The confidence interval estimates that the confidence interval limits contain 0., suggesting that the garlic treatment did not affect the LDL cholesterol levels.
A confidence interval is a range of estimates for an unknown parameter in frequentist statistics. The 95 percent confidence level is the most common, but other levels, like 90 percent or 99 percent, are occasionally used when computing a confidence interval.
Given in a test of effectiveness of garlic for lowering cholesterol, 50 subjects were treated with garlic in a processed tablet form.Both before and after the therapy, cholesterol levels were assessed.
LDL cholesterol variations had a mean of 4.4 and a standard deviation of 19.4 (in mg/dL). The best point estimate is 4.4.
We have to find 95% confidence interval estimate of the population mean
So,
x-bar = 4.4
ME = 1.96 = 5.27
H: no difference
Ha: is a difference
We fail to reject H since 0 is in the CI.
Hence the confidence interval estimates that the confidence interval limits contain 0., suggesting that the garlic treatment did not affect the LDL cholesterol levels.
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3x+7-6=(8/7)-0
Value of x?
Answer:
[tex]\boxed{\sf x = \dfrac{1}{21}}[/tex]
Explanation:
[tex]\rightarrow \sf 3x+7-6= \dfrac{8}{7} - 0[/tex]
simplify the following
[tex]\rightarrow \sf 3x+1= \dfrac{8}{7}[/tex]
subtract 1 from both sides
[tex]\rightarrow \sf 3x+ 1 -1= \dfrac{8}{7} - 1[/tex]
simplify the following
[tex]\rightarrow \sf 3x= \dfrac{1}{7}[/tex]
multiply both sides by 1/3
[tex]\rightarrow \sf 3x \cdot \dfrac{1}{3}= \dfrac{1}{7}\cdot \dfrac{1}{3}[/tex]
simplify the following
[tex]\rightarrow \sf x = \dfrac{1}{21}[/tex]
[tex]3x + 7 - 6 = \frac{8}{7} - 0 \\ \\ 3x + 1 = \frac{8}{7} \\ \\ 3x = \frac{8}{7} - 1 \\ \\ 3x = \frac{ 8 - 7}{7} \\ \\ 3x = \frac{1}{7} \\ \\ x = \frac{1}{7 \times 3} \\ \\ x = \frac{1}{21} .[/tex]
A coin is tossed, and a die is rolled. What is the probability that the outcome is a head or an even number?
Answer: When a coin is tossed and a die is rolled the probability of getting a head or an even number is = 3/4
Step-by-step explanation:
probability : The ratio of the favorable outcome to the total outcomes is gives the probability.
So for the given case all possible outcomes are = 12(1,H),(1,T),(2,H),(2,T),(3,H),(3,T),(4,H),(4,T),(5,H),(5,T),(6,H),(6,T)
total no of outcomes when there is head on coin are = 6(1,H),(2,H),(3,H),(4,H),(5,H),(6,H)
Total no of outcomes when there is even on dice are = 3(2,T),(4,T),(6,T)
So the total number of favorable outcomes are:6+3 = 9
Total outcomes = 12Therefore the probability is given by 9/12 = 3/4
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Answer: The probability of getting a head or an even number is = 3/4
What is probability?It is the measure of how likely an event or outcome is. Different events have different probabilities!For the given case: Possible outcomes are(1,H),(1,T),(2,H),(2,T),(3,H),(3,T),(4,H),(4,T),(5,H),(5,T),(6,H),(6,T)
So, no. of possible outcomes 12
No. of coin outcomes (when it's head) = 6(1,H),(2,H),(3,H),(4,H),(5,H),(6,H)
No of dice outcomes (when it's even) = 3(2,T),(4,T),(6,T)
So the total number of favourable outcomes are:6+3 = 9
Total outcomes = 12
Probability = [tex]\frac{No. of favorable outcomes}{total outcomes}[/tex]
Probability for this case is = [tex]\frac{9}{12} =\frac{3}{4}[/tex]
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) The correlation between a car’s engine size and its fuel economy (in mpg) is r= -0.774. What fraction of the variability in fuel economy is accounted for by the engine size?
The fraction of the variability in fuel economy is accounted for by the engine size is 59.91%.
Given that, r= -0.774.
To solve such problems we must know about the fraction of the variability in data values or R-squared.
What fraction of the variability in fuel economy is accounted for by the engine size?The fraction by which the variance of the dependent variable is greater than the variance of the errors is known as R-squared.
It is called so because it is the square of the correlation between the dependent and independent variables, which is commonly denoted by “r” in a simple regression model.
Fraction of the variability in data values = (coefficient of correlation)²= r²
Now, the variability in fuel economy = r²= (-0.774)²
= 0.599076%= 59.91%
Hence, the fraction of the variability in fuel economy accounted for by the engine size is 59.91%.
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Solve the following triangle. Round side measure to the nearest tenth and angle measure to the nearest degree:
Answer: [tex]AB=4.7, BC=8.8, \angle C=28^{\circ}[/tex]
Step-by-step explanation:
As angles in a triangle add to 180 degrees,
[tex]\angle C=180^{\circ}-90^{\circ}-62^{\circ}=\boxed{28^{\circ}}[/tex]
We know that:
[tex]\sin 62^{\circ}=\frac{BC}{10}\\\\BC=10\sin 62^{\circ} \approx \boxed{8.8}[/tex]
Similarly,
[tex]\cos 62^{\circ}=\frac{AB}{10}\\\\AB=10\cos 62^{\circ} \approx \boxed{4.7}[/tex]
A concert manager counted 600 ticket receipts the day after a concert. The price for a student ticket was $13.50, and the price for an adult ticket was $17.00. The register confirms that $9,587.50 was taken in. How many student tickets and adult tickets were sold?
The number of student tickets is 175 and the number of adult tickets is 425.
What is an expression?Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Given that:-
A concert manager counted 600 ticket receipts the day after a concert. The price for a student ticket was $13.50, and the price for an adult ticket was $17.00. The register confirms that $9,587.50 was taken inSuppose the number of the student ticket is St and adult are At.
St + At = 600
St = 600 - At
Another expression for the total amount will be given as:-
13.5St + 17At = 9587.50
Put the value of St in the equation to find the value of At.
13.5( 600 - At) + 17At = 9587.50
8100 - 13.5At +17At = 9587.5
17At - 13.5 At = 9587. 5 - 8100
3.5 At = 1487.5
At = 425
St + At = 600
St = 600 - At = 600 - 425 = 175
Therefore the number of student tickets is 175 and the number of adult tickets is 425.
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Which expression is equivalent to One-fifth (150 x minus 80 y + 50 minus 50 x minus 25 y + 20)?
20 x minus 21 y + 14
20 x + 11 y + 14
20 x minus 11 y + 6
20 x + 21 y + 6
Answer:
150 x - 80 y + 50 - 50 x - 25 y + 20
Arranging like terms
150 x - 50 x -25 y - 80y + 50 + 20
100x - 105 y + 70
5 ( 20x - 21y + 14)Answer:
20x - 21y + 14
Explanation:
[tex]\rightarrow \sf \dfrac{1}{5} (150x - 80y + 50 - 50x - 25y + 20)[/tex]
collect like terms
[tex]\rightarrow \sf \dfrac{1}{5} (150x-50x - 80y -25y + 50 + 20)[/tex]
add/subtract like terms
[tex]\rightarrow \sf \dfrac{1}{5} (100x - 105y+70)[/tex]
distribute inside parenthesis
[tex]\rightarrow \sf \dfrac{1}{5} (100x) + \dfrac{1}{5}( - 105y) + \dfrac{1}{5}(70)[/tex]
simplify the following
[tex]\rightarrow \sf 20x -21y + 14[/tex]
Evaluate
3(x+4)(x+1)
HP for x = 4.
(x+2)(x-2)
Answer:
120
Step-by-step explanation:
3(x+4)(x+1)
3((4)+4) ((4)+1)
(12 + 12)(4+1)
(24)(5)
120
If you need the other function, here:
(4+2)(4-2)
6(2)
12
Answer:
below
Step-by-step explanation:
3×x=12
3×4=12
3(x+4)=12+12+12+3=39
A student needed to find the measure of angle b. She incorrectly said mZb=118°. Find the correct measure of angle b. What mistake did she likely make?
Answer:
D
Step-by-step explanation:
To find angle B, you should subtract 62 from 90 since because a right angle is 90 degrees.
Find the measure of PR.
The length of PR = 18 .
What is a Chord ?A chord is a line segment whose both points lie on the circle.
When a chord is extended it is called secant .
When two chords meet outside the circle , the product of length of the secant and its external segment is equal to the product of length of other secant and its external segment.
According to the given data
FR and FP are the secants of the circle
To determine the measure of PR
From the secant theorem
(7+9) * 9 = (5x+8) * 8
16 * 9 = (5x+8) *8
2 *9 = 5x+8
18 = 5x+8
5x = 10
x = 2
Therefore the length of PR = 5x+8 = 10+8 = 18
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Help me with this question please!! :)
Answer: 20/63
Step-by-step explanation:
The probability that the first marble is red is 16/28.The probability that the second marble is red is 15/27.Multiplying these probabilities, we get (16/28)(15/27) = 20/63
2) An electronic gadgets distributor distributes various brands of mobiles to retailers.
The data for the number of smartphones distributed in nine months (Jan-Sep) are
collected to make a box-and-whisker plot. Read the plot and answer the questions.
H
20
30
40
a) Write the median from the above given plot.
b) What is the least number of smartphones distributed?
c) Write the third quartile from the given plot.
50
t>
60
The median is 40, the least number of smartphones distributed is 33, and the third quartile is 48.
What is the box and whisker plot?A box and whisker plot is a method of abstracting a set of data that is approximated using an interval scale. It's also known as a box plot. These are primarily used to interpret data.
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
We have a box and whisker plot shown in the picture.
From the box plot, the line between the box ends represents the median of the data.
The median = 40
The least number of smartphones distributed = 33
Q3 = 48
Thus, the median is 40, the least number of smartphones distributed is 33, and the third quartile is 48.
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Dan Barker, the chief engineer, told Ms. Silva that the company is currently making 150 units of Model Diamond per batch and 245 units of Model Gold per batch. He suggests doubling the batch sizes to cut the number of setups in half, thereby reducing the setup cost by 50 percent. Compute the cost per unit for each product if Ms. Silva adopts his suggestion.
The cost per unit for each product is given as:
x ≈ 0.0067; and
y ≈ 0.0041. See explanation below.
What is the cost per unit for each product?Given that the current production:
Model Diamond (Md) - 150 UnitsModel Gold (Mg) - 245 UnitsCurrent cost of production is given as:
Current Total Cost = 150y + 245x where;
if doubling the batch sizes will reduce the cost per unit by 50% then the new cost equation will be:
Thus, New Total Cost of production = (150 x 2) (y/2) + (245 x 2) (x/2)
= (300)(y/2) + (490) (x/2)
Since we are looking for the cost per unit of each product:
f(x) = 300 * (x/2)..........Unit cost of Model Gold
If we make x subject of the formula, then we arrive at:
1/300 = x/2
x = (1/300) * 2
x = 0.00666666666
x ≈ 0.0067
f(x) = 490* (x/2)
If we make y subject of the formula, then we arrive at:
i/490 = y/2
y = (1/490) * 2
y = 0.00408163265306122448979591836735
y ≈ 0.0041
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Change a Relation to Make It a Function The relation R is shown below as a list of ordered pairs. R = { (1, 4), (1, 3), (-1, 3), (2, 15) } Which ordered pairs prevent this relation from being a function? (1, 4) and (1, 3), because they have the same x-value (1, 3) and (–1, 3), because they have the same y-value
Answer: (1,4) and (1,3) because the have the same x-value
Step-by-step explanation:
A function is defined so that for each input (known as the domain), there is no more than one output (known as the range).
HELP ME !!!!!!! Which of the following best describes a single fixed point that is the same
distance from the parabola as the directrix is from the parabola?
A. center
B. vertex
C. focus
D. locus
Answer:
C. Focus
.............
Please answer all four of the questions please I will mark u brainliest
Answer:
1: 8 ft
2: 10 cm
3: c is approximately 127.2 or exactly equal to 90 * sqrt(2)
4: sqrt(133)
Step-by-step explanation:
(1) Kevin tries to climb a wall with a ladder. The length of a ladder is 17 feet and it reaches only 15 feet up the wall. What is the distance between the base of the ladder and the wall? :
Here you can use the Pythagorean Theorem to find the length of the base.
the equation is a^2 + b^2 = c^2 where c is the hypotenuse. In this case 17 is the hypotenuse which is c, 15 is a or b it doesn't really matter where you put it.
a^2 + (15)^2 = 17^2
a^2 + 225= 289
a^2 = 64
a = 8
(2) In a right triangle, if the length of one leg is 8 cm and the length of the other leg is 5 cm, what is the length of the hypotenuse? :
The same formula can be used except you don't have to move anything around.
8^2 + 6^2 = c^2
64 + 36 = c^2
100 = c^2
10 = c
10 cm
A baseball field is a square with sides of length 90 feet. What is the shortest distance between the first base and the third base?:
So if you look at the image provided, the shortest distance is just a straight line, but more specifically that straight line forms two triangles with the same lengths, That line is the hypotenuse so you can use the same equation as the previous equations
90^2 + 90^2 = c^2
16,200 = c^2
c is approximately 127.2 or exactly equal to 90 * sqrt(2)
(4) How far up a wall will a 13-meter ladder reach, if the foot of the ladder is 6 meters away from the base of the wall?:
6^2 + b^2 = 13^2
36 + b^2 = 169
b^2 = 133
b = sqrt(133)
pls help with thisc...................................
Answer:
D
598*47+38=
28106+38=
28134
Suppose we want to choose 7 colors, without replacement, from 9 distinct colors
If the order of the choices does not matter, how many ways can this be done?
The number of ways to choose the colors is 36
How to determine the number of ways?The given parameters are:
Colors = 9
Colors to choose = 7
Since order does not matter, then it is combination
This is calculated using:
[tex]^nC_r = \frac{n!}{(n - r)!r!}[/tex]
This gives
[tex]^nC_r = \frac{9!}{7!2!}[/tex]
Evaluate
[tex]^nC_r = 36[/tex]
Hence, the number of ways is 36
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Karen runs 7 miles in 50 minutes. At the same rate, how many miles would she run in 75 minutes?
Answer :
10.5 miles
Given :
7 miles in 50 mins
Step-by-step explanation :
Calculate how many miles in 1 minute :
Divide both by 50 :
7/50 miles in 1 minute
To work out 75 minutes we multiply both by 75 :
75 × 7/50 =
10.5
Therefore our final answer is 10.5 miles
Hope this helped and have a good day
why f is not differentiable at x = 0 , where f(x) is x ^1/3
Therefore the f is continuous on R , i.e. real numbers and f is not differentiable at 0 ,Option A and D is the correct answer.
What is a Function ?A function is a mathematical statement which find relation between independent variable and dependent variable.
It always comes with a defined range and domain.
It is given that :
[tex]\rm f(x) = x^{1/3}\\\\LHD (at\; x = 0) = RHD (at \; x = 0)\\\\\= \lim_{x\rightarrow 0}\dfrac{f(x)-f(0)}{x-0}\\\\=\lim_{h\rightarrow 0}\dfrac{f(0-h)-f(0)}{0-h-0}[/tex]
[tex]=\lim_{h\rightarrow 0}\dfrac{f(0-h)-f(0)}{0-h-0} \\\\= \lim_{h\rightarrow 0}\dfrac{(-h)^{1/3}}{-h}\\\\\lim_{h\rightarrow 0}\dfrac{(-1)^{1/3}(h)^{1/3}}{-1*h}\\\\\lim_{h\rightarrow 0} (-1)^{-2/3}h^{-2/3}[/tex]
if we substitute h = 0 ,
Here, LHD and RHD does not exist at x = 0 So, f(x) is not differentiable at x = 0 .
Therefore the f is continuous on R , i.e. real numbers
and f is not differentiable at 0
Option A and D is the correct answer.
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Two parallel lines are intersected by a third line so that angles 1 and 5 are congruent.
2 parallel horizontal lines are intersected by a third line. On the first horizontal line where the third line intersects, 4 angles are created. Labeled clockwise, from uppercase left, the angles are 1, 2, 4, 3. On the second horizontal line, where the third line intersects, 4 angles are created. Labeled clockwise, from uppercase left, the angles are 5, 6, blank, blank.
Which statement is true about angles 3 and 5?
They are acute.
They are congruent.
They are complementary.
They are supplementary.Two parallel lines are intersected by a third line so that angles 1 and 5 are congruent.
2 parallel horizontal lines are intersected by a third line. On the first horizontal line where the third line intersects, 4 angles are created. Labeled clockwise, from uppercase left, the angles are 1, 2, 4, 3. On the second horizontal line, where the third line intersects, 4 angles are created. Labeled clockwise, from uppercase left, the angles are 5, 6, blank, blank.
Which statement is true about angles 3 and 5?
They are acute.
They are congruent.
They are complementary.
They are supplementary.
Answer:
4. They are supplementary
Answer:
4 they are supplemental
Solve based off of the screenshot provided below.
Answer:
48 cm²
Explanation:
The figure can be cut into 1 rectangle and 1 triangle.
Area of the figure:
⇒ area of rectangle + area of triangle
⇒ Length × Width + 1/2 × Base × Height
⇒ 6 × 4 + 1/2 × 6 × 8
⇒ 24 + 24
⇒ 48
Therefore, area of figure is 48 cm².
Answer:
48 cm squared
Step-by-step explanation:
The given figure is composed of a rectangle (L=6 cm and W = 4 cm) and a right angled triangle { Base = (12- 4) = 8 cm, height = 6 cm. }
Area of the two figures is to be calculated separately and then added to get the required result.
Area of the rectangle = l × w
= 6 × 4
= 24 cm²
Area of the right triangle = ½ × base × height
= ½ × 8 × 6
= 24 cm²
Hence, area of the given figure = 24 + 24
= 48 cm squared.
The Scooter Company manufactures and sells electric scooters. Each scooter cost $150 to produce, and the company has a fixed cost of $2,000. The Scooter Company earns a total revenue that can be determined by the function R(x) = 400x − 2x2, where x represents each electric scooter sold. Which of the following functions represents the Scooter Company's total profit?
−2x2 − 150x − 2,000
−2x2 + 250x − 2,000
−2x2 + 150x − 1,600
−300x3 − 4,000x2 + 60,000x + 800,000
The function that represents the Scooter Company's total profit is given by:
P(x) = -2x² + 250x - 2,000.
How to calculate the profit function?The profit function is calculated by the revenue function subtracted by the cost function, hence:
P(x) = R(x) - C(x).
In this problem, we have that:
The revenue function is: R(x) = 400x - 2x².The cost function is: X(x) = 150x + 2000.Hence the profit function is:
P(x) = R(x) - C(x).
P(x) = 400x - 2x² - (150x + 2000).
P(x) = -2x² + 250x - 2,000.
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who is known as the father of computer
Answer:
Charles Babbage
Step-by-step explanation:
Answer: Hope this may help you
Charles Babbage, I think
Step-by-step explanation:
Charles Babbage is sometimes referred to as the father of computers.
On the SAT exam a total of 25 minutes is allotted for students to answer 20 math questions without the use of a calculator. A guidance counselor would like to know if the students in his school are prepared to complete this portion of the exam in the timeframe allotted. To investigate, the counselor selects a random sample of 35 students and administers this portion of the test. The students are instructed to turn in their test as soon as they have completed the questions. The mean amount of time taken by the students is 23.5 minutes with a standard deviation of 4.8 minutes. The counselor would like to know if the data provide convincing evidence that the true mean amount of time needed for all students of this school to complete this portion of the test is less than 25 minutes and therefore tests the hypotheses H0: μ = 25 versus Ha: μ < 25, where μ = the true mean amount of time needed by students at this school to complete this portion of the exam. The conditions for inference are met. What are the appropriate test statistic and P-value? Find the t-table here. t = –1.85; the P-value is 0.9678. t = –1.85; the P-value is between 0.025 and 0.05. t = 1.85; the P-value is 0.9678. t = 1.85; the P-value is between 0.025 and 0.05.
Using the t-distribution, the correct option regarding the test statistic and the p-value is given as follows:
t = –1.85; the P-value is between 0.025 and 0.05.
What are the hypothesis tested?
The null hypothesis is:
[tex]H_0: \mu = 25[/tex]
The alternative hypothesis is:
[tex]H_1: \mu < 25[/tex]
What are the test statistic and the p-value?The test statistic is given by:
[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]
The parameters are:
[tex]\overline{x}[/tex] is the sample mean.[tex]\mu[/tex] is the value tested at the null hypothesis.s is the standard deviation of the sample.n is the sample size.In this problem, the values of the parameters are given as follows:
[tex]\overline{x} = 23.5, \mu = 25, s = 4.8, n = 35[/tex]
Hence the value of the test statistic is:
[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]
[tex]t = \frac{23.5 - 25}{\frac{4.8}{\sqrt{35}}}[/tex]
t = -1.85.
Using a t-distribution calculator, with a left-tailed test, as we are testing if the mean is less than a value and 35 - 1 = 34 df, the p-value is of 0.0365.
Hence the correct statement is:
t = –1.85; the P-value is between 0.025 and 0.05.
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A candle burns down at the rate of 0.5 inches per hour. The original height of the candle was 8 inches.
Part A: Write a list of 6 ordered pairs to show the height of the candle in inches (y) as a function of time in hours (x) from the first hour after it started burning. For example, the point (0, 8) would represent a height of 8 inches after 0 hours. Explain how you obtained the ordered pairs. (5 points)
Part B: Is this relation a function? Justify your answer using the list of ordered pairs you created in Part A. (2 points)
Part C: If the rate at which the candle burned was 0.4 inches per hour instead of 0.5 inches per hour, would the relation be a function? Explain your answer using input and output values. (3 points)
The ordered pairs are (0,8), (1, 7.5), (2, 7), (3,6.5), (4, 6) and (5, 5.5)
How to determine the ordered pairs?The given parameters are:
Initial height, h = 8 inches
Rate = 0.5 inches per hour
The height of the candle at x hour is:
y = Initial - rate * x
This gives
y = 8 - 0.5x
Set x = 0 to 5
y = 8 - 0.5(0) = 8
y = 8 - 0.5(1) = 7.5
y = 8 - 0.5(2) = 7
y = 8 - 0.5(3) = 6.5
y = 8 - 0.5(4) = 6
y = 8 - 0.5(5) = 5.5
So, the ordered pairs are (0,8), (1, 7.5), (2, 7), (3,6.5), (4, 6) and (5, 5.5)
Is the relation a function?In (a), we have:
y = 8 - 0.5x
The above is a linear relation.
All linear relations are functions
Hence, the relation is a function.
Would a new relation be a function?
We have
Initial height, h = 8 inches
New rate = 0.4 inches per hour
The height of the candle at x hour is:
y = Initial - rate * x
This gives
y = 8 - 0.4x
The above is a linear relation.
All linear relations are functions
Hence, the new relation is also a function.
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In the last three years Frederic’s basketball team win 40 more games than they lost
Answer:
Wht is the total matches they played?
The number of wrecks at a certain intersection varies directly as the number of cars that travel through the intersection. If there are 31 wrecks when 1,085 cars have traveled through the intersection, how many cars have passed through the intersection after 7 wrecks?
The number of cars that have passed through the intersection after 7 wrecks is 1/5 cars
Direct variationNumber of wrecks = wNumber of cars = cw = k × c
31 = k × 1,085
31 = 1,085k
k = 1085/31
k = 35
If w = 7
w = k × c
7 = 35 × c
7 = 35c
c = 7/35
c = 1/5 car
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How do I find dy/dx of the following?
Answer:
[tex]\displaystyle\frac{dy}{dx} \ = \ 3x^{2} \ + \ \displaystyle\frac{1}{2\sqrt{x^{3}}} \ - \ \displaystyle\frac{12}{x^{5}}[/tex]
Step-by-step explanation:
[tex]y \ = \ x^{3} \ - \ \displaystyle\frac{1}{\sqrt{x}} \ + \ \displaystyle\frac{3}{x^{4}} \\ \\ y \ = \ x^{3} \ - \ x^{-\frac{1}{2}} \ + \ 3x^{-4} \\ \\ \displaystyle\frac{dy}{dx} \ = \ 3x^{3 \ - \ 1} \ - \ \left(-\displaystyle\frac{1}{2}\right)x^{-\frac{1}{2} \ - \ 1} \ + \ \left(-4 \ \times \ 3\right)x^{-4-1}[/tex]
[tex]\displaystyle\frac{dy}{dx} \ = \ 3x^{2} \ + \ \displaystyle\frac{1}{2}x^{-\frac{3}{2}} \ - \ 12x^{-5} \\ \\ \displaystyle\frac{dy}{dx} \ = \ 3x^{2} \ + \ \displaystyle\frac{1}{2\sqrt{x^{3}}} \ - \ \displaystyle\frac{12}{x^{5}}[/tex]
The graph of the quadratic function f(x) = - 1/2 x ^ 2 + 3 is shown. Describe the end behavior of the function.
(07.01) A bacteria culture begins with 4 bacteria which double in size every hour. How many bacteria exist in the culture after 8 hours?
Answer: By 8 hours, there will be 65536 bacteria in the culture.
Step-by-step explanation:
The numerical expression used for this problem is [tex]4^{8}[/tex].
You can find the value of this on a calculator. I hope this helps!! :)
If that is not the answer, then try 32 because 4*8=32.
