Answer:
cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
Explanation:
What is the smallest possible value of the principal quantum number n for an s electron?
Answer:
The smallest possible value of the principal quantum number (n) for an electron in an atom is n = 1. This is referred to as the first energy level or the "1s" orbital, and it corresponds to the lowest energy state of an electron in an atom.
Explanation:
In general, the value of n determines the size and energy of the electron orbital. The larger the value of n, the larger the size of the orbital and the higher the energy of the electron. The smallest possible value of n is therefore always 1, and it corresponds to the electron being in its lowest energy state.
If the line on a distance versus time graph and the line on a speed versus time graph are both straight lines going through the origin and the 2 graphs be displaying the motion of the same object
No, because covering uniform distance in uniform units of time ( which the graph one represents) is constant speed, and not uniform speed (as represented in the second graph).
What is a graph?
A generalisation that enables several edges to share the same pair of endpoints is a multigraph. Multigraphs are sometimes simply referred to as graphs in writings.The edges that connect a vertex to itself are known as loops, and they are occasionally permitted in graphs. The definition above needs be modified to define edges as multisets of two vertices rather than sets in order to support loops.When it is obvious from the context that loops are permitted, such generalised graphs are referred to as graphs with loops or just graphs.The set of edges must also be finite because the set of vertices V is typically assumed to be finite. Although occasionally taken into consideration, infinite graphs are typically seen as a specific type of binary relation because most findings on finite graphs are binary.To know more about graph, click the link given below:
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Blackbody Temperature 5800 K B GR Graph Values Labels Intensity 100 Sirius A o Spectral Power Density (MW/m/um) Sun Light Bulb 0 Earth Wavelength (m) 1 n = 1000 mm This simulation shows the amount of power opaque objects at different temperatures will emit at different electromagnetic wavelengths. Such spectra are known as blackbody spectra and it is the feature of the light emitted by any object due to its temperature. Stars, famously, produce blackbody spectra that affect the colors that they appear. The simulation starts with simulating the Sun's spectrum. Explore the simulation and search through the different options to determine the wavelength of light in micrometers where the Sun's blackbody spectrum peaks: micrometers Express this value in nanometers: nanometers What kind of electromagnetic radiation is this? infrared visible ultraviolet What is the solar intensity (the amount of power per unit area emitted by the Sun 10
The wavelength of light in micrometers where the Sun's blackbody spectrum peaks is approximately 0.5 micrometers or 500 nanometers.
The simulation provided allows the user to explore blackbody spectra emitted by opaque objects at different temperatures. Such spectra are the characteristic feature of light emitted by any object due to its temperature. The simulation begins by showing the blackbody spectrum of the Sun. By exploring the different options, the user can determine the wavelength of light in micrometers where the Sun's blackbody spectrum peaks, which turns out to be around 0.5 micrometers or 500 nanometers. This is within the visible spectrum of electromagnetic radiation, which is why we can see the Sun as a yellowish-white color. Additionally, the simulation provides information about solar intensity, which is the amount of power per unit area emitted by the Sun.
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1. we know that the total amount of heat that flows out of the sample and into the water at a specific time is given byLaTeX: Q\:=\:m_sc_s\left(T_{s,i}-T_s\right)Q=mscs(Ts,i−Ts), whereLaTeX: T_sTs is the temperature of the sample at a specific time and, again,LaTeX: T_{s,i}Ts,i is the initial temperature of the sample (at time 0). To simplify the math, we may neglect the heat leak term here to say that this is roughly the same amount of heat the flows into the water, soLaTeX: Q=m_wc_w\left(T_w-T_{w,i}\right)Q=mwcw(Tw−Tw,i), whereLaTeX: T_wTw is the temperature of the water at this same specific time andLaTeX: T_{w,i}Tw,i is the initial temperature of the water.
In the lab, we will measure both the sample and water temperatures as a function of time, but the important quantity is the difference between these temperatures since this is what drives the heat flow between the center of the sample and the water. Using the above equations (solving for the temperatures of the sample and the water bath at a particular time), we can find the relationship between the total amount of heat flow and the difference in the temperatures of the center of the sample and water at some moment in time. This yields _________________________________.
sample and water at some moment in time. This yields _________________________________.
Group of answer choices
Option D: the link between the total heat flow and the temperature difference between the sample's Centre and the water at a specific time.
[tex]Q\:=\:m_sc_s\left(T_{s,i}-T_s\right)[/tex]
[tex]T_s\right =(T_{s,i}-T_s\right))[/tex]
[tex]Q=m_wc_w\left(T_w-T_{w,i}\right)[/tex]
[tex]Q=m_wc_w\left(T_w-T_{w,i}\right)[/tex]
[tex]T_{diff} =(T_{s}-T_w\right))[/tex]
= [tex]T_{s,i} -\frac{Q}{m_{s}C_{s}} -(T_{w,i}\right +\frac{Q}{m_{s}C_{s}} )[/tex]
=[tex](T_{s,i} - T_{w,i} )-Q(\frac{1}{m_{s}C_{s}} +\frac{1}{m_{w}C_{w}})[/tex]
Specific time refers to a precise moment in time, often denoted by a particular time and date. It can be expressed in different ways depending on the context, such as using a 24-hour clock or the AM/PM system. Specific time is essential for scheduling events, meetings, and appointments, and for coordinating activities across different time zones. It is also crucial for time-sensitive activities such as transportation, where schedules must be coordinated down to the minute. The concept of specific time is used in many fields, including science, technology, business, and everyday life. In modern times, technologies such as smartphones and computers have made it easier than ever to track and coordinate specific times across the globe.
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The complete question is:
1. we know that the total amount of heat that flows out of the sample and into the water at a specific time is given by LaTeX: [tex]Q\:=\:m_sc_s\left(T_{s,i}-T_s\right)Q=mscs(Ts,i−Ts)[/tex], where LaTeX: [tex]T_sTs[/tex] is the temperature of the sample at a specific time and, again, LaTeX: [tex]T_{s,i}Ts,i[/tex]is the initial temperature of the sample (at time 0). To simplify the math, we may neglect the heat leak term here to say that this is roughly the same amount of heat the flows into the water, so LaTeX: [tex]Q=m_wc_w\left(T_w-T_{w,i}\right)Q=mwcw(Tw−Tw,i)[/tex], where LaTeX:[tex]T_wTw[/tex] is the temperature of the water at this same specific time and LaTeX: is the initial temperature of the water.
In the lab, we will measure both the sample and water temperatures as a function of time, but the important quantity is the difference between these temperatures since this is what drives the heat flow between the center of the sample and the water. Using the above equations (solving for the temperatures of the sample and the water bath at a particular time), we can find the relationship between the total amount of heat flow and the difference in the temperatures of the center of the sample and water at some moment in time. This yields _________________________________.
sample and water at some moment in time. This yields _________________________________.
Group of answer choices
A. [tex]T_{dif}=T_{s\:}-T_w=\left(T_{s,i}-T_{w,i}\right)-\left(\frac{1}{m_sc_s}-\frac{1}{m_wc_w}\right)Q[/tex]
B [tex]T_{dif}=T_{s\:}-T_w=\left(T_{s,i}-T_{w,i}\right)+\left(\frac{1}{m_sc_s}+\frac{1}{m_wc_w}\right)Q[/tex]
C.[tex]T_{dif}=T_{s\:}-T_w=\left(T_{s,i}-T_{w,i}\right)+\left(\frac{1}{m_sc_s}-\frac{1}{m_wc_w}\right)Q[/tex]
D. [tex]T_{dif}=T_{s\:}-T_w=\left(T_{s,i}-T_{w,i}\right)-\left(\frac{1}{m_sc_s}+\frac{1}{m_wc_w}\right)Q[/tex]
A 5.0 kilogram initially at rest is accelerated by a force of 25 newtons such that it attains 5.0 x 102 joules of kinetic energy
Therefore, the distance over which the force acts is 20 meters.
explain about kinetic energy ?The initial kinetic energy of the object is zero since it is at rest. The work done on the object by the applied force is equal to the change in its kinetic energy:
[tex]W = ΔK[/tex]
where W is the work done and [tex]ΔK[/tex] is the change in kinetic energy.
The work done by the force can be found using:
[tex]W = Fd[/tex]
where F is the force applied and d is the distance over which the force acts.
Since the object starts from rest, we can use the equation for the work-energy principle:
[tex]W = Kf - Ki[/tex]
where Kf is the final kinetic energy and Ki is the initial kinetic energy.
Setting these two expressions for W equal to each other, we have:
[tex]Kf - Ki = Fd[/tex]
Substituting the given values, we have:
[tex]Kf - 0 = (25 N) dKf = 25d[/tex]
But we also know that the final kinetic energy is[tex]5.0 x 10^2 J[/tex], so:
[tex]5.0 x 10^2 J = 25d[/tex]
d = 20 meter
Therefore, the distance over which the force acts is 20 meters.
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Record your data either in your lab notebook or in the tables below.
Table A
(T₁= 25°C; mwater 1.0 kg; meylinder = 5.0 kg)
h
AT
Cylinder
Height
Change in
Water
Temperature
(m)
(°C)
100
200
500
1,000
Table B
(T₁= 25°C; mwater = 1.0 kg; h= 500 m)
mc
Cylinder
Mass
(kg)
Ts
Final
Temperature
of Water
(°C)
1.0
3.0
6.0
9.0
Ts
Final
Temperature
of Water
(°C)
AT
Change in
Water
Temperature
(°C)
PEg
Gravitational
Potential Energy
of Cylinder
(kJ)
PE,
Gravitational
Potential Energy
of Cylinder
(kJ)
ΔΗ
Heat
Generated
(kJ)
ΔΗ
Heat
Generated
(kJ)
Answer:
play used his in but been been by in BBC in in in just not is suspension as SBB is is abbess a
Explanation:
no exception
Forensic Entomology
Forensic Entomology
The study of the life cycle of insects that feed on the flesh to the dead, to establish time of death and occasionally identify chemicals present in a person's body at the time of death.
Time since death
Arrive a few hours after a death and are active through decomposition process. They feed on larvae and other insects rather than the corpse itself.
Larvae that feed on human excrement and remains, and are found late in the decomposition process.
Forensic Entomology is the study of life cycles of insects that feed on the flesh of dead, to establish time of death and occasionally identify chemicals present in a person's body at time of death
What is meant by Forensic Entomology?The scientific study of the colonization of dead body by arthropods is called forensic entomology .
Larvae and adults feed on dry skin and hairs of corpse and arrive later in decomposition process : Carpet Beetles
Time since death : postmortem Interval.
Rove Beetles : Arrive a few hours after death and are active throughout decomposition process. They feed on larvae and other insects rather than the corpse itself.
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a) calculate the magnitude of the force parallel to surface 1 b) calculate the magnitude of the force parallel to surface 2
A force can make a body at rest to move. The magnitude of force parallel to surface 1 is 5.04 N and the magnitude of the force parallel to surface 2 is 4.02 N.
What is Force?The force can be defined as the quantity which is expressed as the product of mass (m) and acceleration (a). It is known as the push or pull on an object which produces acceleration in the body on which it acts.
The equation which is used to calculate the force is given as:
F = ma
a) F₁ = m₁ g sin40
= 0.800 kg × 9.81 m/s² × 0.64
= 5.04 N
b) F₂ = m₂ g sin55
= 0.500 kg × 9.81 m/s² × 0.82
= 4.02 N
Thus the magnitude of the force parallel to surface 1 is 5.04 N and the magnitude of the force parallel to surface 2 is 4.02 N.
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A 1500 kg car traveling east at 20 m/s collides with a moving 2500 kg truck moving 30 m/s west.. After they collide, the two interlock and move together. What was the final velocity of the truck? (Hint-momentum is a vector and direction matters, use + or - values as appropriate)*
A. 11.25 m/s west
B. 11.25 m/s east
C. 32.6 m/s east
D. 32.6 m/s west
The final velocity of the truck after collision, given that the car and the truck interlock and move together is 11.25 m/s west (Option A)
How do I determine the final velocity of the truck?The final velocity of the truck after the collision can be obtained as illustrated below:
Mass of car (m₁) = 1500 KgInitial velocity of car (u₁) = 20 m/sMass of truck (m₂) = 2500 KgInitial velocity of truck (u₂) = 11 m/sEast = Positvie directionWest = Negative directionFinal velocity (v) = ?Momentum before = momentum after
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(1500 × 20) - (2500 × 30) = v(1500 + 2500)
30000 - 75000 = v × 4000
-45000 = v × 4000
Divide both sides by 4000
v = -45000 / 4000
v = -11.25 m/s
Recall => West is negative
v = 11.25 m/s west
Thus, the final velocity is 11.25 m/s west (Option A)
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A proton moving along the lines of force of a uniform electric
field, the intensity of which is 10 kV/m, increased its speed from 106 m/s
up to 1.1∙ 106 m/s. Find: 1) potential difference between points, 2)
acceleration of a proton, 3) path of a proton during acceleration, 4) work
electric field. The charge of a proton is 1.6 ∙ 10−19 K; the mass of a proton
1.67 ∙ 10−27 kg.
An 8.7 hour trip is made at an average speed of 73.0 km/hr. If the first third of the trip (chronologically) was driven at 96.5 km/hr, what was the average speed for the rest of the journey?
The average speed for rest of the journey = (632.1 - 281.55) / 5.8 km/hr = 88.4 km/hr.
What is average speed?Average speed is a measure of the rate of change of a certain distance traveled over a period of time. It is usually calculated by dividing the total distance traveled over time, usually in hours, minutes, or seconds. Average speed is a measure of the average rate of motion, not necessarily the actual speed at any given moment.
Let the total distance covered be D. Time taken for first third of the journey = 8.7/3 hrs = 2.9 hrs
Distance covered in first third of the journey = 2.9 * 96.5 km/hr = 281.55 km
Therefore, distance covered in rest of the journey = D - 281.55 km
Time taken for rest of the journey = 8.7 - 2.9 hrs = 5.8 hrs
Average speed for rest of the journey = (D - 281.55) / 5.8 km/hr
Substituting the value of D = 8.7 hrs * 73 km/hr = 632.1 km
Therefore, average speed for rest of the journey = (632.1 - 281.55) / 5.8 km/hr = 88.4 km/hr
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A car moving with an initial velocity of 25 m/s north has a constant acceleration of 5.5 m/s2 south. After 10 seconds its velocity will be
Answer:
80 m/s
Explanation:
v = v₀ + at
v = 25 m/s + (5.5 m/s²)(10 s) = 80 m/s
Electric Field Direction only OO Voltage Values Grid 00V a +1 nc -1 nc Sensors Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 m away from the positive charge (1 m is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength. Consider the locations to the right, left, above, and below the positive charge, all 1 m away. For these four locations, the magnitude of the electric field is. greatest to the right of the charge. greatest below the charge. greatest above the charge. greatest to the left of the charge. O O O the same. Submit Request Answer
Considering the locations to the right, left, above, and below the positive charge, all 1 mm away. For these four locations, the magnitude of the electric field is the same.
The area, space, or field around it is an electric field of an isolated charge. There are mainly two types of electric fields i.e., static and dynamic. Moving charges produced dynamic electric fields whereas static electric fields are produced by stationary charges.
Direction and magnitude do not change over time for static electric fields. The direction can be positive or negative which is determined by the charge of the source.
The electric field formula is the electric field magnitude at a certain point from the charge Q, and it hangs on two factors- the distance r from the point to the origin Q and the amount of charge at the origin Q.
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The correct question is:
Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/mV/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 mm away from the positive charge (1 mm is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength.
Consider the locations to the right, left, above, and below the positive charge, all 1 mm away. For these four locations, the magnitude of the electric field is________________.
How do you calculate soil cation exchange capacity and base saturation?
To determine the cation exchange capacity (CEC), calculate the milliequivalents of H, K, Mg, and Ca per 100g of soil (meq/100g soil) by using the following formulas: H, meq/100g soil = 8 (8.00 - buffer pH) K, meq/100g soil = lbs/acre extracted K ÷ 782. Mg, meq/100g soil = lbs/acre extracted Mg ÷ 240.
To begin, multiply the total CEC by the percentage for that ion to determine the cmolc of each cation on the exchange complex. It is 0.05 * 30 cmolc/kg for hydrogen. The cmolc/kg for each ion is then converted to mass of ion per kg by multiplying by the mass of 1 cmolc.
Soil testing laboratories calculate CEC by adding the calcium, magnesium, and potassium levels measured during the soil testing procedure to an estimate of exchangeable hydrogen derived from the buffer pH. In general, CEC values obtained through this summation method will be slightly lower than those obtained through direct measurementsdirect.
The percentage of CEC occupied by bases (Ca2+, Mg2+, K+, and Na+) is represented by base saturation (BS). The%BS increases as soil pH rises (Figure 5). Ca2+, Mg2+, and K+ availability increases as %BS increases. An 80% BS soil, for example, provides cations to plants more easily than a 40% BS soil.
Base saturation is the percentage of base cations (Ca2+, Mg2+, K+, and Na+) held onto soil exchange sites divided by total CEC.
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The diagram below shows three cubes of the same material and density. If the cubes all start out at 80°C, which cube will cool the most slowly?
Answer:
the cube that will slowly cool is 2
The cube 2 will cool the most slowly.
What is meant by cooling ?The removal of heat from a system is known as cooling, and it usually leads to a decrease in temperature or a change in phase.
Here,
Three cubes of same material and density are given in the diagram. They all are said to be cooling starting from 80°C.
The three cubes have different volumes.
We know that, as the volume of the cube increases, the surface area of the cube decreases accordingly. That means, the volume of a cube is inversely proportional to its surface area.
V ∝ 1/A
According to the principle of cooling, the rate of cooling is directly proportional to the surface area. That means, the rate of cooling is higher for objects with higher surface area and slower for those with lower surface area.
So, the cube 2 is having the lowest volume among the three cubes and thus the highest surface area.
Therefore, it will take more time to cool down.
Hence,
The cube 2 will cool the most slowly.
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Would the field representation of a positive or negative charge be a better
representation for the gravitational field around one mass? Why?
Field representation of a positive or of a positive or negative charge cannot be a representation for the gravitational field around one mass. It height from the ground must be determined.
What is gravitational force?The gravitational force is a kind of force by which an object attracts other objects into its center of a mass. Earth attracts every objects in its surface in to the ground and that is why we are all standing on the ground.
Gravitational force between two objects depends on their mass and distance between them. The field representation of the charge does not represent a gravitational field but it can show an electric field between them.
The height of the mass from the surface have to be determined to represent the gravitational field. The gravitational field is not at all depending on the charge of the object.
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A skier with a mass of 55 kg is skiing down a snowy slope that has an incline of 30°.
Find the coefficient of kinetic friction for the skier if friction is known to be 25 N.
The coefficient of kinetic friction for the skier, if friction is known to be 25 N, is calculated to be 0.463.
What is Kinetic friction?Kinetic friction may be characterized as a type of force that considerably resists the relative movement of the surfaces once they're in motion. It is just the opposite of static friction.
According to the question,
The total weight of a skier = mass of a skier × gravity = 55 × 9.8
The angle at which it inclines = 30° i.e. θ = 30°.
Normal force, N = mgcosθ
The friction force, F = kinetic friction (N)
25 N = Kf (55 × 9.8 × 30)
Kf = 0.463.
Therefore, the coefficient of kinetic friction for the skier, if friction is known to be 25 N, is calculated to be 0.463.
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The blood pressure in millimeters was measured for a large sample of people. The average pressure is 140 mm, and the sd of the measurements is 20 mm. The histogram looks reasonably like a normal curve. Use the normal curve to estimate the following percentages. Choose the answer that is closest to being correct.
Here are some possible percentages and their corresponding estimated z-scores:
Percentage of people with blood pressure below 120 mm: approximately 9.1% Estimated z-score: z = (120 - 140) / 20 = -1Percentage of people with blood pressure between 120 and 160 mm: approximately 68.3%Estimated z-scores: z1 = (120 - 140) / 20 = -1 and z2 = (160 - 140) / 20 = 1Percentage of people with blood pressure above 160 mm: approximately 9.1%Estimated z-score: z = (160 - 140) / 20 = 1These percentages are based on the empirical rule, which states that for a normal distribution, approximately 68% of the data falls within one standard deviation of the mean, approximately 95% falls within two standard deviations, and approximately 99.7% falls within three standard deviations.
What is the empirical rule?The empirical rule, also known as the 68-95-99.7 rule, is a statistical principle that describes the approximate distribution of data in a normal distribution. The rule states that:
Approximately 68% of the data falls within one standard deviation of the mean.Approximately 95% of the data falls within two standard deviations of the mean.Approximately 99.7% of the data falls within three standard deviations of the mean.This rule is based on the assumption that the data is normally distributed, meaning that it follows a symmetrical bell-shaped curve. The empirical rule is widely used in statistics and is helpful in understanding the range of values that are likely to occur in a normal distribution.
It is important to note that the empirical rule provides only approximations and can vary in accuracy depending on the specific data and distribution being analyzed.
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Option: B, The percentage of people with blood pressure between 114 and 166 mm
What is the empirical rule?The empirical rule, also known as the 68-95-99.7 rule, is a statistical principle that describes the approximate distribution of data in a normal distribution. The rule states that:
=> P(114 < x < 166)
=> P((114-140)/20 < z < (166-140)/20)
=> P(-1.3 < z < 1.3)
=> 0.8064
=> 80.6% rounded
option: D The percentage of people with blood pressure between 114 and 166 mm
=> P(140 < x < 166)
=> P((140-140)/20 < z < (166-140)/20)
=> P(0 < z < 1.3)
=> 0.4032
=> 40.3% rounded
option: C The percentage of people with blood pressure over 166 mm
=> P(x > 166)
=> P(z > (166-140)/20)
=> P(z > 1.3)
=> 0.0968
=> 9.7% rounded
This rule is based on the assumption that the data is normally distributed, meaning that it follows a symmetrical bell-shaped curve. The empirical rule is widely used in statistics and is helpful in understanding the range of values that are likely to occur in a normal distribution.
It is important to note that the empirical rule provides only approximations and can vary in accuracy depending on the specific data and distribution being analysed.
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Describe protons.
Location:
Charge:
Mass:
The protons location is nucleus of an atom, the Mass is 1 amu and the charge is positive.
What is protons?
Protons are subatomic particles with a positive electrical charge. They are found in the nucleus of atoms and are responsible for most of the atom’s mass. Protons are one of the three main subatomic particles, along with neutrons and electrons.
Location: Proton is located in the nucleus of an atom. The nucleus is the small, dense, positively charged center of an atom. The protons, along with the neutrons, make up the nucleus of the atom.
Mass: The mass of a proton is approximately 1.007276467 u (unified atomic mass units). It is slightly heavier than a neutron, which has a mass of approximately 1 u.
Charge: A proton has a positive charge of +1 elementary charge (e). This charge is what gives the proton its repelling force to other positively charged particles and its attractive force to negatively charged particles.
Hence, a proton is a positively charged subatomic particle with a mass of 1 amu, located in the nucleus of an atom.
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Answer:
Location:
✔ nucleus
Charge:
✔ positive
Mass:
✔ one amu
Explanation:
4 Carbon monoxide gas (CO) contained within a piston–
cylinder assembly undergoes three processes in series:
Process 1–2: Constant pressure expansion at 5 bar from V1 5
0.2 m3
to V2 5 1 m3
.
Process 2–3: Constant volume cooling from state 2 to state 3
where p3 5 1 bar.
Process 3–1: Compression from state 3 to the initial state during
which the pressure–volume relationship is pV = constant.
Sketch the processes in series on p–V coordinates and
evaluate the work for each process, in kJ.
To sketch the processes in a p-V diagram, we need to first determine the initial and final states of each process, as well as the path each process takes.
How do we determine the state of each process?Process 1-2 is a constant pressure expansion from state 1 to state 2. So, the path is a straight horizontal line on the p-V diagram, from (0.2, 5) to (1, 5) (in units of m^3 and bar).
Process 2-3 is a constant volume cooling from state 2 to state 3, so the path is a straight vertical line on the p-V diagram, from (1, 5) to (1, 1).
Process 3-1 is a compression process during which the pressure-volume relationship is pV=constant. This implies that the path on the p-V diagram is a hyperbola, passing through state 3 and returning to state 1.
The work done in each process can be calculated using the following equations:
W = P(V2 - V1) for constant pressure process (1-2)
W = 0 for constant volume process (2-3)
W = -nRT ln(V2/V1) for isothermal process (3-1), where n is the number of moles of CO, R is the gas constant, and T is the temperature of the gas.
Assuming standard temperature and pressure conditions (STP), which is 1 atm and 273.15 K, the gas constant R can be taken as 0.0821 Latm/(molK).
Using these equations, we can calculate the work for each process as follows:
W1-2 = 5*(1-0.2) = 4 kJ
W2-3 = 0
W3-1 = -nRT ln(V2/V1) = -10.0821273.15 ln(1/0.2) = 11.1 kJ
Therefore, the total work done on the gas in the three processes is the sum of the work done in each process, which is 4 kJ + 0 kJ + 11.1 kJ = 15.1 kJ.
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Simulate a blackbody spectrum of temperature 1700 Kelvin. Determine the peak wavelength in 3.22 nanometers of an object of that temperature nanometers What is the emissive intensity of the object
a) The peak wavelength in 3.22 nanometers of an object is 345 nanometre, b) the emissive intensity of the object is 2.82 * 10⁸ W/m².
The relationship between the temperature,T and the peak wavelength, [tex]\lambda[/tex] emitted by a black body is given by wien's displacement law:
[tex]\lambda[/tex] = b / T
Where, b is a constant and it's value is 2.898 * 10-3 m-K
Given: T = 8400 K
So, [tex]\lambda[/tex] = (2.898 * 10-3 )/8400
\lambda = 3.45 * 10-7
\lambda = 345 nm
Hence, the peak wavelength of the object at this temperature is 345 nanometre.
The amount of power emitted per unit area, P is given by Stefan Boltzmann law:
P =[tex]\sigma[/tex]T⁴
Where,
Absolute temperature, T = 8400 K
Stefan Boltzmann constant, [tex]\sigma[/tex] = 5.67 * 10-8 W/m²K⁴
So, P = 5.67 * 10-8 * (8400)⁴
P = 2.82 * 10⁸ W/m²
Hence, the power emitted per unit area is 2.82 * 10⁸ W/m².
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A child is riding on a merry go round. As the speed of the merry go round is doubled, the magnitude of the centripetal force acting on the childa. Remains the sameb. Is quadrupledc. Is doubledd. Is halved
A youngster is on a merry-go-round. The centripetal force acting on the toddler is quadrupled as the merry-go-speed round's is doubled. So, option B is correct.
What is centripetal force?
Centripetal force is a term used to describe a force that moves a body along a curved path. The centripetal force is always applied in the general direction of the path's instantaneous center of curvature and against the motion of the subject. According to Isaac Newton, it is "a force by which bodies are dragged or forced, or in any other way gravitate, towards a point as to a center." Gravity is the centripetal force that generates astronomical orbits, according to Newtonian mechanics theory.
As, the formula of Centripetal force,
[tex]F=\frac{mv^2}{r}[/tex],
We can see that, F is directly proportional to [tex]v^{2}[/tex], When the speed of the merry-go-round is doubled, the centripetal force acting on the child is multiplied by four.
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what is the difference in mechanical energy from point A to point C below?
Answer:
their speed maybe cause of the ups and downs
A 25kg turkey is fired from a 1.2x10^3 kg turkey launcher. If the horizontal velocity of the turkey is 245m/s east, what is the recoil of the launcher? A.) 9.38 m/s B.) 7325 m/s C.) 4925 m/s D.) 5.1 m/s
Answer:
Explanation:
A
In which collision(s) is momentum conserved?
A.Elastic
B.Inelastic
C.Perfectly inelastic
Momentum is conserved in both elastic and perfectly inelastic collisions.
In an elastic collision, the total momentum of the colliding objects is conserved before and after the collision. This means that the sum of the momentum of the objects before the collision is equal to the sum of the momentum of the objects after the collision.
In a perfectly inelastic collision, the two objects stick together after the collision, forming a single object with new momentum. In this case, the total momentum of the system is also conserved.
However, in an inelastic collision, momentum is not conserved, as some of the momenta are transformed into other forms of energy, such as heat or sound. This means that the total momentum of the objects before the collision is not equal to the total momentum of the objects after the collision.
Answer:
Explanation:
A
Which of these is an example of acceleration?
Answer:
a bus triveling north at 25m/s
A moving object has
kinetic energy
velocity.
speed.
all of these
It has all of these. everything has kinetic energy, it is moving so it will have both speed and velocity as well.
A charged particle is located 1 meter away from a charged sphere and experiences a force of -0.5 N. If the distance is decreased to 0.5 meter, which of the following would be correct?
A. The force would be one-fourth the original force.
B. The force would be one-half the original force.
C. The force would be two times greater.
D. The force would be four times greater.
Answer: the correct answer is A
Explanation: the correct answer is A. The force would be one-fourth the original force.
You use a ruler marked with 1 mm increments to measure the lengths of the height h of a block and find h = 121 mm. According to the half least count rule, what is the uncertainty in your measurement of the height?
The uncertainty in height is, 0.5 mm.
The "half least count rule" states that the uncertainty in a measurement is equal to half of the smallest division on the measuring instrument. In this case, the ruler is marked in 1 mm increments, so the smallest division is 1 mm.
Using the half least count rule, the uncertainty in the measurement of the height is,
uncertainty = 1/2 * 1 mm = 0.5 mm
Therefore, the uncertainty in the measurement of the height is 0.5 mm. We can express the result as,
h = 121 ± 0.5 mm
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block and sphere are connected by a cord that passes over a pulley, as shown. Neglect friction and assume the cord is massless,
m1= 2.00 kg,
m2= 540 kg, and θ= 49.0∘.
What is the tension (in N) in the cord?
Tension is a force along the length of a medium, especially a force carried by a flexible medium, such as a rope or cable.
The tension in the cord is approximately 10624 N.
To solve this problem, we can use the principles of Newton's laws and apply them to each of the objects involved. We will also use the fact that the tension in the cord is the same on both sides of the pulley (neglecting any friction or mass in the pulley).
First, we can consider the forces acting on the block (m1). The only forces acting on the block are its weight (mg) and the tension in the cord (T), which is directed upward. We can resolve these forces into components parallel and perpendicular to the inclined plane:
The weight of the block has a component parallel to the inclined plane given by [tex]mg*sin(θ)[/tex].
The tension in the cord has a component parallel to the inclined plane given by [tex]T*sin(θ)[/tex].
Using Newton's second law, we can write:
[tex]m1 * a = T * sin(θ) - m1 * g * sin(θ)[/tex]
where a is the acceleration of the block down the inclined plane.
Next, we can consider the forces acting on the sphere ([tex]m2[/tex]). Since the sphere is hanging from the cord, the only force acting on it is its weight ([tex]mg[/tex]), which is directed downward. Using Newton's second law, we can write:
[tex]m2 * a = m2 * g - T[/tex]
where a is the acceleration of the sphere downward.
Since the cord is assumed to be massless and the pulley is assumed to be frictionless, the tension in the cord is the same on both sides of the pulley. Therefore, we can set the two expressions for T equal to each other:
[tex]T * sin(θ) - m1 * g * sin(θ) = m2 * g - T[/tex]
Solving for T, we get:
T = [tex](m2 + m1) * g / (sin(θ) + 1)[/tex]
Substituting the given values, we get:
T = [tex](540 kg + 2.00 kg) * 9.81 m/s^2 / (sin(49.0°) + 1)[/tex]
T = 10624 N (to three significant figures)
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