if you were to draw a 3rd harmonic of a tube open at both ends, what would you draw at the ends of the tube?

Answer:

Case 1: Balancing length when cell is shunted l1 = 150 cm = 1.5 m, Value of shunt = R = 5 ohm. Case 2: Balancing length when cell is shunted l1 = 175 cm = 1.75 m, Value of shunt = R = 10 ohm. Example 06: A cell balances against a length of 250 cm on potentiometer wire when it is shunted by a resistance of 10 ohms

The final common speed of the two carts will be 69.3 m/sec.The momentum conservation principle is applied.

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

Unit conversion:

1 metric tons = 1000 kg

Given data;

m₁= 11.6 metric ton =11600 kg

m₂ = 23.2 metric ton =  23200 kg

Let v represent the combined velocity of the two carts once they are connected, and let u represent the starting velocity of cart 1 when it reaches the bottom.

Considering energy conservation;

[tex]\rm m_1 g h = \frac{1}{2} m_1 \times u^2 \\\\ u^2 = 2gh\\\\ u^2 = 2 \times 9.8 \times 10.6 \\\\ u = 207.972 \ m/s[/tex]

From the conservation of momentum principle;

[tex]\rm m_1 \times u = (m_1 + m_2) v\\\\ 11600 \times 207.972 = (11600 + 23200) \times v \\\\ v = 69.3 \ m/s[/tex]

Hence, the final common speed of the two carts will be 69.3 m/sec.

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Charles Darwin's theory of natural selection states that features that offer survival or reproductive advantage are more likely to be handed down to subsequent generations.

A trait is a distinctive pattern of behavior or conscious motivation that may be evaluated by peers or oneself.

Traits that provide a survival or reproductive advantage are more likely to be passed on to future generations is Charles Darwin’s theory of natural selection state traits.

Hence option D is correct.

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Answer: option d

Explanation:

Answer:

50km/h

Explanation:

average = (a + b) / 2

average = (60 + 40) / 2

average = 50

Answer:

the answer to the question is a reflector

Ocean bulges on Earth would be bigger if the Moon had twice as much mass and yet orbited the planet at the same distance. Option B is correct.

The fluid and moveable ocean water are drawn towards the moon by the gravitational attraction between the moon and the Earth.

The ocean nearest to the moon experiences a bulge as a result, and as the Earth rotates, the affected seas' locations shift.

The Moon's bulges in the oceans would be larger if it had twice the mass and orbited Earth at the same distance.

Hence option B is corect.

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Explanation:

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(a) The segment A shows acceleration as velocity increases with the increase in time.

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(b) The segment C shows the object is slowing down as the time increases in segment C, the velocity decreases and afterwards it comes to rest.

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(c) The velocity is segment B is 40m/s. And in the diagram there is no change in velocity.

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(d) The acceleration of segment B is zero. As there in no change in curve and it is moving with uniform velocity.

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[tex] \: [/tex]

Answer:

1 A and C

2 C

3 40m/s

4 zero

Explanation:

Answer:I would say that it would be about 2/3rds as fast as the moon and i have seen a similar question but it asked different info about it. I also believe that the basketball would have a lower weight due to it being in space. I feel bad saying this but i know that i got some info off this website when working with this and i hope it helps.

Explanation:

Note- I am new to Brainly so sorry if this isn't as helpful as you expected this to be.

The output voltage of a transformer is 40V.

An output voltage is the voltage released by a device, such as a voltage regulator or a generator.

The formula to calculate Output voltage of transformer is:

[tex]\frac{V_{s} }{V_{p} } = \frac{N_{s} }{N_{p} }[/tex]

here,  [tex]V_{s}[/tex] is the secondary voltage, [tex]V_{p}[/tex] is the primary voltage, [tex]N_{s}[/tex] is the number of secondary windings and [tex]N_{p}[/tex] is the number of primary windings.

According to the question.

[tex]N_{p}[/tex] =1200 , [tex]N_{s}[/tex]=200 , [tex]V_{p}[/tex]=240V  ,[tex]V_{s}[/tex]= ?

By using the formula of Output voltage,

[tex]{V_{s} } = \frac{V_{p}N_{s} }{N_{p} }[/tex]

=[tex]\frac{240*200}{1200}[/tex]

[tex]=40V[/tex]

Therefore, 40V is the output voltage of a transformer.

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Answer:

ways can carry either __machanical___ or electromagnetic energy

Answer:

D

Explanation:

15m/ s

i hope this helps

Speed can be defined as the change in distance with respect to time.

The speed is the change in distance with the time and velocity is the change in displacement with the time. Speed is a scalar quantity having magnitude only and Velocity is a vector quantity having magnitude as well as direction.

If the velocity of the object is changing, it shows that the object is accelerating.

Inertia is a resistance of an object to resist a change in its state of motion or of rest. If a ball is rolled, it will continue rolling unless friction or something else stops it by force.

Some common forces are gravitational forces, electric forces, magnetic forces, nuclear forces, etc. Gravitational forces act between the earth and the object, it is an attraction force. Similarly, there is an electric force, which acts between the two charges, it can be attractive or repulsive.

The forces that are opposite in direction and equal in size, are known as balanced forces. This can be explained as forces acting horizontal, and the forces are balanced, so the left-sided forces and right-sided forces must be equal.

Power can be defined as the measure of the amount of work that can be done in a given amount of time. Power is work done per unit time.

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The magnitude and direction of the resultant velocity of the car will be 169.70 km/h and 45°.

The quantity which has magnitude, direction and follows the law of vector addition is called a vector.

A car traveling at 120 km/h towards west makes a right turn and travel north without changing its speed.

Then the magnitude (R) will be

R² = 120² + 120²

R² = 28800

R = 169.70 km / h

Then the direction of the resultant velocity will be

tan θ = 120 / 120

tan θ = 1

tan θ = tan 45°

     θ = 45°

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Answer:

2kg brick

Explanation:

2kg brick at 25 degrees.

Answer: A 2kg brick at 20*C

Explanation:

Answer:

B

Explanation:

Answer:

D. 0.43 A

Explanation:

First you will find the total resistance which is

R=R¹+R²

R=2+12

R= 14 ohms

I = V/R

I = CURRENT

V= VOLTAGE

R = RESISTANCE

I= 6/14

I =0.43 A

(a) The average velocity of the particle in the time interval t₁=2sec and t₂=3sec is 10 m/s.

(b) The velocity and acceleration at any time t is v =  (2ati + bj) m/s and a = 2ai m/s²

(c)  The average acceleration in the time interval given in part (a)​ is 4 m/s².

x = at²i + btj

x = 2t²i + tj

Δv = Δx/Δt

x(2) = 2(2)²i + 2j

x(2) = 8i + 2j

|x(2)| = √(8² + 2²) = 8.246

x(3) =  2(3)²i + 3j

x(3) = 18i + 3j

|x(3)| = √(18² + 3²) = 18.248

Δv = (18.248 - 8.246)/(3 - 2)

Δv =  10 m/s

x = at²i + btj

v = dx/dt

v =  (2ati + bj) m/s

a = dv/dt

a = 2ai m/s²

a = 2ai m/s²

a = 2(2)(1)

a = 4 m/s²

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Answer:

a force of acts on a body of mass 50 kg for 10 sec when the first of acting on the body the body covers 80 and in the next 10 second

Answer:

a = 0.4 ms⁻²

Explanation:

• First calculate the resultant force on the body:

If we consider upwards to be the positive direction and downwards to be the negative direction, then the resultant force will be:

F = +100 + (-80)

  = +20 N

The resultant force is positive, so it will act upwards.

• Next calculate the acceleration:
F = ma

a = F/m

a = 20/ 50

a = 0.4 ms⁻²

As the force is acting upwards, the acceleration will also be upwards.

The amount of current in the blood sample is determined as 0.12 A.

The current in the blood is calculated by applying Ohm's law as shown below;

V = IR

where;

From resistivity chart corresponding to 0.98 g/L, resistance, R = 7.4

I = V/R

I = 0.9 /7.4

I = 0.12 A

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Answer:

B

Explanation:

i's 100% paset bro.....

Answer:

D. 3 cm

Wavelength is the distance between two crests or two troughs.

In the given picture, the distance between two adjacent crests is 3 cm.

Hence, the wavelength is 3 cm.

The acceleration of this sled can be calculated by doing: option A, B, E and F.

The acceleration of this sled can be calculated by using Newton's Second law of motion. Mathematically, the acceleration of an object is given by this formula:

Net force = Mass × acceleration

Deductively, the acceleration of this sled can be calculated by doing the following:

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Complete Question:

A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 n. What must be done to find the acceleration of the sled? check all that apply.

A. The force of gravity must be broken into its parallel and perpendicular components.

B. Acceleration can be found by dividing the net force by mass.

C. Acceleration can be found by multiplying the net force by mass.

D. The magnitude of the force components must be multiplied by gravity.

E. Trigonometry can be used to solve for the magnitude of the force components.

F. Net force must be found before acceleration can be found.

Answer:

To find the acceleration, you do 20N/50kg = 0.4 m/s^2

Explanation:

example: a = F/m = 10/2 = 5 m/s2

The bomb strike the ground relative to the point at 1km . B

Using the equation

h = 1/2 gt^2

500 = 1/2 * 10* t^2

500 = 5t^2

t = √500/5

t = √100

t = 10seconds

To find the distance,

Distance = velocity * time

Distance = 100 ÷ 10

Distance = 1000m = 1km

Therefore, the bomb strike the ground relative to the point at 1km . B

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Hello!

Recall the period of an orbit is how long it takes the satellite to make a complete orbit around the earth. Essentially, this is the same as 'time' in the distance = speed * time equation. For an orbit, we can define these quantities:

[tex]d = 2\pi r[/tex] ← The circumference of the orbit

speed = orbital speed, we will solve for this later

time = period

Therefore:

[tex]T = \frac{2\pi r}{v}[/tex]

Where 'r' is the orbital radius of the satellite.

First, let's solve for 'v' assuming a uniform orbit using the equation:
[tex]v = \sqrt{\frac{Gm}{r}}[/tex]

G = Gravitational Constant (6.67 × 10⁻¹¹ Nm²/kg²)

m = mass of the earth (5.98 × 10²⁴ kg)

r = radius of orbit (1.276 × 10⁷ m)

Plug in the givens:
[tex]v = \sqrt{\frac{(6.67*10^{-11})(5.98*10^{24})}{(1.276*10^7)}} = 5590.983 m/s[/tex]

Now, we can solve for the period:

[tex]T = \frac{2\pi (1.276*10^7)}{5590.983} =\boxed{ 14339.776 s}[/tex]

Answer:

Explanation:

missing info .....

The Total assets based on the given table is $88,800.

An asset refers to a resource owned by an individual or company which has tangible value and whose value is expected to rise in the future.

The Total assets based on the table = Cash + Supplies + Prepaid rent + Equipment

Total assets = 13,100 + 6,000 + 3,800 + 65,900

Total assets = $88,800

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Answer:

a (2m)

Explanation:

according to wavelenght = speed / frequency,

the wavelength is 2 m

Bianca is helping the theatre director at her school with lighting, sound, and set design for a school play. She will be choosing the materials that will be used on stage and on the walls of the theatre the materilas neee to be changes is The only lights available are white, purple, and yellow.

A proper echo is a single mirrored image of the sound source. The phrase echo derives from the Greek ἠχώ (ēchō), itself from ἦχος (ēchos), "sound". Echo withinside the Greek peoples tale is a mountain nymph whose cappotential to talk changed into cursed, leaving her capin a position handiest to copy the ultimate phrases spoken to her.

Bianca draws a detailed illustration of her plan to show the theatre director. She labels it with the materials she plans to use the  only lights available are white, purple, and yellow should be removed as to avoid the light refraction.

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The side of this cube will be 2.9996 cm. The net force on the solid cube is acting upward.

What is buoyancy force?

A fluid exerts an upward force against the weight of a partly or completely submerged item. The weight of the overlying fluid causes pressure to rise with depth in a column of fluid.

Given data;

Actual weight.W=0.714 N

Apparent weight,W'=0.450 N

The density of water,ρ=1000 kg/m³

The net force on the solid cube is;

Apparent weight = actual weight - buoyancy force

Buoyancy force = Actual weight - apparent weight

F=W-W'

F = 0.714 - 0.450

F= 0.264 N

The buoyancy force(F) is found as;

F = ρgV

0.264 = 1000 × 9.81 × V

V=2.69 × 10⁺⁵

The volume of a cube is found as;

V=a³

2.69 × 10⁺⁵ m³=a³

a=0.02996 m

As we know that 1 m = 100 cm

a=2.996 cm

Hence, the side of this cube will be 2.9996 cm.

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(a) A graph of u as a function of position (r) along the line between the two planets is attached below.

(b) The minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]

If an object is lifted, work is done against gravitational force. The object gains energy.

Given are two planets, both of mass m, are separated by a distance d. Their relative velocity is negligible, and there is an inertial frame in which both planets are essentially at rest. The gravitational potential u(r) at the position r in the presence of the two planets, located at R1 and R2, is given as

u(r) = − (Gm /R1 −r) − (Gm / R2 −r) .

This problem takes place far out in space and there are no other massive objects in the vicinity of the two planets

(a) A graph of u (r)  versus position (r) along the line between the two planets is attached in answer.

(b) There are space stations Alpha and Beta located on the line between the planets. Both space stations are at rest with respect to the planets. Alpha is at distance d 4 from planet 1 and Beta is at distance d 3 from planet 2. A projectile of mass m is fired from station Alpha, with its velocity v pointing directly at planet 2.

The range of the projectile is given by R =  v²sin2θ / g

g = gravitational acceleration of Earth

If g = g(p) for planet , range  R =  v²sin2θ / g(p)..................(1)

The gravitational force of attraction = weight force

Gm² /d² = m g(p)

g(p) = Gm/d².........................(2)

For R = d/3, from equation (1), we have

d/3 =  v²sin2θ / g(p)

Plug the expression for g(p) , we get

v = √ [Gm/3dsin2θ ]

For velocity to be minimum, sin2θ =1

So, the minimum velocity will be

v = √ [Gm/3d]

Thus, the minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]

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