Answer:
Angle 1 is 30° and angle 2 is 150°
Step-by-step explanation:
Two angles are said to be linear if they are adjacent angles formed by two intersecting lines. The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees.Let angle 1 is a, angle 2 is b and we got b = 5a
a + b = 180°b = 5aa + 5a = 6a6a = 180°a = 180°/6a = 30°and
b = 5*30° = 150°What is the value of the expression
x2 + y2 + x - y
when x = -1 and y = 3
Answer:
ahhh i dont remeber
A soccer team is having a car wash. The team spent $55 on supplies. They earned $275, including tips. The team’s profit is the amount the team made after paying for supplies. Write a sum of integers that represents the team’s profit.
Answer:
-55 + 275
Step-by-step explanation:
You add the total earned to the expenses. The expenses are a negative integer.
-55 + 275
what is the opposite 25 degrees
Answer:
The opposite of 25 degrese is -25 degrese.
Step-by-step explanation:
The opposite 25 degrees will be 205 degrees.
What is an angle?The angle is the distance between the intersecting lines or surfaces. The angle is also expressed in degrees. The angle is 360 degrees for one complete spin.
For the opposite angle, add 180° to the given angle.
The opposite 25 degrees will be
⇒ 25° + 180°
⇒ 205°
The diagram is given below.
More about the angled link is given below.
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#SPJ2
Write the opposite of 47
Answer:
-47
Step-by-step explanation:
Answer:
-47
Step-by-step explanation:
The opposite of a number is just the number on the opposite side of zero on the number line.
For example, the opposite of 5 is -5.
can I get an answer please
Answer:
2 is the answer to the question I think
eratosthenes estimated the circumference of the earth as 250,000 stadia (the length of an athletic stadium). if we assume he used the most common length of stadia of his time, his estimate of the circumference of the Earth would be 46,620 km. Currently, the accepted average circumference of the Earth is 40,030.3 km. Find the percentage error of Eratosthenes' estimate of the circumference of the Earth
Answer: 16.5%
Step-by-step explanation:
given data:
estimated circumfrence of the earth = 250,000 stadia.
Actual value = 46,620km
expected Value = 40,030.3km
solution:
percentage error = actual value – expected value/ expected value * 100
= 46,620 – 40,030.3 / 40,030.3 * 100
= 6589.7 / 40,030.3 * 100
= 0.16462 * 100
= 16.5%
percentage error is 16.5%
Function or not ? Please help me thanks
Answer:This graph parabola is not a function
6. Simplify the expression. 8.5(4+3h)-h
Answer:
34+24.5h
Step-by-step explanation:
Please show all of the steps to solve the Algebra math problems below.Evaluate the following.|10| = |-4| =Subtract. Write your answer as a fraction in simplest form.5/8 � 3/8 =Subtract.7/8 � 5/6Write your answer as a fraction in simplest form.Multiply.6*(-7/2) =Write your answer in simplest form.Divide. Write your answer as a fraction or mixed number in simplest form.6/5 / (- 12/25) =Evaluate.3 + 4^2 * 2 =Evaluate.2/3 + 5/6 * � =Write your answer in simplest form.Evaluate-16 - 12 / (-4) =Use the distributive property to remove the parentheses.-9(3w � x � 2) =Simplify.-2(w + 2) + 5w =Simplify the following expression.16x^2 + 8 � 10x � 2x^2 � 14x =Evaluate the expression when b = -5 and y = 6b � 9y =Evaluate the expression when y = -3Y^2 + 5y � 4 =Evaluate.(-4)^3 =(-7)^2 =Evaluate. Write your answers as fractions.3/5^3 =(-1/3)^2 =Evaluate the expressions.(-7)^0 =2(1/3)^0 = Multiply.3v^2(-5v^4) =Simplify your answer as much as possible.Multiply.2y^2w^4*6y*2w^8 =Simplify your answer as much as possible.Simplify.(4p^3/3p^7)^-2 =Write your answer using only positive exponents.Simplify.X^-2/x^-3 =Write your answer with a positive exponent only.
Answer:
See Explanation
Step-by-step explanation:
Please note that I'll replace all � with +
1. |10|
This implies the absolute value of 10 and it always returns the positive value;
Hence;
[tex]|10| = 10[/tex]
2. |-4|
Using the same law applied in (1)
[tex]|-4| = 4[/tex]
3. 5/8 - 3/8 = ?
Take LCM
[tex]= \frac{5 - 3}{8}[/tex]
Subtract the numerator
[tex]= \frac{2}{8}[/tex]
Divide the numerator and denominator by 2
[tex]= \frac{1}{4}[/tex]
Hence:
[tex]\frac{5}{8} - \frac{3}{8} = \frac{1}{4}[/tex]
4. 7/8 - 5/6
Take LCM
[tex]= \frac{21 - 20}{24}[/tex]
[tex]= \frac{1}{24}[/tex]
Hence;
[tex]\frac{7}{8} - \frac{5}{6} = \frac{1}{24}[/tex]
5. 6 * (-7/2)
[tex]= 6 * \frac{-7}{2}[/tex]
Multiply the numerator
[tex]= \frac{-42}{2}[/tex]
[tex]= -21[/tex]
Hence:
[tex]6 * \frac{-7}{2} = -21[/tex]
5. 6/5 /(-12/25)
[tex]= \frac{6}{5} / \frac{-12}{25}[/tex]
Change the divide to multiplication
[tex]= \frac{6}{5} * \frac{-25}{12}[/tex]
Divide 6 and 12 by 6
[tex]= \frac{1}{5} * \frac{-25}{2}[/tex]
Divide 5 and 25 by 5
[tex]= \frac{1}{1} * \frac{-5}{2}[/tex]
[tex]= \frac{-5}{2}[/tex]
Hence;
[tex]\frac{6}{5} / \frac{-12}{25} = \frac{-5}{2}[/tex]
6. 3 + 4^2 * 2
[tex]= 3 + 4^2 * 2[/tex]
Solve the exponent
[tex]= 3 + 16 * 2[/tex]
Apply B.O.D.M.A.S
[tex]= 3 + 32[/tex]
[tex]= 35[/tex]
[tex]3 + 4^2 * 2 = 35[/tex]
7. 2/3 + 5/6
[tex]= \frac{2}{3} + \frac{5}{6}[/tex]
Apply LCM
[tex]= \frac{4 + 5}{6}[/tex]
[tex]= \frac{9}{6}[/tex]
Divide the numerator and denominator by 3
[tex]= \frac{3}{2}[/tex]
Convert to mixed fraction
[tex]= 1\frac{1}{2}[/tex]
Hence;
[tex]\frac{2}{3} + \frac{5}{6} = 1\frac{1}{2}[/tex]
8. 16 - 12/(-4)
[tex]= 16 - \frac{12}{-4}[/tex]
Solve the fraction
[tex]= 16 - (-3)[/tex]
Open the bracket
[tex]= 16 + 3[/tex]
[tex]= 19[/tex]
Hence;
[tex]16 - \frac{12}{-4} = 19[/tex]
9. -9(3w + x + 2)
[tex]= -9(3w + x + 2)[/tex]
Open brackets: Distributive property
[tex]= -9*3w -9* x -9 * 2[/tex]
[tex]= -27w -9 x -18[/tex]
Hence;
[tex]-9(3w + x + 2) = -27w -9 x -18[/tex]
10. -2(w + 2) + 5w
[tex]= -2(w + 2) + 5w[/tex]
Open bracket: using distributive property
[tex]= -2*w -2 * 2 + 5w[/tex]
[tex]= -2w -4 + 5w[/tex]
Collect Like Terms
[tex]= 5w-2w -4[/tex]
[tex]= 3w -4[/tex]
Hence;
[tex]-2(w + 2) + 5w = 3w- 4[/tex]
11. 16x^2 + 8 + 10x + 2x^2 + 14x
[tex]= 16x^2 + 8 + 10x + 2x^2 + 14x[/tex]
Collect Like Terms
[tex]= 16x^2 + 2x^2 + 10x + 14x+ 8[/tex]
[tex]= 18x^2 + 24x + 8[/tex]
Expand the expression
[tex]= 18x^2 + 12x + 12x + 8[/tex]
Factorize:
[tex]= 6x(3x + 2) + 4(3x +2)[/tex]
[tex]= (6x + 4)(3x +2)[/tex]
Hence;
[tex]16x^2 + 8 + 10x + 2x^2 + 14x = (6x + 4)(3x +2)[/tex]
12. b = -5 and y = 6
[tex]b + 9y =?[/tex]
Substitute -5 for b and 6 for y
[tex]= -5 + 9 * 6[/tex]
[tex]= -5 + 54[/tex]
[tex]= 49[/tex]
Hence;
[tex]b + 9y = 49[/tex]
13. y = -3
[tex]y^2 + 5y + 4 =?[/tex]
Substitute -3 for y
[tex]= (-3)^2 + 5(-3) + 4[/tex]
Open all brackets
[tex]= 9 -15 + 4[/tex]
[tex]= -2[/tex]
Hence;
[tex]y^2 + 5y + 4 = -2[/tex]
14.
[tex](-4)^3[/tex]
Open bracket:
[tex]= -4 * -4 * -4[/tex]
[tex]= -64[/tex]
Hence;
[tex](-4)^3 = -64[/tex]
[tex](-7)^2[/tex]
Open bracket:
[tex]= -7 * -7[/tex]
[tex]= 49[/tex]
Hence;
[tex](-7)^2 = 49[/tex]
15. Express as fractions:
[tex]\frac{3}{5^3}[/tex]
Evaluate the denominator
[tex]= \frac{3}{125}[/tex]
Hence:
[tex]\frac{3}{5^3} = \frac{3}{125}[/tex]
[tex](\frac{-1}{3})^2[/tex]
Evaluate the exponent
[tex]= (\frac{-1}{3})*(\frac{-1}{3})[/tex]
[tex]=\frac{1}{9}[/tex]
Hence:
[tex](\frac{-1}{3})^2=\frac{1}{9}[/tex]
16. Evaluate
[tex](-7)^0 =[/tex]
Evaluate the exponent
[tex](-7)^0 = 1[/tex]
[tex]2 * (1/3)^0[/tex]
Evaluate the exponent
[tex]= 2 * 1[/tex]
[tex]= 2[/tex]
Hence;
[tex]2 * (1/3)^0 = 2[/tex]
17. Evaluate
[tex]3v^2(-5v^4)[/tex]
Open bracket
[tex]= 3 * v^2*-5* v^4[/tex]
Reorder
[tex]= 3 *-5* v^4 * v^2[/tex]
[tex]= -15* v^4 * v^2[/tex]
Apply law of indices
[tex]= -15* v^{4 +2}[/tex]
[tex]= -15* v^6[/tex]
[tex]= -15v^6[/tex]
Hence:
[tex]3v^2(-5v^4) = -15v^6[/tex]
18.
[tex]2y^2w^4*6y*2w^8[/tex]
Rewrite as
[tex]2 *y^2 * w^4*6 * y*2 * w^8[/tex]
Reorder the terms
[tex]=2*6 * w^4 * w^8*y^2 * y*2[/tex]
[tex]=12 * w^4 * w^8*y^2 * y*2[/tex]
Apply law of indices
[tex]=12 * w^{4+8} *y^{2+2}[/tex]
[tex]=12 * w^{12} *y^4[/tex]
[tex]=12 w^{12} y^4[/tex]
Hence:
[tex]2y^2w^4*6y*2w^8 =12 w^{12} y^4[/tex]
19.
[tex](\frac{4p^3}{3p^7})^{-2}[/tex]
Apply law of indices
[tex]= (\frac{4p^{3-7}}{3})^{-2}[/tex]
[tex]= (\frac{4p^{-4}}{3})^{-2}[/tex]
Apply law of indices
[tex]= (\frac{4}{3p^4})^{-2}[/tex]
Apply law of indices
[tex]= (\frac{3p^4}{4})^{2}[/tex]
[tex]= (\frac{3p^4}{4}) * (\frac{3p^4}{4})[/tex]
Evaluate
[tex]= \frac{9p^8}{16}[/tex]
Hence;
[tex](\frac{4p^3}{3p^7})^{-2} = \frac{9p^8}{16}[/tex]
20.
[tex]\frac{x^{-2}}{x^{-3}}[/tex]
Apply law of indices
[tex]= x^{-2 - (-3)}[/tex]
[tex]= x^{-2 +3}[/tex]
[tex]= x^1[/tex]
[tex]= x[/tex]
Hence:
[tex]\frac{x^{-2}}{x^{-3}} =x[/tex]
Answer: So 5 + x = 8 beacase x is 3
Step-by-step explanation:
Find the missing power in the following calculation:108/9 · 10? = 10
Answer:
108/9 needs to be raised to the power of 0
Step-by-step explanation:
Any number that has an exponent of 0 equals 1. So:
(108/9)^0x10=10
Exercise 4.28: Keeping water supplies clean requires regular measurement of levels of pollutants. The measurements are indirect—a typical analysis involves forming a dye by a chemical reaction with the dissolved pollutant, then passing light through the solution and measuring its “absorbance.” To calibrate such measurements, the laboratory measures known standard solutions and uses regression to relate absorbance and pollutant concentration. This is usually done every day. Here is one series of data on the absorbance for different levels of nitrates. Nitrates are measured in milligrams per liter of water. Data can be found on Crunchit>File>Load from> Chapter 4> Exercise 28. b) It is appropriate to find the correlation (r) because the form of the relationship is c) Chemical theory says that these data should lie on a straight line. If the correlation is not at least 0.997, something went wrong, and the calibration procedure is repeated. Find the correlation using Crunchit!. Correlation r = (Enter it exactly as it appears on Crunchit!) d) The calibration process sets nitrate level and measures absorbance. At this point it appears as if Nitrate level is x and the absorbance is y but the roles of x and y get switched. Once established, the linear relationship will be used to estimate the nitrate level in water from a measurement of absorbance. If we are going to estimate the Nitrate level then that becomes the response variable. What is the equation of the line used for estimation? Write it in the form ____ = _____ + ______*_____. The two variables are "Nitrates", "Absorbance". e) What is the estimated nitrate level in a water specimen with absorbance 40? Your answer must have two decimal places. mg/liter f) Based on the correlation r we can say that the predicted value (estimate) of nitrate level is (very good/good/bad) g) The percent of the variation in Nitrate s that can be explained by absorbance is %. (two decimal places) h) We will only be able to use the regression equation to make predictions of nitrates for absorbance between nd . That is, we cannot plug in a number outside this range into the the regression equation to make a prediction
Answer:
..
Step-by-step explanation:
4•6÷2 to the power of 3=
The answer is 1728
First you must set up the equation
[tex](\frac{4*6}{2})^3[/tex]
Then, you must multiply the numerator
[tex](\frac{24}{2} )^3[/tex]
Next, divide
[tex](12)^3[/tex]
Finally, simplify exponents
[tex](12^3) =12*12*12[/tex]
12*12*12=1728
Answer:
3
Step-by-step explanation:
4 ×6 :2 ^3 =
24 :8 =
3
A tennis tournament starts with 117 players. If a player is eliminated after losing three matches, what is the least possible number of matches played when four players are left?
The least possible number of matches played when 4 players are left is 37 matches.
The given parameters;
total number of players in the tournament = 117 playersnumber of players to be eliminated after losing 3 matches = 1let the number of matches played when 4 players are left = nThe least possible number of matches played when 4 players are left is calculated as;
117 - 1(3n) = 4
117 - 3n = 4
3n = 117 - 4
3n = 113
divide both sides by 3
[tex]n = \frac{113}{3} \\\\n = 37.67 \\\\n \approx 37 \ matches[/tex]
Thus, the least possible number of matches played when 4 players are left is 37 matches.
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Help me I need help with this factorization of 630?
Answer:
The prime factors are: 2 x 3 x 3 x 5 x 7
or also written as { 2, 3, 3, 5, 7 }
Written in exponential form: 2 x 3 × 3 x 5 ×1 x 7×1
Complete the square
x2 – 24x – 5 = 0
Answer:
(x -12)^2 -149 = 0
Step-by-step explanation:
Add and subtract the square of half the x-coefficient:
x^2 -24x +(-24/2)^2 -(-24/2)^2 -5 = 0
(x -12)^2 -149 = 0
Are BD and CE congruent
Answer:
no
Step-by-step explanation:
b to d is 4 jumps away and c and e is 10 jumps
edit i meant 8 and d i messed up the calculations but the answer is correct
BD is 8 units long
CE is 10 units long
BD and CE are NOT congruent.
You are going to the mall with your friends and you have $200 to spend from your recent birthday money. You discover a store that has all jeans for $25 and all dresses for $50. You really, really want to take home 6 items of clothing because you "need" that many new things.
Answer:
4 Jeans and 2 dresses
Step-by-step explanation:
25×4=100
50×2=100
You want to take home 6 items of clothing. you can buy 4 jeans and 2 all dresses using 200 dollars .
Given :
You discover a store that has all jeans for $25 and all dresses for $50
Total of 6 items needed
Total amount you can spend is 200 dollars
Let x be the number of jeans and y be the number of all dresses
Lets frame equations using x and y
Total of 6 items ,
[tex]x+y=6\\y=6-x[/tex]
all jeans is for $25 and all dresses is for $50. total of 200 dollars can spend
[tex]25x+50y=200[/tex]
Substitute y=6-x in second equation
[tex]25x+50(6-x)=200\\25x+300-50x=200\\-25x+300=200\\-25x+300-300=200-300\\-25x=-100\\\frac{-25x}{-25}=\frac{-100}{-25}\\x=4[/tex]
Now substitute x=4 in first equation
[tex]y=6-x\\y=6-4\\y=2[/tex]
you can by 4 jeans and 2 all dresses
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scale used 1:250000 amd the distance is 8.5 mile whats the actual distance
Answer:
.
Step-by-step explanation:
Dan Pawlik is paid a straight commission of $5.75 for each item he sells. Last month he sold 103 items. Find his estimated and exact commissions.
Answer:
[tex]Estimated\ Commission = \$618[/tex]
[tex]Exact\ Commission = \$592.25[/tex]
Step-by-step explanation:
Given
[tex]Commission = \$5.75[/tex]
[tex]Items = 103[/tex]
Required
Find the estimate and exact commission
Estimate Commission
First, we need to approximate the given commission
[tex]Commission = \$6[/tex]
[tex]Estimated\ Commission = Commission * Items[/tex]
[tex]Estimated\ Commission = \$6 * 103[/tex]
[tex]Estimated\ Commission = \$618[/tex]
Exact Commission
[tex]Exact\ Commission = Actual\ Commission * Items[/tex]
[tex]Exact\ Commission = \$5.75 * 103[/tex]
[tex]Exact\ Commission = \$592.25[/tex]
Solve for x.
X +1=10
8
Answer:
Step-by-step explanation:
x + 1 = 10
x = 9
Answer:
x = 9
Step-by-step explanation:
x + 1 = 10
=> x = 10 - 1
=> x = 9
I will give brainliest answer
Answer:
Isnt it 12? the first rectangle says 2 on one side and 6 on another. The rectangle didn't change shape, but position.
Am I right??
f(x) = -2(x+3)(x - 1)
What is the vertex
Answer:
see attechment: - vertex (-1, 8)
Step-by-step explanation:
focus | (-1, 63/8) = (-1, 7.875)
vertex | (-1, 8)
semi-axis length | 1/8 = 0.125
focal parameter | 1/4 = 0.25
eccentricity | 1
directrix | f = 65/8
luke can paint 91 portraits in 7 weeks. how many portraits does he paint each week?
Answer:
the answer is 13, because you need to divide 91 by 7.
Find the modulus of z = 3 + 3i.
Answer: 3√2
Step-by-step explanation:
i had a quiz with this question and it said this was the correct answer
Which is greater 4.08 or 4.1
Answer:
4.1 is greater
Step-by-step explanation:
4.1 is greater than 4.08 by 0.02 units
Answer:
4.1
Step-by-step explanation:
4.1 can also be written as 4.10 . Now if we compare 4.08 & 4.10 then in 4.10 , then
4.10 > 4.08 (because 0.10 is greater than 0.08 by 0.02 units )
y = c1 cos(3x) + c2 sin(3x) is a two-parameter family of solutions of the second-order DE y'' + 9y = 0. If possible, find a solution of the differential equation that satisfies the given side conditions. The conditions specified at two different points are called boundary conditions. (If not possible, enter IMPOSSIBLE.)
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is [tex]y = 5sin3x[/tex]
Step-by-step explanation:
From the question we are told that
[tex]y = c_1\ cos3x + c_2 \ sin 3x[/tex]
given that y(0) = 0
We have that
[tex]c_1\ cos3(0) + c_2 \ sin 3(0) = 0[/tex]
=> [tex]c_1 = 0[/tex]
This means that
[tex]y = c_2 \ sin 3x[/tex]
We also given that
[tex]y[\frac{\pi}{6} ] = 5[/tex]
So
[tex]c_2 sin (3 * \frac{\pi}{6} ) = 5[/tex]
=> [tex]c_2 = 5[/tex]
Hence
[tex]y = 5sin3x[/tex]
PLEASE SOMEONE HELP, ZERO CLUE HOW TO DO THIS, pleaseeeee
Answer:
4) 15) 4Step-by-step explanation:
You just need to find the corresponding coordinates on the graph by using one of the coordinates and the graph.
4) Find f(0.8)
Find the point 0.8 on the x-axis and check the point the vertical line from that point crosses the graph. See what that point is on the y-axis.
This is point 1
The answer is 1, the point has coordinates (0.8, 1)
5) Find x when f(x) = 3
Find the point of the graph against 3 on the y- axis
And check what is corresponding point on x-axis, this is point 4
So the answer is 4, the point has coordinates of (4,3)
Answer:?
Step-by-step explanation:
Qual a expressão algébrica representa o perímetro das figuras a seguir:
Answer:
mom
Step-by-step explanation:
Is 3 a whole number
In a certain class, 11/20 of the students got problem 20 wrong on Friday's math test.
Answer:
U need to copy and paste more of the question
Step-by-step explanation:
Start copy at the top go all the way to the bottem of the question and paste into brainly.
use ctrl c for copy and crtl v for paste
Answer:
Then 9/20 got them right
Step-by-step explanation:
20/20-11/20=9/20
there isn't enough context so that's the best i can do
