Answer:
Sure. Here are the steps on how to construct a confidence interval at a 95% confidence level for the mean amount spent on a child's last birthday gift:
Identify the sample size, n. In this case, n=13.
Identify the sample mean,
x
ˉ
. In this case, $\bar{x} = $36.
Identify the sample standard deviation, s. In this case, $s = $15.
Identify the t-critical value, t. The t-critical value is the value that cuts off 2.5% of the distribution in each tail, leaving 95% of the distribution in the middle. To find the t-critical value, we need to know the degrees of freedom, df. The degrees of freedom are calculated as df=n−1. In this case, df=13−1=12.
We can find the t-critical value using a t-distribution table. The t-distribution table shows the t-critical values for different degrees of freedom and different confidence levels. For a 95% confidence level and 12 degrees of freedom, the t-critical value is 2.179.
Calculate the confidence interval. The confidence interval is calculated as follows:
$\bar{x} \pm t \cdot \frac{s}{\sqrt{n}}$
In this case, the confidence interval is:
$36 \pm 2.179 \cdot \frac{15}{\sqrt{13}} = (27.28, 44.72)$
Therefore, a 95% confidence interval for the mean amount spent on a child's last birthday gift is $27.28 to $44.72.
Step-by-step explanation:
Bookwork code: M56
Calculator
not allowed
Select all of the options which are true of the perpendicular bisector of
line AB.
It is a fixed distance from line AB
It meets line AB at 90°
It meets line AB at 180°
It passes through A
It passes through B
It does not meet line AB
It passes through the midpoint of line AB
Answer: It meets at 90, and it passes through the midpoint.
Step-by-step explanation:
It isn't the first option because there is no distance between the line and it's bisector
It meets at AB because at a 90 degree angle because it perpendicular
Because of that, it can't also meet at a 180 degree angle
because its a bisector, it would not pass through A or B
It must meet line AB to bisect it
And because it bisects the line, it would also pass through the midpoint.
I will give brainilest and 100 points!!!!
the sum of the percent frequencies for all classes in a frequency distribution will always equalT/F
The statement "the sum of the percent frequencies for all classes in a frequency distribution will always equal" is True.
The sum of the percent frequencies for all classes in a frequency distribution will always equal 100%. This is because the percent frequency for each class is calculated by dividing the frequency of that class by the total number of observations and then multiplying by 100. Therefore, when we add up all the percent frequencies for all the classes, we get the total percentage of observations, which must be 100%.
In a frequency distribution, percent frequencies are calculated by dividing the frequency of each class by the total number of observations and then multiplying by 100. Since all observations are accounted for in the distribution, the sum of the percent frequencies for all classes will always equal 100%.
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john drives his car a distance of 16 miles to work, at a rate of m miles per hour. if, on a certain day, the car stops after only v miles, how many hours will it take john to travel the rest of the way, at the same rate?
Answer:
time left = (16 - v) / m----------------------------
Use the formula:
distance = rate x time.We know that John drives a distance of 16 miles to work at a rate of m miles per hour.
So, the time it takes him to travel the full distance is:
time = distance / rate time = 16 / mOn a certain day, the car stops after only v miles. So, the distance John still needs to travel is:
distance left = 16 - vWe also know that he will be traveling at the same rate, so we can use the formula again:
distance left = rate x time left 16 - v = m x time leftTo find the time left, we can rearrange the formula:
time left = (16 - v) / mFrom the sum of 2/9 and -3/7 subtract the difference of 3/7 & -13/23
The final result of the expression is -12,173/10,083. First, let's find the sum of 2/9 and -3/7. To add fractions, we need a common denominator. The least common multiple of 9 and 7 is 63.
To simplify the given expression, let's break it down step by step:
The sum of 2/9 and -3/7 is:
(2/9) + (-3/7)
To add these fractions, we need a common denominator, which is the least common multiple (LCM) of 9 and 7, which is 63.
(2/9) + (-3/7) = (2 * 7)/(9 * 7) + (-3 * 9)/(7 * 9)
= 14/63 - 27/63
= (14 - 27)/63
= -13/63
The difference of 3/7 and -13/23 is:
(3/7) - (-13/23)
Again, we need a common denominator, which is the LCM of 7 and 23, which is 161.
(3/7) - (-13/23) = (3 * 23)/(7 * 23) - (-13 * 7)/(23 * 7)
= 69/161 + 91/161
= (69 + 91)/161
= 160/161
Now, we subtract the second result from the first result:
(-13/63) - (160/161)
To subtract fractions, we need a common denominator, which is the LCM of 63 and 161, which is 10,083.
(-13/63) - (160/161) = (-13 * 161)/(63 * 161) - (160 * 63)/(161 * 63)
= -2,093/10,083 - 10,080/10,083
= (-2,093 - 10,080)/10,083
= -12,173/10,083.
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Answer ASAP please!!
Select the correct answer.
In a sequence described by a function, what does the notation f(3) = 1 mean?
A.
The first term in the sequence has a value of 3.
B.
The third term in the sequence has a value of 1.
C.
The common ratio of the sequence is 3.
D.
The common difference of the sequence is 3.
Answer: b
Step-by-step explanation: b
Which value is closest to 81120 ? 8 8 1/2 8 3/4 9
Answer:
Step-by-step explanation:
it is 83/49 because I searched it up.
for infinity car wash, the arrival rate is 9 / hour and the service rate is 16 / hour. the arrival and service distributions are not known so we can't use the m/m/1 formulas. if the average waiting time in the line is 23 minutes, then how many customers (waiting and being served) are at the carwash
The approximate number of customers (waiting and being served) at the carwash is 3.
To determine the number of customers (waiting and being served) at the carwash, we can use Little's Law, which states that the average number of customers in a system is equal to the average arrival rate multiplied by the average time spent in the system.
In this case, the average arrival rate is 9 customers per hour, and the average waiting time is given as 23 minutes (which is equivalent to 23/60 = 0.3833 hours).
Using Little's Law, we can calculate the average number of customers in the system:
Average number of customers = Average arrival rate * Average time spent in the system
Average number of customers = 9 customers/hour * 0.3833 hours
Average number of customers = 3.4497 customers
Since we can't have fractional customers, we round the value to the nearest whole number.
Therefore, the approximate number of customers (waiting and being served) at the carwash is 3.
It's important to note that this calculation assumes steady-state conditions and that the arrival and service distributions are not known.
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obsa has two prism shaped container. one has a volume of2 1/3 cubic feet, and the other has a volume of 4/3 cubic feet. how many smaller prisms would it take to fill the larger?
Obsa will need 2 smaller prisms to fill the larger prism, with each smaller prism having a volume of 4/3 cubic feet.
To find out how many smaller prisms it would take to fill the larger one, we need to first determine the volume of the larger prism. We know that the larger prism has a volume of 2 1/3 cubic feet, which can also be expressed as 7/3 cubic feet.
Next, we need to find out how many of the smaller prisms will fit into the larger one.
To do this, we can divide the volume of the larger prism by the volume of the smaller prism.
The smaller prism has a volume of 4/3 cubic feet, so:
(7/3 cubic feet) / (4/3 cubic feet) = 7/4
This means that it will take 7/4 smaller prisms to fill the larger prism.
However, since we can't have a fraction of a prism, we need to round up to the nearest whole number.
Therefore, it will take 2 smaller prisms to fill the larger prism. One prism will fill up 4/3 cubic feet, and the other will fill up 4/3 cubic feet, totaling to 8/3 cubic feet, which is just a bit more than the 2 1/3 cubic feet of the larger prism.
This means that it takes 1 and 3/4 smaller prisms to fill the larger container.
However, since we cannot have a fraction of a prism, we need to round up to the nearest whole number, which is 2.
Therefore, it would take 2 smaller prisms to fill the larger prism-shaped container.
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6. two cards are drawn from a standard deck of cards. the first card is not put back into the deck after being drawn. what is the probability that the first card is a diamond or the second card is face card?
Therefore, the probability that the first card is a diamond or the second card is a face card is approximately 0.3039.
We can solve this problem by using the addition rule of probability.
The probability of the first card being a diamond is 13/52 (since there are 13 diamonds in a standard deck of 52 cards). The probability of the second card being a face card is 12/51 (since there are 12 face cards left in the deck after the first card is drawn).
To find the probability that either event occurs, we add the probabilities and subtract the probability of both events happening together (since we only want to count that once):
P(diamond or face card) = P(diamond) + P(face card) - P(diamond and face card)
P(diamond or face card) = 13/52 + 12/51 - (3/51) [since there are 3 face cards that are also diamonds]
Simplifying the expression, we get:
P(diamond or face card) = 0.3039
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y[tex]y\leq -\frac{1}{2} x^2+4x+7[/tex]
The graph of the inequality is a downward-opening parabola that passes through (0, 7) and (8, -9). The shaded region is below the curve.
y≤-1/2x² + 4x + 7
The inequality is a quadratic function in standard form.
To graph it, we can find the vertex and the x-intercepts.
The vertex is at the point (h, k) where h = -b/2a and k = f(h), and f(x) = -1/2x² + 4x + 7.
a = -1/2, b = 4, and c = 7,
so h = -b/2a = -4/(-1) = 4, and
k = f(h) = -1/2(4)² + 4(4) + 7 = 15.
So the vertex is at (4, 15).
Now let us find the x-intercepts by setting y value as 0 and solve for x:
0 ≤ -1/2x² + 4x + 7
1/2x² - 4x - 7 ≤ 0
x² - 8x - 14 ≤ 0
We find roots by using the quadratic formula
x = (8 ± √8² - 4(1)(-14))) / 2
x = 4 ± √18
So the x-intercepts are 0.34 and 7.66.
Hence, the graph of the inequality is a downward-opening parabola that passes through (0, 7) and (8, -9). The shaded region is below the curve.
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Explain the graph of the inequality y≤-1/2x² + 4x + 7?
For what values of r will the area of the shaded region be greater than or equal to half of the area of the larger rectangle
(The larger rectangle has a length of 12 cm and a width of 8 cm)
(the shaded region has a length of r and a width of 6cm)
The values of r where the area of the shaded region be greater are values at least 8
Calculating the values of r where the area of the shaded region be greaterFrom the question, we have the following parameters that can be used in our computation:
The larger rectangle has a length of 12 cm and a width of 8 cm)The shaded region has a length of r and a width of 6cmThe area of the larger rectangle is
Area = 12 * 8
Area = 96
The area of the shaded region is
Area = r * 6
Area = 6r
When the shaded region is greater than or equal to half of the area of the larger rectangle, we have
6r ≥ 1/2 * 96
This gives
r ≥ 1/12 * 96
Evaluate
r ≥ 8
Hence, the values of r are r ≥ 8
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Can somebody pls answer this question fast
The solution of the expression is,
⇒ 0 + (7/11)√5
We have to given that;
Expression is,
⇒ (7 + √5) / (7 - √5) - (7 - √5) / (7 + √5)
Take LCM we get;
⇒ (7 + √5)² - (7 - √5)² / (7 - √5) (7 + √5)
⇒ (49 + 5 + 14√5) - (49 + 5 - 14√5) / (7² - √5²)
⇒ (28√5) / (49 - 5)
⇒ 28√5 / 44
⇒ 7√5 / 11
⇒ 0 + (7/11)√5
Thus, The solution of the expression is,
⇒ 0 + (7/11)√5
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The small submarine is at –1,320 feet in relation to sea level. The submarine needs to be 180 feet below sea level in 60 minutes.
How far must the submarine travel?
The small submarine must travel 1,140 feet and maintain a speed of 19 feet per minute in order to reach a depth of 180 feet below sea level within 60 minutes.
To determine the distance that the small submarine must travel to reach 180 feet below sea level, we need to use some basic math.
First, we need to determine the distance between the current position of the submarine (-1,320 feet) and its target depth (-180 feet below sea level). To do this, we subtract the target depth from the current depth:
-1,320 ft - (-180 ft) = -1,140 ft
This means that the submarine needs to travel 1,140 feet down in order to reach its target depth.
Next, we need to figure out how long it will take the submarine to travel that distance. We know that it has 60 minutes to do so, so we can use the formula:
distance = rate x time
We know the distance (1,140 feet), so we need to solve for rate. Rearranging the formula, we get:
rate = distance / time
Plugging in the values we know, we get:
rate = 1,140 ft / 60 min = 19 ft/min
So the small submarine needs to travel at a rate of 19 feet per minute in order to reach its target depth of 180 feet below sea level in 60 minutes.
In summary, the small submarine must travel 1,140 feet and maintain a speed of 19 feet per minute in order to reach a depth of 180 feet below sea level within 60 minutes.
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Rodarius wants to make a special gift for the raffle. He has 120 mini footballs and 30 signed autographs from the Titans. What is the most amount of gift packages he can make so that each recipient gets an equal number of footballs and autographs? PLSSS ANSWERR ILL GIVE POINTSS
The maximum number of gift packages that Rodarius can make is 30. Each gift package will contain 4 mini footballs and 1 signed autograph from the Titans.
To determine the maximum number of gift packages Rodarius can make so that each recipient gets an equal number of footballs and autographs, we need to find the greatest common factor (GCF) of the two numbers, 120 and 30.
The prime factorization of 120 is:
120 = 2³ x 3 x 5
The prime factorization of 30 is:
30 = 2 x 3 x 5
To calculate the GCF, multiply the product of the common factors by the lowest exponent:
GCF = 2 x 3 x 5 = 30
So the maximum number of gift packages that Rodarius can make is 30. Each gift package will contain 4 mini footballs and 1 signed autograph from the Titans.
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Write x2 + 4x − 5 = 0 in the form of (x − a)2 = b, where a and b are integers.
a
(x + 4)2 = 9
b
(x + 4)2 = 5
c
(x + 2)2 = 9
d
(x + 2)2 = 3
Answer:
C. (x+2)2=3
Step-by-step explanation:
Take the root of both sides and solve.
Both x2+4x-5=0 and (x+2)2=3 have the solution of x=1,-5
have a great day and thx for your inquiry :)
in general, how does the number of zeroes (or x-intercepts) relate to the highest power of a polynomial? be specific. can you make a statement about the minimum number of zeroes as well as the maximum?
The number of zeroes or x-intercepts of a polynomial function is related to its highest power, which is determined by the degree of the polynomial. Let's consider a polynomial of degree "n" where "n" is a positive integer.
How to explain the informationThe minimum number of zeroes or x-intercepts a polynomial can have is zero. This occurs when all the terms of the polynomial have non-zero coefficients and there are no factors that would cause the polynomial to equal zero. For example, a polynomial of degree 2, such as f(x) = x^2 + 1, has no zeroes.
The maximum number of zeroes or x-intercepts a polynomial of degree "n" can have is "n". This is known as the Fundamental Theorem of Algebra, which states that a polynomial of degree "n" can have at most "n" distinct zeroes.
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Let p represent the regular price of one poster. Which equation represents
Sunita's purchase?
5(p-3)=63
What is the regular price of one poster?
$
Answer:
p=$16.5
Step-by-step explanation:
By using the distributive Property, you can say:
5p-15=63
Then add 15 on both sides to make the equation balanced:
5p=78
Then divide by 5:
p=78/5=$16.5
SECTION 11 17. Half the sum of the present ages of a mother and daughter equal to the clipference bhen their ages now. In lour's time the mother's age will be exactly twice the daughter's ag Calculate their present ages
Answer:
Step-by-step explanation:
let the present age of mother and daughter be x and y
[tex]\frac{1}{2} * (x + y) = x - y\\x + y = 2x - 2y\\x = 3y --- (1)\\[/tex]
[tex]x+4 = 2(y+4)\\3y+4 = 2y + 8\\y = 4\\x = 3y = 12[/tex]
Age of mother = 12 yrs
Age of daughter = 4 yrs
a) find a power series representation for f (x) =ln(1+x).
What is the radius of convergence?
b)use part (a) to find a power series for f (x) = xln(1+x).
c)use part (a) to find a power series for f(x)ln(x2 + 1)
a) The radius of convergence is also 1, since it is the same as the radius of convergence of ln(1+x).
a) We can find a power series representation for f(x) = ln(1+x) by using the formula:
ln(1 + x) = ∑(-1)^(n-1) * x^n / n for |x| < 1
So, the power series representation for ln(1+x) is:
ln(1 + x) = x - x^2/2 + x^3/3 - x^4/4 + x^5/5 - ...
The radius of convergence is 1, since the series converges for |x| < 1 and diverges for |x| > 1.
b) To find a power series for f(x) = xln(1+x), we can use the product rule of power series:
xln(1 + x) = x * [x - x^2/2 + x^3/3 - x^4/4 + x^5/5 - ...]
= x^2 - x^3/2 + x^4/3 - x^5/4 + x^6/5 - ...
So, the power series representation for f(x) = xln(1+x) is:
f(x) = xln(1+x) = ∑(-1)^(n-1) * x^(n+1) / n for |x| < 1
c) To find a power series for f(x)ln(x^2 + 1), we can use the product rule of power series again:
f(x)ln(x^2 + 1) = [x - x^2/2 + x^3/3 - x^4/4 + x^5/5 - ...] * ln(x^2 + 1)
= [xln(x^2 + 1)] - [x^2 ln(x^2 + 1)]/2 + [x^3 ln(x^2 + 1)]/3 - [x^4 ln(x^2 + 1)]/4 + [x^5 ln(x^2 + 1)]/5 - ...
We already have a power series for xln(1+x), which is the same as xln(x^2+1) for |x| < 1. So, we can substitute it in the above series:
f(x)ln(x^2 + 1) = ∑(-1)^(n-1) * x^(2n+1) / (2n+1) * [1 - 1/2 + 1/3 - 1/4 + 1/5 - ...]
= ∑(-1)^(n-1) * x^(2n+1) / (2n+1) * ln(x^2 + 1)
The radius of convergence of this power series is also 1, since it is the same as the radius of convergence of ln(1+x) and xln(1+x).
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find an expression for the general term of the series and give the range of values for the index.
ex2 = 1+x2+x4/2!+x6/3!+x8/4!+......
the series ex2 converges for all real values of x.
The general term of the series ex2 = 1 + x^2 + x^4/2! + x^6/3! + x^8/4! + ... is given by:
an = xn/(n!) for n ≥ 0, where n is an even integer.
Here, xn represents the term with exponent n in the series.
Therefore, the range of values for the index n is all even non-negative integers starting from 0.
Note that n! (n factorial) in the denominator of the general term ensures that each term after the first term (which is 1) is smaller than the preceding term, as n increases.
what is integer?
An integer is a whole number that can be positive, negative, or zero. It does not include fractions or decimals. Examples of integers include -3, -2, -1, 0, 1, 2, 3, and so on. The set of integers is denoted by the symbol Z.
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If angle 5=91-2x and angle 10=5x find the value of x
The value of x for the same angle based on the information is 13.
How to calculate tie angleIn Plane Geometry, a figure which is formed by two rays or lines that shares a common endpoint is called an angle
Since angles 5 and 10 are the same, we can set them equal to each other:
91 - 2x = 5x
Simplifying this equation, we can add 2x to both sides:
91 = 7x
Then, we can divide both sides by 7 to solve for x:
x = 13
Therefore, the value of x for the same angle is 13.
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uppose that the time it takes to get service in a restaurant follows an expo- nential distribution with mean 10 minutes. find the 75th percentile of the wait time.
The 75th percentile of the wait time in a restaurant, assuming it follows an exponential distribution with a mean of 10 minutes, can be found using the inverse of the exponential cumulative distribution function.
In an exponential distribution, the probability density function (PDF) is given by f(x) = λe^(-λx), where λ is the rate parameter. The mean of the exponential distribution is equal to 1/λ. In this case, we are given that the mean is 10 minutes, so λ = 1/10.
To find the 75th percentile, we need to find the value x for which P(X ≤ x) = 0.75. In other words, we want to find the value of x such that 75% of the wait times are less than or equal to x.
Using the exponential cumulative distribution function (CDF), we can solve for x by setting P(X ≤ x) = 0.75 and solving for x. The formula for the exponential CDF is F(x) = 1 - e^(-λx).
Setting 1 - e^(-λx) = 0.75, we can solve for x to find the 75th percentile of the wait time.
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Harley-Davidson Inc. Currently has $750,000 in accounts receivable, and its days sales outstanding (DSO) is 55 days. It wants to reduce its DSO to 35 days by pressuring more of its customers to pay their bills on time. If this policy is adopted, the company’s average sales will fall by 15%. What will be the level of accounts receivable following the change? Assume a 365-day year
The level of accounts receivable will be $479,452.05.
If Harley-Davidson Inc. reduces its DSO to 35 days by pressuring more of its customers to pay their bills on time, the company’s average sales will fall by 15%. To calculate the level of accounts receivable following this change, we need to use the formula for DSO:
DSO = (Accounts Receivable / Average Daily Sales) x Number of Days in Period
We know that the current DSO is 55 days, and the company wants to reduce it to 35 days. Therefore, we can assume that the current average daily sales are:
Average Daily Sales = Annual Sales / 365
DSO = (Accounts Receivable / Average Daily Sales) x Number of Days in Period
55 = ($750,000 / (Annual Sales / 365)) x 365
Solving for Annual Sales, we get:
Annual Sales = $1,095,890.41
If the company’s average sales will fall by 15%, then the new Annual Sales will be:
New Annual Sales = $931,507.85 ($1,095,890.41 - 15%)
Using this new Annual Sales figure, we can now calculate the new level of accounts receivable following the change:
35 = (New Accounts Receivable / (New Annual Sales / 365)) x 365
New Accounts Receivable = $479,452.05
Therefore, if Harley-Davidson Inc. reduces its DSO to 35 days by pressuring more of its customers to pay their bills on time and its average sales fall by 15%, the level of accounts receivable will be $479,452.05.
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mike has under 1/4 of a tank of gas, and he decides to fill up his gas tank. his gas tank holds 16 gallons. the gas cost $3.59 per gallon. approximately, how much will it cost mike to fill up his car?
Mike has under 1/4 of a tank of gas, and he decides to fill up his gas tank. his gas tank holds 16 gallons. the gas cost $3.59 per gallon. It will cost Mike $43.08 to fill up his car.
To help you with your question, we first need to determine the amount of gas Mike needs to fill up his car. Since he has less than 1/4 of a tank, let's assume he has exactly 1/4 of a tank for simplicity.
Mike's car has a 16-gallon gas tank, so:
1/4 * 16 gallons = 4 gallons already in the tank.
To fill up the tank, Mike needs to add:
16 gallons - 4 gallons = 12 gallons.
The gas costs $3.59 per gallon, so to find the total cost:
12 gallons * $3.59 = $43.08.
Approximately, it will cost Mike $43.08 to fill up his car.
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please answer the question in the image
[tex]\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta r^2}{2} ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ r=6\\ \theta =\frac{\pi }{6} \end{cases}\implies A=\cfrac{(\frac{\pi }{6})(6)^2}{2} \\\\\\ A=3\pi \implies A\approx 9.42~m^2[/tex]
HELP!! Please!! i will write brainuiest.
Answer:
20
Step-by-step explanation:
16 / 20 = 0.80
0.80 = 80%
This question is really confusing me, thank you so much if you can explain it to me, I would really appreciate it.
Factor completely.
9j² - 25k6
Enter your answer in the blanks in order from left to right.
(Oj − Okº) (Oj + k)
-
Blank # 1
Blank # 2
Blank # 3
Blank #4
Blank # 5
Blank # 6
Step-by-step explanation:
(3j - 5k^3) ( 3j + 5k^3) = 9j^2 - 25k^6
HELP NOW IT IS 6th GRADE MATH HELPPPPPP
Answer:
S=2t
or
T=1/2 S
Whic if the following functions is graphed
The piecewise function graphed in this problem is defined as follows:
y = x + 6, x ≤ 1.y = x² + 3, x > 1.What is a piece-wise function?A piece-wise function is a function that has different definitions, depending on the input of the function.
The definitions for this problem are given as follows:
Up to x = 1.Greater than x = 1.For the function up to x = 1, the function is a linear function with slope of 1 and intercept of 6, hence:
y = x + 6, x ≤ 1.
For the function greater than x = 1, the quadratic function y = x² + 3 is defined, hence:
y = x² + 3, x > 1.
More can be learned about piece-wise functions at brainly.com/question/19358926
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