If the height of a cone is 7.5 cm and the radius is 2 cm, find the approximate volume of the cone.
WILL MARK BRAINLIEST AND IS WORTH 100 POINTS

Answers

Answer 1

Answer:31

Step-by-step explanation:

Answer 2
It is 31 so ur welcome

Related Questions

Part A: A store had a 20% off
Black Friday sale. One item was
originally $75. How much was it on
sale for? Part B: if that same store gave an extra 10% off for using their credit card, what’s the final cost of the item (not including tax)

Answers

Answer:

Part A: $60

Part B: $54

Step-by-step explanation:

Which inequality is best represented by the following number line?

Answers

Answer:

A

Step-by-step explanation:

Answer:

solve:

-3x+10<dividing22

-3x< 12

by a negativie flips sign

x>4

So A is correct because the because its an open circle  on number line

What number president was john quincy adams.

Answers

Answer:

6

Step-by-step explanation:

john quincy adams was the 6th president

10495 divide 530 x 48939 - 283 + 38920 =?

Answers

Answer:

1007721.54

Step-by-step explanation:

You first divide 10495 divide 530 which equals 19.8. Then you multply it by 48939 and get 969084.53. Then you add 38637 to 969084.53. Coulda just used a caculator.

1. The coordinates tell you that every 12 seconds 5 gallons of water runs from the
hose into a bucket
How many gallons of water were in the bucket after 1 second

Answers

Answer:

5/12 of a gallon

Step-by-step explanation:

5 divided by 12 is 5/12

6 1/2 divided by 3/4 in simplest form

Answers

Answer:

26/3

Step-by-step explanation:

6 1/2 divided by 3/4 = 13/2 divided by 3/4

[tex]\frac{13}{2} / \frac{3}{4}\\[/tex]

[tex]=\frac{13}{2} * \frac{4}{3}[/tex]

=[tex]\frac{26}{3}[/tex]

A baseball tournament begins with 128 teams. After each round of games, only half of the teams are left. How many teams will be left after three rounds of games?

Answers

Answer:

End of round 1:

128 ÷ 2 = 64

End of round 2:

64 ÷ 2 = 32

End of round 3:

32 ÷ 2 = 16

Step-by-step explanation:

Answer: 16

Step-by-step explanation: i think :)

The width of a rectangle is 3 inches less than its length. The perimeter is equal to 94 inches, what is the length in inches?

Answers

Answer:

l=44in

Step-by-step explanation:

Using the formula

P=2(l+w)

Solving forl

l=P

2﹣w=94

2﹣3=44in

A line passes through the points (1, 4) and (3 -4). Which is the equation of the line?

Answers

Answer:

Step-by-step explanation:

(-4 - 4)/(3 - 1)= -8/2= -4

y - 4 = -4(x - 1)

y - 4 = -4x + 4

y = -4x + 8

answer is option 1

State what additional information is required in order to know that the triangles are congruent for the reason given. If possible, write the triangle congruence statement.

refer to attachment

Answers

Answer:

SU ≅ RPΔPQR ≅ ΔUTS

Step-by-step explanation:

For SSS congruence, all three pairs of sides must be marked as congruent. That is, there needs to be 3 hash marks on sides SU and RP. (Note the order of the vertices.)

  needed: SU ≅ RP

If we label the triangles in order by hash marks, the congruence statement becomes ...

  ΔPQR ≅ ΔUTS

Anyone know how to answer this

Answers

Answer:

21

Step-by-step explanation:

The average rate of change of function f(x) from x = a to x = b is

[tex] \dfrac{f(b) - f(a)}{b - a} [/tex]

Here we have

a = -1

b = 2

f(a) = f(-1) = 1

f(b) = f(2) = 64

[tex] \dfrac{f(b) - f(a)}{b - a} = [/tex]

[tex] = \dfrac{f(2) - f(-1)}{2 - (-1)} = [/tex]

[tex] = \dfrac{64 - 1}{2 + 1} [/tex]

[tex] = \dfrac{63}{3} [/tex]

[tex] = 21 [/tex]

Twelve football teams are playing in a league. Each team played each of the other teams exactly once. How many matches were played in the league? *
1 point
a. 72
b. 66
c. 11
d. 132

Answers

Each team will play with 11 other teams. Hence each team plays 11 games. Hence a total of 11*12 =132 games but since each game involves two teams divide 132/2 = 66 so B

w^3 x w^-5
please help and please explain

Answers

= W^3+(-5)
= W^3-5
= W^-2

Answer:

 [tex]\Large \text{$ \frac{1}{w^2} $}[/tex]

Step-by-step explanation:

Given the exponential expression, [tex]\displaytext\mathsf{w^3\:\times\:w^{-5}}[/tex], where it involves the multiplication of the same base, w, with varying powers.  

Using the Product Rule of Exponents, where it states that, [tex]\displaystyle\mathsf{a^{m}\:\times\:a^{n}\:=\:a^{(m\:+\:n)}}[/tex].

Hence, we simply need to add the exponents:  

[tex]\displaytext\mathsf{w^3\:\times\:w^{-5}\:=\:w\:^{[3\:+\:(-5)]}\:=\:w^{-2}}[/tex]

Next, apply the Negative Exponent Rule, where it states that: [tex]\displaystyle\mathsf{a^{-n}\:=\:\frac{1}{a^n}}[/tex].

Transforming the negative exponent of  [tex]\displaytext\mathsf{w^{-2}}[/tex]  becomes a positive exponent by using the Negative Exponent Rule.

  [tex]\displaytext\mathsf{w^{-2}\:=\:\frac{1}{w^2}}[/tex]

Find an equation for this line?

Answers

Answer:

y = -20/5 or -4/1 + 20 for the equation

Hayley learned a total os 13 appetizer recipes over the course of three weeks of culinary school. how many weeks does she need to complete to have learned 21 appetizers ?

Answers

Answer:

5 would be the answer.

Step-by-step explanation:

13 divided by 3(weeks) = 4.3

4.3 x 5 = 21.

= 5.

At a charity fund-raiser, adult tickets were sold for $7 each and children's tickets were sold for $2 each. Write an algebraic expression for the total amount of
money raised from the sale of tickets. How much money was raised if the fundraiser fsold 246 adult tickets and 380 children's tickets?
Let a = the number of adult tickets and let c = the number of child tickets. Then, an algebraic expression for the total money raised from the sale of tickets is

Answers

Answer:

x is amount of money

c + a = 646

2c + 7a = x

2(380) + 7(246) = 2486

x = $2486

help me brainlist if you right Mona is inviting 10 friends to a party. Each friend wants 5 cookies and each box has 10 cookies. How many boxes should Moana get?​

Answers

Answer:

its 5 boxes

Step-by-step explanation:

Jack estimates that a piece of wood measures 4.5 cm. If it actually measures 4.72 cm, what is the percent error of Jack’s estimate? (Show all of your work)

Answers

Answer:

ion

Step-by-step explanation:srry

5. INDIRECT MEASUREMENT A lighthouse casts a 128-foot shadow. A nearby lamppost that

measures 5.25 feet casts an 8-foot shadow.

Write a proportion that can be used to determine the height of the lighthouse. What is the height of the lighthouse?

MGSE9-12.G.SRT 5

b. 5.25

a. 1285.25; 195 ft

X 128

8 ; 84 ft

128

c. 5.25" 8 ; 672 ft

X 128

d. 3 5.25; 195 ft

Answers

Using proportions, it is found that the height of the lighthouse is of 84 ft.

This question is solved by proportions, using a rule of three.For a height of 5.25 feet, the shadow is of 8 feet. What is the height when the shadow is of 128 feet?

The rule of three is:

5.25 feet - 8 feet

x feet - 128 feet

Applying cross multiplication:

[tex]8x = 5.25(128)[/tex]

[tex]x = \frac{5.25(128)}{8}[/tex]

[tex]x = 84[/tex]

The height of the lighthouse is of 84 ft.

A similar problem, which also uses proportions, is given at https://brainly.com/question/24372153

ANSWER QUICKLY WILL GIVE BRAINLIEST

Answers

Answer:

\sqrt(3)[cos((4\pi )/(45))+isin((4\pi )/(45))]

Step-by-step explanation:

The first one.

four more than the price ,p

Answers

What? What do you need help with?

Can Someone please help me with this Math homework? Please respond ASAP

Answers

It’s y=x+5 your welcome have a nice day

I need help with this also I had was to repost it again because someone deleted it

Answers

Answer: 8:05

Step-by-step explanation:

Answer: 8:05

Step-by-step explanation:

Alex laughed, "You're always studying, Dave." This line from the story is an example of: *


symbolism

indirect characterization

sensory details

direct characterization

Answers

The answer is symbolism

In a group of students, 50% like tea, 70% like coffee, 10% don't like both and 120 like both. By using Venn diagram, find the total number of students.​

Answers

Answer:

Since 10% like neither, then 90% must like tea(T), coffee(C) or both(B). So what % like both? That % would have to be deducted from both the tea and coffee likers to arrive at tea only (TO), coffee only (CO) and those liking both and the three would have to sum to 90%, since 10% like neither. So whatever % the 120 represents it must be deducted from both the tea and coffee likers. I don’t know how to add graphics but in equation form

50-x + 70-x + x + 10 = 100, 130-x = 100, -x = -30, X = 30%,

120/30% = 400, 50%(T)-30%(B)=20%(TO) or 80, 70%-30%=40% or 160, 30% or 120, and 10% or 40

80+160+120+40=400

Answer:

Step-by-step explanation:

  50%        70%                 10%

like tea    like coffee      don't like both

100%-10% =90%

                   like coffee,tea or both

   50%  +   70%         =120%  -   90%   =   30%

like tea + like coffee  =          -           =    like both

LIKE BOTH           30%=`120

means 1%=4

100%=400

60 millions barrels and 34% gas and 29% diesel how many barrels are there total

Answers

Answer:

31800000

Step-by-step explanation:

The Clark family bought 8 crates of eggs last week. Each crate had 12 eggs. Since then, they have eaten 28 of the eggs. How many eggs are left?

Answers

8 • 12 -28

96 - 28

68

68 eggs are left.

I need help with these two questions!! HELP

Answers

Answer:

AB and GF are skew

DH and BF are II

EF and HG are skew

ABCD and EFGH are II

Step-by-step explanation:

II is parralell or side by side.

Skew would be like intercepting with one another.

Have an awesome day! :D

plss answer it correctly...I need asap​

Answers

Answer:

sorry I cannot understand that

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

Answers

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

[tex]\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}[/tex]

Then

[tex]Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\[/tex]

Note that since

[tex]F \cap R=\varnothing[/tex], [tex]Perm(F)\cap Perm(R)\ne \varnothing[/tex]

But since

[tex]B \cap R \ne \varnothing[/tex], [tex]Perm(B)\cap Perm(R)= \varnothing[/tex]

and

[tex]B \cap F \ne \varnothing[/tex] , [tex]Perm(B)\cap Perm(F)= \varnothing[/tex]

Since

[tex]|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\[/tex]

where [tex]|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}[/tex]

and

[tex]|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}[/tex]

What we are looking for is the number of permutations of the 26 letters of the alphabet that do  not contain the strings fish, rat or bird, or

[tex]|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}[/tex]

This link contains another solved problem on permutations:

https://brainly.com/question/7951365

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Any invalid user entries should generate an appropriate message, and the user should be required to reenter the data.using System;using static System.Console;class GreenvilleRevenue{static void Main(string[] args){const int fee = 25;int lastYearsContestants;int thisYearsContestants;const int LOW = 0;const int HIGH = 30;int other = 0;int dancer = 0;int musician = 0;int singer = 0;WriteLine("**********************************");WriteLine("* The stars shine in Greenville. *");WriteLine("**********************************");WriteLine("");lastYearsContestants = getContestantsNum(message, LOW, HIGH);string[] contestant = new string[thisYearsContestants];string[] talent = new string[thisYearsContestants];getContestantsInfo(contestant, talent);for (int x = 0; x < talent.Length; ++x){if (talent[x] == "O"){++other;}else if (talent[x] == "S"){++singer;}else if (talent[x] == "D"){++dancer;}else if (talent[x] == "M"){++musician;}}Clear();WriteLine("Currently signed up, there are..");WriteLine("{0} dancers", dancer);WriteLine("{0} singers", singer);WriteLine("{0} musicians", musician);WriteLine("{0} everything else!", other);contestantByTalent(contestant, talent);Clear();contestantInfo(thisYearsContestants, lastYearsContestants, fee);}static int getContestantsNum(string message, int LOW, int HIGH){WriteLine("Please enter the number of contestants for last year.>>");string input = ReadLine();int contestantsNum = Convert.ToInt32(input);while (contestantsNum < LOW || contestantsNum > HIGH){WriteLine("Valid numbers are 0 through 30, Please try again.>>");contestantsNum = Convert.ToInt32(ReadLine());}return contestantsNum;WriteLine("Please enter the number of contestants for this year.>>");string input = ReadLine();int contestantsNum = Convert.ToInt32(input);while (contestantsNum < LOW || contestantsNum > HIGH){WriteLine("Valid numbers are 0 through 30, Please try again.>>");contestantsNum = Convert.ToInt32(ReadLine());}return contestantsNum;}static string getTalent(int contestantsNum){bool correct = false;string talentType = "";while (!correct){WriteLine("What is contestant " + contestantsNum + "'s skill? Please enter 'S' for Singer, 'D' for Dancer, 'M' for " +"Musician, 'O' for Other.>>");talentType = ReadLine().ToUpper();if (talentType == "S" || talentType == "D" || talentType == "M" || talentType == "O"){correct = true;}else{WriteLine("Please enter a valid response.>>");}}return talentType;}static void contestantByTalent(string[] contestant, string[] talent){WriteLine ("To see a list of all contestants with a specific talent, Please enter a talent code.talent codes are(S)inger, (D)ancer, (M)usician, (O)ther; altenatively, you may type (E) to exit.>>");string entry = ReadLine().ToUpper();while (entry != "E"){if (entry != "S" && entry != "D" && entry != "M" && entry != "O"){WriteLine("That wasn't a valid talent code. Valid talent codes are (S)inger, (D)ancer, (M)usician, (O)ther; altenatively, you may type (E) to exit.>>");entry = ReadLine().ToUpper();if (entry == "E")break;}for (int x = 0; x < talent.Length; ++x){if (entry == talent[x])WriteLine("Contestant " + contestant[x] + " talent " + talent[x]);}WriteLine("To see a list of all contestants with a specific talent, Please enter a talent code. talent codes are (S)inger, (D)ancer, (M)usician, (O)ther; altenatively, you may type (E) to exit.>>");entry = ReadLine().ToUpper();}}static void getContestantsInfo(string[] contestant, string[] talent){for (int x = 0; x < contestant.Length; ++x){WriteLine("What is the name for Contestant " + (x + 1) + "?");contestant[x] = ReadLine();talent[x] = getTalent(x + 1);}}static void contestantInfo (int thisYearsContestants, int lastYearsContestants, int fee){if (thisYearsContestants > lastYearsContestants * 2){WriteLine("The competition is more than twice as big this year!");WriteLine("The expected revenue for this year's competition is {0:C}", (thisYearsContestants * fee));}elseif (thisYearsContestants > lastYearsContestants && thisYearsContestants