If force F, volume V and density D are taken as fundamental quantities, then the representation of pressure P will be​

Answers

Answer 1

Using the principle of dimensional analysis, the representation of Pressure would be [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]

Pressure is related to Force, Volume and Density thus :

[tex] Pressure, P = F^{a}V^{b}D^{c}[/tex]

Using dimensional analysis :

Pressure, P = ML¯¹T¯²

Substituting the dimension into the relation :

[tex] ML^{-1}T^{-2}= [MLT¯²]^{a} [L³]^{b} [ML¯³]^{c} [/tex]

[tex] ML^{-1}T^{-2} = M^{a+c}L^{a+3b-3c}T^{-2a} [/tex]

Equating the power ;

a + c = 1 - - - (1)

a + 3b - 3c = - 1 - - - (2)

-2a = - 2

a = - 2/-2

a = 1

From (1)

1 + c = 1

c = 1 - 1 = 0

c = 0

From (2) :

1 + 3b - 3(0) = - 1

1 + 3b = - 1

3b = - 2

b = - 2/3

Hence, [tex] P = F^{1}V^{-\frac{2}{3}}D^{0}[/tex]

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Answer 2

The representation of pressure is:

[tex]P=FV^{-\frac{2}{3} }[/tex]

Given that:

Force F, volume V and density D are taken as fundamental quantities, hence pressure P is:

[tex]P=F^aV^bD^c\\\\(ML^{-1}T^{-2})=(MLT^{-2})^a(L^3)^b(ML^{-3})^c\\\\\\(ML^{-1}T^{-2})=(M)^{a+c}(L)^{a+3b-3c}(T)^{-2a}[/tex]

Hence:-

2 = -2a

a = 1

a + c = 1

1 + c = 1

c = 0

a + 3b - 3c = -1

1 + 3b - 3(0) = -1

3b = -2b = -2/3

Hence the representation of pressure is:

[tex]P=FV^{\frac{-2}{3} }D^{0}\\\\P=FV^{\frac{-2}{3} }[/tex]

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Answer:

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Answers

Answer:

625                                      GIVE ME BRAINLIEST ANSWER PLEASE

Explanation:

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So By Pascal's Law

=

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Answer:

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Answers

Answer:

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Explanation:

Answer:

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Answers

The amount of potential energy the block contains is 2,822.4 Joules

Given the following data:

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To determine the amount of potential energy the block contains:

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[tex]P.E = 12 \times 9.8 \times 24[/tex]

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An object weighs 15 N in air and 13 N when submerged in mineral spirits, which has a density of 788 kg/m3. Determine the density of the object

Answers

The density of the object is 5911.94 kg/m³

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The buoyancy = weight of the object - weight in water

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The buoyancy force can also be determined by using the expressed:

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[tex]\mathbf{2 = Volume (V) \times788 \ kg/m^3 \times9.8 }[/tex]

[tex]\mathbf{ Volume (V) = \dfrac{2}{ 788 \ kg/m^3 \times9.8 }}[/tex]

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Recall that:

The mass of an object can be estimated by using the formula:

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mass = 1.5306 kg

The density of the object can now be calculated using the relation

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Density = 1.5306 kg / 2.589 × 10⁻⁴m³

Density = 5911.94 kg/m³

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Answer:

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Carbon -14 is a dating method that is applicable to only samples of organic origin which are less than 50,000 years old.

When living things contain carbon- 14. Carbon - 14 is a radioactive isotope of carbon that decays by beta emission. As long as a plant or animal is alive, there is a balance between its intake and output of carbon -14.

However, when the plant or animal dies, this carbon - 14 begins to decay. The half life of carbon - 14 is 5700 years and it can be used to measure the age of materials or organic origin that are less than 50,000 years old.

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The main goal of every defense is to __________. A. stop the ball B. regain possession of the ball C. protect the goal or basket D. all of the above

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Answer:

D.

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Answer:

d

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