In a 30cm by 25cm rectangle, a quadrant of a circle of radius 7cm has been cut away from each corner. What is the perimeter of the part left? ​

Answer: A

Heat engine

Explanation: just took the test

Answer:

Explanation:

An electromagnet is obtained by winding an insulated wire round a soft iron rod with the wire ends connected to a DC source. such magnets have temporary magnetic properties which disappears with time as the current supply is cut off.

Furthermore the strength off an electromagnet

Answer:

When energy contained in coal is turned into heat, and then into electrical energy. As boiling water heated by the burning coal is cooled, steam forges from these cone-shaped cooling towers.

Answer: Hope this is right

4 x 10^26 watts every second.

Explanation:

The sun, like all active stars, is a massive hydrogen-burning furnace producing huge amounts of light, heat and radiation, about 4 x 10^26 watts every second.

Answer:

The ratio of the ratio of series and parallel combination​ is n²:1.

Explanation:

The equivalent resistance in case of series combination is given by :

[tex]R_s=R_1+R_2+.....+R_n=nR[/tex] ....(1)

The equivalent resistance in case of parallel combination is given by :

[tex]R_P=\dfrac{1}{R_1}+\dfrac{1}{R_2}+.....+\dfrac{1}{R_n}=\dfrac{R}{n}[/tex] ....(2)

Dividing equation (1) and (2) we get :

[tex]\dfrac{R_s}{R_P}=\dfrac{nR}{R/n}\\\\\dfrac{R_s}{R_P}=\dfrac{n^2}{1}\\\\R_s:R_P=n^2:1[/tex]

So, the ratio of the ratio of series and parallel combination​ is n²:1. Hence, this is the required solution.

n resistance is each of resistance R is first connected in series and then in parallel , the ratio of series and parallel combination​ will be [tex]n^{2}[/tex] : 1

In a series combination, the resistances are connected with end to end in contact, such that current flow is equal in all the resistances in the combination. Whereas in the parallel combination, resistances are connected in such a manner that they get an equal voltage across their ends.

Parallel combination. When two or more resistances are connected between the same two points, they are said to be connected in parallel combination. The reciprocal of the combined resistance of a number of resistances connected in parallel is equal to the sum of the reciprocals of all the individual resistances.

if n number of resistances are connected in series combination .

R (equivalent ) = R1 + R2 + R3 + R4 -------- + Rn

                        = R + R + R + R ---------------- + R

                        = n*R

if n number of resistances are connected in parallel combination .

1/ R (equivalent )  = 1/R1 + 1/R2 + 1/R3 ---------------- 1/Rn

                             = 1/R + 1/R + 1/R + --------------------- 1/R

                             = n/R

R  (equivalent )  = R/n

Ration = series combination / parallel combination

          = n*R / (R/n) = [tex]n^{2}[/tex] /1

           = [tex]n^{2}[/tex] : 1

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OPTION  B IS THE ANSWER

Answer:

The real answer is A 2023 answer -_-

Explanation:

Answer:

The observed temperature was 10º Celsius or 50º Fahrenheit.

Explanation:

The traveler observed that the temperature in Fahrenheit is five times the value of the temperature in Celsius, therefore:

[tex]F = 5*C[/tex]

A Fahrenheit temperature relates to a Celsius one by the following expression:

[tex]F = \frac{9}{5}*C + 32[/tex]

Using the second expression on the first, we can solve for the temperature in Celsius, this is done below:

[tex]\frac{9}{5}*C + 32 = 5*C\\\frac{9}{5}*C - 5*C = -32\\\frac{9*C - 25*C}{5} = -32\\\frac{-16*C}{5} = -32\\-16*C = -32*5\\-16*C = -160\\C = \frac{-160}{-16} = 10\º\text{C}\\F = 5*C = 5*10 = 50\º\text{F}[/tex]

The observed temperature was 10º Celsius or 50º Fahrenheit.

Answer:

Time = 12.43 years

Mass = 4.71.43kg

Explanation:

Given the following :

Distance = 8.7 light years

Speed = 70% the speed of light

Diameter = 6m

Lengtg = 25m

Density = 1 hydrogen atom/m^3

Mass of proton(Me) = 1.673x 10^-27

A.) time it takes your spaceship to reach Sirius :

From the relation: Speed = (distance / time)

Time = distance / speed

Time = (70/100) × 1 light year

Distance = 8.7 light years

Time = 8.7 / 0.7 = 12.4285 years

Time = 12.43 years

B.) Mass of inter-stellar gas that collides with the spaceship can be calcuted by finding the product of the surface area of the cylindrical space ship and the mass of proton.

That is ;

surface area * mass of proton

Surface area of a cylinder = 2πrh + πr^2×Me

= 2πrh + Me×πr^2)

=( 2 × 22/7 × 3 × 25) + (22/7 × 3^2 × 1.673 * 10^-27)

= 2× 235.714 + 28.285) × 1.673 * 10^-27

= 471.428 + 47.31 * 10^-27

= 471.428 + 4.73 × 10^-26

= 4.71.43kg approximately

Newton's law of universal gravitation doesn't say anything about the cause of gravity.

Einstein's theory of relativity does.

party and being happy..........

Answer:

102000N/m2

This is the same as 102KN/m2 (where K = 10^3):

Explanation:

The expression 750 mmHg means 750 height the atmospheric pressure will cause mercury to be suspended due to gravity.

If we brought another fluid under investigation under the influence of the atmospheric pressure the height would be different)

Note that 750 mmHg would be the same as 750/1000 m Hg ( when we convert the mm to m)

0.75mHg

Now to get the pressure in N/m2.

We multiply the height of mercury by the density by the acceleration due to gravity.

This is expressed mathematically thus;

H×d × g ; let d- denote density

Hence we have;

H×d × g = 0.75 × 13600 × 10= 102000N/m2;

Now let's look at the flip.side assuming you don't know the formula for what you require you could use the idea of Unit derivation ;

The unit of interest is N/m2

The unit of height is m

The unit of density is kg/m3

The unit of g is Nkg-1

We would observe if we multiply

m × N/Kg × Kg/m3

We would have (m× N × Kg)/(kg×m3)

Kg cancels out, m cancels out one m from me remaining m2.

Hence our unit becomes N/m2

Note : the unit for density is wrongly expressed remember density is Mass/ volume and their units are respectively kg/m3

The atmospheric pressure on a particular day was measured as 750 mm of Hg. this would be in 102000 N/m²  ( By Assuming the density of

mercury is 13600 kg/m3 and g =10Nkg-1

The total applied force per unit of area is known as the pressure.

The pressure depends both on externally applied force as well the area on which it is applied.

The mathematical expression for the pressure

Pressure = Force /Area

the pressure is expressed by the unit pascal or N /m²

As given in the problem The atmospheric pressure on a particular day was measured as 750 mm of Hg.

Atmospheric pressure is measured by the formula

P = ρgh

where ρ is the density of the mercury

g is the acceleration due to gravity

h is the height of the liquid

By substituting the respective values

P = 13600*10*(750/1000)

P = 102000 N/m²

Thus, the atmospheric pressure would be 102000 in N/m².

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Answer:

Compound microscope

Explanation:

Answer:

Compound microscope

Explanation:

Compound microscope is the kind of optical microscope which creates a two dimensional image when the visible light is illuminated it magnifies the object and produces its image.

Answer:

A. 16t2 -116t -101=0 B. 8.0s

Explanation:

Known parameters from the question:

Height of Cliff,h0 = 101ft

Velocity of rocket ,v= 116ft/s.

1.Substituting the above to the above formula we have;

h(t) = -16t2 + vt + h0

Since h(t) =0, it means the rocket is falling towards the ground, when it gets to the ground when it's at rest the height h(t) = 0m

{Note the rocket is launched from the height of the Cliff so that would be the initial height of the rocket,h0}

2.Substituting into h(t) = -16t2 + vt + h0

We have;

0 = -16t2 + 116t + 101=> 16t2 -116t -101=0

Using formula method for solving quadratic equation we have;

t = -(-116)+_√[(-116)^2 -( 4× 16 ×-101]/ (2× 16)

t = [116 +_(141.1382)]/32

t = (116 -141.1382)/32 or (116 +141.1382)/32

-0.786s or 8.036s

-0.8s or 8.0s to the nearest tenth.

Now time cannot be negative in real life situation hence the time is 8.0s

Note : the general equation of a quadratic equation with variable t is given below;

at2 + bt + c=0

Formula method for quadratic equation is :

t =( -b+_√[(b^2 -( 4× a×c)] ) / (2× a)

Answer:

The force of gravity on an object increases with its mass; thus, the acceleration of gravity is constant.

Explanation:

one can prove this by plugging in values to Newton's 2nd law equation

F = ma, or by using the formula to calculate the force of gravity.

Force of Gravity = GMm/r^2

with G being the gravitational constant, M the mass of the earth, m the mass of the falling body, and r the distance from the earth's center.

Force of Gravity can be written as mg, with g being the acceleration due to gravity.

As we can see, m cancels on both sides, leaving

g = GM/r^2

Generally in physics problems, r will be treated as constant to achieve

g = 9.8m/s^2

Answer:

Mass is the amount of matter in a substance.

Explanation:

The basic SI unit for mass is the kilogram (kg).

Answer: The degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

Answer:

Hey!

Your answer would be option B. Light; heat...

Explanation:

In bioluminescent organisms, the energy is transformed int light energy and less then 20% of the total energy is put into Thermal Radiation!

HOPE THIS HELPS!!

Answer:

I=V/R is the formula for ohm's law .

Explanation:  I=V/R is the formula for ohm's law

Answer:

I= V/R

Explanation:

The equation, i = v/r, tells us that the current, i, flowing through a circuit is directly proportional to the voltage, v, and inversely proportional to the resistance, r. (Study.com)

His name is

Narendra Modi

Answer:

Hey!

*its kinda the wrong topic but ill answer anyway!!!*

The Prime Minister of India is...

Explanation:

HOPE THIS HELPS!!

Answer:

The net displacement is

[tex]R= \sqrt{A^2+B^2+2AB \cos \theta}[/tex]

[tex]=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m[/tex]

Explanation:

Suppose that you walk 15 meters at 30 degrees as measured from the East. Then you walk another 25 meters at 60 degrees from the East what is your net displacement

Given data

A = 15 m

B = 25 m

Angle between the vectors A and B is θ = 30°

The net displacement is

[tex]R= \sqrt{A^2+B^2+2AB \cos \theta}[/tex]

[tex]=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m[/tex]

Answer:

Explanation:

goes down as the temperature decreases, and vice versa. Sound's frequency is independent of temperature, while its speed is directly proportional to temperature. Heat, like sound, is a form of kinetic energy. Molecules at higher temperatures have more energy, thus they can vibrate faster. Since the molecules vibrate faster, sound waves can travel more quickly. ... This is faster than 331 meters per second, which is the speed of sound in air at freezing temperatures.

hope this helps!!!!

Sound waves travel more fastly in hot air , since particles in atmosphere gets more energetic in higher temperature. Hence, as the temperature decreases, the wave’s speed decreases.

Sound waves are mechanical waves passing through a medium. Sound waves are longitudinal where, the oscillation of particles is along the direction of wave propagation.

Compression waves, which at a microscopic scale rely on molecules transmitting energy one to another, are used to convey sound through the air.

Higher temperatures produce more energetic air molecules, which vibrate more rapidly. As a result of the molecules colliding with one another, the sound waves can move more quickly.

Therefore, as the temperature decreases, the speed of sound wave decreases. Thus, option B is correct.

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Answer:

True

Explanation:

Answer:

The Event Horizon Telescope comprises of a an interconnection of radio observatories. These radio observatories work in unison and helps in efficient observation of radio sources associated with black holes with angular resolution in comparison to their event horizons. This equipment functions by ensuring that anything or light which goes through the event horizon cannot escape from the black hole. Instead there will be a continual falling towards the center of the black hole.

Explanation:

presence of food, water ,etc

Explanation:

here is five all you have to do is just pick

Answer:

Los datos que tienes son:

m = 13 kg

d = 46 m

∪ = 0,45

g = 9,8 m/s²

Fr = ? 

w = ? 

Lo primero que haremos que calcular Fr

Fr = ∪mg

Fr = (0,45) (13 kg) (9,8 m/s²)

Fr = 57,33 N

Calculamos el trabajo realizado.

w = Fd

w = (57,33 N) (46 m)

w = 2637,18 Joules

Respuesta.

El trabajo realizado es 2637,18 Joules

Explanation:

Answer:

Power is 4373.25 W

Explanation:

We have,

The lift raises a car of mass 850 kg to a height of 2.1 m. It uses a force of 8330 N and takes 4 seconds to raise the car. It is required to find the power of the lift. Power is equal to the rate at which the work is done. So,

[tex]P=\dfrac{Fd}{t}\\\\P=\dfrac{8330\times 2.1}{4}\\\\P=4373.25\ W[/tex]

So, the power of the lift is 4373.25 W.

Answer:

k = 2560 N/m

Explanation:

To find the spring constant, you take into account that all the kinetic energy of the block becomes elastic potential energy in the spring, when the block compressed totally the spring:

[tex]K=U\\\\\frac{1}{2}mv^2=\frac{1}{2}kx^2[/tex]

m: mass of the block = 4.0kg

v: velocity of the block just before it hits the spring

x: compression of the spring = 0.25m

k: spring constant = ?

You solve the previous equation for k:

[tex]k=\frac{mv^2}{x^2}[/tex]     (1)

Then, you have to calculate the velocity v of the block. First, you calculate the acceleration of the block by using the second Newton law:

[tex]F=ma[/tex]

F: force over the block = 10.0N

a: acceleration

[tex]a=\frac{F}{m}=\frac{10.0N}{4.0kg}=2.5\frac{m}{s^2}[/tex]

With this value of a you can calculate the final velocity after teh block has traveled a distance of 8.0m:

[tex]v^2=v_o^2+2ad[/tex]

vo: initial velocity = 0m/s

d: distance = 8.0m

[tex]v=\sqrt{2ad}=\sqrt{2(2.5m/s^2)(8.0m)}=6.32\frac{m}{s}[/tex]

Now, you can calculate the spring constant by using the equation (1):

[tex]k=\frac{mv^2}{x^2}=\frac{(4.0kg)(6.32m/s)^2}{(0.25m)^2}=2560\frac{N}{m}[/tex]

hence, the spring constant is 2560 N/m

Answer: 35

Explanation:

Given the following :

M = 0.5 kg

Power of heater = 100W

From the graph ;

Time (t) = 7seconds

Change in temperature(Dt) = t2 - t1

Where t2 = 70°C, t1 = 30°C

Dt = (70 - 30)°C = 40°C

Recall Q = iVt

IV = power

Q = mcDt

c = specific heat capacity of liquid

mcDt = ivt

mcDt = power × t

0.5 × c × 40°C = 100 × 7

20°C × c = 700 J

c = 700 J/ 20°C

c = 35 J / kg°C

Answer:

a. 6 A

b. 3 V

Explanation:

a. By using Kirchoff's Junction Rule, which states that the current flowing into a junction must equal the current flowing out of it. As you can see in the first 3-way split, the current splits into 3A, 2A, and 1A. This means that when the 3 wires rejoin, the current must have a magnitude equal to the total of the current flowing in all 3 branches, which would equate to 3+2+1 = 6 A.

b. Voltage differences across branches of a parallel circuit are identical. This means that we can treat the 3 resistors as one, and say that the voltage drop across that whole area is 3 V. Since that is the only voltage drop in the circuit, the battery's voltage drop must also be 3 V to equate to it. This is explained by Kirchoff's Loop Rule.

Answer:

The second knife-edge must be placed 46.2 cm from the zero mark of the rod.

Explanation:

From the law of equilibrium, ΣF = 0 and ΣM = 0.

Let R be the reaction at the knife edge. Since the weight of the rod and zinc load act downward, and we take downward position as negative

-32 N - 2 N + R = 0

-34 N = -R

R = 34 N

Also, let us assume the knife-edge is x cm from the zero mark. Taking moments about the weight and assuming the knife-edge is right of the weight of the rod. Taking clockwise moments as positive and anti-clockwise moments as negative,

-(45 - 25)2 + (x - 45)R = 0

-(20)2 + (x - 45)34 = 0

-40 = -(x - 45)34  

x - 45 = 40/34

x - 45 = 1.18

x = 45 + 1.18

x = 46.18 cm

x ≅ 46.2 cm

The second knife-edge must be placed 46.2 cm from the zero mark of the rod.