If the Ksp of NaCl is experimentally determined to be 43.9, then what is the concentration of Na (in M) when it begins to crystallize out of solution

Answer:

b. radicals form easily in the presence of chlorine radicals.

Explanation:

Chlorine radicals perform the first propagation step: because "radicals form easily in the presence of chlorine radicals."

This is because the first propagation step consumes a CHLORINE RADICAL while the second propagation step regenerates a CHLORINE RADICAL. In this way, a chain reaction occurs, whereby one CHLORINE RADICAL can ultimately cause thousands of molecules of methane to be converted into chloromethane with C12 present.

Hence, in this case, the correct answer is that "radicals form easily in the presence of chlorine radicals."

Answer: Options related to your question is missing below are the missing options

a. cytochrome c is a one-electron acceptor, whereas QH2 is a two-electron donor.

b. cytochrome c is a two-electron acceptor, whereas QH2 is a one-electron donor.

c. cytochrome c is water soluble and operates between the inner and outer mitochondrial membranes

d. heart muscle has a high rate of oxidative metabolism, and therefore requires twice as much cytochrome c as QH2 for electron transfer to proceed normally.

e. two molecules of cytochrome c must first combine physically before they are catalytically active.

answer:

cytochrome c is a one-electron acceptor, whereas QH2 is a two-electron donor. ( A )

Explanation:

The overall stoichiometry of the reaction requires 2 mol of cytochrome per mole of QH2 because a cytochrome is simply a one-electron acceptor while QH2 is not a one-electron donor ( i.e. it is a two-electron donor )

An electron donor in a reaction is considered a reducing agent because it donates its electrons to another compound thereby self oxidizing itself in the process.

Explanation:

Following are the kinetic theory of gases postulates:

1) Space-volume to molecules ratio is negligible.

2)There is no force of attraction between the molecules at normal temperature and pressure. The force of attraction between the molecules build when the temperature decreases and the pressure increases.

3) There is large space between the molecules resulting in continuous motion.

4) The free movement of molecules results in collision which is perfectly elastic.

5) The molecules have kinetic energy due to random movement. But the average kinetic energy of these molecules differs with temperature.

6) Molecules exert pressure on the walls of the container.

the mass percent of sugar in this solution is 46%.

Answer:

Solution given:

mass of solute=34.5g

mass of solvent=75g

mass percent=[tex]\frac{mass\:of\:solute}{mass\:of \:solvent}*100\%[/tex]

=[tex]\bold{\frac{34.5}{75.0}*100\%=46\%}[/tex]

We know that,

[tex]mass \: solute = \frac{mass \: of \: solute}{mass \: of \: solvent} [/tex]×100

[tex] \frac{34.5}{75.0} = 0.46[/tex]

hope it helps..

Answer:

See explanation

Explanation:

We must first write the equation of the reaction as follows;

C3H8 + 5O2 ----> 3CO2 + 4H2O

Now;

We obtain the number of moles of C3H8 = 132.33g/44g/mol = 3 moles

So;

1 mole of C3H8 yields 3 moles of CO2

3 moles of C3H8 yields 3 × 3/1 = 9 moles of CO2

We obtain the number of moles of oxygen = 384.00 g/32 g/mol = 12 moles

So;

5 moles of oxygen yields 3 moles of CO2

12 moles of oxygen yields 12 × 3/5 = 7.2 moles of CO2

We can now decide on the limiting reactant to be C3H8

Therefore;

Mass of CO2 produced = 9 moles of CO2 × 44 g/mol = 396 g of CO2

Again;

1 moles of C3H8 yields 4 moles of water

3 moles of C3H8 yields 3 × 4/1 = 12 moles of water

Hence;

Mass of water = 12 moles of water × 18 g/mol = 216 g of water

In order to obtain the percentage yield from the reaction, we have;

b) Actual yield = 269.34 g

Theoretical yield = 396 g

Therefore;

% yield = actual yield/theoretical yield × 100/1

Substituting values

% yield = 269.34 g /396 g × 100

% yield = 68%

Answer:

Spontaneous processes are ones that occur quickly and have a low activation energy. - False -

Spontaneous processes always require an input of energy to overcome the activation energy, but always react quickly - False

Spontaneous processes can occur slowly, but always have a low activation- false

Spontaneous reactions can react slowly and can have a high activation energy - True

Spontaneous processes always react slowly and always have a high activation energy- False

Explanation:

A spontaneous reaction is reaction that proceeds on its own without us having to do a thing at all!

A spontaneous reaction may be fast or slow depending on the activation energy of the reaction. A spontaneous reaction having a high activation energy will be slow. However, if the spontaneous reaction has a low activation energy then it will be fast.

We have to note here that a spontaneous reaction proceeds without a prolonged input energy. Sometimes energy may be supplied to the reaction at the beginning for instance in the case of the combustion of hydrocarbons.

So, spontaneous processes are not necessarily fast. Some of them may have a very high activation energy such as in the rusting of iron hence they are slow.

Answer:

catenation

Explanation:

Carbon atoms have four electrons to share in bonding environments to get to the ideal octet. To do this, it bonds with other carbon molecules, called catenation. Catenation is the ability of an atom to bond and share electrons with other atoms of its kind.

Answer:

Time is 2.2 seconds.

Explanation:

Time:

[tex]{ \boxed{ \bf{time = \frac{distance}{speed} }}}[/tex]

Substitute into the formula:

speed = 715 km/h = 198.61 m/s

[tex]{ \tt{time = \frac{435}{198.61} }} \\ { \tt{time = 2.2 \: seconds}}[/tex]

Answer:

a. Na(s); b. Al(s); c. Zn(s)

Explanation:

Let's consider the following redox reactions.

a. ZnCl₂ (aq) + 2 Na(s) → Zn(s) + 2 NaCl(aq)

Na is oxidized because its oxidation number increases from 0 to +1 (in NaCl) whereas Zn is reduced because its oxidation number decreases from 2+ (in ZnCl₂) to 0.

b. Al(s) + FeBr₃ (aq) → AlBr₃ (aq) + Fe(s)

Al is oxidized because its oxidation number increases from 0 to +3 (in AlBr₃) whereas Fe is reduced because its oxidation number decreases from 3+ (in FeBr₃) to 0.

c. FeSO₄ (aq) + Zn(s) → Fe(s) + ZnSO₄(aq)

Zn is oxidized because its oxidation number increases from 0 to +2 (in ZnSO₄) whereas Fe is reduced because its oxidation number decreases from 2+ (in FeSO₄) to 0.

Kc = [CH4]×[H2O] / [CO]×[H2]^3

Kc = 1.078×0.878 / (0.989×0.933^3)

Kc = 0.977

The numerical value of the equilibrium constant, Kc, for the given reaction is found to be 0.977.

The Equilibrium constant may be defined as the numerical value that significantly indicated the correlation between the amounts of products and reactants present at equilibrium in a reversible chemical reaction at a definite temperature.

According to the question, the reaction is as follows:

[tex]CO +3H_2[/tex] ↔ [tex]CH_4+ H_2O[/tex].

The equilibrium concentrations are 0.989 M, 0.993 M, 1.078 M and 0.878 M, respectively.

Now, the equilibrium constant is calculated by the following formula:

             =  1.078×0.878 / (0.989×0.93[tex]3^3[/tex]).

             = 0.9464/(0.989 × 0.8121)

             =  0.977.

Therefore, the numerical value of the equilibrium constant, Kc, for the given reaction is found to be 0.977.

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#SPJ2

Answer:

59.8 g of PbSO₄.

Explanation:

The balanced equation for the reaction is given below:

Pb + PbO₂ + 2H₂SO₄ —> 2PbSO₄ + 2H₂O

Next, we shall determine the mass of PbO₂ that reacted and the mass of PbSO₄ produced from the balanced equation. This can be obtained as follow:

Molar mass of PbO₂ = 207 + (16×2)

= 207 + 32

= 239 g/mol

Mass of PbO₂ from the balanced equation = 1 × 239 = 239 g

Molar mass of PbSO₄ = 207 + 32 + (16×4)

= 207 + 32 + 64

= 303 g/mol

Mass of PbSO₄ from the balanced equation = 2 × 303 = 606 g

SUMMARY:

From the balanced equation above,

239 g of PbO₂ reacted to produce 606 g of PbSO₄.

Finally, we shall determine the mass of PbSO₄ that will be produced by the reaction of 23.6 g of PbO₂. This can be obtained as follow:

From the balanced equation above,

239 g of PbO₂ reacted to produce 606 g of PbSO₄.

Therefore, 23.6 g of PbO₂ will react to produce = (23.6 × 606) / 239 = 59.8 g of PbSO₄.

Thus, 59.8 g of PbSO₄ were obtained from the reaction.

Answer:

The atomic mass of this element would be 12 amu

Explanation:

The subatomic particles provide several bits of information about a given element.

The number of protons is equal to the atomic number of the element. For this element having 6 protons makes the atomic number 6 and makes the element Carbon.

The number of protons plus the number of neutrons equals the atomic mass of the element based upon atomic mass units (amus)

For this element 6 protons and 6 neutrons combine to make an atomic mass of 12 amus.

Lastly, the values of protons and electrons tell whether the atom is an ion or neutral. When protons equal electrons the atom is neutral. When protons are greater than neutrons the atom is a positive charge or cation. When the protons are less than the electrons the atom is a negative charge or anion. For this example the Carbon atom has 6 protons and 6 electrons making it neutral.

Answer:

Sorry but I know only what ksf stand for

Explanation:

Ksf stand for solubility product constant

Answer:

ksp stands for solubility product constant .

kf stands for molal freezing point depression constant ..

Explanation:

KSP = The solubility product constant, Ksp​, is the equilibrium constant for a solid substance dissolving in an aqueous solution. It represents the level at which a solute dissolves in solution. The more soluble a substance is, the higher the Ksp value it has .

KF = Kf is a constant for a given solvent. Kf is called the molal freezing point depression constant and represents how many degrees the freezing point of the solvent will change when 1.00 mole of a nonvolatile nonionizing (nondissociating) solute dissolves in one kilogram of solvent.

Answer:

where is the quantities?

Answer:

groups are based on how many electrons to become stable

Explanation:

Answer:

CuSO4(s) + 5H2O(l) ----> CuSO4.5H2O(s)

Explanation:

Hydration is the process by which anhydrous CuSO4 acquires molecules of water of crystalization to form the pentahydrate.

The water of crystalization becomes attached go the crystals of the CuSO4 to form the hydrated salt.

Beginning with solid anhydrous CuSO4 we have;

CuSO4(s) + 5H2O(l) ----> CuSO4.5H2O(s)

The question is incomplete, the complete question is;

Cesium-137 is radioactive and has a half life of 30. years. Calculate the activity of a 6.8 mg sample of cesium-137. Give your answer in becquerels and in curies. Round your answer to 2 significant digits Bq Ci

Answer:

See explanation

Explanation:

The formula for activity is;

R= 0.693N/t1/2

N= 6.02 ×10^23 mol × 6.8 ×10^-3g/137 g/mol = 3 × 10^19

Substituting into the formula;

R= 0.693 × 3 × 10^19/30 years

R= 6.93 ×10^17 y^-1

In Bq;

6.93 ×10^17 y^-1 × 1.00y/3.16 ×10^7 seconds

= 2.19 ×10^10 Bq

In Ci;

2.19 ×10^10 Bq/3.7 ×10^10 Bq/Ci

= 0.59 Ci

Nitrogen Dioxide

Carbon Monoxide

Iron (II) Oxide

Aluminum Oxide

DiPhosphorus Monoxide

Explanation:

here's the answer to your question

Answer:

с

Explanation:

the first quantum number of an electron gives the information about the energy level the electron is in

The information first quantum number of an electron give is the energy level the electron is in.

Quantum numbers is a set of symbols which gives idea about the position  of electron present inside an atom.

Hence first quantum number of electron gives ideal about the energy level.

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Answer: The thermal energy that would be released by 276.0g of sodium acetate trihydrate is 71.8kJ.

Explanation:

Supercooling is the process of lowering the temperature a liquid below its freezing point, without it becoming solid. A liquid below its freezing point will crystallize in the presence of a seed crystal because it serves as a structure for formation of crystals. From the question,

The given mass of sodium acetate trihydrate

(CH3COONa.3H2O)= 276.0g

Molar mass of sodium acetate

trihydrate= 136.08g/mol

Thermal heat of fusion of sodium acetate

trihydrate = 35.9 kJ/mol

From the given mass the number of moles present= 276.0/ 136.08

= 2.0moles

Therefore the heat (thermal) energy of the given mass of sodium acetate

trihydrate = 2.0 × 35.9

= 71.8kJ

Therefore, upon addition of a small seed crystal, the solution temperature increases as sodium acetate trihydrate crystallizes.

Answer:

acetone, (CH3)2CO cyclohexane are the compound that possesses a permanent dipole

Explanation:

Permanent dipole describes the partial charge separation that can occur within a molecule along with the bond dat form between 2 different atoms

Answer:

See explanation

Explanation:

The equation of the reaction is;

C3H8 + 5O2 ----> 3CO2 + 4H2O

Number of moles of C3H8 = 132.33g/44g/mol = 3 moles

1 mole of C3H8 yields 3 moles of CO2

3 moles of C3H8 yields 3 × 3/1 = 9 moles of CO2

Number of moles of oxygen = 384.00 g/32 g/mol = 12 moles

5 moles of oxygen yields 3 moles of CO2

12 moles of oxygen yields 12 × 3/5 = 7.2 moles of CO2

Hence C3H8 is the limiting reactant.

Mass of CO2 produced = 9 moles of CO2 × 44 g/mol = 396 g of CO2

1 moles of C3H8 yields 4 moles of water

3 moles of C3H8 yields 3 × 4/1 = 12 moles of water

Mass of water = 12 moles of water × 18 g/mol = 216 g of water

b) Actual yield = 269.34 g

Theoretical yield = 396 g

% yield = actual yield/theoretical yield × 100/1

% yield = 269.34 g /396 g × 100

% yield = 68%

Answer:

[tex]\gamma=1.125[/tex]

Explanation:

From the question we are told that:

Initial Heat [tex]Q_1=800kJ[/tex]

initial Temperature [tex]T_1=10.0K[/tex]

Final Heat [tex]Q_2=800kJ[/tex]

Final Temperature [tex]T_2=10.0K[/tex]

Generally the equation for Adiabatic constant is mathematically given by

[tex]\gamma=\frac{Cp}{Cv}[/tex]

Since

Equation for Heat [tex]dQ=nCdT[/tex]

Where

[tex]n_1=n_2\\\\T_1=T_2[/tex]

Therefore

[tex]Q_1=Cv\\\\Cv=800[/tex]

And

[tex]Cp=900[/tex]

Therefore

[tex]\gamma=\frac{900}{800}\\\\\gamma=\frac{9}{8}[/tex]

[tex]\gamma=1.125[/tex]

Answer:

"[tex]6.7\times 10^{-4} \ atm[/tex]" is the right answer.

Explanation:

Given:

Partial pressure of [tex]N_2[/tex],

= 0.20 atm

Partial pressure of [tex]H_2[/tex],

= 0.15 atm

[tex]K_p = 1.5\times 10^3[/tex] at [tex]400^{\circ} C[/tex]

As we know,

⇒ [tex]K_p = \frac{pN_2\times pH_2^3}{pNH_3^2}[/tex]

By putting the values, we get

    [tex]1.5\times 10^3=\frac{0.20\times (0.15)^3}{pNH_3^2}[/tex]

        [tex]pNH_3^2 = \frac{0.000675}{1.5\times 10^3}[/tex]

                    [tex]=6.7\times 10^{-4} \ atm[/tex]

Answer:

water, when the metastable state is reached, is cooled below the zero temperature. It freezes abruptly. this is called metastable. They are not at equilibrium per se; as at negative temperatures the only equilibrium state of water is ice.

Explanation:

Answer:

Mn2+(aq) + 2H2O(l)  ⇒ MnO2(s) + 4H+(aq) + 2e-

Explanation:

Step 1: Data given

The oxidation number of manganese ion (Mn2+ ) is +2

The oxidation number of manganese dioxide  is +(MnO2)4

This means the oxidation number from Mn will go from +2 to +4, since it's increased, this is an oxidation reaction

Mn2+(aq)  ⇒ MnO2(s)

We have to balance both sides. Mn is already the same. But on the right side we have O atoms. T obalance both sides we have to add O atoms to the left side. This by adding 2x H2O

Mn2+(aq) + 2H2O(l)  ⇒ MnO2(s)

Now the amount of O atoms is balanced, but we have H- atoms at the left side. To balance we have to add 4 H atoms to the right side

Mn2+(aq) + 2H2O(l)  ⇒ MnO2(s) + 4H+(aq)

Now the amount of atoms is balanced at both sides. We also have to check if the charge on both sides is the same.

Since the left side has a charge of +2, and right has a charge of +4, we have to add 2 electrons to balance this.

Mn2+(aq) + 2H2O(l)  ⇒ MnO2(s) + 4H+(aq) + 2e-