importance of electric circuit​

Answer:

6.5 m/s

Explanation:

We are given that

Distance, s=100 m

Initial speed, u=1.4 m/s

Acceleration, [tex]a=0.20 m/s^2[/tex]

We have to find the final velocity at the end of the 100.0 m.

We know that

[tex]v^2-u^2=2as[/tex]

Using the formula

[tex]v^2-(1.4)^2=2\times 0.20\times 100[/tex]

[tex]v^2-1.96=40[/tex]

[tex]v^2=40+1.96[/tex]

[tex]v^2=41.96[/tex]

[tex]v=\sqrt{41.96}[/tex]

[tex]v=6.5 m/s[/tex]

Hence, her final velocity at the end of the 100.0 m=6.5 m/s

Answer:

6.5

Explanation:

Answer: the last period. i think has the largest energy level

Explanation:

Answer:

honestly?

Explanation:

the atoms changed

Answer:

The magnitude of third force is 74.4 N and direction of third force  is 72.8 degrees South.

Explanation:

Let F1, F2 and F3 are three forces exerted on an object.

[tex]\theta_1=90^{\circ}[/tex]

[tex]\theta_2=60^{\circ}[/tex]

[tex]|F_1|=33 N[/tex]

[tex]|F_2|=44 N[/tex]

We have to find the direction and magnitude of third force i.e F3.

[tex]F_{1x}=33cos(90^{\circ})=0 N[/tex]

[tex]F_{1y}=33sin(90^{\circ})=33 N[/tex]

[tex]F_{2x}=44cos(60^{\circ})=22 N[/tex]

[tex]F_{2y}=44 sin(60^{\circ})=22\sqrt{3}=38.11 N[/tex]

Now,

x-component of  resultant

[tex]R_x=F_{1x}+F_{2x}=0+22=22 N[/tex]

y-component of resultant

[tex]R_y=F_{1y}+F_{2y}=33+38.11=71.11 N[/tex]

[tex]|R|=\sqrt{R^2_x+R^2_y}[/tex]

[tex]|R|=\sqrt{(22)^2+(71.11)^2}=74.4 N[/tex]

[tex]\theta=tan^{-1}(\frac{R_y}{R_x})[/tex]

[tex]\theta=tan^{-1}(\frac{71.11}{22})=72.8^{\circ}[/tex] South

Hence, the magnitude of third force is 74.4 N and direction of third force  is 72.8 degrees South.

The magnitude and direction of the third force is;

F3 = 74.44 N

θ3 = 72.81° in the south direction

We are given;

F1 = 33 N

F2 = 44 N

θ1 = 90°

θ2 = 60°

Let the third force be F3 which will serve as the resultant

Let's first find the x and y component of the forces.

F1x = F1 cos θ1

F1x = 33 × cos 90

F1x = 0 N

F1y = F1 sin θ1

F1y = 33 × sin 90

F1y = 33 N

F2x = F2 cos θ2

F2x = 44 × cos 60

F2x = 22 N

F2y = F2 sin θ2

F2y = 44 × sin 60

F2y = 38.11 N

Thus, the resultant of the x component is;

F3x = F1x + F2x

F3x = 0 + 22

F3x = 22 N

The resultant of the y component is;

F3y = F1y + F2y

F3y = 33 + 38.11

F3y = 71.11 N

Thus, magnitude of resultant of the F3 force is;

F3 = √((F3x)² + (F3y)²)

F3 = √(22² + 71.11²)

F3 = 74.44 N

The direction of the resultant of F3 is;

θ3 = tan^(-1) F3y/F3x

θ3 = tan^(-1) 71.11/22

θ3 = 72.81° in the south direction

Read more about resultant of forces at;

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Answer:five times five is twenty five divded by 10 is 2.5 seconds of acceleration

Answer:

When the motion of an object changes, the forces are unbalanced. Balanced forces are equal in size and opposite in direction. When forces are balanced, there is no change in motion.

Explanation:

Answer:

Tropic of Cancer in the north and the Tropic of Capricorn in the south.

Explanation:

Answer:

Swimmer B had the greatest displacement:)

Explanation:

Hope you do great! :)

brainliest would be nice:)

Answer:

C

Explanation:

Answer:

The position where an earthquake begins below the earths surface is called the hypo center. The point directly above the hypo center is called the epicenter.

Explanation:

www.usga.gov | United States of America Department of Geological Surveys.

If an object must be slowed quickly, the force applied to it must be greater than that required for gradual slowing. For example, the greater the force applied to a bicycle's brakes, the faster it will slow or stop.

A force is an influence in physics that can change the motion of an object. A force can cause a mass object to change its velocity, or accelerate.

Intuitively, force can be described as a push or a pull. A force is a vector quantity because it has both magnitude and direction.

Force is defined as the tendency of a body to modify or change its state as a result of an external cause. When applied force, the body can also change shape, size, and direction.

The same force that was used to accelerate something can be used to slow it down. It will stop faster if more force is applied.

Thus, it can be concluded that it take more force to slow something down than to speed it up.

For more details regarding force, visit:

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#SPJ2

Answer:

there is no momentum

Explanation:

if an object is at rest there is no momentum to build, no speed, no acceleration it does not move unless force is acted upon it.

Answer:

The amount of solid ice remaining after 6 hours is approximately 3.68664 kg

Explanation:

The given parameters are;

The side length of the cube box, s = 3(0) cm = 0.3 m

The thickness of the cube box, d = 5.0 cm = 0.05 m  

The mass of ice in the box, m = 4.0 kg

The outside temperature of the cube box, T₁ = 45°C

The temperature of the melting ice inside the box, T₂ = 0°C

The latent heat of fusion of ice, [tex]L_f[/tex] = 3.35 × 10⁵ J/K/hr/kg

The surface area of the box, A = 6·s² 6 × (0.3 m)² = 0.54 m²

The coefficient of thermal conductivity, K = 0.01 J/s·m⁻¹·K⁻¹

For thermal equilibrium, we have;

The heat supplied by the surrounding = The heat gained by the ice

The  heat supplied by the surrounding, Q = K·A·ΔT·t/d

Where;

ΔT = T₁ - T₂ =  45° C - 0° C = 45° C

ΔT = 45° C

Q = K·A·ΔT·t/d = 0.01 × 0.54 × 45 × 6× 60×60/0.05 = 104976

∴ The  heat supplied by the surrounding, Q = 104976 J

The heat gained by the ice = [tex]L_f[/tex] × [tex]m_{melted \ ice}[/tex] =3.35 × 10⁵ J/kg × [tex]m_{melted \ ice}[/tex]

Therefore, from Q =  [tex]L_f[/tex] × [tex]m_{melted \ ice}[/tex], we have;

Q = 104976 J =  [tex]L_f[/tex] × [tex]m_{melted \ ice}[/tex] = 3.35 × 10⁵ J/kg × [tex]m_{melted \ ice}[/tex]

104976 J = 3.35 × 10⁵ J/kg × [tex]m_{melted \ ice}[/tex]

[tex]m_{melted \ ice}[/tex] = 104976 J/(3.35 × 10⁵ J/kg) ≈ 0.31336 kg

The mass of melted ice, [tex]m_{melted \ ice}[/tex] ≈ 0.31336 kg

∴ The amount of solid ice remaining after 6 hours, [tex]m_{ice}[/tex] = m - [tex]m_{melted \ ice}[/tex]

Which gives;

[tex]m_{ice}[/tex] = m - [tex]m_{melted \ ice}[/tex] = 4.0 kg - 0.31336 kg ≈ 3.68664 kg

The amount of solid ice remaining after 6 hours, [tex]m_{ice}[/tex] ≈ 3.68664 kg.

Answer:

What question?

Explanation:

Answer:

The Football

Explanation:

They have the same velocity, but different shapes and weight. Although the balling ball would be easier to stop (due to slow velocity), but if you see a bowling coming your way in the air, GET OUT OF THE WAY!

Answer:

The orbital radius is approximately 42,259 kilometers.

Explanation:

From Newton's Law of Gravitation we find that acceleration experimented by the satellite ([tex]a[/tex]), measured in meters per square second, is defined by:

[tex]a = \frac{G\cdot M}{r^{2}}[/tex] (1)

Where:

[tex]G[/tex] - Gravitational constant, measured in cubic meters per kilogram-square second.

[tex]M[/tex] - Mass of Earth, measured in kilograms.

[tex]r[/tex] - Orbital radius, measured in meters.

By supposing the satellite rotates at constant speed and in a circular path, we find that acceleration is entirely centripetal and can be defined in terms of period, that is:

[tex]\frac{4\pi^{2}\cdot r}{T^{2}} = \frac{G\cdot M}{r^{2}}[/tex]

[tex]4\pi^{2}\cdot r^{3} = G\cdot M\cdot T^{2}[/tex]

[tex]r^{3} = \frac{G\cdot M\cdot T^{2}}{4\pi^{2}}[/tex]

[tex]r = \sqrt[3]{\frac{G\cdot M\cdot T^{2}}{4\pi^{2}} }[/tex]

Where [tex]T[/tex] is period, measured in seconds.

If we know that [tex]G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}[/tex], [tex]M = 5.98\times 10^{24}\,kg[/tex] and [tex]T = 86400\,s[/tex], then orbital radius of the satellite is:

[tex]r = \sqrt[3]{\frac{\left(6.674\cdot 10^{-11}\,\frac{m^{2}}{kg\cdot s^{2}} \right)\cdot (5.98\times 10^{24}\,kg)\cdot (86400\,s)^{2}}{4\pi^{2}} }[/tex]

[tex]r \approx 42.259\times 10^{6}\,m[/tex]

[tex]r \approx 42.259\times 10^{3}\,km[/tex]

The orbital radius is approximately 42,259 kilometers.

Answer:

Follows are the solution to this question:

Explanation:

In point a:

Place of particles

[tex]X(t)=\int V_{x}(t)dt[/tex]

       [tex]=\int 2t^{2}dt\\\\=\frac{2}{3}t^{3}+C[/tex]

[tex]\to t=0\\\\ \to X(0)=2.3 \ m[/tex]

[tex]\to X(0)=0+C\\\\ \to C=2.3\ m[/tex]

[tex]\to X(t)=( \frac{2}{3})t^3 + 2.3\\\\ \to t=2.2\\\\\to X=( \frac{2}{3})\times 2.2^3 +2.3 \\\\[/tex]

        [tex]= \frac{2}{3}\times 10.648 +2.3\\\\= \frac{21.296}{3}+2.3\\\\ = 7.09+2.3\\\\ =9.39\\\\ =9.4\ m[/tex]

In point b:

when [tex]t=2.2 \ s[/tex]

the Particle velocity  [tex](V)=2 \times 2.22 =9.68\ \frac{m}{s}[/tex]

In point c:

Calculating the Particle acceleration:

[tex]\to a=\frac{dV}{dt} =4\ t\\\\\to t=2.2 \ s\\\\\to a=4\times 2.2 =8.8 \ \frac{m}{s^2}[/tex]

Answer:

False

Explanation:

the total distance of a moving body is always positive

Distance is the total distance between any two points

Answer:

When two players are running full speed at each other on a football field they build up their momentum

Answer:

Explanation:

I hope it helps

Answer:

5Hz

Explanation:

I hope that by stating f you mean frequency

so I think people in this app just like to give answers without explaining so let me try to explain to you why

first of all, you must know the formula

just insert the values in

50 = 10 x frequency

50/10 = frequency

5 = frequency

Answer:

You are given that the mass of the clock M is 95 kg.

This is true whether the clock is in motion or not.

Fs is the frictional force required to keep the clock from moving.

Thus Fk = uk W = uk M g      the force required to move clock at constant speed.     (the kinetic frictional force)

uk = 560 N / 931 N = .644   since the weight of the clock is 931 N  (95 * 9.8)

us  is the frictional force requited to start the clock moving

us = static frictional force = 650 / 931 -= .698

Answer:

1.15*10^-5 kg/m^3

Explanation:

Given data

mass= 1kg

hieght= 40 mm

diameter= 52.5mm

radius= 53.5/2= 26.25mm

The volume of the cylinder

V=πr^2h

V=3.142*26.25^2*40

V=3.142*689.0625*40

V=86601.375 mm^3

Density= mass/volume

Density= 1/86601.375

Density=0.00001154716

Density= 1.15*10^-5 kg/m^3

Hence the density is  1.15*10^-5 kg/m^3

Answer:

Masseter

The masseter runs from the temporal bone (that forms part of the sides and base of the skull) to the lower jaw (the mandible). It lifts the lower jaw, to close the mouth. The masseter is the strongest muscle in your body.

Temporalis

The temporalis begins on two bones of the skull, at the front (the frontal) and at the side and base (the temporal). It runs to the top of the lower jaw (the mandible). Like the masseter, the temporalis helps close the mouth.

Deltoid

The deltoids are the triangular muscles of the shoulder. The strongest point is the central section, which raises the arm sideways. The front and back parts of the muscle twist the arm. Deltoid comes from the Greek word deltoeides, meaning shaped like a (river) delta, which is triangular.

Pectoralis major

(The pecs!) The pectoralis major is a large, fan-shaped muscle. It covers much of the front upper chest, beginning at the breastbone (or sternum) including the second to the sixth ribs.

Adductor Longus

The adductor longus is located on the inner thigh. Adduct means move, so this muscle allows the thigh bone (the femur) to move inward and to the side.

Soleus

Located in the lower leg, the soleus runs from the lower leg bones (the tibia and fibula) to the heel (the calcaneus). The soleus muscle flexes the foot by moving the foot at the ankle. It also helps circulation by pumping blood back up towards the head.

Biceps brachii

The biceps brachii runs from the shoulder to the elbow. It is attached to the shoulder blade (the scapula), and extends along the front surface of the upper arm bone (the humerus). When the bicep contracts, the arm bends at the elbow. Notice that humerus sounds like humour – we call this area of the elbow the funny bone.

The Buccinator

The buccinator muscle compresses the cheek. This muscle allows you to whistle, blow, and suck; and it contributes to the action of chewing.

The Suprahyoid

The suprahyoid muscles raise the hyoid bone, the floor of the mouth, and the larynx during deglutition.

The Splenius

The splenius muscles originate at the midline and run laterally and superiorly to their insertions. From the sides and the back of the neck, the splenius capitis inserts onto the head region, and the splenius cervicis extends onto the cervical region. These muscles can extend the head, laterally flex it, and rotate it.

Answer: 9.81 times 3s= 29.43m/s

so 29.43 m/s times 3= 88.29m

Explanation:

Answer:

Explanation:

Density=mass÷volume

=45÷3

=15

Answer:

naturalistic observation

Explanation: