If the domain of the function f(x) = 2x - 8 is {-2, 3, 5), then the range is

The system of linear equations that models this scenario is: 4s - 4w = 72 ,3s + 3w = 72

To solve this problem, we can use the formula:

distance = speed x time

Let's first find the speed of Turkey the Pigeon in still air. Let's call this speed "s". We can then use this speed to find the speed of Turkey the Pigeon with the wind and against the wind.

Against the wind:
Let's call the speed of the wind "w". So, the speed of Turkey the Pigeon against the wind would be:

s - w

With the wind:
The speed of Turkey the Pigeon with the wind would be:

s + w

Now, we can create two equations based on the distances traveled with each of these speeds.

Against the wind:
distance = speed x time
72 = (s - w) x 4
Simplifying this equation, we get:

4s - 4w = 72

With the wind:
distance = speed x time
72 = (s + w) x 3
Simplifying this equation, we get:

3s + 3w = 72

So, the system of linear equations that models this scenario is:

4s - 4w = 72
3s + 3w = 72

We can now solve for "s" and "w" using any method we prefer (substitution, elimination, etc.).

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It is to be noted that the probability of a randomly picked whole carton of grade A eggs to weight more than 850gm is 10.2%

Let W represent the weight of a fun carton of eggs chosen at random. W is distributed normally, with a mean of 840 grams and a standard variation of 7.9 grams.

The z-score for a weight of 850gms is:

z = 850 - 840 / 7.9 ≈ 127.

The standard normal probability table reveals that

P (W > 850) = P( Z > 1.27) ≈ 1-  0.8980 = 0.1020.

As a result, it is acceptable to assert that the likelihood of a randomly picked whole carton of grade A eggs weighing more than 850 grams is  10.2%.

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If 3 over 5 of the family income is spent on food, The amount spent on  food is $2118.6

If their total income is 3531 dollar and 3/5 is spend on food, we find the sum total of the amount of money spend on food by multiply the fraction or ratio to the total income the family gets monthly.

Therefore; Amount spent on food = monthly income x 3/5

It becomes $3531 x 3/5 or 3531 x 0.6

= $2118.6

It means that 2/5 of the income will be 2/5 x  $3531  = $1 412.4

$2118.6 + $1412.4 = 3531

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The coordinates of the third vertex of the triangle with vertices (0,1) and (3,4) and a line of symmetry along the y-axis are (-3,1) or (1.5, 0.5).

Let's take the point (0,1) as a reference. Its mirror image across the y-axis will have the same y-coordinate, but a negative x-coordinate. Therefore, the coordinates of the third vertex will be (-3,1).

We can also verify this by calculating the slope of the line connecting the two given vertices, which is

=> (4-1)/(3-0) = 3/3 = 1.

The line of symmetry for the triangle will be perpendicular to this line and will therefore have a slope of

=> -1/1 = -1.

The equation of the line of symmetry will be x = 1.5, which is the midpoint between the x-coordinates of the two given vertices. Thus, the x-coordinate of the third vertex will be -1.5, which when reflected across the y-axis becomes

=> -(-1.5) = 1.5.

So the coordinates of the third vertex are (1.5, y).

To find y, we can use the fact that the line connecting the two given vertices has equation

=> y = x - 1.

Therefore, the y-coordinate of the third vertex is (1.5) - 1 = 0.5.

Thus, the coordinates of the third vertex are (1.5, 0.5).

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The surface area of the composite solid is 286 square feet.

To calculate the surface area of this composite solid,

Find the areas of each individual shape and then add them up.

The rectangular prism has a surface area of,

2(11x2 + 11x2 + 2x11)

= 2(22 + 22 + 22)

= 2(66)

= 132 square feet.

The square pyramid has a base area of,

11x11 = 121 square feet.

The area of each triangular side can be found using the formula,

1/2 x base x height.

The base of each triangle is 11 feet (since it is the same as the length of the base of the pyramid), and the height of each triangle is 7 feet.
So each triangle has an area of 1/2 x 11 x 7 = 38.5 square feet.

There are four triangular sides, so the total area of the triangular sides is 4 x 38.5 = 154 square feet.

Adding the surface area of the rectangular prism and the square pyramid, we get

132 + 154 = 286 square feet.

Therefore, the correct answer is 286 square feet.

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To find the distance between objects 1 and 2 for which the net force on object 2 is zero, we need to use the equation for gravitational force:

F = G (m1m2 / d^2)
where F is the gravitational force between two objects, G is the gravitational constant, m1 and m2 are the masses of the two objects, and d is the distance between them.
Let's start by finding the mass of each object. We are given that:
mass of object 1 = 7 x mass of object 2
mass of object 1 = 4 x mass of object 3
We can use these equations to solve for the masses of the objects:
mass of object 2 = (1/7) x mass of object 1
mass of object 3 = (1/4) x mass of object 1
Now let's consider the gravitational force between objects 1 and 2. We want to find the distance at which the net force on object 2 is zero. This means that the gravitational force between the two objects must be equal and opposite to any other forces acting on object 2. Mathematically, we can express this as:
F_gravity = - F_other
where F_gravity is the gravitational force between objects 1 and 2, and F_other is the force acting on object 2 in the opposite direction.
We don't know what the other force is, but we do know that its magnitude must be equal to the gravitational force between the two objects. So we can set up an equation:
G (m1m2 / d^2) = G (m2m_other / x^2)
where x is the distance between objects 1 and 2 at which the net force on object 2 is zero.
Now we can plug in the masses we found earlier:
G (7m2 x m_other / x^2) = G (m2m_other / x^2)
Simplifying this equation, we get:
7m2 = m_other
So the other mass is equal to seven times the mass of object 2.
Now we can plug in the masses and solve for x:
G (7m2^2 / x^2) = G (m2 x 7m2 / x^2)
Simplifying this equation, we get:
x = distance between objects 1 and 2 = sqrt(7) x distance between objects 2 and 3
So the distance between objects 1 and 2 for which the net force on object 2 is zero is the square root of seven times the distance between objects 2 and 3.

To find the distance between objects 1 and 2 for which the net force on object 2 is zero, you need to consider the mass of each object and their gravitational forces.
Let's denote the mass of object 1 as M1, object 2 as M2, and object 3 as M3. According to the information given, we have:
M1 = 4M3 and M1 = 7M2.
Next, let's denote the distance between objects 1 and 2 as D12, between objects 1 and 3 as D13, and between objects 2 and 3 as D23.
For the net force on object 2 to be zero, the gravitational forces between objects 1 and 2, and objects 2 and 3 must be equal and opposite. Using the gravitational force equation:
F12 = (G * M1 * M2) / D12^2, and F23 = (G * M2 * M3) / D23^2.
Where G is the gravitational constant.
For net force on object 2 to be zero:
F12 = F23.
(G * M1 * M2) / D12^2 = (G * M2 * M3) / D23^2.
Now, substitute M1 and M3 in terms of M2:
(G * 7M2 * M2) / D12^2 = (G * M2 * (1/4) * 7M2) / D23^2.
Simplify the equation:
7 / D12^2 = (7/4) / D23^2.
Now, you would need more information such as the distance between object 1 and object 3 (D13) or other givendistances to find the exact values of D12 or D23. But with this equation, you have set up the relationship between the distances required for the net force on object 2 to be zero.

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Answer:it has many solutions

Answer:

it have the property of parallelogram ,

Answer:

[tex](2x - 1)(x + 3) = [/tex]

[tex]2 {x}^{2} + 5x - 3[/tex]

A = 2, B = 5, C = -3

Answer:

(2 × 4 × 8) + (2 × 4 × 3) = 64 + 24 = 88 in.^3

The domain of the relation in the graph is:

{-2, -1, 0, 2, 5}

A relation maps elements from one set (the domain) into elements from another set (the range).

Such that the domain is represented in the horizontal axis.

In the graph, we can see the points:

{(-2, -3), (-1, -1), (0, 3), (2, 1), (5, 2)}

The domain is the set of the first values of these points, then the domain is:

{-2, -1, 0, 2, 5}

The correct option is the first one.

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The equation of the perpendicular bisector of the line segment with endpoints (-1, -8) and (7, -2) is y = (-4/3)x - 1.

The perpendicular bisector of a line segment is the line that passes through the midpoint of the segment and is perpendicular to it. To find the midpoint of the segment with endpoints (-1, -8) and (7, -2), we can use the midpoint formula: ((x₁ + x₂)/2, (y₁ + y₂)/2)

By using given the values, we get :

((-1 + 7)/2, (-8 + (-2))/2)

= (3, -5)

So the midpoint is (3, -5).

To find the slope of the line segment connecting the two endpoints. We can use the slope formula: (y₂ - y₁)/(x₂ - x₁)

By using the given values, we get:

(-2 - (-8))/(7 - (-1))

= 6/8

= 3/4

So the slope of the line segment is 3/4.

To find the slope of the perpendicular bisector, we need to find the negative reciprocal of the slope of the line segment. The negative reciprocal of 3/4 is -4/3.

To find the equation of the line in point-slope form, we can use:

y - y₁ = m(x - x₁)

y - (-5) = (-4/3)(x - 3)

y + 5 = (-4/3)x + 4

y = (-4/3)x - 1

Therefore, the equation of the perpendicular bisector of the line segment with endpoints (-1, -8) and (7, -2) is y = (-4/3)x - 1.

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The correct statement is: reducing the number of attributes in data is a data transformation subtask.

Explanation:
- Selecting the relevant data by deciding which data sources to collect is a data preparation task, not specifically a data reduction subtask.
- Converting numeric variables into discrete representations is a form of data discretization, which is a data reduction subtask.
- Normalizing observed values between 0 and 1 is a form of data scaling, which is a data transformation subtask.
- Reducing the number of attributes in data is a form of dimensionality reduction, which is also a data transformation subtask.

1. For numerical variables, normalizing the observed values between 0 and 1 is a data transformation subtask.
2. Reducing the number of attributes in data is a data transformation subtask.
In these statements, data transformation subtasks are mentioned, which involve normalizing numeric variables between 0 and 1 and reducing the number of attributes in the data. The other two statements do not fit the context of data reduction, numeric variables, or data transformation.

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The pocket money that Sam had to start with is: £24

Let the amount of money he had at the beginning be x.

He spent 1/4 of the money on magazines. Thus:

Amount left = ³/₄x

He spent ²/₃ of what he had left on a present. Thus< he spent:

²/₃ * ³/₄x = ¹/₂x

Amount left = ³/₄x - ¹/₂x

He had £6 left. Thus:

³/₄x - ¹/₂x = 6

9x - 6x = 72

3x = 72

x = £24

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The only value of x in the interval [-3, 3] for which the function equals its average value is approximately x = 2.984.

What is integration?

Integration is a mathematical operation that is the reverse of differentiation. Integration involves finding an antiderivative or indefinite integral of a function.

To find the average value of the function f(x) = 6e^x over the interval [-3, 3], we need to evaluate the definite integral of f(x) over that interval and divide the result by the length of the interval:

Average value = (1/(3-(-3))) * ∫[−3, 3] 6e^x dx

= (1/6) * [[tex]6e^x[/tex]] from -3 to 3

= (1/6) * ([tex]6e^3[/tex] - [tex]6e^{(-3)}[/tex])

≈ 118.936

Therefore, the average value of the function over the given interval is approximately 118.936.

To find all values of x in the interval [-3, 3] for which the function equals its average value, we need to solve the equation f(x) = 118.936, which means:

[tex]6e^x[/tex] = 118.936

Dividing both sides by 6, we get:

[tex]e^x[/tex] = 19.823666...

Taking the natural logarithm of both sides, we get:

x = ln(19.823666...)

≈ 2.984

Therefore, the only value of x in the interval [-3, 3] for which the function equals its average value is approximately x = 2.984.

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For this function, A is -2/3, B is 0 and C is 2/3.

To find the critical numbers of the function f(x) = 9x + 4[tex]x^{-1}[/tex] , we need to find the values of x where the derivative of the function is equal to zero or undefined.

The derivative of f(x) is:

f'(x) = 9 - 4[tex]x^{-2}[/tex] = 9 - 4/[tex]x^{2}[/tex]

To find where the derivative is equal to zero, we set f'(x) = 0 and solve for x:

9 - 4/[tex]x^{2}[/tex]  = 0

4/[tex]x^{2}[/tex]  = 9

[tex]x^{2}[/tex] = 4/9

x = ±2/3

Therefore, the critical numbers of f(x) are x = 2/3 and x = -2/3.

To find the intervals where the function is not defined, we need to look for values of x that make the denominator of the expression 4[tex]x^{-1}[/tex]  equal to zero. In this case, the function is not defined at x = 0.

Now we need to determine the sign of the derivative in each of the intervals (−∞,A], [A,B), (B,C], and [C,∞).

For x < -2/3, f'(x) is negative because 4/[tex]x^{2}[/tex]  is positive and 9 is greater than 4/[tex]x^{2}[/tex] . Therefore, the function is decreasing on the interval (−∞,−2/3).

For −2/3 < x < 0, f'(x) is still negative because 4/[tex]x^{2}[/tex]  is positive and 9 is still greater than 4/[tex]x^{2}[/tex] . Therefore, the function is decreasing on the interval (−2/3,0).

For 0 < x < 2/3, f'(x) is positive because 4/[tex]x^{2}[/tex]  is positive and 9 is less than 4/[tex]x^{2}[/tex] . Therefore, the function is increasing on the interval (0,2/3).

For x > 2/3, f'(x) is still positive because 4/[tex]x^{2}[/tex]  is positive and 9 is still less than 4/[tex]x^{2}[/tex] . Therefore, the function is increasing on the interval (2/3,∞).

Finally, the function is not defined at x = 0, so the interval [A,B) is (−∞,0) and the interval (B,C] is (0,∞).

Therefore, we have:

A = -2/3

B = 0

C = 2/3

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The degree of the Maclaurin polynomial required for the error in the approximation of the function is 0.04443 which is less than 0.001 as required.

The Maclaurin series for sin(x) is:

[tex]sin(x) = x - (x^3 / 3!) + (x^5 / 5!) - (x^7 / 7!) + ...[/tex]

The error (E) in approximating sin(x) with its Maclaurin polynomial of degree n is given by the remainder term:

[tex]E = Rn(x) = sin(c) x^(n+1) / (n+1)![/tex]

where c is some value between 0 and x.

To find the degree of the Maclaurin polynomial required for the error in the approximation of sin(x) at x = 0.5 to be less than 0.001, we need to solve the inequality:

[tex]|Rn(0.5)| < 0.001[/tex]

[tex]|sin(c) 0.5^(n+1) / (n+1)!| < 0.001[/tex]

We can see that the maximum value of |sin(c)| is 1, so we can simplify the inequality as follows:

[tex]0.5^(n+1) / (n+1)! < 0.001[/tex]

To solve for n, we can use trial and error or a computer program to find the smallest integer value of n that satisfies the inequality. Alternatively, we can use the ratio test for the convergence of series to estimate n:

[tex]|0.5^(n+2) / (n+2)!| / |0.5^(n+1) / (n+1)!| = 0.5 / (n+2) < 1[/tex]

Solving for n, we get:

[tex]n > 1 / 0.5 - 2 = 2[/tex]

Therefore, we need a Maclaurin polynomial of degree at least 3 (n = 3) to approximate sin(x) at x = 0.5 with an error of less than 0.001. The third degree Maclaurin polynomial is:

[tex]P3(x) = x - (x^3 / 3!)[/tex]

Substituting x = 0.5, we get:

[tex]sin(0.5) = P3(0.5)[/tex]

[tex]= 0.5 - (0.5^3 / 3!)[/tex]

[tex]= 0.47917[/tex]

The error in this approximation is:

[tex]|sin(0.5) - P3(0.5)| = |0.52360 - 0.47917|[/tex]

[tex]= 0.04443[/tex]

which is less than 0.001 as required.

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The exact values of the trigonometric ratios are:

sin θ = 5/13, cos θ = 12/13, tan θ = 5/12, csc θ = 13/5, sec θ = 13/12, cot θ = 12/5.

What is trigonometry?

Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles. It is primarily concerned with the study of the six trigonometric functions: sine, cosine, tangent, cosecant, secant, and cotangent, which are defined as ratios of the sides of a right-angled triangle.

We can use the coordinates of the given point to determine the trigonometric ratios of the angle that it lies on.

Let r be the distance from the origin to the point (48, 20), which is given by the Pythagorean theorem:

[tex]r = \sqrt{(48^2 + 20^2)} = \sqrt{(2304 + 400)} = \sqrt{(2704)} = 52[/tex]

We can then use the coordinates of the point and the value of r to determine the trigonometric ratios:

sin θ = y/r = 20/52 = 5/13

cos θ = x/r = 48/52 = 12/13

tan θ = y/x = 20/48 = 5/12

csc θ = r/y = 52/20 = 13/5

sec θ = r/x = 52/48 = 13/12

cot θ = x/y = 48/20 = 12/5

Therefore, the exact values of the trigonometric ratios are:

sin θ = 5/13

cos θ = 12/13

tan θ = 5/12

csc θ = 13/5

sec θ = 13/12

cot θ = 12/5

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This study represents a descriptive statistical study.

This is because it simply presents and summarizes the data regarding the surplus/deficit of the U.S. treasury during the periods of two different presidents. The data is not being used to make any generalizations or conclusions beyond the specific time periods being analyzed. Therefore, it does not involve making any inferences or predictions about the population beyond the data presented.

Flaherty did not use statistical inference to draw conclusions about a larger population beyond the data that she collected. Instead, she used the data to paint a picture of the state of the U.S. Treasury during that time period.

Therefore, this study is an example of a descriptive statistical study because it describes the data collected without making any inferences about the population beyond the data that were collected.

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The lower bound of the interval suggests that at least 42.58% of Americans who decide not to go to college do so because they cannot afford it, while the upper bound suggests that at most 53.42% do.

What is statistics?

Statistics is a branch of mathematics that deals with the collection, analysis, interpretation, presentation, and organization of numerical data.

To calculate the confidence interval, we can use the formula:

CI = p ± z*(sqrt((p*(1-p))/n))

Where:

p = sample proportion = 0.48

n = sample size = 331

z = z-score for 90% confidence level = 1.645 (from standard normal distribution table)

Plugging in the values, we get:

CI = 0.48 ± 1.645*(sqrt((0.48*(1-0.48))/331))

CI = (0.4258, 0.5342)

To interpret the interval in context, we can say:

We are 90% confident that the true proportion of Americans who decide not to go to college because they cannot afford it is between 0.4258 and 0.5342. This means that if we were to repeat this poll multiple times, we would expect the true proportion to fall within this interval in 90% of the cases.

Therefore, the lower bound of the interval suggests that at least 42.58% of Americans who decide not to go to college do so because they cannot afford it, while the upper bound suggests that at most 53.42% do.

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The distribution of X is (6,11).

Suppose the time it takes your daughter Lizzie to eat an apple is uniformly distributed between 6 and 11 minutes.

Let X represent the time it takes Lizzie to eat an apple.

The distribution of X can be described as follows,

X ~ Uniform(6, 11) which means the time it takes Lizzie to eat an apple, represented by the random variable X, follows a uniform distribution with a minimum value of 6 minutes and a maximum value of 11 minutes. In this distribution, every time interval between 6 and 11 minutes has an equal probability of occurring.

The distribution of X which represents the time it takes Lizzie to eat an apple is uniformly distributed between 6 and 11 minutes.

Therefore, we can write X ~ Uniform(6,11).

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The y-intercept of the straight line crosses the x-axis at (3,0) and the y-axis at (0,2) is 2.

The point of the line is the x-axis at (3,0) and the y-axis at (0,2)

Using two-point line equation

[tex](y_{2} - y) = m(x_{2} - x)[/tex]

m = slope = change in y / change in x

m = 2-0/0-3

m = -2/3

(2 - y) = -2/3 (0-x)

3(2-y) = -2(-x)

6 - 3y = 2x

-3y = 2x - 6

y = -2/3 x + 2

On comparing equation with y = mx + c

c in y intercept we get c = 2

Hence y - intercept = 2

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i have no idea for answer

If Bobby is sanding only the outside of the five-sided storage chest, then the area he needs to sand is 236 ft²..

The five sided regular pentagon chest consists of 2 regular-pentagons, and 5 rectangular shape;

The area of the pentagon shape top is = 43 ft²,

So, the area of the top and bottom of the chest is = 43 + 43 = 86 ft²,

The length(height of chest) of the rectangular shape is = 6 ft,

The width(base of chest) of the rectangular shape is = 5 ft,

So, the lateral surface area of chest = 5 × (6×5),

⇒ 5 × (30)

⇒ 150 ft²,

So, the area to be sanded is = 86 + 150 = 236 ft².

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The given question is incomplete, the complete question is

Bobby is sanding a five-sided storage chest with dimensions; the area of pentagon base is 43 ft², one side of the pentagonal base is 6ft, the height of the chest is 5ft. The base is a regular pentagon;

If he sands only the outside of the chest, how much area much he sand?

The total lease cost of William would be the sum of the deposit, monthly payments, title fee, and the license fee which is found out to be $6,820.

Deposit = $1,419

Monthly payments = $219 x 24 = $5,256

Title fee = $80

License fee = $65

Total lease cost = Deposit + Monthly payments + Title fee + License fee

Total lease cost = $1,419 + $5,256 + $80 + $65

Total lease cost = $6,820

Therefore, it can be concluded, based on the provied informations and the given values, the total lease cost is found out being equal to $6,820.

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The value of k that makes the matrix defective is k = 2/3 and the matrix is defective if and only if k = 0.

(a) For the matrix to be defective, it must not be diagonalizable. We can find the eigenvalues of the matrix by solving the characteristic equation:

| 3 - λ 3 3 |

| 0 k - λ 0 |

| 0 3k - λ 3k - 5 |

(3-λ) [(k-λ)(3k-5)] - 3[3(k-λ)] = 0

Simplifying, we get:

λ³ - (9k + 8) λ² + (27k² + 15k)λ - 27k³ + 45k² = 0

To find the value of k that makes the matrix defective, we need to find a value of k for which this equation has a repeated root.

We can use the fact that the sum of the eigenvalues is equal to the trace of the matrix, which is:

3 + k + (3k - 5) = 4k - 2

Therefore, the sum of the eigenvalues is a linear function of k. If this function has a repeated root, it must have a critical point where its derivative is zero:

12k - 8 = 0

Solving for k, we get:

k = 2/3

Therefore, the value of k that makes the matrix defective is k = 2/3.

(b) For this matrix to be defective, it must have a repeated eigenvalue. The eigenvalues of this matrix are 0 and k. Therefore, the matrix is defective if and only if k = 0.

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Question:

For each of the following matrices, determine the value of the scalar k that makes the matrix defective.

(a)

| 3 3 3 |

| 3 3 3 |

| 0 k k |

(b)

|3k  -5   0|

|0    k    0|

|0     0   k|

Answer:

Step-by-step explanation:

see image

The action which best demonstrates the fairness is (c) manager hires an "older-woman" based on her "job-performance" for security position even though men have traditionally held this job.

This action demonstrates fairness because the manager made the hiring decision based on job performance, rather than on any gender or age biases.

The fact that the job was traditionally held by men, the manager recognized that the older woman was the best candidate for the position based on her qualifications and abilities.

This shows that the hiring-process was fair and unbiased, and that the manager was focused on selecting the most qualified candidate for the job, regardless of any stereotypes.

Therefore, the correct option is (c).

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The given question is incomplete, the complete question is

Which action demonstrates fairness?

(a) A referee position is opened at a sport organization but only men are told about the position since traditionally men perform the job.

(b) A man's application to work as a make-up artist at a department store is passed over even though he has more experience.

(c) A manager hires an older woman based on job performance for a security position even though men have traditionally held the job.

(d) A twenty-five-year-old with a strong Hispanic accent is told he is ineligible to apply for a public speaking position even though he is overqualified.

The relation R is not reflexive, but it is symmetric and transitive.

A homogeneous relation R over the set A, which comprises the elements x, y, and z, is known as a transitive relation. If R relates x to y and y to z, then R likewise relates x to z.

For x, y ∈ Z, xRy if and only if (x+y)² ≡ ±1.

(a) Reflexivity: For x ∈ Z, we have (x + x)² = 4x² ≡ 0 (mod 1), which is not equal to ±1. Therefore, xRx does not hold for any x ∈ Z, and R is not reflexive.

(b) Symmetry: For x, y ∈ Z, if xRy, then (x + y)² ≡ ±1. This implies that (y + x)^2 ≡ (x + y)² ≡ ±1. Therefore, yRx also holds, and R is symmetric.

(c) Transitivity: For x, y, z ∈ Z, if xRy and yRz, then (x + y)² ≡ ±1 and (y + z)² ≡ ±1. Expanding these expressions, we get:

(x + y)² ≡ ±1  =>  x² + 2xy + y² ≡ ±1

(y + z)² ≡ ±1  =>  y² + 2yz + z² ≡ ±1

Adding these two equations, we get:

x² + 2xy + y² + y² + 2yz + z² ≡ ±2

Simplifying, we get:

x² + 2xy + 2yz + z² ≡ ±2 - 2y²

Now, we need to show that (x + z)² ≡ ±1. Expanding (x + z)², we get:

(x + z)² = x² + 2xz + z²

Substituting x² + 2xy + 2yz + z² ≡ ±2 - 2y², we get:

(x + z)² ≡ 2 - 2y² + 2xz

To complete the proof, we need to show that there exists some integer k such that 2 - 2y² + 2xz - k² ≡ ±1. We can rewrite this expression as:

2xz - k² ≡ 2y² - 3 (mod 4)

Since the left-hand side is even, the right-hand side must also be even. Therefore, y² ≡ 1 (mod 4), which implies that y is odd.

Now, we can substitute y = 2m + 1 for some integer m, and simplify:

2xz - k² ≡ 8m² + 8m - 1 (mod 4)

We can rewrite the right-hand side as 4(2m² + 2m) - 1, which is congruent to -1 (mod 4). Therefore, there exists some integer k such that 2xz - k² ≡ ±1, which implies that (x + z)² ≡ ±1. Hence, xRz holds, and R is transitive.

In summary, the relation R is not reflexive, but it is symmetric and transitive.

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We can see here that values will:

c = 6

d = 2.

A square is a geometric shape with two dimensions that has four equal sides and four equal 90 degree angles. It is a particular kind of quadrilateral and a regular polygon, which means that all of its sides and angles are congruent (equal in length).

We can see that using Pythagoras Theorem, a² = c² + d²

Triangle existence theorem = c + d > a

From the question, we see that: 6 < a < 7

Thus, 36 < c² + d² < 49

c + d > 7

c = 6, d = 2

Whenever the conditions are met, many values can still fit in.

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