In this challenge you will use the file regex_replace_challenge_student.py to:
Write a regular expression that will replace all occurrences of:
regular-expression
regular:expression
regular&expression
In the string: This is a string to search for a regular expression like regular expression or regular-expression or regular:expression or regular&expression
Assign the regular expression to a variable named pattern
Using the sub() method from the re package substitute all occurrences of the 'pattern' with 'substitution'
Assign the outcome of the sub() method to a variable called replace_result
Output to the console replace_results
Regular Expression Replace Challenge
The Python statement containing the string to search for the regular expression occurrence is below. search_string=’’’This is a string to search for a regular expression like regular expression or regular-expression or regular:expression or regular&expression’’’
Write a regular expression that will find all occurrences of:
a. regular expression
b. regular-expression
c. regular:expression
d. regular&expression in search_string
Assign the regular expression to a variable named pattern
The Python string below is used for substitution substitution="regular expression"
Using the sub() method from the re package substitute all occurrences of the ‘pattern’ with ‘substitution’
Assign the outcome of the sub() method to a variable called replace_result
Output to the console replace_results
import re
#The string to search for the regular expression occurrence (This is provided to the student)
search_string='''This is a string to search for a regular expression like regular expression or
regular-expression or regular:expression or regular&expression'''
#1. Write a regular expression that will find all occurrances of:
# a. regular expression
# b. regular-expression
# c. regular:expression
# d. regular&expression
# in search_string
#2. Assign the regular expression to a variable named pattern
#The string to use for subsitution (This is provided to the student)
substitution="regular expression"
#3. Using the sub() method from the re package substitute all occurrences of the 'pattern' with 'substitution'
#4. Assign the outcome of the sub() method to a variable called replace_result
#5. Output to the console replace_results

Answer:

C. Resource Pool share value.

Explanation:

The vSphere is a term used to describe the VMware’s virtualization cloud platform. The vSphere comprises of the following, vCenter Server, ESXi, Virtual Machine File System (VMFS) and vCenter Client.

If a vSphere Administrator receive complaints that a database Virtual Machine (VM) is experiencing performance issues and the Virtual Machine (VM) is a member of the high priority resource pool and the cluster has not experienced contention.

In order to address immediate performance concerns, the vSphere Administrator should check the Resource Pool share value.

VMware resource pool refers to the aggregated central processing unit and memory allocated to a Virtual Machine (VM) for flexible management of the resources.

Also, the vSphere Administrator should install VMware tools to check which processes are having high CPU usage by using vimtop, as well as checking if vCenter Server is swapping.

Answer:

The csharp program is given below.

using System;

using System.Collections.Generic;

using System.ComponentModel;

using System.Data;

using System.Drawing;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.Windows.Forms;

namespace WindowsFormsApplication1

{

   public partial class Form1 : Form

   {

       public Form1()

       {

           InitializeComponent();

      }

       private void button6_Click(object sender, EventArgs e)

       {

           int total = (Convert.ToInt32(textBox1.Text) +  Convert.ToInt32(textBox2.Text) + Convert.ToInt32(textBox3.Text) + Convert.ToInt32(textBox4.Text) + Convert.ToInt32(textBox5.Text));

           int dozen = total / 12;

           int eggs = total % 12;

           textBox6.Text = dozen.ToString();

           textBox7.Text = eggs.ToString();

       }

       private void button7_Click(object sender, EventArgs e)

       {

           textBox1.Text = "";

           textBox2.Text = "";

           textBox3.Text = "";

           textBox4.Text = "";

           textBox5.Text = "";

           textBox6.Text = "";

           textBox7.Text = "";

       }

        private void button8_Click(object sender, EventArgs e)

       {

           Close();

       }

    }

}

Explanation:

1. The integer variables are declared for total eggs, number of dozens and number of eggs.

2. The input of each text box is converted into integer by using the Convert.ToInt32() method on the value of that particular text box.

3. All the inputs are added and the sum is assigned to variable, total.

4. The number of dozens are obtained by dividing total by 12 and assigning the value to the variable, dozen.

5. The number of extra eggs are obtained by taking the modulus of total and 12 and the value is assigned to the variable, eggs.

6. The integer values in the variables, dozen and eggs, are converted into string using the ToString() function with that particular value.

dozen.ToString();

eggs.ToString();

7. The text boxes are assigned the respective values of dozens and number of eggs.

textBox6.Text = dozen.ToString();

textBox7.Text = eggs.ToString();

8. Two additional buttons, clear and exit, are also added.

9. The clear button erases the contents of all the text boxes. The Text property of each textbox is set to “” thereby clearing all the text fields.

10. The exit button closes the application using Close() function.

11. The program is made in visual studio and the output is attached.

Answer:

There's nothing wrong with the question you posted except that it's not well presented or arranged.

When properly formatted, the program will be error free and it'll run properly.

The programming language used in the question is Java programming lamguage.

in java, the sign ";" signifies the end of each line and lines that begins with // represent comments. Using this understanding of end of lines and comments, the formatted code goes thus

import java.util.Scanner;  

public class Arraysum {  

public static void main(String[] args) {  

Scanner scnr = new Scanner(System.in);  

final int NUM_ELEMENTS = 8;

// Number of elements  

int[] userVals = new int[NUM_ELEMENTS];  

// User numbers  

int i = 0;  

// Loop index  

int sumVal = 0;  

// For computing sum  

// Prompt user to populate array  

System.out.println("Enter " + NUM_ELEMENTS + " integer values...");  

for (i = 0; i < NUM_ELEMENTS; ++i) {  

System.out.print("Value: ");  

userVals[i] = scnr.nextInt();  

}  

// Determine sum  

sumVal = 0;

for (i = 0; i < NUM_ELEMENTS; ++i)

{

sumVal = sumVal + userVals[i];

}

System.out.println("Sum: " + sumVal); return;

}

}

Also, see attachment for source file

Answer: Provided in the explanation section

Explanation:

C++ Code

#include<iostream>

#include<fstream>

#include<string>

using namespace std;

// read plain text from file

void readPlaneText(char *file,char *txt,int &size){

  ifstream inp;

  inp.open(file);

  // index initialize to 0 for first character

  int index=0;

  char ch;

  if(!inp.fail()){

      // read each character from file  

      while(!inp.eof()){

          inp.get(ch);

          txt[index++]=ch;

      }

  }

  // size of message

  size=index-1;

}

// read key

int **readKey(char *file,int **key,int &size){

  ifstream ink;

  //

  ink.open(file);

      if(!ink.fail()){

          // read first line as size

      ink>>size;

      // create 2 d arry

      key=new int*[size];

      for(int i=0;i<size;i++){

          key[i]=new int[size];

      }

      // read data in 2d matrix

      for(int i=0;i<size;i++){

          for(int j=0;j<size;j++){

              ink>>key[i][j];

          }  

      }

  }

  return key;

}

// print message

void printText(string txt,char *msg,int size){

  cout<<txt<<":\n\n";

  for(int i=0;i<size;i++){

      cout<<msg[i];

  }

}

// print key

void printKey(int **key,int size){

  cout<<"\n\nKey matrix:\n\n";

  for(int i=0;i<size;i++){

      for(int j=0;j<size;j++){

          cout<<key[i][j]<<" ";

      }  

      cout<<endl;

  }

}

void encrypt(char *txt,int size,int **key,int kSize,char *ctxt){

  int *data=new int[kSize];

  for(int i=0;i<size;i=i+kSize){  

  // read key size concecutive data

      for(int a=0;a<kSize;a++){

          data[a]=txt[i+a]-'a';

      }

      // cipher operation

      for(int a=0;a<kSize;a++){

          int total=0;

          for(int b=0;b<kSize;b++){

              total+=key[a][b]*data[b];

          }  

          total=total%26;

          ctxt[i+a]=(char)('a'+total);

      }      

  }

}

int main(int argc,char **argv){

  char text[10000];

  char ctext[10000];

  int **key;

  int keySize;

  int size;

  // input

  key=readKey(argv[1],key,keySize);

  readPlaneText(argv[2],text,size);

  encrypt(text,size,key,keySize,ctext);

  // output

  printKey(key,keySize);

  cout<<endl<<endl;

  printText("Plaintext",text,size);

  cout<<endl<<endl;

  printText("Ciphertext",ctext,size);

  return 0;

}

cheers i hope this helped !!!

Answer:

Replace /* Your solution goes here */  with the following lines of code

for(i = 0;i<SCORES_SIZE-1;i++)

{

bonusScores[i]+=bonusScores[i+1];

}

Explanation:

The above iteration starts from the index element (element at 0) and stops at the second to the last element (last - 1).

Using an iterative variable, i

It adds the current element (element at i) with the next element; element at i + 1.

The full code becomes

#include<iostream>

using namespace std;

int main(void) {

const int SCORES_SIZE = 4;

int bonusScores[SCORES_SIZE];

int i = 0;

bonusScores[0] = 10;

bonusScores[1] = 20;

bonusScores[2] = 30;

bonusScores[3] = 40;

for(i = 0;i<SCORES_SIZE-1;i++)

{

bonusScores[i]+=bonusScores[i+1];

}

/* Your solution goes here */

for (i = 0; i < SCORES_SIZE; ++i) {

printf("%d ", bonusScores[i]);

}

printf("\n");

return 0;

}

See attachment for .cpp file

Answer:int main() {

const int SCORES_SIZE = 4;

int bonusScores[SCORES_SIZE];

int i;

for (i = 0; i < SCORES_SIZE; ++i) {

cin >> bonusScores[i];

}

for (i = 0; i < SCORES_SIZE-1; ++i){

bonusScores[i] += bonusScores[i+1];

}

for (i = 0; i < SCORES_SIZE; ++i) {

cout << bonusScores[i] << " ";

}

cout << endl;

return 0;

}

Explanation: SCORES_SIZE -1 will prevent the for loop from going past the last value in the array. bonusScores[i] += will add the value of bonusScores[i+1] to the original bonusScores[i].

for example, i = 1; 1 < SCORES_SIZE - 1 ; bonusScores[1] += bonusScores[1+1} becomes{ bonusScores[1] + bonusScores{2];

Answer:

b. Try to convince the owner of the computer to give you to decryption key/password.

Explanation:

Encrypted hard drives have maximum security and high data protection. to access them you need to enter a password to unlock them.

The image filtering technique is a method that serves to selectively highlight information contained in an image, for which it does not work.

The encryption algorithm is a component used for the security of electronic data transport, not to access data on an encrypted hard drive.

The encryption key is used in encryption algorithms to transform a message and cannot be exposed by disconnecting the hard drive from its power source.

Answer:

Full back up

It creates complete copy of the source of data. This feature made it to the best  back  up with good speed of recovery of the data and  simplicity.However, because it  is needed for backing up  of  a lot of data, it is time consuming process,Besides it also  disturbs the routine application of  the technologist infrastructure. In addition large capacity storage is needed  for the  storage of  the large volume of back up with each new creation.

Incremental back up: back up work at high speed thus saves time, Little storage capacity is needed. This type of back up can be run as  many time as wished.

However, the restoration of data takes time, due to the time spent for restoration of initial back up and the incremental.

Differential Back up has very fast back up operation, because it only requires two pieces of back up.This is however slower compare to the Incremental.

The selective back up enable selection of certain type of file or folders for back up.

it can only be used to back up folders only when important data  are needed only.Thus the  storage capacity is low.

CPD eliminates back up window and reduces the recovery point objective.However, it has issue of compatibility with the resources to back up.,it is also expensive because its solutions are disk based.

Cloud based is affordable and save cost,It is easier to access. it is efficient,it can be access remotely for convenience.

However, Internet sources and some bandwidth must be available for access., always depends on third party providers,There is also problems encountered when switching providers.

Explanation:

Answer:

I think that they should ban ads for all four products.  These products, e-cigarettes, abortion clinics, ice cream, and sugared soft drinks, are all discreet adult products that should not be advertised because of their health hazards.  Since the "large online company provides a widely used search engine, social network, and/or news service, which are mainly patronized by younger people, such ads that promote products injurious to individual health should be banned.  Those who really need or want these products know where they could get them.  Therefore, the products should not be made easily accessible to all people.  Nor, should ads promote their patronage among the general population.

Explanation:

Advertisements create lasting and powerful images which glamourize some products, thereby causing the general population, especially children, to want to consume them without any discrimination of their health implications.  If online banning is then contemplated, there should not be any distinguishing among the four products: e-cigarettes, abortion clinics, ice cream, and sugared soft drinks.

Answer:

Here is the function unzip:

def unzip(lst):

   result= zip(*lst)

   return list(result)

The complete program in Python is given below:

def unzip(lst):

   result= zip(*lst)

   return list(result)

lst =[(1, "one"), (2, "two"), (3, "three")]

tup= unzip(lst)

print(tup)

Explanation:

Here zip() function is used in the unzip function. The return type of zip() function is a zip object. This means the function returns the iterator of tuples. This function can be used as its own inverse by using the * operator.

If you do not want to use zip() function then the above program can also be implemented as following which uses a for loop for elements in the given list (lst). This can make a pair of lists (2 tuple) instead of list of tuples:

def unzip(lst):

   output = ([ a for a,b in lst ], [ b for a,b in lst ])

   return output

lst =[(1, "one"), (2, "two"), (3, "three")]  

tup= unzip(lst)  

print(tup)

The programs along with their output are attached.

Answer:

This program is written using python

It uses less comments (See explanation section for more explanation)

Also, see attachments for proper view of the source code

Program starts here

#Prompt user for price of package 1

price1 = int(input("Enter Price 1: "))

while(price1 <= 0):

     price1 = int(input("Enter Price 1: "))

#Prompt user for weight of package 1

weight1 = int(input("Enter Weight 1: "))

while(weight1 <= 0):

     weight1 = int(input("Enter Weight 1: "))

#Calculate Unit of Package 1

unit1 = float(price1/weight1)

print("Unit cost of Package 1: "+str(unit1))

#Prompt user for price of package 2

price2 = int(input("Enter Price 2: "))

while(price2 <= 0):

     price2 = int(input("Enter Price 2: "))

#Prompt user for weight of package 2

weight2 = int(input("Enter Weight 2: "))

while(weight2 <= 0):

     weight2 = int(input("Enter Weight 2: "))

#Calculate Unit of Package 2

unit2 = float(price2/weight2)

print("Unit cost of Package 2: "+str(unit2))

#Compare units

if unit1 > unit2:

     print("Package 1 has a better price")

elif unit1 == unit2:

     print("Both Packages have the same price")

else:

     print("Package 2 has a better price")

Explanation:

price1 = int(input("Enter Price 1: ")) -> This line prompts the user for price of package 1

The following while statement is executed until user inputs a value greater than 1 for price

while(price1 <= 0):

     price1 = int(input("Enter Price 1: "))

weight1 = int(input("Enter Weight 1: ")) -> This line prompts the user for weight of package 1

The following while statement is executed until user inputs a value greater than 1 for weight

while(weight1 <= 0):

     weight1 = int(input("Enter Weight 1: "))

unit1 = float(price1/weight1) -> This line calculates the unit cost (per weight) of package 1

print("Unit cost of Package 1: "+str(unit1)) -> The unit cost of package 1 is printed using this print statement

price2 = int(input("Enter Price 2: ")) -> This line prompts the user for price of package 2

The following while statement is executed until user inputs a value greater than 1 for price

while(price2 <= 0):

     price2 = int(input("Enter Price 2: "))

weight2 = int(input("Enter Weight 2: ")) -> This line prompts the user for weight of package 2

The following while statement is executed until user inputs a value greater than 1 for weight

while(weight2 <= 0):

     weight2 = int(input("Enter Weight 2: "))

unit2 = float(price2/weight) -> This line calculates the unit cost (per weight) of package 2

print("Unit cost of Package 2: "+str(unit2)) -> The unit cost of package 2 is printed using this print statement

The following if statements compares and prints which package has a better unit cost

if unit1 > unit2:

     print("Package 1 has a better price")

elif unit1 == unit2:

     print("Both Packages have the same price")

else:

     print("Package 2 has a better price")

Answer:

one-sided looking

Explanation:

Larry purposely looks away

Answer:

The programming language is not stater; However, I'll answer this question using C++.

This program does not use comments (See explanation)

See Attachment for program file

Program starts here

#include <iostream>

using namespace std;

int main()

{

string response;

cout<<"What kind of swallow?\n";

cin>>response;

for(int i =0; i<response.length();i++)

{

 response[i]=toupper(response[i]);

}

   if(response == "AFRICAN")

   {

    cout<<"Yes, it could grip it by the husk.";

}

else if(response == "EUROPEAN")

   {

    cout<<"A five-ounce bird could not carry a one-pound coconut.";

}

else

{

 cout<<"You really are not fit to be a king.";

}

   return 0;

}

Explanation:

string response; -> A string variable to hold user input is declared

cout<<"What kind of swallow?\n"; -> prompts user for input

cin>>response; -> user input is stored here

The following iteration converts user input to uppercase; so that the program will work for inputs like African, AFRICAN, AFriCAN, etc.

for(int i =0; i<response.length();i++)

{

 response[i]=toupper(response[i]);

}

The following if statement prints "Yes, it could grip it by the husk." if user input is AFRICAN

   if(response == "AFRICAN")

   {

    cout<<"Yes, it could grip it by the husk.";

}

Otherwise, if user input is EUROPEAN, it prints; "A five-ounce bird could not carry a one-pound coconut."

else if(response == "EUROPEAN")

   {

    cout<<"A five-ounce bird could not carry a one-pound coconut.";

}

Lastly; for every inputs different from AFRICAN and EUROPEAN, the program displays "You really are not fit to be a king."

else

{

 cout<<"You really are not fit to be a king.";

}

Answer:

Web pages with personal or biographic information are called. a. Social Networking sites. c.

Explanation:

Camera and Mic

These 2 things are the most likely things to get you in trouble. Unless you have a 100% protected device, and honestly even if you do, cover up the camera and close your mic. This will definitely save you later.

Answer:

Brute force is  technique that is used for cracking password

In this case the system uses only three characters(0-9). By applying Brute force attack in "hit and try" manner we easily crack the password.

Explanation:

Solution

There are a wide variety of password cracking mechanisms.Brute force is one of the popular password cracking technique.Brute force attack is generally used to crack small passwords.

In the given example the system uses only three characters(0-9).By using Brute force attack in "hit and try" manner we easily crack the password.There are only 10 possible passwords for this type of system.Because we can arrange 0-9 only in 10 ways.But for Systems with long passwords it is difficult to find it in hit and try manner.But instead of having plain password each password have a random salt value.

In a system of 32 bit salt value there are 2^32 different key values.

By increasing the salt value from 32 bits to 64 bits there are 2^64 different key values.It increases the time taken to crack a password for an attacker.so by changing salt value from 32 to 64 bits will make it more harder for the adversary's attack to be successful.

Answer:

CASE tools reduce the need for end user participation in systems development.

Explanation:

CASE is an acronym for Computer-aided Software Engineering and it comprises of software application tools that provide users with automated assistance for Software Development Life Cycle (planning, analysing, designing, testing, implementation and maintenance). The CASE tools helps software developers in reducing or cutting down of the cost and time of software development, as well as the enhancement of the software quality.

Some other benefits of using the CASE tools are;

- CASE tools provide automated graphics facilities for producing charts.

- CASE tools have capabilities for validating design diagrams and specifications.

- CASE tools support collaboration among team members.

- CASE tools facilitate the creation of clear documentation.

- CASE tools checks for consistency, syntax errors and completeness.

The CASE tools can be grouped as, requirement and structure analysis, software design, test-case and code generation, reverse engineering, and document production tools.

Examples of CASE tools are flowchart maker, visible analyst (VA), dreamweaver, net-beans, microsoft visio, adobe illustrator and photoshop etc.

Answer:

import java.util.*;

public class Grade {

   public static void main(String[] args) {

       Scanner input = new Scanner(System.in);

       double[] grades =  new double[4];

       for (int i=0; i<4; i++){

           System.out.print("Enter a grade: ");

           grades[i] = input.nextDouble();

       }

       double lowest = grades[0];

       double highest = grades[0];

       double total = 0;

       for (int i=0; i<4; i++){

           System.out.println("Grade " + (i+1) + " is: "  + grades[i]);

           if(grades[i] >= highest)

               highest = grades[i];

           if(grades[i] <= lowest)

               lowest = grades[i];

           total += grades[i];

       }

       double average = total/4;

       System.out.println("The highest grade is: " + highest);

       System.out.println("The lowest grade is: " + lowest);

       System.out.println("The average is: " + average);

  }

}

Explanation:

Ask the user for the grades and put them in the grades array using a for loop

Create another for loop. Inside the loop, print the grades. Find highest and lowest grades in the grades array using if-structure. Also, add each grade to the total.

When the loop is done, calculate the average, divide the total by 4.

Print the highest grade, lowest grade and average.

Philosophy, I beleive. He tought Sikander liturature and eloquence, but his most famous teachings were of philosophy.

Aristotle taught the world science. He was considered the best scientists of his time.

Answer:

B - The user is no longer able to log on to the network

Explanation:

Answer:

change bullets to numbers

Explanation:

100%

Answer: Provided in the explanation section

Explanation:

import java.util.Scanner;

public class commission

{

   public static void main(String[] args) {

      Scanner input = new Scanner(System.in);

        int totals[]={0,0,0,0,0,0,0,0,0};          

      int n,sales,i,index;

       double salary;

        System.out.print("how many salesmen do you have? ");                          

      n=input.nextInt();

        for(i=1;i<=n;i++)

           {System.out.print("Salesman "+i+" enter sales: ");

            sales=input.nextInt();

            salary=200+(int)(.09*sales);

               System.out.printf("Salary=$%.2f\n",salary);

            index=(int)salary/100-2;

            if(index>8)

                index=8;

            totals[index]++;

            }

        System.out.println("SUMMARY\nSALES\t\tCOUNT");

        for(i=0;i<8;i++)

           System.out.println("$"+(i*100+200)+"-"+(i*100+299)+"\t"+totals[i]);

        System.out.println("$1000 and over\t"+totals[i]);

       }                                

   }

cheers i  hope this helped !!      

Answer:

weight1 = float(input("Enter the weight of first package: "))

price1 = float(input("Enter the price of first package: "))

weight2 = float(input("Enter the weight of second package: "))

price2 = float(input("Enter the price of second package: "))

if weight1 > 0 and price1 > 0 and weight2 > 0 and price2 > 0:

   unit_cost1 = price1 / weight1

   unit_cost2 = price2 / weight2

   if unit_cost1 < unit_cost2:

       print("Package 1 has a better price.")

   else:

       print("Package 2 has a better price.")

else:

   print("All the entered values must be positive!")

Explanation:

*The code is in Python.

Ask the user to enter the weight and the price of the packages

Check if the all the values are greater than 0. If they are, calculate the unit price of the packages, divide the prices by weights. Then, compare the unit prices. The package with a smaller unit price has a better price.

If all the entered values are not greater than 0, print a warning message

Answer:

Explanation:

public class Team {

   private String teamName;

   private int teamWins;

   private int teamLosses;

   public String getTeamName() {

       return teamName;

   }

   public void setTeamName(String teamName) {

       this.teamName = teamName;

   }

   public int getTeamWins() {

       return teamWins;

   }

   public void setTeamWins(int teamWins) {

       this.teamWins = teamWins;

   }

   public int getTeamLosses() {

       return teamLosses;

   }

   public void setTeamLosses(int teamLosses) {

       this.teamLosses = teamLosses;

   }

   public double getWinPercentage() {

       return teamWins / (double) (teamWins + teamLosses);

   }

}

Following are the Java program to define the Team class and calculate its  value:

class Team //defining the class Team

{

   private String teamName;//defining String variable

   private int teamWins, teamLosses;//defining integer variable

   //defining the set method to set value the input value

   public void setTeamName(String teamName)//defining setTeamName method that takes one String parameter

   {

       this.teamName = teamName;//using this keyword that sets value in teamName

   }

   public void setTeamWins(int teamWins) //defining setTeamWins method that takes one integer parameter

   {

       this.teamWins = teamWins;//using this keyword that sets value in teamWins

   }

   public void setTeamLosses(int teamLosses)//defining setTeamLosses method that takes one integer parameter

   {

       this.teamLosses = teamLosses;//using this keyword that sets value in teamLosses

   }

   //defining the get method that returns the input value

   public String getTeamName() //defining getTeamName method

   {

       return teamName;//return teamName value

   }

   public int getTeamWins()  //defining getTeamWins method

   {

       return teamWins;//return teamWins value

   }

   public int getTeamLosses() //defining getTeamLosses method

   {

       return teamLosses;//return teamLosses value

   }

   public double getWinPercentage()//defining getWinPercentage method

   {              

       return ((teamWins * 1.0) / (teamWins + teamLosses));//using the return keyword that returns percentage value

   }      

}

Please find the complete code in the attached file and its output file in the attached file.

Class definition:

Find out more about the Class here:

brainly.com/question/17001900

Answer:

Many-to-one (multiple inputs, single output)

Explanation:

Solution

In the case of a recurrent neural network that listens to a audio speech sample, and classifies it according to whose voice it is, the RNN will listen to the audio and will give result by doing classification.

There will be a single output, for the classified or say identified person.

The RNN will take a stream of input as the input is a audio speech sample.

Therefore, there will be multiple inputs to the RNN and a single output, making the best fit Architecture to be of type Many-to-one(multiple inputs, single output).

Answer:

Explanation:

The objective here is to determine if the programmer can simply increase the upperbound to 80,000.

Of course Yes, The programmer can simply increase the delay by doubling the upperbound by 80000. The representation can be illustrated as:

( int : i = 0;  i <  40,000; i ++ )

{

  // delay code

}

Which can be modified as:

( int : i = 0;  i <  80,000; i ++ )

{

  // delay code

}

b)  If the code contains a delay loop and we noticed that no delay is being created at run-time. What should we suspect during debugging?

Assuming there is no delay being created at the run-time,

The code is illustrated as:

For ( int : i = 0 ; i < 0 ; i ++ )

{

  // delay code which wont

  //execute since code delay is zero

}

we ought to check whether the loop is being satisfied or not.  At the Initial value of loop variable, is there any break or exit statement is being executed in between loop. Thus, the  aforementioned delay loop wont be executed since the loop wont be executed for any value of i.

Answer:

1. The solution to question 1 is as follows;

srand(seedVal);

cout<<rand()%10<<endl;

cout<<rand()%10<<endl;

2. The solution to question 2 is as follows

cout<<100+rand()%50 <<endl;

cout<<100+rand()%50 <<endl;

Explanation:

The general syntax to generate random number between interval is

Random Number = Lower Limit + rand() % (Upper Limit - Lower Limit + 1)

In 1;

The solution starts by calling srand(seedVal);

The next two statements is explained as follows

To print two random integers between intervals of 0 and 9 using rand()"

Here, the lower limit = 0

the upper limit =  9

By substituting these values in the formula above; the random number will be generated as thus;

Random Number = 0 + rand() % (9 - 0 + 1)

Random Number = 0 + rand() % (10)

Random Number = rand() % (10)

So, the instruction to generate the two random variables is rand() % (10)

2.

Similar to 1 above

To print two random integers between intervals of 100 and 149 using rand()"

Here, the lower limit = 100

upper limit = 149

By substituting these values in the formula above; the random number will be generated as thus;

Random Number = 100 + rand() % (149 - 100 + 1)

Random Number = 100 + rand() % (50)

So, the instruction to generate the two random variables is 100 + rand() % (50)

Answer:

1  

def dict_intersect(d1,d2): #create dictionary

  d3={} #dictionaries

  for key1,value1 in d1.items():       #iterate through the loop  

      if key1 in d2:   #checking condition

          d3[key1]=(d1[key1],d2[key1])   #add the items into the dictionary  

  return d 3

print(dict_intersect({'a': 'apple', 'b': 'banana'}, {'b': 'bee', 'c': 'cat'})) #display

2

def consolidate(*l1):  #create consolidate

  d3={} # create dictionary

  for k in l1:       #iterate through the loop

      for number in k:   #iterate through  the loop                               d3[number]=d3.get(number,0)+1   #increment the value

             return d 3 #return

print(consolidate([1,2,3], [1,1,1], [2,4], [1])) #display

Explanation:

1

Following are  the description of program

2

Following are  the description of program