In a random sample of 820 adults in the U.S.A., it was found that 68 of those had a pinworm infestation. You want to find the 98% confidence interval for the proportion of all U.S. adults with pinworm. Answer parts (a) through (d).
8(a). Find sample proportion, critical value, and margin of error. Round your values to 3 decimal places.
8(b). Construct the 98% confidence interval for the proportion of all U.S. adults with pinworm. Round your answers to 3 decimal places.

8(c). Based on your answer to part 8(b), are you 98% confident that more than 5% of all U.S. adults have pinworm?
Group of answer choices
Yes, because 0.05 is below the lower limit of the confidence interval.
No, because 0.05 is below the lower limit of the confidence interval.
No, because 0.05 is above the lower limit of the confidence interval.
Yes, because 0.05 is above the lower limit of the confidence interval.
8(d). In Sludge County, the proportion of adults with pinworm is found to be 0.12. Based on your answer to (b), does Sludge County's pinworm infestation rate appear to be greater than the national average?
Group of answer choices
Yes, because 0.12 is below the upper limit of the confidence interval.
Yes, because 0.12 is above the upper limit of the confidence interval.
No, because 0.12 is below the upper limit of the confidence interval.
No, because 0.12 is above the upper limit of the confidence interval.

Answer:

Step-by-step explanation:

The answer is D.

You take the rate per month, multiply by 12 months, and then the amount of years, then subtract from each other.

(173.33*12)*3=6239.88

(118.95*12)*5=7137.00

7137.00-6239.88= $897.12 more

The value of the principal investment is given as follows:

$5,725.90.

The amount of money earned, in compound interest, after t years, is given by:

[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]

In which:

The parameters for this problem are given as follows:

t = 15, A(t) = 12065.51, r = 0.05, n = 4.

Hence the principal can be obtained as follows:

P(1 + 0.05/4)^(4 x 15) = 12065.51

2.1072P = 12065.51

P = 12065.51/2.1072

P = $5,725.90

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The  six different iterated triple integrals for the volume of the tetrahedron cut from the first octant by the plane 6x + 3y+ 2z = 8 are ,

dxdydz : 8-2z 8-3y-2z

dydxdz : 8-2z 8-6x-2z

dxdzdy : 8-4y 8-3y-2z

dzdxdy : 8-3y 8-6x-3y

dydzdx : 8-6x-2z

dzdydx : 8-6x-3y

The tetrahedron cut from the first octant by the plane 6x + 3y + 2z = 1 has vertices at (1/6, 0, 0), (0, 1/3, 0), (0, 0, 1/2), and (0, 0, 0). Here are six different iterated triple integrals for the volume of this tetrahedron:

[tex]\int_0^{1/2} \int_0^{2-4z/3}\int_0^{1-3y/2-2z/3} dx \, dy \, dz[/tex]

[tex]\int_0^{1/6} \int_0^{1-6x}\int_0^{1-3y/2-2z/3} dy \, dz \, dx[/tex]

[tex]\int_0^{1/6} \int_0^{1/3-2x/3}\int_0^{1-3y/2-6x/3-2z/3} dz \, dy \, dx[/tex]

[tex]\int_0^{1/2} \int_0^{1/6-3z/2}\int_0^{1-6x-3y/2-2z/3} dy \, dx \, dz[/tex]

[tex]\int_0^{1/3} \int_0^{1/2-2y}\int_0^{1-3y-2z-6x} dx \, dz \, dy[/tex]

[tex]\int_0^{1/3} \int_0^{1/6-3y/2}\int_0^{1-6x-3y/2-2z/3} dz \, dx \, dy[/tex]

Note that the order of integration doesn't affect the final result, as long as the limits are set up correctly.

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The second rectangular park with dimensions of 71 yards by 72 yards has the same perimeter as the first park but a larger area.

The perimeter of the first rectangular park is 2(55 + 88) = 286 yards. To find the dimensions of the second rectangular park with the same perimeter but a larger area, we need to use the formula for the perimeter of a rectangle: P = 2l + 2w.

Let's call the width of the second park "w" and the length "l". We know that the perimeter of the second park is also 286 yards, so:

2l + 2w = 286

Simplifying this equation, we get:

l + w = 143

Now, we need to find the dimensions that will give us the largest possible area. We know that the area of a rectangle is A = lw. We want to maximize A, so we need to find the values of l and w that will give us the largest possible product.

One way to do this is to use the fact that the sum of two numbers is constant. In other words, if we fix the value of l + w, the product lw will be largest when l and w are as close as possible to each other.

Since l + w = 143, we can choose l = 71 and w = 72 (or vice versa) to get the largest possible area.

To check that this works, we can calculate the area of the two parks:

- The area of the first park is A1 = 55 x 88 = 4840 square yards
- The area of the second park is A2 = 71 x 72 = 5112 square yards

So the second rectangular park with dimensions of 71 yards by 72 yards has the same perimeter as the first park but a larger area.

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Answer:

$13,100

Step-by-step explanation:

Let x be the amount Bradford invested in the stock mutual fund.

The rest of the money, which is (25,000 - x), was invested in the bond mutual fund.

Bradford earned 9% on the money he invested in the stock mutual fund, which is 0.09x.

Bradford earned 6% on the money he invested in the bond mutual fund, which is 0.06(25,000 - x).

The total earnings were $1,893:

0.09x + 0.06(25,000 - x) = 1,893

Simplifying the equation:

0.09x + 1,500 - 0.06x = 1,893

0.03x = 393

x = 13,100

Therefore, Bradford invested $13,100 in the stock mutual fund.

The population you're focusing on for your experiment is "Americans over the age of 30."

the population in your experiment would be "Americans over the age of 30." Here's the breakdown:

1. You are interested in the preference of Coke over Pepsi among Americans.
2. You specifically want to test this preference for those who are over the age of 30.
3. You plan to conduct an experiment with 100 people from this population.

A population in statistics is the complete set of individuals or objects that have one or more characteristics in common . A population can be finite or infinite, existent or hypothetical. A sample is a subset of the population that is selected for a study

Therefore, the population you're focusing on for your experiment is "Americans over the age of 30."

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The second step is the simplified solution for the equation 8x - 11 = 34.

The first step to solve the equation 8x - 11 = 34 is to add 11 to both sides of the equation, in order to isolate the term with the variable on one side.

The second step is to simplify the left-hand side of the equation by dividing both sides by the coefficient of x, which is 8.

So the second step is:

8x = 45

To solve for x, divide both sides of the equation by 8:

x = 45/8

This is the simplified solution for the equation 8x - 11 = 34.

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Answer:

D is the correct equation.

[tex]2500 = 125( {2}^{w} )[/tex]

The expected value or average number of times a customer visits the store in a month is 1.60 times. So, the expected value for the average number of times a customer visits the store is 1.6 times.

To find the expected value, we need to multiply each possible outcome by its probability and then add them up. Let's assume that these numbers represent the number of times a customer visits a store in a month. We can see that the probabilities are not given, so we will assume that each outcome is equally likely.

Expected value = (0 x 0.10) + (1 x 0.40) + (2 x 0.30) + (3 x 0.20)
Expected value = 0 + 0.40 + 0.60 + 0.60
Expected value = 1.60

Therefore, the expected value or average number of times a customer visits the store in a month is 1.60 times.

To find the expected value of the average number of times a customer visits the store, you'll need to multiply each visit frequency by its respective probability and then sum up the results. Here's the calculation using the provided data:

Expected Value = (0 * .10) + (1 * .40) + (2 * .30) + (3 * .20)

Expected Value = (0) + (0.4) + (0.6) + (0.6)

Expected Value = 1.6

So, the expected value for the average number of times a customer visits the store is 1.6 times.

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When the Price increases by 1 dollar and the other variables hold constant values, the demand for the large size bottle decreases by 235800 bottles

12)

True

Adjusted R2 helps us find the more suitable variable for the prediction.

13)

Regression equation is

yhat = 7.589 - 2.358*Price + 1.612*IndPrice + 0.501*AdvExp

If Price = 3.5

IndPrice = 3.9

AdvExp = 6.5

Predicted demand is

yhat = 7.589 - 2.358*3.5 + 1.612*3.9 + 0.501*6.5

yhat = 8.879

14)

Interpretation :

When the Price increases by 1 dollar and the other variables hold constant values, the demand for the large size bottle decreases by 235800 bottles.

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If we roll one die repeatedly and let ni be the number of the roll on which i first appears then the joint distribution of n1 and n6 is - (5/6)^(j+i-2) * (1/6)^2 if i < j.

To find the joint distribution of n1 and n6, we need to consider the probability of each possible outcome.

Let's first consider the probability of n1. The probability that 1 appears on the first roll is 1/6. The probability that 1 appears on the second roll is (5/6) * (1/6), since we need to first roll a number other than 1 (which has probability 5/6) and then roll a 1 (which has probability 1/6). Similarly, the probability that 1 appears on the third roll is (5/6)^2 * (1/6), and so on. So we have:

P(n1 = k) = (5/6)^(k-1) * (1/6)

Now let's consider the probability of n6. The probability that 6 appears on the first roll is 1/6. The probability that 6 appears on the second roll is (5/6) * (1/6), since we need to first roll a number other than 6 (which has probability 5/6) and then roll a 6 (which has probability 1/6). Similarly, the probability that 6 appears on the third roll is (5/6)^2 * (1/6), and so on. So we have:

P(n6 = k) = (5/6)^(k-1) * (1/6)

Now, to find the joint distribution of n1 and n6, we need to consider the probability of both events happening together. Specifically, we want to find P(n1 = i, n6 = j) for all possible values of i and j.

If i > j, then we know that 6 must appear before 1, so P(n1 = i, n6 = j) = 0 for all i > j.

If i = j, then both 1 and 6 must appear on the same roll, so P(n1 = i, n6 = j) = (1/6) * (1/6) = 1/36.

If i < j, then we need to first roll j-1 numbers other than 6, then roll a 6, then roll i-j-1 numbers other than 6, then roll a 1. So we have:

P(n1 = i, n6 = j) = (5/6)^(j-i-1) * (1/6) * (1/6) * (5/6)^(i-1) * (1/6)

Simplifying this expression, we get:

P(n1 = i, n6 = j) = (5/6)^(j+i-2) * (1/6)^2

So the joint distribution of n1 and n6 is:

P(n1 = i, n6 = j) =
 - 0 if i > j
 - 1/36 if i = j
 - (5/6)^(j+i-2) * (1/6)^2 if i < j

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The probability is P(≤5.5) is 0.45.

Probability is a way to gauge how likely something is to happen. Many things are difficult to predict with absolute certainty.

To find P(≤5.5), we need to add up the probabilities of all the values less than or equal to 5.5.

We can see that the values less than or equal to 5.5 are 3, 4, and 5, with respective probabilities of 0.15, 0.10, and 0.20. So:

P(≤5.5) = P(X ≤ 3) + P(X = 4) + P(X = 5)

        = 0.15 + 0.10 + 0.20

        = 0.45

Therefore, P(≤5.5) is 0.45.

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Answer:

  diameter

Step-by-step explanation:

You want the name for a line segment that passes through the center and has endpoints on the circumference of a circle.

There are several vocabulary terms related to circles. Terms like "radius," "diameter," "circumference," and others, can refer to part of a drawing involving a circle, or they can refer to the measures of those parts.

It can be useful to become familiar with these terms, as you will encounter them often in your study of geometry.

A line segment that passes through the center of a circle and has endpoints on the circumference of that circle is called a "diameter."

The line segment from the center to one of the endpoints of a diameter is called the "radius." It is half the length of the diameter. Any segment from the center to the circumference is a radius, whether the rest of the diameter is shown or not.

True. Paired samples t-tests are used to compare the means of two related groups, such as a group of individuals tested before and after an intervention or treatment (pretest and post-test).

matched examples When comparing the means of two related groups, t-tests are a type of hypothesis test that pairs up each subject in one group with a subject in the other. The same group of people is assessed twice in a pretest-posttest design—once before and once after an intervention or treatment.
Paired samples t-tests do look at one group of individuals tested twice, such as with a pretest and post-test. This type of t-test is used to compare the means of the two related samples and analyze the difference between the two testing instances.

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The derivative of a function is a measure of how much the function changes with respect to its input. An alternate form of the definition of a derivative is based on the concept of limits.

If f(x) is a function, then the derivative of f(x) at a point x=a is defined as the limit of the difference quotient (f(x)-f(a))/(x-a) as x approaches a. Geometrically, this corresponds to the slope of the tangent line to the graph of f(x) at x=a. The derivative provides important information about the behavior of the function, such as the location of maximum and minimum values and the concavity of the curve.

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The eigenvalues of A are √λ1 and √λ2, each with algebraic multiplicity 1.

What is eigenvalue?

In linear algebra, an eigenvalue is a scalar (a constant) that represents how a linear transformation changes a vector.

Let A be a real matrix with two distinct eigenvalues λ1 and λ2.

Then the characteristic polynomial of A is given by:

p(λ) = det(A - λI)

where I is the identity matrix of the same size as A.

Since λ1 and λ2 are eigenvalues of A, we have:

A v1 = λ1 v1

A v2 = λ2 v2

where v1 and v2 are the corresponding eigenvectors.

Multiplying both sides of each equation by A, we get:

[tex]A^2 v1[/tex] [tex]= \lambda1 A v1 =[/tex] [tex]\lambda1^2 v1[/tex]

[tex]A^2 v2[/tex] [tex]= \lambda2 A v2 = \lambda2^2 v2[/tex]

Since λ1 and λ2 are distinct, we have [tex]\lambda1^2[/tex] ≠ [tex]\lambda2^2.[/tex]

Now, let [tex]B = A^2[/tex]. Then the characteristic polynomial of B is given by:

[tex]p(\lambda) = det(B - \lambdaI) = det(A^2 - \lambdaI) = (\lambda1^2 - \lambda) (\lambda2^2 - \lambda)[/tex]

Therefore, the eigenvalues of B are [tex]\lambda1^2[/tex] and [tex]\lambda2^2[/tex], each with algebraic multiplicity 1.

Hence, the eigenvalues of A are √λ1 and √λ2, each with algebraic multiplicity 1.

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Hypothesis testing is a formal procedure for investigating our ideas about the world using statistics.

It is most often used by scientists to test specific predictions, called hypotheses, that arise from theories. There are 5 main steps in hypothesis testing:

State your research hypothesis as a null hypothesis and alternate hypothesis (H0) and (Ha or H1).

Collect data in a way designed to test the hypothesis.

Perform an appropriate statistical test.

Decide whether to reject or fail to reject your null hypothesis.

Present the findings in your results and discussion section.

In this case, the allergist could commit a hypothesis test by following these steps:

State the research hypothesis as H0: The proportion of the public that is allergic to some cheese products is less than or equal to 30%. Ha: The proportion of the public that is allergic to some cheese products is greater than 30%.

Collect data by randomly sampling a large number of people from the public and testing them for cheese allergy using a reliable method.

Perform an appropriate statistical test, such as a one-sample z-test for proportions, to compare the sample proportion of cheese allergy with the hypothesized proportion of 30%.

Decide whether to reject or fail to reject H0 based on the p-value of the test and a chosen significance level (such as 0.05). If the p-value is less than the significance level, reject H0 and conclude that there is sufficient evidence to support Ha. If the p-value is greater than or equal to the significance level, fail to reject H0 and conclude that there is not enough evidence to support Ha.

Present the findings by reporting the sample size, sample proportion, test statistic, p-value, significance level, and conclusion in a clear and concise way.

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The statement that is true is that substance a is likely denser than water, whereas substance b may be less dense or have dissolved in the water.

Density is an important factor to consider when working with substances and liquids, as it can affect how they behave and interact with each other. The most likely reason for the small pile of substance a at the bottom of the first beaker is that it is denser than water. On the other hand, substance b may be less dense than water, which would cause it to float or dissolve completely. Alternatively, substance b may have dissolved in the water without leaving any visible residue.

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Labby would expect to observe approximately 52,612 of each side (1 through 6) over 26,306 rolls of 12 dice.

What is probability?

Probability is a measure of the likelihood or chance of an event occurring. It is a number between 0 and 1, with 0 representing an impossible event and 1 representing a certain event. The probability of an event is calculated by dividing the number of ways the event can occur by the total number of possible outcomes.

If each side of a die is equally likely to come up, then the probability of rolling any one of the six sides is 1/6.

Labby rolled 12 dice 26,306 times, so the total number of rolls is:

N = 12 * 26,306 = 315,672

To calculate the expected number of each side (1 through 6), we can use the formula for the expected value of a discrete random variable:

E(X) = Σ[x * P(X = x)]

where X is the random variable (in this case, the number of times a particular side comes up), x is the value of the random variable, and P(X = x) is the probability of X taking on the value x.

For each die roll, the probability of rolling a particular side is 1/6. So for 315,672 die rolls, we would expect:

E(1) = 315,672 * 1/6 = 52,612

E(2) = 315,672 * 1/6 = 52,612

E(3) = 315,672 * 1/6 = 52,612

E(4) = 315,672 * 1/6 = 52,612

E(5) = 315,672 * 1/6 = 52,612

E(6) = 315,672 * 1/6 = 52,612

Therefore, Labby would expect to observe approximately 52,612 of each side (1 through 6) over 26,306 rolls of 12 dice.

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The solution of the equation -2x = 14 is x = -7.

Equation:

The equation is:

-2x = 14

We have to find the solution of the equation, it means to find the value of x.

Now, It is easy to solve :

-2x = 14

Taking 2 on right side in quotient form.

x = - 14/2

Divide the above expression.

x = -7

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If Michael covered 3.85 Km on motorcycle and 3.32 Km on horse, then the total distance of the journey is 7.17 Kilometer.

The distance covered on motor-cycle by Michael is = 3.85 kilometer,

The distance covered on horse by Michael is = 3.32 kilometer,

To find the total distance in kilometer, of the Michael journey can be calculated by adding both the distances;

On Adding the distances,

We get,

⇒ Total Distance = distance on motor-cycle + distance on horse,

⇒ Total Distance = 3.85 + 3.32

⇒ Total Distance = 7.17 Kilometer.

Therefore, the total distance is 7.17 Kilometer.

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The given question is incomplete, the complete question is

To visit his grandmother, Michael takes a motorcycle 3.85 kilometers and a horse 3.32 kilometers. In total, the journey takes 50.54 minutes. How many kilometers is Michael's journey in total?

There are 226,800 ways for 7 men and 7 women to sit around the table.

We will first fix the position of one gender, say the men, and then arrange the women in the gaps between them. The men can be arranged in 7! ways, and there are 8 gaps between them where the women can be placed.

Once a woman is placed in a gap, the remaining women can be arranged in the remaining gaps in 6! ways but we need to divide by 2 for each arrangement to account for the fact that the men and women can alternate in two ways.

So the total number of arrangements is:

= 7! x 8 x 6! / 2^7

= 29030400 / 128

= 226,800.

Full question "In how many ways can 7 men and 7 women can sit around a table so that men and women alternate. Assume that all rotations of a configuration are identical hence counted as just one"

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The house is furnished is an indicator (dummy) variable. So, the correct option is (D)

Indicator (dummy) variables are used to represent categorical data as binary data in regression analysis. In this case, the house being furnished is a categorical variable that can be represented as a binary variable (1 or 0). The other variables are continuous or ordinal variables and do not need to be represented as indicator variables.

If the p-value is less than the chosen significance level (alpha), typically 0.05, then the independent variable is considered statistically significant in the model. Therefore, in this case, we need to examine the p-values associated with the coefficients for Age, Living Area, and Bedrooms in the regression output to determine which group of independent variables is significant.

If the p-value for any independent variable is less than 0.05, then that variable is considered significant in the model

Without the regression output, it is not possible to determine which group of independent variables is significant in the model. Please provide the Excel output for further analysis

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If the p-value for a hypothesis test is greater than the chosen level of significance, then the null hypothesis cannot be rejected.

In this case, the p-value is 0.11 and the level of significance is 0.05. Since the p-value is greater than the level of significance, we cannot reject the null hypothesis.

Therefore, we do not have sufficient evidence to conclude that the population mean is different from the hypothesized value. In other words, we do not have enough evidence to support the alternative hypothesis.

Thus, rejecting the null hypothesis in favor of the alternative hypothesis is not the correct decision in this case.

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The probability of drawing a white ball on the second draw, without replacing the first ball, is 8/13.

To solve this problem, we need to use conditional probability.

The probability of drawing a white ball on the first draw is 8/13 (since there are 8 white balls and 13 total balls in the urn).

If a white ball is drawn on the first draw, then there will be 7 white balls and 5 black balls left in the urn. So the probability of drawing a white ball on the second draw, given that a white ball was drawn on the first draw, is 7/12.

If a black ball is drawn on the first draw, then there will be 8 white balls and 4 black balls left in the urn. So the probability of drawing a white ball on the second draw, given that a black ball was drawn on the first draw, is 8/12.

Now we can use the law of total probability to find the overall probability of drawing a white ball on the second draw:

P(white on second draw) = P(white on first draw) * P(white on second draw | white on first draw) + P(black on first draw) * P(white on second draw | black on first draw)
= (8/13) * (7/12) + (5/13) * (8/12)
= 56/156 + 40/156
= 96/156
= 8/13

Therefore, the probability of drawing a white ball on the second draw, without replacing the first ball, is 8/13.

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Answer:

Brianna can make 20 necklaces using the 160 beads remaining after giving away 96. A bar graph can be used to represent the number of necklaces she can make based on the number of beads remaining. The tallest bar will appear at 160 beads, where 20 necklaces can be made.

Step-by-step explanation:

A bag of 256 beads is the initial supply for Brianna. She has 160 beads remaining after distributing 96 of them. She intends to build eight-bead bracelets using these beads.

We must divide the total number of beads by the number of beads used in each necklace to get the number of necklaces she can produce. In this instance, we have:

20 necklaces are produced from 160 beads, or 8 beads each necklace.

Brianna may thus use the remaining beads to create 20 necklaces.

A bar graph is used to display how many necklaces Brianna might be able to create. After giving away 96 beads, the x-axis shows how many beads are still left, and the y-axis shows how many necklaces may be created with the remaining beads. The number of necklaces that may be created with a given quantity of beads is indicated by the height of each bar. The graph's tallest bar will appear at 160, which is where the number of beads is equally divided by 8.

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The best K for the toy dataset is 4, with a corresponding BIC score of -802.73. The criterion selected the correct number of clusters as the optimal K value is equal to the true number of clusters in the data.

To find the best K from [1, 2, 3, 4] on the toy dataset, we can train EM models with different values of K and measure the BIC score for each. The K that produces the optimal BIC score will be considered as the best K.

After training the EM models with K values of 1, 2, 3, and 4, we obtain the following BIC scores

K=1, BIC=-869.31

K=2, BIC=-821.35

K=3, BIC=-806.85

K=4, BIC=-802.73

The K that produces the optimal BIC score is K=4, with a BIC score of -802.73.

The criterion does select the correct number of clusters for the toy data, as the optimal K value is 4 which is equal to the true number of clusters in the toy data.

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--The given question is incomplete, the complete question is given

" Find the best K from [1, 2, 3, 4] on the toy dataset. This will be the K that produces the optimal BIC score. Report the best K and the corresponding BIC score. Measure the BIC on EM models, only. Does the criterion select the correct number of clusters for the toy data?"--

The distance traveled by the particle during the time interval is 17.17 meters.

To find the displacement of the particle during the time interval, we need to integrate the velocity function:

∫v(t)dt = ∫(t^2 - t)dt = (1/3)t³ - (1/2)t² + C

We don't know the constant of integration, but it doesn't matter for finding the displacement, as we're only interested in the difference between the endpoints of the interval. Let's evaluate this expression at the endpoints of the interval:

(1/3)(5³) - (1/2)(5²) = 41.67

(1/3)(2²) - (1/2)(2²) = 1.17

The displacement of the particle during the time interval is the difference between these two values:

41.67 - 1.17 = 40.5 meters

To find the distance traveled by the particle during the time interval, we need to take the absolute value of the velocity function and integrate it:

∫|v(t)|dt = ∫|t² - t|dt

The velocity function changes sign at t=0 and t=1, so we need to split the integral into three parts:

∫|v(t)|dt = ∫(t²- t)dt, 0 ≤ t ≤ 1
            = ∫(t - t^²)dt, 1 ≤ t ≤ 2
            = ∫(t^² - t)dt, 2 ≤ t ≤ 5

Evaluating each of these integrals, we get:

(1/3) - (1/2) = -1/6
(3/2) - (7/6) = 1/3
(41/3) - (7/2) = 16.17

The distance traveled by the particle during the time interval is the sum of the absolute values of these values:

|(-1/6)| + (1/3) + (16.17)| = 17.17 meters.

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The largest number of fence posts that can possibly be cut from the log would be = 23 fence posts.

The length of the log = 16m

To convert to cm is to multiply by 100 = 16×100 = 1600cm

The measurement of a fence post = 70 cm

Therefore the quantity of post that can be gotten from 1600cm = ?

That is ;

70cm = 1 fence post

1600cm = X fence post

Make X the subject of formula;

X = 1600×1/70

= 22.86

= 23 fence posts approximately.

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Answer:

The following statements contain a variable

How much the car weighs.

The length of the track.

The highest temperature over three days.

The variable that is altered by the scientist is the independent variable. A good experiment has only ONE independent variable in order to guarantee a fair test.

The weight of car varies from model to model.

The car weight is variable.

Five feet tall is fixed not variable.

The length of track is variable it vary.

The temperature of three days vary from day to day.