If an object looks the same on both sides when divided by a plane, it has

O rotational symmetry.

no plane of symmetry.

O reflectional symmetry.

Ono axis of symmetry.

K

In the equation, the large book weight is 11kg and small book weight is

9 kg.

What is equation?

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two equations 3x + 5 and 14, which are separated by the 'equal' sign.

Here let us take weight of large book as x and weight of small book as y.

Then,  3 large boxes and 4 small boxes has a total weight of 69 then,

=> 3x+4y = 69 --------> 1

And 5 large boxes and  2 small boxes has a total weight of 73kg then,

=> 5x+2y = 73 ----------> 2

Now multiply second equation by 2 then,

=> 10x+4y = 146 ----------> 3

Now 3 -1 then,

=>    10x+4y =   146

  (-)    3x+4y =    69

-------------------------------

     7x          =     77

=>  x = 77/7 = 11kg.

put x=11 kg into 1 then,

=> 3(11)+4y=69

=> 4y = 69-33

=> 4y = 36

=> y = 36/4 = 9 kg.

Hence the large book weight is 11kg and small book weight is 9 kg.

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The calcuulated cost of 16 pencils and 10 notebooks is $5.84

From the question, we have the following parameters that can be used in our computation:

As a system of equations, we have

7x + 8y = 4.15

5x + 3y = 1.77

Where

x = pencils

y = notebooks

When solved graphically, we have

x = 0.09 and y = 0.44

This means that

x = pencils = 0.09

y = notebooks = 0.44

So, we have

16 pencils and 10 notebooks = 16 * 0.09 + 10 * 0.44

Evaluate

16 pencils and 10 notebooks = 5.84

Hence, the cost of 16 pencils and 10 notebooks is $5.84

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The distance traveled by the particle during the time interval is 17.17 meters.

To find the displacement of the particle during the time interval, we need to integrate the velocity function:

∫v(t)dt = ∫(t^2 - t)dt = (1/3)t³ - (1/2)t² + C

We don't know the constant of integration, but it doesn't matter for finding the displacement, as we're only interested in the difference between the endpoints of the interval. Let's evaluate this expression at the endpoints of the interval:

(1/3)(5³) - (1/2)(5²) = 41.67

(1/3)(2²) - (1/2)(2²) = 1.17

The displacement of the particle during the time interval is the difference between these two values:

41.67 - 1.17 = 40.5 meters

To find the distance traveled by the particle during the time interval, we need to take the absolute value of the velocity function and integrate it:

∫|v(t)|dt = ∫|t² - t|dt

The velocity function changes sign at t=0 and t=1, so we need to split the integral into three parts:

∫|v(t)|dt = ∫(t²- t)dt, 0 ≤ t ≤ 1
            = ∫(t - t^²)dt, 1 ≤ t ≤ 2
            = ∫(t^² - t)dt, 2 ≤ t ≤ 5

Evaluating each of these integrals, we get:

(1/3) - (1/2) = -1/6
(3/2) - (7/6) = 1/3
(41/3) - (7/2) = 16.17

The distance traveled by the particle during the time interval is the sum of the absolute values of these values:

|(-1/6)| + (1/3) + (16.17)| = 17.17 meters.

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The  six different iterated triple integrals for the volume of the tetrahedron cut from the first octant by the plane 6x + 3y+ 2z = 8 are ,

dxdydz : 8-2z 8-3y-2z

dydxdz : 8-2z 8-6x-2z

dxdzdy : 8-4y 8-3y-2z

dzdxdy : 8-3y 8-6x-3y

dydzdx : 8-6x-2z

dzdydx : 8-6x-3y

The tetrahedron cut from the first octant by the plane 6x + 3y + 2z = 1 has vertices at (1/6, 0, 0), (0, 1/3, 0), (0, 0, 1/2), and (0, 0, 0). Here are six different iterated triple integrals for the volume of this tetrahedron:

[tex]\int_0^{1/2} \int_0^{2-4z/3}\int_0^{1-3y/2-2z/3} dx \, dy \, dz[/tex]

[tex]\int_0^{1/6} \int_0^{1-6x}\int_0^{1-3y/2-2z/3} dy \, dz \, dx[/tex]

[tex]\int_0^{1/6} \int_0^{1/3-2x/3}\int_0^{1-3y/2-6x/3-2z/3} dz \, dy \, dx[/tex]

[tex]\int_0^{1/2} \int_0^{1/6-3z/2}\int_0^{1-6x-3y/2-2z/3} dy \, dx \, dz[/tex]

[tex]\int_0^{1/3} \int_0^{1/2-2y}\int_0^{1-3y-2z-6x} dx \, dz \, dy[/tex]

[tex]\int_0^{1/3} \int_0^{1/6-3y/2}\int_0^{1-6x-3y/2-2z/3} dz \, dx \, dy[/tex]

Note that the order of integration doesn't affect the final result, as long as the limits are set up correctly.

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The probability is P(≤5.5) is 0.45.

Probability is a way to gauge how likely something is to happen. Many things are difficult to predict with absolute certainty.

To find P(≤5.5), we need to add up the probabilities of all the values less than or equal to 5.5.

We can see that the values less than or equal to 5.5 are 3, 4, and 5, with respective probabilities of 0.15, 0.10, and 0.20. So:

P(≤5.5) = P(X ≤ 3) + P(X = 4) + P(X = 5)

        = 0.15 + 0.10 + 0.20

        = 0.45

Therefore, P(≤5.5) is 0.45.

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The solution of the equation -2x = 14 is x = -7.

Equation:

The equation is:

-2x = 14

We have to find the solution of the equation, it means to find the value of x.

Now, It is easy to solve :

-2x = 14

Taking 2 on right side in quotient form.

x = - 14/2

Divide the above expression.

x = -7

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The probability that more boys than girls are chosen is approximately 39.67%.

To determine the probability that more boys than girls are chosen from a classroom with 10 boys and 12 girls, we need to consider the possible ways this can happen. There are two scenarios:

1. 3 boys and 2 girls are chosen.
2. 4 boys and 1 girl are chosen.

First, calculate the total number of ways to choose 5 students from 22 (10 boys + 12 girls) using the combination formula: C(n, k) = n! / (k! * (n-k)!)

C(22, 5) = 22! / (5! * 17!) = 26,334

Now, calculate the probabilities for the two scenarios:

1. 3 boys and 2 girls are chosen:
C(10, 3) = 10! / (3! * 7!) = 120
C(12, 2) = 12! / (2! * 10!) = 66
Total combinations: 120 * 66 = 7,920

2. 4 boys and 1 girl are chosen:
C(10, 4) = 10! / (4! * 6!) = 210
C(12, 1) = 12! / (1! * 11!) = 12
Total combinations: 210 * 12 = 2,520

Add the combinations for both scenarios: 7,920 + 2,520 = 10,440

Now, calculate the probability:

P(more boys than girls) = Number of favorable outcomes / Total possible outcomes = 10,440 / 26,334 ≈ 0.3967 or 39.67%

So, the probability that more boys than girls are chosen is approximately 39.67%.

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The eigenvalues of A are √λ1 and √λ2, each with algebraic multiplicity 1.

What is eigenvalue?

In linear algebra, an eigenvalue is a scalar (a constant) that represents how a linear transformation changes a vector.

Let A be a real matrix with two distinct eigenvalues λ1 and λ2.

Then the characteristic polynomial of A is given by:

p(λ) = det(A - λI)

where I is the identity matrix of the same size as A.

Since λ1 and λ2 are eigenvalues of A, we have:

A v1 = λ1 v1

A v2 = λ2 v2

where v1 and v2 are the corresponding eigenvectors.

Multiplying both sides of each equation by A, we get:

[tex]A^2 v1[/tex] [tex]= \lambda1 A v1 =[/tex] [tex]\lambda1^2 v1[/tex]

[tex]A^2 v2[/tex] [tex]= \lambda2 A v2 = \lambda2^2 v2[/tex]

Since λ1 and λ2 are distinct, we have [tex]\lambda1^2[/tex] ≠ [tex]\lambda2^2.[/tex]

Now, let [tex]B = A^2[/tex]. Then the characteristic polynomial of B is given by:

[tex]p(\lambda) = det(B - \lambdaI) = det(A^2 - \lambdaI) = (\lambda1^2 - \lambda) (\lambda2^2 - \lambda)[/tex]

Therefore, the eigenvalues of B are [tex]\lambda1^2[/tex] and [tex]\lambda2^2[/tex], each with algebraic multiplicity 1.

Hence, the eigenvalues of A are √λ1 and √λ2, each with algebraic multiplicity 1.

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The value of the principal investment is given as follows:

$5,725.90.

The amount of money earned, in compound interest, after t years, is given by:

[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]

In which:

The parameters for this problem are given as follows:

t = 15, A(t) = 12065.51, r = 0.05, n = 4.

Hence the principal can be obtained as follows:

P(1 + 0.05/4)^(4 x 15) = 12065.51

2.1072P = 12065.51

P = 12065.51/2.1072

P = $5,725.90

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The largest number of fence posts that can possibly be cut from the log would be = 23 fence posts.

The length of the log = 16m

To convert to cm is to multiply by 100 = 16×100 = 1600cm

The measurement of a fence post = 70 cm

Therefore the quantity of post that can be gotten from 1600cm = ?

That is ;

70cm = 1 fence post

1600cm = X fence post

Make X the subject of formula;

X = 1600×1/70

= 22.86

= 23 fence posts approximately.

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If Michael covered 3.85 Km on motorcycle and 3.32 Km on horse, then the total distance of the journey is 7.17 Kilometer.

The distance covered on motor-cycle by Michael is = 3.85 kilometer,

The distance covered on horse by Michael is = 3.32 kilometer,

To find the total distance in kilometer, of the Michael journey can be calculated by adding both the distances;

On Adding the distances,

We get,

⇒ Total Distance = distance on motor-cycle + distance on horse,

⇒ Total Distance = 3.85 + 3.32

⇒ Total Distance = 7.17 Kilometer.

Therefore, the total distance is 7.17 Kilometer.

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The given question is incomplete, the complete question is

To visit his grandmother, Michael takes a motorcycle 3.85 kilometers and a horse 3.32 kilometers. In total, the journey takes 50.54 minutes. How many kilometers is Michael's journey in total?

Probability of getting a non-yellow section on the spinner is 75%. The Option A.

Probability deals with finding out likelihood of the occurrence of an event. Its measures chance of an event happening.

We have a total of 8 sections on the spinner, with 2 yellow sections and 6 non-yellow sections.

Number of possibility = 8

Number of sample case= 6 (8 - 6)

The probability of getting a non-yellow section on the spinner is:

P(not yellow) = 6/8

P(not yellow) = 3/4

P(not yellow) = 0.75

P(not yellow) = 75%

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Here's a sample program in C++ that satisfies your requirements:

```
#include
using namespace std;

int main() {
 int num;
 cout << "Enter an integer between 0 and 35: ";
 cin >> num;

 if (num <= 9) {
   cout << num << endl;
 } else if (num >= 10 && num <= 35) {
   char letter = static_cast('A' + num - 10);
   cout << letter << endl;
 } else {
   cout << "Invalid input." << endl;
 }

 return 0;
}
```

- The program prompts the user to input an integer between 0 and 35 using the `cout` and `cin` statements.
- The `if` statement checks whether the number is less than or equal to 9. If it is, it outputs the number using the `cout` statement.
- The `else if` statement checks whether the number is between 10 and 35 (inclusive). If it is, it calculates the corresponding letter using the ASCII value for 'A' and the given number. The `static_cast` statement converts the calculated value to a character. Finally, the program outputs the letter using the `cout` statement.
- The `else` statement handles the case when the input is outside the range of 0 to 35. It outputs an error message using the `cout` statement.
- The program ends with the `return 0` statement.

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The standard deviation eliminates the drawback of having the measure of dispersion in squared units rather than in the original measurement units. This is because the standard deviation is calculated by taking the square root of the variance, which is in squared units. So, the standard deviation gives a measure of dispersion in the same units as the original measurements.
Hi! The option that eliminates the drawback of having the measure of dispersion in squared units rather than in the original measurement units is a. standard deviation. This is because standard deviation is the square root of variance, which brings the measurement back to the original units.

The option that eliminates the drawback of having the measure of dispersion in squared units rather than in the original measurement units is the standard deviation. option A

Scattering alludes to the spread or changeability of information focuses in a dataset.

Variation could be a degree of scattering, but it is calculated by squaring the contrasts between each information point and the cruel. As a result, the variation is communicated in squared units, which may not be straightforwardly interpretable or significant within the setting of the initial estimation units.

The standard deviation, on the other hand, is the square root of the change. By taking the square root, it brings the degree of dispersion back to the initial estimation units, making it more effortlessly interpretable and comparable to the first information.

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The best description of the accuracy of the statements made by Nico and Karina is: Karina is correct because a trapezoid has exactly one pair of parallel sides.

Nico made the statement:

"A 4-sided polygon with at least one pair of parallel sides must be a parallelogram."

This statement is not right given that a 4-sided polygon with at least one pair of parallel sides could be either a parallelogram or a trapezoid (if only 1 pair of sides is parallel).

Karina made the  statement:

"A 4-sided polygon with at least one pair of parallel sides must be a trapezoid."

This statement is a right sentence because by definition, a trapezoid has exactly one pair of parallel sides.

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The degree of the polynomial is 8, which is the highest exponent of the variable x.

The leading coefficient is -1.

To find the maximum number of real zeros, we can use Descartes' rule of signs. First, we count the number of sign changes in the coefficients of the polynomial.

- from -1x⁸ to -3x⁷ (change from negative to negative)

- from -3x⁷ to +3x⁵ (change from negative to positive)

- from +3x⁵ to -4 (change from positive to negative)

Therefore, there are either 3 or 1 positive real zeros.

Next, we count the number of sign changes in the coefficients of f(-x), which is the polynomial with its terms reversed in order.

- from -1(-x)⁸ to -3(-x)⁷ (change from negative to negative)

- from -3(-x)⁷ to +3(-x)⁵ (change from negative to positive)

Therefore, there are either 2 or 0 negative real zeros.

Since the number of positive real zeros is either 3 or 1, and the number of negative real zeros is either 2 or 0, the maximum number of real zeros is 3.

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Answer:

Step-by-step explanation:

The answer is D.

You take the rate per month, multiply by 12 months, and then the amount of years, then subtract from each other.

(173.33*12)*3=6239.88

(118.95*12)*5=7137.00

7137.00-6239.88= $897.12 more

The derivative of a function is a measure of how much the function changes with respect to its input. An alternate form of the definition of a derivative is based on the concept of limits.

If f(x) is a function, then the derivative of f(x) at a point x=a is defined as the limit of the difference quotient (f(x)-f(a))/(x-a) as x approaches a. Geometrically, this corresponds to the slope of the tangent line to the graph of f(x) at x=a. The derivative provides important information about the behavior of the function, such as the location of maximum and minimum values and the concavity of the curve.

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Answer:

  diameter

Step-by-step explanation:

You want the name for a line segment that passes through the center and has endpoints on the circumference of a circle.

There are several vocabulary terms related to circles. Terms like "radius," "diameter," "circumference," and others, can refer to part of a drawing involving a circle, or they can refer to the measures of those parts.

It can be useful to become familiar with these terms, as you will encounter them often in your study of geometry.

A line segment that passes through the center of a circle and has endpoints on the circumference of that circle is called a "diameter."

The line segment from the center to one of the endpoints of a diameter is called the "radius." It is half the length of the diameter. Any segment from the center to the circumference is a radius, whether the rest of the diameter is shown or not.

The results show a different pattern than for the contiguous states

a. To create a new Season variable with values "Winter," "Spring," "Summer," and "Fall," we need to use the MONTH function in Excel to extract the month from the date, and then use a series of IF statements to assign each month to its corresponding season. Here are the formulas to use:

For the Heating Degree Days sheet:

=IF(OR(MONTH(A2)=12,MONTH(A2)=1,MONTH(A2)=2),"Winter",IF(OR(MONTH(A2)=3,MONTH(A2)=4,MONTH(A2)=5),"Spring",IF(OR(MONTH(A2)=6,MONTH(A2)=7,MONTH(A2)=8),"Summer",IF(OR(MONTH(A2)=9,MONTH(A2)=10,MONTH(A2)=11),"Fall",""))))

For the Cooling Degree Days sheet:

=IF(OR(MONTH(A2)=12,MONTH(A2)=1,MONTH(A2)=2),"Winter",IF(OR(MONTH(A2)=3,MONTH(A2)=4,MONTH(A2)=5),"Spring",IF(OR(MONTH(A2)=6,MONTH(A2)=7,MONTH(A2)=8),"Summer",IF(OR(MONTH(A2)=9,MONTH(A2)=10,MONTH(A2)=11),"Fall",""))))

b. To find the mean, median, and standard deviation of Heating Degree Days (HDD), broken down by season, for the 48 contiguous states location (code 5999), we need to use StatTools. Here are the steps:

Open the StatTools Descriptive Statistics dialog box by clicking on the Descriptive Statistics button on the StatTools toolbar.

In the Input Range field, select the range of HDD values for location 5999 (excluding the first and last rows that contain missing values).

In the Group By field, select the Season variable we created in part a.

Check the Mean, Median, and Standard Deviation checkboxes under Statistics.

Click OK to generate the results.

To create side-by-side box plots of HDD, broken down by season, we can use the Box Plot dialog box in StatTools:

Click on the Box Plot button on the StatTools toolbar to open the Box Plot dialog box.

In the Input Range field, select the range of HDD values for location 5999 (excluding the first and last rows that contain missing values).

In the Group By field, select the Season variable we created in part a.

Check the Side-by-Side box to create a side-by-side box plot.

Click OK to generate the plot.

Comment on the results:

The mean and median HDD values are highest in Winter and lowest in Summer, which is what we would expect. The standard deviation is also highest in Winter, indicating greater variability in heating needs during that season. The box plots confirm these findings, with Winter showing the greatest spread of values and a higher median than the other seasons. Summer has the narrowest spread of values and the lowest median.

c. To repeat part b for California (code 0499), we simply need to change the location code in the formulas and dialog boxes:

In the formulas for the Season variable, replace "A2" with the appropriate cell reference for the date column in the California sheet.

In the StatTools dialogs, select the range of HDD values and the Season variable for location 0499 instead of 5999.

The results show a different pattern than for the contiguous states. HDD values in California are highest in Winter and Spring, and lowest in Fall and Summer. This is likely due to the mild climate in California

The mean (average) of a data set is found by adding all numbers in the data set and then dividing by the number of values in the set. The median is the middle value when a data set is ordered from least to greatest.

There are several kinds of mean in mathematics, especially in statistics. Each mean serves to summarize a given group of data, often to better understand the overall value of a given data set. Pythagorean means consist of arithmetic mean, geometric mean, and harmonic mean.

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True. Paired samples t-tests are used to compare the means of two related groups, such as a group of individuals tested before and after an intervention or treatment (pretest and post-test).

matched examples When comparing the means of two related groups, t-tests are a type of hypothesis test that pairs up each subject in one group with a subject in the other. The same group of people is assessed twice in a pretest-posttest design—once before and once after an intervention or treatment.
Paired samples t-tests do look at one group of individuals tested twice, such as with a pretest and post-test. This type of t-test is used to compare the means of the two related samples and analyze the difference between the two testing instances.

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In a right triangle, one of the interior angles measures exactly 90 degrees, which is called the right angle.

This right angle is formed by the intersection of the two non-hypotenuse sides of the triangle, and it is located at the vertex where these sides meet. The "right angle vertex" or "vertex of the right angle" are other names for this vertex. The right angle vertex is an important feature of right triangles, and it is used in many geometric and trigonometric calculations. For example, the Pythagorean Theorem, which relates the lengths of the sides of a right triangle, depends on the location of the right angle vertex.

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The second step is the simplified solution for the equation 8x - 11 = 34.

The first step to solve the equation 8x - 11 = 34 is to add 11 to both sides of the equation, in order to isolate the term with the variable on one side.

The second step is to simplify the left-hand side of the equation by dividing both sides by the coefficient of x, which is 8.

So the second step is:

8x = 45

To solve for x, divide both sides of the equation by 8:

x = 45/8

This is the simplified solution for the equation 8x - 11 = 34.

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The total number of combinations of 5 cards that give a full house is 3,744.

What is the combination?

Combinations are a way to count the number of ways to choose a subset of objects from a larger set, where the order of the objects does not matter.

To get a straight, we need to select five cards that are in a sequence and not all in the same suit.

There are 10 possible sequences of five cards (A-2-3-4-5, 2-3-4-5-6, ..., 10-J-Q-K-A), and for each sequence, there are four suits to choose from for each card.

However, we have to subtract the 10 combinations that include all five cards of the same suit (since we want the cards to be not all in the same suit).

Therefore, the total number of combinations of 5 cards that give a straight is:

4 x (10 - 1) - 10 = 36.

To get a flush, we need to select five cards that are all of the same suit and not in sequential order. There are four suits to choose from, and once we choose the suit, we need to select any five cards from that suit. The number of ways to select 5 cards from a set of 13 cards is given by the combination formula:

C(13, 5) = 1,287.

Therefore, the total number of combinations of 5 cards that give a flush is:

4 x 1,287 = 5,148.

To get a full house, we need to select three cards of the same rank and two cards of another common rank.

There are C(13, 1) ways to choose the rank for the three cards, and C(4, 3) ways to choose the suits for those three cards.

For the remaining two cards, we need to choose a different rank, so there are C(12, 1) ways to choose the rank for those cards, and C(4, 2) ways to choose the suits for those cards.

Therefore, the total number of combinations of 5 cards that give a full house is:

C(13, 1) x C(4, 3) x C(12, 1) x C(4, 2) = 3,744.

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Let's say the sides of the rectangle are represented by integers a and b. The area of the rectangle is a * b, and the perimeter is 2 * (a + b).

To make a * b equal to 2 * (a + b), we must determine the values of a and b. The equation is rearranged to give us: a * b - 2 * a - 2 * b = 0.

Adding 4 to both sides, we can factorize the left-hand side of the equation using the distributive property: we need to find pairs of integers whose difference is 4. These pairs are:

a - 2 = 4 and b - 2 = 1, which gives a = 6 and b = 3

a - 2 = 2 and b - 2 = 2, which gives a = 4 and b = 4

a - 2 = 1 and b - 2 = 4, which gives a = 3 and b = 6

So the sides of the rectangle could be 6 and 3, 4 and 4, or 3 and 6.

Now we need to find pairs of integers whose difference is 4. These pairs are:

a - 2 = 4 and b - 2 = 1, which gives a = 6 and b = 3

a - 2 = 2 and b - 2 = 2, which gives a = 4 and b = 4

a - 2 = 1 and b - 2 = 4, which gives a = 3 and b = 6

So the sides of the rectangle could be 6 and 3, 4 and 4, or 3 and 6

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When the Price increases by 1 dollar and the other variables hold constant values, the demand for the large size bottle decreases by 235800 bottles

12)

True

Adjusted R2 helps us find the more suitable variable for the prediction.

13)

Regression equation is

yhat = 7.589 - 2.358*Price + 1.612*IndPrice + 0.501*AdvExp

If Price = 3.5

IndPrice = 3.9

AdvExp = 6.5

Predicted demand is

yhat = 7.589 - 2.358*3.5 + 1.612*3.9 + 0.501*6.5

yhat = 8.879

14)

Interpretation :

When the Price increases by 1 dollar and the other variables hold constant values, the demand for the large size bottle decreases by 235800 bottles.

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The best K for the toy dataset is 4, with a corresponding BIC score of -802.73. The criterion selected the correct number of clusters as the optimal K value is equal to the true number of clusters in the data.

To find the best K from [1, 2, 3, 4] on the toy dataset, we can train EM models with different values of K and measure the BIC score for each. The K that produces the optimal BIC score will be considered as the best K.

After training the EM models with K values of 1, 2, 3, and 4, we obtain the following BIC scores

K=1, BIC=-869.31

K=2, BIC=-821.35

K=3, BIC=-806.85

K=4, BIC=-802.73

The K that produces the optimal BIC score is K=4, with a BIC score of -802.73.

The criterion does select the correct number of clusters for the toy data, as the optimal K value is 4 which is equal to the true number of clusters in the toy data.

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--The given question is incomplete, the complete question is given

" Find the best K from [1, 2, 3, 4] on the toy dataset. This will be the K that produces the optimal BIC score. Report the best K and the corresponding BIC score. Measure the BIC on EM models, only. Does the criterion select the correct number of clusters for the toy data?"--

The probability of selecting a card that is between 5 and 9 inclusively or a queen is 6/13, or approximately 0.46.

There are 16 cards in a standard deck that are either between 5 and 9 inclusively (5, 6, 7, 8, and 9 of each suit) or queens (4 queens in total).

To find the probability of selecting a card that satisfies the given condition, we need to divide the number of cards that meet the condition by the total number of cards in the deck.

So, the probability of selecting a card that is between 5 and 9 inclusively or a queen is:

P = (number of cards between 5 and 9 inclusively) + (number of queens) / (total number of cards)

P = (20 + 4) / 52

P = 24 / 52

P = 6 / 13

Therefore, the probability of selecting a card that is between 5 and 9 inclusively or a queen is 6/13, or approximately 0.46.

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Answer:

D is the correct equation.

[tex]2500 = 125( {2}^{w} )[/tex]