If h(x) = 5 + x and (x) =
XE
which expression is equivalent to (kh)(x)?

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex] \tt{sin(\Theta) = \cfrac{3}{8}} [/tex]

[tex]\qquad \tt \rightarrow \: x = 6\:\: cm[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: \sin( Theta) = \cfrac{Opposite \:\: side}{Hypotenuse}[/tex]

[tex]\qquad \tt \rightarrow \: \sin( \Theta) = \cfrac{3}{8} [/tex]

since the Triangles are similar, ratio of their corresponding sides are equal :

[tex]\qquad \tt \rightarrow \: \sin( \Theta) = \cfrac{3}{8} = \dfrac{x}{16} [/tex]

[tex]\qquad \tt \rightarrow \:x = 16 \sdot \cfrac{3}{8}[/tex]

[tex]\qquad \tt \rightarrow \: x = 2 \sdot3[/tex]

[tex]\qquad \tt \rightarrow \: x = 6 \: \: cm[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Since  the two right-angled triangles have the same angles, the values are; ai. sin θ= 3/8ii. sin θ= x/16b. x = 6cm

Using the sine trigonometric identity expressed as;

sin θ = opposite/hypotenuse

Then, we have that for the first triangle;

sin θ= 3/8

For the bigger triangle;

sin θ= x/16b.

Then, since we have that the sine identity is;

sin θ= x/16

But sin θ= 3/8

Divide the values and find the sine inverse in

θ= 0. 375θ = 22. 0 degrees

x = 0. 375 (16)

Multiply

x = 6 cm

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The equation that represents the relationship between the radius, r, and arc length, s is s = Θ * r

See attachment for the complete question

From the complete question, we have:

The angle is given in radians.

So, the arc length is calculated using

Arc length = Angle * Radius

Substitute known values

s = Θ * r

Hence, the equation that represents the relationship between the radius, r, and arc length, s is s = Θ * r

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Answer:

A

Step-by-step explanation:

On Edge

Hey there!

[tex] \sf{ \purple{ \boxed{\bold{m = - \dfrac{7}{3} }}}} [/tex]

[tex] \\ [/tex]

We are given the points [tex] \sf{P_1(\overbrace{ \blue{8}}^{\blue{x_1}} ,\underbrace{\orange{-8}}_{ \orange{y_1}}) \: and \: P_2(\overbrace{ \green{5}}^{\green{x_2}} ,\underbrace{\red{-1}}_{\red{y_2} })} [/tex] . To find the slope [tex] \sf{\purple{m}} [/tex] of such a line, we use the slope formula which is the following:

[tex] \sf{ \purple{m} }= \dfrac{\Delta y}{\Delta x} = \dfrac{ \red{y_2} - \orange{y_1}}{ \green{x_2 }- \blue{x_1}} [/tex]

[tex] \\ [/tex]

⇢Now, by plugging in our values, we get :

[tex] \sf{ \purple{m}} = \dfrac{ \red{ - 1} - \orange{( - 8)}}{ \green{5} \: - \: \blue{8}} = \dfrac{ \: \: 7 \: }{ - 3 \: } \\ \\ \implies \sf{ \purple{ \boxed{m = - \dfrac{7}{3} }}}[/tex]

Therefore, the slope of the line is [tex] \sf{ \purple{ \boxed{m = - \dfrac{7}{3} }}} [/tex]

[tex]\Large\maltese\underline{\textsf{A. What is Asked}}[/tex]

What is the slope of a linear function that goes through (8,-8) and (5,-1)?

[tex]\Large\maltese\underline{\textsf{B. This problem has been solved!}}[/tex]

Formula utilised, here [tex]\bf{\dfrac{y2-y1}{x2-x1}}[/tex].

We utilise that formula because we have two points as our given information.

So, we

put in the values

[tex]\bf{\dfrac{-1-(-8)}{5-8}}[/tex] | subtract on top and bottom

[tex]\bf{\dfrac{-1+8}{-3}}[/tex] | simplify

[tex]\bf{\dfrac{7}{-3}[/tex]

[tex]\cline{1-2}[/tex]

[tex]\bf{Result:}[/tex]

                [tex]\bf{=Slope=-\dfrac{7}{3}}[/tex]

[tex]\LARGE\boxed{\bf{aesthetic\not1\theta l}}[/tex]

Answer:

Prob Online

Step-by-step explanation:

Can't really think of one

2. 3 is not a function

3. 4 is a function

To be a function it has to pass the vertical line test, meaning the x value can not repeat. So for this problem, you need to look at the ordered pair (x,y). For problem 2, answer 3 is not a function because the x value of 1 appears twice. For problem 3, answer 4 is a function because there aren't any x values being repeated.

(A) n=w by the corresponding angles theorem.

(B) This is the correct answer. n=s by the vertical angles theorem and s and x are supplementary by the same-side interior angles theorem. Thus, n and x are supplementary, and are not always equal.

(C) n=z by the alternate exterior angles theorem.

(D) s=w, so (s+w)/2 = (s+s)/2 = s. Since n=s by the vertical angles theorem, n=s.

(E) n and w are equal by the corresponding angles theorem, and w and y are supplementary as they form a linear pair. Thus, n+y=180, and it follows n=180-y.

The x-intercepts and the y-intercepts of the function is that determines the graph is:

The function of an absolute equation can be graphed by determining the values of x-intercepts and the y-intercepts of the function.

From the given equation:

y = 2|x+3| - 4

To determine the y-intercepts, we need to set the values of x to zero, and vice versa for x-intercepts.

By doing so, the x-intercepts and the y-intercepts of the function is:

Therefore, since we know the x and y-intercepts, the graph of the absolute value can be seen as plotted below.

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answer for b

catch the 9:10 bus from Beasley.

answer for c

10:06

hope this might help u.

Answer:

Answer for B is 9:10 for Beasley and The answer for C is 10:06

Step-by-step explanation:

Answer:34

Step-by-step explanation:

Giving away all that is not new or fav so 12 fav + 18 new + 4 which are new an favorite = 34

Answer:

22

Step-by-step explanation:

63 is the total

14 are new

8 are fav

14+8=22

Answer:

0

y = 2

Step-by-step explanation:

Since it's a flat line, the slope is 0.

Since all of the points have a y-value of 2, the equation is y = 2.

Answer:

Slope = 0

Equation: y = 2

Step-by-step explanation:

PQ is parallel  to x-axis. Slope of the line parallel to x-axis = 0.

Slope of diagonal PQ = 0

Equation of line parallel to x-axis : y = a

Equation of diagonal PQ: y = 2  or y -2 = 0

The coordinates of point N are (3, 5).2 the answer is 2/1 but just write 2.

We have given that,

Polygon MNOPQ is dilated by a scale factor of 0.8 with the origin as the center of dilation, resulting in the image M′N′O′P′Q′.

A coordinate system is a system that uses one or more numbers, or coordinates, to uniquely determine the position of the points or other geometric elements on a manifold such as Euclidean space.

The coordinates of point M are (2, 4), and the coordinates of point N are (3, 5)

Therefore we get,

2 the answer is 2/1 but just write 2.

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Answer:

B

Step-by-step explanation:

the volume (V) of a sphere is calculated as

V = [tex]\frac{4}{3}[/tex] πr³ ( r is the radius )

here r = 13 , then

V = [tex]\frac{4}{3}[/tex] π × 13³ = [tex]\frac{4}{3}[/tex] π × 2197 = [tex]\frac{4(2197)}{3}[/tex] π = [tex]\frac{8788}{3}[/tex] π units³

The solution is, B.  8788/3 * π units³ is the volume of the sphere shown below.

In mathematics, volume is the space taken by an object. Volume is a measure of three-dimensional space. It is often quantified numerically using SI derived units or by various imperial or US customary units. The definition of length is interrelated with volume.

here, we have,

the volume (V) of a sphere is calculated as

V = 4/3 πr³ ( r is the radius )

now, we have,

from the given figure, we get,

here r = 13 , then

V =  4/3* π × 13³

= 4/3* π × 2197

= 8788/3 * π units³

Hence, The solution is, B.  8788/3 * π units³ is the volume of the sphere shown below.

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Answer:

y = 7/25x

Step-by-step explanation:

For a proportional relationship, we have

y ∞ x.

Let k = constant of proportionality = 7/25

Removing the proportionality sign, we have

y = k x

Therefore, the answer is  

y = 7/25x

Instead of y= x + 7/25

So, the error is that x should be multiplied by 7/25 and not added.

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Answer: 2:3

Step-by-step explanation:

common factor of 42 and 63: 21

42/21= 2

63/21= 3

find the common factor to find the ratio!

therefore the ratio is 2:3

Step-by-step explanation:

eq of a circle is

(x-h)^2+(y-k)^2=r^2

h is 0

k=3

r is 1.5 this is radius of the circle

x^2+(y-3)^2=1.5^2

Answers for different section are given below;

The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input x.

Here, given function;

   f(x) = -x² - 4x + 6

1.    If we take -1 common from the given function, we get

                      f(x) = -1 (x² + 4x - 6)

                      f(x) = -1 (x² + 4x) + 6

      Thus, first block contains -1 and second block contains 4.

2.   Then we add half of the coefficient of x², (b/2)², inside the bracket and subtract it outside a times, a(b/2)².

                 f(x) = -1 ( x² + 2. 2x + 2²) +2² + 6

                 f(x) = -1 ( x² + 4x + 2²) +4 + 6

Thus, first block contains -1, second block contains 4, third block contains 4, and fourth block contains 4.

3. Then we factorize the bracket and simplify outside the bracket;

                 f(x) = -1 (x + 2)² + 10

Thus, first block contains -1, second block contains 2 and third block contains 10.

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Answer:

3y⁷ + 2y⁵ - 4y³ + y + 12

Step-by-step explanation:

2y⁵ + y + 3y⁷ - 4y³ + 12

(greatest - least powers)

I hope this helps!

The value of K will be equal to 4 for an expression (5a²b³)(6a[tex].^k[/tex]b)=30a⁶b⁴.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division

We have an expression given as:-

(5a²b³)(6a[tex].^k[/tex]b)=30a⁶b⁴.

The mathematical properties we knew

[tex]x^mx^n = x^{m+n}[/tex]

[tex]x^m[/tex]÷[tex]x^n=x^{m-n}[/tex]

So the expressions will be written as:-

(5. 6 . a². a[tex].^k[/tex] .b³ .b =  30a⁶b⁴.

30 ( [tex]a^{2+k}[/tex])([tex]b^{3+1}[/tex]) =  30a⁶b⁴.

Comparing the terms we will get:-

[tex]a^{2+k}[/tex] = a⁶

2 + k = 6

k = 6 - 4

k = 4

Therefore the value of K will be equal to 4 for an expression (5a²b³)(6a[tex].^k[/tex]b)=30a⁶b⁴.

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The equation of the hyperbola with a given origin has vertices at (±[tex]\sqrt{61}[/tex], 0) and foci at  (±[tex]\sqrt{98}[/tex], 0) is  [tex]\frac{x^2}{61} -\frac{y^2}{37} =1[/tex].

Given, that a hyperbola centred at the origin has vertices at (±[tex]\sqrt{61}[/tex], 0) and foci at  (±[tex]\sqrt{98}[/tex], 0)

In mathematics, a hyperbola is a type of smooth curve lying in a plane, defined by its geometric properties or by equations for which it is the solution set. A hyperbola has two pieces, called connected components or branches, that are mirror images of each other and resemble two infinite bows.

The formula for a hyperbola centred at the origin is [tex]\frac{x^2}{a^2} -\frac{y^2}{b^2 } =1[/tex]

The vertices are located at (±a, 0), so we have that the value of a is [tex]\sqrt{61}[/tex].

The foci are located at (±c, 0), where [tex]c^2 = a^2 + b^2[/tex].

So if we have that [tex]c = \sqrt{98}[/tex], we can find the value of b:

[tex]98 = 61 + b^2[/tex]

⇒ [tex]b^2 = 37[/tex]

⇒ [tex]b = \sqrt{37}[/tex]

So, the formula for this hyperbola is [tex]\frac{x^2}{61} -\frac{y^2}{37} =1[/tex].

Therefore, the equation of the hyperbola with a given origin has vertices at (±[tex]\sqrt{61}[/tex], 0) and foci at  (±[tex]\sqrt{98}[/tex], 0) is  [tex]\frac{x^2}{61} -\frac{y^2}{37} =1[/tex].

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Answer:

The exponent is 2, so the degree is 2

Answer:

(-5,0)

Step-by-step explanation:

The x intercept is where it crosses the x axis

It crosses the x axis where x = -5

The y value is 0

(-5,0)

Answer:

A  

Step-by-step explanation:

The x -intercept is 'shorthand' for  x - AXIS intercept

  where the graph crosses the x - axis

      this will always have a   ZERO  value for the 'y'- coordinate

looking at the graph this point is   -5,0

An expression is defined as a set of numbers, variables, and mathematical operations. There are a total of 10 benches in the class.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

Let the total number of benches be represented by x. If students sit 3 per bench, we are short 3 benches. Therefore, the total number of students can be written as,

Total number of students = 3x + 9

If they sit 5 per bench, 2 benches are left empty, and one bench only has 4 students.

Total number of students = 5(x-1) - 10 +4

Now, the total number of students can be written as,

3x + 9 = 5(x-1) - 10 +4

3x + 9 = 5x - 11

20 = 2x

x = 10

Hence, there are a total of 10 benches in the class.

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Answer:

distance = 9.4 units

Step-by-step explanation:

* using the distance formula *

d =

[tex] \sqrt{(x2 - x1 )^{2} + (y2 - y1)^{2} } [/tex]

[tex] \sqrt{( - 4 - 4) ^{2} + ( - 2 - 3) ^{2} } [/tex]

= 9.4 units

Answer:

x < 3

Step-by-step explanation:

The last step is to divide by -2. When you divide by a negative number you must reverse (flip) the inequality symbol.

-6 < -2x

-6/-2 > -2x/-2

3 > x

This is the same as

x < 3 (see the pointy side pointing at the x and the wide open side facing the 3)

[tex] \sf{\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Let's solve for y and z ~

[tex]\qquad \sf  \dashrightarrow \: z + 61 = 180[/tex]

[ Co- interior angle pair ]

[tex]\qquad \sf  \dashrightarrow \: z = 180 - 61[/tex]

[tex]\qquad \sf  \dashrightarrow \: z = 119 \degree[/tex]

now,

[tex]\qquad \sf  \dashrightarrow \: 5y + 14 = 119[/tex]

[ by Alternate interior angle pair ]

[tex]\qquad \sf  \dashrightarrow \: 5y = 119 - 14[/tex]

[tex]\qquad \sf  \dashrightarrow \: 5y = 105[/tex]

[tex]\qquad \sf  \dashrightarrow \: y = 21 °[/tex]

The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the inequality:

3 ≤ |x + 2| ≤ 6

Hence:

x + 2 ≤ 6, -(x + 2) ≤ 6, 3 ≤ x + 2 and 3 ≤ -(x + 2)

This gives:

x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

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The measure of angle CED is y. The correct option is the second option-   y, because Triangle ABC is similar to triangle EDC

From the question, we are to determine the measure of angle CED

In the diagram, we can observe that ΔABC is similar to ΔEDC

This is by the Angle-Angle similarity theorem

The theorem states that

If any two angles of a triangle are equal to any two angles of another triangle, then the two triangles are similar to each other

Thus,

Angle CAB = Angle CED

In the diagram,

Angle CAB = y

∴ Angle CED = y

Hence, the measure of angle CED is y. The correct option is the second option-   y, because Triangle ABC is similar to triangle EDC

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The correct answer is option D which is p ³+ 2; when p = 3 the number of plants is 29.

The complete question is given below:-

liana cubed the number of flowering plants in her garden, then added 2 vegetable plants. Let p represent the original number of plants in her garden. Which shows an expression to represent the total number of plants in her garden and the total number of plants if p = 3? 3 p minus 2; when p = 3 the number of plants is 7 3 p + 2; when p = 3 the number of plants is 11 p cubed minus 2; when p = 3 the number of plants is 25 p cubed + 2; when p = 3 the number of plants is 29

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

The given expression is liana cubed the number of flowering plants in her garden, then added 2 vegetable plants.

If she cubed the number of the plants will be:- P³

Now she added two vegetable plants:- 2

Then the equation will be: - p³ + 2. Now we will put the value of p = 3 in the equation.

Total number of the plants = ( 3 )³ + 2 = 27 + 2 = 29

Therefore the correct answer is option D which is p³+ 2; when p = 3 the number of plants is 29.

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Answer:

y = 47

Step-by-step explanation:

All of the angles in a triangle must add up to 180. The angle marked 3y can help us find the missing angle of the triangle: 180-3y
Then you can make an equation to help solve for y:
50 + (2y-3) + (180-3y) = 180
Combine like terms:
227-y=180
y = 47

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: y=47 \degree[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \:(2y - 3) + 50 = 3y[/tex]

[tex]\qquad \tt \rightarrow \:2y - 3 + 50 - 3y = 0[/tex]

[tex]\qquad \tt \rightarrow \:2y - 3y + 47 = 0[/tex]

[tex]\qquad \tt \rightarrow \: - y = - 47[/tex]

[tex]\qquad \tt \rightarrow \:y = 47 \degree[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

-1-5=x-8

or, -1-5+8=x

or, x= -1-5+8

or, x= -6+8

or, x=2

therefore, x=2