The wavelength of radio waves with a frequency of 93.5 MHz is equal to 3.2 meters
What is wavelength?Wavelength is a measure of the distance between two consecutive points in a wave. It is determined by the speed of the wave and its frequency, which is the number of waves that pass a point in a given period of time. Wavelength is usually measured in meters, and is sometimes expressed as the number of waves that pass a point in one second. Wavelengths can range from fractions of a nanometer to many kilometers.
The wavelength of radio waves is calculated using the following formula: wavelength (λ) = velocity (c) / frequency (f).
The velocity of radio waves in air is approximately 300,000,000 m/s.
Therefore, the wavelength of radio waves with a frequency of 93.5 MHz is equal to:
λ = 300,000,000 / 93,500,000 = 3.2 meters
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Help! Rate constant k=0.23 /s in a first order reaction
The concentration at t = 300 s is 1.1 * 10^-30 M
What is the rate constant?The rate constant, also known as the reaction rate constant, is a constant of proportionality that relates the rate of a chemical reaction to the concentration of reactants. It is a measure of the speed at which a chemical reaction occurs and is dependent on temperature, pressure, and other physical and chemical factors.
The rate constant is represented by the symbol "k" and is usually expressed in units of reciprocal time, such as per second (s^-1).
We know that for the first order reaction;
ln[A] =ln [A]o - kt
[A] = final concentration at time t
[A]o = Initial concentration
k = rate constant
t = time taken
ln[A] = ln1 - 0.23 * 300
ln[A] = -ln69
[A] = e^-69
= 1.1 * 10^-30 M
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Determine the volume in milliliters of a rock that weighs 52.0 g and has a density of 19.4 g/ml. (6 points)
Taking into account the definition of density, the volume of a rock that weighs 52.0 g and has a density of 19.4 g/mL is 2.68 mL.
Definition of densityDensity is defined as the property of matter, whether solid, liquid or gas, that allows to measure the amount of mass in a certain volume of a substance.
The expression for its calculation is the quotient between the mass of a body and the volume it occupies:
denstiy= mass÷ volume
VolumeIn this case, you know that:
Density= 19.4 g/mLMass= 52 gVolume= ?Replacing in the definition of density:
19.4 g/mL= 52 g÷ volume
Solving:
19.4 g/mL× volume= 52 g
volume= 52 g÷ 19.4 g/mL
volume= 2.68 mL
In summary, the volume is 2.68 mL.
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Lab: Measuring pH Table or
Lab Report please ( just link it )
There are two ways to measure pH: calorimetrically with indicator fluids or sheets and electrochemically with electrodes and a millivoltmeter for greater accuracy (pH meter).
A pH lab report is what?The pH scale is used to indicate how basic or acidic a solution is (pH stands for potential of hydrogen). The pH scale gauges a substance's acidity or basicity. It falls between 0 and 14. Seven is the neutral pH.
How is pH calculated?The pH scale is a useful tool for illustrating how basic or acidic a solution is. By using the negative logarithm of the hydronium ion concentration, or pH = -log[H3O+], we may determine the pH of a solution.
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Answer: here’s mine :)
Predicting Products in Precipitation Reactions:
Given the following compounds, predict what the reaction products would be?
Ie: potassium sulfate and barium nitrate
K2SO4 + Ba(NO3)2 KNO3 + BaSO4 (not balanced) BaSO4 is a precipitate
- Lithium chloride and silver hydroxide
-Sodium iodide and silver nitrate
-Calcium hydroxide and potassium carbonate
In precipitation reaction, two reactants in aqueous solution form an insoluble product, or precipitate, that separates from the solution.
What do you mean by precipitation reaction?
Precipitation reactions are chemical reactions in which two or more aqueous solutions react to produce an insoluble product, known as a precipitate. Precipitation reactions can occur between two ionic compounds, or between an ionic compound and a molecular compound.
The reaction products would be:
LiCl + AgOH → LiOH + AgCl
NaI + AgNO3 → AgI + NaNO3
Ca(OH)2 + K2CO3 → KOH + CaCO3
The products of these reactions are the insoluble compound formed, often referred to as the precipitate, and the two aqueous solutions that remain after the reaction has taken place. Examples of common precipitation reactions include those involving two salts, such as silver nitrate and sodium chloride, which form silver chloride, and the reaction between lead nitrate and potassium iodide, which form lead iodide.
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An aqueous solution containing 35.3 g of an unknown molecular (non-electrolyte) compound in 148.5 g of water was found to have a freezing point of -1.2°C.
Calculate the molar mass of the unknown compound.
The molar mass is 370 g/mol.
What is the freezing point?The freezing point is the temperature at which a substance changes from a liquid to a solid state. This change of state occurs when the thermal energy of the substance decreases to the point where the molecules can no longer move freely and instead become organized in a fixed, solid structure.
We know that;
ΔT = K m i
ΔT = Freezing point depression
K = freezing constant
m = molality
i = Van't Hoff factor
Thus;
Molality = 35.3/M/148.5 * 10^-3
Where M is the molar mass
Then;
ΔT = Freezing point of pure solvent - Solution
= 0 - (-1.2°C) = 1.2°C
Thus;
1.2 = 1.86 * 35.3/0.148 M * 1
1.2 * 0.148 M = 1.86 * 35.3
M = 1.86 * 35.3/1.2 * 0.148
M = 65.658/0.1776
M = 370 g/mol
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When a pot of water is put on a stove, the water at the surface gets hot primarily by.
When a pot of water is put on a stove, the water at the surface gets hot primarily by conduction.
When a pot of water is put on a stove, the water at the surface gets hot primarily by conduction.
Conduction is the transfer of heat through a material by direct contact. When the pot is heated on the stove, the metal of the pot gets hot, and this heat is conducted to the water molecules in contact with the pot. These water molecules then transfer the heat to neighboring water molecules through conduction, and so on. As a result, the heat gradually spreads throughout the pot and heats up the water.
It's important to note that convection also plays a role in heating the water in a pot. As the water near the bottom of the pot gets heated, it becomes less dense and rises to the top, while cooler water near the top sinks to the bottom to replace it. This movement of water, called convection, helps to distribute the heat more evenly throughout the pot. However, in the initial stages of heating, when the water is still and has not yet started to convect, conduction is the primary mechanism by which the surface water gets heated.
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Analysis of a 5.68-g sample of ZnS contains 3.80 g of Zn. Calculate the mass of Zn that can be obtained from 7.53 kg of Zns.
a.5.65 kg
b.5.04 kg
c.3.73 kg
d.2.87 kg
If a 5.68-g sample of ZnS contains 3.80 g of Zn then the mass of Zn that can be obtained from 7.53 kg of Zns. is 5.04kg so correct option is
(b) 5.04kg.
With the provided data, we can first determine the mass percent content of zinc in ZnS:
(Mass of Zn / Mass of ZnS) times 100% Equals mass percent of Zn
3.80 g / 5.68 g x 100%, where mass percent of Zn
Zn mass percentage is 66.9%.
This indicates that zinc accounts for 66.9% of the mass of ZnS. This number can be used to determine how much Zn can be extracted from 7.53 kg of ZnS:
mass of Zn from 7.53 kg of ZnS is equal to (66.9 / 100) × 7.53 kg, or 5.04 kg.
As a result, 5.04 kg of Zn can be extracted from 7.53 kg of ZnS. 5.04 kg is the correct answer (b).
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A sample of aluminum with mass of 53.2 g is initially at
155 °C. What is the temperature of the aluminum after it
en loses 2.87 x 10³ J?
Answer:
the final temperature of the aluminum after losing 2.87 x 10^3 J of heat is approximately 91.3 °C.
Explanation:
The relationship between heat, mass, and temperature change can be described by the formula:
Q = mcΔT
where Q is the heat transferred (in joules), m is the mass of the sample (in kilograms), c is the specific heat capacity of aluminum (about 0.9 J/g°C), and ΔT is the change in temperature (in degrees Celsius).
Rearranging the equation to solve for ΔT, we get:
ΔT = Q / (mc)
First, we need to convert the mass from grams to kilograms:
m = 53.2 g / 1000 g/kg = 0.0532 kg
Next, we can plug in the values for Q, m, and c and solve for ΔT:
ΔT = (2.87 x 10^3 J) / (0.0532 kg * 0.9 J/g°C) = approximately 63.7 °C
Finally, we can subtract the ΔT from the initial temperature to find the final temperature:
T_final = 155 °C - 63.7 °C = 91.3 °C
There are three sets of sketches below, showing the same pure molecular compound (hydrogen chloride, molecular formula HCl) at three different temperatures. The sketches are drawn as if a sample of hydrogen chloride were under a microscope so powerful that individual atoms could be seen. Only one sketch in each set is correct. Use the slider to choose the correct sketch in each set. You may need the following information: melting point of HCl: -114.8 °C boiling point of HCl: -85.1 °C C A DODODODO 5 3. C -124. "C -105. C ? X
As per the temperature, the molecules of a substance act differently. The melting point is -114.2 °C and The boiling point of hydrogen chloride (HCl) is -85.05 °C. The correct sketch in each set is as follows:
Thus, if the temperature is kept above -85.05 °C, the molecules will be placed widely apart and will be in the gaseous state, revealing their properties.
If the temperature is between -114.2 °C and -85.05 °C, the molecules will be organized in layers capable of slipping over one another since they will be in a liquid state.
At last, the molecules will be arranged in an orderly manner because they will be in a solid state if the temperature is below -114.2 °C.
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Describe some common chemical properties of matter?
Answer:
Some are Oxidation, Reduction, Combustion and electronegativity
Explanation:
To what volume should you dilute 0.20L of a 15.0M NaOH solution to obtain a 3.00M NaOH?
Answer: 1 L
Explanation: M1V1 = M2V2
Given :
M1 =15 M
V1=0.2 L
M2=3 M
V 2= ?
15 × 0.2 = 3V2
Thus, V 2=1 L
PLEASE HELP
Calculate the number of oxygen atoms in a 120.0 g sample of forsterite (Mg2SiO4).
Be sure your answer has a unit symbol if necessary, and round it to 4 significant digits.
Answer:
The molar mass of Mg2SiO4 can be calculated by adding the atomic masses of each element:
Mg: 2 x 24.31 g/mol = 48.62 g/mol
Si: 1 x 28.09 g/mol = 28.09 g/mol
O: 4 x 16.00 g/mol = 64.00 g/mol
Molar mass of Mg2SiO4 = 48.62 + 28.09 + 64.00 = 140.71 g/mol
To calculate the number of oxygen atoms in a 120.0 g sample of forsterite, we first need to calculate the number of moles of Mg2SiO4 in the sample:
n = mass / molar mass = 120.0 g / 140.71 g/mol = 0.853 mol
Next, we can use the molecular formula to determine the number of oxygen atoms in one mole of Mg2SiO4:
Mg2SiO4 has 4 oxygen atoms per molecule, so one mole of Mg2SiO4 has 4 moles of oxygen atoms.
Therefore, the number of oxygen atoms in 0.853 mol of Mg2SiO4 is:
0.853 mol Mg2SiO4 x 4 mol O / 1 mol Mg2SiO4 = 3.412 mol O
Finally, we can convert the number of oxygen atoms to a more convenient unit, such as atoms. One mole of oxygen atoms contains 6.022 x 10^23 atoms, so the total number of oxygen atoms in 0.853 mol of Mg2SiO4 is:
3.412 mol O x 6.022 x 10^23 atoms/mol = 2.055 x 10^24 atoms of oxygen
Rounding this result to 4 significant digits, we get:
2.055 x 10^24 atoms of oxygen (to 4 significant digits)
Explanation:
How many moles of nitrogen gas are produced when 36. 0 g of NH4NO3 reacts?
[tex]0.225 moles[/tex] of nitrogen gas are produced when[tex]36.0 g[/tex] of NH4NO3 reacts.
The reaction for the decomposition of ammonia nitrate (NH4NO3) is given by:
NH4NO3 → N2 + 2H2O
The number of moles of nitrogen gas (N2) produced when 36.0 g of NH4NO3 reacts can be determined using the following steps:
1. Calculate the molar mass of NH4NO3.
[tex]Molar mass of NH4NO3 = (1 *14.007 g/mol) + (4 *1.008 g/mol) + (3 * 14.007 g/mol) \\ = 80.042 g/mol[/tex]
2. Calculate the number of moles of NH4NO3 present in the given mass.
Number of moles =[tex]\farc{Mass}{Molar mass}\\ = \frac{36.0 g}{80.042 g/mol}\\ = 0.45 moles[/tex]
3. Calculate the number of moles of nitrogen gas produced.
Number of moles of N2 produced = [tex]\frac{0.45 moles}{2 }= 0.225 moles[/tex]
Therefore,36.0 g of NH4NO3 react with oxygen to generate g of nitrogen gas [tex]0.225 moles[/tex].
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Can vitamins be a source of energy for muscle work?
Answer:
No
Explanation:
Vitamins cannot be a direct source of energy for muscle work. Vitamins play important roles in various metabolic processes, but they do not provide energy directly. Energy is primarily provided by the breakdown of carbohydrates, fats, and proteins. Vitamins are essential for the proper functioning of these metabolic processes and for the release of energy from these macronutrients.
Answer:
Vitamins are not a reliable source of immediate energy for working muscles. Vitamins are necessary for optimum health and for supplying energy for many metabolic processes, however they do not directly provide energy to muscles. The breakdown of glucose or glycogen, which is stored in muscle cells, is the main source of energy for muscle action. Although they are not an energy source in themselves, vitamins are essential for supporting the metabolic processes that turn glucose and glycogen into energy. Vitamin consumption must remain adequate to sustain healthy energy metabolism and overall health, but vitamins cannot take the place of the need for carbohydrates and other meals high in energy to power physical activity.
Hope it helps! : )Explanation:
when 12.0 g of hydrogen reacts with oxygen, how many grams of water are produced?
Answer:
12.0 grams of hydrogen would produce 12.0 grams of water.
Explanation:
The reaction between hydrogen and oxygen to form water can be represented as follows:
2H2(g) + O2(g) -> 2H2O(l)
From the equation, it can be seen that for every 2 grams of hydrogen, 1 gram of oxygen is required to produce 2 grams of water. Therefore, if 12.0 grams of hydrogen reacts with oxygen, 12.0/2 = 6.0 grams of oxygen would be required. This amount of oxygen would produce 2 * 6.0 = 12.0 grams of water.
Answer:
Explanation:
the grams of water produced= 44 grames
2B.1 (b) When 178J of energy is supplied as heat to 1.9 mol of gas molecules,
the temperature of the sample increases by 1.78 K. Calculate the molar heat
capacities at constant volume and constant pressure of the gas.
The molar heat capacity at constant volume of the gas is 100 J/mol·K, and the molar heat capacity at constant pressure of the gas is 108.31 J/mol·K.
What is molar heat capacity?
Molar heat capacity, also known as specific heat capacity, is the amount of heat required to raise the temperature of one mole of a substance by one degree Celsius (or Kelvin). The molar heat capacity is expressed in units of joules per mole per kelvin (J/mol·K).
The molar heat capacities at constant volume (Cv) and constant pressure (Cp) can be calculated using the following equations:
Cv = ΔQ/ΔT (at constant volume)
Cp = ΔQ/ΔT (at constant pressure)
where ΔQ is the heat absorbed by the gas and ΔT is the change in temperature.
In this case, ΔQ = 178 J and ΔT = 1.78 K.
At constant volume, the heat absorbed by the gas will cause an increase in the internal energy of the gas, so only the Cv can be calculated.
Cv = ΔQ/ΔT = 178 J / 1.78 K = 100 J/mol·K
At constant pressure, the heat absorbed by the gas will cause an increase in both the internal energy and the pressure-volume work done by the gas, so Cp can be calculated. The relationship between Cp and Cv is given by:
Cp = Cv + R
where R is the universal gas constant (8.31 J/mol·K).
Cp = Cv + R = 100 J/mol·K + 8.31 J/mol·K = 108.31 J/mol·K
Therefore, the molar heat capacity at constant volume of the gas is 100 J/mol·K, and the molar heat capacity at constant pressure of the gas is 108.31 J/mol·K.
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The weight of a millimole of (NH4)2HPO4 is
The molar mass of (NH4)2HPO4 ( N H 4 ) 2 H P O 4 is 132.06 grams per mole.
What is the weight of a millimole of NH4 2HPO4?The millimole is 1/1000 of a mole. The mass in grams of a millimole is the millimolar mass (mM)= 1/1000 of the molar mass. The canine mass M of a substance is the mass in grams NH4 2HPO4 of 1 mole of that material. (M: 106.1 g/mol) that are carried in 2.00 g of pure sodium carbonate.
The formula weight of the amalgam, Al2(SO4)3 . ... The weight of a millimole of (NH4)2HPO4 is: (a) 132 g: (b) 114 g: (c) 1.14 x 10-3 g: (d) 0.132 g .(NH4)2HPO4 subatomic weight. The molar mass of (NH4)2HPO4 = 132.056221 g/mol. Convert grams (NH4)2HPO4 to moles or moles (NH4)2HPO4 to grams.
So we can conclude that A fusion of NH4NO3 and (NH4)2HPO4 contains 30.40 % mass percent of nitrogen.
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Why is phenacetin more polar than aspirin?
Phenacetin is more polar than aspirin because of its molecular structure. Phenacetin has a polar functional group, the acetamide group (-CONH2), which makes the molecule more polar overall. This group has a positive charge on the nitrogen atom and a negative charge on the oxygen atom, making it a dipole, or a molecule with a positive and negative end.
In contrast, aspirin has a non-polar functional group, the acetyl group (-COCH3), which does not have a dipole moment. This makes aspirin less polar overall.
The polarity of a molecule affects its solubility in different solvents. Polar molecules are soluble in polar solvents, such as water, while non-polar molecules are soluble in non-polar solvents, such as oil. Phenacetin is more soluble in water because of its polar functional group, while aspirin is less soluble in water because of its non-polar functional group.
In summary, phenacetin is more polar than aspirin because it has a polar functional group, the acetamide group, while aspirin has a non-polar functional group, the acetyl group. This difference in polarity affects the solubility of the two molecules in different solvents.
Predict the missing component in the nuclear equation.
Since what we have is an alpha decay, the missing component is 234/90 Th
What is Alpha decay?Alpha decay is a type of radioactive decay in which an atomic nucleus emits an alpha particle, which is a helium nucleus consisting of two protons and two neutrons. During alpha decay, the atomic number of the parent nucleus decreases by two, and the mass number decreases by four.
Apha particles can be stopped by a thin layer of material such as paper or skin, and they do not penetrate very far into matter.
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An ___________________ that is useful for living in one type of ______________ may be useless in a different environment.
Organisms must live in a place that has the conditions they need to _____________
Organisms generally have adaptations that allow them to survive in one particular ______________.
An adaptation that is useful for living in one type of environment may be useless in a different environment. Organisms must live in a place that has the conditions they need to survive. Organisms generally have adaptations that allow them to survive in one particular enviroment.
What do adaptations in a particular enviroment mean?The expression adaptations in a particular enviroment mean that these traits are only advantageous regarding the enviroment.
Therefore, with this data, we can see that the adaptations in a particular enviroment can be detrimental or beneficial depending on the enviroment.
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if u coated the surface of a penny with a thin layer of a nonpolar liquid (oil) and then dropped alcohol and water onto the penny what would occur
When water is carefully dropped onto the surface of a penny, it can form a dome before spilling over the small lip around the penny's perimeter. Rubbing alcohol can also accumulate, but it will spill before forming a well-rounded dome.
What caused the water to spill over the penny?Cohesive forces are powerful, but not invincible. The force of gravity on the water molecules will eventually overcome the cohesive forces as a water drop builds up and out, usually bulging over the sides of the penny. The "skin" will rupture, allowing all the water to escape.
When the drops of water you add to the penny reach the penny's edge, the cohesion and surface tension of water become apparent.
Thus, When the water reaches the edge, a bubble or dome of water begins to form on top of the penny.
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A student wishes to prepare 500-mL of a 0.235 M chromium(II) nitrate solution using solid chromium(II) nitrate, a 500-mL volumetric flask, and deionized water.
(a) How many grams of chromium(II) nitrate must the student weigh out?
? g
(b) Which of the following would NOT be an expected step in the procedure used by the student?
A)Carefully weigh the flask.
B)Stopper the flask and invert it to mix the contents.
C)Add a small amount of water to the volumetric flask and swirl until the salt sample has dissolved.
The student needs to weigh out 18.055 g of chromium(II) nitrate.
What is mass?
Mass is a measure of the amount of matter in an object, typically measured in units of kilograms (kg), grams (g), or milligrams (mg). It is a scalar quantity, meaning it has magnitude but no direction.
(a) To prepare a 0.235 M solution of chromium(II) nitrate in 500 mL of water, we need to calculate the amount of chromium(II) nitrate that needs to be weighed out.
The formula weight of chromium(II) nitrate is Cr(NO3)2. Using the periodic table, we can find the atomic weights of the elements in this compound:
Cr: 52
N: 14
O: 16
So, the formula weight of chromium(II) nitrate is:
52 + 2(14 + 3(16)) = 154 g/mol
To prepare a 0.235 M solution, we need 0.235 moles of chromium(II) nitrate in 1 liter (1000 mL) of solution. In 500 mL of solution, we need:
0.235 moles/L x 0.5 L = 0.1175 moles
The mass of chromium(II) nitrate that contains 0.1175 moles can be calculated using the formula:
mass = moles x formula weight
mass = 0.1175 mol x 154 g/mol = 18.055 g
Therefore, the student needs to weigh out 18.055 g of chromium(II) nitrate.
(b) Option C, "Add a small amount of water to the volumetric flask and swirl until the salt sample has dissolved," would not be an expected step in the procedure used by the student. When preparing a solution in a volumetric flask, it is important to first add a portion of the solvent (in this case, water) to the flask, and then add the solute (chromium(II) nitrate) and mix it thoroughly to dissolve it. This is to ensure that the final volume of the solution is accurate, since the volumetric flask is calibrated to contain a specific volume of liquid only when filled to the mark after adding the solute.
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How does charge change with dielectric?
On changing dielectric, charge changes directly. It is directly proportional to dielectric permittivity of free space.
In electromagnetism, a dielectric (or dielectric medium) is an electrical insulator that can be captivated by an applied electric field. At the point when a dielectric material is put in an electric field, electric charges don't course through the material as they do in an electrical conduit, since they have no inexactly bound, or free, electrons that might float through the material, however rather they shift, just somewhat, from their typical balance positions, causing dielectric polarization.
Due to dielectric polarization, positive charges are dislodged toward the field and negative charges change in the course inverse to the field (for instance, assuming that the field is moving lined up with the positive x hub, the negative charges will change in the negative x course). This makes an inside electric field that decreases the general field inside the actual dielectric. Assuming a dielectric is made out of pitifully reinforced particles, those atoms become energized.
We know that Q=CV where Q is charge, C is capacitance and V is the voltage of capacitor.
Since, capacitance is equal to= (∈A₀) /d where ∈ is permittivity of free space or dielectric value.
If we increase dielectric value, capacitance will increase. When capacitance increase ,charge will also increase.
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NaBr(aq) + F2(g) ->NaF(aq)+Br2(g)
Single Replacement
Synthesis
O Double Replacement
Decomposition
Combustion
O Acid/Base Neutralization
Answer: Single Replacement
Explanation:
This is single replacement because the Fluorine replaces Bromine in the Sodium Bromide solution. This happens because Fluorine is higher on the halogens activity series.
What is the molecular formula of a compound with the empirical formula sf5 and a formula mass of 254. 1 amu?.
Molecular formula S₂F₁₀ for the compound with the empirical formula SF₅ and formula weight 254.1 a.m.u.
Molecular formula for a compound with the empirical formula CH₂O and formula weight 180.156 a.m.u: C₆H₁₂O₆.
Molecular Formula:
Molecular formulas use subscripts that give the actual number of atoms of each type in the molecule of a compound. The molecular formula is related to the molecular weight in grams, which is a simple integer multiple of the mass of the corresponding empirical formula.
Empirical Formula:
The empirical formula of a compound is the formula for a substance written in terms of the smallest integer exponent. The empirical formula provides information about the atomic number ratio of a compound. The percent composition of a compound leads directly to the empirical formula.
Now,
The molecular formula of a compound with a given empirical formula can be calculated as:
molecular formula = (empirical formula)n
The molecular formula for this compound is: n = 254.1
⇒ 127n = 254.1
⇒ n = 2
Formula = (SF5)₂ = S2F10
⇒ (CH2O)n = 180.156amu 44 {41 24424} = 180. 156
⇒ (30)n = 180.156
⇒ n = 6
Molecular formula = (CH2O)₆ = C6H12O₆
Molecular formula of a compound with empirical formula CH2O and formula weight 180.156 amu: C₆H₁₂O₆.
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Answer:
The molecular formula of the compound with the empirical formula SF5 and a formula mass of 254.1 amu is S2F10. This can be determined by dividing the formula mass by the empirical formula mass (254.1/48.3 = 5.26) and then multiplying the elements of the empirical formula by this value (S x 5.26 = S2, F x 5.26 = F10).
Kinetic energy is proportional to the square of the car's speed. How do the tables and your graph on the previous page show this relationship?(must answer rn!!!)
Answer:
The Speed squared is equal to the Kinetic Energy
Explanation:
1^{2} = 1
2^{2} = 4
3^{2} = 9
4^{2} = 16
Therefore the data on the table proves that the Speed squared is equal to the Kinetic Energy
It shows that the number of individuals in the population will ________ until the carrying capacity of the environment is reached.
Ecological models are _________ because they help scientists ________ what will occur in real life.
Explain what happened to the carrying capacity of reindeer on St. Matthew Island over time. ________
In ________ times, populations do well, and the number of individuals _________ rapidly. A period of rapid population ________ often follows, followed again by a ________ in numbers.
Give some examples of organisms present in a pond community: ___________________________________
A community and its ________ _ (nonliving) environment make up an ________
It shows that the number of individuals in the population will decrease until the carrying capacity of the environment is reached.
What is the environment?
Built environments stand in stark contrast to natural environments. With the conversion of agricultural land into urban areas and other built environments, humans have fundamentally altered the landscape. The result is a greatly altered natural environment that is now more suited to human life. Even seemingly less severe actions like constructing a mud home or a solar system in the desert turn the environment into an artificial one. Despite the fact that many animals construct structures to improve their living conditions, since they are not human, beaver dams and termite mounds are seen as natural.To know more about environment, click the link given below:
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One mole each of SO, and NO, were combined in a one-
liter container, and the following reaction was allowed to
come to equilibrium.
SO₂(g) + NO₂(g) = SO₂(g) + NO(g)
The equilibrium concentrations were found to be [SO₂] =
[NO₂] = 0.350 M and [SO,] = [NO] = 0.650 M. Calculate Kc
for the reaction.
Answer: Kc = 0.5625
Explanation: The equilibrium constant, Kc, can be calculated using the equilibrium concentrations of the reactants and products: Kc = ([SO₂] * [NO]) / ([SO] * [NO₂]) Plugging in the given concentrations: Kc = (0.350 * 0.650) / (0.650 * 0.350) Kc = 0.5625
How does the amount of energy coming from the energy source (low vs. high) affect the amount of electrical energy released.
If (A. more), (B. less) energy is put into the system, then (A. more), (B. less) energy will be released from the system.
The quantity of electrical energy released is a function of the quantity of energy coming from the energy source (low vs. high). The system will release (A) more (B) less energy depending on how much energy is introduced into it.
What is the use of electrical energy in the system?The rotor shaft of a generator is spun or rotated by the fluid's force on the blades. The generator then transforms the kinetic (mechanical) energy of the rotor into electrical energy.
Turbines come in a variety of forms, including steam, combustion (gas), hydroelectric, and wind turbines.
At the scale that a large utility would use them, solar and wind power are currently the least expensive sources of energy. They are much less expensive than coal and nuclear power plants and slightly less expensive than natural gas-fired power plants.
Therefore, Depending on how much energy is supplied into the system, it will either (A) release more (B) or less (C).
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Write an equation for the formation of each compound from its elements in their standard states, and find AH for each in Appen- dix IIB. MISSED THIS?
a. NH3(g
b. CO2(8)
c. Fe203(s)
d. CH4(g)
The equation for the formation of each compounds are given below:
N₂ (g) + 3 H₂ (g) --> 2 NH₃ (g)
C (s) + O₂ (g) --> CO₂ (g)
4 Fe (s) + 3 O₂ (g) --> 2 Fe₂O₃ (s)
C (s) + 2 H₂ (g) --> CH₄ (g)
The standard enthalpy of formation of a substance is defined as the enthalpy change that occurs when 1 mole of the substance is formed from its constituent elements in their standard states.
Hf for NH₃ is -46.0 kJ/mol.
Hf for CO₂ is -393.5 kJ/mol
Hf for solid Fe₂O₃ is -826.0 kJ/mol.
Hf for methane gas is -74.9 kJ/mol.
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