If Corolla does 1,800,000 Joules of work in a 400 meter race, how much average force was applied through that distance?

Answers

Answer 1

Answer:

4500 N

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

To find the force applied we make force the subject in the formula above

That's

[tex]f = \frac{w}{d} \\ [/tex]

w is the workdone

d is the distance

From the question we have

[tex]f = \frac{1800000}{400} = \frac{18000}{4} = 4500\\ [/tex]

We have the final answer as

4500 N

Hope this helps you


Related Questions

please help pleaseeeeee

Answers

Answer:

25mg

Explanation:

it basically explains itself

When did the objects that we now see as asteroids and comets form in the solar system?.

Answers

Answer:

After solid particles condensed from the gas but before the planets finished forming

Why are people so rude???

Answers

Answer:

It could be low self-esteem

Explanation:

There probably insecure have problems and issues of their own could be that were abused growing up and weren’t treated right who knows.

What are 4 ways you can determine if a website is reliable?

Answers

Answer:

Identify the name of the individual, group or institution that created the website. A reliable website should clearly state the name of its creator. Generally, websites created by government institutions (.gov) and educational institutions (.edu) are considered more reliable.

A 50-n force is applied to a 10-kg chair, but the chair does not change its motion. What could explain this?.

Answers

Explanation:

it will not change it's motion because it's force is less than the force applied

Name two processes that release nuclear energy?

Answers

Answer:  Nuclear energy is released from an atom through one of two processes: nuclear fusion or nuclear fission. In nuclear fusion, energy is released when the nuclei of atoms are combined or fused together. This is how the sun produces energy. In nuclear fission, energy is released when the nuclei of atoms are split apart.

Let me know if it helps!

a gas increases in pressure from 2.00 atm to 6.00 atm at a constant volume of 1.00 m3 and then expands at constant pressure to a volume of 3.00 m3 before returning to its initial state as shown in the figure below. how much work is done in one cycle?

Answers

The work done on the given gas in one cycle is -405.3 kJ.

The given parameters;

initial pressure of the gas, P₁ = 2 atmfinal pressure of the gas, P₂ = 6 atminitial volume of the gas, V₁ = 1 m³final volume of the gas, V₂ = 3 m³

Convert the pressure to Pascal (N/m²);

1 atm = 101325

The work done in one cycle is the area of the triangle and it is calculated as follows

[tex]Area = \frac{1}{2} \times base \times height\\\\Area = \frac{1}{2} \times (3 \ m^3\ -\ 1 \ m^3)\times (6 \ atm \ - \ 2 \ atm)\\\\Area = 4 \ atm -m^3\\\\Area = 4 \ atm -m^3 \ \times \frac{101325 \ Pa}{1 \ atm} \\\\Area = 405,300 \ m^3.Pa\\\\Area = 405,300 \ m^3. (N/m^2)\\\\Area = 405,300 \ Nm\\\\Area = 405,300 \ J\\\\Area = 405.3 \ kJ[/tex]

the net work done on the gas = - 405.3 kJ

Thus, the work done on the given gas in one cycle is -405.3 kJ.

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Please help :[ Hold a flat piece of paper horizontally. Lift it high in front of you, and drop it. Then crumple a piece of paper into a tight ball, hold it high in front of you, and drop it from the same height. Compare the motion of the two pieces of paper.

Answers

The one you lifted in front of you ( the flat piece of paper being holded horizontally ) goes down so slow. While the one being crumpled into a ball goes down fast. Subscribe to DreamfanBG for support.

Answer:

Answer below

Explanation:

The flat piece of paper just gently glided to the ground, as if it were a feather. It didn’t go down in a straight line, it swayed from side to side. The crumpled piece of paper seemed like it had more weight to it (although I know that it didn’t), and it fell way quicker than the flat piece of paper.

_____________________________________________________

(Hope this helps can I pls have brainlist (crown)☺️)

. Which of the following are forces that push upward on an indoor skydiver? Choose all that apply. *
gravity
acceleration
air resistance
lift


WILL GIVE BRAINLIST

Answers

The forces that push upward on an indoor skydiver are lift force and air resistance.

The forces that act on a skydiver moving downwards includes, gravity due to his weight, air resistance and lift force.

The downward forces on the indoor skydiver include the following;

gravity due to its weightdownward force due its acceleration

The upward force on the indoor skydiver include the following;

lift forceair resistance

Thus, we can conclude that the forces that push upward on an indoor skydiver are lift force and air resistance.

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ECONOMIC Q‼️
Which of these is a common concern of an economist ?

A-The distributions of populations and earths resources
B-How people have organized the rules and laws of their societies
C-The cultural habits and social customs of societies
D-How well resources are used by a society

Answers

Answer:

D-How well resources are used by a society

Explanation:

Most economists are concerned with practical applications of economic policy in a particular area, such as finance, labor, agriculture, transportation...

Hope this helps luvv :)

a ball is thrown vertically up ward with a velocity of 25m/s. a/how fast was it moving after 2sec?​

Answers

Answer:

12.5

Explanation:

given

distance=25

time=2sec

required

=speed

solution

=v=s/t

25/2

=12.5m/s

If 40 N force is exerted by a box covering 2 metre square area, calculate pressure.

Answers

Force=40NArea=2m^2

[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]

[tex]\\ \sf\longmapsto Pressure=\dfrac{40}{2}[/tex]

[tex]\\ \sf\longmapsto Pressure=20Pa[/tex]

[tex] \sf \huge \red {\dag} Given[/tex]

[tex]\sf \longmapsto \: Force \: = 40 \: Newtons[/tex]

[tex]\sf \longmapsto \: Area \: = \: 2m \: Square \: ( {2m}^{2} )[/tex]

We know that the formula of Pressure is

[tex]\sf \longmapsto \: Force/Area[/tex]

Let's start.

Put the values

[tex]\sf \longmapsto \: \: P = 40 \: newtons(force)/2(Area)[/tex]

[tex]\sf \longmapsto Pressure \: 20 \: N/m^2[/tex]

[tex]\boxed{\sf\red{\boxed{ \sf Pressure ≈ \: 20 \: N/m^2}}}[/tex]

What happens when you want to move the boat forward? You pull the oars toward yourself.Explain why you do this.

Answers

Answer:

You pull on the oars. By the third law, the oars push back on your hands, but that’s irrelevant to the motion of the boat. The other end of each oar (the blade) pushes against the water. By the third law, the water pushes back on the oars, pushing the boat forward.

Sheeeeeeeeeeeeeeeeeeeeeeeeeeeeesh

What is Kepler’s first law?

Answers

Answer:

Kepler's First Law: each planet's orbit about the Sun is an ellipse. The Sun's center is always located at one focus of the orbital ellipse. The Sun is at one focus. The planet follows the ellipse in its orbit, meaning that the planet to Sun distance is constantly changing as the planet goes around its orbit.

Answer:

Explanation:

Kepler 's first law - sometimes referred to as the law of ellipses - explains that planets are orbiting the sun in a path described as an ellipse. An ellipse can easily be constructed using a pencil, two tacks, a string, a sheet of paper and a piece of cardboard. Tack the sheet of paper to the cardboard using the two tacks.

Help me quickly! please!!!

A cable pulls a car up a mountain with a force of 4 × 103 N at a vertical constant velocity of 5 m.s-1. It takes 5 minutes to reach the top.

(a)How much work is done in getting the car to the top?
(b)How much work would have been done if the vertical speed was 2,5 m.s-1?
(c)Calculate the power exerted on the cable car in those 5 minutes.

Answers

Answer:

(a) 6,000,000J      

(b)  3,000,000J

(c)  For A 20,000W

But for B 10,000W

The work done in getting  the car to the top is equal to 6 ×10⁶ J. If the vertical speed is 2.5 m/s then, the work done will be  3 ×10⁶ J. The power exerted on the car is in 5 minutes is 20000 J/s.

What is work done ?

In physics, work done is the dot  product of force and displacement. Let w be the work done and F and ds be the force and displacement. Then

W = F.ds

It is given that the, the force of the cable is 4 × 10³ N. The velocity is 5 m/s and time is 5 minutes or 300 seconds. Now, the displacement is the product of time and velocity.

ds = velocity ×  time

    =  300 s ×  5 m/s

    = 1500 m.

Thus the work done = F × ds

                                  = 4 × 10³ N ×  1500 m

                                  = 6 ×10⁶ J .

If the velocity is reduced to half 2.5 m/s , then work done will be reduced to half as 3 ×10⁶ J.

Power is the rate of work done. Thus it is the ratio of work done to time. The power exerted on the car in 5 minutes = 6 ×10⁶ J /300s

                                                                        = 20000 J/s

Hence, the power exerted on the cable car in 5 minutes is 20000 J/s.

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The rate at which work is done is called

a. efficiency

b. effort time

c.

force

d. power

Please select the best answer from the choices provided

Ο Α

ОВ

ОС

Answers

Answer:

The rate at which work is done is power

Interpreting Graphics
11. Look at the model of an atom below. Does the
model represent a metal atom or a nonmetal
atom? Explain your answer.
ng

Answers

answer:
This is a metal atom

explanation:
metal atoms have fewer electrons in their outer shells than non-metal atoms do.

By looking at the model shown in the problem one can clearly say that this model represents the metal because there are a total of 12 electrons revolving around the nucleus which clearly represents the Magnesium metal.

What are metalloids?

The elements of the periodic tables that behave as metals, as well as the nonmetal in some chemical or physical aspects, are known as metalloids. Some examples of metalloids are Boron, silicon, germanium, arsenic, antimony, tellurium, etc.

As given in the problem, there is a graphical representation of the model of an atom,

One can see that the model in the problem accurately depicts the metal by looking at the total of 12 electrons circulating around the nucleus, which is a clear representation of the magnesium metal.

To learn more about metalloids here, refer to the link given below

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Bella wants to know which mode of transportation is the fastest for getting from her home to the grocery store. She can drive her car, ride her bike, walk, or charter a helicopter.
Independent variable
Dependent variable
Controlled variables
Hypothesis

Answers

Based on the question, the following applies:

Independent variable: Time Dependent variable: Mode of transportationControlled variable: Distance traveledHypothesis: IF Bella charters a helicopter, THEN she will get to the grocery store faster.

VARIABLES IN AN EXPERIMENT:

The following are definitions of some variables in an experiment:

Independent variable in an experiment is the variable that is altered or changed by the experimenter. Dependent variable is the variable that is measured or recorded in an experiment. Controlled variable is the variable that is kept constant or unchanged throughout the experiment.

According to this question, Bella wants to know which mode of transportation is the fastest for getting from her home to the grocery store. The following are the variables in this experiment:

Independent variable: Time Dependent variable: Mode of transportationControlled variable: Distance traveledHypothesis: IF Bella charters a helicopter, THEN she will get to the grocery store faster.

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density differences in different materials are able to change the _____________ of a wave.

Answers

Answer:

Wavelength and speed both depend on the material of the medium.

Explanation:

Let [tex]f[/tex] denote the frequency of a wave. Let [tex]v[/tex] denote the speed of that wave in a given medium. Let [tex]\lambda[/tex] denote the wavelength of that wave in this medium.

The frequency [tex]f[/tex] of a wave stays the same regardless of the material of the media. However, the speed [tex]v[/tex] of a wave indeed depends on the material of the medium (density of the medium, etc.)

[tex]\lambda = v / f[/tex] and [tex]f[/tex] stays the same regardless of the medium. Thus, the wavelength [tex]\lambda[/tex] of this wave in a given medium would be proportional to the speed [tex]v[/tex] in that medium.

For example, the speed of sound in materials with a larger density (e.g., water) is generally larger than that in materials with lower density (e.g., air.)

When a sound wave travels from air into water, the frequency [tex]f[/tex] of this wave would stay the same. However, since the speed [tex]v[/tex] of the wave would increase, the wavelength [tex]\lambda[/tex] of this wave would also increase.

Change.
Wax melting is an example of a chemical reaction.
True or false

Answers

i believe it is a physical change not chemical

1. Shelly pushes a .0035 kg marble with
a force of .07.N.

Answers

Answer:

pressure= force/area

Explanation:

pressure= 0.07/0.0035

             = 20 pascal

a uniform metre rule of mass 100g balances at the 40cm mark when a mass X is placed at the 10cm mark what is the value of x.pls help I don't know how to solve it​

Answers

Answer:

The fulcrum of the metre stick is at the 40 cm mark

100 g * 10 cm = 1000 g-cm clockwise torque

x * 30 cm = 1000 gm-cm = counterclockwise torque for balance

X = 1000 / (40 -10) = 1000 / 30 = 33.3 gm  at 10 cm to balance


Why does the blue force have a negative sign?
-20 N
50 N
Because 50 is smaller than 20
Because 20 is smaller than 50
Because it is pointing to the left
Because it is blue

Answers

it’s B (because 20 Is smaller than 50)

What would be the extension of the spring for a 3 N weight if the extension of the spring was 4 mm for a 50 g mass?
А 4 mm B)8 mm C)12mm D)24 mm​

Answers

Answer:

24mm

Explanation:

3 N to g is 305.9 g

50g ---- 4 mm

305.9 ----- 4×305.9/50 = 24 mm

A 1,500 kg car’s speed changes from 30 m/s to 15 m/s after the brakes are applied. Calculate the work done onto the car from the brakes.

Answers

The work done onto the car is 506,250 J

The work done on a system implies an increase in the internal energy of the system as a result of some forces acting on the system from the outside.

From the parameters given:

The mass of the car = 1500 kgThe initial speed = 30 m/sThe final speed = 15 m/s

The work done onto the car refers to the change in the kinetic energy (i.e. ΔK.E)

[tex]\mathbf{=\dfrac{1}{2} mv_1^2 -\dfrac{1}{2} mv_2^2}[/tex]

[tex]\mathbf{=\dfrac{1}{2} m(v_1^2 - v_2^2)}[/tex]

[tex]\mathbf{=\dfrac{1}{2} \times 1500 \times (30^2 - 15^2)}[/tex]

= 506,250 J

Therefore, we can conclude that the work done on the car is 506,250 J

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A girl pushes her little brother on his sled with a force of 300 N for 750 m.

Answers

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

an astronomer looking out into space will observe that

Answers

Answer:

The farther out a galaxy is from Earth, the faster it is moving away.

Explanation:

How to find the energy in a compressed spring.

Answers

Energy stored in a spring
Work is done when a spring is extended or compressed . Elastic potential energy is stored in the spring. ...
The elastic potential energy stored can be calculated using the equation:
elastic potential energy = 0.5 × spring constant × (extension) 2

A marble is launched at by dropping it through a marble launcher. The marble took 0.22s to land 0.31m from
where it was launched. Find the horizontal velocity of the marble as it rolls off the table.

A. 1.4m/s
B. 0.53m/s
C. 0.71 m/s
D. 0.07m/s

Answers

Hi there!

For projectile motion, the horizontal and vertical components are SEPARATE.

We can use the kinematic equation to solve:

dₓ = vₓt

We can rearrange to solve for vₓ:

dₓ/t = vₓ

0.31/0.22 = vₓ

vₓ = 1.4 m/s ⇒ A

something about the earth's surface (land or water) changes

Answers

I would say land changes.
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