If point C is between points A and B, then ___ + CB = AB.
A. BC
B. CA
C. ABC
D. AB

Answer:

pete

Step-by-step explanation:

i think its pete???

Answer:it is o to 10/5 which is 1/

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Similar to the one you asked earlier.

Given from the table

1 Gallon of gas = $2.15

15 gallons of gas = $2.15 x 15

= $32.25 (B)

The direct proportion is shown by table (B)

Direct proportion or direct variation is the relation between two quantities where the ratio of the two is equal to a constant value.

Here the second table shows the direct proportion relation.

This is because the ratio of x/y remain same.

4/2= 7/3.5= 10/5= 11/5.5= 15/7.5 = 2/1

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Answer:

894.035793467 or roughly 894

Step-by-step explanation:

I square rooted it by using a calculator, and by working it out on paper.

The time when the object will be 6 inches above the rest position is C. 4.62 seconds.

From the information, the object is attached to a spring and is stretched and released.

The given model is given as:

d = -8 cos (π/6t)

In this case, it's important to plot the graph based on the model given. Therefore, the time when the object will be 6 inches above the rest position is 4.62 seconds.

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We use Tan in this case:

Tan=(opposite/adjacent)

Tan(36)=23/x

x=23/Tan(36)

x=31.64 length

Hope it helps!

Answer:

x ≈ 31.64

Step-by-step explanation:

Trigonometric ratios

[tex]\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}[/tex]

where:

Given:

The given trigonometric ratios all use the angle of 36°.

From inspection of the given diagram:

Therefore, we should use the tan trig ratio.

[tex]\implies \sf \tan(36^{\circ})=\dfrac{23}{x}[/tex]

[tex]\implies \sf x=\dfrac{23}{\tan(36^{\circ})}[/tex]

Substituting the given value for tan 36°:

[tex]\implies \sf x \approx \dfrac{23}{0.727}[/tex]

[tex]\implies \sf x\approx31.64[/tex]

Answer:

Step-by-step explanation:

Is there answer choices?

Answer:

48

Step-by-step explanation:

The mean of a number is the sum of all the numbers divided by how many numbers there are. We can set up this formula: [tex]mean = \frac{sum}{amountnumbers}[/tex].

When we plug our values into this equation, we get: [tex]6 = \frac{sum}{8}[/tex]. Solving this equation gets us sum = 6 * 8 = 48

The simplified expression of [tex]x^{-2/3} . x^{6/7}[/tex] is [tex]x^{4/21}[/tex]

The expression [tex]x^{-2/3} . x^{6/7}[/tex] can be simplified as follows:

using law of indices,

xⁿ . xᵇ = xⁿ⁺ᵇ

Therefore,

[tex]x^{-2/3} . x^{6/7}[/tex] = [tex]x^{-2/3 + 6/7}[/tex]

[tex]x^{-2/3 + 6/7} = x^{ -14+18/ 21}[/tex]

[tex]x^{-2/3 + 6/7} = x^{ -14+18/ 21} = x^{4/21}[/tex]

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Answer:

g(x) = (x - 5)²

Step-by-step explanation:

This is an example of the transformation of functions.

In this example, we see the graph f(x) has been moved 5 in the positive direction on the x-axis.

Due to the fact that we are working with the x-axis, our transformation will be placed inside the bracket, and it will do the opposite of what we expect.

This means that our transformation will be set out in this format:

[tex]g(x) = f(x-5)[/tex]

We know that:

[tex]f(x) = x^2[/tex]

Therefore,

[tex]g(x) = f(x-5) = (x-5)^2[/tex]

So, [tex]g(x) = (x-5)^2[/tex].

Answer:

1st option

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

here (h, k ) = (- 2, 1 ) and r = 3 , then

(x - (- 2) )² + (y - 1)² = 3² , that is

(x + 2)² + (y - 1)² = 9 ← expand factors using FOIL

x² + 4x + 4 + y² - 2y + 1 = 9

x² + 4x + y² - 2y + 5 = 9 ( subtract 9 from both sides )

x² + 4x + y² - 2y - 4 = 0 , that is

x² + y² + 4x - 2y - 4 = 0 ← in general form

Answer:

[tex]\textsf{1)} \quad x^2+y^2+4x-2y-4=0[/tex]

Step-by-step explanation:

Equation of a circle

[tex](x-a)^2+(y-b)^2=r^2[/tex]

where:

From inspection of the graph:

Substitute the found values into the formula:

[tex]\implies (x-(-2)^2+(y-1)^2=3^2[/tex]

[tex]\implies (x+2)^2+(y-1)^2=9[/tex]

Expand and simplify:

[tex]\implies (x+2)^2+(y-1)^2=9[/tex]

[tex]\implies x^2+4x+4+y^2-2y+1=9[/tex]

[tex]\implies x^2+y^2+4x-2y+5=9[/tex]

[tex]\implies x^2+y^2+4x-2y-4=0[/tex]

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Answer:

-23

Step-by-step explanation:

f(2)= 2*2-6 = -2

g(-3)= -3-2*9 = -21

---> f(2)+G(-3)= -2-21 = -23

Answer: -23

Step-by-step explanation:

     f(2) + g(-3) means that we will substitute 2 as x into the function f, and add that to -3 substituted as x into function g.

     First, we will find the substituted and simplified values of these functions.

f(x) = 2x - 6

f(2) = 2(2) - 6

f(2) = -2

[tex]-----[/tex]

g(x) = x - 2x²

g(-3) = (-3) - 2(-3)²

g(-3) = -21

     Lastly, we can add them.

f(2) + g(-3)

-2 + -21

-23

Using the cosine ratio, the expression that can be used to determine the  side length of the given rhombus is: x = 10/cos 30.

The cosine ratio that can be used to solve a right triangle is, cos ∅ = adj/hyp.

x represents the side of the rhombus as shown in the image attached.

cos 30 = 10/x

x(cos 30) = 10

x = 10/cos 30

Thus, the equation that would be used to determine the side length is: x = 10/cos 30

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Answer:

A

Step-by-step explanation:

10/cos 30°

Answer:

2.4

Step-by-step explanation:

We must do the inverse of every operation:

15 + 12 = 27

27/5 = 5.4

5.4 - 3 = 2.4

2p-4p ≤ -2

-2p ≤ 2

[tex]\frac{-2p}{-2} \leq \frac{-2}{-2}[/tex]  (Sign flips as both sides it is getting divided by NEGATIVE 2)

p≥1

Interval notation: [1, infinity)

Hope it helps!

Answer:

2x(x^2 - 3)(x^2 + 9)

Step-by-step explanation:

2x^5 + 12x^3 − 54x

2x(x^4 + 6x - 27)

Since -3 + 9 = 6 and -3 x 9 = -27:

2x(x^2 - 3)(x^2 + 9)

Answer:

[tex]2x(x^2-3)(x^2+9)[/tex]

Step-by-step explanation:

Given polynomial:

[tex]2x^5+12x^3-54x[/tex]

Factor out the common term [tex]2x[/tex]:

[tex]\implies 2x(x^4+6x^2-27)[/tex]

To factor the trinomial [tex]x^4+6x^2-27[/tex]:

[tex]\textsf{Let }u=x^2 \implies u^2+6u-27[/tex]

Factor the quadratic by finding two numbers that multiply to -27 and sum to 6:  9 and -3

Rewrite the middle term as the sum of these two numbers:

[tex]\implies u^2+9u-3u-27[/tex]

Factorize the first two terms and the last two terms separately:

[tex]\implies u(u+9)-3(u+9)[/tex]

Factor out the common term (u + 9):

[tex]\implies (u-3)(u+9)[/tex]

Substitute back [tex]u=x^2[/tex]:

[tex]\implies (x^2-3)(x^2+9)[/tex]

Therefore, the factored form of the given polynomial is:

[tex]\implies 2x(x^2-3)(x^2+9)[/tex]

The composite function (boa)(x) is equivalent to √3x-3

Given the following functions

a(x) = 3x +1

b(x) = √x - 4

To determine the composite function (boa)(x)

b(a(x) = b(3x +1)

Substitute 3x + 1 into b(x) to have:

(boa)(x)= √(3x + 1) - 4

(boa)(x) = √3x-3

Hence the composite function (boa)(x) is equivalent to √3x-3

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Answer:

1•4

Step-by-step explanation:

1•54÷1•1

1•54

1•1

divide by 10 both side with can move decimal

15•4

11

=my answer is 1•4.

Answer:

The correct answer for algebraic expression 1.54÷1.1 is = 1.4.

Step-by-step explanation:

this is question based on simple algebra -

Simple Algebraic equations -  An algebraic equation can be defined as a mathematical statement in which two expressions are set equal to each other. The algebraic equation usually consists of a variable, coefficients and constants. we can apply many operations on algebraic equations like addition, subtraction, multiplication, division and raising to a power, and extraction of a root.

these equations are two algebraic expressions that are joined together using an equal to ( = ) sign. An algebraic equation is also known as a polynomial equation because both sides of the equal sign contain polynomials

so in the question algebraic operation used to solve is simple division.

therefore here in question we have to divide 1.54 with 1.1,

using the concept written above,

let the value of division be 'x'

we can write 1.54/1.1 = x

by dividing and multiplying the equation by 100 to remove the decimals.

            (1•54/ 1•1)×100/100    = x

                    154/110    =  x

now by simple division,

                      1.4   =  x  answer

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Answer:

7/9     ( or  7:9)

Step-by-step explanation:

Children = 35

Total people = 35 + 10 = 45

ratio Children / total people =  35/45  = 7/9

In order to evaluate consistency in studies with more than one data collector, the Inter-rater reliability is used.

This is a measure in research that is used to test the data presented by different data collectors, for consistency.

It essentially checks the extent to which the data collected from the different sources agree with each other.

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Answer:

D.All of the choice

Step-by-step explanation:

D.All of the choice

Answer:

Step-by-step explanation:

If AC is a supplementary line, then

x + 90° + x = 180°

solution:

2x + 90° = 180°   |subtract 90° from both sides

2x = 90°    |divide both sides by 2

x = 45°

Answer:

[tex] \sf \: b) \: {45}^{o} [/tex]

Step-by-step explanation:

Now we have to,

→ find the required value of x.

Forming the equation,

→ x + x + 90° = 180°

Then the value of x will be,

→ x + x + 90° = 180°

→ 2x = 180° - 90°

→ 2x = 90°

→ x = 90° ÷ 2

→ [ x = 45° ]

Hence, the value of x is 45°.

[tex]2 {x}^{5} {y}^{8} [/tex]

Step-by-step explanation:

yes

The complete question is

"Find the general solution of the given differential equation

y''-y=0, y1(t)=e^t , y2(t)=cosht

The function [tex]y(t)=e^t[/tex]  is the solution of the given differential equation.

The function y(t)=cosht is the solution of given differential equation.

The function is a type of relation, or rule, that maps one input to specific single output.

Given;

[tex]y_1(t) = e^t[/tex]

Given differential equations are,

y''-y = 0

 So that,  

[tex]y' (t) = e^t, y'' (t) = e^t[/tex]

Substitute values in the given differential equation.

[tex]e^t -e^t=0[/tex]

Therefore, the function [tex]y(t)=e^t[/tex]  is the solution of the given differential equation.

Another function;

[tex]y(t)=cosht[/tex]  

So that,  

[tex]y"(t)=sinht\\\\y"(t)=cosht[/tex]

Hence, function y(t)=cosht is solution of given differential equation.

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Answer:

700 kWh which is more than 200 so

0.10(x - 200) + 30

0.10( 700 -200)+ 30

0.10( 500) + 30

50 + 30

80

$80

Answer:

[tex]-2x^2-x[/tex]. Your answer was wrong because "x-squared" terms didn't cancel.

Step-by-step explanation:

To solve this problem, set up an equation.  We know something is supposed to be added to the expression [tex]2x^2+2x[/tex], and the result should be x. So:

[tex]2x^2+2x+(\text{ ? })=x[/tex]

We want to solve for the question mark... the unknown thing that we're adding to the original expression, in order to get x.

It is uncommon to put question marks in equations to represent quantities. Usually we use a letter. Since x is already being used in the equation, we should pick something else ... we could use "y".

[tex]2x^2+2x+(\text{ } y \text{ })=x[/tex]

...or just...

[tex]2x^2+2x+y=x[/tex]

Algebra allows us to solve the equation and find out what "y" is equivalent to.

To solve, we want to get the "y" by itself. To do so, we try to eliminate the other "terms" from the left side of the equation.

Understanding "terms" & "like terms"

Terms

"Terms" in an equation are either a number multiplied to other things, or just a single number that isn't multiplied to anything else.

For example, the various terms in our equation above are

[tex]2x^2[/tex], [tex]2x[/tex], [tex]y[/tex], [tex]x[/tex]

You might ask why the last things, which don't have a number, are considered terms.

Remember that multiplying by 1 doesn't change anything, so we could imagine each of the last two terms as being 1 times the letter.

So, we can rewrite our equation:

 [tex]2x^2+2x+1y=1x[/tex]

Like terms

"Like terms" are terms where the "other stuff the numbers are multiplied to" is the same, so for instance, the [tex]2x[/tex] and the [tex]1x[/tex] are like terms. They are like terms because, the "other stuff" that the numbers are multiplied to are "x" for both terms. Note that [tex]2x[/tex] and [tex]2x^2[/tex] are not "like terms" because the "stuff" is different:

[tex]x[/tex] is different than [tex]x^2[/tex]

"Like terms" are important because only like terms can be "combined" into a single simplified term.

Solving equations

To solve an equation, we isolate what we're solving for, y, by disconnecting the other terms from it, and simplify.

Starting with subtracting 2x from both sides of the equation:

[tex]2x^2+2x+1y=1x\\(2x^2+2x+1y)-2x=(1x)-2x[/tex]

Subtraction is the same as "adding a negative":

[tex]2x^2+2x+1y+(-2x)=1x+(-2x)[/tex]

Since all terms are now connected by addition, we can add in any order we want (because of the Commutative Property of Addition), and we can combine like terms.

Thinking just about the number parts, since [tex]1+(-2)=-1[/tex],  then [tex]1x+(-2x)=-1x[/tex].

Returning to our main equation, the right side simplifies:

[tex]2x^2+2x+1y+(-2x)=1x+(-2x)\\2x^2+2x+1y+(-2x)=-1x[/tex]

On the left side: [tex]2x[/tex] and [tex]-2x[/tex] are like terms.

Fact: [tex]2+(-2)=0[/tex]

So, [tex]2x+(-2x)=0x[/tex]

Since anything times zero is just zero, [tex]0x=0[/tex]. Furthermore, adding zero to anything doesn't change it.  So when the [tex]2x[/tex] and [tex]-2x[/tex] terms on the left side of our main equation are combined, they "disappear" (While we talked through are a lot of rules/steps to justify why that works, it is common to omit those justifications, and to just combine those like terms and make them disappear.)

So, [tex]2x^2+2x+1y+(-2x)=-1x[/tex] simplifies to:

[tex]2x^2+1y=-1x[/tex]

Similarly for the [tex]2x^2[/tex] term, we subtract from both sides:

[tex]2x^2+1y=-1x\\(2x^2+1y)-2x^2=(-1x)-2x^2\\2x^2+1y+(-2x^2)=-1x+(-2x^2)[/tex]

Combining like terms on the left, they disappear.

[tex]1y=-1x+(-2x^2)[/tex]

There are no like terms on the right.

Since the two terms on the right are added together, we can use the commutative property of addition to rearrange:

[tex]1y=-2x^2+(-1x)[/tex]

Addition of a negative can turn back into subtraction, and simplify multiplication by 1.

[tex]y=-2x^2-x[/tex]

Remembering we chose "y" as the unknown thing we wanted to know, that's why the "correct answer" is what it is.

Verifying an answer

Verifying can double check an answer, and helps explain why the answer you chose doesn't work.

To verify an answer, the original statement said add something to the expression and get a result of "x". So, let's see if the "correct answer" does:

[tex]2x^2+2x+(\text{ } ? \text{ })\\2x^2+2x+(-2x^2-x)\\2x^2+2x+(-2x^2-1x)\\2x^2+2x+(-2x^2)+(-1x)[/tex]

Combining the "x-squared" terms, completely cancels...

[tex]2x+(-1x)[/tex]

Combining the "x" terms, and simplifying...

[tex]1x\\x[/tex]

So it works.

Why isn't the answer what you chose:

[tex]2x^2+2x+(\text{ } ? \text{ })\\2x^2+2x+(-x^2-x)\\2x^2+2x+(-1x^2-1x)\\2x^2+2x+(-1x^2)+(-1x)[/tex]

Combining the x-squared terms, things don't completely cancel...

[tex]1x^2+2x+(-1x)[/tex]

Combining the x terms...

[tex]1x^2+1x\\x^2+x[/tex]

So adding the answer that you chose to the expression would not give a result of "x", which is why it is "wrong"

Answer: No it could not be ACB.

Step-by-step explanation:

Angles are named based on the vertex of the angle so this could be referred to as ∠B. The other way to name an angle is by saying the three points, However, when you say the three points the vertex must be in the middle. Hence, the answer is ∠CBA as the middle point of the angle is in the middle of the name.