If you vertically stretch the exponential function f(x)=2x by a factor of 3, what is the equation of the new function

Answers

Answer 1

Answer:

g(X)=3(2^x)

Step-by-step explanation:


Related Questions

Urban Community College is planning to offer courses in Finite Math, Applied Calculus, and Computer Methods. Each section of Finite Math has 40 students and earns the college $40,000 in revenue. Each section of Applied Calculus has 40 students and earns the college $60,000, while each section of Computer Methods has 10 students and earns the college $26,000. Assuming the college wishes to offer a total of seven sections, accommodate 220 students, and bring in $292,000 in revenues, how many sections of each course should it offer?
Finite Math section(s)
Applied Calculus section(s)
Computer Methods section(s)

Answers

Answer:

meh

Step-by-step explanation:

the length of a ruler is 170cm,if the ruler broke into four equal parts.what will be the sum of the length of three parts

Answers

Answer:

Step-by-step explanation:Srry it's bit rough...

A multiple-choice standard test contains total of 25 questions, each with four answers. Assume that a student just guesses on each question and all questions are answered independently. (a) What is the probability that the student answers more than 20 questions correctly

Answers

Answer:

[tex]P(x>20)=9.67*10^{-10}[/tex]

Step-by-step explanation:

If we call x the number of correct answers, we can said that P(x) follows a Binomial distribution, because we have 25 questions that are identical and independent events with a probability of 1/4 to success and a probability of 3/4 to fail.

So, the probability can be calculated as:

[tex]P(x)=nCx*p^{x}*q^{n-x}=25Cx*0.25^{x}*0.75^{25-x}[/tex]

Where n is 25 questions, p is the probability to success or 0.25 and q is the probability to fail or 0.75.

Additionally, [tex]25Cx=\frac{25!}{x!(25-x)!}[/tex]

So, the probability that the student answers more than 20 questions correctly is equal to:

[tex]P(x>20)=P(21)+P(22)+P(23)+P(24)+P(25)[/tex]

Where, for example, P(21) is equal to:

[tex]P(21)=25C21*0.25^{21}*0.75^{25-21}=9.1*10^{-10}[/tex]

Finally, P(x>20) is equal to:

[tex]P(x>20)=9.67*10^{-10}[/tex]

PLEASE HELP Last year Lenny had an annual earned income of $58,475. He also had passive income of $1,255, and capital gains of $2,350. What was Lenny’s total gross income for the year?
a.
$58,475
b.
$59,730
c.
$60,985
d.
$62,080


Please select the best answer from the choices provided

A
B
C
D

Answers

The answer is D
If you add it, the total is 62,080

Answer:

D

Step-by-step explanation:

How many solutions does the system have? y = -2x-4 \\\\ y = 3x+3

Answers

Answer:

The system has one solution.

Step-by-step explanation:

We have two equations:

y = -2x - 4

y = 3x + 3

Equalling them:

y = y

-2x - 4 = 3x + 3

5x = -7

[tex]x = -\frac{7}{5}[/tex]

And

[tex]y = 3x + 3 = 3(-\frac{7}{5}) + 3 = \frac{-21}{5} + 3 = \frac{-21}{5} + \frac{15}{5} = -\frac{6}{5}[/tex]

Replacing in the other equation we should get the same result.

[tex]y = -2x - 4 = -2(-\frac{7}{5}) - 4 = \frac{14}[5} - 4 = \frac{14}{4} - \frac{20}{5} = -\frac{6}{5}[/tex]

So the system has one solution.

This Question: 4 pts
1 of 11 (0 complete)
Music Preferences
Students at a high school were polled to determine the type of music they preferred. There were 1960 students who
completed the poll. Their responses are represented in the circle graph.
Rap 916
Alternative 46
Rock and Roll 279
Country 183
Jazz 32
Other 89
About What % of the students who completed the poll preferred rock and roll music.
(Round to one decimal place as needed.)​

Answers

Answer:

The percentage of the students who completed the poll preferred rock and roll music.

P(RR) = 0.1423 = 14.23 %

Step-by-step explanation:

Explanation:-

Given total number of students n(S) = 1960

Given the Students at a high school were polled to determine the type of music they preferred.

Rap 916

Alternative 46

Rock and Roll 279

Country 183

Jazz 32

Other 89

Let ' RR' be the event of Rock and Roll preferred music

given Rock and Roll = 279

n( RR) =  279

The percentage of the students who completed the poll preferred rock and roll music.

[tex]P(RR) = \frac{n(RR)}{n(s)} = \frac{279}{1960}[/tex]

P(RR) = 0.1423 = 14.23 %

123 grams is rounded to nearest whole. Write down the minimum possible mass it could have been.

Answers

Answer:

The nearest whole is 122.99 repeated

Step-by-step explanation:

Alguien me puede ayudar con en esto por favor !!!

Answers

Answer:

y=cosx

Step-by-step explanation:

cosx has a domain of all real numbers

What value of x makes 3(x + 4) = 3x + 4 true?

Answers

Well lets see.

[tex]3(x+4)=3x+4\implies 12 = 4\implies x\notin\mathbb{C}[/tex].

There are no such x-es that satisfy the equation.

The total mass of the Sun is about 2×10^30 kg, of which about 76 % was hydrogen when the Sun formed. However, only about 12 % of this hydrogen ever becomes available for fusion in the core. The rest remains in layers of the Sun where the temperature is too low for fusion.
Part A
Use the given data to calculate the total mass of hydrogen available for fusion over the lifetime of the Sun.
Express your answer using two significant figures.
Part B
The Sun fuses about 600 billion kilograms of hydrogen each second. Based on your result from part A, calculate how long the Sun’s initial supply of hydrogen can last. Give your answer in both seconds and years.
Express your answer using two significant figures.
Part D
Given that our solar system is now about 4.6 billion years old, when will we need to worry about the Sun running out of hydrogen for fusion?
Express your answer using two significant figures.

Answers

Answer:

A. 1.8 ×[tex]10^{30}[/tex] Kg

B i. 3.0 × [tex]10^{17}[/tex] seconds

  ii. 9.6 × [tex]10^{9}[/tex] years

C. After 9.2 × [tex]10^{9}[/tex] (9.2 billion) years

Step-by-step explanation:

Given that the mass of the Sun = 2× [tex]10^{30}[/tex] Kg.

Mass of hydrogen when Sun was formed = 76% of 2× [tex]10^{30}[/tex] Kg

                            = [tex]\frac{76}{100}[/tex]  ×2× [tex]10^{30}[/tex] Kg

                           = 1.52 × [tex]10^{30}[/tex] Kg

Mass of hydrogen available for fusion = 12% of 1.52 × [tex]10^{30}[/tex] Kg

                           = [tex]\frac{12}{100}[/tex] × 1.52 × [tex]10^{30}[/tex] Kg

                           = 1.824 ×[tex]10^{30}[/tex] Kg

A. Total mass of hydrogen available for fusion over the lifetime of the sun is 1.8 ×[tex]10^{30}[/tex] Kg.

B. Given that the Sun fuses 6 × [tex]10^{11}[/tex] Kg of hydrogen each second.

i. The Sun's initial hydrogen would last;

                                     [tex]\frac{1.8*10^{30} }{6*10^{11} }[/tex]

                                 = 3.04 × [tex]10^{17}[/tex] seconds

The Sun's hydrogen would last 3.0 × [tex]10^{17}[/tex] seconds

ii. Since there are 31536000 seconds in a year, then;

The Sun's initial hydrogen would last;

                                     [tex]\frac{3.04*10^{17} }{31536000}[/tex]

                                 = 9.640 × [tex]10^{9}[/tex] years

The Sun's hydrogen would last 9.6 × [tex]10^{9}[/tex] years.

C. Given that our solar system is now about 4.6 × [tex]10^{9}[/tex] years, then;

                               [tex]\frac{9.6*10^{9} }{4.6*10^{9} }[/tex]

                             = 2.09

So that;   2 × 4.6 × [tex]10^{9}[/tex] = 9.2 × [tex]10^{9}[/tex] years

Therefore, we need to worry about the Sun running out of hydrogen for fusion after 9.2 × [tex]10^{9}[/tex] years.

Part(A): The total mass of hydrogen available 9.6 billion years.

Part(B): The total time is 5.10 billion years.

Part(D): The hydrogen will last [tex]5.04\times 10^9 \ years[/tex]

Mass of the sun:

Our sun is the largest object in our solar system. The mass of the sun is approximately [tex]1.988\times 1030[/tex] kilograms

Part(A):

Given that,

The total mass of the Sun =[tex]2\times10^{30} kg[/tex]

Mass of hydrogen in Sun =  [tex]2\times10^{30} \times0.76\ kg[/tex]

The mass of hydrogen ever available for fusion is,

[tex]2\times10^{30} \times 0.76 \times 0.12 kg = 1.824\times 10^{29}[/tex]

Mass of hydrogen fuses each second = 600 billion kg/second.

Time hydrogen will last in seconds=[tex]1.824\times 10^{29}seconds.[/tex]

[tex]= 0.00304\times 10^{29 }= 3.04\times 10^{17}.[/tex]

Time hydrogen will last in seconds =[tex]1 year = 31,536,000 seconds.[/tex]

[tex]31,536,000 x = 3.04\times 10^{17} = 9.6 \ billion \ years.[/tex]

(B) Present age of sun = [tex]9.6-4.5 \ billion \ years[/tex]

The time when we need to worry about Sun running out of hydrogen for fusion = 5.10 billion years.

(D) The solar system is 4.6 billion years old that is [tex]4.6\times 10^9\ years[/tex]

And in part (B) we have calculated that hydrogen will last [tex]9.64\times 10^9[/tex] then,

[tex]9.64\times 10^9-4.6\times 10^9=5.04\times 10^9[/tex]

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what is the value of this expression plssssss 8z-3 when z =7

Answers

Answer:

53

Step-by-step explanation:

8•7 is 56

56 - 3 is 53

Answer:

53

Step-by-step explanation:

z = 7

8z is the same as saying 8×z

8×7-3 (do multiplication first)

56-3 = 53

Write the number one and three quarter million in figures.

Answers

Answer 1750000

Step-by-step explanation:

The number "one and three-quarter million" can be written in figures as 1,750,000.

Given the number one and three quarter million.

"One" represents the digit 1.

"Three-quarter" means three-fourths or 3/4.

In decimal form, this fraction is 0.75.

"Million" signifies a value of 1,000,000.

To represent this number in figures, we combine these components:

We start with the digit 1, representing "one."

Then we append the value 750,000, which corresponds to "three-quarter million."

Combining these two parts, we have 1,750,000.

Therefore, "one and three-quarter million" can be written in figures as 1,750,000.

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Salinas Corporation has net income of $15 million per year on net sales of $90 million per year. It currently has no long-term debt but is considering a debt issue of $20 million. The interest rate on the debt would be 7%. Salinas Corp. currently faces an effective tax rate of 40%. What would be the annual interest tax shield to Salinas Corp. if it goes through with the debt issuance?

Answers

Answer:

The annual interest tax shield to Salinas Corp would be of $560,000

Step-by-step explanation:

In order to calculate the annual interest tax shield to Salinas Corp if it goes through with the debt issuance we would have to calculate the following formula:

Annual Interest tax shield = Interest * tax

Interest = debt *rate of interest

Interest=$20 million * 0.07

Interest= $ 1.40 million

tax= 40%

Therefore, Annual Interest tax shield =$1.40 million * 0.40

Annual Interest tax shield = $560,000

The annual interest tax shield to Salinas Corp would be of $560,000

Which of the following terminating decimals is equivalent to -1 3/4

Answers

Answer:

-1.75

Step-by-step explanation:

5 of 5


It is worked out that if 5 ladles full of soup are given to


each person,


140 people can be fed.


The customers have complained in the past that the


portions are too small.


The cook decides to give 7 ladles full of soup to each


person.


How many people can now be fed soup?


people

Answers

Answer:

Number of people that can be served 7 ladles = 100 people

Step-by-step explanation:

We are told that;

Initial number of ladles proposed per person = 5

Number of persons to be fed based on 5 ladles = 140 persons

Thus, amount of ladles based on that data is;

140 people x 5 ladle/1 person = 700 ladles full of soup

Now, since the cook decides to give 7 ladles full of soup to each person, the number of people that can be fed will now be;

700 ladles ÷ 7 ladles/person = 100 persons

You wake up one morning, and find yourself wearing a toga and scarab ring. Always a logical person, you conclude that you must have become an Egyptian pharoah. You decide to honor yourself with a pyramid of your own design. You decide it should have height h = 130 and a square base with side s = 870
To impress your Egyptian subjects, find the volume of the pyramid.

Answers

Answer:

32799000 cubic units

Step-by-step Explanation:

Height if the Pyramid=130 Units

Side Length of square base=870 Units

Volume of a Pyramid=[tex]\frac{1}{3}[/tex]* Base Area*Height

Since the base is a square,

Area of a Square of side length s[tex]=s^2[/tex]

Therefore:

Volume[tex]=\frac{1}{3}*870^2*130[/tex]

=32799000 cubic units

The volume of your pyramid is 32799000 cubic units.

Answer:

V = 3.28x10⁷

Step-by-step explanation:

The volume of a pyramid is given by:

[tex] V = \frac{1}{3}bh [/tex]

Where:

b: is the base of the pyramid  

h: is the height of the pyramid = 130            

The base of the square base of the pyramid is given by:

[tex] b = s^{2} [/tex]

Where:

s: is the side of the square base = 870

Thus, the base of the square base of the pyramid is:

[tex] b = s^{2} = (870)^{2} = 7.56 \cdot 10^{5} [/tex]  

Now, the volume of a pyramid is:

[tex] V = \frac{1}{3}bh = \frac{1}{3}(7.56 \cdot 10^{5})*130 = 3.28 \cdot 10^{7} [/tex]

Therefore, the volume of the pyramid is 3.28x10⁷.

I hope it helps you!

From a sample with nequals24​, the mean number of televisions per household is 4 with a standard deviation of 1 television. Using​ Chebychev's Theorem, determine at least how many of the households have between 2 and 6 televisions. At least nothing of the households have between 2 and 6 televisions.

Answers

Answer:

At least 18 of the households have between 2 and 6 televisions.

Step-by-step explanation:

Chebyshev Theorem

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]100(1 - \frac{1}{k^{2}})[/tex].

In this question:

Mean = 4

Standard deviation = 1

Percentage of households that have between 2 and 6 televisions.

2 = 4 - 2*1

So 2 is two standard deviations below the mean

6 = 4 + 2*1

So 6 is two standard deviations above the mean

By Chebyshev's Theorem, at least 75% of the measures are within 2 standard deviations of the mean.

Out of 24

0.75*24 = 18

At least 18 of the households have between 2 and 6 televisions.

Which point is coplanar with B , C , H ?

Answers

Answer:

G

Step-by-step explanation:

Point G is coplanar with points B, C, H.

Which equation has a k-value of -12? y=−12x y=12+12x y=x−12 y=12x+1

Answers

Answer:

  y = -12x

Step-by-step explanation:

We assume you're concerned with the form ...

  y = kx

Putting -12 for k gives ...

  y = -12x . . . . . the first choice

_____

Additional comment

The answer will depend somewhat on the context of the question. If you're studying proportions, then "k" is the constant of proportionality as shown above.

If you're studying function translations, then "k" is the vertical translation, as in ...

  y = m(x -h) +k

In this case, the equation y = x -12 will have a "k" value of -12.

85% of z is 106,250. What is z?

Answers

Answer:

z=12500

Step-by-step explanation:

Of means multiply and is means equals

85% *z = 106250

Change to decimal form

.85z = 106250

Divide each side by .85

.85z/.85 = 106250 /.85

z=12500

Z = 12500
....
.....
....
...

What is the next pattern ?

Answers

The answer to the pattern coming next will be A

The accompanying data are the times to failure (in millions per cycle) of high-speed turbine engine bearings made out of two different compounds. These were taken from "Analysis of Single Classification Experiments Based on Censored Samples from the Two-parameter Weibull Distribution" by J.I. McCool (The Journal of Statistical Planning and Inference, 1979) Compound 1 3.03 5.53 5.60 9.30 9.92 12.51 12.95 15.21 16.04 16.84 Compound 2 3.19 4.26 4.47 4.53 4.67 4.69 5.78 6.79 9.37 12.75 (a) Find the 0.84 quantile of the Compound 1 failure times (b) Give the coordinates of the two lower-left points that would appear on a normal plot of the compound 1 data (c) Make back-to-back stem-and-leaf plots for comparing the life length properties of bearings made from Compounds 1 and 2 (d) Make (to scale) side-by-side boxplots for comparing the life lengths for the two compounds. Mark numbers on the plots indicating the locations of their main features (e) Compute the sample means and standard deviations of the two sets of lifetimes (f) Describe what your answers to parts (c), (d), and (e) above indicate about the life lengths of these turbine bearings.

Answers

Find the given attachments

Find x in this 45°-45°-90° triangle.
145972
x
X=
4.572
9
18

Answers

IOS share with you and your family

Find the median of the data in the dot plot below.

Answers

The value of the median is 25 from the dot plot because the middle value is 25 on the dot plot,

What is the median?

A median is a middle number in a series of numbers that have been arranged to lift, and it might be more informative of the set of data than the average. When there are extremes in the sequences that might affect the average of the numbers, the median is sometimes employed instead of the mean.

We have a dot plot shown in the picture.

As we can see in the dot plot there are a total of 9 dots.

4 dots left side and 4 dots right side.

One dot is left which is pointing to the value 25 at the number line.

Thus, the value of the median is 25 from the dot plot because the middle value is 25 on the dot plot,

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A recent graduate school study of a random sample of 250 US manufacturing companies determined the average financial report preparation time was 68.04 days with a standard deviation of 35.74 days. Calculate to three decimal places the 95 percent confidence interval for the mean report prep time for all US manufacturing companies. [63.001, 72.008] [63.957, 75.568] [63.505, 72.414] [61.612, 74.468] [63.612, 72.468]

Answers

Answer:

[tex]68.04-1.959\frac{35.74}{\sqrt{250}}=63.618[/tex]    

[tex]68.04+1.959\frac{35.74}{\sqrt{250}}=72.461[/tex]    

And the best option for this case would be

Step-by-step explanation:

Information given

[tex]\bar X=68.04[/tex] represent the sample mean

[tex]\mu[/tex] population mean

s=35.74 represent the sample standard deviation

n=250 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]   (1)

The degrees of freedom are given by:

[tex]df=n-1=250-1=249[/tex]

The Confidence level is 0.95 or 95%, and the significance [tex]\alpha=0.05[/tex] and [tex]\alpha/2 =0.025[/tex], and the critical value for this case woud be [tex]t_{\alpha/2}=1.956[/tex]

And replacing we got:

[tex]68.04-1.959\frac{35.74}{\sqrt{250}}=63.618[/tex]    

[tex]68.04+1.959\frac{35.74}{\sqrt{250}}=72.461[/tex]    

And the best option for this case would be

What’s the correct answer for this question?

Answers

Answer:

C.

Step-by-step explanation:

First finding height using Pythagoras theorem

(H)²=(B)²+(P)²

8.2²=5.4²+P²

P² = 67.24 - 29.16

P² = 38.08

P = 6.2

Now

Volume of cone = (1/3)πr²h

= (1/3)(3.14)(5.4)²(6.2)

= (1/3)(567.9)

= 189.2 cm³

In a survey of a group of​ men, the heights in the​ 20-29 age group were normally​ distributed, with a mean of 69.9 inches and a standard deviation of 4.0 inches. A study participant is randomly selected. Complete parts​ (a) through​ (d) below. ​(a) Find the probability that a study participant has a height that is less than 65 inches. The probability that the study participant selected at random is less than 65 inches tall is nothing. ​(Round to four decimal places as​ needed.)

Answers

Answer:

The probability that a study participant has a height that is less than 65 inches is 0.1103.

Step-by-step explanation:

We are given that the heights in the​ 20-29 age group were normally​ distributed, with a mean of 69.9 inches and a standard deviation of 4.0 inches.

A study participant is randomly selected.

Let X = heights in the​ 20-29 age group.

So, X ~ Normal([tex](\mu=69.9,\sigma^{2} =4.0^{2}[/tex])

The z-score probability distribution for the normal distribution is given by;

                             Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = mean height = 69.9 inches

           [tex]\sigma[/tex] = standard deviation = 4.0 inches

Now, the probability that a study participant has a height that is less than 65 inches is given by = P(X < 65 inches)

      P(X < 65 inches) = P( [tex]\frac{X-\mu}{\sigma}[/tex] < [tex]\frac{65-69.9}{4}[/tex] ) = P(Z < -1.225) = P(Z [tex]\leq[/tex] 1.225)

                                                                 =  1 - 0.8897 = 0.1103

The above probability is calculated by looking at the value of x = 1.225 in the z table which lies between x = 1.22 and x = 1.23 which has an area of 0.88877 and 0.89065 respectively.

A boy is playing a ball in a garden surrounded by a wall 2.5 m high and kicks the ball vertically up from a height of 0.4 m with a speed of 14 m/s. For how long is the ball above
the height of the wall.​

Answers

Answer:

2.54 seconds

Step-by-step explanation:

We can use the following equation to model the vertical position of the ball:

S = So + Vo*t + a*t^2/2

Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.

Then, using S = 2.5, So = 0.4, Vo = 14 and a = -9.8 m/s2, we have that:

2.5 = 0.4 + 14*t - 4.9t^2

4.9t^2 - 14t + 2.1 = 0

Solving this quadratic equation, we have that t1 = 2.6983  s and t2 = 0.1588 s.

Between these times, the ball will be higher than 2.5 m, so the amount of time the ball will be higher than 2.5 m is:

t1 - t2 = 2.6983  - 0.1588 = 2.54 seconds

What is the simplest form of this expression?
4(y + 2) - 2

Answers

the simplest form is 4y+6?


you distribute the 4 to everything in the parentheses and then combine like terms so you would combine the 8 and -2

Answer & Step-by-step explanation:

4(y + 2) - 2

Distribute 4 to (y + 2)

4y + 8 - 2

Combine like terms

4y + 6

So, your answer in the simplest form is 4y + 6

Which triangle congruence postulate can be used to prove that FEH=HGF?


SAS
HL
ASA
SSS

Answers

Answer:

Option (2).

Step-by-step explanation:

From the figure attached,

EFGH is a quadrilateral and FH is line which divides the quadrilateral into two right triangles, ΔFEH and ΔHGF.

In ΔFEH and ΔHGF,

Sides EH ≅ FG [Given]

FH ≅ FH [reflexive property]

ΔFEH ≅ ΔHGF [HL (Hypotenuse - length) postulate of congruence]

Option (2) will be the answer.

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mention any four features of land Which of the following leading to VSD?Select onea. POAb. AVCC. ASDd. TOF what is the radius of circle O Calculate the theoretical yield for the amount of sodium carbonate produced as a result of this chemical reaction. Record your final answer in the above data table.Calculate the percent yield using your theoretical yield and the amount of sodium carbonate that was actually recovered. Record your final answer in the above data table.How did your calculated mass of sodium carbonate compare with the actual mass you obtained from the experiment? If the two masses are different, suggest reasons for the difference.Predict the amount of water and carbon dioxide that was produced as a result of this reaction.1.Mass of crucible 5.26 g2.Mass of crucible & NaHCO3 8.27 g3.Mass of NaHCO3 (2-1)3.01g4.Theoretical Yield of Na2CO3(Use the amount calculated in #3 as your starting amount)g5.Mass of crucible & Na2CO3 7.13 g6.Mass of Na2CO3 Actual Yield (5-1)1.87 g7.% Yield = actual yield x 100theoretical yield % HELPPPP ASAP !!!!!!! A triangle was dilated by a scale factor of 4. If tan a = four thirds and segment FD measures 12 units, how long is segment EF?triangle DEF in which angle F is a right angle, angle D measures a degrees, and angle E measures b degrees segment EF = 6 units segment EF = 9 units segment EF = 12 units segment EF = 16 units What does source A tell you about the knowledge of the Holocaust amongst ordinary Germans? An oligarchy is similar to what other type of government?unitarymonarchyautocraticdemocracy Factorise fully5ac - 10a2b + 30a PLZ HELP MEEE!!!!!!!!!!!!!!! what were the sources of information about thedelhi sutanate ? Charlotte has been working for her company for x years. Travis has been working for the same company exactly 3 years longer than Charlotte. What is the range of the relationship? A random sample of 18 graduates of a certain secretarial school typed an average of 80.6 words per minute with a standard deviation of 7.2 words per minute. Assuming a normal distribution for the number of words typed per minute, compute the 95% prediction interval for the next observed number of words per minute typed by a graduate of the secretarial school. Many parasites cause more harm tothe host than just feeding alonebecause...A. many parasites transmit disease.B. many parasites become 'part' of the hostorganism.C. many parasites return with swarms. Compare and contrast heat exhaustion and heat stroke. Which sentence does not have a compound PREDICATE?A. The twins promote books, wander through bookstores, and join book clubs throughout the summer.B. I'm slicing cucumbers and baking pita bread to make some Mediterranean food. C. The boys dug up worms for fishing.D. My family eats catfish, grills trout, and smokes salmon at their annual fish fry. Please help with this question Which of the following is the factored form of the quadratic *12x^2+5x-2=01.(4x - 1)(3x - 2)2.(4x - 1)(3x + 2)3.(4x + 1)(3x - 2) Work out the value of 5 - 19 x 24 Given: HJ =4x+9, JK=3x+3and KH=33Find: x, HJ, and JKX= BLANK?HJ=BLANK?JK=BLANK? Please Help!!! I will give brainliest 20 points!! here is the story: he Persistent Gardener It was Jilly's last day in the green house. Summer was coming to an end and so was the growing season. School would be starting next week and the fall plants were well enough along to allow Mrs. T. to manage the greenhouses herself. As Jilly worked the plants for the last time, she tried to focus on the new school year instead of the details of the greenhouse. It had been a hard, hot summer, but Jilly was not ready for it to be over. Jilly moved down the tables, tucking a stray hair behind her ear with a gloved and already dirty hand. She'd repotted the last of the rosemary plants and mixed a new batch of potting soil already. Mrs. T. now had enough potting soil to last her through September. Jilly looked at a couple of maiden-hair ferns that were beginning to yellow in their small pots. She loved their lacey fronds and had grown concerned over the last few days that they needed repotting or a boost of fertilizer. She had also worried that she would continue to find chores that needed doing, plants that needed help, right up until the minute she left today. She hated unfinished things. She hated details not being tended to. The sun had been above the trees and blasting the greenhouse for a good hour now. Jilly listened for the familiar whirr of the automatic vents opening. When the greenhouse reached a certain temperature, the vents would open automatically. The vents would have a cooling effect for an hour or so, and then no amount of breeze would put a dent in the heat. Mrs. T. often claimed Jilly must be part reptile as she was able to work longer in the greenhouse than anyone else. The heat just didn't bother her. In fact, Jilly often looked forward to the warmth of the greenhouse and feeling the heat seep into her bones. It felt good to her, but she understood others who found it hard to breathe in 100 degree temperatures. Jilly heard the greenhouse door bang, and looked up from her ferns to see Mrs. T. walking down the aisle with a tray of young plants. Mums, Jilly supposed, the flowers everyone wants for fall. She had helped Mrs. T. take cuttings and plant the small stems in new pots. They were doing nicely from the look of things. "We will keep these in here for now," said Mrs. T. "They are getting too much rain outside." It had been a rainy couple of days. Jilly knew, as well as anyone, that overwatering could kill potted plants quickly. "Do you remember when I overwatered those mint plants?" Jilly asked Mrs. T. "I used to think no one could kill a mint plant," Mrs. T. said, laughing. "Well I am full of surprises, apparently," Jilly replied. Jilly remembered the sad green plants that just kept looking more and more wilted no matter how much water she gave them. It was a beginner's mistake, and Jilly had been so embarrassed for making it. "That you are," replied Mrs. T. "But I know you learned a lesson you won't ever forget." "Of course. Herbs like their roots damp, not flooded," Jilly answered. "Well that is not the lesson I was thinking of," Mrs. T. said. Jilly wondered for a minute what the lesson could be. She straightened the rows of geraniums in front of her, picking up one or two to check for aphids under the leaves. It had been a summer full of lessons, some especially hard for a girl who thought she knew a lot about plants. She breathed deeply the warm, humid air. She hated the cooped up feeling of air conditioned air, the feeling of being cut off from the sun. She knew school and the library would offer only these uncomfortable feelings and little time to spend in the sun or with plants. She had come to understand this over the summer-her need to be around growing things was huge. "I'm not sure, Mrs. T." she said, "I've learned so much this summer. I couldn't possibly say what you are thinking." "You did learn many lessons, Jilly. You knew so much when you started. You've gone farther than any other assistants I've had. I will miss you." "And I will miss you," Jilly replied. "Thank you for the opportunity and the job." Jilly watched Mrs. T. put the tray of mums down on the center row of tables. Wearing her familiar brown apron, Mrs. T. looked just as she had on Jilly's first day. "My pleasure, of course, dear," Mrs. T. replied. "My hope for you, as for all my assistants over the years, is that you will learn as much about yourself as you do about growing plants." Recalling her thoughts all morning, about what she enjoyed about her summer job, Jilly realized she knew much more than just how to not drown the mint. Here are the questions: I Have a answer circled in I just need to verify That is why one is circled THX!!!