In a volatile liquid lab, how would the molar mass be affected if the volatile liquid in the flask was not properly evaporated? Would molar mass increase or decrease?

Answer: alteration in the charge of the molecule

The solutes in the new solution are salt and alcohol. The original solution contained only salt as the solute, but when alcohol was added to it, it became a new solution with two solutes.

The concentration of salt in the new solution will still be 2%, but the concentration of alcohol will be much lower since only 5 ml was added to 65 ml of saltwater. It is important to note that alcohol is a volatile substance and can easily evaporate from the solution if left open to the air.

Therefore, the concentration of alcohol in the solution can decrease over time. Overall, the new solution is a mixture of saltwater and alcohol, and it is important to know the concentration of each solute for any specific application or use.

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The structural isomers are isomers that have the same molecular formula but different arrangements of atoms. Among the given options, coordination isomers and geometric isomers are the structural isomers. Coordination isomers have the same composition of atoms but differ in the way the ligands are coordinated around the metal center.

Geometric isomers are also known as cis-trans isomers and differ in the orientation of ligands around a rigid bond, resulting in different physical and chemical properties.

Linkage isomers and optical isomers are not structural isomers. Linkage isomers are coordination compounds in which the ligand is attached to the central metal atom via a different atom, resulting in a different chemical behavior.

Optical isomers are stereoisomers that are non-superimposable mirror images of each other and have different optical activity. Therefore, the answer to the question is option (a) I, III as coordination isomers and geometric isomers are the structural isomers among the given options.

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The most important consideration when cutting a gem that displays pleochroism or other optical phenomena is the orientation of the gem.

This is because these optical phenomena are dependent on the crystal structure and orientation of the gem, so the cutter must carefully examine the stone and determine the best orientation to maximize its beauty and value.

Additionally, an explain and detailed answer would involve the cutter using specialized equipment to analyze the gem's optical properties and determine the optimal orientation for cutting. They may also take into account the durability and reactivity to acids of the stone to ensure it will hold up during the cutting and polishing process. Fluorescence testing may also be conducted to ensure that the stone's color is not negatively affected by exposure to certain light sources. Ultimately, the cutter must take a comprehensive approach to ensure that they are maximizing the gem's beauty and value while also considering its durability and stability.

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The pH of the solution prepared by adding 0.001 mole of NaOCl to one liter of distilled water is 7.60.

the balanced equation for the dissociation of NaOCl in water:

NaOCl + H2O ⇌ Na+ + OH- + HOCl

Since we are neglecting ionic strength effects, we can assume that all the NaOCl dissociates into its ions. Therefore, we have:

[Na+] = 0.001 mol/L
[OH-] = [HOCl]

Now we can use the equilibrium constant expression for the dissociation of HOCl:

Ka = [H+][OCl-]/[HOCl]

Since we know the pKa for HOCl at 25 oC, we can calculate the Ka:

pKa = -log(Ka)
7.60 = -log(Ka)
Ka = 10^-7.60

Substituting the values we have into the equilibrium constant expression, we get:

10^-7.60 = [H+][0.001]/[HOCl]

Solving for [HOCl], we get:

[HOCl] = [H+] / 10^-7.60 / 0.001

Since [HOCl] = [OH-], we can substitute this into the equation:

[OH-] = [H+] / 10^-7.60 / 0.001

Taking the negative logarithm of both sides, we get:

pOH = pKw - pKa + log([Na+]/V)
pOH = 14.00 - 7.60 + log(0.001/1)
pOH = 6.40
pH = 14.00 - 6.40
pH = 7.60

Therefore, the pH of the solution prepared by adding 0.001 mole of NaOCl to one liter of distilled water is 7.60.

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The ph at the equivalence point in the hno₃ titration will be lower than the ph at the equivalence point in the ch₃cooh titration. this statement is true.

The pH at the equivalence point of an acid-base titration depends on the strength of the acid and base being titrated. Nitric acid (HNO₃) is a strong acid and acetic acid (CH₃COOH) is a weak acid. At the equivalence point of a strong acid-strong base titration, the pH is typically neutral (pH 7), while at the equivalence point of a weak acid-strong base titration, the pH is typically basic (pH > 7). Since HNO₃ is a strong acid, the pH at its equivalence point will be lower than that of CH₃COOH.

The pH value is a measurement of the acidity or alkalinity (basicity) of a solution, typically ranging from 0 to 14. The term "pH" stands for "power of hydrogen" and refers to the concentration of hydrogen ions (H+) in the solution.

On the pH scale, 7 is neutral, meaning there is an equal concentration of hydrogen ions and hydroxide ions (OH-) in the solution. Below 7 is acidic, with a higher concentration of hydrogen ions, while above 7 is basic, with a higher concentration of hydroxide ions.

Therefore, the correct option is true.

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The oxidation number of manganese in KMnO4 is +7.

In KMnO4, the compound consists of a potassium ion (K+), a manganese ion (Mn), and four oxygen ions (O2-). The oxidation number of potassium (K) is +1, and the oxidation number of oxygen (O) is -2. To find the oxidation number of manganese (Mn), we can use the following equation:

(K Oxidation Number) + (Mn Oxidation Number) + 4*(O Oxidation Number) = 0

(+1) + (Mn Oxidation Number) + 4*(-2) = 0

Solving for the Mn Oxidation Number, we get:

Mn Oxidation Number = +7

Thus, the sum of the oxidation numbers of all the atoms must equal zero, leading to the oxidation number of manganese being +7.

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To identify the limiting reagent in a chemical reaction, you first need to write the balanced chemical equation for the reaction. The balanced equation shows the mole ratios of the reactants and products involved in the reaction.

Once you have the balanced equation, you can determine the limiting reagent by comparing the number of moles of each reactant available to the mole ratios in the balanced equation.

The reactant that produces the smallest amount of product is the limiting reagent because it limits the amount of product that can be formed.

In a two-step synthesis, there are two reactions involved, and each reaction has its own balanced equation. The limiting reagent for the first reaction becomes the reactant for the second reaction, and the limiting reagent for the second reaction determines the maximum amount of product that can be formed.

For example, consider the two-step synthesis of ammonia (NH3) from nitrogen gas (N2) and hydrogen gas (H2):

Step 1: N2 (g) + 3H2 (g) → 2NH3 (g)

Step 2: NH3 (g) + H2O (l) → NH4+ (aq) + OH- (aq)

The balanced equations for these reactions show that one mole of nitrogen gas reacts with three moles of hydrogen gas to produce two moles of ammonia in the first step, and one mole of ammonia reacts with one mole of water to produce one mole of ammonium ions and one mole of hydroxide ions in the second step.

To determine the limiting reagent in this two-step synthesis, you need to consider the amount of each reactant available for each step.

For example, if you have one mole of nitrogen gas and two moles of hydrogen gas available, the limiting reagent in the first step would be nitrogen gas because it produces only two moles of ammonia, whereas the excess hydrogen gas would produce six moles of ammonia.

In the second step, the limiting reagent would depend on the amount of ammonia produced in the first step.

If two moles of ammonia were produced, then two moles of ammonia would react with two moles of water, and the limiting reagent would be water because it produces only two moles of ammonium ions and two moles of hydroxide ions, whereas the excess ammonia would not react.

In summary, the identification of the limiting reagent in a two-step synthesis depends on the amount of each reactant available for each step, and it determines the maximum amount of product that can be formed.

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The [SO42−] in 0.20 MH₂SO₄can be calculated using the balanced chemical equation for the dissociation of H₂SO₄

the answer is e. 2.5 × 10−1 M.

The [SO42−] in 0.20 M H₂SO₄can be calculated using the balanced chemical equation for the dissociation of H₂SO₄:

H₂SO₄ ⇌ 2H+ + SO42−

From this equation, we know that 1 mole of H₂SO₄ dissociates into 1 mole of SO42−. Therefore, the concentration of SO42− is equal to the concentration of H₂SO₄

[SO42−] = 0.20 M

Therefore, the answer is e. 2.5 × 10−1 M.

This is defined as a written expression of a chemical reaction and contains the reactants and products which are involved.

It also has to be balanced which means that the number of atoms of elements on the reactants side has to be equal to that on the product side.

This is therefore the reason why only coefficients are adjusted to ensure the equation is balanced. Other parts such as the superscripts and subscripts shouldn't be adjusted in this scenario.

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Sofia leaves Harpo because Harpo keeps trying to take Sofia's independence and assertiveness away, Sofia is mad at him.

Sofia eventually makes the decision to move in with her sister and her children. When Sofia leaves, Harpo tries to hide his emotions, but Celie sees him wipe a tear with his baby's cloth diaper.

He transforms the residence into a juke joint after Sofia leaves Harpo. Harpo moves in with another woman he can control, Squeak.

At the end of the book, the two sisters get back together, and Albert and Harpo have learned to play new roles in the family and in their relationships. In Letter 12, Celie fantasizes about wearing a purple dress because she associates the color purple with royalty.

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The total pressure in the 10.0 L vessel that contains 2.34 mol of carbon dioxide, 1.73 mol of sulfur dioxide, and 4.50 mol of argon at standard temperature is 18.5 atm.

To find the total pressure in the vessel, we can use the ideal gas law equation: PV = nRT. At standard temperature and pressure (STP), which is 0°C (273 K) and 1 atm, we can assume that the gas constant (R) is equal to 0.0821 L·atm/(mol·K).

First, we need to calculate the total moles of gas in the vessel:

Total moles = 2.34 mol CO2 + 1.73 mol SO2 + 4.50 mol Ar = 8.57 mol

Next, we can use the ideal gas law equation to find the total pressure:

P(total) * V = n * R * T

P(total) = (n * R * T) / V

P(total) = (8.57 mol * 0.0821 L·atm/(mol·K) * 273 K) / 10.0 L

P(total) = 18.5 atm

Therefore, the total pressure in the 10.0 L vessel that contains 2.34 mol of carbon dioxide, 1.73 mol of sulfur dioxide, and 4.50 mol of argon at standard temperature is 18.5 atm.

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1680 kJ energy is required to decompose 765 g of PCl3, according to 4PCl3(g) → P4(s) + 6Cl2(g) ΔH = 1207 kJ

The molar mass of PCl3 is 137.33 g/mol, so 765 g corresponds to:

n = m/M = 765 g / 137.33 g/mol = 5.572 mol PCl3

According to the balanced equation, 4 moles of PCl3 decompose to release 1207 kJ of energy. Therefore, the amount of energy required to decompose 5.572 mol of PCl3 is:

(5.572 mol PCl3) x (1207 kJ / 4 mol PCl3) = 1682.2 kJ

Rounding to three significant figures, the answer is 1680 kJ (option a).

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In lab organic solvent done add sodium wire and benzophenone to a volume of THF that has been pre-dried over calcium hydride or 4A molecular sieves.

Heat for several hours at reflux or under nitrogen until the solvent turns a deep blue color. This demonstrates the dissolvable is dry, and you can distil off the volume you require.

Last hints of water are eliminated by treating the natural arrangement with a drying specialist. A drying specialist is an inorganic salt which promptly takes up water to become hydrated. A few such salts are utilized regularly in the natural science educating labs: Agent for drying

The solution splits into three phases when an organic solvent and ammonium sulfate are added to a protein solution. Both the upper organic phase and the lower aqueous phase contain proteins that, depending on the concentration of ammonium sulfate, precipitate out and form an intermediate layer.

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The product of oxidizing 1-propanol with the shown structure is propanal.

1-propanol is a primary alcohol with the chemical formula C₃H₈O. When it undergoes oxidation with an oxidizing agent such as chromic acid or chromate, it loses two hydrogen atoms and gains an oxygen atom to form a carbonyl group.

In the case of 1-propanol, the carbonyl group forms at the second carbon atom, resulting in the formation of propanal. The balanced chemical equation for this reaction is:

CH₃CH₂CH₂OH + [O] → CH₃CH₂CHO + H₂O

where [O] represents the oxidizing agent. Therefore, propanal is the product of oxidizing 1-propanol.

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The answer is: "C. re > ra > rd".  This represents the order of rates of reaction for the three steps involved in a typical reaction mechanism.

"re" refers to the rate-determining step, which is the slowest step in the reaction mechanism and therefore limits the overall rate of the reaction. "ra" and "rd" refer to the rates of the other steps in the reaction mechanism.  In general, the rate-determining step will have the slowest rate, followed by the other steps in order of decreasing rate.

Therefore, the general order of importance for the rate constants is re > ra > rd, and the correct answer is C. re > ra > rd.

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The true about the initial numbers of the cobalt-60 and the strontium-90 nuclei in the samples is There will more strontium-90 than the cobalt-60 nuclei. The correct option is A.

In the 28 years of the strontium 90 it posses the 50 % of original atoms. The cobalt 60 will have over the five of the half lives. The percent of the cobalt 60 atoms remains is 128 atoms.

Thus, There will  more the strontium-90 than the cobalt-60 nuclei. The correct option is A.

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This question is incomplete, the complete question is :

The half-life of cobalt-60 is 5.3 years, while that of strontium-90 is 28 years. suppose that samples of cobalt-60 and strontium-90 are such that they initially have the same activity (number of decays per second). what is true about the initial numbers of cobalt-60 and strontium-90 nuclei in these samples?

A. There will be more strontium-90 than cobalt-60 nuclei.

B. There will be equal numbers of cobalt-60 and strontium-90 nuclei.

C. There will be more cobalt-60 than strontium-90 nuclei.

D. It is not possible to compare the number of nuclei without knowing the masses of the samples.

To lubricate glass joints, there are a few options available. One common method is to use a silicone-based lubricant. This type of lubricant is suitable for glass joints as it doesn't damage the material and is resistant to water, heat, and chemicals.

Silicone lubricant can be applied directly to the joint or using a cotton swab or brush. It is important to avoid using petroleum-based lubricants as they can damage the glass and cause it to crack or break.
Another option is to use a thin layer of glycerin or vegetable oil. These substances can be applied to the joint using a cotton swab or brush, and they provide temporary lubrication for glass joints. However, they are not as long-lasting as silicone lubricant and may need to be reapplied more frequently.
In some cases, it may be necessary to disassemble the joint and clean it before lubricating. This can be done by soaking the joint in warm, soapy water and using a soft-bristled brush to remove any dirt or debris. Once cleaned, the joint can be dried and lubricated using one of the methods mentioned above.
Overall, it is important to choose a lubricant that is safe for use with glass and to apply it carefully to avoid damaging the joint or surrounding areas.

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Molar solubility of Ba₃(PO₄)₂ = 8.89 E× 10⁻⁹ M in pure water , Ba₃(PO₄)₂ dissociates in aqueous solution the Ksp = 6.00 × 10⁻³⁹.

Option E is correct.

Molar solubility of Ba₃(PO₄)₂ = 8.89 E × 10⁻⁹ M

Ba₃(PO₄)₂ dissociates in aqueous solution into its constituent ions in part.

           Ba₃(PO₄)₂   ↔ 3 Ba₂⁺    +      2PO₄³⁺

initial                             0.00                0.00

change                           +3 s                 + 2 s

equilibrium                     3 s                     2 s

Solubility product Ksp = Ba₂⁺³[ PO₄³⁻ ]²

                                         = [3s]³                    [2s]²

                                  = 27 × 4 × s⁵

                                  = 108 × 8.89× 10⁻⁹ = 09⁵

                   Ksp = 6.00 × 10⁻³⁹

A substance's molar solubility is expressed as the molecular weight of the solute dissolved in one liter of solution. The salt's concentration in the equation is determined by the solubility value, which indicates how much of the salt dissociates into ions. As a result, we can use the molar ratio of the ions to the salt to determine their concentration.

In any case, the vital contrast between molar solvency and item dissolvability steady is that the molar solvency depicts the disintegration of a substance for every liter of an answer, while the item dissolvability consistent portrays the disintegration of a strong substance in a watery arrangement

Incomplete question :

The molar solubility of Ba 3(PO 4) 2 is 8.89 x 10 -9 M in pure water. Calculate the Ksp for Ba 3(PO 4) 2.

A. 8.16 x 10-31

B. 5.33 x 10-37

C. 4.94 x 10-49

D. 5.55 x 10-41

E. 6.00 x 10-39

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The amount of iron (III) sulfate to produce is 143 grams.

To balance the equation FePO₄ + Na₂SO₄ → Fe₂(SO₄)₃ + Na₃PO₄.

The molar masses of each compound are:

FePO₄: 55.85 + 30.97 + 4(16) = 150.82 g/mol

Na₂SO₄: 2(23.00) + 32.07 + 4(16.00) = 142.04 g/mol

Fe₂(SO₄)₃: 2(55.85) + 3(32.07 + 4(16.00)) = 399.88 g/mol

Na₃PO₄: 3(22.99) + 1(30.97) + 4(16.00) = 163.94 g/mol

To determine the amount of iron (III) sulfate formed, use stoichiometry and the given masses of FePO₄ and Na₂SO₄.

First, find the limiting reagent by comparing the moles of each reactant. Using the molar masses above:

Moles of FePO₄ = 54 g / 150.82 g/mol = 0.358 mol

Moles of Na₂SO₄ = 75 g / 142.04 g/mol = 0.529 mol

FePO₄ is the limiting reagent since it produces fewer moles of product than Na₂SO₄.

The balanced equation shows that 1 mol of FePO₄ produces 1 mol of Fe₂(SO₄)₃, so:

0.358 mol FePO₄ × (1 mol Fe2(SO4)3 / 1 mol FePO₄) = 0.358 mol Fe₂(SO₄)₃

Finally, find the mass of Fe₂(SO₄)₃ produced using its molar mass:

Mass of Fe₂(SO₄)₃ = 0.358 mol × 399.88 g/mol = 143 g

Therefore, 143 grams of iron (III) sulfate can be made.

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Out of the given options, the substance that is not a base is CuCO3, which is copper carbonate. CuCO3 is a compound that is formed from the reaction between copper(II) ions and carbonate ions. It is a blue-green solid that is insoluble in water and has no basic properties.

On the other hand, NaOH (sodium hydroxide) and CuO (copper oxide) are strong bases that dissociate completely in water to produce hydroxide ions (OH-) that can neutralize acids. NaHCO3 (sodium bicarbonate) is a weak base that can act as a buffer and help regulate pH in the body.
NaCl (sodium chloride) is not a base, but rather a salt that is formed from the reaction between an acid (HCl) and a base (NaOH). It is a neutral compound that does not affect the pH of a solution.
In conclusion, CuCO3 is not a base, while NaOH, CuO, and NaHCO3 are all bases of varying strengths.

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The tripeptide sequence beginning with glycine and containing glycine, proline, and lysine is Gly-Gly-Pro-Lys.

Tripeptides are chains of three amino acids linked together by peptide bonds. Glycine, proline, and lysine are three different amino acids, each with a unique three-letter abbreviation. To create the tripeptide sequence, we simply string together the abbreviations for each amino acid in the correct order, separated by hyphens. In this case, the sequence begins with glycine, so we start with "Gly," followed by "Gly" for the second amino acid, "Pro" for the third, and "Lys" for the fourth.

Peptide bonds are the chemical bonds that link amino acids together in a protein or peptide chain. These bonds form between the carboxyl group of one amino acid and the amino group of another, resulting in the release of a molecule of water. The resulting peptide bond is a strong covalent bond that helps to give proteins and peptides their unique three-dimensional structures and functions.

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Alcohol is absorbed into the bloodstream through the stomach lining and it is also rapidly absorbed in the small intestine.

A human or other vertebrate's complete body is circulated by a system of organs called the blood circulatory system, which includes the heart, blood arteries, and blood itself. It contains the cardiovascular system, also known as the vascular system, which is made up of the heart and blood vessels (the words "blood vessels" and "heart" are derived from the Latin word "vascula," respectively). A systemic circulation or circuit and a pulmonary circulation or circuit are the two divisions of the circulatory system. The circulatory system is sometimes referred to as the cardiovascular system or vascular system.

big elastic arteries, big veins, other arteries, smaller arterioles, capillaries that connect to venules (small veins), and other veins make up the network of blood vessels that make up the vast vessels of the heart. In vertebrates, the circulatory system is closed, which implies that the blood never exits the system of blood vessels. Arthropods, for example, have an open circulatory system. Diploblasts without a circulatory system include sponges and comb jellies.

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Answer:

Decrease the temperature in the system

Oil baths are commonly used in laboratories as a method of heating or maintaining the temperature of samples. However, they come with several inconveniences that can be frustrating and time-consuming to deal with. One of the main issues with oil baths is the mess they create.

Since oil is a liquid, it can easily spill or splash onto surfaces, creating a slippery and potentially dangerous environment. Cleaning up spilled oil can be time-consuming and may require special equipment or solvents.

Another inconvenience with oil baths is the need to constantly monitor the temperature to ensure it remains stable. Since oil heats up relatively slowly, it can take longer to reach the desired temperature, and fluctuations in temperature can be common. This can be particularly frustrating when working with sensitive samples that require a precise temperature range.

Additionally, oil baths require regular maintenance to ensure the oil remains clean and free from contamination. If not properly maintained, the oil can become rancid, which can impact the accuracy of experiments and even damage equipment. Overall, while oil baths can be a useful tool in the laboratory, they require careful management and attention to avoid inconveniences and potential hazards.

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Yes, I agree with the student's claim that the reaction is an oxidation-reduction reaction because the oxidation number of carbon changes. Oxidation involves the loss of electrons, while reduction involves the gain of electrons. When the oxidation number of an element changes, it means that there has been a transfer of electrons between that element and another element. Therefore, if the oxidation number of carbon changes during a reaction, it indicates that an oxidation-reduction reaction has occurred.
Oxidation number, also known as oxidation state, is a concept used in chemistry to describe the degree of oxidation (loss of electrons) of an atom in a compound. It is a formalism used to assign a charge to each atom in a molecule or ion.The oxidation number of an atom in a molecule or ion is determined by a set of rules that take into account the electronegativity of the elements involved and the arrangement of the atoms in the molecule or ion.

In general, the oxidation number of an atom is equal to the charge it would have if all the shared electrons in the bond were assigned to the more electronegative atom in the bond. For example, in H2O, the oxygen atom is more electronegative than the hydrogen atoms, so it is assigned an oxidation number of -2, while each hydrogen atom is assigned an oxidation number of +1.The sum of the oxidation numbers of all the atoms in a neutral molecule is equal to zero, while the sum of the oxidation numbers of all the atoms in an ion is equal to the charge of the ion.

Oxidation numbers are useful in predicting the reactivity of elements and in balancing chemical equations. They are also used in various fields of chemistry, including organic chemistry, biochemistry, and electrochemistry.

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The chemist has approximately 56.0 days to perform the experiment.

Radioactive chromium-51 has a half-life of 28.0 days. This means that after 28.0 days, the radioactivity will reduce to 50% of the initial value. To find out how many days it takes for the radioactivity to fall below 25%, we can use the half-life formula:

Remaining radioactivity (%) = Initial radioactivity * (1/2)^(time / half-life)

We need to find the time (in days) when the remaining radioactivity is 25%. So, we can set up the equation:

25% = 100% * (1/2)^(time / 28.0 days)

To solve for time, we first need to divide both sides of the equation by 100%:

0.25 = (1/2)^(time / 28.0 days)

Now, take the logarithm of both sides of the equation and use the logarithm properties to solve for time:

log(0.25) = (time / 28.0 days) * log(1/2)
time / 28.0 days = log(0.25) / log(1/2)
time = 28.0 days * (log(0.25) / log(1/2))
time ≈ 56.0 days

The chemist has approximately 56.0 days to perform the experiment before the radioactivity falls below 25% of the initial measured value.

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An aqueous material is added to the Grignard reaction in order to provide a source of protons (hydrogen ions) which are necessary for the protonation of the Grignard reagent.

Grignard reagents are organometallic compounds containing a carbon-magnesium bond and are used as a powerful synthetic tool for organic synthesis. The Grignard reagent is created by reaction of an alkyl halide such as a bromide or iodide with magnesium metal, usually in the presence of a dry solvent such as ether. This results in the formation of a highly reactive magnesium alkyl compound that can be used to introduce a wide range of functional groups into organic molecules.

The protonation is necessary as it allows the Grignard reagent to react with the desired organic compound to form the desired organic product. Aqueous materials are typically added to the reaction to provide protons because they have a large concentration of hydrogen ions due to the presence of water molecules which are composed of hydrogen and oxygen.

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The molarity of a Ca(OH)2 solution whose pH = 11.00 is 0.005 (E).

Calculation:

pH + pOH = 14

pOH = 3

[OH-] = 10^-3 M

[Ca2+] = [OH-]/2 = 5 x 10^-4 M (since Ca(OH)2 dissociates into one Ca2+ and two OH- ions)

Molarity = moles of solute/volume of solution in liters = 5 x 10^-4 M

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The temperature of Kr gas in kelvin would be 372 K if the volume increases from 66.7 L to 100.0 L while keeping the pressure constant.

According to Charles's Law, when the pressure is constant, the volume of a gas is directly proportional to its temperature in Kelvin. The formula for Charles's Law is V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature. Using this formula, we can find the final temperature of Kr gas.
First, we need to convert the initial temperature of 25 °C to Kelvin by adding 273.15. So, T1 = 25 °C + 273.15 = 298.15 K. Then we can set up the equation as (66.7 L)/(298.15 K) = (100.0 L)/T2 and solve for T2. This gives us T2 = (100.0 L x 298.15 K)/(66.7 L) = 372 K. Therefore, the temperature of Kr gas in Kelvin would be 372 K if the volume increases to 100.0 L while keeping the pressure constant.

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The substances that will exhibit hydrogen bonds is option A which says ethanol.

The hydrogen bonding means hydrogen bonds with the following elements: N, O, and F. (NOF)

In trimethylamine, as we can see, the hydrogens will bond on to all the carbons while the carbons complete their octet with the nitrogen.

In the case of dimethyl ether, you have:

Again. NO hydrogens have bonded onto the oxygen.  thus, this is not the correct option.

In ethanol, there exhibit hydrogen bonding from the hydroxide ion at the end - OH.

Thus, the correct option is A.

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