in the absence of clothing between the barrel of a gun and the person being shot, about how far away does the shooter have to be in order to leave no soot or stippling around the gun shot hole?

The magnitude of the force at this distance of 2.0 m is 25.6 N.

The force between two charges q1 and q2 separated by a distance r is given by Coulomb's law:

F = k (q1 q2)/r^2

where k is the electrostatic constant (9 x 10^9 Nm^2/C^2).

In this problem, the distance is 1.0 m and the magnitude of the force is 104 N, so we can solve for the charge on each particle:

104 N = (9 x 10^9 Nm^2/C^2) (q1 q2) / 1.0 m^2

q1 q2 = 104 N / (9 x 10^9 Nm^2/C^2)

q1 q2 = 1.2 x 10^-7 C^2

Since the magnitudes of the charges are equal, q1 = q2 = q, so we can solve for q:

q^2 = 1.2 x 10^-7 C^2

q = 3.4 x 10^-4 C

Now that we know the charge on each particle, we can calculate the force when the separation is doubled to 2.0 m:

F = (9 x 10^9 Nm^2/C^2) (q1 q2) / (2.0 m)^2

F = (9 x 10^9 Nm^2/C^2) (3.4 x 10^-4 C)^2 / (2.0 m)^2

F = 25.6 N

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Moons that display few craters presumably. They all pass straight over the equator of the globe. Uranus's five biggest moons. have the closest magnetic field axis.

There are many fascinating moons around the globe, but the Galilean satellites—Io, Europa, Ganymede, and Callisto—the first four moons identified beyond Earth—hold the most scientific curiosity.

Moon and Earth

The basic explanation is that Earth only has one moon, that we name “the moon”. It is the biggest and brightest object in the night sky, and the only solar system body except Earth that humanity have visited in our space travel activities.

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The speed at the bottom of the incline is  6.87 m per second.

The conservation of the energy is a fundamentally law of physics, chemistry stating that the total of the energy of an isolated by the system is constant despite internally changes. It is mostly common expressed as “energy can neither to be created nor destroyed”, and it is the basis of the first-ever law of the thermodynamics.

As per the given question

The length of the inclined plane L= 8.00m

angle of inclination is = 37°

Height of the inclined plane h= L sin ø

     (8.00m) sin 37°

     =4.814 m

Let's take m= mass of hoop

Let's take r=radius of hoop

Let's v be the velocity of the hoop bottom to the inclined plane.

Now we can apply conservation of energy at the top of the inclined plane  and at to the bottom of the inclined plane.

mgh = ¹/₂ mv²

mgh = ¹/₂ mv² + ¹/₂ Iω²

Where, I = moment of inertia

ω = angular velocity

I = L/ω

mgh = ¹/₂ mv² + ¹/₂ (L/ω)ω²

mgh = ¹/₂ mv² + ¹/₂ Lω

mgh = ¹/₂ mv² + ¹/₂ mvrω

ω = vr

mgh = ¹/₂ mv² + ¹/₂ mvrvr

gh = ¹/₂ v² + ¹/₂ (vr)²

gh = ¹/₂v² (1 + r²)

v=gh

v=√(9.8m/s^2)(4.814m)

v=6.87 m/s

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A. In the ideal Amp, V⁺ = V⁻

B. [tex]V_{out} = -2v[/tex]

C. [tex]P_{8K} = 4.5 m watts[/tex]

Solution:

[tex]V_{out} = 3-5 = -2v = V_{out} = -2v\\\\I_{y} = \frac{V_{out} }{500} = \frac{-2}{500} = I_{y} = -4ma[/tex]

Power delivered by 6v = P6v = (6)(1) (6)(m) -6mworth = = 6 V Vgk = (8k) (a) = (8k) (0,75 mA)

Power dissipated in the 8k = P₁₁ = (6v) (ia) = (6) (0.75 m) = 4.5 mwatts.

A schematic is a graphical representation of an electrical circuit. Schematics uses simple images of components, and schematics use standardized symbolic representations to show circuit components and connections. A schematic is a simplified representation of the components of an electrical circuit using either pictures of individual parts or standard symbols.

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The electric field at x = 1.0 m is 12.18.

The electric field at x = 2.0 m is 0.135.

The electric potential at a point is a scalar quantity that is used to describe the electric potential energy per unit charge at that point. In the equation you provided, V is the electric potential at a point along the x-axis and x is the position along the x-axis. To find the electric field, which is denoted by Ex, you can use the equation Ex = -dV/dx, where dV is the change in electric potential and dx is the change in position along the x-axis.

To find the electric field at x = 1.0 m, you can plug in these values into the equation to get Ex = -dV/dx = -(-100e^(-2x))/dx = 50e^(-2x) = 50e^(-2*1.0) = 50e^(-2) = 12.18.

To find the electric field at x = 2.0 m, you can plug in these values into the equation to get Ex = -dV/dx = -(-100e^(-2x))/dx = 50e^(-2x) = 50e^(-2*2.0) = 50e^(-4) = 0.135.

In both cases, the electric field is positive, indicating that the electric field is directed away from the origin.

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Electric forces include all of the above, while gravitational forces do not.

Electric forces involve the interaction of electrically charged particles, and the strength of the force depends on the distance between the charges and the strength of the charges. The force decreases inversely with the square of the distance between the charges. The range of electric forces is theoretically infinite, meaning that the force can extend across any distance.

In contrast, gravitational forces involve the interaction of two masses and the strength of the force depends on the mass of the two objects and the distance between them. The force also decreases inversely with the square of the distance between the two masses, but the range of gravitational forces is limited to the universe.

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The possible wavelengths that appear In the emission spectrum of the system are [tex]$210 \mathrm{~nm}, 250 \mathrm{~nm}, 410 \mathrm{~nm}, 620 \mathrm{~nm}, 1200 \mathrm{~nm}$[/tex].

Given:

The quantum energy levels allowed In the system are:

[tex]$$\begin{aligned}& E_1=1.0 \mathrm{eV} \\& E_2=2.0 \mathrm{eV} \\& E_3=4.0 \mathrm{eV} \\& E_4=7.0 \mathrm{eV}\end{aligned}$$[/tex]

What is wavelength of the emission?

As the transition of electron takes from one energy level to another, there is an emission of particular wavelength from the transition. The relation between the wavelength of the emission and the energy of the energy level Is expressed as:

[tex]$$E_f-E_i=\frac{h c}{\lambda}$$[/tex]

Here, [tex]$E_f$[/tex] is the final energy level, [tex]$E_i$[/tex] is the Initlal energy level and [tex]$\lambda$[/tex] is the wavelength of emlsslon.

(1). Transition of electron from [tex]$E_1$[/tex] to [tex]$E_2$[/tex] energy level:

[tex]$$\begin{aligned}E_2-E_1 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(2-1)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =1.244 \times 10^{-6} \mathrm{~m} \\& \approx 1200 \mathrm{~nm}\end{aligned}$$[/tex]

(2). Transition of electron from [tex]$E_1$[/tex] to [tex]$E_3$[/tex] energy level:

[tex]$$\begin{aligned}E_3-E_1 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(4-1)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.414 \times 10^{-6} \mathrm{~m} \\& \approx 410 \mathrm{~nm}\end{aligned}$$[/tex]

(3). Transition of electron from [tex]$E_1$[/tex] to [tex]$E_4$[/tex] energy level:

[tex]$$\begin{aligned}E_4-E_1 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-31}\right) \times\left(3 \times 10^8\right)}{(7-1)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.207 \times 10^{-6} \mathrm{~m} \\& \approx 210 \mathrm{~nm}\end{aligned}$$[/tex]

(4). Transition of electron from [tex]$E_2$[/tex] to [tex]$E_3$[/tex] energy level:

[tex]$$\begin{aligned}E_3-E_2 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(4-2)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.621 \times 10^{-6} \mathrm{~m} \\& \approx 620 \mathrm{~nm}\end{aligned}$$[/tex]

(5). Transition of electron from[tex]$E_2$[/tex] to [tex]$E_4$[/tex] energy level:

[tex]$$\begin{aligned}E_1-E_2 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(7-2)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.248 \times 10^{-6} \mathrm{~m} \\& \approx 250 \mathrm{~nm}\end{aligned}$$[/tex]

(6). Transition of electron from [tex]$E_3$[/tex] to [tex]$E_4$[/tex] energy level:

[tex]$$\begin{aligned}E_4-E_3 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(7-4)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.414 \times 10^{-6} \mathrm{~m} \\& \approx 410 \mathrm{~nm}\end{aligned}$$[/tex]

Thus, The posslble wavelengths that appear in the emisslon spectrum of the system are[tex]$210 \mathrm{~nm}, 250 \mathrm{~nm}, 410 \mathrm{~nm}, 620 \mathrm{~nm}, 1200 \mathrm{~nm}$[/tex].

Complete question: The allowed energies of a quantum system are 1.0 ev, 2.0 ev, 4.0 ev, and 7.0 ev. what wavelengths appear in the system's emission spectrum

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The height at which the weight of mass 8.86 kg was lifted is 3.5 m.

Height is the vertical distance between two points.

To calculate how high the weight is lifted, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the height the weight can be lifted is 3.5 m.

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The separation between fifth maximum and seventh minimum from central maximum is calculated to be 2.457mm.

The double-slit experiment shows that light and matter can exhibit the properties of classically defined waves and particles. This experiment was first performed by Thomas Young in 1802 to demonstrate the wave behavior of visible light

This experiment belongs to general class of double-path experiments, in which a wave is split into two separate waves. Changes in the path length of both the waves leads to a phase shift that creates interference patterns.

Separation between 5th and 7th minima is,

= 2 * (wavelength)x(Distance of the screen) / (slit separation)

=(2x 585x10^-9 x21x10^-2 )/ 0.1x10^-3

Hence, Separation between 5th and 7th minima is =2.457mm.

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Answer:

bhai what is yhis? i dont understand

The distance travelled and the time it takes to travel that distance must be measured in order to determine an object's speed in motion.

Movement is the act or process of moving or changing one's location or position. ability to move with the force of a living body. gait is the term for the way a person walks. Motion can be divided into three categories depending on its type, as follows: linear movement Rotational Motion Motion in oscillations.

Things move in response to forces. They have the power to initiate motion, as well as to slow down, stop, or alter the path of an already moving item. We can say that forces produce changes in velocity because they alter an object's speed or direction. Keep in mind that acceleration is a modification of velocity.

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According to Charles' Law, the V/T = k, V1/T1=V2/T2, in case v1= 4.39, T1= 44C=317 K (being O C= 273 K) V2=3.78 L T2=?. Charles law, 4.39L/317K = 3.78L/T2. T2x=4.39L/317K = 3.78 L. T2= 3.78L/4.39/317k, T2=273K=0 C

Place the bucket into the larger container, fill it with water, then submerge the inflated balloon completely. After that, remove the bucket, pour the water from the larger container into the measuring container, and measure the volume of the water.

The basic formula for volume is length, breadth, and height, as opposed to length, width, and height for the area of a rectangular shape. The calculation is unaffected by how you refer to the various dimensions; for instance, you can use "depth" instead of "height."

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Answer:

Hubble's law is considered a fundamental relation between recessional velocity and distance. However, the relation between recessional velocity and redshift depends on the cosmological model adopted and is not established except for small redshifts.

Explanation:

The relationship between recessional distance and velocity is thought to be governed by Hubble's law. Although it is not confirmed save for minor redshifts, the relationship between recessional velocity and redshift relies on the cosmological model used.

Although Hubble was a real person, a spacecraft that was launched into space was given his name. He found that the galaxies that seem to be farthest from us are accelerating their distance from us, while the galaxies that are nearer to us are lagging.

Hubble's law is therefore that. If you study higher-level astronomy, you can do a mathematical operation known as Hubble's law. You can determine a mathematical relation that says that anything moves quicker the further distant it is from you.

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The final momentum will be the sum of the initial momentum of the two vehicles. The final velocity of the combined mass will be 5.9 m/s.

Collision is a short range force exerted by an object on other object make them move either to the same side or opposite sides based on their mass.

Momentum of a moving body is the product of its mass and velocity. During a collision, the initial momentum will be equal to the final momentum.

The momentum of the car  = mass × velocity

                                             = 1193 Kg × 27.6 m/s

                                             = 32926 kg m/s

The initial momentum of the truck is zero because it was stationary.

The final momentum with the velocity v, of the combined mass is equal to the total initial momentum i.e. 32926 kg m/s.

32926 kg m/s =  (1193 Kg  + 4302 Kg) v

v = 32926 kg m/s /   (1193 Kg  + 4302 Kg)

  = 5.9 m/s.

Therefore, the final velocity of the vehicles when they stuck together is 5.9 m/s.

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A reflecting telescope is built with a 10-cm-diameter mirror having a 1.00 m focal length. it is used with a 5× eyepiece. F/10.

What is Magnification?

Magnification of the[tex]$M_{\text {tellicops }}=\frac{\text { Focallength of the objective }}{\text { focal length of the eyepiece }}$[/tex]

Focal length of the objective [tex]$=1.0 \mathrm{~m}=100 \mathrm{~cm}$[/tex]

For a magnifier, magnification [tex]$M=\frac{10}{\text { Focal length }}$[/tex]

Where the focal length must be in inches

Magnification of eyepiece [tex]$M=5 X$[/tex]

Focal length of the eyepiece[tex]$=\frac{10}{5}=2$ inches $=5.08 \mathrm{~cm}$[/tex]

There for magnification of the telescope

[tex]$$\begin{aligned}& M_{\text {telescope }}=\frac{100}{5.08} \\& M_{\text {telesccpe }}=19.68 \approx 20 \mathrm{X}\end{aligned}$$[/tex]

f number of the telescope[tex]$\mathrm{N}=\frac{f}{D}$[/tex]

f is the focal length of the objective[tex]$=1 \mathrm{~m}=100 \mathrm{~cm}$[/tex]

[tex]$\mathrm{D}$[/tex] is the diameter of the objective[tex]$=10 \mathrm{~cm}$[/tex]

[tex]N=\frac{100}{10}=f / 10$$[/tex]

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Answer: MOVING

Explanation:

A magnetic field is caused by a MOVING electric charge.

Charge can be positive or negative.

The weight of a 31 kg object on the earth is 304.017 newtons.

Weight equals (mass of the thing) x (acceleration of gravity in that place).

— The acceleration of gravity on Earth is approximately 9.807 m/s2.

31 kilograms of mass has a weight of (31 kg) x (9.807 m/s2) = 304.017 newtons.

— On the Moon, the gravitational acceleration is approximately 1.623 m/s2.

The identical mass of 31 kg has a weight of (31 kg) x (1.623 m/s2) = 5.313 newtons.

The Moon is significantly lighter in mass than the Earth. The Moon is not just smaller than the Earth, but it is also only around 60% as dense. As a result, a person weighs less on the Moon than they do on Earth due to the significantly lower gravitational attraction there.

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Shifting gears correctly is important when driving a vehicle to ensure that the car is operating at its most efficient level.

By selecting the correct gear, you can ensure that the engine works at its optimal speed, allowing it to produce the most power with the least fuel. This helps you save money on fuel costs and reduces your car’s environmental impact.

Shifting gears correctly allows you to control the speed of your car. When accelerating, you need to select a higher gear so that the engine produces more torque, enabling your car to accelerate faster. When slowing down, you should select a lower gear to reduce the engine’s revolutions per minute (RPM), allowing you to slow down quickly and safely.

Finally, correctly shifting gears also ensure your passengers' safety, including yourself. If you shift gears too quickly or at the wrong time, you increase the risk of your car stalling, which can be dangerous in certain situations. In addition, selecting the wrong gear for your traveling speed can lead to acceleration and braking, leading to an uncomfortable and potentially difficult ride.

In conclusion, it is important to shift gears correctly when driving a vehicle to ensure efficient fuel use, control the speed of the car, and keep you and your passengers safe.

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A 90 kg goaltender celebrate by jumping 110 cm into the air after defending the goal. 970.20 J was work done throughout the celebration.

The sum of the displacement as well as the components of the force applied of the object in the displacement direction is the work done by a force. The body moves with certain acceleration when we push a blocks with certain force, and work is completed.

m = mass of the body = 90 kg

g = gravitational force

h = height = 110cm

Formula -

work done = mgh

                   = 90 × 9.8 × 110

                   = 970.20 J

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The spring constant for storing the same amount of energy is given as x = 0.707 cm.

What does a string mean?

A string is a computer data type that is similar to an integer and a floating point unit, except it represents text instead of numbers. It is made up of a series of symbols that may also include spaces and numerals.

briefing :

E = /kx2 is the energy that has been stored.

E1 = E2

1/2 k(1.0)² = 1/2 (2k)x²

x^2 = 1/2 (1.0)²

x = 1.0/√2 cm

x = 0.707 cm

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In both cases, y and x components are solved and added. The resulting speed hypotenuse is then computed and its direction calculated.

Airplane:

Ф = 270 - 265 = 5°

Hypotenuse, h = 400 mph

y component = 400 Sin Ф = 400 Sin 5 = 36.61 mph

x component = 400 Cos Ф = 400 Cos 5 = 418.40 mph

Wind

Ф = 315 -210 = 60°

Hypotenuse, h = 30 mph

y component = 30 Sin 60 = 25.98 mph

x component = 30 Cos 60 = 15 mph

Total y = 36.61+25.98 = 62.59 mph

Total x = 418.40+15 = 433.40 mph

Resulting speed of airplane = Sqrt (y^2+x^2) = Sqrt (62.59^2+433.40^2) = 437.9 mph

Direction = 270 -[tan^-1 (y/x)] = 270 -[tan^-1(62.59/433.40)] = 261.78°

Therefore, the resulting speed is 437.9 mph in the direction of 261.78°

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Making a few assumptions like uniformity and flatness of the universe we have :

A. [tex](\frac{a}{a} )^{2} = \frac{8\pi gs+\pi }{3}[/tex]

B. [tex]\frac{a}{a} = - \frac{4\pi G}{3} (S+3P)+\frac{\pi }{3}[/tex]

where is 'a' is a scale factor which tells us how expanded the Universe is. And it's the first derivative gives the rate of expansion and its second derivative gives the acceleration of the universe.

So if G increases, due to the mass of neutrons. Then the acceleration would have a negative value which would mean slowing down.

All the above however does not consider dark energy, which would modify the equations. We still have to understand the nature of dark matter to be able to predict how much in the long run would gravity affect acceleration.

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16775 watts or 16.7kW is the amount of work done in 2.3 minutes when the water is pumped for a distance of 38m/s.

The sum of the displacement and the component of the applied force of the object in the displacement direction is the work done by a force. Work is accomplished when we push a block with some force; the body moves more rapidly.

Distance is the sum of an object's movements, regardless of direction. The distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.

Calculation:

Given,

Distance= 38m

Rate = 25mL/s = 0.25L/s

To find work done in 2.5mins Or 150seconds

Potential energy (P.E) = (mgh) /t

P.E = (mgh) /t

     = (0.25 Ls-¹ * 9.81 * 38m) / 1sec

     = 93.195 Watts

For 1 sec 93.195 watt is used

For 2.5mins Or 180 seconds = 93.195 × 180= 16775 watts or 16.7kW power is used for the work done.

Hence, 16775 watts or 16.7kW is the amount of work done in 2.3 minutes when the water is pumped for a distance of 38m/s.

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The surface area of the flament is -4 m square feet.

Surface means an outside part of an body or object.

We are asked to find the surface area. So we have to use the equation that relates power and surface area. So power is :

H= Ae σ T⁴

Where, H= power (60 watts)

A=area

σ=universal constant (5.67×10⁻⁸ w/m²)

T=Temperature(1773k)

So our surface area is just our area. A. So A. Is equal to power divided by the emissivity times of the  Stefan bolts, mons, constant to the  times the temperature to the fourth of  power.

So now we can the  substitute our values

(60/600.23)×5.67×10⁻⁸×1773⁴=4.65×10⁻⁴m²

Area of the filament is 4.65×10⁻⁴m²

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According to the question the far point in m of a person's eye is 0.30m.

In terms of the space the eye can accommodate, this refers to the farthest distance from which an item can be positioned for its picture to be mirrored on the retina. It can also be thought of as the distance from the eyes at which pictures are clearly visible. The units are meters, or m.

P = relaxed power of the eye

F =far point

Given in the question:

The power of the eye is given as

P = 1/di + 1/do

P is power of the eye

di is the distance between eye lens and the image

d₀ is distance between eye lens and image

Given that,

P =53.3d

Take note that the power unit "d" stands for "dioptre," which means "per meter."

If the person can see clearly, the separation between the eye lenses and the picture (di), which is 2 cm, must be identical to that distance.

Thus, di = 2cm = 0.02m

P = 1/di + 1/d₀

1/d₀ = P — 1/di

1/d₀ = 53.3 — 1/0.02

1/d₀ = 53.3—50

1/d₀ = 3.3m

taking reciprocal

d₀ = 1/3.3

d₀ =0.3030m

Then, d₀ = 0.3030m

d₀≈ o.30m

The far point the person can see is 0.30m

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Solving the acceleration is S=ut +1/2at^2, S=27

v 2 = v 0 2 + 2 a ( x − x 0 ) ( constant a ).

Sn = u + a (n – ½). Hence, the formula for distance travelled in nth second is given by, Sn = u + a (n – ½).

distance = speed × time.

Where

S is displacement

u is initial velocity =0 (as the body is at rest)

a is acceleration

t is time taken

So,

S=1/2at^2

S=1/2 ×6×3 ×3

S=3×3 ×3

S=27

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The kinetic energy of the object with a mass of 10 kilograms traveling at a speed of 10 meters per seconds is 500 Joules.

Newton’s laws are encapsulated in what may be the second most famous equation in physics: F = ma, which states that a force F applied to a mass m results in an acceleration a.

Since the mass is accelerating, its velocity v is not constant, but since the acceleration is constant, and acceleration is the rate of change of velocity, the rate at which v is changing is constant and is equal to the acceleration a.

Since the work done by the force is just the energy imparted to the mass, we will use the letters K.E to stand for this work. Then we get,

K.E = ½ × m × v²

Where;

K.E = kinetic energy

m = mass

v = speed

K.E = ½ × 10 × 10²

K.E = 5 × 100 =  500 J

Hence, the correct option is b.

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The approximate acceleration of the bookshelf is 1.3 m/s².

Using this formula

Acceleration = Net force ÷ Mass of bookshelf

Where:

Mass of bookshelf = 51.5 kilogram

Net force = 67 Newton

Let plug in the formula

Acceleration = 67 ÷ 51.5

Acceleration = 1.30 m/s²

Inconclusion the approximate acceleration of the bookshelf is:- 1.3 m/s².

What is acceleration?

An item is said to be accelerated if there is a change in its velocity. The change in the velocity of an item could be an increment or decrement in speed or a change in the direction of motion. A few examples of acceleration are the falling of an orange, the earth orbiting around the sun, or when a car is stopped at the traffic lights. Through these examples, we can deem that when there is a change in the direction of a moving item or an increment or decrement in speed, acceleration occurs.

The approximate acceleration of the bookshelf is 1.3 m/s².

Using this formula

Acceleration = Net force ÷ Mass of bookshelf

Where:

Mass of bookshelf = 51.5 kilogram

Net force = 67 Newton

Let plug in the formula

Acceleration = 67 ÷ 51.5

Acceleration = 1.30 m/s²

Inconclusion the approximate acceleration of the bookshelf is:- 1.3 m/s².

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The volume of the sprinkler for the given water supply is V1 = 0.32m/s, by using Bernoulli's equation.

According to Bernoulli's principle of fluid dynamics, a fluid's speed increases at the same time as its static pressure or potential energy decreases. The Bernoulli equation is regarded as the definition of energy conservation for flowing fluids. This is thought to be the qualitative behaviour that reduces pressure in high-velocity zones. Also, referred to as the Bernoulli effect.

Calculations:

Using continuity equation, Bernoulli's equation.

A1×V1 = A2×V2

Where,

A1 = area of the supply pipe

V1 = volume of supply pipe

A2 = area of sprinkler

V2 = volume of sprinkler

Given,

Diameter of supply pipe = 2.5cm therefore radius = 1.25cm.

Diameter of sprinkler = 0.5cm therefore radius = 0.25cm.

V1 = (A2×V2) /A1

V1 = (π [tex]r_{2}[/tex]²× V2) / (π [tex]r_{1}[/tex]²)

V1 = {π (0.25) ² × 8} / { π (1.25) ²}

V1 = 0.32m/s.

Hence, the volume of the sprinkler for the given water supply is V1 = 0.32m/s, by using Bernoulli's equation.

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The speed of the block after a time t1 be greater than, less than, or equal to v1 is higher.

Initial velocity is the velocity at time interval t = 0 and it's miles represented by way of u. it's far the speed at which the motion begins. they're four initial pace formulation: (1) If time, acceleration and very last pace are supplied, the initial velocity is articulated as. u = v – at.

Calculation:-

V 1 = R/ (R/v + ut)

Since the denominator is smaller. So the Velocity becomes higher.

Speed is described as. The rate of exchange of function of an item in any course. pace is measured because the ratio of distance to the time wherein the distance was included. speed is a scalar amount as it has simplest course and no magnitude.

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