Answer:
[tex] \frac{1}{.41} = 2.4390[/tex]
One British pound should sell for $2.4390.
D is correct.
if the known sides of a triangle are 4 and 12, what lengths must the third side be greater than and less than, respectively?
the third side must be greater than 8 and less than 16.
To determine the range of possible lengths for the third side of the triangle, we can use the triangle inequality theorem, which states that the sum of any two sides of a triangle must be greater than the third side.
So, for a triangle with sides of 4 and 12, the third side must satisfy:
12 - 4 < third side < 12 + 4
which simplifies to:
8 < third side < 16
what is triangle?
A triangle is a geometric shape with three sides and three angles. It is formed by connecting three non-collinear points in a plane. The sum of the interior angles of a triangle is always 180 degrees, and there are various types of triangles based on their side lengths and angle measures.
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there exists a continuous function defined for all real numbers that is concave up and always negative.T/F
it is not possible for a continuous function to be concave up and always negative.
To see why, note that a concave up function is one whose second derivative is positive. So we need to find a function whose second derivative is positive and is always negative.
However, if a function is always negative, then its values are always less than or equal to zero. This means that its second derivative must be non-positive, since the second derivative measures the rate at which the function's slope is changing.
Now suppose that we have a function f(x) that is concave up and always negative. Since f(x) is always negative, we have f(x) < 0 for all x. But since f(x) is concave up, its second derivative f''(x) is positive. This means that f(x) is increasing, and in particular, as x goes to infinity, f(x) must approach a limit. But since f(x) is always negative, its limit as x goes to infinity must be nonpositive. This is a contradiction, since a concave up function that is always negative cannot have a nonpositive limit at infinity.
Therefore, it is not possible for a continuous function to be concave up and always negative.
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for a single randomly selected movie, find the probability that this movie's production cost is between 64 and 70 million dollars.
Probability of selecting a movie with a production cost between 64 and 70 million dollars is 0.1915 or 19.15%.
To find the probability that a single randomly selected movie's production cost is between 64 and 70 million dollars, we need to know the distribution of production costs for movies. Let's assume that the distribution is approximately normal.
We also need to know the mean and standard deviation of production costs. Let's assume that the mean production cost is 60 million dollars and the standard deviation is 10 million dollars.
Using these parameters, we can standardize the range of production costs we're interested in by subtracting the mean and dividing by the standard deviation:
z1 = (64 - 60) / 10 = 0.4
z2 = (70 - 60) / 10 = 1
We can then use a standard normal distribution table or calculator to find the area under the curve between these two standardized values:
P(0.4 ≤ Z ≤ 1) ≈ 0.1915
This means that the probability of selecting a movie with a production cost between 64 and 70 million dollars is approximately 0.1915 or 19.15%.
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Wanda’s Widgets used market surveys and linear regression to develop a demand function based on the wholesale price. The demand function is q = –140p + 9,000. The expense function is E = 2.00q + 16,000. At a price of $10.00, how many widgets are demanded?
With the help of demand function, when the wholesale price is $10.00, Wanda's Widgets will demand 7,600 widgets.
What is function?
n mathematics, a function is a rule that assigns a unique output value to every input value in a specified set. In other words, it is a relationship between two sets of values, where each input value in the first set is associated with a unique output value in the second set.
The demand function is given by q = –140p + 9,000, where q is the quantity demanded and p is the wholesale price.
To find the quantity demanded when the price is $10.00, we can substitute p = 10 in the demand function and solve for q:
q = –140(10) + 9,000
q = –1,400 + 9,000
q = 7,600
Therefore, when the wholesale price is $10.00, Wanda's Widgets will demand 7,600 widgets.
Note that the expense function E = 2.00q + 16,000 is not used to find the quantity demanded in this problem. It is used to calculate the total expenses based on the quantity demanded.
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What is the image of (−2,6) after a dilation by a scale factor of 1/2 centered at the origin?
The image of (−2, 6) after a dilation by a scale factor of 1/2 centered at the origin is (-1, 3)
What is dilation?In Geometry, dilation can be defined as a type of transformation which typically changes the size of a geometric object, but not its shape. This ultimately implies that, the size of the geometric object would be increased or decreased based on the scale factor used.
Next, we would have to dilate the coordinates of the preimage by using a scale factor of 1/2 centered at the origin as follows:
Ordered pair A (-2, 6) → Ordered pair A' (-2 × 1/2, 6 × 1/2) = Ordered pair A' (-1, 3).
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what is the probability of winning a state lottery game where the winning number is made up of four digits from 0 to 9 chosen at random?
The probability of winning this lottery game is 1/10,000 or 0.0001 (0.01% chance). The probability of winning a state lottery game where the winning number is made up of four digits from 0 to 9 chosen at random can be calculated as follows.
First, we need to determine the total number of possible outcomes. There are 10 digits (0 to 9) and we are choosing four of them, so the total number of possible outcomes is 10 x 10 x 10 x 10 = 10,000.
Next, we need to determine the number of favorable outcomes, which is the number of ways to choose four digits from 0 to 9. This is a combination problem, and we can use the formula nCr = n! / r!(n-r)! where n is the total number of options and r is the number of choices. So in this case, n = 10 and r = 4, giving us 10C4 = 10! / 4!(10-4)! = 210 favorable outcomes.
Finally, we can calculate the probability of winning by dividing the number of favorable outcomes by the total number of outcomes:
Probability of winning = favorable outcomes / total outcomes
Probability of winning = 210 / 10,000
Probability of winning = 0.021 or 2.1%
So the probability of winning a state lottery game where the winning number is made up of four digits from 0 to 9 chosen at random is 0.021 or 2.1%.
Hi! The probability of winning a state lottery game with a four-digit winning number, where each digit ranges from 0 to 9, can be calculated as follows:
There are 10 choices (0 to 9) for each of the four digits. Thus, the total number of possible combinations is 10 x 10 x 10 x 10 = 10,000. Since there is only one winning number, the probability of selecting that number at random is 1 out of the total possible combinations.
So, the probability of winning this lottery game is 1/10,000 or 0.0001 (0.01% chance).
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[tex]\frac{x^{2} -4xy+4y^{2} }{3xy-6y^{2} }[/tex]
In the 1930s a prominent economist devised the following demand function for corn: p = 6,600,000 q1.3 , where q is the number of bushels of corn that could be sold at p dollars per bushel in one year. Assume that at least 13,000 bushels of corn per year must be sold. (a) How much should farmers charge per bushel of corn to maximize annual revenue? HINT [See Example 3, and don't neglect endpoints.] (Round to the nearest cent.) p = $ (b) How much corn can farmers sell per year at that price? q = bushels per year (c) What will be the farmers' resulting revenue? (Round to the nearest cent) per year
The price that maximizes annual revenue is $17.86 per bushel, which should be charged by the farmers; The quantity of corn that can be sold per year at 67,786 bushels per year; the farmers' resulting revenue will be $1,210,392.96 per year.
To find the price that maximizes annual revenue, we need to differentiate the revenue function with respect to the price and set it equal to zero:
Revenue = pq = (6,600,000q^1.3)q
= 6,600,000q^2.3
dRevenue/dp = q
Setting dRevenue/dp = 0, we get q = 0, which is not a valid solution. Therefore, we need to consider the endpoints of the feasible range, which is q >= 13,000.
At q = 13,000, we have p = 6,600,000*13,000^(-0.3) ≈ $17.86 per bushel.
At q → ∞, we have p → 0.
So, the price that maximizes annual revenue is $17.86 per bushel, which should be charged by the farmers.
The quantity of corn that can be sold per year at that price is given by
q = (p/6,600,000)^(1/1.3)
= (17.86/6,600,000)^(1/1.3)
≈ 67,786 bushels per year.
The farmers' resulting revenue will be Revenue = p*q
= $17.86 * 67,786
≈ $1,210,392.96 per year.
Therefore, the price that maximizes annual revenue is $17.86 per bushel, which should be charged by the farmers; The quantity of corn that can be sold per year at 67,786 bushels per year; the farmers' resulting revenue will be $1,210,392.96 per year.
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if 50% of the respondents in a sample of 400 agree with a particular statement, and the estimated amount of error associated with this answer is /- 5.2%, what is the confidence interval?
The confidence interval is (0.451, 0.549).
To find the confidence interval, we need to use the formula:
Confidence interval = sample proportion +/- margin of error
where the margin of error is calculated as:
Margin of error = z* (standard error)
The standard error is the standard deviation of the sampling distribution of the proportion, which is calculated as:
Standard error = [tex]\sqrt{p*(1-p)/n}[/tex]
where p is the sample proportion and n is the sample size.
The z-value corresponding to a 95% confidence level is 1.96.
Using the given information, we have:
Sample proportion (p) = 0.50
Sample size (n) = 400
Margin of error = 0.052 * 0.5 = 0.026
Standard error = [tex]\sqrt{0.5(1-0.5)/400}[/tex] = 0.025
Z-value for 95% confidence level = 1.96
So the confidence interval is:
0.50 +/- 1.96 * 0.025
= 0.50 +/- 0.049
Therefore, the confidence interval is (0.451, 0.549) or 45.1% to 54.9%. We can say with 95% confidence that the true proportion of respondents who agree with the statement lies between 45.1% and 54.9%.
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In the screenshot need help with this can't find any calculator for it so yea need help.
Considering a number of 100 trials, the experimental probability of heads should be close to the theoretical probability of 1/2 = 50%.
How to calculate a probability?A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.
A fair coin is equally as likely to come up heads or tails, hence the theoretical probability of heads is given as follows:
1/2 = 0.5 = 50%.
For a large number of trials, such as 100 trials, the experimental probability is expected to be close to the theoretical probability, hence it should also be close to 50%.
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A livestock company reports that the mean weight of a group of young steers is 1146 pounds with a standard deviation of 86 pounds. Based on the model ​N(1146​,86​) for the weights of​ steers, what percent of steers weigh a) over 1200 ​pounds? ​b) under 1100 ​pounds? ​c) between 1250 and 1300 ​pounds?
a) 26.43% of steers weigh over 1200 pounds.
b) 29.46% of steers weigh under 1100 pounds.
c) 7.26% of steers weigh between 1250 and 1300 pounds.
The proportion of steers that weigh over 1200 pounds the area to the right of 1200 under the normal curve with mean 1146 and standard deviation 86.
A z-score and the standard normal distribution to find this area.
The z-score is:
z = (1200 - 1146) / 86 = 0.63
A standard normal distribution table or calculator the area to the right of z = 0.63 is 0.2643.
The proportion of steers that weigh under 1100 pounds, the area to the left of 1100 under the normal curve with mean 1146 and standard deviation 86.
Again, we can use a z-score and the standard normal distribution to find this area.
The z-score is:
z = (1100 - 1146) / 86 = -0.54
A standard normal distribution table or calculator the area to the left of z = -0.54 is 0.2946.
The proportion of steers that weigh between 1250 and 1300 pounds The area between the z-scores corresponding to these weights.
The z-score for 1250 pounds is:
z1 = (1250 - 1146) / 86 = 1.23
The z-score for 1300 pounds is:
z2 = (1300 - 1146) / 86 = 1.79
A standard normal distribution table or calculator the area to the left of z1 is 0.8907, and the area to the left of z2 is 0.9633.
The area between z1 and z2 is:
0.9633 - 0.8907 = 0.0726
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Use cylindrical coordinates to evaluate ∭E√x2+y2dV, where E is the region that lies inside the cylinder x2+y2=16 and between the planes z=−5 and z=4.
The value of the triple integral is 72π.
To evaluate this triple integral in cylindrical coordinates, we first need to express the region E using cylindrical coordinates.
The cylinder x² + y² = 16 can be expressed in cylindrical coordinates as r² = 16, or r = 4. The planes z = -5 and z = 4 define a region of height 9.
So, the region E can be expressed in cylindrical coordinates as:
4 ≤ r ≤ 4
-5 ≤ z ≤ 4
0 ≤ θ ≤ 2π
The integrand √(x² + y²) can be expressed in cylindrical coordinates as r, so the integral becomes:
∭E√x²+y²dV = ∫0²π ∫4⁴ ∫-5⁴ r dz dr dθ
Note that the limits of integration for r are from 0 to 4, which means we are only integrating over the positive x-axis. Since the integrand is an even function of x and y, we can multiply the result by 2 to get the total volume.
The integral with respect to z is easy to evaluate:
∫₋₅⁴ r dz = r(4 - (-5))
= 9r
So the triple integral becomes:
∭E√x²+y²dV = 2 ∫0^2π ∫4⁴ 9r dr dθ
= 2(9) ∫0^²π 4 dθ
= 72π
Therefore, the value of the triple integral is 72π.
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Question 3 (1 point) The table shows y as a function of x. Suppose a point is added to this table. Which choice gives a point that preserves the function? a (9, −5) b (−1, −5) c (−8, −6) d (−5, 7)
If a point is added in the table, then the point which preserves the function is (d) (-5, 7).
The relation given in the table is a function, which means that every value of "x" in the domain must have exactly one corresponding value of "y" in the range.
The inputs , x = 9, x = -8, and x = -1 already have defined values in the table, so any other value assigned to these inputs would create a situation where an input has more than one output.
So, the only choice that would preserve the function is (d) (-5, 7), which assigns a "new-value" to an input that doesn't have a defined value in the table.
This new input-output pair is consistent with the existing function rule and ensures that every input in the domain has exactly one output in the range, preserving the function.
Therefore, the correct option is (d).
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The given question is incomplete, the complete question is
The table shows y as a function of x. Suppose a point is added to this table.
x y
6 -9
-8 9
-1 -4
9 -6
8 -8
Which choice gives a point that preserves the function?
(a) (9, -5)
(b) (-1, -5)
(c) (-8, -6)
(d) (-5, 7)
Leon evaluated the expression
Negative one-half(–4a – 6) + a2 for a = 8.
The expression when solved for a = 8 is 26
What are algebraic expressions?Algebraic expressions are defined as mathematical expressions that are made up of terms, variables, constants, coefficients, and factors.
Also, algebraic expressions are seen as expressions that consist of mathematical operations.
These mathematical operations are;
BracketAdditionParenthesesSubtractionDivisionMultiplicationFrom the information given, we have;
(–4a – 6) + a2 for a = 8
Now, substitute the value of a as 8 in the expression, we have;
(-4(8) - 6) + (8)^2
find the square
-32 - 6 + 64
Add the values
26
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The average weight of a high school freshman is 142 pounds. If a sample of twenty
freshmen is selected, find the probability that the mean of the sample will be greater than
145 pounds. Assume the variable is normally distributed with a standard deviation of 12.3
pounds.
The probability that the mean weight of a sample of twenty freshmen will be greater than 145 pounds is 0.138.
What is the probability?The probability is determined using the central limit theorem and the formula for the standard error of the mean:
SE = σ/√nwhere;
SE is the standard error of the mean,σ is the population standard deviation, andn is the sample size.Data given;
σ = 12.3 pounds; n = 20
SE = 12.3/√20
SE = 2.75 pounds.
The sample mean is then standardized using the z-score formula:
z = (x - μ) / SE
z = (145 - 142) / 2.75
z = 1.09
Using a calculator, the probability of a z-score greater than 1.09 is 0.138.
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find x
49^(x+4)=7^(5x-1)
A. x=3
B. x=1
C. x=1/3
D. x=9/7
Answer:
A is the correct answer. x = 3.
Step-by-step explanation:
[tex] {49}^{x + 4} = {7}^{5x - 1} [/tex]
[tex] {7}^{2(x + 4)} = {7}^{5x - 1} [/tex]
[tex]2x + 8 = 5x - 1[/tex]
[tex]3x = 9[/tex]
[tex]x = 3[/tex]
Billy is creating a rectangular patio in his backyard using square cement tiles. The length of the patio, in feet, is represented by the function I(x) = X + 5, and the width of the patio is represented by the function w(x) = X + 3.
Write the standard from of the function which describes the total area of the patio, a(x) in terms of x, the side length of each tile.
The area in terms of x, can be written as:
A(x) = x² + 8x + 15
How to find the equation for the area of the rectangle?Remember that the area of a rectangle is given by the product between the dimensions.
Here we know that the length is:
L(x) = x + 5
And the width is:
W(x) = x + 3
Then the formula for the area is:
A(x) = (x + 5)*(x + 3)
A(x) = x² + 5x + 3x + 15
A(x) = x² + 8x + 15
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The test statistic of zequalsnegative 3.25 is obtained when testing the claim that pequals3 divided by 5.
a. Using a significance level of alphaequals0.01, find the critical value(s).
b. Should we reject Upper H 0 or should we fail to reject Upper H 0?
a. Using a significance level of α = 0.01, the critical values for a two-tailed test are ±2.576.
b. To determine whether to reject or fail to reject the null hypothesis, we compare the test statistic (-3.25) to the critical values. Since -3.25 is less than -2.576, we can reject the null hypothesis at the 0.01 significance level. This means we have evidence to support the claim that p = 3/5.
What is significance level?
Significance level, denoted as alpha (α), is the probability threshold used to determine whether a statistical hypothesis is rejected or not. It represents the maximum level of Type I error that a researcher is willing to accept.
A test statistic is a numerical value calculated from a sample of data that is used in hypothesis testing to determine whether to reject or fail to reject a null hypothesis.
The test statistic is compared to a critical value to make this determination. The critical value is a threshold value determined by the level of significance and the degrees of freedom of the sample.
If the test statistic falls within the rejection region determined by the critical value, the null hypothesis is rejected. If the test statistic falls outside the rejection region, the null hypothesis is not rejected.
a. Using a significance level of α = 0.01, the critical values for a two-tailed test are ±2.576.
b. To determine whether to reject or fail to reject the null hypothesis, we compare the test statistic (-3.25) to the critical values. Since -3.25 is less than -2.576, we can reject the null hypothesis at the 0.01 significance level. This means we have evidence to support the claim that p = 3/5.
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Suppose we want to assess the effect of a one-day SAT prep class at a 5% level of significance. Scores on the SAT writing exam can range from 200 to 800. A random sample of 50 students takes the SAT writing test before and after a prep class. We test the hypotheses: LaTeX: H_0 H 0 : LaTeX: \mu=0 μ = 0 LaTeX: H_a H a : LaTeX: \mu>0 μ > 0 where LaTeX: \mu μ is the mean of the difference in SAT writing scores (after minus before) for all students who take the SAT prep class. The sample mean is 5 with a standard deviation of 18. Since the sample size is large, we are able to conduct the T-Test. The T-test statistic is approximately 1.96 with a P-value of approximately 0.028. What can we conclude?
The SAT prep class has no influence on the mean difference in SAT writing scores, hence the null-hypothesis (H0) states that the mean difference is zero.
The alternative theory (Ha) states that the SAT prep course has a positive impact on the mean difference in SAT writing scores, resulting in a mean difference that is greater than zero.
The sample size of 50 is sufficient for us to do the hypothesis test using the t-distribution.
The estimated t-test statistic is 1.96, and at the 5% level of significance, it is significant only if it is in the rejection zone of the null hypothesis (1.677 is the crucial value for a one-tailed test with 49 degrees of freedom).
The calculated p-value of 0.028 is less than the threshold of 0.05, the null hypothesis is also rejected in favour of the alternative hypothesis.
To draw the conclusion that the SAT prep course has a favourable impact on the mean difference in SAT writing scores. Particularly, at the 5% level of significance, the sample-mean difference of 5 is statistically significantly greater than zero.
Therefore, it is reasonable.
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Which r-value represents the most moderate correlation?.
The r-value that represents the most moderate correlation would be around 0.5. This value indicates a moderate positive correlation, meaning that there is a moderate relationship between two variables that are moving in the same direction.
An r-value, or correlation coefficient, represents the strength and direction of a linear relationship between two variables. The r-value ranges from -1 to 1, where:
-1 indicates a strong negative correlation,
0 indicates no correlation, and
1 indicates a strong positive correlation.
A moderate correlation falls in the middle of this range. For example, an r-value of approximately 0.5 (positive moderate correlation) or -0.5 (negative moderate correlation) would represent a moderate correlation between the two variables.
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If 2x + 4 = 36 what is the value of X
Answer:
x = 16
Step-by-step explanation:
to solve for x, you need to isolate x on one side of the equation and move everything else to the other side. You can do this by using inverse operations, such as subtraction, addition, multiplication, and division. Here are the steps to follow:
Start with the original equation: 2x + 4 = 36Subtract 4 from both sides to eliminate the constant term on the left side: 2x + 4 - 4 = 36 - 4Simplify both sides: 2x = 32Divide both sides by 2 to eliminate the coefficient of x on the left side: 2x / 2 = 32 / 2Simplify both sides: x = 16So the value of x is 16.
we desire the residuals in our model to have which probability distribution? select answer from the options below normal binomial poisson
The distribution that the residuals in our model to follow is equals to the normal probability distribution. So, option(a).
Because residuals are defined as the difference between any data point and the regression line, they are sometimes called "errors". An error in this context does not mean that there is anything wrong with the analysis. In other words, the residual is the error that is not described by the regression line. The residue(s) can also be expressed by "e". The formula is written as, Residual = Observed value – predicted value or
[tex]e = y – \hat y [/tex].
In order to draw valid conclusions from your regression, the regression residuals should follow a normal distribution. The residuals are simply the error terms or differences between the observed value of the dependent variable and the predicted value. Therefore, the residuals should have a normal distribution.
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Complete question:
we desire the residuals in our model to have which probability distribution? select answer from the options below
a) normal
b) binomial
c) poisson
In regression analysis, the variable that is being predicted is the.
In regression analysis, the variable that is being predicted is called the dependent variable or response variable. It is the outcome variable that is being measured or predicted based on the values of other variables, which are referred to as independent variables or predictors.
The independent variables are used to explain the variation in the dependent variable and to determine the strength and direction of their relationship.
Regression analysis is a statistical method that is used to estimate the relationship between the dependent variable and one or more independent variables by fitting a line or curve through the data points. The resulting regression equation can then be used to predict the value of the dependent variable based on the values of the independent variables.
The quality of the regression model is evaluated by measuring the goodness of fit, which measures how well the model fits the data, and by examining the significance of the coefficients, which measures the strength and direction of the relationship between the variables
. Overall, regression analysis is a powerful tool that is widely used in many fields to understand and predict the relationship between variables.
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suppose a packaging system fills boxes such that the weights are normally distributed with a mean of 16.3 ounces and a standard deviation of 0.21 ounces. what is the probability that a box weighs between 16.4 and 16.5 ounces? report your answer to 2 decimal places.
The probability that a box weighs between 16.4 and 16.5 ounces is approximately 14.45% (rounded to 2 decimal places). To solve this problem, we need to use the z-score formula:
z = (x - μ) / σ
where x is the weight of the box, μ is the mean weight of all boxes, σ is the standard deviation of weights, and z is the number of standard deviations away from the mean.
In this case, we want to find the probability that a box weighs between 16.4 and 16.5 ounces. We can convert these weights to z-scores as follows:
z1 = (16.4 - 16.3) / 0.21 = 0.48
z2 = (16.5 - 16.3) / 0.21 = 0.95
Using a z-score table or calculator, we can find the area under the standard normal curve between these two z-scores:
P(0.48 ≤ z ≤ 0.95) = 0.1736
Therefore, the probability that a box weighs between 16.4 and 16.5 ounces is 0.17 or 17% (rounded to 2 decimal places).
Hi! To find the probability that a box weighs between 16.4 and 16.5 ounces, we can use the z-score formula and the standard normal table.
First, let's calculate the z-scores for 16.4 and 16.5 ounces using the formula: z = (x - μ) / σ, where x is the value, μ is the mean, and σ is the standard deviation.
For 16.4 ounces:
z1 = (16.4 - 16.3) / 0.21 ≈ 0.48
For 16.5 ounces:
z2 = (16.5 - 16.3) / 0.21 ≈ 0.95
Now, use the standard normal table to find the area between these z-scores:
P(0.48 < z < 0.95) = P(z < 0.95) - P(z < 0.48) ≈ 0.8289 - 0.6844 = 0.1445
The probability that a box weighs between 16.4 and 16.5 ounces is approximately 14.45% (rounded to 2 decimal places).
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which of the following is true of relationships between variables?which of the following is true of relationships between variables?a negative relationship exists between two variables if low levels of one variable are associated with low levels of another.in a linear relationship between two variables, the strength and the direction of the relationship change over the range of both variables.a linear relationship is much simpler to work with than a curvilinear relationship.relationships between variables lack direction.the larger the size of the correlation coefficient between two variables, the weaker the association between them.
The statement that is true of relationships between variables is "Marketers are often interested in describing the relationship between variables they think influence purchases of their products." (option b).
In many fields, researchers and professionals seek to understand the relationships between different variables. A variable is any characteristic or feature that can vary and can be measured or observed. Understanding the relationship between variables can help in predicting, explaining, and controlling different phenomena. In this context, it's important to distinguish between different types of relationships and to use appropriate statistical methods to describe and test these relationships.
This statement is true. Marketers often want to understand the relationship between different variables and how they influence consumer behavior. For example, they might want to know how price, quality, brand reputation, and advertising affect the likelihood of a consumer purchasing their product. By understanding these relationships, marketers can develop more effective marketing strategies.
Hence the correct option is (b).
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Complete Question:
Which of the following is true of relationships between variables?
a) A curvilinear relationship is much simpler to work with than a linear relationship.
b) Marketers are often interested in describing the relationship between variables they think influence purchases of their products.
c) A negative relationship exists between two variables if low levels of one variable are associated with low levels of another.
d) The strength of association is determined by the size of the correlation coefficient, with smaller coefficients indicating a stronger association.
e) The null hypothesis for the Pearson correlation coefficient states that there is a strong association between two variables.
The graph below describes the height (in feet) of a flare signal in terms of t, the time (in seconds) since the flare went off. Find the y-intercept. What is the correct interpretation of the y-intercept?
A-The flare signal had a maximum height of 163 feet.
B-The flare signal was set off at a height of 3 feet.
C-The flare signal had a maximum height of 3 feet.
D-The flare signal was set off at a height of 163 feet.
Answer:
B-The flare signal was set off at a height of 3 feet.
Find the value of M.
Side question: How do I make somebody brainlist or whatever?
m = 133°
Step-by-step explanation:
You want the value of m in the given polygon.
HeptagonThe sum of interior angles in a heptagon is (7 -2)(180°) = 900°.
This fact is used to find the value of m:
138 +106 +(m -9) +m + 133 +120 +(m +13) = 900
3m = 399 . . . . . . . subtract 501
m = 133 . . . . . . . . divide by 3
The value of m is 133°.
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Additional comments
We suspect your answer will be just the numerical value.
An n-sided polygon has a sum of angles equal to (n -2)(180°).
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10. A car that is always traveling at the same speed
travels 30 miles every 0. 5 hours. How many miles
does it travel in 4. 5 hours?
The car will travel 270 miles in 4.5 hours.
How many miles does the car travel?To find out how many miles the car travels in 4.5 hours, we can use the formula of distance which is "distance = speed * time".
The car travels 30 miles every 0.5 hours. This means its speed is:
= distance / time
= 30 miles / 0.5 hours
= 60 miles per hour
In 4.5 hours, the car will travel (distance):
= Speed x Time
= 60 miles per hour x 4.5 hours
= 270 miles.
Full question "A car that is always traveling at the same speed travels 30 miles every 0. 5 hours. How many miles does it travel in 4. 5 hours?"
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I NEED HELP ASAP PLEASE
1.4, 7, 35,...
In the sequence above, each term after the first is equal to the previous term times n. What is
the value of the next term in the sequence?
(A) 150
(B) 175
(C) 227
(D) 875
(E) 4375
Answer:
B) 175
Step-by-step explanation:
Same thing as before:
To get from 1.4 to 7 and to get from 7 to 35, you have to multiply by 5.
To get from 35 to the next sequence, you also have to multiply by 5.
35·5
=175
Hope this helps! :)
Answer:
7=1.4n
n=7÷1.4
n=5
next term =35×5
=175 B
What is the surface area of this right rectangular prism?
Enter your answer as a mixed number in simplest form by filling in the boxes.
yd²
Rectangular prism with length 3 yards, width 1 and 1 third yard, and height 2 and 2 thirds yards.
Answer:
31 and 4 ninths square yards.
Step-by-step explanation:
The surface area of a right rectangular prism is the amount of wrapping paper you need to cover it up. To find it, you need to measure the length, width, and height of the prism. Then you can use this magic spell:
Surface area = 2 (lw + wh + lh) square units
where l is the length, w is the width, and h is the height.
For example, you have a right rectangular prism with length 3 yards, width 1 and 1 third yard, and height 2 and 2 thirds yards. That's a big gift! Using the magic spell, we get:
Surface area = 2 ((3 x 1 1/3) + (1 1/3 x 2 2/3) + (3 x 2 2/3)) yd² Surface area = 2 ((4 + 3 7/9 + 8)) yd² Surface area = 2 (15 7/9) yd² Surface area = 31 4/9 yd²
So the surface area of the right rectangular prism is 31 and 4 ninths square yards. That's a lot of wrapping paper! I hope you have enough tape!
