Stephon makes the following statements: statement 1 lim x -3 f(x) exists and is equal to 1 statement 2 lim x 1 f(x) exists and is equal to 1
Neither statement 1, nor statement 2 are correct
The given Stephon's statements are;
Statement 1; [tex]\mathbf{\lim \limits _{x \to -3} f(x)} \ \mathbf{Exist} \ and \mathbf{\lim \limits _{x \to -3} f(x) = 1}[/tex]
Statement 2; [tex]\mathbf{\lim \limits _{x \to 1} f(x)} \ \mathbf{Exist} \ and \mathbf{\lim \limits _{x \to 1} f(x) = 1}[/tex]
The analysis of the graph and reason for the answer
From the graphed line on the left of the y-axis, we have an open circle at x = -3, and an arrow at the other end pointing towards negative infinity, (-∞) which indicates that the domain is -∞ ≤ x < -3, therefore, at x = -3, f(x) does not exist, therefore, we can write the following statement
The limits of the domain and range of the graph includes;
[tex]\mathbf{\lim \limits _{x \to -3} f(x)} = \mathbf{Does \ not \ exist}[/tex]
f(x) = Defined for -∞ ≤ x < -3
Similarly, from the graphed line on the right of the y-axis, we have an open circle at x = 1 and an arrow at the other end of the line f(x) = 4 pointing towards positive (+∞) infinity, which indicates the domain and the graph of the function is 1 < x ≤ ∞ , therefore, f(x) does not exist at x = 1, and we can write
[tex]\mathbf{\lim \limits _{x \to 1} f(x)} = \mathbf{Does \ not \ exist}[/tex]
From we above, we have that neither statement 1, nor statement 2 are correct
Learn more about open and closed circles on graph lines
https://brainly.com/question/8648835
Số nghiệm của pt | 2x-3| - | 3x+2|=0 là?
Answer:
2 solutions
Step-by-step explanat
ion:|2x-3|-|3x-2|=0
<=>|2x-3|=|3x-2|
<=>2x-3=3x-2
Or 2x-3=-3x+2
<=>2x-3x=-2+3
or 2x+3x=2+3
<=>x=-1
Or x=1
Are 5-x=y and x-5=y the same ?
Answer:
not really
Step-by-step explanation:
because on the first equation you subtract 5and take to y as a negative and in the second equation 5 goes as a positive at least that is what i think
Answer:
no cause
5-x=y
5 is positive , x is negative
BUT
x-5=y
5 is negative, and x is positive
Solve 4 sinx + 9 cosx=0 for 0°
4 sin(x) + 9 cos(x) = 0
4 sin(x) = -9 cos(x)
tan(x) = -9/4
x = arctan(-9/4) + nπ … … … (in radians)
or
x = arctan(-9/4) + 180n ° … … … (in degrees)
where n is any integer.
I'm guessing you're solving for x over some domain, probably 0° ≤ x < 360°. In that case, you would have two solutions for n = 1 and n = 2 of
x ≈ 113.96° and x ≈ 293.96°
NOW ASAP PLEASE NEED FAST ANSWERRRRRRRR
Let's take any 2 points from the line.
1. (-4,-2)
2. (-2,-7)
[tex]slope \\ = \frac{Δy}{Δx} \\ = \frac{y_{2} - y_1}{x_{2} - x_1} \\ = \frac{ 7 - ( - 2)}{ - 2 - ( - 4)} \\ = \frac{5}{2} \\ = 2 \frac{1}{2} \\ = 2.5[/tex]
simplify 1+tan^2x÷1+tan^2x
Answer:
uihuii
Step-by-step explanation:
a) 61°
b) 29°
C) 40°
d) 50°
Answer:
29 degrees (~0.506 rad)
A music shop sold 25 50$ radios at a profit of 8% and 6 30$ radios at a loss of 15% how much was the profit or loss combined
Answer:
The profit or loss combined is $2.99
Step-by-step explanation:
Given;
cost price of first radio, CP = $25.50
profit percent, = 8%
The profit made is calculated as;
[tex]\frac{Profit}{CP} \times 100\% = \frac{SP-CP}{CP} \times 100\% = 8\%\\\\Profit = SP-CP = 0.08CP = 0.08\times \$25.50 = \$ 2.04[/tex]
Cost price of the second radio, CP = $6.30
loss percent = 15%
The loss incurred is calculated as;
[tex]\frac{Loss}{CP} \times 100\% = 15\%\\\\Loss = 0.15CP\\\\Loss = 0.15 \times \$6.30 = \$0.95[/tex]
The profit or loss combined = $2.04 + $0.95
= $2.99
Does Anybody Know The Answer?
Yes. When a graph has more than one line it is a piece wise graph.
please help fast!! geometry
Answer:
512 inches ^2
Step-by-step explanation:
The surface area is found by
SA = 2(lw+wh+hl) where l is the length h is the height and w is the width
SA = 2( 8*8 + 8*12 + 12 * 8)
= 2(64+ 96+96)
= 2 ( 256)
= 512 inches ^2
Answer:
512 square inches
Step-by-step explanation:
8 x 8 = 64
12 x 8 = 96
64 x 2 = 128
96 x 4 = 384
128 + 384 = 512 in^2
PLEASE HELP ITS TIMED
If x/3=5/6,
then x=
Step-by-step explanation:
x/3 = 5/6
cross multiply
6x=15
x=2.5
Answer:
x=5/2
Step-by-step explanation:
help pls due in 3hrs
9514 1404 393
Answer:
(-3, -2), (-2, -2), (-2, -3), (-3, -3)
Step-by-step explanation:
Dilation about the origin multiplies each coordinate value by the dilation factor. Here, every coordinate of the original image is multiplied by 1/2 to form the "enlargement." Since the scale factor is less than 1, the "enlarged" image will be smaller and closer to the origin.
The coordinates, clockwise from upper left, are ...
(-3, -2), (-2, -2), (-2, -3), (-3, -3)
Find the measure of each angle indicated.
A) 25°
C) 35°
B) 45°
D) 40°
Answer:
here's the answer to your question
Answer:
D) 40
Step-by-step explanation:
To solve the question you can use the knowledge that every triangle has a total of 180 degrees. Two of the angles are known one is 50 and the other is 90. We know one is 90 because of the square around the angle. Then, you can set up an algebraic equation to solve. We know that 50+90+x=180, so solve for x for the final answer of 40.
15) A new BMW decreases in value exponentially after it is purchased. If a new BMW is valued at $55,000 and
depreciate at a rate of 22% a year, what is the value after 4 years? After 8 years)
The values of BMW after 2, 4 and 8 years according to the EXPONENTIAL FUNCTION are $33,462, $20,358.28 and $7,535.63 respectively.
Using the parameters given, we define an decreasing exponential function :
[tex]A = A_{0} (1 - r)^{t}[/tex]
Where,
[tex]A_{0}[/tex] = initial amount ; r = Rate ; t = time ; A = final amount
Value after 2 years :
t = 2
A = 55000(1 - 0.22)²
A = 55000(0.78)²
A = $33,462
Value after 4 years :
t = 4
A = 55000(1 - 0.22)^4
A = 55000(0.78)^4
A = $20,358.28
Value after 8 years :
t = 4
A = 55000(1 - 0.22)^8
A = 55000(0.78)^8
A = $7,535.63
Therefore, the value of BMW after 2, 4 and 8 years are $33,462, $20,358.28 and $7,535.63 respectively.
Learn more about Exponential functions :
https://brainly.com/question/14355665
[tex]\sqrt{x^{2} +4x+4[/tex] -3=0
Answer:
Given,
[tex] \sqrt{ {x}^{2} + 4x + 4} - 3 = 0 \\ = > \sqrt{ {x}^{2} + 4x + 4} = 3 \\ = > {( \sqrt{ {x}^{2} + 4x + 4} })^{2} = {3}^{2} \\ = > {x}^{2} + 4x + 4 = 9 \\ = > {x}^{2} + 4x + 4 - 9 = 0 \\ = > {x}^{2} + 4x - 5 = 0 \\ = > {x}^{2} + 5x - x - 5 = 0 \\ = > x(x + 5) - 1(x + 5) = 0 \\ = > (x - 1)(x + 5) = 0 \\ \\ \sf \: either \: x - 1 = 0 \: \: \: \: \\ = > x = 1 \: \: \\ \\ \sf \: or \\ x + 5 = 0 \\ = > x = - 5 \\ \\ \green{ \boxed{ \bf \: \: \: \: \: x = 1 \: \: or \: - 5}}[/tex]
But if we put the value of x = 5 then it doesn’t satisfy the equation.
So,
X = 1
Answer:
The answer is [tex]x=1[/tex].
Step-by-step explanation:
To solve this problem, start by factoring the equation using the perfect square trinomial rule, which is states that the middle term is the first term multiplied by the last term, and then multiplied by 2. The formula for the perfect square trinomial rule looks like [tex]a^2+2ab+b^2[/tex], where [tex]a=x[/tex] and [tex]b=2[/tex]. The equation will look like [tex]\sqrt{(x+2)^2}-3=0[/tex].
Next, pull out the terms from under the radical, assuming positive real numbers, which will look like [tex]x+2-3=0[/tex]. Then, simplify the equation by subtracting 3 from 2, which will look like [tex]x-1=0[/tex]. Finally, add 1 to both sides of the equation, and the answer will be [tex]x=1[/tex].
A number, y, is equal to the difference of a larger number and 3. The same number is one third of the sum of the larger
number and 9 Which equations represent the situation?
x+y 3 and - 3y -27
Oxxy-3
and-3--
Oy - 3
and-3--27
X-Y-3 and x-3y --9
Answer:
Set the larger number as x"A number, y, is equal to the difference of a larger number and 3."
[tex]y=x-3[/tex]
You can rearrange this equation to find the matching answer choice:
[tex]y-x=-3\\x-y=3[/tex]
"The same number is one third of the sum of the larger number and 9."
[tex]y=\frac{1}{3} (x+9)[/tex]
You can rearrange this equation to find the matching answer choice:
[tex]y=\frac{1}{3} x+3\\3y=x+9\\3y-x=9\\x-3y=-9[/tex]
state the equation, in slope-intercept form of each of the following graph
Answer:
A) y=(1/4)x-1, 4y=x-4
B) y=-2x
A painter made the table below to show the amount of paint it takes to cover a certain amount of square feet. The amount of paint varies directly with the area of each wall.
Amount of Paint and Size of Wall
Area of wall feet squared, x
64
144
400
Amount of paint (pints), y
4
9
25
How much paint should the painter expect to use to paint a wall with an area of 256 square feet?
16 pints
32 pints
128 pints
225 pints
Answer:
16 pints
Step-by-step explanation:
it seems like there's a pattern. when you divide x by 16, you get the result of y.
64/16 = 4
144/16 = 9
400/16 = 25
so to find the answer would be x/16 = y.
sqrt ft is x, pints is y.
we're looking for how many pints of pain we should use for 256 sqrt ft. we use that same equation, but replace x with 256, and solve for y.
256/16 = 16
therefore, your answer is 16 pints.
please subscribe to #Gauthmath# subreddit if ya can ^^
Answer:
16 pints
Step-by-step explanation:
I did it on edge.
2(2x+3)=3(3x+1)
Duýdhdhdjjdjdjđm
Answer:
12
Step-by-step explanation:
.......................
Answer:
x=1/2
Step-by-step explanation:
Given m
n, find the value of x and y.
m
35°
x
yº
X=
y =
PLS HELP I’m kinda really confused
Answer:
x = 145°, y = 35°Step-by-step explanation:
Given,
m || n
So,
35° = y° [Alternate interior angles]
And,
y° + x° = 180° [Since linear pair]
=> x + 35 = 180
=> x = 180 - 35
=> x = 145°
Hence,
x = 145°, y = 35°
Answer:
x = 145
y = 35
Step-by-step explanation:
35 and y are alternate interior angles and alternate interior angles are equal when the lines are parallel
35 = y
x+y = 180 because x and y form a straight line
x+35 = 180
x = 180-35
x = 145
Simplify (b9)3. See picture please
Answer:
b^27
Step-by-step explanation:
Answer:
A. b^27
You multiply 9x3 and you get 27 with the base "b"
Step-by-step explanation:
A fruit seller bought 160 kg of apples at Rs. 32 per kg. He sold one fourth of them at Rs. 40 per kg and sold the rest at Rs. 31 per kg. Find his profit or loss.
Answer:
A fruit seller bought 160 kg of apples at Rs. 32 per kg. He sold one fourth of them at Rs. 40 per kg and sold the rest at Rs. 31 per kg. Find his profit or loss.
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Guys please help me with this problem
Answer:
11. 5%
Step-by-step explanation:
1 + percent increase = 1.115
Percent increase = 1.115 - 1 = 0.115 = 11.5 /100 = 11.5 %
Answer:
Step-by-step explanation:
In the exponential form of an equation, the growth or decay rate is found inside the parenthesis. The standard form of an exponential equation is
[tex]y=a(1+r)^x[/tex] if it's growth, or
[tex]y=a(1-r)^x[/tex] if it's decay.
Looking at those equations, logically a growth equation is greater than 1, while a decay equation is less than 1. Obviously, our function is a growth.
To determine the rate of growth, we look closely at (1.115) inside the parenthesis. BECAUSE that is greater than 1, we KNOW it is growth, therefore, it follows the (1 + r) pattern. Let's break up our (1.115) so it models that pattern:
(1.115) --> (1 + .115) and since these are percentages in their decimal form, it follows that 1 is 100% and .115 is 11.5%. Our growth rate is 11.5%
You hit a tennis ball with an initial vertical velocity of of 10 ms The ball leaves the tennis racket 2 meters above the ground How much time does your opponent have before the ball hits the ground on the other side of the net
Answer:
1.02secs
Step-by-step explanation:
Using the equation of motion
v = u+at
Since the ball moves upward then:
a = -g
Substitute into the formula
v = u-gt
Given the following
Initial velocity u = 10m/s
Final velocity v = 0m/s (on the ground)
g = 9.8m/s²
Required
Time t
Substitute the given values into the formula
0 = 10-9.8t
-9.8t = -10
t = 10/9.8
t = 1.02secs
Hence your opponent have 1.02secs
Write and algebraic expression:
The tens digit of a number is b and the units digit is twice as big. What is the value of the number in terms of b if the digits are reversed?
Answer:
21b
Step-by-step explanation:
Cual de las siguientes expreciones permite a fatima obtener t que es la cantidad de palitos nesesaria para armar una figura n
Answer:
T(n) = 4 + 12*n
Step-by-step explanation:
La pregunta completa se puede ver en la imagen de abajo.
En ella, podemos ver que:
La primera figura tiene: 16 palitos
la segunda figura, con n = 2, se añaden 3 palitos en cada extremo, por lo que tendremos 16 palitos + 4*3 palitos = (16 + 12) palitos
De manera similar, en la tercera figura se vuelven a añadir 3 palitos en cada extremo de la cruz, entonces esta figura tendrá:
(16 + 12) palitos + 4*3 palitos = (16 + 12 + 12) palitos.
Así, tenemos la relación:
T(1) = 16
T(2) = 16 + 12
T(3) = 16 + 12 + 12
Podemos asumir que la forma general será:
T(n) = 16 + 12*(n - 1)
podemos reescribir esto como:
T(n) = (12 + 4) + 12*(n - 1)
= 4 + 12 + 12*(n - 1)
= 4 + 12*n
La opción correcta es la primera.
How many numbers of the set {1, 2, 3, 4, . . . , 297, 298, 299, 300} are multiples of 10 but not multiples of 15?
Answer:
I get 20
Step-by-step explanation:
While there probably is some logical way to go about this I just did it in excel
screenshot below
Answer:
20
Step-by-step explanation:
10
20
40
50
70
80
100
110
130
140
160
170
190
200
220
230
250
260
280
290
factorize
a)a²x+2ax-3x+5a²+10a-15
b)(a+b)(a-b)-a+b
c)x³-x²+x+x²y-xy+y
Answer:
(a)x(a^2+2a-3)+5(a^2+2a-3)
can you help me i got two wrong if I get one wrong I will have a falling grade
Answer:
the bottom left is wrong
Step-by-step explanation:
if u add 40+5+7/10+1/100 it'll only equal to 45.71
Answer:
40 + 5 + [tex]\frac{7}{10}[/tex] + [tex]\frac{1}{100}[/tex] = 45.71
Step-by-step explanation:
The one needs to be in the thousandths place.
For the function p defined by p(m)=2m2−4m+3, find p(13).
A. 41/9
B. 17/9
C. 5
D. 1.8
Answer:
Here we have:
p(m) = 2m^2 - 4m + 3
And we want to find p(13)
This means that we just need to replace all the m's by the number 13 in the equation, so we get:
p(13) = 2*(m = 13)^2 - 4*(m = 13) + 3
p(13) = 2*(13)^2 - 4*13 + 3
= 338 - 52 + 3 = 289
You can see that none of the options matches this, so maybe the equation or some other part of the question is written incorrectly, but here you have at least the general way of solving these type of problems.
