In a random sample of seven aerospace engineers, the sample mean monthly income is $6824 and the sample standard deviation is $340. Construct a 95% confidence interval for the population mean. Assume that the monthly incomes are normally distributed.

Answer:

5880 ways

Step-by-step explanation:

For selections like this, we solve using the combination theory. Recall that

nCr = n!/(n-r)!r!

Hence given to find the number of ways 6 gentleman and 4 ladies can be choosen out of 10 gentleman and 8 ladies,

= 10C6 * 8C4

= 10!/(10-6)!6! * 8!/(8-6)!6!

= 10 * 9 * 8 * 7 * 6!/4 *3 *2 * 6! * 8 * 7 * 6!/2 * 6!

= 210 * 28

= 5880 ways

The arrangement can be done in 5880 ways

Answer:

true

mark me brainist if it comes out to be true

Answer:

The answer is TRUE.

Step-by-step explanation:

Answer:

24 men will take 3 days to dig a 72 meter trench.

Step-by-step explanation:

If 16 workers dig an 80-meter long trench in five days, how long will it take 24 workers to dig a 72-meter long trench?

If 16 workers take 5 days to dig an 80 meter long trench,

24 workers will definitely take lesser time to dig a 72 meter long trench as both the length of the trench and the number of workers is more

Lets write these values down in order: Number of Workers, Length of Trench, Number of Days:

16 80 5

24 72 ?

Lets represent the ? as x:

We know that Ratio of Trench length to men = 80/16 : 72/24 or 5 : 3

Which means that the first set (16 men) will take 5 days to dig a trench of 80 meters.

And therefore from the above ratio (5: 3), 24 men will take 3 days to dig a 72 meter trench.

HOPE IT WILL DEFINITELY HELP YOU

Answer:

For any rectangle, the one with the largest area will be the one whose dimensions are as close to a square as possible.

However, the dividers change the process to find this maximum somewhat.

Letting x represent two sides of the rectangle and the 3 parallel dividers, we have 2x+3x = 5x.

Letting y represent the other two sides of the rectangle, we have 2y.

We know that 2y + 5x = 750.

Solving for y, we first subtract 5x from each side:

2y + 5x - 5x = 750 - 5x

2y = - 5x + 750

Next we divide both sides by 2:

2y/2 = - 5x/2 + 750/2

y = - 2.5x + 375

We know that the area of a rectangle is given by

A = lw, where l is the length and w is the width. In this rectangle, one dimension is x and the other is y, making the area

A = xy

Substituting the expression for y we just found above, we have

A = x (-2.5x+375)

A = - 2.5x² + 375x

This is a quadratic equation, with values a = - 2.5, b = 375 and c = 0.

To find the maximum, we will find the vertex. First we find the axis of symmetry, using the equation

x = - b/2a

x = - 375/2 (-2.5) = - 375/-5 = 75

Substituting this back in place of every x in our area equation, we have

A = - 2.5x² + 375x

A = - 2.5 (75) ² + 375 (75) = - 2.5 (5625) + 28125 = - 14062.5 + 28125 = 14062.5

Step-by-step explanation:

Answer:

a-648²

b-4.2²

Step-by-step explanation:

least 108*48 = 648²

We know

Sum of two interior angles=exterior angle

[tex]\\ \sf\longmapsto 20°+120°=<y[/tex]

[tex]\\ \sf\longmapsto <y=20°+120°[/tex]

[tex]\\ \sf\longmapsto <y=140°[/tex]

Hope it helps

9514 1404 393

Answer:

  $144

Step-by-step explanation:

Multiplication is used to simplify repeated addition. To find the total cost, add up the costs of each of the tickets.

  6 child tickets will cost $10 +10 +10 +10 +10 +10 = 6×$10 = $60

  6 adult tickets will cost $14 +14 +14 +14 +14 +14 = 6×$14 = $84

Then the total cost of all of these tickets will be ...

  $60 +84 = $144 . . . . cost of zoo tickets in all

The locus of the midpoints of all chords that can be drawn from a given fixed point [tex](a,b)[/tex] on a circle with a radius of 6 units, is a circle of radius 3 units with center at a point whose x & y coordinates are shifted from the center of the given circle by [tex]\frac{a}{2}[/tex] and [tex]\frac{b}{2}[/tex] respectively.

Given: A circle of radius 6 units

To find: The locus of the midpoint of all chords that can be drawn from a given point on the circle.

To find the required locus, we need to know the following:

Let, without loss of generality, the given circle be centered at the origin. Even if it is not, we can shift the origin to the center of the given circle with coordinate transformation.

Then, the equation of the given circle is [tex]x^{2}+y^{2} =6^{2}[/tex], that is, [tex]x^{2}+y^{2} = 36[/tex]

Let the coordinates of the given fixed point be [tex](a,b)[/tex]

Let the coordinates of any point on the circle be [tex](p,q)[/tex] and let the coordinates of the midpoint of the chord joining the points [tex](a,b)[/tex] and [tex](p,q)[/tex] be [tex](h,k)[/tex]

We have to find the locus of [tex](h,k)[/tex]

Then, using the midpoint formula,

[tex](h,k)=(\frac{a+p}{2} ,\frac{b+q}{2})[/tex]

On solving, we get,

[tex]p=2h-a,q=2k-b[/tex]

Since [tex](a,b)[/tex] and [tex](p,q)[/tex] are both points on the given circle, they satisfy the equation of the circle, [tex]x^{2}+y^{2} = 36[/tex]

Then,

[tex]a^{2} +b^{2} =36[/tex]

[tex]p^{2} +q^{2} =36[/tex]

Substituting [tex]p=2h-a,q=2k-b[/tex] in [tex]p^{2} +q^{2} =36[/tex], we have,

[tex](2h-a)^{2} +(2k-b)^{2} =36[/tex]

[tex](2(h-\frac{a}{2}) )^{2} +(2(k-\frac{b}{2}))^{2} =36[/tex]

[tex]4(h-\frac{a}{2})^{2} +4(k-\frac{b}{2})^{2} =36[/tex]

[tex](h-\frac{a}{2})^{2} +(k-\frac{b}{2})^{2} =\frac{36}{4}[/tex]

[tex](h-\frac{a}{2})^{2} +(k-\frac{b}{2})^{2} =9[/tex]

[tex](h-\frac{a}{2})^{2} +(k-\frac{b}{2})^{2} =3^{2}[/tex]

This is the locus of the point [tex](h,k)[/tex]

Replace [tex](h,k)=(x,y)[/tex] to get,

[tex](x-\frac{a}{2})^{2} +(y-\frac{b}{2})^{2} =3^{2}[/tex]

This is the equation of a circle with center at [tex](\frac{a}{2} ,\frac{b}{2} )[/tex] and radius 3 units.

Thus, we can conclude that the locus of the midpoints of all chords that can be drawn from a given fixed point [tex](a,b)[/tex] on a circle with a radius of 6 units, is a circle of radius 3 units with center at a point whose x & y coordinates are shifted from the center of the given circle by [tex]\frac{a}{2}[/tex] and [tex]\frac{b}{2}[/tex] respectively.

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Answer:

The bias is they only picked men to test the new medication on to see if it was ready for the general public to use.

Step-by-step explanation:

Answer:

60

step by step explanitation

Answer:

the number of hours in a week Jope, who is not at work, is 102 hours

Step-by-step explanation:

call X is the number of hours in a week Jope is not at work​.

=> the number of hours in a week = X + the number of work hours in a week

=> 6*24 = X + 42

=> X = 6*24 - 42

=> X = 102 hours

Answer:

a

Step-by-step explanation:

Step-by-step explanation:

Many factors would be used to assess the effectiveness of a human rights campaign, including the following:

Social Influence. Direct Interpersonal Reach. Participant Observation. Reputation. Volume of Search & Interest. Website Traffic.

National Research.

Answer:

x = 42

Step-by-step explanation:

24+8 = 32

[tex]\frac{x}{24}[/tex] = [tex]\frac{x+14}{32}[/tex]

32x = 24(x+14)

32x = 24x+336

8x = 336

x = 42

9514 1404 393

Answer:

Step-by-step explanation:

Let x represent the amount invested at 9%. Then the difference in interest amounts is ...

  (9%)x -(5%)(26876 -x) = 720.78 . . . . . assuming a 1-year investment

  0.14x -1343.80 = 720.78 . . . . . . . . . simplify

  0.14x = 2064.58 . . . . . . . . . . . . . . add 1343.80

  x = 14,747 . . . . . . . . . . . . . . . . divide by 0.14

$14,747 is invested at 9%; $12,129 is invested at 5%.

Answer:

V: x = 1; H: y = 4

Step-by-step explanation:

Point A is at x = 1 and y = 4

A vertical line at x=1 and a horizontal line at y = 4

The length of the confidence interval is the margin of error, which is the ratio of the standard deviation and the square root of sample size. Hence, to reduce the length of confidence interval by half, Quadruple the sample size.

Recall :

Evaluating an hypothetical scenario :

Let standard deviation, σ = 2

Sample size = 50

Margin of Error = 2/√50 = 0.554

Using Quadruple of the sample size : (50 × 4) = 200 samples

(0.227 ÷ 0.554) = 0.5

Therefore, increasing the sample size, reduces the margin of error. Hence, using quadruple the sample size, will reduce the margin of error by half.

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Answer : 19.6cm

I hope this helps you! Have a good day!

Let f = ln(x + √(x ² + y ²)) ln(sin(y/x)).

Then the total differential is

[tex]\mathrm df = \dfrac{\mathrm d\left(x+\sqrt{x^2+y^2}\right)}{x+\sqrt{x^2+y^2}}\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}\right)\dfrac{\mathrm d\left(\sin\left(\frac yx\right)\right)}{\sin\left(\frac yx\right)}[/tex]

[tex]\mathrm df = \dfrac{\mathrm dx + \frac{\mathrm d(x^2+y^2)}{\sqrt{x^2+y^2}}}{x+\sqrt{x^2+y^2}}\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}\right)\dfrac{\cos\left(\frac yx\right)\,\mathrm d\left(\frac yx\right)}{\sin\left(\frac yx\right)}[/tex]

[tex]\mathrm df = \dfrac{\mathrm dx + \frac{2x\,\mathrm dx+2y\,\mathrm dy}{\sqrt{x^2+y^2}}}{x+\sqrt{x^2+y^2}\right)\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}}\right)\dfrac{\cos\left(\frac yx\right)\frac{x\,\mathrm dy-y\,\mathrm dx}{x^2}}{\sin\left(\frac yx\right)}[/tex]

[tex]\mathrm df = \dfrac{\left(2x+\sqrt{x^2+y^2}\right)\,\mathrm dx +2y\,\mathrm dy}{x\sqrt{x^2+y^2}+x^2+y^2\right)\ln\left(\sin\left(\dfrac yx\right)\right) \\\\ \indent + \dfrac1{x^2}\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}}\right)(x\,\mathrm dy-y\,\mathrm dx)[/tex]

[tex]\mathrm df = \left(\left(\dfrac{2x+\sqrt{x^2+y^2}}{x\sqrt{x^2+y^2}+x^2+y^2}\right)\ln\left(\sin\left(\dfrac yx\right)\right) - \dfrac y{x^2}\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}\right)\right)\,\mathrm dx \\\\ \indent + \left(\dfrac{2y}{x\sqrt{x^2+y^2}+x^2+y^2}\ln\left(\sin\left(\dfrac yx\right)\right)+\dfrac1x\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}\right)\right)\,\mathrm dy[/tex]

Answer:

Step-by-step explanation:

Semicircle:

Shaded area of semicircle = area of outer semicircle - area of inner semicircle

Outer semicircle:

d = 40 m  r = 40/2 = 20m

Area of outer semicircle = πr²

                                        = 3.14*20*20

                                        =    1256 m²

Inner semicircle:

d = 30 m  r = 30/2 = 15 m

Area of outer semicircle = πr²

                                        = 3.14*15*15

                                        =  706.5 m²

Shaded area of semicircle = 1256 - 706.5 = 549.5 m²

Shaded area of semicircle in both sides = 2 * 549.5 = 1099 m²

Rectangle on both sides:

Length = 50 m

width = 30 m

Area of shaded rectangles on both sides = 2* (length *width)

                                                                      = 2* 50 * 30

                                                                       = 3000 m²

Shaded area = 1099 + 3000 = 4099 m²

Answer:

12

Step-by-step explanation:

10  8  subtract 2

8 12  add 4

12-10  subtract 2

10 14  add 4

Now we subtract 2

14-2 = 12

Answer:

The cotton is $9 per yard and the wool is $11 per yard

Step-by-step explanation:

Create a system of equations where c is the cost per yard for the cotton and w is the cost per yard for the wool.

50c + 80w = 1330

75c + 20w = 895

Solve by elimination by multiplying the bottom equation by -4:

50c + 80w = 1330

-300c - 80w = -3580

Add these together and solve for c:

-250c = -2250

c = 9

Plug in 9 as c into one of the equations, and solve for w:

50c + 80w = 1330

50(9) + 80w = 1330

450 + 80w = 1330

80w = 880

w = 11

The cotton is $9 per yard and the wool is $11 per yard.

Answer:

6x + 24

Step-by-step explanation:

6 * (4 + x) = 6 * 4 + 6 * x = 6x + 24

Answer:

Your dollar target for food service is $22,680

Step-by-step explanation:

It is given in the question that total sales are = $54,000

your food service is 42% of your total sales = 42% × $54,000

=  × 54,000

= 0.42 × 54,000

= $22,680

There are 50 different possible debating teams that could be selected as obtained using COMBINATION.

Since there are EQUAL number of juniors and seniors ;

Then we have 5 of each.

Here, the order of arrangement DOES NOT matter, Hence, we use COMBINATION

since the team MUST contain 4 SENIORS and 2 JUNIORS

4 Seniors from 5  = 5C4 = 5

2 Juniors from 5 = 5C2 = 10

Hence, (5C4 * 5C2) = 5 * 10 = 50

Hence, there are 50 different possible debating teams that could be selected.

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Answer:

((c)).g(x) = 3 × 2^x +2..

Answer:

1 and 5 sevenths of a bag

Step-by-step explanation:

2/7 males half to it takes 4/7 to make a full one multiply 4 by 3 and you get 12/7 so that makes 1 and 5/7

The sum of resistors arranged in parallel is the inverse of the sum of the inverses of the magnitudes of the individual resistances

The correct option for the resistance of the second light bulb in ohms (Ω) is option B;

B. 240

The reason why option B is the correct answer is s follows:

Known parameters:

Based on a online search, the question appears to have some parts missing which can be as follows;

The resistance of the first light bulb = 120 Ω

Janine's model of the total resistance of the circuit, [tex]t = \mathbf {\dfrac{120 \cdot r }{r + 120} }[/tex]

Where;

r = The resistance of the second light bulb

The unknown parameter:

Resistance of the second light bulb

Method:

Find r using Janine's  model of the total resistance, which is the equation of total resistances in parallel arrangement

The inverse relationship modelling the sum, t, of resistances, r, and 120, arranged in parallel, presented as follows;

[tex]\mathbf {\dfrac{1}{t} } =\dfrac{1}{120} + \dfrac{1}{r}[/tex]

∴ [tex]\mathbf {\dfrac{1}{t}} = \dfrac{r + 120 }{120 \cdot r}[/tex]

Therefore, by finding the inverse of both sides of the above equation, we get Janine's model as follows;

[tex]t = \mathbf {\dfrac{120 \cdot r }{r + 120} }[/tex]

The above equation is the inverse equation modelling the total resistance of the parallel arrangement of the resistances in the lightbulb

The question details include:

The total resistance in her circuit, t = 80 Ω

Solution:

Plugging in t = 80 in [tex]t = \mathbf {\dfrac{120 \cdot r }{r + 120} }[/tex], gives;

[tex]80 = \mathbf {\dfrac{120 \cdot r }{r + 120} }[/tex]

Therefore, we get;

80·(r + 120) = 120·r

80·r + 80 × 120 = 120·r

∴ 120·r - 80·r = 80 × 120 = 9,600

120·r - 80·r = 40·r

∴ 40·r = 9,600

r = 9,600/40 = 240

The resistance of the second light bulb, r = 240 Ω

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Answer:240

Step-by-step explanation:

i watched the walk through

Answer: y = ax2 + bx + c

looks like a slightly trick question...

y = ax2 + bx + c is the standard form...

y = a(x - h)2 +k is the graphing form

Step-by-step explanation: