The measure of the largest angle in wxyz is 4 times the measure of angle w, plus double that measure, plus 3 degrees.
Angle w: x = 4w
Angle y: y = 2x = 8w
Angle z: z = y + 3 = 8w + 3
The largest angle in wxyz is z = 8w + 3.
In a convex quadrilateral wxyz, the degree measure of angle x is four times that of angle w. This means that the measure of angle x is four times the measure of angle w. The measure of angle y is double that of angle x. This means that the measure of angle y is twice the measure of angle x, or eight times the measure of angle w. Lastly, the measure of angle z is 3 degrees larger than that of angle y. This means that the measure of angle z is eight times the measure of angle w plus three degrees. Therefore, the measure of the largest angle in wxyz is 8w + 3.
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A car travels the 200 miles along the M1 from London to Leeds. The car leaves London at 8am and travels at a constant speed of 60mph for the first 60 miles. The driver takes a break of 30mins at a motorway services before continuing the journey at a constant speed of 70mph a) Draw a distance-time graph of the journey
Answer:
I can provide you with a description of the graph.
The graph would have the distance on the y-axis and the time on the x-axis.
The first 60 miles of the journey would be represented by a straight line with a slope of 60/1=60, since the car is traveling at a constant speed of 60 mph.
The point where the first 60 miles ends would be (1,60) which is the time of one hour from London, the distance of 60 miles from London.
After the 30-minute break at the motorway services, the car would continue its journey at a constant speed of 70 mph. This part of the journey would be represented by a straight line with a slope of 70/1=70.
The point where the whole journey ends would be (4,200) which is the time of 4 hours from London, the distance of 200 miles from London.
Please note that it is assumed that the car doesn't stop during the second part of the journey.
Which of the following values are solutions to the inequality -9> -4+5x?
The only value that is a solution of the inequality -9> -4+5x is the first one, x = -5.
Which of the following vales are solutions to the inequality?Here we have the inequality:
-9> -4+5x
And we want to see which of the given values is a solution for that inequality.
The first option is x = -5
Replacing that value we will get:
-9 > -4 + 5*-5
-9 > - 4 - 25
-9 > -29
This is true.
The second option is x = 2
-9> -4+5*2
-9 > -4 + 10
-9 > 6
This is false.
The last option is x = -1
-9 > -4 + 5*-1
-9 > -9
This is false.
Then the only solution is the first one, x = -5.
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Which of the following is equivalent to
4x^2 6x/ 2x+2?
a. 2X - 10/2X+2
b. 2X - 5 + 10/2X+2
c. 2x-3
d. 2X + 5 - 10/2X +2
An equation Dividing 4x^2+6x by 4x+2 gives : Therefore , the expression ... 4x + 2, as follows: 4x^2 + 2x + 4x + 2 − 2, or x(4x + 2) + (4x + 2) − 2.
What is equation?An equation is a mathematical formula that connects two assertions using the equal sign (=) to denote equivalence. In algebra, an equation is a mathematical statement that establishes the equivalence of two mathematical expressions. For instance, an equal sign separates the components 3x + 5 and 14 in the equation 3x + 5 = 14. A mathematical formula is used to explain the connection between two sentences on either side of a letter. Frequently, there is just one variable, which is also the symbol. for example, 2x - 4 = 2.
here,
the given equation is
this above equation is equivalent to
2X - 10/2X+2,
as root of both equation are same
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the elisa test is known to have probability 0.05 of producing a false positive result and probability 0.10 of producing a false negative result for a single chicken. a. if no chicken in the flock is infected with the h6n2 virus, what is the probability that the veterinarian will conclude that the h6n2 virus is not present in the flock? show how you found your answer. b. if no chicken in the flock is infected with the h6n2 virus, what is the probability that the veterinarian will conclude that the h6n2 virus is present in the flock? show how you found your answer. c. if every chicken in the flock is infected with the h6n2 virus, what is the probability that the veterinarian will conclude that the h6n2 virus is present in the flock? show how you found your answer. d. if 20 percent of the chickens in the flock are infected with the h6n2 virus and the other 80 percent are not infected, what is the probability that the veterinarian will conclude that the h6n2 virus is present
If no chicken in the flock is infected with the h6n2 virus, the probability that the veterinarian will conclude that the h6n2 virus is not present in the flock
[tex]\left[\begin{array}{ccc}10\\2\\\end{array}\right] * O.O5^2 *0.95^8[/tex]
= 0.98849
Using the answer probability of veterinarian will incorrectly conclude that
h6n2 virus present in the flock
1- 0.98849 =0.1150
veterinarian will incorrectly conclude that h6n2 virus present in the flock least three chicken shows positive result
∑[tex]\left[\begin{array}{ccc}10\\k\\\end{array}\right] 0.90^{k} * 0.10^(10-k)[/tex]
= 1-[tex]\left[\begin{array}{ccc}10\\0\\\end{array}\right] * O.90^0 *0.10^10 +\left[\begin{array}{ccc}10\\1\\\end{array}\right] * O.90^1 *0.10^9 + \left[\begin{array}{ccc}10\\2\\\end{array}\right] * O.90^2 *0.10^8[/tex]
=0.9999996
the probability of randomly selected chicken shows positive result is
P(true positive)*P(infected chicken) +P(false positive)*P(non infected chicken)
= 0.90*0.20 + 0.05*0.80
= 0.22
probability of three chicken shows positive result
[tex]\left[\begin{array}{ccc}10\\0\\\end{array}\right] * O.22^0 *078^10 +\left[\begin{array}{ccc}10\\1\\\end{array}\right] * O.22^1 *0.78^9 + \left[\begin{array}{ccc}10\\2\\\end{array}\right] * O.22^2 *0.78^8[/tex]
=0.38311
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students were surveyed on the number of siblings they have. the following probability model was created from the results. a 2-column table with 5 rows. column 1 is labeled number of siblings with entries 0, 1, 2, 3, 4 or more. column 2 is labeled probability with entries 0.223, 0.532, 0.121, 0.085, 0.039. what is the probability that a randomly selected student does not have 0 siblings? enter your answer as a decimal rounded to the thousandths place. p(not 0 siblings)
The likelihood that a student chosen at random has any siblings is 0.777. This is determined by deducting from 1 the probability of having no siblings (0.223).
1. Get the probability of 0 siblings : 0.223
2. Subtract the probability of 0 siblings from 1 :
1 - 0.223
= 0.777
3. Round the result to 3 decimal places :
0.777
The probability of a student not having 0 siblings can be calculated by subtracting the probability of having 0 siblings from 1. The probability model created from the survey results is a 2-column table with 5 rows. Column 1 is labeled number of siblings with entries 0, 1, 2, 3, 4 or more. Column 2 is labeled probability with entries
0.223, 0.532, 0.121, 0.085, 0.039.
The probability of having 0 siblings is 0.223. To calculate the probability of not having 0 siblings, we subtract 0.223 from 1. This gives us 0.777, which is the probability of not having 0 siblings. This result should be rounded to 3 decimal places, giving us 0.777 as the final answer.
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my three-digit code is . reckha can't choose a code that is the same as mine in two or more of the three digit-positions, nor that is the same as mine except for switching the positions of two digits (so and , for example, are forbidden, but is fine). reckha can otherwise choose any three-digit code where each digit is in the set . how many codes are available for reckha?
9,900 codes that are available for reckha.
There are a total of 10,000 possible three-digit codes when each digit is in the set {0,1,2,3,4,5,6,7,8,9}. Since each digit can take 10 different values, we can use the formula 10^3 = 1000 to calculate the total number of codes.
However, since reckha cannot choose a code that is the same as yours or one that is the same as yours except for switching the positions of two digits, we have to subtract these possibilities from the total. We can calculate the number of codes forbidden by subtracting the number of codes with the same digits in all three positions (10) and the number of codes with the same digits but different positions (90) from the total. This leaves us with 10,000 - (10 + 90) = 9,900 codes that are available for reckha.
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Given that a is an odd multiple of 1183, find the greatest common divisor of 2a^2+29a+65 and a+13
The solution is 26, since gcd (26, a + 13) = 26 when a = 1183k, and k = 1,3,5,7,9...
Let d = [tex](2a^{2} +29a + 65, a+ 13)[/tex]
Now, we can split [tex]2a^{2} + 29a + 65[/tex] in the following way, so that it becomes easier to factorise.
[tex]2a^{2} + 29a + 65 = (2a^{2} + 29a + 39) + 26[/tex]
From this, we can quantify and notice that -13 is one root of this equation, while the other root is -3/2.
Therefore, [tex]2a^{2} + 29a + 39 = (a+13)(2a+3)+26[/tex]
Thus, [tex]d = ((a+13)(2a+3)+26, a+ 13)[/tex]
The greatest common divisor (GCD) of two or more numbers is the greatest common factor number that divides them, exactly. It is also called the highest common factor (HCF).
Now, we can use Euclid's Algorithm.
[tex]= gcd (2a^{2} + 29a + 65, a + 13)\\= gcd (2a^{2} + 29a + 65 - 2a(a+13), a+13)\\= gcd (3a + 65, a + 13)\\= gcd (3a + 65 - 3a(a+13), a+13)\\= gcd (26, a + 13)[/tex]
This is necessarily 1, 2, 13, or 26, which we can see by just looking at the first term. By factoring 1183 and considering that [tex]a[/tex] is an odd multiple, then we should be able to conclude the answer.
Hence, the conclusion is that the solution is 26, since gcd (26, a + 13) = 26 when a = 1183k, and k = 1,3,5,7,9...
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Explain how to solve 5x − 2 = 8 using the change of base formula . include the solution for x in your answer.
The solution to the given exponential equation is 0.791.
What is a logarithm?
The logarithm is the inverse function of exponentiation in mathematics. That is, the exponent to which b must be raised to produce x is the logarithm of a number x to the base b.
Given exponential function is
5x⁻² = 8
Divide both sides by 5:
x⁻² = 8/5
x⁻² = 1.6
Taking logarithm of base x:
[tex]log_x(x^{-2})=log_x1.6[/tex]
-2 [tex]=log_x(1.6)[/tex]
Now applying the logarithm of change of base formula:
-2 = log 1.6/log x
Divide both sides by -2:
1 = log 1.6/( -2log x)
Multiply both sides by log x:
log x = log 1.6/-2
log x = -0.1021
Now applying the formula [tex]log_xa = b[/tex] implies [tex]a = x^b[/tex]:
x = 10^(-0.1021)
x = 0.7905
x = 0.791
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Check all that are equivalent to 256. 28 44 162 1282
2^8, 4^4 and 16^2 are equivalent to 256. We can find this out by using the concept of Factors.
Factors are numbers or algebraic expressions that divide another number of expression without leaving a remainder.
In the question, the number given is 256.
Options are: 2^8, 4^4, 16^2, and 128^2
We will break down all the numbers into the product of their factors and using multiplication, we will verify if they are equivalent to 256 or not.
2^8 = 2*2*2*2*2*2*2*2 = 256
4^4= 4*4*4*4 = 256
16^2= 16*16 = 256
128^2 = 128*128 = 16384
As we can observe, only 128^2 is not equivalent to 256.
Therefore, 2^8, 4^4 and 16^2 are equivalent to 256.
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Please help !!
Given: C is the midpoint of NB; C is the midpoint of MA
Prove: ABC is congruent to NMC
STATEMENTS
Check the picture below.
In a mid-size company, the distribution of the number of phone calls answered each day by each of the 12
receptionists is bell-shaped and has a mean of 64 and a standard deviation of 9. Using the Empirical Rule (as
presented in the book), what is the approximate percentage of daily phone calls numbering between 46 and
822
Do not enter the percent symbol.
ans =
%
The approximate percentage of daily phone calls numbering between 46 and 82 is 95%.
The Empirical Rule states that for a normal distribution, approximately 68% of the data falls within one standard deviation of the mean, approximately 95% falls within two standard deviations, and approximately 99.7% falls within three standard deviations.
In this case, the mean is 64 and the standard deviation is 9. Therefore, approximately 68% of the daily phone calls answered by each receptionist fall between 64 - 9 = 55 and 64 + 9 = 73.
Additionally, approximately 95% of the data falls between 64-18 = 46 and 64 + 18 = 82.
So, the approximate percentage of daily phone calls numbering between 46 and 82 is 95%.
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A researcher creates a scatter plot that displays the relationship between the number of years in business, x, and the percentage of company business that is fair trade, y. the researcher creates a line of best fit, y=0.091x+0.060, and wants to find the residuals for the companies that have been in business for 3 years.
find the residuals for the two points representing companies that have been in business for 3 years, (3, 0.42) and (3, 0.3).
what is the residual for the company with the point (3, 0.42)?
The residuals for the two points representing companies that have been in business for 3 years, (3, 0.42) and (3, 0.3) are 0.087 and -0.033 respectively.
What is a residual value?We gather data and attempt to fit a line that can most closely resemble how the data is distributed across the coordinate plane. Recall that on a 2D cartesian plane, we have the points (x,y), where x is the abscissa and y is the ordinate.Assuming we are working with 2D data, let's write the best-fit line as y = mx + c, where m is the slope and c is the y-intercept.Now, a prediction is made about where the next data point may be using this line. We obtain the error that the best-fit line produced while predicting the actual data when it is used to predict a data point that already exists."Residual value" is used to gauge this.We assume that the prediction for a data point with ordinate b is y. The residual value is then y - b.Recall that the ordinate of the prediction is ahead of that of the actual data point.Given:
The line of best fit is y = 0.091x+0.060.
The two points representing companies that have been in business for 3 years are (3, 0.42) and (3, 0.3).
The predicted value for the point (3, 0.42) can be calculated as:
= (0.091 × 3) + 0.060
= 0.0273 + 0.060
= 0.333
So, the residual will be:
= 0.42 - 0.333 = 0.087
The predicted value for the point (3, 0.3) is calculated as:
y = 0.091x + 0.060.
= (0.091 × 3) + 0.060.
= 0.333
So, the residual will be:
= 0.3 - 0.333 = -0.033
Hence, the residual for the two points will be 0.087 and -0.333 respectively.
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Write an equation in point-slope form of the line that passes through the point (-9, 1) and has a slope of
2/3
Answer:
y-1=2/3(x+9)
Step-by-step explanation:
Sorry cant really explain well but I am positive this is the right answer.
In a circle with radius 8.5, an angle intercepts an arc of length 38.9. Find the angle in
radians to the nearest 10th.
Answer:
The angle in radians is 4.6.
Note that it is expressed in radians, to convert it to degrees you need to multiply it by 180/π, but it is already rounded to the nearest 10th.
Step-by-step explanation:
To find the angle in radians to the nearest 10th, you need to use the relationship between the length of an arc, the radius of the circle, and the angle of the arc:
arc length = (angle in radians) * (radius)
In this case, the radius of the circle is 8.5 and the arc length is 38.9, so you can substitute these values into the equation:
38.9 = (angle in radians) * (8.5)
To solve for the angle in radians, you need to divide both sides of the equation by the radius:
angle in radians = 38.9 / 8.5
The angle in radians is 4.6.
Note that it is expressed in radians, to convert it to degrees you need to multiply it by 180/π, but it is already rounded to the nearest 10th.
A large school district held a district-wide track meet for all high school students.
for the 2-mile run, the population of female students participating had a mean running time of 8.8 minutes with standard deviation of 3.3 minutes, and the population of male students participating had a mean running time 7.3 minutes with standard deviation of 2.9 minutes.
suppose 8 female students and 8 male students who participated in the 2-mile run are selected at random from each population.
let x-barm represent the sample mean running time for the male students, and let x- barf represent the sample mean running time for the female students. what are the mean and standard deviation of the sampling distribution of the difference in sample means x-barm-x-barf?
a. 0.4 & 4.042.
b. 1.5 & 1.553.
c. 0 -1.5 & 2.413.
d. 1.5 & 2.413.
e. -1.5 & 1.553.
The mean and standard deviation of the sampling distribution of the difference in sample means for 8 female and 8 male students who participated in the 2-mile run is -1.5 minutes and 2.413 minutes, respectively.
The mean of the sampling distribution of the difference in sample means is calculated by subtracting the mean of the female students from the mean of the male students, which is 7.3 - 8.8 = -1.5 minutes.
The standard deviation of the sampling distribution of the difference in sample means is calculated by taking the square root of the sum of the squares of the standard deviations of the two populations, which is sqrt(3.3^2 + 2.9^2) = 2.413 minutes.
Therefore, the mean and standard deviation of the sampling distribution of the difference in sample means is -1.5 minutes and 2.413 minutes, respectively.
The mean and standard deviation of the sampling distribution of the difference in sample means for 8 female and 8 male students who participated in the 2-mile run is -1.5 minutes and 2.413 minutes, respectively.
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Suppose you know that the amount of time it takes your friend Susan to get from her residence to class averages 50 minutes, with a standard deviation of 5 minutes. What proportion of Susan's trips to class would take less than 40 minutes? What proportion of Susan's trips to class would take more than 50 minutes or less than 40 minutes?
Answer:
To solve this problem, we will use the following steps:
Step 1: We know that the amount of time it takes Susan to get from her residence to class averages 50 minutes, with a standard deviation of 5 minutes. So we can use this information to calculate the proportion of Susan's trips to class that would take less than 40 minutes.
Step 2: To calculate the proportion of Susan's trips to class that would take less than 40 minutes, we need to find the z-score for the value of 40 minutes. We can use the following formula to find the z-score:
z = (x - μ) / σ
Where x is the value we are interested in (40 minutes), μ is the mean (50 minutes), and σ is the standard deviation (5 minutes).
z = (40 - 50) / 5 = -2
Step 3: We can use a standard normal table or a calculator to find the proportion of Susan's trips to class that would take less than 40 minutes.
The proportion of Susan's trips to class that would take less than 40 minutes is 0.0228 or 2.28%.
Step 4: To calculate the proportion of Susan's trips to class that would take more than 50 minutes or less than 40 minutes, we need to find the proportion of Susan's trips to class that would take more than 50 minutes and add it to the proportion of Susan's trips to class that would take less than 40 minutes.
Step 5: To find the proportion of Susan's trips to class that would take more than 50 minutes, we need to find the z-score for the value of 50 minutes.
z = (50 - 50) / 5 = 0
Using a standard normal table or a calculator, the proportion of Susan's trips to class that would take more than 50 minutes is 0.5 or 50%.
Step 6: Finally, we can add the proportion of Susan's trips to class that would take more than 50 minutes and the proportion of Susan's trips to class that would take less than 40 minutes to find the proportion of Susan's trips to class that would take more than 50 minutes or less than 40 minutes.
0.50 + 0.0228 = 0.5228 or 52.28%
Final Answer: The proportion of Susan's trips to class that would take more than 50 minutes or less than 40 minutes is 0.5228 or 52.28%.
How many protons does tin-112 have? responses 12 12, 50 50, 62 62, 112
Answer:
50
Step-by-step explanation:
One week, Manuel worked his regular 40 hours and overtime 5.75 hours. If his regular hourly rate is $15.00 per hour, what is his gross pay for the week if he earns time and a half for overtime?
Answer:
Manuel worked 40 hours * $15.00/hour = $<<40*15=600>>600 for his regular hours.
For his overtime hours, he worked 5.75 hours * $15.00/hour = $86.25
For overtime, he is paid time and a half, which is $15.00/hour * 1.5 = $22.50/hour.
So he was paid 5.75 hours * $22.50/hour = $128.44 for his overtime hours
Therefore, his gross pay for the week is $600 + $128.44 = $728.44
I don’t know how to do this, explanation too please
Find angle x
Answer:
Step-by-step explanation:
You need to know trigonometry for this.\
You can't solve this without a scientific calculator.
TOA means Tan x = Opposite/Adjacent or in this case, 5.1/4.2
tan x = 5.1/4.2
arctant(tanx) = arctan(5.1/4.2)
x = arctan(5.1/4.2)
≈ 50.5°
arctan x is also known as tan inverse x
malia bought a block of wax to make candles. she used 3.5 pounds of the wax to make vanilla-scented candles and has less than 5 pounds of wax left to make orange-scented candles. let x represent the weight of the block of wax originally. which inequality describes the problem?
The required inequality describes for the given problem is x < 8.5.
What is inequality?The idea of inequality, which is the state of not being equal, especially in terms of status, rights, and opportunities, is at the core of social justice theories. However, because it frequently has diverse meanings to different people, it is prone to misunderstanding in public discourse.
According o question:she used 3.5 pounds of the wax to make vanilla-scented candles and has less than 5 pounds of wax left to make orange-scented candles.
let x represent the weight of the block of wax originally
then,inequality can be written as,
x - 3.5 < 5
x < 8.5
Thus, required inequality is x < 8.5.
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a fisheries biologist is stocking fish in a lake. She knows that when there are n fish per unit of water, the average weight of each fish will be W(n) = 500 -2n, measured in ounces. What is the value of n that will maximize the total fish weight per unit of water? What is that weight?
If a fisheries biologist is stocking fish in a lake. She knows that when there are n fish per unit of water. The value of n that will maximize the total fish weight per unit of water is 125 fish . The weight is 31,250g.
How to find the value of n that will maximize the total fish weight per unit of water?a. Value of n that will maximize the total fish weight per unit of water?
W(n) = 500 -2n
W=n(500 -2n)
W = 500n -2n
0=500 -4n
n =500/4
n = 125 fish
b. Weight
Weight = Number of fish/ Average weight of fish
Weight = 125 × (500/2)
Weight = 125 × 250
Weight = 31,250g
Therefore the value of n that will maximize the total fish weight per unit of water is 125 fish . The weight is 31,250.
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a point $(3\sqrt{5},d 3)$ is $3d$ units away from the origin. what is the smallest possible value of $d$?
If the point (3√5,d+3) is 3d Units away from the origin , then the smallest possible value of d is 3 .
The point (3√5,d+3) is 3d Units away from the origin , that means ,
the distance between the points (0,0) and (3√5,d+3) is 3d units ;
By using the distance formula , the given situation can be represented as
⇒ [tex](3d)^{2} =(3\sqrt{5} -0)^{2} + (d+3)^{2}[/tex] ;
On simplifying the equation ,
we get ;
⇒ [tex]9d^{2} = 45+d^{2} +6d+9[/tex] ;
⇒ [tex]4d^{2} -3d--27 = 0[/tex] ;
Writing in factor form ,
we get ;
⇒ [tex](4d+9)(d-3)= 0[/tex] ;
On solving we have [tex]d=-\frac{9}{4}[/tex] and [tex]d=3[/tex] .
Since the distance is only positive , So we can write d = 3 ;
Therefore , the smallest possible value of d is 3 .
The given question is incomplete , the complete question is
A point (3√5,d+3) is 3d Units away from the origin. What is the smallest possible value of d ?
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In which month was the peak, the largest deposit, made? January June July August
The peak, the largest deposit, made in July
It's the tallest one in the plot.
Let's arrange the number from smallest to greatest:
50<80=80<95<100<110<250<300<320
Jan<Feb=Sep<May<Apr<Mar<June<Aug<July
So, the greatest amount of deposit was in July.
These trades took place between June and August 2020. June 1 After giving it some deliberation, Natalie decides to offer Curtis a mixer for $1,150 (mixer cost: $620) on credit with terms of n/30. 30 Curtis gives Natalie a call. He signs a one-month, 8.35% note payable since he won't be able to pay the sum due for another month. Curtis calls on July 31.
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the perimeter of an isosceles triangle (2 equal sides) pqr is 9 cm. the length of side p is 4 cm and the lengths of q and r are equal
The lengths of q and r are 2.5 , 2.5 respectively if the perimeter of an isosceles triangle pqr is 9 cm.
What is a triangle ?
triangle can be defined in which it consists of three sides , three angles and the sum of three angles is always 180 degrees.
Given ,
The perimeter of an isosceles triangle (2 equal sides) pqr is 9 cm.
the length of side p is 4 cm
Let the lengths of q and r are x and y respectively.
The perimeter of an isosceles triangle = (p+2q)
So,
p+2q = 9
4+2q = 9
2q = 9-4
2q = 5
q = 5/2
q = 2.5 cm
Hence , the lengths of q and r are 2.5 , 2.5 cm respectively .
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Does the point (-3,2) lie inside, outside, or an a circle with center (4,0) and radius 5 units?
Answer:
The given point is outside of the circle---------------------------------------
Find the distance between the given point (-3, 2) and the center of circle (4, 0) using distance formula:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex][tex]d=\sqrt{(4-(-3))^2+(0-2)^2} =\sqrt{7^2+(-2)^2} =\sqrt{49+4} > 7 > r=5[/tex]As we see the distance is greater than radius, hence it is outside circle.
Directions: Use the Law of Sines to find each missing side or angle. Round to the nearest tenth.
Answer: 7.4
Step-by-step explanation:
[tex]\frac{x}{\sin 46^{\circ}}=\frac{5}{\sin 29^{\circ}}\\\\x=\frac{5\sin 46^{\circ}}{\sin 29^{\circ}}\\\\x \approx 7.4[/tex]
Write the time 11 hours after 5:00 PM
Answer:
4am, it's 4 am.
Work backward to find the value of the varible in the eqautoin belw. Show your work. d+7x2=20
How to put this in vertex form?
The vertex form of equation is discussed below,
What is Vertex form?The vertex form of a quadratic function is f(x) = a(x – h)² + k, where a, h, and k are constants. of the parabola is at (h, k).
As, A parabola has a lowest point if it opens upward.
Additionally, a parabola has a highest point if it opens downward.
The vertex of the parabola is located at this lowest or highest point.
Now, the parent function f(x) = x² has its vertex at the origin.
Also, The vertex form of a quadratic function is
f(x) = a(x – h)² + k, where a, h, and k are constants.
For example, The parent function f(x) = x² is vertically stretched by a
factor of 4/3 and then translated 2 units left and 5 units down.
So, the vertex form : g(x) = 4/3 (x+2)² - 5.
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Use implicit differentiation to find
∂z/∂x and ∂z/∂y.
e^9z = xyz
e6z = xyz, implicit differentiation of the following equation-
What are equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
We have LHS = RHS (left hand side = right hand side) in every mathematical equation.
We have LHS = RHS (left hand side = right hand side) in every mathematical equation. To determine the value
To determine the value A statement is not an equation if it has no "equal to" sign.
A mathematical statement that has a "equal to" symbol between two expressions with equal values is called an equation.
According to our question-
Given e6z = xyz
To find ∂z/∂x → consider z as a function of x and take y to be a constant
So differentiating with respect to x, we get
e6z × 6 × ∂z/∂x = z × y + xy × 1 × ∂z/∂x
[using the chain rule on the LHS and the product rule on the RHS]
Factor out the ∂z/∂x:
∂z/∂x [6e6z - xy] = yz
∂z/∂x = yz / [6e6z - xy]
Do the same thing to find ∂z/∂y except consider z to be a function of y and take x to be a constant
Differentiating with respect to y:
e6z × 6 × ∂z/∂y = z × x + xy × 1 × ∂z/∂y
∂z/∂y [6e6z - xy] = xz
∂z/∂y = xz / [6e6z - xy]
Therefore, ∂z/∂x = yz / [6e6z - xy] and ∂z/∂y = xz / [6e6z - xy]
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