The metal which will reach the highest temperature is the metal with the lowest specific heat capacity.
What is the amount of heat added to each metal?The amount of heat Q = mcΔT where
m = mass of metalc = specific heat capacity of mateal and ΔT = temperature changeTemperature change of the metalMaking ΔT subject of the formula, we have
ΔT = Q/mc
Given that Q and m are the same for each metal,
ΔT ∝ 1/c
We see that the temperature change is inversely proportional to the specific heat capacity.
Since the metals are at the same temperature, the metal which will reach the highest temperature is the metal with the lowest specific heat capacity.
So, the metal which will reach the highest temperature is the metal with the lowest specific heat capacity.
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12.11 liters of gas at atmospheric pressure is compressed into a 0.669 L gas cylinder. What is the pressure (mm Hg) of the compressed gas if its temperature remains constant?
a. 1.38e4
b. 42.0
c. 93.8
d. 18.1
Answer:
a. [tex]P_2=1.38*10^4[mmHg][/tex]
Explanation:
If the Temperature of a gas remains constant (and if the amount of gas molecules doesn't change), then compressing the gas from 12.11 L to 0.669L will increase its pressure through Boyle's Law: [tex]P_1V_1=P_2V_2[/tex]
We'll also need to recall that atmospheric pressure with units of mmHg (since that is the unit requested in the answer) is 760 mmHg.
Letting the initial Pressure and Volume be the P1 and V1, and the final pressure be the P2 and V2, we can substitute and solve:
[tex]P_1V_1=P_2V_2[/tex]
[tex](760[mmHg])(12.11[L])=P_2(0.669[L])[/tex]
[tex]\dfrac{(760[mmHg])(12.11[L \!\!\!\!-])}{0.669[L \!\!\!\!-]}=\dfrac{P_2(0.669[L]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}{0.669[L]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----}}[/tex]
[tex]13757.2496[mmHg]=P_2[/tex]
Since the final pressure is only measured to 3 significant figures, we round the pressure accordingly
[tex]13800[mmHg]=P_2[/tex]
Note that in scientific notation, this is [tex]P_2=1.38*10^4[mmHg][/tex], occasionally written as [tex]1.38\text{E}4[mmHg][/tex]
The bonds of the product store 27 KJ more energy than the bonds of the reactants how is energy conserved during this reaction
A.The reaction creates 27 kj of energy when bonds form.
B.The reaction system absorbs 27 kj of energy from the surroundings.
C.The reaction uses up 27 kj of energy when bonds break.
D.The surroundings absorb 27 kj of energy from the reaction system.
ANSWER: the answer is b
If the bonds of the product store 27 KJ more energy than the bonds of the reactants, It means the surroundings absorb 27 kj of energy from the reaction system Hence, Option (D) is the correct answer
What is the Exothermic reaction ?An exothermic process releases heat, causing the temperature of the immediate surroundings to rise.
The bonds of the product store 27 KJ more energy than the bonds of the reactants, It means that energy has been absorbed by the surrounding as the product formed is more stable due to more stronger bond
This can be inferred from more stored energy with in the bonds and Thus, It is a exothermic reaction.Hence, Option (D) is the correct answer
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Can someone help me please
Answer:D
Explanation:
Use the vertex form, y=a(x−h)2+ky=a(x-h)2+k, to determine the values of aa, hh, and kk.a=14a=14h=6h=6k=1k=1Find the vertex (h,k)(h,k).(6,1)(6,1)Find pp, the distance from the vertex to the focus.Find the distance from the vertex to a focus of the parabola by using the following formula.14a14aSubstitute the value of aa into the formula.14⋅1414⋅14Simplify.Combine 4 and 1/4 .1 /4/4Simplify by dividing numbersDivide 4 by 44.1/1Divide 1 by 1/1.Y=0 The Answer is Dwhat is the percent composition of each element within the compound
Answer:
The percentage composition of a given compound is defined as the ratio of the amount of each element to the total amount of individual elements present in the compound multiplied by 100. Here, the quantity is measured in terms of grams of the elements present.
please give me brainliest
The volume of a gas is inversely proportional to the pressure of a gas is known as:.
Answer:
Boyle's law states this.
Which of the following statements are true of thermal energy and kinetic
energy?
Check all that apply.
A. All the molecules or atoms in motion have kinetic energy.
B. All the molecules or atoms in motion have thermal energy.
C. Each molecule or atom in motion has thermal energy.
D. Each molecule or atom in motion has kinetic energy.
Answer:
A. All the molecules or atoms in motion have kinetic energy.
B. All the molecules or atoms in motion have thermal energy.
C. Each molecule or atom in motion has thermal energy.
D. Each molecule or atom in motion has kinetic energy.
Explanation:
How many grams MnO2 are needed
to generate 126.0 g Zn(OH)2?
Zn + 2MnO₂ + H₂O → Zn(OH)2 + Mn₂O3
The mass of manganese oxide (MnO2) that is needed to generate 126.0 g Zn(OH)2 is 220.56 g.
Mass of manganese oxide needed
The mass of MnO2 that is needed to generate 126.0 g Zn(OH)2 is calculated as follows;
Zn + 2MnO₂ + H₂O → Zn(OH)2 + Mn₂O3
From the reaction above;
2(87 g/mol of MnO₂) ---------> 99.4 g/mol of Zn(OH)2
174 ---------------------> 99.4
? -------------------------> 126
= (126 x 174)/99.4
= 220.56 g
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Answer:
220.56
Explanation:
functions of intercalary meristems
Task 2. Protecting Your Model Village from Tsunamis In this task, you will design a model village to withstand the effects of a tsunami. Estimated time to complete: 1 hour You will need the following materials: 2 pieces of printer paper, 8 inches × 11 inches 2 pieces of card stock, 8 inches × 11 inches 1 piece of cardboard, 8 inches × 11 inches a long, shallow plastic container, around 30 inches long, 15 inches wide, and 5 inches deep tape or glue a small plate or tray water a ruler a small bag of sand, about 2 pounds Hypothesis and Data Collection
Part A Before you design your model village, write down the problems you observed in task 1. What were the largest risks to the community? What happened to the homes?
Part B Design a model village that addresses the problems you identified. Consider the following questions: Does elevation play a factor? If so, can the elevation be changed to protect the homes? Could the residents build a structure that would prevent a tsunami from reaching the community? What would this structure look like? How would the residents build it? What could limit the erosion of the beach?
Part C After you design your model, build your homes and place them in the same positions as they were in task 1. Build any additional structures you think will help protect these homes. Repeat the tsunami experiment from task 1, pushing the waves three to four times.
Analyze and Extend Part A Did your results match your predictions about the additional structure protecting the homes?
Part B To prevent damage from natural hazards, scientists must consider the best ways to keep people safe while also considering practicality in terms of cost, interference of new structures in day-to-day life, and other such factors. If your plan worked, was it a practical solution for the community? Can you think of any downsides to your plan? If it didn’t work, how would you improve your plan? Can you foresee any problems with executing your plan?
Part C. Tsunami evacuation plans often consider the elevation of the community and its distance from the shoreline when deciding which towns to evacuate. How could this data help in building new homes and communities along coastal areas that are prone to tsunamis?
Part D
The home in the picture below is from a tsunami-prone area. Based on the results of your experiment, do you think the structure of this home would protect against tsunamis? I'LL GIVE BRAINLIEST TOO.
The structure of this home would protect against tsunamis due to its height and hard structure.
Does the structure of this home would protect against tsunamis?Yes, in my opinion, the structure of this home would protect against tsunamis because of 8 foot tall wall that is present around the house. This wall is enough to protect the house from tsunamis due to its long height and hard composition.
So we can conclude that the structure of this home would protect against tsunamis due to its height and hard structure.
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some one please help me
Answer:
measure their densities
Choose the correct statements when comparing 1 mole of carbon
monoxide and one mole of helium gas.
a: they weigh the same
b: they have the same amount of particles
c: they occupy the same volume
Answer: they have the same amount of particles
Explanation:
This statement is true by Avogadro's Law, which states that in a mole of any substance, there are [tex]6.022 \times 10^{23}[/tex] particles.
Calculate how many grams would be required to prepare 600. 0 ml of 0. 150 m of naf? molar mass of naf is 41. 9 g/mo
Considering the definition of molarity and molar mass, the mass of NaF required is 3.771 grams.
Definition of molarityMolar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
[tex]molarity=\frac{number of moles}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liters}[/tex].
Definition of molar massThe molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
Mass of NaF requiredIn this case, you know:
molarity= 0.15 M= 0.15 [tex]\frac{moles}{L}[/tex]number of moles= ?volume= 600 mL= 0.6 LReplacing in the definition of molarity:
[tex]0.15\frac{moles}{L} =\frac{number of moles}{0.6 L}[/tex]
Solving:
0.15 [tex]\frac{moles}{L}[/tex] × 0.6 L= number of moles
0.09 moles= number of moles
The molar mass of NaF is 41. 9 g/mol. So, you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 41.9 grams, 0.09 moles of the compound contains how much mass?
[tex]mass=\frac{0.09 molesx41.9 grams}{1 mole}[/tex]
mass= 3.771 grams
Finally, the mass of NaF required is 3.771 grams.
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How many individual carbon atoms are contained in one mole of carbon? (Input your answer with scientific notation using "e-notation". (For example, the speed of light in m/s is 3.0 x 108; in "e-notation" this is 3.0e8.) Report your answer to two places past the decimal point. Moodle is looking for a number only, no units.)
6.023 ×[tex]10^{23}[/tex] individual carbon atoms are there in one mole of carbon.
Mass of a 1 [tex]C_{12}[/tex] atom= 12 amu
1 amu = 1.66 ×[tex]10^{-27}[/tex] gm
∴ 12 amu =1.99 ×[tex]10^{-21}[/tex] gm
∴Mass of a 1 [tex]C_{12}[/tex] atom=1.99 ×[tex]10^{-21}[/tex] gm
Mass of C in 1 mole = 12 gm
∴Total number of atoms of carbons in 1 mole = 12 ÷ 1.99 ×[tex]10^{-21}[/tex]
∴Total number of atoms of carbons in 1 mole= 6.023 ×[tex]10^{23}[/tex] atoms
6.023 ×[tex]10^{23}[/tex] individual carbon atoms are there in one mole of carbon.
The number 6.023 ×[tex]10^{23}[/tex] is known as Avogadro's number, which represents the number of individual atoms present in a one mole of substance with respect to [tex]C_{12}[/tex] atoms.
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An exergonic reaction __________ free energy, and an endergonic reaction __________ free energy.
What is the oxidation state of Hg in Hg2Cl₂?
O A. +1
OB. -1
O C. +2
OD. -2
Answer:
+1
Explanation:
The oxidation state of Hg in Hg2Cl2 is +1. It has +1 state. 0=2Hg +2 (-1) Hg=+1. Mercury chloride (HgCl2) is considered as the dominant form of mercury in coal combustion flue gas. The oxidation state of an atom is the charge of this atom after ionic approximation of its heteronuclear bonds. The oxidation number is synonymous with the oxidation state. Determining oxidation numbers from the Lewis structure (Figure 1a) is even easier than deducing it from the molecular formula (Figure 1b). The oxidation number of each atom can be calculated by subtracting the sum of lone pairs and electrons it gains from bonds from the number of valence electrons. Bonds between atoms of the same element (homonuclear bonds) are always divided equally. When dealing with organic compounds and formulas with multiple atoms of the same element, it's easier to work with molecular formulas and average oxidation numbers (Figure 1d). Organic compounds can be written in such a way that anything that doesn't change before the first C-C bond is replaced with the abbreviation R (Figure 1c). Unlike radicals in organic molecules, R cannot be hydrogen. Since the electrons between two carbon atoms are evenly spread, the R group does not change the oxidation number of the carbon atom it's attached to.
source: www.chegg.com
Answer: O A. +1
Explanation: i took the test
Ch3chclch(ch3)ch2ch2ch2ch2br name the molecule iupac rules please
Answer:
1-bromo-6-chloro-5-methylheptane
Explanation:
There are 3 substituents, 1 chlorine, 1 bromine, and 1 methyl group.
The longest carbon chain consists of 7 carbons.
There are no double bonds, based on the saturation and substituents.
So you have a 1-bromo-6-chloro-5-methylheptane.
Hope that was the brainliest answer!
Which of the following is using chemical potential energy?
O A. An apple hanging on a tree
B. A water wheel turning in a stream
OC. A hiker eating an energy bar
OD. A petal falling from a flower
Among the following options eating an energy bar by a hiker using a chemical potential energy.
Wha is chemical potential energy ?Chemical potential energy is the energy stored in the chemical bonds of a substance.
The food we eat contains stored chemical energy.
As the bonds between the atoms in food loosen or break, a chemical reaction takes place, and new compounds are created.
The energy produced from this reaction keeps us warm, helps us move, and allows us to grow
Hence, eating an energy bar by a hiker using a chemical potential energy.
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7 on the pH scale represents what?
Answer:
seven on the ph scale is the neutral point
Explanation:
The range goes from 0 - 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base. pH is really a measure of the relative amount of free hydrogen and hydroxyl ions in the water.
The limiting reactant, O2, can form up to 2.7 mol Al2O3. What mass of Al2O3 forms?
Al2O3 : 101.96 g/mol
[?] g Al₂O3
Answer:
280 g Al₂O₃
Explanation:
To find the mass, you need to multiply the given value by the molar mass. This will cause the conversion because the molar mass exists as a ratio; technically, the ratio states that there are 101.96 grams per every 1 mole Al₂O₃. It is important to arrange the ratio in a way that allows for the cancellation of units. In this case, the desired unit (grams) should be in the numerator. The final answer should have 2 sig figs to reflect the given value (2.7 mol).
Molar Mass (Al₂O₃): 101.96 g/mol
2.7 moles Al₂O₃ 101.96 g
------------------------ x ------------------- = 275 g Al₂O₃ = 280 g Al₂O₃
1 mole
entir
What is the striking back of
the
bunsen-
burner?
Answer:
With too little air, the gas mixture will not burn completely and will form tiny carbon particles that are heated to glowing, making the flame luminous. With too much air, the flame may burn inside the burner tube; that is, it may strike back.
A 250.ml sample of water was
boiled to 97.0°C then placed on
the counter to cool. If the water
cooled to11.0°C, how much heat
did it lose? Remember the
specific heat of water is 4.184
J/g°C.
Answer: The solubility of this gaseous solute will be,
Explanation :
First, we have to calculate the concentration of solute.
Now we have to calculate Henry's law constant.
Using Henry's law :
where,
C = concentration of solute =
p = partial pressure = 27.59 kPa
= Henry's law constant =?
Now put all the given values in the above formula, and we get:
Now we have to calculate the solubility of this gaseous solute when its pressure is 79.39 kPa.
Therefore, the solubility of this gaseous solute will be,
A 20.0-ml sample of glucose Iv solution has a mass of 20.6g.what is the density of the glucose
Taking into account the definition of density, the density of the glucose is 1.03 [tex]\frac{g}{mL}[/tex].
What is densityDensity is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.
In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
[tex]density=\frac{mass}{volume}[/tex]
From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.
Density of the glucoseIn this case, you know that:
Density= ?Mass= 20.6 gVolume= 20 mLReplacing in the definition of density:
[tex]density=\frac{20.6 g}{20 mL}[/tex]
Solving:
density= 1.03 [tex]\frac{g}{mL}[/tex]
In summary, the density of the glucose is 1.03 [tex]\frac{g}{mL}[/tex].
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A 25.0 g sample of metal at
16.0 °C is warmed to 22.1 °C
by 259 J of energy.
What is the change in temperature
for the metal?
The answer to this question is change in temperature will be 6.1 and specific specific heat capacity of metal will be 1698.36.
According to the formula of Calorimetry
Q = msΔT
where, Q = Quantity of heat absorbed (in joules)
M = Mass of water sample given (in kilogram)
S = specific heat capacity of metal
ΔT = Change in temperature
We have given,
Mass as 25 gram which is equal to 0.025 Kg.
Change in temperature as 6.1
Quantity of heat absorbed as 259 J
Applying to the formula of Calorimetry
Q = msΔT
259 = 0.025 × s × 6.1
s = 1698.36
So, specific heat capacity of metal came out to be 1698.36 and the change in temperature will be 6.1
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Answer: specific heat is 1.7
Explanation:
after you answer this question itll then tell you to find the specific heat
What is the volume in L of a 0.825 mole sample of Ar at 600 mm Hg and 300 K?
Answer:
V = 25.7 L
Explanation:
To find the volume of Argon (Ar), you need to use the Ideal Gas Law equation. This looks like:
PV = nRT
In this formula,
> P = pressure (atm)
> V = volume (L)
> n = number of moles
> R = constant (0.0821 L*atm/K*mol)
> T = temperature (K)
While there is a different constant that can be used if you want to keep the pressure in mmHg, there is a more common constant used when the pressure is in atm. So, to find the volume, you need to (1) convert mmHg to atm (by dividing by 760) and then (2) calculate the volume (using Ideal Gas Law).
(Step 1)
600 mm Hg 1 atm
------------------- x --------------------- = 0.789 atm
760 mm Hg
(Step 2)
PV = nRT
(0.789 atm) x V = (0.825 mole)(0.0821 L*atm/K*mol)(300 K)
(0.789 atm) x V = 20.32
V = 25.7 L
Pls tell me how to solve this!
Answer:
12 seconds
Explanation:
Time taken by 50cm³ of oxygen to diffuse from pinhole
= 1 minute = 60 seconds
⠀
⠀
[tex] \textsf{ Rate of oxygen} \sf (O_2) = \frac{50}{60} [/tex]
⠀
⠀
⠀
Let time taken by 50cm³ of hydrogen to diffuse from pinhole = t seconds
⠀
⠀
[tex] \textsf {Rate of hydrogen } \sf(H_2) = \frac{50}{t} [/tex]
⠀
⠀
⠀
According to the formula
[tex] \sf \frac{Rate \: of \: hydrogen(H_2)}{Rate \: of \: oxygen(O_2) } = \sqrt{ \frac{Molar \: mass \: of \: O_2}{Molar \: mass \: of \: H_2} } [/tex]
⠀
⠀
[tex] \large \sf \frac{50}{t} \div \frac{50}{60} = \sqrt{ \frac{\cancel{32}\small 16}{\cancel2} } \\ \\ \sf \large \frac{ \cancel{50}}{t} \times \frac{60}{ \cancel{50}} = \sqrt{16} \\ \\ \sf \large \frac{60}{t} = 4 \\ \\ \sf \large \frac{ \cancel{60} \: \small12}{ \cancel4} = t \\ \\ \large \underline{ \boxed{ \tt t = 12 \: seconds}}[/tex]
⠀
⠀
⠀
Henceforth, the time taken by 50cm³ of hydrogen to diffuse is 12 seconds.⠀
⠀
Thank you!Temperature is one of the conditions that affects both physical and chemical change. Support the statement with an example.
Temperature affects both physical and chemical change because it modifies the state of matter and also it alters the rate of chemical reactions.
How does temperature affect physicochemical properties?Temperature affects physical properties by increasing the motion of constituent atoms and thus altering the state of matter.
Moreover, in a chemical reaction, an increase in temperature also affects the conversion rate of a reactant to one or more products.
In conclusion, temperature affects both physical and chemical change because it modifies the state of matter and also it alters the rate of chemical reactions.
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A hydrate of zinc nitrate has the formula Zn(NO3)2 . xH2O. If the mass of 1 mol of anhydrous zinc nitrate is 63.67% of the mass of 1 mol of the hydrate, what is the value of x?
MM Zn(NO₃)₂ = 189.36 g/mol
mass 1 mol Zn(NO₃)₂ = 189.36 g
mass hydrate = 100 / 63.67 x 189.36 = 297.409 g
mass 1 mol hydrate = 297.409 g
MM hydrate = 297.409 g/mol
MM hydrate = MM Zn(NO₃)₂ + MM xH₂O
297.409 = 189.36 + x(18)
x = 6
A sealed container can hold
0.325 L of gas at 1.00 atm
and 293 K. How many moles of gas
can the container hold?
0.216 moles of gas can the container hold if a sealed container can hold 0.325 L of gas at 1.00 atm and 293 K.
What is an ideal gas equation?The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
V=5 L
P = 1.05 atm
T = 296 K
Putting value in the given equation:
[tex]\frac{PV}{RT}=n[/tex]
[tex]n= \frac{1.05 atm\; X \;5 L}{ 0.08206 L.atm / mol K X 296 K}[/tex]
Moles = 0.216 moles
Hence, 0.216 moles of gas can the container hold if a sealed container can hold 0.325 L of gas at 1.00 atm and 293 K.
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Answer:
0.014
Explanation:
Use the formula PV=nRT; there are calculators for it online as well.
What units are represented by the numbers marked on the meterstick.
Answer:
Centimeters
Centimeter
⇒ metric unit of length equal to 0.01 (1/100) of a meter
Can you find the difference between the following changes? why? a)rolling of chapati from dough b) baking of chapati
Answer:
They have different temperatures.
Explanation:
Answer:
a. when we are rolling the dough it only changes the shape, its a physical change.
b. we cant change the shape once its cooked, its a chemical change
Explanation:
hope it helps
