If a(x) = 3x + 1 and b (x) = square root of x-4, what is the domain of (b o a)(x)

Note that

[tex]x^2 - y^2 = (x - y) (x + y)[/tex]

and

[tex]x^2 + 2xy + y^2 = (x + y)^2[/tex]

Then their LCM is [tex]\boxed{x + y}[/tex].

Answer:

B

Step-by-step explanation:

-2|x - 1| = -4

|x - 1| = 2

since we are dealing with a function that brings 2 values to the same result, the reverse function (needed to find the values of x that create the result y) has 2 branches :

(x - 1) = 2

and

(x - 1) = -2

x - 1 = 2

x = 3

x - 1 = -2

x = -1

therefore, B is the right answer.

Answer:

y = 4x - 17

Step-by-step explanation:

y - 3 = 4(x - 5) ← distribute parenthesis by 4

y - 3 = 4x - 20 ( add 3 to both sides )

y = 4x - 17

Answer:

in the pic...

Step-by-step explanation:

Hope it Helps!!!

Answer:

centre (5,0)

radius:9

I hope it will be helpfulness

Answer:

35 miles per hour

Step-by-step explanation:

Speed of a car or any other object is given by distance divided by time taken.

therefore,

according to the given data in the table :

speed = miles covered/ time taken

           =  140/4 = 35 miles per hour

           =  175/5 = 35 miles per hour

           =  210/6 = 35 miles per hour

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Answer:

The answer is (-84)

putting the value of X =(- 3)

2) X = 216

Hello!

We are going to evaluate the expression with our given x-value for question 2.

We know that our expression is: x^4 + 5x^3 - 3x^2 + 11x - 6

We also know that our x-value = 3

We will simply plug in "3" to "x" in our expression and solve.

Solve:

x^4 + 5x^3 - 3x^2 + 11x - 6

Plug in 3 to x:

(3)^4 + 5(3)^3 - 3(3)^2 + 11(3) - 6

Simplify:

(3)^4 + 5(3)^3 - 3(3)^2 + 11(3) - 6

81 + 5(3)^3 - 3(3)^2 + 11(3) - 6

81 + 135 - 3(3)^2 + 11(3) - 6

81 + 135 - 27 + 33 - 6

216 - 27 + 33 - 6

189 + 33 - 6

222 - 6 = 216

Therefore, our final answer would be 216.

Answer:

216

Answer:

You need 2 numbers whose product is 45 and whose difference is 4.

so the length is 9 and the width is 5.

Hope this helps.

Answer:

a. y = 2(x + 3)² - 17

b. y = 4(x + 6)² - 154

Step-by-step explanation:

a. y = 2x² + 12x + 1

y = 2[(x² + 6x)] + 1

y = 2[(x + 3)² - 9] + 1

y = 2(x + 3)² - 18 + 1

y = 2(x + 3)² - 17

b. y = 4x² + 48x - 10

y = 4[(x² + 12x)] - 10

y = 4[(x + 6)² - 36)] - 10

y = 4(x + 6)² - 144 - 10

y = 4(x + 6)² - 154

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: y= - \cfrac{x}{ 3} + 1 [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

Equation of line (two point form) :

[tex]\qquad \tt \rightarrow \: (y - y_1) = \cfrac{y _1- y_2}{ x_1 - x_2} (x - x_1)[/tex]

[tex]\qquad \tt \rightarrow \: (y - 2) = \cfrac{2 - ( - 1)}{ - 3 - 6} (x - ( - 3))[/tex]

[tex]\qquad \tt \rightarrow \: (y - 2) = \cfrac{2 + 1}{ - 9} (x + 3)[/tex]

[tex]\qquad \tt \rightarrow \: (y - 2) = - \cfrac{3}{ 9} (x + 3)[/tex]

[tex]\qquad \tt \rightarrow \: (y - 2) = - \cfrac{1}{ 3} (x + 3)[/tex]

[tex]\qquad \tt \rightarrow \: y - 2= - \cfrac{x}{ 3} - \cfrac{3}{3} [/tex]

[tex]\qquad \tt \rightarrow \: y = - \cfrac{x}{ 3} - 1 \cfrac{}{} + 2[/tex]

[tex]\qquad \tt \rightarrow \: y = - \cfrac{x}{ 3} + 1[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

10 cm is 20% of 50 cm.

Step-by-step explanation:

1) Put the "question" into fraction form: 10/50

2) Divide the numerator by the denominator (essentially changing the fraction into the decimal form): 10 ÷ 50 = 0.2

3) Multiply the quotient by 100: 0.2 × 100 = 20

4) Slap a "%" on the end and you're good to go!! : 20%

Volume = PI x r*2 x h/3

r = radius which is shown as 8

h is the height which is shown as 63

Volume = 3.14 x 8^2 x 63/3

Volume = 3.14 x 64 x 21

Volume = 4,220.16 cubic units.

Answer:

C. -2

Step-by-step explanation:

Use A-P-E-X

How I solved it:

3/4(1/5÷3/5)(-8)

3/4(1/5×5/3)(-8)

3/4(1/3)(-8)

1/4(-8)=-2

Hope this helps!

If not, I am sorry.

Answer:

B. shifting

Step-by-step explanation:

When the price is rising or shifting higher, the demand curve moves to the left. But, t here is a corresponding change in the demand curve in that scenario while the cost stays unchanged. Since it relies on variables other than price, the simultaneous shift might go either left or right. However, the upward-pointing line depicts a rise in price and a fall in supply. 

Answer: The answer for this problem is all real numbers or R.

Step-by-step explanation: In order to solve first you must deal with what's inside the parenthesis.

[tex]8(4x+2)=8*4x + 8*2= 32x +16[/tex]

Now that the parenthesis is out of the picture, now proceed to subtract the 16 that was outside of the parenthesis.

[tex]32x+16-16=32x[/tex]

You should then have an equation set up like so.

32x = 32x

Now you need to move one of the 32x's to the other side of the equation.

[tex]32x-32x=0[/tex]

Your final equation should be.

0 = 0

So, all real numbers (R) will work for this equation.

Answer:

Step-by-step explanation:

Answer:

well not sure but I think it is 8° or 17.8°

Answer:

The slope is undefined

Step-by-step explanation:

[tex]m=\frac{9-3}{2-2}[/tex]

The denominator leads to 0 so it would not be possible to find the answer

Answer:

undefined

Step-by-step explanation:

anything divided by zero is undefined since you cant logically give (for example) 2 apples to 0 people.

For slopes not so obvious, the formula is (slope)m= (rise)y/(run)x

The error from Jorge's arithmetic operation on the given algebraic expression is that he distributed it incorrectly.

An algebraic expression is a mathematical equation that is made up of variables together with arithmetic operations.

From the given expression, we have:

4x - x + 2 + 6 = 6x + 16

Add similar elements together;

3x + 8 = 6x + 16

Using distributive property, subtract 8 from both sides:

3x + 8 - 8 = 6x + 16 - 8

3x = 6x + 8

Simplify

3x-6x = 8

-3x = 8

Divide both sides by -3

-3/-3x = -8/3

x =  -8/3

So from Jorge's calculation, because he distributed incorrectly, we can conclude that could be his error.

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When a given function is written with factors in the form of ( x - r ), then r is a zero of the function.

We're given:

Therefore, the zeros of the function are 7 and -6.

-6, 7

The zeroes of the function will be equal to ( 7, -6 ).

It is a polynomial with a degree of 2 or the maximum power of the variable is 2 in quadratic equations. It has two solutions as its maximum power is 2.

Given function:-

As we can see that the quadratic equation in the factorized form is ( x - 7 ) ( x+ 6 ) so we will equate each factor to zero.

( x- 7 )  = 0

x = 7

( x+ 6 ) = 0

x = -6

Therefore zeroes of the function will be equal to ( 7, -6 ).

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Answer:

x = 8

Step-by-step explanation:

[tex]\sf If\:\: \overline{NO} \parallel \overline{KJ}\:\:then\:\: \triangle LNO \sim\triangle LKJ[/tex]

Therefore:

[tex]\implies \sf \overline{LN} : \overline{LO} = \overline{LK} : \overline{LJ}[/tex]

[tex]\implies (x-3):(x-4)=(x-3)+(x+2):(x-4)+x[/tex]

[tex]\implies \dfrac{x-3}{x-4}=\dfrac{2x-1}{2x-4}[/tex]

[tex]\implies (x-3)(2x-4)=(2x-1)(x-4)[/tex]

[tex]\implies 2x^2-10x+12=2x^2-9x+4[/tex]

[tex]\implies -10x+12=-9x+4[/tex]

[tex]\implies 12=x+4[/tex]

[tex]\implies x=8[/tex]

Answer:

4 rows

Step-by-step explanation:

First set:

unknown rows, 5 tiles each

meaning old total is divisible by 5

Second set:

3 additional rows, 3 tiles each

meaning that the new total is divisible by 3

so, our total number of tiles is divisible by 5, add 1 and it is divisible by 3 when added 1

{another way I solved it : [and when it is divided by 3, it has 8 that fit into the original pattern; which is another way of knowing that each of the rows of 5 [each have 2 removed when turned into rows of 3] add up to having a remainder of 8 tiles; 8 / 2 = 4; so there were four rows in the original pattern contributing to the change--there were four rows] }

x is divisible by 5, x + 1 is divisible by 3

essentially, we are looking for a number that ends in 5 or 0, and the next number [ending in 6 or 1] is divisible by 3

I know that 5 goes into 20, and that 21 is divisible by 3, so let's test it out:

4 (rows of 5) turns into 7 [4 + 3] rows of 3

because 21 can be split into 7 rows, this number of tiles is possible

so, in the original pattern, there must have been 4 rows

hope this helps!! {so sorry if this confuses you, please let me know if I should explain my reasoning further}

have a lovely day :)

The required piecewise function that represents the graph is given as:

[tex]f(x)=\left \{ {{y = -3x-10} \atop y=-\frac{1}{2}x-3 } \atop y=-2x-6 }} \right.[/tex]

The graph consists of 3 lines with different equations and slopes. In order to determine the function it represents, we will create a piecewise function.

For the line crossing the negative x-axis

Using the coordinate points (-4, 2) and (-2, -4)

Slope = -6/2

Slope = -3

2 = -3(-4) + b
2 - 12 = b

b = -10

The equation of the line will be y = -3x-10

For the line crossing the negative y-axis

Using the coordinate points (-2, -4) and  (2,-2)

Slope = 2/4

Slope = 1/2

-2 = 1/2(2) + b
-2 - 1 = b

b = -3

The equation of the line will be y = -1/2x-3

For the line crossing the positive x-axis

Using the coordinate points (2, -2) and (3, 0)

Slope = 2/1

Slope = 2

0 = 2(3) + b
0 - 6 = b

b = -6

The equation of the line will be y = 2x-6

The required piecewise function that represents the graph is given as:

[tex]f(x)=\left \{ {{y = -3x-10} \atop y=-\frac{1}{2}x-3 } \atop y=-2x-6 }} \right.[/tex]

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Answer: i think no?

Step-by-step explanation:

AD and BE are both parallel lines (they are parallel to eachother), so they will never intersect

CF and GF intersect at point F (i think)

Bg and Ac intersect at point B (i think)

i dont want to give a definite answer in the event im wrong bc I just learned this like a few weeks ago-

Based on the key features, the end behavior and the zeros of function h [h(x) = -x³ - 9x² +4x +96], the statement that is true of the above graph is: "The graph is positive on the intervals (-8, -4) and (3, infinity) (Option B)"

A function's "end behavior" refers to how the function's graph behaves at its "ends" on the x-axis.

In other words, if we look at the right end of the x-axis (as x approaches + ∞) and the left end of the x-axis (as x approaches - ∞ ), the end behavior of a function represents the trend of the graph.

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Answer:

3:1

Step-by-step explanation:

3 and 1 is not divisible by any number

Answer:

1. 3/14

2. 2/7

3. 1/7

4. 5/14

5. 11/14

6. 9/14

Step-by-step explanation:

first get the total number of pens

3 red pens + 4 blue pens + 2 black pens + 5 green pens =

14 total number of pens

1. What is the probability that the pen chosen red?

3 red pens out of a total of 14 pens = 3/14

2. What is the probability that the pen chosen is blue?

4 blue pens out of a total of 14 pens = 4/14 -> simplified -> 2/7

3. What is the probability that the pen chosen is black?

2 black pens out of a total of 14 pens = 2/14 -> simplified -> 1/7

4. What is the probability that the pen chosen is green?

5 green pens out of a total of 14 pens = 5/14

5. What is the probability that the pen chosen is NOT red?

of the 3 red pens, 4 blue pens, 2 black pens and 5 green pens

4 blue pens, 2 black pens and 5 green pens are NOT red

4 blue pens + 2 black pens + 5 green pens =

11 total number of pens that are NOT red

11 total number of pens that are NOT red out of a total of 14 pens = 11/14

6. What is the probability that the pen chosen is NOT green?

of the 3 red pens, 4 blue pens, 2 black pens and 5 green pens

the 3 red pens, 4 blue pens, 2 black pens are NOT green

3 red pens + 4 blue pens + 2 black pens =

9 total number of pens that are NOT green

9 total number of pens that are NOT green out of a total of 14 pens = 9/14

gathmath.com

Given :-

>> Total no. of outcomes = 3 + 4 + 2 + 5

>> Total no. of outcomes = 3 + 4 + 7

>> Total no. of outcomes = 10 + 4

>> Total no. of outcomes = 14

Solution 1 :-

We know,

As there are three red pens. Therefore,

Solution 2 :-

We know,

As there are four blue pens. Therefore,

Solution 3 :-

We know,

As there are two black pens. Therefore,

Solution 4 :-

We know,

As there are five green pens. Therefore,

Solution 5 :-

We know,

As there 11 pens that are not red (Green + black + blue).

Solution 6 :-

We know,

As there are 9 pens that are not green (Red + blue + black).

The height of the shorter cone is 6.81cm

A cone is hollow three-dimensional shape with side lengths that tappers from the base to a point at the vertex.

Analysis:

Let the radius of the first cone be = r

radius of shorter cone = R

height of first cone = h

height of shorter cone = H

if volume of the two cones are same

1/3π[tex]r^{2}[/tex]h = 1/3π[tex]R^{2}[/tex]H

[tex]r^{2}[/tex]h = [tex]R^{2}[/tex]H

H =  [tex]r^{2}[/tex]h /  [tex]R^{2}[/tex]

H = [tex](8.5)^{2}[/tex]x 10 / [tex](10.3)^{2}[/tex] = 6.81cm

In conclusion, the height of the shorter cone is 6.81cm

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Answer:

Maybe the answer will be C. P ( A and B )

explanation:

I think it is OPTION C , P(A and B)

as this is the only option which has the value of 80, which we got from the table...

Answer:

a

Step-by-step explanation:

given a quadratic equation in standard form

ax² + bx + c = 0 ( a ≠ 0 )

then the discriminant

Δ = b² - 4ac

• if b² - 4ac > 0 then 2 real solutions

• if b² - 4ac = 0 then 2 real and equal solutions

• if b² - 4ac < 0 then no real solutions

given

[tex]\frac{3}{4}[/tex] x² - 3x = - 4 ( add 4 to both sides )

[tex]\frac{3}{4}[/tex] x² - 3x + 4 = 0 ← in standard form

with a = [tex]\frac{3}{4}[/tex] b = - 3 , c = 4

then

b² - 4ac = (- 3)² - ( 4 × [tex]\frac{3}{4}[/tex] × 4) = 9 - 12 = - 3

since b² - 4ac < 0 then equation has no real solutions

Answer:

a.  -3; no real solutions.

Step-by-step explanation:

Discriminant

[tex]\boxed{b^2-4ac }\quad\textsf{when}\:ax^2+bx+c=0[/tex]

[tex]\textsf{When }\:b^2-4ac > 0 \implies \textsf{two real solutions}.[/tex]

[tex]\textsf{When }\:b^2-4ac=0 \implies \textsf{one real solution}.[/tex]

[tex]\textsf{When }\:b^2-4ac < 0 \implies \textsf{no real solutions}.[/tex]

Given equation:

[tex]\dfrac{3}{4}x^2-3x=-4[/tex]

Add 4 to both sides of the equation so that it is in standard form:

[tex]\implies \dfrac{3}{4}x^2-3x+4=-4+4[/tex]

[tex]\implies \dfrac{3}{4}x^2-3x+4=0[/tex]

Therefore, the variables are:

[tex]a=\dfrac{3}{4}, \quad b=-3, \quad c=4[/tex]

Substitute these values into the discriminant formula to find the value of the discriminant:

[tex]\begin{aligned}\implies b^2-4ac&=(-3)^2-4\left(\dfrac{3}{4}\right)(4)\\&=9-(3)(4)\\&=9-12\\&=-3\\\end{aligned}[/tex]

Therefore, as -3 < 0, the discriminant is less than zero.

This means there are no real solutions.