Answer:
100 mR
Explanation:
A car travel from A to B at a speed of 30km per hour the average speed of the car the whole journey is?
Suppose a horse leans against a wall as in the figure below.
1.2 m
14 m
1
0.35 m
(0)
(a)
Calculate the force exerted on the wall assuming that force is horizontal and using the data in the schematic representation of the situation. Note that the force exerted on
the wall is equal in magnitude and opposite in direction to the force exerted on the horse, keeping it in equilibrium. The total mass of the horse and rider is 575 kg. Take the
data to be accurate to three digits.
The force the horse and the rider exerts on the wall is equal to the weight combined acting in the opposite direction:
ForceGiven Data
mass of horse and rider = 575kgForce acting on wall = ??When a body of mass rests on a surface, it exerts a force equal to the weight of the mass but opposite in direct on the mass/object
hence the force is computed as
Force = mass * acceleration
Force = 575 * 9.81
Force = 5640.75N
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A physicist would not be consulted on the design for which of the following?
O
A. Golf balls
B. Curtains
C. Aircraft
D. Solar panels
A physicist would not be consulted on the design for Curtains because there is no scientific laws are used in the making of Curtains.
What is physicist?A physicist is a scientist who specializes in the field of physics. It studies the interactions of matter and energy in the physical universe.
So we can conclude that a physicist would not be consulted on the design for Curtains because there is no scientific laws are used in the making of Curtains.
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Objects change their speed and/or direction only when
Answer:
When an external force acts upon them
1. Discuss the two ways by which volcanoes are formed.
2. Does the theory of plate tectonics answer the question on why volcanoes erupt? Support your answer.
3. What are mantle plumes and where are they usually found?
4. What are the gases released by volcanoes in smaller amounts?
5. Extinct volcanoes may be classified as inactive volcanoes but this doest not mean they will not erupt again. Explain this statement.
Answer:
1.Divergent boundaries (crust moves apart, magma fills in) Convergent boundaries (magma fills when one plate goes beneath another) Hot spots (a large magma plume rises from mantle)
2.Some mountains are made of solid rock, like the Rocky Mountains or the Swiss Alps. But, some mountains are actually volcanoes.
3.an area under the rocky outer layer of Earth, called the crust, where magma is hotter than surrounding magma.
4.hydrogen sulfide, carbon monoxide, hydrogen chloride, hydrogen fluoride, and other minor gas species.
5.Extinct volcanoes are not expected to erupt in the future. Inside an active volcano is a chamber in which molten rock, called magma, collects. Pressure builds up inside the magma chamber, causing the magma to move through channels in the rock and escape onto the planet's surface.
Explanation:
hope its help:)
Seamus made an electromagnet from an iron nail, a piece of copper wire with three coils spread out across the nail, and a AAA-
sized battery. His magnet attracts only one paper clip, and he wants to boost the power of his magnet to attract at least four paper
clips. What two things can Seamus do to accomplish his goal?
A)
B
Seamus can add batteries to decrease the voltage, and he can decrease the
space between the wire coils.
Seamus can add batteries to increase the voltage, and he can increase the
space between the wire coils,
Seamus can add batteries to increase the voltage, and he can decrease the
space between the wire coils.
Seamus can add batteries to decrease the voltage, and he can increase the
space between the wire coils
D
Seamus can add batteries to increase the voltage, and he can decrease the space between the wire coils to accomplish this goal.
What is Attraction?This is defined as any type of force that causes objects to come together and is possessed by objects such as a magnet.
In order to increase the power of the magnet it is best to increase the voltage and decrease the space of the coils so as to ensure it attracts at least four paper clips which makes option C the most appropriate choice.
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The warning tag on a lawn mower states that it produces noise at a level of 91.0 dB. What is the intensity of this sound in watts per meter squared
For a lawnmower that produces noise at a level of 91.0 dB, the intensity of this sound is mathematically given as
I=1.26*10^-3W/m^2
What is the intensity of this sound in watts per meter squared?Generally, the equation for the sound is mathematically given as
B=(10dB)log10(1/1_0)
Therefore
91/10=log(I/10^{-12})
I=1.26*10^-3W/m^2
In conclusion, the intensity
I=1.26*10^-3W/m^2
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A parachute falling to the ground.
Answer:
a parachute falling to the ground is uniform
If a lever was a meter long and the fulcrum was placed at 50mm, what would the mechanical advantage be?
Please show work if possible
Answer:
The mechanical advantage would depend on where the load force and the balancing force were placed on the stick
MA = (50 - F) / (L - 50)
Supoose the balancing force was placed at zero and the load at 75 cm
then MA = (50 - 0) / (75 - 50) = 50 / 25 = 2
or the balancing force was applied at 10 cm and the load force was applied at 60 cm then
MA = (50 - 10) / (60 - 50) = 40 / 10 = 4
Two cars collide at an intersection. One car has a mass of 1300 kg and is
moving 12 m/s to the north, while the other has a mass of 1400 kg and is
moving 11 m/s to the south. What is their combined momentum?
O A. 31,000 kg m/s south
O B. 200 kg m/s north
O C. 31,000 kg m/s north
O D. 200 kg m/s south
Answer:B
Explanation:sorry they removed my answer for some reason.
Answer: B
Explanation: Sorry these brainly trolls deleted my first one
The picture shows an object resting on a balance.
The object on the balance weighs 0.500 kilograms.
The weight of an object is given by F = mg, where g = 9.8 m/s2. With what force does the object push down on the balance?
Choose the correct answer.
9.3 kg⋅m/s2
9.3 kg⋅m/s, 2
9.8 kg⋅m/s2
9.8 kg⋅m/s, 2
4.90 kg⋅m/s2
4.90 kg⋅m/s, 2
0.500 kg⋅m/s2
0.500 kg⋅m/s, 2
Skip to navigation
Answer:
4.90kgm^-2
Explanation:
A dragster's top acceleration is 60 m/s.
If it accelerates for 3 seconds from the
starting line, how fast will it be going?
Answer:
very fast
Explanation:
A atom in its ground state contains 18 electrons. how many of these electrons are in orbital l=0 values?
A heat engine exhausts 6000 J of heat while performing 2000 J of useful work.
Determine the efficiency of the engine
Answer:
Explanation:
The efficiency can be calculated by:
[tex]\eta = \frac{Q_{E}-Q_{W}}{Q_{E}}=\frac{6000-2000}{6000}=\frac{2}{3}[/tex]
or we can say it becomes approximately 66.7%
theshold frequency ???
Answer:
The threshold frequency is defined as the minimum frequency of the incident radiation below which photoelectric emission or emission of electrons is not possible. The threshold frequency refers to the frequency of light that will cause an electron to dislodge emit from the surface of the metal.
Microphones are used to convert sound vibrations to electrical signals. In one kind of microphone, sound waves move a coil of wire up and down in a magnetic field, as shown in (Figure 1). The coil shown has a diameter of 1.4 cm and has 100 turns; the 0.010 T magnetic field points radially out from the north pole to the south.
If the microphone's emf at some instant is 10 mV , what is the speed of the coil?
The speed of coil of the microphone is 0.227 m/s
What is a Microphones?
A microphone is a device used to transmit sound energy through electrical energy. it makes use of magnetic fields whose strength is measures in Tesla
Given data
D = 1.4cm = 0.014m
N = 100
B = 0.010T
emf = 10mV
speed = dx / dt = ?
solution
emf = N dΦ / dt
Φ = BA
A = 2 pi R x
R = D / 2 = 0.014 / 2 = 0.007
emf = N d ( B 2 pi R x ) / dt
emf = N B 2 pi R dx / dt
and dx / dt = speed
speed = emf / N B 2 pi R
speed = 10 * 10 ^ -3 / ( 100 * 0.010 * 2 * 3.142 * 0.007)
speed = 10 * 10 ^ -3 / ( 0.043988 )
speed = 0.227 m/s
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ε = vLB
v - velocity = ?
ε - emf = 10mV = 0.01V
B - magnetic field = 0.010 T
L - length of wire = find
Find L
N - turns of wire = 100
d = diameter = 1.4 cm = 0.014 m
L = circumference of 1 turn of wire * # of turns of wire
L = 2πr * N
L = πdN
L = π * 0.014 m * 100
L = 1.4π m
Return to main equation
ε = vLB
[tex]v = \frac{\epsilon}{LB}[/tex]
[tex]v = \frac{0.01}{(1.4\pi)*(0.010)}[/tex]
v = 0.227 m/s
If you go into a store to buy a digital thermometer and there are 8 instruments of the same brand and model, at the same price, but they indicate different temperature values, explain which one you choose and why.
Answer: I would buy the thermometer with the most features because they all cost the same price so why not you getting more than what you are paying for than buying something the same but with less feature and things it can do for the same price.
Hope this helps :) If so brainliest would mean alot thanks!
Explanation:
A cosmic ray photon is bombarding a massive object to pieces. The detectors indicates
that two fragments, each of mass 0, depart due to such a collision each moving at
the speed of 0.6c at the angle of 600 relative to the photon’s original direction of
motion. What is the energy of the cosmic ray photon in terms 0 and c ?
Answer:
Chapter 1
1. Show that the Lorentz transformation is such that the velocity of a light ray
travelling in the x direction is the same for the observer in the frame S and for
the observer in the frame S
.
Solution: Consider a light ray travelling in the x direction. If the light ray
connects two space–time points {t1, x1} and {t2, x2}, we have
c = x2 − x1
t2 − t1
The speed of light observed in the frame S will be
c = x
2 − x
1
t
2 − t
1
= c
γ ((x2 − x1) − βc(t2 − t1))
γ (c(t2 − t1) − β(x2 − x1))
= c
x2 − x1
t2 − t2
− βc
c − β x2 − x1
t2 − t2
= c
2. What is the mean path before decay for a charged pion with a kinetic energy of
1 GeV?
Solution: The pion has a lifetime 2.6 × 10–8 s and a mass of 139.6 MeV. If the
energy is 1 GeV, the velocity of the pion is 99% of the velocity of light (Eq. 1.4).
The mean path before decay is
= 0.99 c γ τ
= 0.99 c
1000 + 139.6
139.6
2.6 10−8 = 63 m
S. Tavernier, Experimental Techniques in Nuclear and Particle Physics, 271
DOI 10.1007/978-3-642-00829-0, C Springer-Verlag Berlin Heidelberg 2010
272 Solutions to Exercises
3. Show that the relativistic expression for the kinetic energy of a particle (Eq. 1.2)
reduces to the non-relativistic expression if the velocity of the particle is small
compared to the velocity of light.
Solution:
E = Ekinetic + m0c2 = m0c2
1 − (v/c)2
≈ m0c2
(1 − 1/2(v/c)2) ≈ m0c2(1 + 1/2(v/c)
2)
= m0c2 +
1
2
m0v2
4. For a Poisson distribution with average value 16, calculate the probability to
observe 12, 16 and 20 as measured value. Calculate the probability density function for a Gaussian distribution with average value 16 and dispersion 4, for the
values x = 12, 16 and 20. Compare the results.
Solution: For a Poisson distribution P(12) = 0.0829, P(16) = 0.1024, P(20) =
0.0418
For a Gaussian distribution, f(12) = 0.0605, f(16) = 0.0997, f(20) = 0.0605
5. Consider a very short-lived particle of mass M decaying into two long-lived particles 1 and 2. Assume you can measure accurately the energies and momenta of
the two long-lived particles. How will you calculate the mass of the short-lived
particle from the known energies and momenta of the two long-lived objects?
Solution: The mass of the short-lived particle, its energy and its momentum are
related by Eq. (1.1). The energy and momentum of the particle are equal to the
sums of the energy and sums of the momenta of the decay products, therefore
M2c4 = (E1 + E2)
2 − c2(P1 + P2)
2
6. Calculate the order of magnitude of the energy levels in atoms and in nuclei
using the ‘particle in a box’ approximation, Eq. (1.9). Use for the dimension of
the atom 10–10 m and for the dimension of the nucleus 10−15 m.
Solution: Atomic energy levels: ≈40 eV; nuclear energy levels: ≈400 MeV.
7 . Show that in a β− or a β+ decay only a very small fraction of the energy derived
from the mass difference goes to the kinetic energy of the final-state nucleon.
The electron is relativistic; therefore this requires a relativistic calculation! Hint:
the 3-body problem can be reduced to a 2-body problem by considering the
electron–neutrino system as one object with a mass of a few MeV.
Solution. Consider the 2-body decay of some heavy object with mass M into
two objects with masses m1 and m2. The kinetic energy of each of the final-state
particles in the overall centre of mass system is found as follows.
Solutions to Exercises 273
Consider two particles with energy and momentum four vectors p1 and p2.
The symbol pi stands for the four-vector {Ei,cpi}. The energy E appearing in this
expression is the total energy E, i.e. the rest energy mc2 plus the kinetic energy.
The four-vector product (p1.p2) is defined as
(p1.p2) =
(
E1E2 − c2 p1 p2
)
A four-vector product is a Lorentz invariant; this quantity can be evaluated in
any reference frame, and the result is the same. Consider now the quantity
(p1.p2)
m1c2
This is a Lorentz invariant. Evaluating this expression in the rest frame of
particle 1 makes clear that this is the energy of particle 2 seen in the rest frame
of particle 1. This remains true also if one of the particles is in fact a system
of particles, for example the system of the two particles 1 and 2. The energy of
particle 2, seen in the overall centre of mass frame of the particles 1 and 2 is
therefore
E∗
2 = (p1 + p2).p2
(p1 + p2)2
We have the following relations:
(p1 + p2)
2 = M2c4
(p1.p2) = 1
2
(
(p1 + p2)
2 − (p1)
2 − (p2)
2
)
= M2c4 − m2
1c4 − m2
2c4
And therefore finally
E∗
2 = M2c4 + m2
2c4 − m2
1c4
2Mc2
Let us now apply the above relation to the decay
N∗ → N + e− + ¯νe + Q
The symbol Q represents the energy liberated in the reaction. Let us denote
by M∗ the mass of the parent nucleus, by M the mass of the final-state nucleus
and by m the mass of the electron–neutrino system. The kinetic energy of the
nucleus in the final state is given by
274 Solutions to Exercises
Ekin = M∗2c4 + M2c4 − m2c4
2M∗c2 − Mc2
= M∗2c4 + M2c4 − m2c4 − 2M∗c2Mc2
2M∗c2
= (M∗ − M)
2 c4 − m2c4
2M∗c2
=
!
mc2 + Q
The energy of the cosmic ray photon is zero. his means that the photon had insufficient energy to create new particles, and instead, it simply scattered off the massive object.
What is Einstein's energy equation?Einstein's energy equation, also known as the mass-energy equivalence, relates the energy E of an object to its mass m and the speed of light c. The equation is:
E = mc^2
where:
E is the energy of the object in joules (J)
m is the mass of the object in kilograms (kg)
c is the speed of light in meters per second (m/s)
This equation means that mass and energy are interchangeable, and that a small amount of mass can be converted into a large amount of energy. The equation is an important consequence of Einstein's theory of special relativity, and it has been confirmed by numerous experiments, including nuclear reactions and particle accelerators.
Here in the Question,
We can use the conservation of momentum and energy to solve this problem. Since the two fragments have equal mass and are moving in opposite directions at the same speed, we know they have equal and opposite momenta. Therefore, the initial momentum of the photon must also be equal and opposite to the total momentum of the fragments.
Let's call the initial momentum of the photon p and the mass of each fragment m. The total momentum of the fragments is:
p' = 2mv
where v is the speed of each fragment, which we know is 0.6c. Therefore, we can write:
p' = 2m(0.6c) = 1.2mc
By conservation of momentum, we have:
p = -p'
where the negative sign indicates that the photon is moving in the opposite direction to the fragments. Therefore:
p = -1.2mc
Now we can use conservation of energy to relate the photon's energy E to its momentum p:
E^2 = p^2c^2 + m^2c^4
Substituting the expression we found for p, we get:
E^2 = (1.2mc)^2c^2 + m^2c^4
E^2 = 1.44m^2c^4 + m^2c^4
E^2 = 1.45m^2c^4
Solving for E, we get:
E = mc^2 * sqrt(1.45)
Plugging in the values for m and c, we get:
E = (0 * 9.0 × 10^16 kg) * sqrt(1.45) = 0
Therefore, The photon from a cosmic ray has no energy. This indicates that the photon was merely scattered off the large object since it lacked the energy to produce new particles.
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In the fishbowl, the glass, water, rocks, and plastic plants are in thermal equilibrium. This situation means the temperature of the rocks is...
A point charge q = -6.0nC is located at the origin. The electric field (in N/C) vector at the point x = -8.0m, y= +1.5m is?
Answer:
Explanation:
The position between point charge q to x = -8.0 m and y = 1.5 m is:
[tex]r=\sqrt{x^{2}+y^{2}}=\sqrt{(-8)^{2}+(1.5)^{2}}=\sqrt{66.25}\approx 8.13[/tex] meter
Then the magnitude of the electric field E is:
[tex]E=\frac{1}{4\pi\epsilon_{o}} \frac{q}{r^{2}}=(9\times 10^{9}) \frac{6.0\times 10^{-9}}{66.25}\approx 0.81 N/C[/tex]
For the vector of E:
[tex]\tan\theta=\frac{1.5}{-8}=-0.1875 \rightarrow \theta = -10.61^{0}[/tex]
[tex]E_{x}=E\cos (-10.16)=(0.81)(0.984)=0.79704 N/C[/tex]
[tex]E_{y}=E\sin\theta = -0.81(0.184)=-0.14904 N/C[/tex]
[tex]\vec{E}=0.79704\hat{i}-0.14904\hat{j}[/tex] in N/C
Help pleasessssssssssssss
Sorry I had the answer but it wont let me type numbers :(.:
Any electricity-charged object creates an electric field. Walking across the carpet in wool socks can create an electric charge. This observation is evidence for which characteristics of electrical forces?
Explanation:
they generate electricity by contact
What are the Applications of electronic polarization?
Answer:
it can be used for communication, industrial application and also for instrumentation application
what are the four things that affect the resistance of a wire? A. length, diameter, material, and temperature B. weight, diameter, material, and temperature C. length, height, material, temperature D. length, weight, material, and temperature
Answer:
A. length, diameter, material, temperature
In a steam engine, steam in a cylinder expands against a piston, exerting 10 atm of external pressure. The volume of the cylinder increases by 10 L and simultaneously the steam cools, losing 3,000 kJ of energy to the surroundings. What is the change in energy of the steam
If steam in a cylinder expands against a piston, exerting 10 atm of external pressure, the change in energy of the steam is mathematically given as
dE= -3010 kJ
What is the change in energy of the steam?Generally, the equation for the workdone is mathematically given as
Work = - (pressure * Volume)
Therefore
w= - (10 x 10)
w= -100 L atm
In conclusion
dEnergy = q + work
dE = -3000 + -10.13
dE= -3010 kJ
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A sound wave has a frequency of 350 Hz and a wavelength of 2.25m. At what speed will the
sound wave move? Show your work.
Answer:
787.5m/s
Explanation:
Speed = wavelength x frequency
speed = 2.25m x 350 Hz
= 787.5m/s
The maximum kinetic energy of electrons ejected from a sheet of uranium exposed to 250 nm ultraviolet light is 1.33 EV.
What is the work function of the uranium metal? (Planck's constant (h) is 6.626 × 10-34 J∙s, c is 3.0 × 108 m/s, 1 eV = 1.6 × 10-19 J)
Answer: The maximum kinetic energy KEe of ejected electrons (photoelectrons) is given by KEe = hf − BE, where hf is the photon energy and BE is the binding energy (or work function) of the electron to the particular material.
Explanation:
The work function of the uranium metal will be given by the value 7.9*10^-19
What is work function?The work function of a particle is defined as the product of the planks constant to the frequency of the particle.
[tex]\phi=h\times f[/tex]
Now the frequency will be given as
[tex]f=\dfrac{c}{\lambda}[/tex]
So the formula will become
[tex]\phi=\dfrac{hc}{\lambda}[/tex]
h=6.626 × 10-34 J∙s
c=3.0 × 108 m/s
[tex]\lambda[/tex] = 250 nm 250* 10^-9
[tex]\phi=\dfrac{6.626\times 10^{-26}\times3\times 10^{8}}{250\times 10^{-9}}[/tex]
[tex]\phi=7.9\times 10^{-19}[/tex]
Hence the work function of the uranium metal will be given by the value 7.9*10^-19
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An electron of mass 9.11 x 10 -31 kg moves with a speed of 0.8725 c. What is its momentum?
Explanation:
momentum = mass × velocity
mass = 9.11 × 10^-31
velocity = 0.8725 multiplied by c ( which is the speed of light )
therefore velocity = 0.8725 × 3 × 10^8 = 2.6175 × 10^8 m/s
[tex]m = 9.11 \times 10 {}^{ - 31} \times 2.6175 \times 10 {}^{8} [/tex]
[tex]m = 9.11 \times 2.6175 \times 10 {}^{ - 31 + 8} [/tex]
[tex]m = 23.85 \times 10 {}^{ - 23} kgms {}^{ - 1} [/tex]
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a cup of coffee has a mass of .297 kg if you place this cup of coffee on a desk and let it sit there undisturbed how much force is the desk exerting on it
The desk is exerting a normal force of approximately 2.913 Newtons on the cup of coffee, which is also equal to 2.913 N in magnitude.
The force that the desk exerts on the cup of coffee is known as the normal force. This force counteracts the weight of the coffee cup due to gravity. The normal force is equal in magnitude and opposite in direction to the force exerted by the cup's weight.
The weight of an object is given by the equation:
Weight = mass × acceleration due to gravity
Where:
Mass = 0.297 kg (mass of the coffee cup)
Acceleration due to gravity (on the surface of the Earth) ≈ 9.81 m/s²
Weight = 0.297 kg × 9.81 m/s² ≈ 2.913 kg m/s² (Newtons)
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A ball which is dropped from the top of building strikes the ground in 2.6 sec. Assume air resistance can be ignored. The height of the building is
approximately
