If f(x) = 2x - 5, then f(4) is
017
03
04
05

Answer:

the answer is B five

Step-by-step explanation:

three hundred and seven minus three hundred and twelve

Answer:

Hi! I'm not too bad at math so I hope I can help you. Except, I can't seem to find your question so please comment your question(s) to me so that I can help you. Have a great day:)

Answer:

A

Step-by-step explanation:

This will have slope in it, so bear with me.

We will use the equation [tex]\frac{y(2) - y(1)}{x(2) - x(1)}[/tex] (keep in mind (2) means second and (1) means first)

Lets fill it out.

[tex]\frac{-4-(-1)}{-4-3}[/tex]

It should be [tex]\frac{-3}{-7} or \frac{3}{7}[/tex]

So it is A

Step-by-step explanation:

to figure this out you would have to take all the numbers and do the rise over run technique

Answer:

1st option, and 4th option

Step-by-step explanation:

Is it select one, or select all that are correct?

Answer: C. 0.25

Step-by-step explanation:

Large Shape: S (-4, 12)   T (2, -4)    U (6, -8)   V (-12, -8)

Small Shape: S (-1, 3)   T (0.5, -1)    U (1.5, -2)   V (-3, -2)

For the smaller shape the distance between V and U is 4.5

For the larger shape the distance between V and U is 18

So when you divide [tex]\frac{4.5}{18}[/tex] you should get 0.25

S: [tex]\frac{-4}{-1}=4[/tex]     [tex]-4 *0.25=-1[/tex]

T: [tex]\frac{2}{0.5}=4[/tex]     [tex]2*0.25=0.5[/tex]

U: [tex]\frac{6}{1.5}=4[/tex]     [tex]6*0.25=1.5[/tex]

V: [tex]\frac{-12}{-3} =4[/tex]    [tex]-12*0.25=-3[/tex]

I hope this helps

Answer:

the first one is 0.5 inches 1.27 centimeters

the second is 0.25 inches or 0.635 centimeters

Step-by-step explanation:

Answer:

3*30 = 90

Step-by-step explanation:

3*30 = 90

Answer:

I don't see any optional answers, but the denominator must be greater than 12.

Step-by-step explanation:

27,890*(12/X) < 27,890

Therefore (12/X) < 1

and X > 12

Answer:

1.25 kg

Explanation:

============

======

So, 1250 gram = (1250/1000) kg

We know

Now

Mass in kg:-

Option A

Answer:

A , B And D

2/4 divide both numbers by to and you get 1/2

3/6 divide both numbers by 3 and you get 1/2

4/8 divide both numbers by 4 and you get 1/2

Answer:

48 made a purchase

Step-by-step explanation:

8% of 600

= [tex]\frac{8}{100}[/tex] × 600 ( cancel 100 and 600 by 100 )

= 8 × 6

= 48

Answer:

p = 4

Step-by-step explanation:

Given equation:

[tex]x^2+(p-3)y^2-4x+6y-16=0[/tex]

Standard equation of a circle:

[tex](x-a)^2+(y-b)^2=r^2[/tex]

(where [tex](a,b)[/tex] is the centre of the circle, and [tex]r[/tex] is the radius)

If you expand this equation, you will see that the coefficient of [tex]y^2[/tex] is always one.

Therefore, [tex]p-3=1[/tex]

[tex]\implies p=1+3=4[/tex]

Additional information

To rewrite the given equation in the standard form:

[tex]\implies x^2+y^2-4x+6y-16=0[/tex]

[tex]\implies x^2-4x+y^2+6y=16[/tex]

[tex]\implies (x-2)^2-4+(y+3)^2-9=16[/tex]

[tex]\implies (x-2)^2+(y+3)^2=16+4+9[/tex]

[tex]\implies (x-2)^2+(y+3)^2=29[/tex]

So this is a circle with centre (2, -3) and radius √29

Answer:

4 inches

Step-by-step explanation:

A = b x h

A = 36

b = 9

36 = 9 x h

4 = h

height = 4 inches

Answer:

5/7.

Step-by-step explanation:

The rise = 5 and the corresponding run si 7.

Answer:

5/7

Step-by-step explanation:

so we start at the point (0,0). the slope is essentially

Rise/Run

so in this graph we see a point of (7,5)

the rise was 5 along the y axis and the run was 7 along the x axis.

so 5/7 is correct

Answer:

Step-by-step explanation:

x is the opposite side of angle 30°

34 is the adjacent side of 30°

So, find the value of x, we have use tan

[tex]\bf \boxed{ tan \ \theta = \dfrac{opposite \ side}{adjacent \ side}}}[/tex]

[tex]tan \ 30^\circ = \dfrac{x}{24} \\\\\\0.58 = \dfrac{x}{24}\\\\\\0.58*24=x[/tex]

x = 13.92

Answer:

C) 35

Step-by-step explanation:

The answer is C because he sold 80 lemon pies and as the question states ten more than twice the number of apple pies were sold .

Subtract 80 by 10 and divide it by 2

80-10=70÷2 = 35

Answer:

c and d

Step-by-step explanation:

because

- In f(x),evey time you find  X you write(-6x+5) instead

4x²-----------4(-6x+5)²

3x+1------------3(-6x+5) +1

-In g(x),evey time you find  X you write(-4x² +3x+1)  instead          

Answer: £198.27

Step-by-step explanation:

Answer:

well over 3 years and almost over 4 months

The system of equations that describes the situation is given by these two following equations:

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are c and x.

Carlos has 10 more friends than Xavier when they start the competition, hence:

c = 10 + x.

Carlos doubles his amount of friends and Xavier triples his. In the end they have a total of 160 friends, hence:

2c + 3x = 160.

More can be learned about a system of equations at https://brainly.com/question/24342899

Step-by-step explanation:

It is given that, the sum of two positive integers is 31 and the sum of the squares of these numbers is 625 and we are to find the smaller of the numbers.

So, let the two positive integers be x and y.

Therefore,

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x + y = 31 \: \: ........ \: (i) }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + y {}^{2} = 625 \: ...... \: (ii)}}} \\ \\[/tex]

Now, From the first equation we have,

[tex]\\ {\longrightarrow \pmb{\sf {\qquad x + y = 31 }}} \\ \\ [/tex]

[tex] {\longrightarrow \pmb{\sf {\qquad y = 31 - x \: ...... \: (iii)}}} \\ \\ [/tex]

Now, substituting the value of y in equation (ii) we get :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x {}^{2} + (31 - x) {}^{2} = 625}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + (31 {}^{2} - 2.x.31 + x{}^{2} ) = 625}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + (961 - 62x + x{}^{2} ) = 625}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + 961 - 62x + x{}^{2} - 625 = 0}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad 2 x {}^{2} + 336 - 62x = 0}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad 2 x {}^{2} - 62x + 336 = 0}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad 2( x {}^{2} - 31 + 168) = 0}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad \frac{2}{2} ( x {}^{2} - 31 + 168) = \frac{0}{2} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} - 31 + 168 = 0}}} \\ \\[/tex]

Now using the quadratic formula :

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} }}} \\ \\[/tex]

Where,

[tex] \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ - (- 31) \pm \sqrt{ {31}^{2} - 4(1)(168)} }{2(1)} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 \pm \sqrt{ 961 -672} }{2(1)} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 \pm \sqrt{ 289} }{2(1)} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 \pm 17 }{2(1)} }}} \\ \\[/tex]

Now, we have two equations,

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 + 17 }{2} \: ... .....\: (iv)}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 - 17 }{2} ... .....\: (v)}}} \\ \\[/tex]

So, Equation (iv) :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 + 17 }{2} }}} \\ \\ [/tex]

[tex]\\ {\longrightarrow \pmb{\sf {\qquad x = \frac{ 48 }{2} }}} \\ \\ [/tex]

[tex]\\ {\longrightarrow \pmb{\sf {\qquad x = 24 }}} \\ \\ [/tex]

Now, Equation (v) :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 - 17 }{2}}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 14 }{2}}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \: 7}}}\\ \\ [/tex]

Now, we are to find the value of y.

Substituting the value of x (24) in equation (iii) :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad y = 31 - x \:}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad y = 31 - 24 \:}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad y = 7 \:}}} \\ \\ [/tex]

Again, Substituting the value of x (7) in equation (iii) :

[tex]\\ {\longrightarrow \pmb{\sf {\qquad y = 31 - x \:}}} \\ \\ [/tex]

[tex] {\longrightarrow \pmb{\sf {\qquad y = 31 - 7 \:}}} \\ \\ [/tex]

[tex]\\ {\longrightarrow \pmb{\sf {\qquad y = 24 \:}}} \\ \\ [/tex]

Therefore,

[tex] \\ [/tex]

So, The smaller of the numbers is 7 .

The sum of two positive integers is 31. If the sum of the squares of these numbers is 625, find the smaller of the numbers.

This question belongs to quadratic equations so we have to find the answer by making equation and solving it .

According to question , sum of two positive integers is 31 . So ,

According to question , sum of square

of these numbers is 625 . So ,

From equation 1 ( x + y = 31 ) , Value

of x :

Now , putting value of x in eq. 2 :

Solving it by using middle term

splitting :

First number ,

Second Number ,

According to question ,

Sum of numbers is equal to 31 :

Sum of squares of these numbers is equal to 625 :

Answer:

60 inches

Step-by-step explanation:

Add 59+61 =120 which you divide by 2 for the mean of 60.

Answer:

The second option

Step-by-step explanation:

Hello!

The domain of a graph is the interval in which the graph is on the x values.

This graph has all the x values that are greater than or equal to -3, as the graph is to the right of it.

The answer would be the second option: [tex]D : x/x \geq -3[/tex]

The range is the y-values of the graph. The y value of this graph is above 0, so it would be y ≥ 0

Answer:

22 is th area

Step-by-step explanation:

Answer: 21/572

[tex]\frac{5.5}{10 . 22} - \frac{4}{52}[/tex]

The dots stand for multiplication

Answer:

This is hard

Step-by-step explanation:

I'm so sorry I can't do it

Answer:

[tex]\frac{69}{20}[/tex]

Step-by-step explanation:

[tex]\frac{3}{7} -\frac{11}{4} +\frac{16}{5} +\frac{18}{7}[/tex]

= [tex]\frac{3}{7} +\frac{18}{7}-\frac{11}{4} +\frac{16}{5}[/tex]

= [tex]\frac{21}{7} -\frac{11}{4} +\frac{16}{5}[/tex] As both denominators have 7 you can add their numerators

=[tex]\frac{21}{7} -(-\frac{9}{20})[/tex]     L.C.M

=[tex]\frac{21}{7} +\frac{9}{20}[/tex]   L.C.M

=[tex]\frac{69}{20}[/tex]

Answer: y = [tex]\frac{1}{6}[/tex]x + 2

Step-by-step explanation:

    [1] First, we will graph the points given. See the attachment with [1] in the corner.

    [2] Next, we will find the slope.

    (2a) Using rise over run. See the attachment with [2] in the corner.

    (2b) Use the slope equation:

[tex]\displaystyle \frac{1-3}{-6-6}= \frac{-2}{-12} =\frac{1}{6}[/tex]

    [3] Find the y-intercept. Look to the graph. See the attachment with [3] in the corner.

         This gives us a final answer of y = [tex]\frac{1}{6}[/tex]x + 2