If g(x) is the inverse of f(x) and f(x)=4x+12, what is g(x)?​

Answer:

To calculate the moles we must first find the molar mass M

M (Na2S2O8) = (23*2) + (32*2) + (16*8)

= 46 + 64 + 168

= 278g/mol

Molar mass = mass/moles

moles =mass / molar mass

= 25.2/278

= 0.0906mol

Hope this helps.

Answer:

You would be able to see the ants clearly with the unique body parts.

Explanation:

Convex lens is also known as Converging lens. It helps in converging rays of light to become a principal focus which is usually very clear and visible to the eyes. The converging lens when used to view the ant makes the ant appear very visible and the individual is able to see all the unique body parts of the ant. This type of lens is used in individuals who are longsighted.

The voltage of an electrolytic cell with copper and magnesium electrodes is 2.71 v. Therefore, option B is correct.

The electrolytic cell is a type of cell that performs a redox reaction while using electrical energy. When electrical energy is applied, a redox reaction occurs in molten NaCl. It is therefore an electrolytic cell.

An electrolyte, two electrodes, and an electrolytic cell make up an electrolytic cell (a cathode and an anode). The electrolyte is typically a mixture of ions that have been dissolved in water or another solvent. Electrolytes can also be molten salts, like sodium chloride.

The standard reduction potential, E° of the metals are as below:

Mg²⁺ + 2e⁻ ⇌  Mg; E° = -2.372

Cu²⁺ + 2e⁻ ⇌  Cu; E° = +0.337

Therefore, magnesium has the the lower E°, it will serve as the anode in the electrolytic cell while copper will serve as the cathode.

At the anode; Mg ⇌  Mg²⁺ + 2e⁻, E° = -2.372

At the cathode; Cu²⁺ + 2e⁻ ⇌  Cu, E° = +0.337

EMF of the cell = E° cathode - E° anode

= 0.337 - (-2.372) = 2.71 V

Therefore, EMF of the cell is 2.71 V

Thus, option B is correct.

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Answer:

Final temperature of the solution = 26.43°C

Explanation:

Concentration of HCl = 0.662 M, Volume = 200 mL= 0.200 L

Concentration of Ba(OH)₂ = 0.331 M, Volume = 200 mL = 0.200 L

Initial temperature of solution = 22.00°C

Specific Heat capacity of water = 4.184 J/g°C

Heat of neutralization = -56.3 KJ/mol of H₂O produced.

The full calculations is found in the attachment below

Answer:

Can A will make a louder and stronger fizz than can B.

Explanation:

Temperature has a direct effect on gas solubility. We know that carbonated water contains carbon dioxide dissolved in water. The extent of dissolution or solubility of this gas is dependent on the temperature of the system.

As the temperature of the system rises, the solubility of gas in solution decreases. It follows that can A, having been stored in a garage is definitely at a higher temperature than can B stored in the refrigerator.

Since solubility of gases decreases with increasing temperature, the carbon dioxide in can A will be less soluble than in can B. This will cause can A to make a louder and stronger fizz when opened than can B.

Answer:

Option D

Explanation:

A mechanical wave is a wave of energy that can travel long distances and could go through characteristics of matter such as solids, liquids, and gases. Mechanical waves can also travel through vacuums. A good example of a mechanical wave would be sound, sound is a wave spread through a object and can go through different types of matter. Which is why your answer is option D "sunshine." Light cannot go through a vacuum while sounds, and water can.

Hope this helps.

The mechanical wave example does not include the sunshine

It is the wave of energy that can travel long distances and considered the characteristics of matter like solids, liquids, and gases. It can also travel via vacuums. The Light cannot go via a vacuum while sounds, and water can go.

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Answer:

0.134 moles of H₂ can be formed if a 3.25g sample of Mg reacts with excess HCl

Explanation:

The balanced reaction is:

Mg + 2 HCl → MgCl₂ + H₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles react:

Being:

the molar mass of the compounds participating in the reaction is:

Then, by stoichiometry of the reaction, the following quantities of mass participate in the reaction:

Then you can apply the following rule of three: if by stoichiometry 24.31 grams of Mg form 1 mole of H₂, 3.25 grams of Mg how many moles of H₂ will they form?

[tex]moles of H_{2} =\frac{3.25 grams of Mg*1 mole of H_{2} }{24.31 grams of Mg}[/tex]

moles of H₂= 0.134

0.134 moles of H₂ can be formed if a 3.25g sample of Mg reacts with excess HCl

0.134 moles of H₂ are formed by the reaction of 3.25 g of Mg with excess HCl.

Let's consider the balanced equation between Mg and HCl.

Mg + 2 HCl ⇒ MgCl₂ + H₂

The molar mass of Mg is 24.3 g/mol. The moles corresponding to 3.25 g of Mg are:

[tex]3.25 g \times \frac{1mol}{24.3g} = 0.134 mol[/tex]

The molar ratio of Mg to H₂ is 1:1. The moles of H₂ formed by 0.134 moles of Mg are:

[tex]0.134 mol Mg \times \frac{1molH_2}{1molMg} = 0.134molH_2[/tex]

0.134 moles of H₂ are formed by the reaction of 3.25 g of Mg with excess HCl.

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Answer:

Explanation:

ratio of  moles of N and O in molecule =

N / O = 2.17 / 4.35

1/2

empirical formula = NO₂

Answer:

The percentage of the void space out of the total volume occupied is 93.11%

Explanation:

A mole of water contains 2 atoms of hydrogen and 1 atom of oxygen.

To calculate the volume of a mole of water, we calculate 2 times the volume of the hydrogen atom and 1 times the volume of the oxygen atom

Let's calculate this one after the other.

For the hydrogen, formula for the volume will be

[tex]V_{hydrogen[/tex] = 2 × 4/3 × π × [tex]r_{H}^{3}[/tex]

where [tex]r_{H}^{3}[/tex] = 37 pm which is read as 37 picometer (1 picometer = 10^-12 m) = 37 × [tex]10^{-12}[/tex] meters

Volume of the hydrogen = 8/3 × (37 × 10^-12)^3 = 4.05 * 10^-31

we multiply this by the avogadro's number = 6.02 * 10^23

= 4.05 * 10^-31 * 6.02 * 10^23 = 2.6 * 10^-8 m^3

We do same for thr oxygen, but this time we do not multiply the volume of the oxygen by 2 as we have only one atom of oxygen

Volume of oxygen = 4/3 * π * (73 * 10^-12) ^3 * avogadro's number = 9.81 * 10^-7 m^3

adding both volumes together, we have 1.24 * 10^-6 m^3 or simply 1.24 ml ( 0.01 m = 1 ml)

Dividing the molar mass of one mole of water by its density, we can get the volume of 1 mole of water

= (18g/mol)/(1 g/ml) = 18 ml/mol

Now we proceed to calculate the volume of void = Total volume - volume of molecule = 18 - 1.24 = 16.76 ml

Now, the percentage of void = volume of void/total volume * 100%

= 16.76/18 * 100% = 93.11%

Answer:

sodium chloride can be used as salt

extraction sodium metal by electrolysis

a common chemical in laboratory experiments

Answer:

sodium chloride can be used as preservatives,

in preserving foods.

Answer:

D. Nitrogen has 5 valence electrons.

Explanation:

Nitrogen is an element in group 5A of the periodic table. Elements in group 5A all contain just 5 valence electrons. (Electrons in the outer shell).

**Elements are organized into these groups in a periodic table based on the number of valence electrons which determines their charge. (Does not apply to transition metals)

Answer:

The fugacity coefficient is  [tex][\frac{f}{p} ] = 1.45[/tex]

Explanation:

From the question we are told that

  The gas obeys the equation [tex]p(v-b) = RT[/tex]

   The value  of b is  [tex]b = b = 0.0391 \ L /mol[/tex]

   The pressure is  [tex]p = 1000 \ atm[/tex]

    The temperature is [tex]T= 1000^oC = 1273 K[/tex]

generally

        [tex]RT ln[\frac{f}{p} ] = \int\limits^{p}_{o} [ {v_{r} -v_{i}} ]\, dp[/tex]

Where  [tex]\frac{f}{p}[/tex] is the fugacity coefficient

          [tex]v_r[/tex] is the real volume which is mathematically evaluated from above equation  as

           [tex]v_r = \frac{RT}{p} + b[/tex]

           [tex]v_r = \frac{RT}{p} + 0.0391[/tex]

and     [tex]v_{i}[/tex] is the ideal volume which is evaluated from the ideal gas equation (pv = nRT , at  n= 1) as

         [tex]v_{i} = \frac{RT}{p}[/tex]

So

     [tex]RT ln[\frac{f}{p} ] = \int\limits^{1000}_{o} [[ \frac{RT}{p} + 0.0391] - [\frac{RT}{p} ]} ]\, dp[/tex]

=>      [tex]RT ln[\frac{f}{p} ] = \int\limits^{1000}_{o} [0.391 ]\, dp[/tex]

=>    [tex]RT ln[\frac{f}{p} ] = [0.391p]\left | 1000} \atop {0}} \right.[/tex]

=>   [tex]RT ln[\frac{f}{p} ] = 38.1[/tex]

   So

         [tex]ln[\frac{f}{p} ] = \frac{39.1}{RT}[/tex]

Where R is the gas constant with value [tex]R = 0.082057\ L \cdot atm \cdot mol^{-1}\cdot K^{-1}[/tex]

         [tex][\frac{f}{p} ] = \frac{39.1}{ 2.303 *0.082057 * 1273}[/tex]

        [tex][\frac{f}{p} ] = 1.45[/tex]

Answer:

[tex]\Delta H=1962.3J[/tex]

Explanation:

Hello,

In this case, we can compute the change in the solution enthalpy by using the following formula:

[tex]\Delta H=mC\Delta T[/tex]

Whereas the mass of the solution is 350 g, the specific heat capacity is 4.184 J/g °C and the change in the temperature is 1.34 °C, therefore, we obtain:

[tex]\Delta H=350g*4.184\frac{J}{g\°C} *1.34\°C\\\\\Delta H=1962.3J[/tex]

It is important to notice that the mass is just 350 g that is the reacting amount and by means of the law of the conservation of mass, the total mass will remain constant, for that reason we compute the change in the enthalpy as shown above, which is positive due to the temperature raise.

Best regards.

Answer:

1. In order to reach equilibrium COCl₂(g) must be consumed.

B. False

2. In order to reach equilibrium Kc must increase.

B. False .

3. In order to reach equilibrium CO must be consumed.

A. True.

4. Qc is greater than Kc.

A. True

5. The reaction is at equilibrium. No further reaction will occur.

B. False.

Explanation:

Based on the reaction:

COCl₂(g) → CO (g) + Cl₂(g)

And Kc is defined as:

Kc = 1.29x10⁻² = [CO] [Cl₂] / [COCl₂]

Molar concentrations of each species are:

[COCl₂] = 0.104 moles of COCl₂ / 1L = 0.104M

[CO] = 4.66×10⁻² moles of CO / 1L = 4.66×10⁻²M

[Cl₂] = 3.76×10⁻² moles of Cl₂ / 1L = 3.76×10⁻²M

Replacing in Kc formula:

4.66×10⁻²M × 3.76×10⁻²M / 0.104M = 1.68x10⁻²

As the concentrations are not in equilibrium, 1.68x10⁻² is defined as the reaction quotient, Qc.

As Qc > Kc, the reaction will shift to the left producing more COCl₂ and consuming CO and Cl₂. Thus

1. In order to reach equilibrium COCl₂(g) must be consumed.

B. False

2. In order to reach equilibrium Kc must increase.

B. False . Kc is a constant that never change.

3. In order to reach equilibrium CO must be consumed.

A. True.

4. Qc is greater than Kc.

A. True

5. The reaction is at equilibrium. No further reaction will occur.

B. False. The reaction is in equilibrium when Qc = Kc

Answer:

Q = 12.38

Explanation:

The Nernst equation is given as; Ecell = E°cell - (2.303RT/nF) log Q  ;where Q is the reaction quotient.

The reaction quotient, Q  in a reaction, is the product of the concentrations of the products divided by the product of the concentrations of the reactants.

In an electrochemical cell, Q is the ratio of the concentration of the electrolyte at the anode to that of the electrolyte at the cathode.

Q = [anode]/[cathode]

therefore , Q = 0.052/0.0042 = 12.38

Answer:

Explanation:

NH3 + H3O+ --> NH4+ + H2O

equllibrium constant =K = [ H2O] [NH4+] / [NH3] [H3O+ ]

                                      =

by inserting thier respecive values can you calcaulte, by the way coniseder  [ H2O] =1 ,

Answer:

C₅H₅N being the weakest base

Explanation:

A weak base (B) is defined as a chemical compound that, in reaction with water, produce a small quantity of BH⁺

The general reaction is:

B + H₂O ⇄ BH⁺ + OH⁻ Where Kb is defined as:

Kb = [BH⁺] [OH⁻] / [B]

That means the smallest Kb is the weakest base because is producing the smallest quantity of BH⁺.

In the problem, the smallest Kb is C₅H₅N being the weakest base.

Answer:

4.07x10⁻³M AlCl₃.

Explanation:

Based on the reaction:

AlCl₃(aq) + 3 AgNO₃(aq) → 3 AgCl(s) + Al(NO₃)₃(aq)

That means 1 mole of AlCl₃ reacts with 3 moles of AgNO₃ to produce 3 moles of AgCl.

As 0.325g of AgCl are produced. Moles of AgCl are (Molar mass AgCl: 143.32g/mol):

0.325g AgCl ₓ ( 1 mol / 143.32g) = 2.27x10⁻³ moles of AgCl

As 3 moles of AgCl are produced from 1 mole of AlCl₃, moles of AlCl₃ that produce 2.27x10⁻³ moles of AgCl are:

2.27x10⁻³ moles of AgCl ₓ (1 mole AlCl₃ / 3 moles AgCl) =

7.56x10⁻⁴ moles AlCl₃

As volume of the AlCl₃ solution that reacts is 185.5mL = 0.1855L, molar concentration of the solution is:

7.56x10⁻⁴ moles AlCl₃ / 0.1855L =

Answer: 1. [tex]H^++OH^-\rightarrow H_2O[/tex]  Lewis acid : [tex]H^+[/tex], Lewis base : [tex]OH^-[/tex]

2. [tex]Cl^-+BCl_3\rightarrow BCl_4^-[/tex] Lewis acid : [tex]BCl_3[/tex], Lewis base : [tex]Cl^-[/tex]

3. [tex]K^++6H_2O\rightarrow K(H_2O)_6[/tex] Lewis acid : [tex]K^+[/tex], Lewis base : [tex]H_2O[/tex]

Explanation:

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

1. [tex]H^++OH^-\rightarrow H_2O[/tex]

As [tex]H^+[/tex] gained electrons to complete its octet. Thus it acts as lewis acid.[tex]OH^-[/tex] acts as lewis base as it donates lone pair of electrons to electron deficient specie [tex]H^+[/tex].

2. [tex]Cl^-+BCl_3\rightarrow BCl_4^-[/tex]

As [tex]BCl_3[/tex] is short of two electrons to complete its octet. Thus it acts as lewis acid. [tex]Cl^-[/tex] acts as lewis base as it donates lone pair of electrons to electron deficient specie [tex]BCl_3[/tex].

3. [tex]K^++6H_2O\rightarrow K(H_2O)_6[/tex]

As [tex]K^+[/tex] is short of electrons to complete its octet. Thus it acts as lewis acid. [tex]H_2O[/tex] acts as lewis base as it donates lone pair of electrons to electron deficient specie [tex]K^+[/tex].

Answer: 7.45 g of [tex]Pb(NO_3)_2[/tex] excess reagent are left over after the reaction is complete.

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

a) [tex]{\text{Number of moles of} KI}=\frac{7.55g}{166g/mol}=0.045moles[/tex]

b) [tex]{\text{Number of moles of} Pb(NO_3)_2}=\frac{9.06g}{331.2g/mol}=0.027moles[/tex]

The balanced chemical reaction is :

[tex]Pb(NO_3)_2(s)+2KI(s)\rightarrow 2KNO_3(s)+PbI(s)[/tex]

According to stoichiometry :

2 moles of [tex]KI[/tex] require = 1 mole of [tex]Pb(NO_3)_2[/tex]

Thus 0.045 moles of [tex]KI[/tex] will require=[tex]\frac{1}{2}\times 0.045=0.0225moles[/tex]  of [tex]Pb(NO_3)_2[/tex]

Thus [tex]KI[/tex] is the limiting reagent as it limits the formation of product and [tex]Pb(NO_3)_2[/tex] is the excess reagent as (0.045-0.0225) = 0.0225 moles are left

Mass of [tex]Pb(NO_3)_2=moles\times {\text {Molar mass}}=0.0225moles\times 331.2g/mol=7.45g[/tex]

Thus 7.45 g of [tex]Pb(NO_3)_2[/tex] of excess reagent are left over after the reaction is complete.

Answer: An element with the same number of protons, but a different number of neutrons

Explanation:

The # of protons in an atom is what determines what atom it is (hydrogen has 1 proton, helium has 2 protons, etc ...). You cannot change the number of protons in an atom without changing what element the atom is.

The number of electrons in atoms varies greatly because electrons are constantly gained, lost, and shared during chemical reactions.

An isotope is a variation of the same element (so they must have the same # of protons) that have different masses (and therefore a different number of neutrons).

The answer is the fourth choice, "An element with the same number of protons, but a different number of neutrons"

The isotopes refer to an element that consists of a similar number of protons but have a distinct no of neutrons.

It is considered to be the members of the family with respect to the elements that consist of a similar number of protons but have a distinct no of neutrons. The no of protons in the nucleus measured the atomic number of elements based on the periodic table.

Therefore, the fourth option is correct.

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Answer:

Sol is a colloidal suspension with solid particles in a liquid. Foam is formed when many gas particles are trapped in a liquid or solid. Aerosol contains small particles of liquid or solid dispersed in a gas. While solid solution contain solid as solute in either solid, liquid or gas.

Answer:

NH4NO3 = N2O + 2(H2O)

Explanation:

there are 2 N, 4 H, 3 O

Answer:

NH4NO3=N2O+2H2O

Explanation:

N-2,O-3,H-4

Answer:

0.032moles

Explanation:

2.10moles in 1000ml what about 15.25ml

(15.25×2.10)÷1000

0.032moles

Answer:

a technique in which cells are purposefully grown under specific conditions

Explanation:

Answer:

its c

Explanation:

correct edge2020

Answer:

The correct IUPAC name for the organic reactant is :

d) 3-methylbutene

Explanation:

Firstly the  missing diagram is attached in the diagram below.

The objective of this question is to draw the major organic product and select the correct IUPAC name for the organic reactant. If there is more than one major product, both may be drawn.

From the image attached below; we would see the reaction that occurs between the alkene and the HBr (hydrobromic acid). What really occur in the reaction is that; in the presence of HBr with an alkene compound a secondary 2° carbocation is usually formed. This secondary 2° carbocation formed is usually unstable, so what we called an hydride shift occurs (Markovnikov's product) here to form a stable tertiary 3° carbocation.

The correct IUPAC name for the organic reactant is : 3-methylbutene

Answer: HA has lowest pH and it is the most acidic as compared to the rest of given acids.

Explanation:

We know that relation between [tex]pK_a[/tex] and [tex]K_a[/tex] is as follows.

       [tex]pK_a = -log K_a[/tex]

This means that more is the value of [tex]K_a[/tex], smaller will be the [tex]pK_a[/tex]. Also, more is the value of [tex]K_a[/tex] smaller will be the pH of a solution.

As, larger is the value of [tex]K_a[/tex] more negative will be the [tex]pK_a[/tex] value. Hence, stronger will be the acid.

In the given options, HA has the smallest [tex]pK_a[/tex] value.

Therefore, we can conclude that HA has lowest pH and it is the most acidic as compared to the rest of given acids.

Answer:

We can produce 6.20 grams of CO2

Explanation:

Step 1: Data given

Mass of hexane = 4.3 grams

Molar mass of hexane = 86.18 g/mol

Mass of oxygen = 7.14 grams

Molar mass of oxygen = 32.0 g/mol

Step 2: The balanced equation

2C6H14 + 19O2 → 12CO2 + 14H2O

Step 3: Calculate moles

Moles = mass / molar mass

Moles hexane = 4.3 grams / 86.18 g/mol

Moles hexane = 0.0499 moles

Moles oxygen = 7.14 grams / 32.0 g/mol

Moles oxygen = 0.2231 moles

Step 4: Calculate the limiting reactant

For 2 moles hexane we need 19 moles O2 to produce 12 moles CO2 and 14 moles H2O

Oxygen is the limiting reactant. It will completely be consumed ( 0.2231 moles). Hexane is in excess. There will react 2/19 * 0.2231 = 0.02348 moles

There will be porduced 12/19 * 0.2231 = 0.1409 moles CO2

Step 5: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 0.1409 moles * 44.01 g/mol

Mass CO2 = 6.20 grams

We can produce 6.20 grams of CO2