travelled to the total time taken.

uniform speed
average speed
uniform velocity
average velocity

Answers

Answer:

The average speed of a particle for a given ‘Interval of time’ is defined as the ratio of total distance travelled to the total time taken.

Explanation:

To find the average speed we take the total

distance traveled divided by the time interval.

If there are a boys pulling a rubber
with the same amount of force what will happen?

Answers

Answer:

The rubber will expand to its maximum and then tear in the middle.

Explanation:

Answer:

Hey!

Well if they continue to pull the rubber band, it would eventually rip apart right in the middle as the force could not be contained by the elastic fibres and had reached its maximum extension!

Explanation:

HOPE THIS HELPS!!

Why would you expect sodium (Na) to react strongly with chlorine?

Answers

Answer:

Na is a alkaline metal, it can very easy give an electron, and form positive ion.  Cl is a very strong non-metal(halogen),  and it is able to take electron, and form negative ion. Positive and negative ion can attract to each other and form ionic bond.

Calculate the transfer of energy by a force of 15N when it moves the object by a distance of 5m
a. In the direction of the force

b. In a direction at 60° to the direction of the force


c. At right angles to the force

NEED EXPLAINATION

Answers

Answer:

a) 75 J

b) 37.5 J

c) 0

Explanation:

Work is the force exerted on an object causing it to move, Work is the product of force and displacement. Work is not done if the force and displacement are at right angles to each other. It is given by:

[tex]Work(energy)=Fxcos(\theta)[/tex]

F is the force, x is the displacement and Θ is the angle between force and displacement.

a) Force (F) = 15N and distance (x) = 5. Since it is in the direction of the force, Θ = 0

[tex]Work(energy)=Fxcos(\theta)= 15*5*cos(0)=75J[/tex]

b) Force (F) = 15N and distance (x) = 5.  Θ = 60

[tex]Work(energy)=Fxcos(\theta)= 15*5*cos(60)=37.5J[/tex]

c) Force (F) = 15N and distance (x) = 5.  Θ = 90

[tex]Work(energy)=Fxcos(\theta)= 15*5*cos(90)=0[/tex]

What are some advantages
and disadvantages to using
superconductors as electric
transmission lines

Answers

Answer:

Insulators show very high resistance to electricity. Conductors like copper show some resistance. Another class of materials show no resistance at all when cooled to very low temperatures, cooler than the coolest deep freezer. Called superconductors, they were discovered in 1911.

Explanation: i looked it up

An astronaut is moving in space when a big explosion occurs about 50 meters behind him. How will the astronaut come to know about the explosion?
Choose:--
From the sound of the explosion
From the light due to the explosion
From light and sound due to the explosion
From the vibrations due to the explosion

Answers

Answer:

The correct answer is B.

The astronaut will know due to the light from the explosion.

Explanation:

Sound and vibrations require a medium such as air to travel through. Space, there is no air. Only a vacuum. So sound and vibrations are unable to travel. Light requires no medium to travel. It can go through a vacuum.  

Therefore the Astronaut will see a bright flash of light as it travels from the explosion to outer space. It is also important to note that light can travel very far because nothing else interacts with its wave particles and as such, it cannot be impeded.

Cheers!

A) Is it possible for an object that, object with zero acceleration have velocity? If yes give an example if not give its proof.

Answers

Answer:

Yes, in case of uniform velocity

Explanation:

This is the case of uniform velocity. If a body covers equal displacement in equal intervals of time, then the velocity of a body is said to be ‘Uniform Velocity’. It meas that the velocity of a body remains constant during the motion and it does not change.

Since, acceleration is defined as the rate of change of velocity.

Therefore, if there is no change in velocity or in other words the change in velocity is zero, then the acceleration is also zero.

a = ΔV/t = 0/t

a = 0 m/s²

So, the acceleration of the body is 0 m/s², but it has a uniform velocity

Hence, it is possible for an object that, object with zero acceleration have velocity, which is the case case of uniform velocity.

4. ____________ occurs when one object slides over another.
a. Sliding friction
b. Static friction
c. Rolling friction
d. Net force

Answers

Answer:

A. Sliding friction

Explanation:

Sliding friction is weaker than static friction

Answer:

Rolling Friction

Explanation:

I know this because the definition of rolling friction is : type of friction that happens when one body rolls over another

Calculate the weight of an object on earth surface having 600km from surface of earth?

Answers

Your question seems to contradict itself. You said "on Earth surface" and then you said "600 km from surface of the Earth" ... both in the same sentence.

I'll assume that the object is actually 600 km from surface of the Earth, because that makes the question (and the answer) more interesting.

We know that the weight of any object is (mass) x (gravity). Those are the two numbers we need in order to calculate the object's weight. Mysteriously, you haven't told us either one.  We'll call the object's mass ' M ' (clever, eh ?), and we'll calculate the value of gravity up there where the object is located.

We now that the acceleration of gravity is inversely proportional to the square of the distance between the centers of two objects.  When an object is on the Earth's surface, it's 6,371 km from Earth's center, and the acceleration of gravity there is 9.8 m/s².  

The object in the question is 600 km farther from Earth's center, so the acceleration of gravity there is

(9.8 m/s²) · (6371 / 6971)²  =  8.2 m/s².

So the object's weight is (8.2 M) Newtons.

This is about 84% of its weight on Earth's surface.

(Notice that the astronauts aboard the International Space Station are NOT "weightless". The strength of gravity up there where they are is around 84% of what it is down on the ground.  The question of why they float, and why their muscles waste away, is a topic for another Brainly question.)

The velocity and acceleration of a body are 90km/hr and 2m/s^2 respectively. find the distance travelled by it in half minute.

Answers

Answer:

1,650 meters

Explanation:

Start by converting the velocity to m/s. There are 3600 seconds in a minute and 1000 meters in a kilometer, so 90km/hr=25m/s. Half a minute is 30 seconds, so:

[tex]d=v_ot+\dfrac{1}{2}at^2 \\\\d=(25)(30)+\dfrac{1}{2}(2)(30)^2 \\\\d=750+900=1650m[/tex]

Hope this helps!

why the weight of a body decreases with increases in distance from the earth's surface​

Answers

because as the distance increases the gravitational force decreases so the weight of a body decreases

Answer:

Weight of the body decreases with increase in distance from the Earth because weight is inversely proportional to distance from the Earth which means Weight of the body decreases with increase in distance from the Earth and vice versa. Also Weight is "gravitational force exerted on the body" so as the distance from the Earth increases , the "gravitational force" decreases.

An object rotates describing a horizontal circumference when subjected to a centripetal force F. What centripetal force will act on the object if the radius of the circle is doubled and the kinetic energy of the object is halved? A) F/4 B) F/2 C) F D) 4F please explain this to me : (

Answers

Answer:

Option A:  F/4

Explanation:

Centripetal force, [tex]F = \frac{mv^{2} }{r}[/tex]

Where v = speed

r = radius

Since Kinetic Energy, [tex]E_{k} = 0.5 mv^{2}[/tex]

Writing centripetal force in terms of kinetic energy, [tex]F = \frac{2 E_k}{r}[/tex]

If the initial radius of the circle, r₁ =r

The doubled radius, r₂ = 2r

If the initial kinetic energy, [tex]KE_1 = E_{k}[/tex]

The halved kinetic energy,  [tex]KE_2 = 0.5E_{k}[/tex]

Therefore, the new Centripetal force becomes:

[tex]F_{2} = \frac{2(0.5 E_k)}{2r} \\F_{2} = \frac{0.5 E_k}{r}\\F_{2} =\frac{1}{4} * \frac{2 E_k}{r}\\Since, F = \frac{2 E_k}{r} \\F_{2} =\frac{1}{4} * F\\F_{2} =\frac{F}{4}[/tex]

SERE
At which temperature does the motion of atoms and molecules stop?
0°C
ОС
0°K
ОК

Answers

Answer: 0 Kelvin, or 0°K.

Explanation:

The Kelvin scale is used primarily in scientific applications due to the unit's lack of negative values.

0 Kelvin is equivalent to "absolute zero", or the temperature at which molecules and atoms no longer physically move.

0 Celsius on the other hand is a system based on the freezing and boiling points of water. 0 Celsius is the freezing point and 100 Celsius is the boiling point.

Please help! 100 points!
What are some ways that the nitrogen cycle overlaps with or influences the oxygen and carbon cycles?


Are any of these interactions between the cycles positive?


Are any negative?


What about when the nitrogen cycle is thrown off balance by the Haber-Bosch process and others like it?


How can that influence the oxygen and carbon cycles?


Are there other cycles involved that have not been mentioned in this question?


What does this discussion suggest about the nature of the Earth as one large system?

Answers

Answer:

1.Nitrification happens when soil organisms change over ammonium into nitrate. Much of the cover between the carbon cycle and the nitrogen cycle happens within the soil, in forms conducted by soil organisms. Organisms break down supplements, construct modern compounds for their possess development, and inevitably pass on.

The second question im not sure sorry- the positive and negative one ;(

3. Many human activities have a significant impact on the nitrogen cycle. Burning fossil fuels, application of nitrogen-based fertilizers, and other activities can dramatically increase the amount of biologically available nitrogen in an ecosystem. As nitrogen makes up 78% of the atmosphere, there is no shortage of it – it just isn't in a form plants and animals can use.

4. Carbon makes its way through living things as carbon-based compounds, like vitality particles, fats and proteins, in the long run cycling its way back into the environment. Nitrogen is basically found within the air as well and enters the environments as supplements for plants. Water, nitrogen and carbon cycles. Carbon moves from the air and back by means of creatures and plants. Nitrogen moves from the environment and back by means of living beings. Water moves on, over, or underneath the surface of the Soil.

5. Carbon cycle, Nitrogen cycle, Nutrient cycle, Oxygen cycle, Phosphorus cycle, Sulfur cycle, Rock cycle, Water cycle.

6. Wind, water, and ice disintegrate and shape the arrive. Volcanic movement and seismic tremors change the scene in a sensational and frequently savage way. And on a much longer timescale, the development of earth's plates gradually reconfigures seas and landmasses. Each one of these forms plays a part within the Cold and Antarctica.

People affect the physical environment in numerous ways: overpopulation, contamination, burning fossil powers, and deforestation. Changes like these have activated climate alter, soil disintegration, destitute discuss quality, and undrinkable water. Earth's surface is the as it were territory accessible to the human race. Understanding the forms by which that environment has been made and persistently changed is critical to decide the causes of natural degradation.

1a. Assuming 100% efficient energy conversion, how much water stored behind a 50cm high hydroelectric dam would be required to charge a 50 ampere-minute 12 volt battery with 600j of energy stored in it

Answers

Answer:

7.22 m³ of water should be stored behind the hydroelectric dam.

Explanation:

First we find the total energy that can be stored in the battery. For that purpose we use the formula:

P = VI

where,

P = Power delivered by battery

V = Voltage of Battery = 12 volts

I = Current in Battery

Multiplying both sides by time interval (t), we get:

Pt = VIt

where,

Pt = (Power)(Time) = Total Energy Stored in Battery = E = ?

It = Current Rating of Battery = (50 A.min)(60 s/min) = 3000 A.s

Therefore,

E = (12 volt)(3000 A.s)

E = 36000 J

Now, we have to find the energy required to fully charge the battery:

Energy Required = ΔE = Total Energy Capacity(E) - Already Stored Energy

ΔE = 36000 J - 600 J

ΔE =  35400 J

Now, this energy must be equal to the potential energy of water stored behind hydroelectric dam to fully charge the battery, provided that the conversion efficiency is 100 %.

Therefore,

ΔE = mgh

where,

m = mass of water behind hydroelectric dam

g = 9.8 m/s²

h = height of dam = 50 cm = 0.5 m

Therefore,

35400 J = m(9.8 m/s²)(0.5 m)

m = (35400 J)/(4.9 m²/s²)

m = 7224.5 kg

Now, to find the volume of stored water, we use:

ρ = m/V

V = m/ρ

where,

ρ = density of water = 1000 kg/m³

V = Volume of water behind dam = ?

V = (7224.5 kg)/(1000 kg/m³)

V = 7.22 m³

what is the wavelength of radio waves transmitted by an FM station at 90MHz where 1M=10^6, and speed of radiowave is 3*10^8m/s

Answers

Answer:

λ = 3.33 m

Explanation:

Given:

Frequency = f = 9 × 10⁷ Hz

Speed = v = 3 × 10⁸ m/s

Required:

Wavelength = λ = ?

Formula:

v = fλ

Solution:

Putting the givens in the formula

v = fλ

λ = [tex]\frac{v}{f}[/tex]

λ = [tex]\frac{3*10^8}{9*10^7}[/tex]

λ = 0.33 × 10¹

λ = 3.33 m

An object with more mass has more kinetic energy than an object with less
mass, if both objects are moving
OA) at the same speed
OB) in the same direction
OC) in opposite directions​

Answers

Explanation:

The kinetic energy of an object is given in terms of its mass and object as :

[tex]K=\dfrac{1}{2}mv^2[/tex]

An object with more mass has more kinetic energy. An object with less  mass, if both objects are moving at the same speed, in opposite directions, will have less kinetic energy. The square of v will give positive number.

A car starts from rest and attains a velocity of 30m/s in 5 sec . calculate the total distance travel by that car and acceleration

Answers

Answer:

Acceleration (a) = 6 m/s²

Total distance travel by car(s) = 75 meter

Explanation:

Given:

Initial velocity (u) = 0

Final velocity (v) = 30 m/s

Time (t) = 5 sec

Find:

Total distance travel by car(s) = ?

Acceleration (a) = ?

​Computation:

v = u +at

30 = 0 + a(5)

30 = a(5)

Acceleration (a) = 6 m/s²

Total distance travel by car(s) = ut +1/2(a)(t)²

Total distance travel by car(s) = 1/2(a)(t)²

Total distance travel by car(s) = (0.5)(6)(5)²

Total distance travel by car(s) = 75 meter

A 1.00 kg block of ice, at -25.0°C, is warmed by 35 kJ of energy. What is the final temperature of the ice?

Answers

Answer:

-8.4°C

Explanation:

From the principle of heat capacity.

The heat sustain by an object is given as;

H = m× c× (T2-T1)

Where H is heat transferred

m is mass of substance

T2-T1 is the temperature change from starting to final temperature T2.

c- is the specific heat capacity of ice .

Note : specific heat capacity is an intrinsic capacity of a substance which is the energy substained on a unit mass of a substance on a unit temperature change.

Hence ; 35= 1× c× ( T2-(-25))

35= c× ( T2+25)

35 =2.108×( T2+25)

( T2+25)= 35/2.108= 16.60°{ approximated to 2 decimal place}

T2= 16.60-25= -8.40°C

C, specific heat capacity of ice is =2.108 kJ/kgK{you can google that}

To solve this we must be knowing each and every concept related to energy. Therefore, -8.40°C is the final temperature of the ice.

What is energy?

In physics, energy is the capacity to accomplish work. It can be potential, kinetic, temperature, electrical, chemical, radioactive, or in other forms.

There is also heat and work—energy inside the process of being transferred through one body to the other. Energy is always classified according to its type once it has been transmitted. As a result, heat transported could become thermal energy, whereas labor done may emerge as mechanical energy.

H = m× c× (T2-T1)

35= 1× c× ( T2-(-25))

35= c× ( T2+25)

specific heat capacity of ice is =2.108 kJ/kgK

35 =2.108×( T2+25)

( T2+25)= 35/2.108= 16.60°

T2= 16.60-25= -8.40°C

Therefore, -8.40°C is the final temperature of the ice.

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explain the causes of yaa asantewaa war of 1900​

Answers

Answer: the conflict began when a british representative - Sr. Frederick Mitchell Hodgson sat on the golden stool.

Explanation:

since the stool wasn't a throne, when Yaa Asantewaa found out, he led a rebellion which killed 1000 British and allied African soldiers and 2,000 Ashanti.      

good luck with your assignment :)

Concrete and steel expand to almost the same amount when they are heated. Explain why you think this is lucky?

Answers

Answer:

While making a bridge or a building, the first thing that comes to our mind is that these are always made by the combination of concrete and steel. Concrete is cheap, but it has the property of breaking when it is twisted or under tension. Steel is expensive, If we made the whole thing with it, it will cost a lot. To provide strength under a reasonable cost, we use the combination of concrete and steel. Another postive point which they have together is that they both expand equally under heat, because they have the same coefficient of thermal expansion. It proves really useful, because if they had different coefficients of thermal expansions, one would expand more than the other, which will create tensions in the mixture and would break it easily. In the case, many cracks would start to appear in the bridge or buildings, which will eventually break them.

A sphere of radius 0.03m has a point charge of q= 7.6 micro C located at it’s centre. Find the electric flux through it?

Answers

Answer:

The electric flux through the sphere is [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]

Explanation:

Given

[tex]Radius,\ r = 0.03m\\Charge,\ q =7.6\µC[/tex]

Required

Find the electric flux

Electric flux is calculated using the following formula;

Ф = q/ε

Where ε is the electric constant permitivitty

ε [tex]= 8.8542 * 10^{-12}[/tex]

Substitute ε [tex]= 8.8542 * 10^{-12}[/tex] and [tex]q =7.6\µC[/tex]; The formula becomes

Ф = [tex]\frac{7.6\µC}{8.8542 * 10^{-12}}[/tex]

Ф = [tex]\frac{7.6 * 10^{-6}}{8.8542 * 10^{-12}}[/tex]

Ф = [tex]\frac{7.6}{8.8542} *\frac{10^{-6}}{10^{-12}}[/tex]

Ф = [tex]\frac{7.6}{8.8542} *10^{12-6}}[/tex]

Ф = [tex]0.85834970974 *10^{12-6}}[/tex]

Ф = [tex]0.85834970974 *10^{6}}[/tex]

Ф = [tex]8.5834970974 *10^{5}}[/tex]

Ф = [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]

Hence, the electric flux through the sphere is [tex]8.58 *10^{5} \frac{Nm^2}{C}[/tex]

Which objects would sink in honey, which has a density of 1.4 g/cm³? Check all that apply.

Answers

Answer:

any object that has density more than 1.4

Explanation:

The object that has density more than 1.4 is denser than the honey

1. Calculate the total binding energy of 12

6 C.

Answer in units of MeV.



2. Calculate the average binding energy per nucleon of 24

12Mg.

Answer in units of MeV/nucleon.



3. Calculate the average binding energy per nucleon of 85

37Rb.

Answer in units of MeV/nucleon.



4. Find the binding energy per nucleon of 238

92U.

Answer in units of MeV/nucleon.



5. Calculate the total binding energy of 20

10Ne.

Answer in units of MeV.



6. Calculate the total binding energy of 40

20Ca.

Answer in units of MeV.

Answers

Answer:

1. B = 79.12 MeV

2. B = -4.39 MeV/nucleon

3. B = 2.40 MeV/nucleon

4. B = 7.48 MeV/nucleon

5. B = -18.72 MeV

6. B = 225.23 MeV            

Explanation:

The binding energy can be calculated using the followng equation:

[tex] B = (Zm_{p} + Nm_{n} - M)*931 MeV/C^{2} [/tex]

Where:

Z: is the number of protons

[tex]m_{p}[/tex]: is the proton's mass = 1.00730 u

N: is the number of neutrons

[tex]m_{n}[/tex]: is the neutron's mass = 1.00869 u

M: is the mass of the nucleus

1. The total binding energy of [tex]^{12}_{6}C[/tex] is:

[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]

[tex] B = (6*1.00730 + 6*1.00869 - 12.011)*931.49 MeV/u = 79.12 MeV [/tex]

 

2. The average binding energy per nucleon of [tex]^{24}_{12}Mg[/tex] is:

[tex] B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u [/tex]

Where: A = Z + N

[tex] B = \frac{(12*1.00730 + 12*1.00869 - 24.305)}{(12 + 12)}*931.49 MeV/u = -4.39 MeV/nucleon [/tex]                                  

   

3. The average binding energy per nucleon of [tex]^{85}_{37}Rb[/tex] is:

[tex] B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u [/tex]

[tex] B = \frac{(37*1.00730 + 48*1.00869 - 85.468)}{85}*931.49 MeV/u = 2.40 MeV/nucleon [/tex]

     

4. The binding energy per nucleon of [tex]^{238}_{92}U[/tex] is:

[tex] B = \frac{(92*1.00730 + 146*1.00869 - 238.03)}{238}*931.49 MeV/u = 7.48 MeV/nucleon [/tex]

 

5. The total binding energy of [tex]^{20}_{10}Ne[/tex] is:

[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]

[tex] B = (10*1.00730 + 10*1.00869 - 20.180)*931.49 MeV/u = -18.72 MeV [/tex]

6. The total binding energy of [tex]^{40}_{20}Ca[/tex] is:

[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]

[tex] B = (20*1.00730 + 20*1.00869 - 40.078)*931.49 MeV/u = 225.23 MeV [/tex]

I hope it helps you!

*
A light year is
1 Point
O 365 days
O The distance light travels in a year
O The distance from Earth to Proxima Centauri
Helppp now is my final exammmm pleaseeee

Answers

Answer:

2.The Distance Light Travels In A Year

Explanation:

A Light Year Is Nothing But The Distance That The Light Travels In Onw Year

Answer:

Shown from explanation.

Explanation:

Light year is the distance light travels in one year and you can calculate that.

Light travels 3× 10^8m in 1 second; so you calculate the number of seconds in 365days and multiply by 3× 10^8m.

Light year was a unit of measure derived by man for expressing planetary distances due to their so huge distance which goes beyond our scale of measure.

Which force does not operate at a distance of 1 m?
A. Weak nuclear
O B. Electric
C. Gravitational
D. Magnetic

Answers

Answer:

A

Explanation:

The Force that doesn’t operate at the distance of 1m is Weak Nuclear

A water distiller which is used to purify water. The distiller boils water and then condenses most of the water vapour back to water. (a) The water distiller is filled with 5.0 kg of water at 20 °C The specific heat capacity of water = 4 200 J/Kg °C Calculate the energy needed to raise the temperature of the water to 100 °C ___________________________________________________________________

Answers

Answer:

Energy needed 1680kJ

Explanation:

The quantity of heat required to raise the temperature of water to 100 degrees is expressed as

[tex]Q= mc(T2-T1)[/tex]

Given data

mass of water = 5kg

initial temperature T1= 20 °C

final temperature T2= 100 °C

Specific heat capacity of water=  4 200 J/Kg °C

[tex]Q= 5* 4 200(100-20)\\Q= 21000(80)\\Q= 1680000\\Q= 1680kJ[/tex]

In a hydroelectric power station, how much potential energy is lost by 100tonnes of water flowing down through the pipes, falling a vertical distance of 200metres? [1tonne=1000kg.]

Answers

Answer:

196000000 J

Explanation:

Potential Energy: This can be defined as the energy of a body due to its position in the gravitational field.

From the question,

P.E = mgh.................. Equation 1

Where P.E = potential Energy, m = mass of the water, h = height, g = acceleration due to gravity.

Given: m = 100 tonnes = (100×1000) = 100000 kg, h = 200 m

Constant: g = 9.8 m/s²

Substitute into equation 1

P.E = 100000(200)(9.8)

P.E = 196000000 J.

Note: When a object falls through a height he losses its potential energy.

Hence the potential energy lost = 196000000 J = 196 MJ.

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