in a pairs figure skating competition, a 65 kg man and his 45 kg female partner stand facing each other on skates on the ice. if they push apart and the woman has a velocity of 1.5 m/s eastward, what is the velocity of her partner? (neglect friction.)

Answer:

Approximately [tex]0.515\; {\rm m\cdot s^{-2}}[/tex] (assuming that all other forces are negligible).

Explanation:

Look up the following quantities:

At a distance of [tex]r[/tex] from the center of the Earth, the magnitude of the gravitational field strength of the Earth would be:

[tex]\begin{aligned} g &= \frac{G\, M}{r^{2}}\end{aligned}[/tex].

In this question, the asteroid is at [tex]3.30\, R[/tex] above the surface of the Earth. The actual distance between the asteroid and the center of the Earth would be [tex]r = (3.30 + 1)\, R[/tex].

Thus, at the current position of this asteroid, the magnitude of the gravitational field of the Earth would be:

[tex]\begin{aligned} g &= \frac{G\, M}{r^{2}} \\ &= \frac{G\, M}{((3.30 + 1)\, R)^{2}} \\ &\approx \frac{(6.6743 \times 10^{-11}\; {\rm m^{3}\cdot kg^{-1}\cdot s^{-2}})\, (5.792 \times 10^{24}\; {\rm kg})}{((3.30 + 1)\, (6.371 \times 10^{6}\; {\rm m}))^{2}} \\ &\approx 0.515\; {\rm m\cdot s^{-2}}\end{aligned}[/tex].

Assume that the gravitational attraction from the Earth is the only force on this asteroid. Acceleration of the asteroid would be equal to the gravitational field strength: approximately [tex]0.515\; {\rm m\cdot s^{-2}}[/tex].

Your bulk and weight would be different on a different planet compared to how they are on Earth.

The correct option is A.

This was the most basic characteristic of matter and is one of the essential building blocks of physics. The term "mass" refers to a body's total amount of matter. The kilo is the SI unit of mass (kg). A body's bulk remains constant throughout time.

Scientists frequently use balances to quantify mass. Using an electronic balance or a beam balance, one may directly determine the mass of solids. A liquid's mass may be calculated by measuring its volume and using the density table to determine the liquid's density. The kg is the SI mass unit (Kg).

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The complete question is -

Compared to their values on Earth, on another planet your

(a) mass and weight would both be the same.

(b) mass would be the same but your weight would be different.

(c) weight would be the same but your mass would be different.

The acceleration of the boxes are 1.625 m/s^2.

What is acceleration?

Acceleration is a measure of how much an object's velocity changes over time. Velocity is a vector quantity that includes both speed and direction, so acceleration can refer to changes in speed, direction, or both. Acceleration is typically measured in meters per second squared (m/s^2) or feet per second squared (ft/s^2). Positive acceleration indicates an increase in speed, while negative acceleration indicates a decrease in speed.

To find the acceleration of the boxes, we can use the formula:

force = mass x acceleration.

In this case, we know the force applied (39.0 N) and the mass of the boxes (9.00 kg + 14.0 kg + 1.00 kg = 24.00 kg).

So we can calculate the acceleration as:

force = mass x acceleration

39.0 N = 24.00 kg x acceleration

acceleration = force / mass

acceleration = 39.0 N / 24.00 kg

acceleration = 1.625 m/s^2

Therefore, the acceleration is 1.625 m/s^2.

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Rock layer that can be porous but must have very low to no permeability is option A. above oil and natural gas

Soil permeability is a measure of a soil's ability to allow water to flow through it. It is determined by the size, shape, and arrangement of the soil particles, as well as by the presence of pores or fractures in the soil.

Soils with high permeability allow water to flow through them quickly, while soils with low permeability do not allow water to flow through as easily. Permeability is important for both agricultural and engineering applications, as it can affect water availability for plants, and the stability of foundations for buildings and other structures.

Therefore, the correct answer is as given above

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The complete question goes thus:

Rock layer that can be porous but must have very low to no permeability.

A. above oil and natural gas

B. Under oil and natural gas

C. Coal, oil, natural gas

D. anthracite

Following are the different values asked in the question-

The kinetic energy of the two-skater system is 8.8 102J..

Each skater weighs m = 50 kg.

Two skaters are separated by a distance of d = 3m.

Each skater moves at a velocity of 1.4 meters per second.

The diameter of the circle formed by the separation of two stars. Then, we may determine the angular speed by using this and the relationship between v, r, ω. To get the kinetic energy of the two-skater system, enter the information into the rotating K.E. formula. As you get closer, continue the same process to locate the.

Equations: V = r ω

KE = 1/2 I ω²

Given that both skaters have the same mass and opposite, equal, and accelerating velocities, their total linear momentum is zero. As a result, the system's center of mass stays fixed at the pole's center.

They are 3 meters apart, and that distance will remain constant as it is the diameter of the circular motion they will be performing.

Consequently, the circular motion's radius is 1.5m.

Given that both skaters have the same mass and opposite, equal, and accelerating velocities, their total linear momentum is 0

As a result, the system's center of mass stays fixed at the pole's center.

They are 3 meters apart, and that distance will remain constant as it is the diameter of the circular motion they will be performing.

Consequently, the circular motion's radius is radius is 1.5m.

The angular speed of the skaters is

ω = 0.93 rad/s

The two-skater system's moment of inertia is I = (mr2) I = 2 (50) (1.5)2 I = 225 kgm 2.

The two-skater system's kinetic energy is K.E = I2 K.E = (225) (0.93)2 K.E. = 98J.

Step 6: When skaters pull along the pole until they are separated by 1.0 m, determine their angular speed (d)

The radius of the rotating motion would be r f = = 0.5m if the skaters drag the pole till they are separated by.

The two-skater system's M.I would then be

If = 25kgm2 and If = 2 (50) (0.5)2.

I0; = I f W f is the definition of the law of conservation of angular momentum.

As a result, the skaters' angular speed is given by f= If = 2250.93 25 of 8.4 rad/s =

Step 7: Determine the system's kinetic energy when skaters drag the pole until they are separated by 1.0 m. (e)

The two-skater system's kinetic energy is given by K.E = I2 K. E f = (25) (8.4)2 K. E. 8.8 102J.

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The peak current through 200 ohm resistor for both the cases 50mA.

The number of turns times the size of the coil times the magnetic field's intensity times the angular speed equals peak emf.

The largest amount of current that an output is capable of providing for brief periods of time is known as the peak current. When an electrical device or power source is turned on for the first time, a large initial current known as the peak current flows into the load, starting at zero and increasing until it reaches a peak value.

Formula for the peak current is

peak current=[tex]\frac{peak voltage}{resistance}[/tex]

As in the formula it does not matter whether frequency changes or not.

So, peak current in both cases will be

peak current=[tex]\frac{10}{200}[/tex]

peak current=50mA

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If the bottle is dropped from rest at a height of 1.2 m above the ground, it will take about 0.49 seconds for the water bottle to hit the ground by using the equation of motion.

To calculate the time it will take for the water bottle to hit the ground, we need to use the equation for motion under constant acceleration, which is the equation t = (2d/g)(1/2) is derived from the kinematic equation of motion, which relates the distance fallen (d), the initial velocity (vo), the final velocity (vf), acceleration (a), and time (t) in the following way: vf2 = 2a*d + vo2

t = (2*d / g)^(1/2)

where t is the time, d is the distance fallen, and g is the acceleration due to gravity (approximately 9.8 m/s2).

Plugging in the given values, we get:

t = (2 * 1.2 m) / 9.8 m/s^2

t = 0.49 s

So it will take about 0.49 seconds for the water bottle to hit the ground if it's dropped from a height of 1.2 meters above the ground.

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"The work done in accelerating an object along a frictionless horizontal surface is equal to the change in the object's kinetic energy."

The amount of internal and mechanical energy that objects possess fluctuates as a result of work. When work is done on a system or an object, energy is contributed to it. When a system or item accomplishes work, some of its energy is transferred to something else.

Work involves the transfer of energy from the agent to the object, which modifies the object's motion.

The energy of motion is known as kinetic energy, and it can be observed in the motion of objects or subatomic particles. Kinetic energy can be found in all particles and moving objects. Examples of kinetic energy in action include a person walking, a baseball soaring through the air, a piece of food falling from a table, and a charged particle in an electric field.

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Answer: 4 seconds are elapsed before the cannonball strikes the ground.

Explanation:

Height of tower (h) = 80m

Initital velocity in x-dir ([tex]u_{x}[/tex]) = 337m/s

Initial velocity in y-dir ([tex]u_{y}[/tex]) = 0m/s

Time of flight (T)

Gravitational acceleration (g) = 10 m/s

Using second equation of motion,

h = [tex]u_{y}[/tex] + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]

80 = [tex]\frac{1}{2}[/tex]×10×[tex]T^{2}[/tex]

[tex]T^{2}[/tex] = 16

T = 4s

According to the given question ,-53x10^10 electrons were transferred during this process

The negatively charged particles called as electrons revolve about the outside of the nucleus. For scientists, it might be hard to monitor them due to the way quickly they spin. The tiniest atoms in an atom, you can put 2000 of them in a proton, they are drawn to the positive ions of the protons.

Charge that the balloon has collected, q = 85 nC

e determines an electron's charge.

e = -1.6x10^-19 C

The amount of total value to the charge of one particle yields the number of electrons.

Suppose there are n electrons.

e = 85x10^-9/-1.6x10^-19 

= -53x10^10

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The aluminum foil is 2.5 millimeters thick. For instance, a certain roll measures 18.5 m^2 in size and weighs 1275 g. making use of the 2.7g/cm^3 density of aluminum.

Its density is defined as its mass per unit of volume (also known as specific mass or volumetric mass density). Although density can also be symbolised by the Latin letter D, the most typical mark is (the lower case Greek letter rho). The mathematical definition of density is mass divided by volume. Aluminum foil, usually referred to as aluminium foil in North American English, is a thin metal leaf made of aluminium that has a thickness of less than 0.2 mm (7.9 mils), but micrometres (0.24 mils) are also widely used. It is commonly known as tin foil.

In terms of thickness, 1275/(18.5*104*2.7*10-3) = 2.5mm.

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The correct answer is Option 3: her moment of inertia increases and her angular speed increases. When the lady extends her arms out, her moment of inertia increases because she is now further away from the axis of rotation and the mass of her arms is now contributing to her moment of inertia. Since her moment of inertia increases, her angular speed must also increase in order to conserve angular momentum.

For a lens with a negative focal length, the image formed by an object placed at the focal point will be a virtual, inverted image with a magnification of -1. The object needs to be placed at the distance of the negative focal length in front of the lens for the magnification to be -1.

Magnification is the capability to make small objects appear larger. For instance using it to make a microscopic organism observable. Resolution is the capability to differentiate two objects from each other.

A concave lens always creates a erect, virtual, and reduced image irrespective of its position. Hence, the magnification is always positive, but less than 1.

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The force that the push impala push down on ground is 1941 N and the ratio of this force to the antelope's weight is 4.4.

a)The force that did the impala push down on the ground will be 1941 N.

   The acceleration= 7-0/0.21

    a= 33.33m/sec^2

    The value of force can be calculated by

    F= m (a + g)

    F= 45( 33.33+9.81)

    F= 1941 N

Hence the force that did the impala push down on the ground will be 1941 N.

(b)The ratio of this force to the antelope's weight will be 4.4.

   The weight of the antelope=

    W= mg

    W=45×9.81

    Therefore, W=441 N

The ratio of this force to the antelope's weight can be calculated by

   F/W=1941/441

   F/W= 4.4

Therefore, the ratio of force to the antelope's weight will be 4.4.

What is force?

Force is defined as the product the of mass and acceleration.

Unit of the force= Newton

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Complete question

An impala is an African antelope capable of a remarkable vertical leap. In one recorded leap, a 45 kg impala went into a deep crouch, pushed straight up for 0.21 s, and reached a height of 2.5 m above the ground. To achieve this vertical leap, with what force did the impala push down on the ground? What is the ratio of this force to the antelope's weight?

A temperature of 100 degrees Fahrenheit is equivalent to 37.78 degrees Celsius.

The conversion formula between Fahrenheit and Celsius is as follows:

°C = (°F - 32) x (5÷9)

So, to convert 100 degrees Fahrenheit to degrees Celsius, we can plug in 100 for °F and solve for °C:

°C = (100 - 32) x (5÷9) = 68 x (5÷9) = 37.78

It is important to note that the degree unit size (Fahrenheit and Celsius) is not the same, and thus the numerical value of the temperature measured in those scales does not match one to one. The freezing point of water is 32 degrees Fahrenheit (0 degrees Celsius) and the boiling point is 212 degrees Fahrenheit (100 degrees Celsius). This means that 100 degrees Fahrenheit is considered a "hot" temperature, but 37.78 degrees Celsius is considered a "normal" room temperature.

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it will take the cheetah 1.118 seconds to move at 25.0 mph.

Kinematic equations are mathematical equations used in physics to describe the motion of objects. These equations are used to solve problems involving velocity, acceleration, and displacement. The equations rely on the use of Newton's laws of motion, which state that the acceleration of an object is equal to the sum of all the forces acting upon it, divided by its mass.

First let's convert 25.0 mph to m/s:
25 mph = 11.176 m/s
Now we can use the kinematic equation for uniform acceleration:
vf = vi + at
where vf is the final velocity, vi is the initial velocity (which is 0 m/s since the cheetah is starting from rest), a is acceleration (10.0 m/s2), and t is the time interval.
11.176 = 0 + (10.0)(t)
t = 1.118 seconds
Therefore, it will take the cheetah 1.118 seconds to move at 25.0 mph.

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Ladybug covers distance from the moment she begins to decelerate until she comes to the rest. The deceleration is 0.25m/ s2.

The net work done on a body is equal to change in kinetic energy of the body. This is called as Work-energy theorem.

Numerically. To find the distance, which Ladybug cover from the moment she begins to decelerate until she comes to the rest, use the formula.

Where,  is final velocity,  is initial velocity,  is acceleration and  is displacement. After moving, ladybug comes to the rest, so final velocity,  Placing the value of the given initial velocity, , acceleration.

Therefore, Ladybug covers  distance from the moment she begins to decelerate until she comes to the rest.

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According to the question, 12 m should a spring of indefinite length be compressed to have a potential energy equivalent to a ball of mass 6 kg raised to a height of 120 m above the ground.

Potential energy is the energy of energy stored that depends on how various system elements interact with one another.

Potential Energy of ball = m x g x h

m= 6 kg

g= 10 m/s^2

h= 120 m

PE = 7200 J

Potential Energy of spring = 1/2 x k x d^2

k = 100 N/m

as we know that

Potential Energy of spring = Potential Energy of ball

1/2 x k x d^2 = m x g x h

d = 12 m

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Answer:

  76.9 m/s

Explanation:

You want the speed of a 45.8 g golf ball after it has been hit by a 220 g club traveling 49.9 m/s, if the club is traveling 33.9 m/s in the same direction after the collision.

The conservation of momentum requires ...

  m1·v1 +m2·v2 = m1·v1f +m2·v2f

Rearranging this equation, we get ...

  m1·(v1 -v1f) = m2·(v2f -v2)

When v2 = 0, we can solve for v2f:

  m1(v1 -v1f)/m2 = v2f . . . . . . . divide by m2

In the given scenario, we have ...

The speed of the driven golf ball will be ...

  v2f = (220)(49.9 -33.9)/45.8 ≈ 76.9 . . . m/s

The speed of the golf ball after impact will be 76.9 m/s.

All objects close to the earth are subject to the force of weight. You may determine an object's weight by multiplying its mass by the gravitational acceleration it experiences.

What does physics mean by acceleration?

The rate at which the velocity changes is the precise definition of acceleration. According to the aforementioned equation, the acceleration,, is determined by the ratio of the time it took for the speed to change from to and the difference between both the starting and final speeds,,.

How much of an acceleration is there?

The rate at which velocity changes is called acceleration. The rate at which of velocity in both size and direction provides the amount of the acceleration at every point on a trajectory.

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A) To find the distance a sound wave travels in a certain time, we can use the formula:

distance = speed x time

Given that the speed of sound is 343 m/s and the time is 3000 microseconds, we can calculate the distance as:

distance = 343 m/s x (3000 x 10^-6 s) = 1.029 m

converting this to cm we get:

distance = 1.029 m x 100 cm/m = 102.9 cm

B) To find the time it takes for a sound wave to travel a certain distance, we can use the formula:

time = distance/speed

Given that the distance is 30 cm and the speed of sound is 343 m/s, we can calculate the time as:

time = 30 cm / 343 m/s = 0.00087 s

converting this to microseconds we get:

time = 0.00087 s * 10^6 microseconds/s = 87 microseconds

C) The time it takes for the sound wave to travel to the object and back is twice the time it takes for the sound wave to travel to the object alone. Given that the distance is 50 cm and the speed of sound is 343 m/s, we can calculate the time as:

time = 2 * (50 cm / 343 m/s) = 2 * 0.000146 s = 0.000292 s

converting this to microseconds we get:

time = 0.000292 s * 10^6 microseconds/s = 292 microseconds

So it takes 292 microseconds for a sound wave generated to bounce and gets back from an object 50 cm away.

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The sentence is true. When providing transcutaneous pacing, the appearance of wide QRS complexes and tall, broad T waves after each pacing spike confirms that mechanical capture has been achieved.

Transcutaneous pacing is a method of providing cardiac pacing by delivering electrical impulses through the skin to the heart. When mechanical capture is achieved, it means that the electrical impulse is strong enough to cause the heart muscle to contract.

This is confirmed by the appearance of wide QRS complexes and tall, broad T waves on an electrocardiogram (ECG) after each pacing spike. The QRS complex represents ventricular depolarization, and the T wave represents ventricular repolarization.

Wider QRS complex and taller T waves indicate that the electrical impulse is strong enough to depolarize the entire ventricular muscle, resulting in a stronger mechanical contraction.

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The circumference of a circle of radius 17 mm is 34π or 34 × 3.14 = 106.76 mm.

The length of a circular or other curved geometrical object is referred to as its circumference. It is the edge of a surface like this with two dimensions, calculated linear in one dimension. A circle's circumference, which is equivalent to the length of it's own edge measured in linear distance, serves as a measure of length. In order to measure the circumference of a circle in the metric system, a most common units are millimetre, centimeter, and meter, but in the imperial system, the most common units include inch, foot, and yard.

Given :

Radius of circle = 17mm

By using the formula of circumference -

circumference = 2 × π × r

circumference = 2 × π × 17

circumference = 34 π

or 34 × 3.14 = 106.76 mm

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if it didn't have a ramp it would be harder to load the truck.

W=mg=435NW=mg=435N is the weight of the box. If the box accelerates by 0.250 m/s2, the plane is inclined. much friction is there on the bix

The force of friction is influenced by outside forces. The two elements that friction depends on are as follows: 1. Regarding the makeup of the contact objects in touch. The two sides that are in touch with one other's depend on each other for friction.

In mathematics, the portion or component of the complete item is represented by a fraction.

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The disk will rotate through an additional angle of 52.5 rad during the next 7 seconds.

Angular acceleration is scaled in units of angle per unit time   squared (which in SI units is radians per second squared) and is ordinarily characterized by the symbol alpha( α). It is a pseudovector quantity.

To find the additional angle the disk will turn during the next 7 seconds, we can use the equation for angular displacement: Δθ = α × t² / 2 + ωi × t Where: α = angular acceleration (constant), t = time ,ωi = initial angular velocity (which is 0, since the disk is starting from rest)

We know the angular acceleration and time, so we can plug in the values to get: Δθ = α × (7.0s) ² / 2 + 0 × 7.0s

We don't know the angular acceleration, but we know the final angular displacement, which is 30 rad and the time taken which is 4s, so we can use the equation Δθ = α × t²/2 + ωit 30 = α × 4² / 2 + 04

Solving for α, we get: α = 30/8 rad/s²

Now we can use this value of angular acceleration to find the additional angle the disk will turn during the next 7 seconds: Δθ = α × (7.0s) ² / 2 + 0 × 7.0s

Δθ = (30/8) × (7.0s) ² / 2 + 0 × 7.0s

Δθ = (30/8) × 49/2

Δθ = 52.5 rad

So, the disk will rotate through an additional angle of 52.5 rad during the next 7 seconds.

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The complete answer is as follows:

All of those that we have found took place in far-off galaxies. is accurate when it comes to gamma ray bursts.

A redistribution of electric charge within a nucleus produces gamma rays, a kind of electromagnetic radiation. The difference between gamma rays and X rays is not based on their basic characteristics, but rather on their origins.

The universe's hottest and most energetic objects, including as neutron stars and pulsars, supernova explosions, and regions near black holes, all produce them. Nuclear explosions, lightning, and the less dramatic process of radioactive decay all produce gamma radiation here on Earth.

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Answer:

48 J

Explanation:

Work Done = Force X Distance moved in a stated direction

Work Done = 3N + 5N X 6m

Work Done = 48 J

Two forces 3N and 5N acting on an object are inclined at 60 degrees to each other. If the resultant force moves the object a distance of 6m, the work done is 35.92 Joules (J).

In physics, work is defined as the transfer of energy that occurs when a force is applied to an object and the object is displaced in the direction of the force. Mathematically, work done is the product of the force applied and the distance moved in the direction of the force.

Work is a scalar quantity and is measured in joules (J) in the International System of Units (SI). When a force is applied to an object and there is no displacement, no work is done. Similarly, if there is displacement but no force acting on the object, no work is done.

Here in the Question,

To find the work done, we need to first find the resultant force.

Using vector addition, we can find the magnitude and direction of the resultant force:

cos(60) = adjacent/hypotenuse

adjacent = cos(60) x 5N = 2.5N

sin(60) = opposite/hypotenuse

opposite = sin(60) x 5N = 4.33N

The horizontal component of the 3N force is 3N cos(60) = 1.5N

The vertical component of the 3N force is 3N sin(60) = 2.6N

The horizontal component of the 5N force is 5N cos(30) = 4.33N

The vertical component of the 5N force is 5N sin(30) = 2.5N

The horizontal component of the resultant force is 4.33N + 1.5N = 5.83N

The vertical component of the resultant force is 2.5N + 2.6N = 5.1N

The magnitude of the resultant force is given by the Pythagorean theorem:

Resultant force = sqrt(5.83^2 + 5.1^2) = 7.59N

The direction of the resultant force is given by:

tan(theta) = opposite/adjacent

theta = tan^-1(5.1/5.83) = 43.1 degrees

The work done is given by:

work = force x distance x cos(theta)

work = 7.59N x 6m x cos(43.1) = 35.92 Joules (J)

Therefore, the work done is 35.92 Joules (J).

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If the atomic radius of gold is 0.144 nm, then the  volume of its unit cell in cubic meters is  6.7847 × 10⁻²⁹ m³.

A chemical element's atomic radius, which is typically the average or typical distance between the nucleus's centre and the outermost isolated electron, serves as a gauge for the size of its atom. There are numerous non-equivalent definitions of atomic radius because the boundary is not a clearly defined physical entity.  

Van der Waals radius, ionic radius, metallic radius, and covalent radius are the four most frequently used definitions of atomic radius. The atomic radius is typically measured in a chemically bonded state because it is difficult to isolate individual atoms to measure their radii separately.  

However, theoretical calculations are easier when considering isolated atoms. A variety of definitions result from the dependencies on environment, probe, and state.

Atomic radius of gold (r)  = 0.1442nm

                                         = 0.1442 × 10⁻⁹m

Gold is FCC then

FCC unit cell  side a        = [tex]2\sqrt{2r}[/tex]

Unit of the volume v        = a³ = ( [tex]2\sqrt{2r}[/tex] )

Unit cell volume (V)         = 16[tex]\sqrt{2\times r^{3}[/tex]

volume of unit cell           =6.7847  × 10⁻²⁹ m³

Thus, If the atomic radius of gold is 0.144 nm, then the  volume of its unit cell in cubic meters is  6.7847 × 10⁻²⁹ m³.

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