Answer:
Atom is the smallest particle of pure sustance which can take part in a chemical reaction.A chrged atom is called an ion.
A molecule of an element or compound is the smallest particle of it that is stable and capable of independent existence. The molecules of element and compound are different.
What do sponges eat?
Answer:
crabby patties I'm not good at english probably spelled that wrong
explain why metals above zinc in activity series of metals are extracted from the ores by the electrolysis?
Answer:
Metals above zinc in the reactivity series are too reactive to be extracted by heat- ing with carbon or carbon monoxide gas. In this extraction process the metal ions are reduced and the carbon is oxidised. Both iron and copper can be extracted from the ore by heating with carbon.
Explanation:
ok?
Why do you think Democritus and dalton are grouped together
Democritus and Dalton are grouped together because they had similar opinion about the existence of atom.
Who is Democritus?Democritus is an ancient Greek philosopher who is remembered for his formulation of an atomic theory.
Who is Dalton?Dalton is an english chemist who is known for introducing the theory of atom to chemistry.
What is an atom?An atom is the smallest unit of matter.
According to Democritus's theory of atom, all matter is made up of tiny particles called atoms and according to Dalton all matter is made up of tiny indivisible particles called matter.
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construct
an isotope has 17 protons 20 neutrons and 18 electrons
To solve this we must be knowing each and every concept related to isotope and its example. Therefore, the corresponding isotope is ₁₇Cl³⁷.
What are isotope?Each atom contains the exact same quantity of electrons like protons, but isotopes differ somewhat; they contain the very same amount of electrons as well as protons but differing quantities of neutrons.
Isotopes, on the other hand, possess the same atomic number as well as the same location in the periodic table, but they have unique atomic weights. These isotopes will deteriorate over time and transform into some other isotope or element. The majority of elements discovered in nature are composed of stable isotopes.
number of proton +number of neutrons = Mass number = 37
number of proton=atomic number= 17
The corresponding isotope is ₁₇Cl³⁷.
Therefore, the corresponding isotope is ₁₇Cl³⁷.
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How much energy (heat) is required to convert 248 g of water from 0 oC to 154 oC? Assume that the water begins as a liquid, that the specific heat of water is 4.184 J/goC over the entire liquid range, that the specific heat of steam is 1.99 J/goC, and the heat of vaporization of water is 40.79 kJ/mol.
Answer:
The total heat required is 691,026.36 J
Explanation:
Latent heat is the amount of heat that a body receives or gives to produce a phase change. It is calculated as: Q = m. L
Where Q: amount of heat, m: mass and L: latent heat
On the other hand, sensible heat is the amount of heat that a body can receive or give up due to a change in temperature. Its calculation is through the expression:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the change in temperature (Tfinal - Tinitial).
In this case, the total heat required is calculated as:
Q for liquid water. This is, raise 248 g of liquid water from O to 100 Celsius. So you calculate the sensible heat of water from temperature 0 °C to 100° CQ= c*m*ΔT
[tex]Q=4.184\frac{J}{g*C} *248 g* (100 -0 )C[/tex]
Q=103,763.2 J
Q for phase change from liquid to steam. For this, you calculate the latent heat with the heat of vaporization being 40 and being 248 g = 13.78 moles (the molar mass of water being 18 g / mol, then[tex]\frac{248 g}{18 \frac{g}{mol} } =13.78 moles[/tex] )Q= m*L
[tex]Q=13.78moles*40.79 \frac{kJ}{mol}[/tex]
Q=562.0862 kJ= 562,086.2 J (being 1 kJ=1,000 J)
Q for temperature change from 100.0 ∘ C to 154 ∘ C, this is, the sensible heat of steam from 100 °C to 154°C.Q= c*m*ΔT
[tex]Q=1.99\frac{J}{g*C} *248 g* (154 - 100 )C[/tex]
Q=25,176.96 J
So, total heat= 103,763.2 J + 562,086.2 J + 25,176.96 J= 691,026.36 J
The total heat required is 691,026.36 J
The specific heat can be defined as the amount of heat required to raise the temperature of one gram of substance by one degree Celsius. The total heat of the reaction has been 691.029 kJ.
What is heat of vaporization?The heat of vaporization is the amount of heat required to convert the liquid to the vapor state.
The water at 0 degree Celsius has been converted to the water at 100 degree Celsius. The 100 degree Celsius water vaporized to 100 degree steam. The 100 degree steam will be converted to the 154 degree Celsius.
The conversion of 0 degree Celsius water to 100 degree Celsius
[tex]Q_1=mc\Delta T[/tex]
Substituting the values of mass ([tex]m[/tex]), specific heat ([tex]c[/tex]), and change in temperature ([tex]\Delta T[/tex]):
[tex]Q_1=248\;\times\;4.184\;\times\;(100-0)\\Q_1=103,763.2\;\text J\\Q_1=103.7632\;\rm k\text J[/tex]
The amount of heat required to convert 100 degree Celsius water to 100 degree Celsius steam has been:
[tex]Q_2=mL[/tex]
Substituting the values of mass ([tex]m[/tex]), and heat of vaporization ([tex]L[/tex]):
[tex]Q_2=248\;\times\;40.79\\Q_2-562.0862\;\rm kJ[/tex]
The amount of heat required to convert 100 degree Celsius steam to 154 degree Celsius steam has been:
[tex]Q_3=mc\Delta T[/tex]
Substituting the values of mass ([tex]m[/tex]), heat of steam ([tex]c[/tex]), and change in temperature ([tex]\Delta T[/tex]):
[tex]Q_3=248\;\times\;1.99\;\times\;(154-100)\\Q_3=25,176.96 \;\text J\\Q_3=25.1796\;\rm kJ[/tex]
The total amount of heat in the reaction has been:
[tex]Q=Q_1+Q_2+Q_3[/tex]
Substituting the values for the total heat of the reaction:
[tex]Q=103.7632+562.0862+25.1796\;\rm kJ\\\textit Q=691.029\;kJ[/tex]
The total heat of the reaction for the conversion of water from 0 degree Celsius to 100 degree Celsius is 691.029 kJ.
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A hiker caught in a thunderstorm loses heat when her clothing becomes wet. She has emergency rations that if completely metabolized will release 35 kJ of heat per gram of rations consumed. How much rations must the hiker consume to avoid a reduction in body temperature of 2.5 K as a result of heat loss? Assume the heat capacity of the body equals that of water and that the hiker weighs 50.0 kg. State any additional assumptions.
Answer:
Amount of required rations ≥ 15 g
Other assumptions made:
1. All the energy released from the rations is converted to heat
2. All the rations is completely metabolized to release energy
3. No other heat losses occur in the body except due to wetness of her clothing.
Explanation:
Using H = mcθ
where m is mass of the hiker in Kg,
c is specific heat capacity of water/hiker = 4200 JKg⁻¹K⁻¹
θ is temperature change in K
Note : heat capacity of water = specific heat capacity x molar mass
specific heat capacity = heat capacity / molar mass
c = 75.348 JK⁻¹mol⁻¹/18 x 10⁻³ Kgmol⁻¹ = 4186 JKg⁻¹K⁻¹ ≅ 4200 JKg⁻¹K⁻¹
Heat lost, H = 50.0 Kg x 4200 JKg⁻¹K⁻¹ x 2.5 K
H = 5.25 x 10⁵ J = 525 KJ
To avoid this heat loss, the hiker must consume enough emergency rations that releases heat equal to or greater than the heat loss due to wetness of her clothing.
Energy per gram of rations = 35 KJ
Amount of required rations ≥ 525 KJ / 35 KJ/g
Amount of required rations ≥ 15 g
Therefore, the hiker must consume 15 g or more of her emergency rations.
Other assumptions made:
1. All the energy released from the rations is converted to heat
2. All the rations is completely metabolized to release energy
3. No other heat losses occur in the body except due to wetness of her clothing.
which choice is not an example of a molecule
Mn
O3
KOH
H2S
Answer:
The answer to your question is A | Mn
3. Classify each of the following as a physical or a
chemical property
a. Iron and oxygen form rust.
b. Iron is more dense than aluminum.
C. Magnesium burns brightly when ignited.
d. Oil and water do not mix.
e Mercury melts at -39°C.
The classification of the following elements as a physical or chemical property is shown below
a) iron and oxygen form rust
b)iron is more dense than aluminum
c) magnesium burns brightly when ignited
d)oil and water do not mix
e)mercury melts as -39 C
A. Chemical
B. Physical
C. Chemical
D. Physical
E. Physical
For better understanding let's explain what the statement that
Physical Property is simply known as any features of a material that can be observed or measured even without changing the composition of the substances in the materialChemical Property is commonly known as a features of matter that can be observed as it alters to a different type of matter.From the above we can therefore say that the answer The classification of the following elements as a physical or chemical property is shown below;
a) iron and oxygen form rust
b)iron is more dense than aluminum
c) magnesium burns brightly when ignited
d)oil and water do not mix
e)mercury melts as -39 C
A. Chemical
B. Physical
C. Chemical
D. Physical
E. Physical
is correct
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The United Nations hires a global firm to study digital communications around the world. Here is what that firm wrote based on its research. Many people in the world have little experience with computers, and only one-fifth of the world’s population has Internet access. The differences in the ability to use this technology make it challenging to reach people from around the world. The firm’s findings are best described as the digital divide. inequality divide. Internet divide. computer divide.
Answer:
The answer is digital divide.
Explanation:
Digital divide is the answer because if there is only one-fifth of the world that has computers then the United Nations cannot communicate with everyone ,so there is a digital divide and that is your answer. Also, I took the test and I got the question right.
Answer:
The answer is digital divide.
Explanation:
Digital divide is the answer because if there is only one-fifth of the world that has computers then the United Nations cannot communicate with everyone ,so there is a digital divide and that is your answer. Also, I took the test and I got the question right.
2. A student wishes to find the density of an irregularly shaped rock. He finds the mass to be 12.34
g. He fills a graduated cylinder to the 50.0 mL mark and drops in the rock. The fluid level rises to
54.5 mL. What is the density of the rock? (Show all work, with units, for credit.)
Answer:
The answer is
2.74 g/mLExplanation:
The Density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} [/tex]
From the question
mass of rock = 12.34 g
volume = final volume of water - initial volume of water
volume = 54.5 mL - 50 mL = 4.5 mL
So the density is
[tex]density = \frac{12.34}{4.5} \\ = 2.744444444...[/tex]
We have the final answer as
2.74 g/mLHope this helps you
Which of the following describes a particle that contains
36 electrons, 49 neutrons, and 38 protons?
an ion with a charge of 2-
an ion with a charge of 2+
an atom with a mass of 38 amu
an atom with a mass of 49 amu
Od
Answer:
an ion with charge of 2+
Explanation:
proton and electron numbers do not cancel out...
it has 2 more protons than electrons.
since protons carry a positive charge, a charge of 2+ is now carried by the ion.
it is no longer called an atom as the charges do not cancel out.
Answer: An ion with a charge of +2.
Explanation:
Blood plasma contains a total carbonate pool of 0.0252M.
(a) What is the HCO3"/CO2 ratio
(b) What is the concentration of each buffer component present at pH=7.4
(c) What would the pH be if 0.01M H" is added assuming that the excess CO2 is not
released.
(d) What would the pH be if 0.01M H is added assuming that the excess CO2 is released.
Answer:
a what is the HCO3"/CO2 ratio
A certain sample of rubidium has just two isotopes, 85Rb (mass = 84.911amu) and 87Rb (mass = 86.909amu). The atomic mass of this sample is 86.231 amu. What are the percentages of the isotopes in this sample?
Answer:
[tex]\%_{Rb-85}=33.9\%[/tex]
[tex]\%_{Rb-87}=66.1\%[/tex]
Explanation:
Hello,
In this case, for the natural occurring isotopes we equal the average atomic mass via:
[tex]86.231=84.911*\%_{Rb-85}+86.909*\%_{Rb-87}[/tex]
Thus, since both percentages of abundance must turn out 100%, we can write:
[tex]\%_{Rb-85}+\%_{Rb-87}=100\%\\\\\%_{Rb-85}=100\%-\%_{Rb-87}[/tex]
So we can write:
[tex]86.231=84.911*(100\%-\%_{Rb-87})+86.909*\%_{Rb-87}[/tex]
Solving for the percentage of abundance of Rb-87:
[tex]86.231=84911.00\%-84.911\%_{Rb-87}+86.909*\%_{Rb-87}\\\\\%_{Rb-87}=\frac{86.231-84.911}{-84.911+86.909}\\ \\\%_{Rb-87}=66.1\%[/tex]
Therefore, the percentage of abundance of Rb-85 turns out:
[tex]\%_{Rb-85}=100\%-66.1\%\\\\\%_{Rb-85}=33.9\%[/tex]
Best regards.
Considering the definition of atomic mass, isotopes and atomic mass of an element, the percentages of the isotopes in this sample are:
percent of Rb-87= 66.07%percent of Rb-85 = 33.93%
First of all, the atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus of a chemical element.
The same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element.
On the other hand, the atomic mass of an element is the weighted average mass of its natural isotopes. In other words, the atomic masses of chemical elements are usually calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.
In this case, a certain sample of rubidium has just two isotopes, 85Rb (mass = 84.911amu) and 87Rb (mass = 86.909amu). Then, the average mass of lithium can be calculated as:
84.911× percent of Rb-85 + 86.909× percent of Rb-87= 86.231
Since both abundance percentages must be 100%, you can write:
percent of Rb-85 + percent of Rb-87= 100
Then:
percent of Rb-85 = 100% - percent of Rb-87
So, replacing this expression in the first equation:
84.911× (100% - percent of Rb-87) + 86.909× percent of Rb-87= 86.231
Solving:
84.911×100% - 84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231
8491.1% -84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231
-84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231 - 8491.1%
-84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231 - 84.911
1.998× percent of Rb-87= 86.231 - 84.911
1.998× percent of Rb-87= 1.32
percent of Rb-87= 1.32÷ 1.998
percent of Rb-87= 0.6607
percent of Rb-87= 66.07%
Therefore, the percentage of abundance of Rb-85 is:
percent of Rb-85 = 100% - percent of Rb-87
percent of Rb-85 = 100% - 66.07%
percent of Rb-85 = 33.93%
Finally, the percentages of the isotopes in this sample are:
percent of Rb-87= 66.07%percent of Rb-85 = 33.93%Learn more:
brainly.com/question/14403750?referrer=searchResults brainly.com/question/10043246?referrer=searchResults brainly.com/question/15553207?referrer=searchResultsA 250ml aqueous solution contains 45.1microgram of pesticide.express the pesticide concentration in:
1 .weight percent
2.parts per thousand
3.parts per million
please help its urgent
Answer:
1. 1.80x10⁻⁵ (w/w %).
2. 1.80x10⁻⁴ parts per thousand
3. 0.18 parts per million
Explanation:
The solution contains 45.1μg / 250mL.
1. Weight percent (100 times mass in grams of solute per gram of solution, as there are 250mL of water = 250g):
45.1x10⁻⁶g / 250g * 100 =
1.80x10⁻⁵ (w/w %)2. Parts per thousand (mg of solute per g of solution).
45.1μg * (1x10⁻³mg / 1μg) = 0.0451mg.
0.0451mg / 250g =
1.80x10⁻⁴ parts per thousand3. Parts per million (μg of solute per g of solution):
45.1μg / 250g =
0.18 parts per million0.73 grams of toluene was reacted with 2.0 grams of potassium permanganate in presence of 7.0 mL of 6 Molar potassium hydroxide and 30 mL of water. After refluxing for 1 hour the reaction mixture was treated with 6 Molar sulfuric acid to pH~ 2.0 followed by oxalic acid. On cooling this solution in an ice bath 0.633 grams of pure benzoic acid was obtained. Calculate the % yield of benzoic acid in this reaction.
Answer:
The value is [tex]k =66\%[/tex]
Explanation:
From the question we are told that
The mass of toluene [tex] m_t =0.73 \ g [/tex]
The mass of potassium permanganate is [tex] m =2.0 \ g [/tex]
The volume of potassium hydroxide V = 7.0 mL
The concentration of potassium hydroxide C = 6 M
The mass of benzoic acid is [tex]m_b = 0.633 \ g[/tex]
Generally the % yield of benzoic acid is mathematically represented as
[tex]k = \frac{m_b}{Z} * 100[/tex]
Here Z is the theoretical yield which is mathematically represented as
[tex]Z = \frac{E}{W} * m_t [/tex]
Here W is the molecular weight of product (benzoic acid) with value
W = 92.14 \ g
E is the molecular weight of reactant (toluene)with a constant value of
E = 122.12 g
So
[tex]Z = \frac{122.12 }{92.14} * 0.73 [/tex]
=> [tex]Z = 0.968 \ g [/tex]
So
[tex]k = \frac{0.633}{0.968} * 100[/tex]
=> [tex]k =66\%[/tex]
A student measures the mass of a substance as 1.7132 kg and it’s volume as 0.65 L. What is the density of the substance in g/mL? Round your answer to the correct number of significant figures.
Answer:
[tex]\rho =2.6g/mL[/tex]
Explanation:
Hello,
In this case, considering that the density is defined as:
[tex]\rho =\frac{m}{V}[/tex]
Thus, since 1 kg equals 1000 g and 1 L equal 1000 mL, the required density in g/mL turns out:
[tex]\rho =\frac{1.7132kg}{0.65L}*\frac{1000g}{1kg}*\frac{1L}{1000mL} \\\\\rho=2.6g/mL[/tex]
Take into account that since 0.65 L has two significant figures, the result is also shown with two significant figures.
Regards.
What is the steps of the photosynthetic equation?
Answer: The photosynthesis equation is as follows: 6CO2 + 6H20 + (energy) → C6H12O6 + 6O2 Carbon dioxide + water + energy from light produces glucose and oxygen.
Explanation: Photosynthesis is comprised of two stages, the light-dependent reaction and the light-independent reactions, so that for the light suports energy.
Hope this helps:)
If a soft-drink bottle whose volume is 1.10 L is completely filled with water and then frozen to -10 ∘C, what volume does the ice occupy? Water has a density of 0.997 g/cm3 at 25 ∘C; ice has a density of 0.917 g/cm3 at -10 ∘C.
Answer:
The ice occupies a volume of 1.196 liters at -10 ºC.
Explanation:
We must remember that density ([tex]\rho[/tex]), measured in grams per cubic centimeters, is the ratio of mass ([tex]m[/tex]), measured in grams, to occupied volume ([tex]V[/tex]), measured in cubic centimeters, that is:
[tex]\rho = \frac{m}{V}[/tex]
We clear the mass within the formula:
[tex]m = \rho\cdot V[/tex]
The mass of the water inside the soft-drink bottle is: ([tex]\rho = 0.997\,\frac{g}{cm^{3}}[/tex] and [tex]V = 1100\,cm^{3}[/tex])
[tex]m =\left(0.997\,\frac{g}{cm^{3}} \right)\cdot (1100\,cm^{3})[/tex]
[tex]m = 1096.7\,g[/tex]
There are 1096.7 grams of water filling the soft-drink bottle completely.
Then, the water is frozen to -10 ºC and transformed into ice, the volume occupied by the ice which we can deduct from definition of density. That is:
[tex]V = \frac{m}{\rho}[/tex]
The volume occupied by the ice inside the soft-drink bottle is: ([tex]m = 1096.7\,g[/tex] and [tex]\rho = 0.917\,\frac{g}{cm^{3}}[/tex])
[tex]V = \frac{1096.7\,g}{0.917\,\frac{g}{cm^{3}} }[/tex]
[tex]V = 1195.965\,cm^{3}\,(1.196\,L)[/tex]
The ice occupies a volume of 1.196 liters at -10 ºC.
An object has a mass of 33g and a volume of 11ml. What is it's density?
Answer:
3g/ml
Explanation:
Density = [tex]\frac{33g}{11ml}[/tex]
33 divided by 11 = 3
A certain gas obeys the van der Waals equation with a = 0.50 m6 Pa mol−2. Its molar volume is found to be 5.00 × 10–4 m3 mol−1 at 273 K and 3.0 MPa. From this information calculate the van der Waals constant b. What is the compression factor for this gas at the prevailing temperature and pressure?
Answer:
a
The value is [tex]b = 4.61 *10^{-5} \ m^3 /mol[/tex]
b
[tex]Z = 0.66[/tex]
Explanation:
Generally the pressure of the gas is mathematically represented as
[tex]P = \frac{RT}{V_m -b} - \frac{a}{(V_m)^2}[/tex]
Substituting [tex]8.314 \ m^3\cdot Pa\cdot K^{-1}\cdot mol^{-1}[/tex] for R , 273K for T , [tex]5.00 * 10^{-4} m^3[/tex] for [tex]V_m[/tex] , [tex]0.50 \ m^6 \cdot Pa\cdot mol^{-2}[/tex] for a and [tex]3.0 MPa = 3.0*10^{9} \ Pa[/tex] for P
We have
[tex]3*10^6 = \frac{8.314 * 273}{5.00*10^{-4} - b} - \frac{0.50}{(5.00*10^{-4})^2 }[/tex]
=> [tex]b = 4.61 *10^{-5} \ m^3 /mol[/tex]
Generally the compression factor is mathematically represented as
[tex]Z = \frac{P* V_m }{RT}[/tex]
=> [tex]Z = \frac{3.0 *10^{6}* 5.0 *10^{-4} }{8.314 *273}[/tex]
=> [tex]Z = 0.66[/tex]
what density will an object have if the mass of it ia 46g and it takes up 561 mL of space?
in an investigation that uses the scientific method which step immediately follows asking a question
Answer:
Infer and form a hypothesis
For which initial concentration of chromate anion would[Ag +] = 6.0 x 10^ -6 M and cause the solution to begin to preciitate Ag2CrO4(s)? Where Ksp = 9.0 x 10^-12
Ag2CrO4 --> 2Ag+ + CrO4(-2)
a. 0.08
b. 0.11
c. 0.21
d. 0.25
Answer:
d. 0.25.
Explanation:
Hello,
In this case, since the equilibrium repression for the considered chemical reaction is:
[tex]Ksp=[Ag^+]^2[CrO_4^{2-}][/tex]
For a concentration of silver of 6.0x10⁻⁶ we need a concentration of chromate anion that makes the reaction quotient greater than the solubility product, thus, we write:
[tex][CrO_4^{2-}]=\frac{Ksp}{[Ag^+]^2} =\frac{9.0x10^{-12}}{(6.0x10^{-6})^2}[/tex]
[tex][CrO_4^{2-}]=0.25M[/tex]
It means that at concentrations of chromate anion of 0.25 M or more, the reaction quotient Q becomes greater than the solubility product which means that precipitation will begin occurring, therefore, answer is d. 0.25.
Best regards.
Which of the scientists reponsible for cell theory would be the most likely to write a book titled cells come from cells
Answer:
Matthias Schleiden and Theodor Schwann. However, many other scientists like Rudolf Virchow contributed to the theory.
Explanation:
Answer:Theodor Shwann
Explanation:
1. Convert each of the following into scientific notation.
Answer:
[tex]7.27[/tex] x [tex]10^{2}[/tex]
[tex]1.72[/tex] x [tex]10^{5}[/tex]
[tex]9.84[/tex] x [tex]10^{-4}[/tex]
[tex]2[/tex] x [tex]10^{4}[/tex]
[tex]1.4[/tex] x [tex]10^{0}[/tex]
[tex]2.560[/tex] x [tex]10^{33}[/tex]
List the inner planets in order from the closest to th
Answer : The inner planets (in order of distance from the sun, closest to furthest) are Mercury, Venus, Earth and Mars. After an asteroid belt comes the outer planets, Jupiter, Saturn, Uranus and Neptune. The interesting thing is, in some other planetary systems discovered, the gas giants are actually quite close to the sun.
Answer:
Mercury
venus
earth
mars
jupiter
saturn
uranus
Neptune
Explanation:
At liftoff, a space shuttle uses a solid mixture of ammonium perchlorate and aluminum powder to obtain great thrust from the volume change of solid to gas. In the presence of a catalyst, the mixture forms solid aluminum oxide and aluminum chloride and gaseous water and nitrogen monoxide.A. Write a balanced equation for the reaction, assign oxidation states for all atoms, and identify the reducing and oxidizing agents.B. How much aluminum oxide can you make when you react 150.0 g of ammonium perchlorate with 50.0 g of powdered aluminum
Answer:
A) 3NH₄ClO₄ + 3Al ---> Al₂O₃ + AlCl₃ + 6H₂O + 3NO
B) 150 g of ammonium perchlorate will produce 43.4 g of aluminum oxide
Explanation:
A)Balanced equation of reaction:
3NH₄ClO₄ + 3Al ---> Al₂O₃ + AlCl₃ + 6H₂O + 3NO
Oxidation states:
Nitrogen, N: from -3 to +2
Hydrogen, H: from +1 to +1
Chlorine, Cl: From +7 to -1
Oxygen, O: from -2 t0 -2
Aluminum, Al: from 0 to +3.
Oxidizing agent is ammonium perchlorate while the reducing agent is the aluminum powder.
B) molar mass of aluminum oxide = 102 g/mol; molar mass of ammonium perchlorate =117.5 g/mol
From the equation of reaction 3 moles of ammonium perchlorate reacts with 3 moles of aluminum to produce 1 mole of aluminum oxide;
that is 3 * 117.5 g of ammonium perchlorate reacts with 3 * 27 g of aluminum to produce 102 g/mol of aluminum oxide
150 g of ammonium perchlorate will react with (150 * 3*27) / (3 * 117.5) of aluminum = 34.47 g of Al
Ammonium perchlorate is the limiting reactant.
150 g of ammonium perchlorate will produce (150 * 102)/(3*117.5) g of aluminum oxide = 43.4 g of aluminum oxide
The branch of science that deals with chemicals and bonds are called chemistry. Chemistry deals with the physical and chemical behavior of the element.
The correct answer to the question is [tex]3NH_4ClO_4 + 3Al ---> Al_2O_3 + AlCl_3 + 6H_2O + 3NO[/tex]
B) 150 g of ammonium perchlorate will produce 43.4 g of aluminum oxide
What is the balanced reaction?A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge are the same for both the reactants and the products. In other words, the mass and the charge are balanced on both sides of the reaction.Oxidation states:Nitrogen, N: from -3 to +2Hydrogen, H: from +1 to +1Chlorine, Cl: From +7 to -1Oxygen, O: from -2 t0 -2Aluminum, Al: from 0 to +3.The oxidizing agent is ammonium perchlorate while the reducing agent is the aluminum powder.
B) molar mass of aluminum oxide = 102 g/mol; molar mass of ammonium perchlorate =117.5 g/mol. From the equation of reaction 3 moles of ammonium perchlorate reacts with 3 moles of aluminum to produce 1 mole of aluminum oxide;
That is[tex]3 * 117.5[/tex] g of ammonium perchlorate reacts with [tex]3 * 27[/tex]g of aluminum to produce 102 g/mol of aluminum oxide. 150 g of ammonium perchlorate will react with [tex]\frac{(150 * 3*27) }{ (3 * 117.5)}[/tex] of aluminum = 34.47 g of Al
Ammonium perchlorate is the limiting reactant.
150 g of ammonium perchlorate will produce (150 * 102)/(3*117.5) g of aluminum oxide
= 43.4 g of aluminum oxide.
Hence, the correct answer is 4.34g.
For more information about the balanced reaction, refer to the link:-
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For double-helix formation, change in Gibbs free energy, ΔG, can be measured to be −54 kJ⋅mol−1 (−13 kcal⋅mol−1) at pH 7.0 in 1 M NaCl at 25 °C (298 K). The heat released indicates an enthalpy change of -251 kJ/mol (-60 kcal/mol). For this process, calculate the entropy change for the system and the entropy change for the surroundings.
Answer:
Explanation:
Entropy change in the system : --
ΔG = −54 kJ⋅mol−1 (−13 kcal⋅mol−1) = −54 kJ⋅mol−1 (−13 x 4.2 kJ⋅mol−1)
= - 108.6 KJ / mol
ΔH = -251 kJ/mol (-60 kcal/mol) = -251 kJ/mol (-60 x 4.2 kJ/mol)
= - 503 KJ / mol
ΔG = ΔH - TΔS
ΔS = ( ΔH - ΔG ) / T
= - 503 + 108.6 / ( 273 + 25 ) KJ / mol k⁻¹
= - 1323.48 J / mol k⁻¹
Entropy change in the surrounding
+ 1323.48 J / mol k⁻¹
Which particles affect the stability in of the atom
The stability of an atom is affected by the balance between the electrons, protons, and neutrons in an atom.
What are sub-atomic particles?A particle less than an atom is referred to as a subatomic particle. A subatomic particle can either be an elementary particle, which is not made of other particles, or a composite particle, which is composed of other particles, according to the Standard Model of particle physics.
Particles smaller than an atom are referred to as subatomic particles. The three primary subatomic particles present in an atom are protons, neutrons, and electrons.
Learn more about sub-atomic particles at: https://brainly.com/question/16847839
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Please help
1. The atomic number tells us how many ____________ an element has.
protons
neutrons
electrons
atomic number tells us how many neutrons an element has
