In a school, the number of girls is 70 more than boys. the total number of students is 1280. find the number of girls and boys

Answer:

566

Step-by-step explanation:

I got it right..................

Answer:

1/6

Step-by-step explanation:

As usual in trigonometry, there are so many relationships between the trigonometric functions, there is bound to be more than one method to arrive at the answer.

Knowing values for the sine and cosine function for certain angles on the unit circle proves to be quite helpful.  In general, I recommend 0°, 30°, 45°, 60°, and 90° at a minimum.

Recall the following 6 things:

Knowing these 6 things (4 things from the unit circle, a way to write the tangent function in terms of sine and cosine, and the definition of a squared trig function), we can simplify the given expression down to a single number:

The definition of the tangent squared function is that the output of the tangent function is squared...

[tex]\dfrac{1-\tan^2(30^o)}{1+\tan^2(60^o)}=\dfrac{1-(\tan(30^o))^2}{1+(\tan(60^o))^2}[/tex]

Using fact 5, and turning the tangent function into sines and cosines...

[tex]=\dfrac{1-\left(\frac{\sin(30^o)}{\cos(30^o)}\right)^2}{1+\left(\frac{\sin(60^o)}{\cos(60^o)}\right)^2}[/tex]

Using facts 1-4, and substituting known values for sines and cosines...

[tex]=\dfrac{1-\left(\frac{(\frac{1}{2})}{(\frac{\sqrt{3}}{2})}\right)^2}{1+\left(\frac{(\frac{\sqrt{3}}{2})}{(\frac{1}{2})}\right)^2}[/tex]

Division is multiplication by the reciprocal...

[tex]=\dfrac{1-\left(\frac{1}{2}*\frac{2}{\sqrt{3}}\right)^2}{1+\left(\frac{\sqrt{3}}{2}*\frac{2}{1}\right)^2}[/tex]

Reducing/simplifying common factors of 2...

[tex]=\dfrac{1-\left(\frac{1}{\sqrt{3}}\right)^2}{1+(\sqrt{3})^2}[/tex]

Squaring a square root...

[tex]=\dfrac{1-\left(\frac{1}{3}\right)}{1+(3)}[/tex]

Finding a common denominator...

[tex]=\dfrac{\frac{3}{3}-\frac{1}{3}}{4}[/tex]

Definition of subtracting fractions...

[tex]=\dfrac{\frac{3-1}{3}}{4}[/tex]

Arithmetic...

[tex]=\dfrac{\frac{2}{3}}{4}[/tex]

Division is multiplication by a reciprocal...

[tex]=\dfrac{2}{3}*\dfrac{1}{4}[/tex]

Simplification and reducing the fraction...

[tex]=\dfrac{1}{6}[/tex]

So, [tex]\dfrac{1-\tan^2(30^o)}{1+\tan^2(60^o)}=\dfrac{1}{6}[/tex]

Answer:38.9

Step-by-step explanation:

A slope is also known as the gradient of a line. Slope of a line or straight object is the ratio of how much amount of rise occurs in correspondence to the increment in the run.

A slope is also known as the gradient of a line is a number that helps to know both the direction and the steepness of the line.

Slope of a line or straight object is the ratio of how much amount of rise occurs in correspondence to the increment in the run.

Thus, we get:

Slope = rise/ run

The slope of any line can found by finding the ratio of the vertical distance to horizontal distance between two ends. Therefore, the blanks can be filled as shown below.

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Answer: y = 0.75x + 80

Step-by-step explanation:

let x = 1 mile

y = 0.75x + 80

The value of x for the equation to the true is 2/3

Given the following functions

f f(x) = −3x + 4 and;

g(x) = 2

If the functions are equal, then;

-3x + 4 = 2

Subtract 4 from both sides

-3x = 2 - 4

-3x = -2

x = 2/3

Hence the value of x for the equation to the true is 2/3

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Answer:

C

Step-by-step explanation:

calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (0, 2) and (x₂, y₂ ) = (4, 0) ← 2 points on the line

m = [tex]\frac{0-2}{4-0}[/tex] = [tex]\frac{-2}{4}[/tex] = - [tex]\frac{1}{2}[/tex]

the y- intercept is the value of y where the line crosses the y- axis , then

y- intercept = 2

The values of the angles based on the information will be:

Angle 2 = 110°

Angle 3 = 70°

Angle 4 = 70°

From the information given, angle 1 is 110° and the horizontal lines n and m are intersected by lines q and p.

In this case, it should be noted that vertcally opposite angles are equal. Hence, angle 2 is also 110°.

Angle 3 will be:

= 180° - 110° = 70° (angle on a straight line).

Angle 4 will also be 70° as a vertically opposite angle to angle 3.

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Answer:

The values of the angles based on the information will be:

Angle 2 = 110°

Angle 3 = 70°

Angle 4 = 70°

Step-by-step explanation:

The method that can be used to write the equation of a line in slope-intercept form given two points is option A.

When a person wants to write the equation of a line in slope-intercept form given two points, he would have to:

Therefore, the answer is option A.

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Answer:

1a7

Step-by-step explanation:

26+-25=1

Answer:

[tex]a_{n}[/tex] = 100n - 78

Step-by-step explanation:

the nth term of an arithmetic sequence is

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

given a₁₄ = 1322 and a₃₈ = 3722 , then

a₁ + 13d = 1322 → (1)

a₁ + 37d = 3722 → (2)

subtract (1) from (2) term by term to eliminate a₁

24d = 2400 ( divide both sides by 24 )

d = 100

substitute d = 100 into either of the 2 equations and solve for a₁

substituting into (1)

a₁ + 13(100) = 1322

a₁ + 1300 = 1322 ( subtract 1300 from both sides )

a₁ = 22

then nth term formula is

[tex]a_{n}[/tex] = 22 + 100(n - 1) = 22 + 100n - 100 = 100n - 78

Option 1 corresponds to Part B , Option 2 corresponds to Part D , Option 3 corresponds to Part A , Option 4 corresponds to Part C

The complete question is attached in the image

An expression corresponds to the mathematical statement that consists of variables , Constants and mathematical operators  simultaneously.

Solving the given option will give us the answer.

(x²+15x+65)+(2x-5)*(3x+8)

(x²+15x+65)+(6x²+16x-15x-40)

(7x²+16x+25)

Option 1 corresponds to Part B

(4x+1)*(3x-4)-(5x²-10x-12)

(4x+1)*(3x-4)-(5x²-10x-12)

(12x²-16x+3x-4)-(5x²-10x-12)

(7x²-3x+8)

Option 2 corresponds to Part D

(8x²+19x+4)+(3x+2)*(x-5)

(8x²+19x+4)+(3x²-15x+2x-10)

(11x²+6x-6)

Option 3 corresponds to Part A

(6x+1)*(3x-7)-(7x²-34x-20)

(18x²-42x+3x-7)-(7x²-34x-20)

(11x²-5x+13)

Option 4 corresponds to Part C

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Answer:

==============

Imagine the height of the triangle is h, which is perpendicular to 15 m side.

The area is:

Use this formula and given values and find the value of h:

Since h is opposite to 30° angle and x is the hypotenuse of the formed right triangle, we'll use the property of 30°x60°x90° triangle.

In our case h is opposite to 30° angle, therefore we have:

Answer:

x = 16

Step-by-step explanation:

the area (A) of the triangle is calculated as

A = [tex]\frac{1}{2}[/tex] absinC

where a, b are 2 sides of the triangle and C the angle between them

here a = 15, b = x, C = 30° and A = 60 , then

[tex]\frac{1}{2}[/tex] × 15 × x × sin30° = 60

7.5x × [tex]\frac{1}{2}[/tex] = 60 ( multiply both sides by 2 to clear the fraction )

7.5x = 120 ( divide both sides by 7.5 )

x = 16

Answer:

$42.95

Step-by-step explanation:

If Chris lost $8.59 playing poker in one week, in five weeks he would lose $42.95.

$8.59 lost per week.

5 weeks.

$8.59 x 5 = $42.95.

Hope this helps!

If not, I am sorry.

Answer:

888

Step-by-step explanation:

Sahil chooses a number, [We'll call it x]

divides it by 8 ,   [x/8]

adds 8 to the answer.  [(x/8) + 8]

Then multiples the answer with 8 .  [((x/8) + 8)*8]

He obtains the result as 952 .   [((x/8) + 8)*8 = 952]

The number he chooses in the beginning was

((x/8) + 8)*8 = 952

x + 64 = 952

x = 888

CHECK:

Does (888/8 + 8)*8 = 952?

(119)*8 = 952?   YES

The number is 888

The image was formed by a reflection of the letter M would be image A in the second quadrant b the reflection on X-axis. The correct option is A.

When a graph is reflected along an axis, say x axis, then that leads the graph to go just in the opposite side of the axis as if we're seeing it in a mirror.

If you study it more, you will find that it's symmetric, thus each point is equidistant from the axis of reflection as that of the image of that point.

Thus, if you're reflecting a point (x,y) along the x-axis, then its x abscissa will stay the same but y coordinates will negate.

Thus (x,y) turns to (x, -y)

Similarly, if you're reflecting a point (x,y) along the y -axis, the resultant image of the point will be (-x,y).

The image was formed by a reflection of the letter M would be image A in the second quadrant b the reflection on X-axis. The correct option is A.

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The reflection of letter M is (A)

A figure is said to be a reflection of the other figure, then every point in a figure is at equidistant from each corresponding point in another figure.

According to the graph the reflection of Of letter M is with same coordinates but with x as positive and y as negative.

Hence the reflection is (A).

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Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a rotation about point P at; D: 105°

From the given image, If we connect points C of the blue quadrilateral to point C' of the rotated quadrilateral using the center of rotation P, then we will notice that ∠CPC' will be greater than 90°.

Now, the rotation is counterclockwise and it therefore means that the angle of rotation is will be positive and since ∠CPC' is greater than 90°, then we can say that the only correct option is Option D which is 105°

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Answer:

[tex]\frac{q+p}{2(p-q)}[/tex]

Step-by-step explanation:

[tex]\frac{4(p+q)}{p-q} *\frac{q+p}{8(p+q)}[/tex]

We will cancel out like terms.

[tex]\frac{4}{p-q} *\frac{q+p}{8}\\=\frac{4(q+p)}{8(p-q)} \\=\frac{q+p}{2(p-q)}[/tex]

The solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

Equation 1: 1 - cos(x) = 2 - 2sin²(x) from (-π, π)

The equation can be split as follows:

y = 1 - cos(x)

y = 2 - 2sin²(x)

Next, we plot the graph of the above equations (see graph 1)

Under the domain interval (-π, π), the curves of the equations intersect at:

(-π/3, 0.5) and (π/3, 0.5)

Hence, the solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

Equation 2: 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π)

The equation can be split as follows:

y = 4cos⁴(x) - 5cos²(x) + 1

y = o

Next, we plot the graph of the above equations (see graph 2)

Under the domain interval [0, 2π), the curves of the equations intersect at:

(π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

Hence, the solutions to 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π) are (π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

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1) -15+4r=-9

-15+4r=-9

We move all terms to the left:

-15+4r-(-9)=0

We add all the numbers together, and all the variables

4r-6=0

We move all terms containing r to the left, all other terms to the right

4r=6

r=6/4

r=1+1/2

2) 5-y/3=-1

5-y/3=-1

We move all terms to the left:

5-y/3-(-1)=0

We add all the numbers together, and all the variables

-y/3+6=0

We multiply all the terms by the denominator

-y+6*3=0

We add all the numbers together, and all the variables

-1y+18=0

We move all terms containing y to the left, all other terms to the right

-y=-18

y=-18/-1

y=+18

3) 42=-5x-8

42=-5x-8

We move all terms to the left:

42-(-5x-8)=0

We get rid of parentheses

5x+8+42=0

We add all the numbers together, and all the variables

5x+50=0

We move all terms containing x to the left, all other terms to the right

5x=-50

x=-50/5

x=-10

An estimate of the mean travelling time will be 24.8 mins.

The mean is the average value which can be calculated by dividing the sum of observations by the number of observations

Mean = Sum of observations/the number of observations

Given;

Time > timemark > frequency

0 – 10 > 10/2 = 5 > 5

10 – 20 > (10+20)/2 = 15 > 15

20 – 30 > (20+30)/2 = 25 > 13

30 – 40 > (30+40)/2 = 35 > 10

40 – 50 > (40+50)/2 = 45 > 7

The mean time for the 50 people can be calculated as;

Mean = Summation of (mid-time x frequency) / total frequency

Mean = [5x5 + 15x15 + 25x13 + 35x10 + 45x7] / 50

Mean = [25 + 225 + 325 + 350 + 315] / 50

Mean = 1240 / 50

Mean = 24.8 mins

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Answer:

2000 tickets were sold

Step-by-step explanation:

40% can also be written as 0.40

800/ 0.40 = 2000 total tickets

Answer:

The sum of the interior angles of any quadrilateral is 360°.

Answer:

Step-by-step explanation:

A quadrilateral is a polygon which has 4 vertices and 4 sides enclosing 4 angles and the sum of all the angles is 360°.

I'll give you an example with the square, it has 4 right angles, so the sum is 360 ° as in all quadrilaterals.

Answer:

14.

Step-by-step explanation:

If f(x) = 2x2 + 3x and g(x) = x - 2, (f + g)(2) is 14.

Answer:

14

Step-by-step explanation:

f(x) = 2x² + 3x

f(2) = 2 * 2^2 + 3(2) = 2*4 + 6 = 8+6 = 14

g(x)= x - 2

g(2) = 2-2 = 0

(f+ g)(2) = 14+0 = 14

Answer:

45 degrees

Step-by-step explanation:

A bisector divides an angle into two equal parts. Since we are dividing a 90 degree angle by 2, we get a resulting value of 45 degrees.

Step-by-step explanation:

The lcm of first question is 630 and second is 840

Answer:

LCM of 15,18,21: 630

LCM of 56,84,140: 840

Step-by-step explanation:

The right method is to list all the multiples of the number and circle the least common ones. In this way you will get your answer for any LCM question!

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

slope=(1-3)/(-2-(-5))

=-2/(-2+5)

=-2/3

Answer:

[tex]\large {\textsf{B and E}}\ \implies x_1=-2\sqrt{5}-3,\ x_2=+2\sqrt{5}-3[/tex]

Step-by-step explanation:

Quadratic Formula: [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

Quadratic Equation: ax² + bx + x = 0, where a ≠ 0

Given equation: x² + 6x + 9 = 20

Step 1: Subtract 20 from both sides.

x² + 6x + 9 - 20 = 20 - 20

⇒ x² + 6x - 11 = 0

Step 2: Identify the values of a, b, and c and substitute them in the formula.

⇒ a = 1, b = 6, c = -11

[tex]x=\dfrac{-6\pm\sqrt{\bold{6^2}-4(1)(-11)}}{\bold{2(1)}}\\\\x=\dfrac{-6\pm\sqrt{36\bold{\ - \ 4(-11)}}}{2}\\\\x=\dfrac{-6\pm\sqrt{\bold{36+44}}}{2}\\\\x=\dfrac{-6\pm\sqrt{80}}{2}\\\\x=\dfrac{-6\pm\sqrt{16\times5}}{2}\implies \dfrac{-6\pm\sqrt{\bold{16}}\times\sqrt{5}}{2} \\\\x=\dfrac{-6\pm4\sqrt{5}}{2}[/tex]

Step 3: Separate into possible cases.

[tex]x_1=\dfrac{-6-4\sqrt{5}}{2}\implies \dfrac{-6}{2}+\dfrac{-4\sqrt{5}}{2}\implies \boxed{-3-2\sqrt{5}\ \ \textsf{or}\ -2\sqrt{5}-3}\\\\x_2=\dfrac{-6+4\sqrt{5}}{2}\implies \dfrac{-6}{2}+\dfrac{4\sqrt{5}}{2}\implies \boxed{-3+2\sqrt{5}\ \ \textsf{or}\ \ 2\sqrt{5}-3}[/tex]

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