If ionization energy of hydrogen atom is 13.6 eV then its ionization potential will be

Answer:

[tex]r=215pm[/tex]

[tex]N_{Mn}=20[/tex]

Explanation:

From the question we are told that:

Edge length of the unit cell [tex]l=608pm[/tex]

a)

Generally the equation for The relationship between edge length and radius is mathematically given by

[tex]4r=\sqrt{2a}[/tex]

Therefore

[tex]4r=\sqrt{2*608}[/tex]

[tex]r=\frac{\sqrt{2*608}}{4}[/tex]

[tex]r=215pm[/tex]

b)

From the question we are told that:

Density [tex]\rho=7.297[/tex]

Edge length of [tex]l=630.0 pm=>630*10^-{10}[/tex]

Therefore Volume  is given as

[tex]V=l^3[/tex]

[tex]V=630*10^-{10}^3[/tex]

[tex]V=2.50047*10^{−22}[/tex]

Generally the equation for Mass is mathematically given by

[tex]m=Volume*density[/tex]

[tex]m=V*\rho[/tex]

[tex]m=2.50047*10^{−22}*7.297[/tex]

[tex]m=1.83*10^{-21}g[/tex]

Therefore Molarity is given as

[tex]n=\frac{M}{Molar M}[/tex]

[tex]n=\frac{1.83*10^{-21}g}{55}[/tex]

[tex]n=3.32*10^{-23}[/tex]

Finally The atoms in a unit cell is

[tex]N_{Mn}=Moles*Avogadro\ constant[/tex]

[tex]N_{Mn}=3.32*10^{-23}*6.023*10^{23}[/tex]

[tex]N_{Mn}=20[/tex]

Answer:

a. It turns color in the presence of an enzyme that us bound to the secondary antibody.

Explanation:

The compound chloronapthenel is used in the reaction because it changes the color in the presence of an enzyme. It is strong organic compound which is used in biochemical processes.

Answer:

A

Explanation:

it increase the rate of reaction when necessary

The chemical change that is  responsible for producing the heat that maintains the temperature of your body is metabolism.

Chemical changes are defined as changes which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical change.

There are several characteristics of chemical changes like change in color, change in state , change in odor and change in composition . During chemical change there is also formation of precipitate an insoluble mass of substance or even evolution of gases.

There are three types of chemical changes:

1) inorganic changes

2)organic changes

3) biochemical changes

During chemical changes atoms are rearranged and changes are accompanied by an energy change as new substances are formed.

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Answer:

6.2g of NaBr are produced

Explanation:

The reaction of HBr with NaOH occurs as follows:

HBr + NaOH → NaBr + H2O

Where 1 mole of each reactant produce 1 mole of NaBr

To solve this question we need to find the moles of each reactant using their molar mass. With moles we can find limiting reactant and the moles (And mass) of NaBr produced, as follows:

Moles HBr -Molar mass: 80.9119g/mol)-

4.9g * (1mol/80.9119g) = 0.0606 moles HBr

Moles NaOH -Molar mass: 40g/mol-

3.86g * (1mol/40g) = 0.0965 moles NaOH

As the reaction is 1:1 and the moles of HBr < Moles NaOH, the limiting reactant is HBr and moles of NaBr produced are 0.0606 moles.

The mass of NaBr (Molar mass: 102.894g/mol) is:

0.0606 moles * (102.894g/mol) =

Answer:

the metal become red hot

Answer:

5g/cm3

Explanation:

firstly convert the litres and kilograms to grams and centimeters.

1l is equivalent to 1000cm3

0.58×1000

580cm3

and 1kg is equivalent to 1000g

2.9×1000

2900

then find the density by using the formula

density=mass/volume

=2900g/580cm3

=5g/cm3

I hope this helps

Explanation:

Because molarity is mol/L, we'll have to convert 17g to mol.

After obtaining the mol, we'll divide that by the volume to obtain Molarity.

[tex]\\ \sf\longmapsto NH_3[/tex]

[tex]\\ \sf\longmapsto 14u+3(1u)[/tex]

[tex]\\ \sf\longmapsto 14u+3u[/tex]

[tex]\\ \sf\longmapsto 17u[/tex]

[tex]\\ \sf\longmapsto 17g/mol[/tex]

Moles of Ammonia:-

[tex]\boxed{\sf No\:of\:moles =\dfrac{Given\:mass}{Molar\:mass}}[/tex]

[tex]\\ \sf\longmapsto No\:of\:moles=\dfrac{17}{17}[/tex]

[tex]\\ \sf\longmapsto No\;of\:moles=1mol[/tex]

We know

[tex]\boxed{\sf Molarity=\dfrac{Moles\:of\:solute}{Volume\:of\: Solution\:in\:L}}[/tex]

[tex]\\ \sf\longmapsto Molarity=\dfrac{1}{0.50}[/tex]

[tex]\\ \sf\longmapsto Molarity=2M[/tex]

Answer:

It is 1.25 moles

Explanation:

Molar mass of sulphur = 32 g

[tex]{ \bf{moles = \frac{given \: mass}{molar \: mass} }} [/tex]

Substitute:

[tex]{ \sf{moles = \frac{40}{32} }} \\ { \sf{ = 1.25 \: moles}}[/tex]

Answer:

The energy required to break a covalent bond

Explanation:

When a chemical bond is formed, energy is released. When a chemical bond is broken, energy is absorbed.

We define the bond dissociation energy as the energy required to break a covalent bond. The process of covalent bond cleavage is endothermic hence energy is absorbed for the process to occur.

Answer:

In 36 minutes, 100 grams of Chemical C is formed.

Explanation:

Combination of chemicals A and B = chemical C

Chemical A available = 100 grams

Chemical B available = 50 grams

Proportion of A mixed with C = A2

Proportion of B mixed with C = B1

Therefore, Chemical C = A2 + B1

If 25 grams of C is formed in 9 minutes

In one minute 25/9 grams of C will be formed

Therefore, in 36 minutes, 25/9 * 36 = 100 grams

Answer:

The number of moles of strontium sulfide produced is:

= 1.663.

Explanation:

Chemical formula for strontium sulfide = SrS

Production of strontium sulfide = 199g

1 mole = 1 moles Strontium Sulfide, which is equal to 119.685 grams

The number of moles of strontium sulfide produced = 1.663 (199/119.685)

The number of moles of strontium sulfide produced is the dividend of the amount of strontium sulfide produced during the experiment divided by the mass of 1 mole.

N₂ + 3H₂ ⇄ 2NH₃ + heat

In the given equilibrium, we notice that the heat is on the right. which means that if the heat requirements don't meet, the reactants on the right will no longer react due to the lack of heat

but because the reactants on the left don't have such weaknesses, they will keep reacting hence producing more and more ammonia until a new equilibrium is reached

where there will be more ammonia and less nitrogen and hydrogen as compared to the equilibrium we had initially

Answer:

Explanation:

heat is given out as 1 of the products, along w/ NH3 in the forward reaction. so its an exothermic reaction

decreasing temperature favors exothermic reaction as more heat can be absorbed by the environment

so equilibrium will shift towards the products

Answer:

When ionic compounds dissolve, they break apart into ions which are then able to conduct a current ( conductivity ). ... Many molecular compounds, such as sugar or ethanol, are nonelectrolytes. When these compounds dissolve in water, they do not produce ions.

Explanation:

Ethanol is an organic compound with an alcoholic functional group and is nonelectrolytes. Ethanol (CH₃CH₂OH) does not form ions in an aqueous solution. Thus, option B is correct.

Nonelectrolytes are substances that do not dissociate readily to yield ions and also are poor conductors of electricity and heat due to a lack of charged ions.

Ethanol is a nonelectrolyte that does not show conductivity and can be dissolved in water without producing ions. They cannot forms ions upon dissociation as covalent bonds are present.

Instead of ions that have covalent compounds that lack the ability to transfer the electron to conduct the electrical charge. Glucose, ethanol, etc. are some examples of a nonelectrolyte.

Therefore, option B. ethanol does not form ions is the correct blank.

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Answer: A buffer solution reacts with basic solutions.

A buffer solution resists small changes in pH.

A buffer solution reacts with acidic solutions.

Explanation:

A buffer solution simply refers to an aqueous solution that consist of a mixture of a weak acid and the conjugate. From the options given, the ones application to a buffer solution include:

• A buffer solution reacts with basic solutions.

• A buffer solution resists small changes in pH.

• A buffer solution reacts with acidic solutions.

Answer:

6.63 M

Explanation:

NaCl(s) ---> Na^+(aq) + Cl^-(aq)

Given that [Na^+] = [Cl^-] = s

Where s= concentration of the both ions

Ksp = s^2

s= √Ksp

s= √43.9

s= 6.63 M

The concentration of Na (in M) obtained when it begins to crystallize out of solution is 6.63 M

The solubility of product (Ksp) is defined as the concentration of products raised to their coefficient coefficients. This is illustrated below:

mX <=> nY + eZ

Ksp = [Y]^n × [Z]^e

NaCl(aq) → Na⁺(aq) + Cl¯(aq)

Ksp = [Na⁺] × [Cl¯]

43.9 =  y × y

43.9 = y²

Take the square root of both side

y = √43.9

y = 6.63 M

Thus, the concentration of Na⁺ is 6.63 M

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it's helpful

you can try this answer

Answer:

Al + MnO4- + 2H2O → Al(OH)4- + MnO2

Explanation:

First of all, we out down the skeleton equation;

Al + MnO4- → MnO2 + Al(OH)4-

Secondly, we write the oxidation and reduction equation in basic medium;

Oxidation half equation:Al + 4H2O + 4OH- → Al(OH)4- + 4H2O + 3e-

Reduction half equation:MnO4- + 4H2O + 3e- → MnO2 + 2H2O + 4OH-

Thirdly, we add the two half reactions together to obtain:

Al + MnO4- + 8H2O + 4OH- + 3e- → Al(OH)4- + MnO2 + 6H2O + 3e- + 4OH-

Lastly, cancel out species that occur on both sides of the reaction equation;

Al + MnO4- + 8H2O→ Al(OH)4- + MnO2 + 6H2O

The simplified equation now becomes;

Al + MnO4- + 2H2O → Al(OH)4- + MnO2

The question is incomplete. The complete question is :

Hydrogen [tex](H_2)[/tex] gas and oxygen [tex](O_2)[/tex] gas react to form water vapor [tex](H_2O)[/tex]. Suppose you have 11.0 mol of [tex]H_2[/tex] and 13.0 mol of [tex]O_2[/tex] in a reactor. Calculate the largest amount of [tex]H_2O[/tex] that could be produced. Round your answer to the nearest 0.1 mol .

Solution :

The balanced reaction for reaction is :

[tex]$2H_2(g) \ \ \ \ + \ \ \ \ \ O_2(g)\ \ \ \rightarrow \ \ \ \ 2H_2O(g)$[/tex]

11.0                      13.0

11/2                       13/1     (dividing by the co-efficient)

6.5 mol               13 mol    (minimum is limiting reagent as it is completely consumed during the reaction)

Therefore, [tex]H_2[/tex] is limiting reagent. It's stoichiometry decides the product formation amount from equation above it is clear that number of moles for [tex]H_2O[/tex] will be produced = number of moles of [tex]H_2[/tex]

                                     = 11.0 mol

Answer:

Line graphs are used to track changes over short and long periods of time. When smaller changes exist, line graphs are better to use than bar graphs. Line graphs can also be used to compare changes over the same period of time for more than one group.

Answer:

dissolution is the process

Answer:

N2 but i really didn't know

The compound that would be expected to be an electrolyte is : ( A ) N₂

An electrolyte is any subsatnce which conducts electircity when dissolved in a solvent such as water. From the question the compound that can conduct electricty when dissolved in water is N₂

Hence we can conclude that The compound that would be expected to be an electrolyte is : ( A ) N₂

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Answer:

2Ag(s) + 2H²S(g) + O2(g) ➡️ Ag2S(s) + 2H2O(g)

Explanation:

Sorry for my typo. but you understand

Answer:

HClO₃(aq) + NaOH(aq) ⇒ NaClO₃(aq) + H₂O(l)

Explanation:

We have the products of a reaction and we have to predict the reactants. Since the products are salt and water, this must be a neutralization reaction. In a neutralization reaction, an acid reacts with a base. To form NaClO₃, the acid must be HClO₃(aq) and the base NaOH(aq). The balanced chemical equation is:

HClO₃(aq) + NaOH(aq) ⇒ NaClO₃(aq) + H₂O(l)

Explanation:

Lanthanide series= E4

Boron=Si

Chalogen=O

Alkaline Earth metal =M9

The equilibrium constant K₁ = Equilbrium constant K₂.

The equilibrium constant, K, of a reaction, is defined as:

"The ratio between concentration of products powered to their reaction quotient and concentration of reactants powered to thier reaction quotient".

For the reaction:

aA + bB ⇄ cC + dD

The equilibrium constant, K, is:

[tex]K = \frac{[C]^c[D]^d}{[A]^a[B]^b}[/tex]

Now, assuming the reaction of the problem is 1:1:

A + B ⇄ C + D

[tex]K = \frac{[C][D]}{[A][B]}[/tex]

The concentrations of the reactants are directly proportional to the volume added. Thus, we can assume that concentration = Volume. Replacing for K₁ and K₂:

[tex]K_1 = \frac{[C][D]}{[10mL][10mL]} = K_1 = \frac{[C][D]}{100mL^2}[/tex]

In the same way:

[tex]K_2 = \frac{[C][D]}{[1mL][100mL]} = K_2 = \frac{[C][D]}{100mL^2}[/tex]

Thus, we can say:

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Answer:

The answer is "[tex]32819.9 \ \frac{J}{mol}\\\\[/tex]"

Explanation:

[tex]Boron: 5^{B}\to 1s^2 2s^2 2p^1[/tex]

[tex]\Delta E=-2.18\times 10^{-18}\ \frac{J}{atom}\ (\frac{1}{\infity^2}-\frac{1}{n^2_{initial}})(z^2) (6.022\times 10^{23}\ \frac{atom}{mol})\\\\[/tex]

      [tex]=-2.18\times 10^{-18}\ \frac{J}{atom}\ (0-\frac{1}{1})(5^2) (6.022\times 10^{23}\ \frac{atom}{mol})\\\\ =2.18\times 10^{-18}\times 25 \times 6.022\times 10^{23}\ (\frac{J}{mol})\\\\ =328.199 \times 10^{5}\ (\frac{J}{mol})\\\\ =32819 \times 10^{3}\ (\frac{J}{mol})\\\\ =32819.9 \ (\frac{J}{mol})\\\\[/tex]

Answer:

The correct answer is "1.0100".

Explanation:

Let the volume of mixture be 100 ml.

then,

The volume of DMSO will be 10 mL as well as that of water will be 90 mL.

DMSO will be:

= [tex]10\times 1.1004[/tex]

= [tex]11.004 \ g[/tex]

The total mass of mixture will be:

= [tex]90+11.004[/tex]

= [tex]101.004 \ g[/tex]

Density of mixture will be:

= [tex]\frac{Mass}{Volume}[/tex]

= [tex]\frac{101.004}{100}[/tex]

= [tex]1.01004 \ g/mL[/tex]

hence,

Specific gravity of mixture will be:

= [tex]\frac{Density \ of \ mixture}{Density \ of \ water}[/tex]

= [tex]\frac{1.01004}{1}[/tex]

= [tex]1.0100[/tex]