The output force increases by a factor of F2 = 14, 148. 207 N.
Solution:
To find fr let's plug in the value of Fr, Yi¹ Ye in Og f¹
825/(8.51)² = f₂/(33.6)²
F2 = 14, 148. 207 N
The force which is applied to an object by another object. A person pushing a barrel is an example of applied force. When the person pushes the barrel then there is an applied force acting upon the barrel. An applied force is a force that is applied to an object by a person or another object.
If a person is pushing a desk across the room then there is an applied force acting upon the object. The applied force is the force exerted on the desk by the person. Applied forces can be broadly divided into two types: contact and non-contact forces. Contact forces are those where the interaction between two or more objects occurs while the objects are in physical contact, whereas non-contact forces exist between objects that are not in physical contact.
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1 how much work must denise do to drag her basket of laundry of mass 5.0kg a distance of 5.0 m along a floor, if the forse she exerts is a constant 30.0 n at an angle of 60.0 degrees with the horizontal?
The amount of work done by denise to drag her basket of laundry of mass 5 kg is 75 J.
Work is defined as the product of distance and force.
To calculate the amount of work done by denise to drag the basket, we use the formula below.
W = Fd cosθ
where, W is the work done by the denise
F is the force applied to the basket
d is the distance
θ is the angle made with the horizontal
Given that, F = 30 N
d = 5 m
θ = 60°
Substituting the values in the above equation,
W = 30* 5* cos 60° = 75 J
Thus, work done by the denise is 75J.
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a 75 kg road bicycle racer rides down the highway from pikes peak. during one stretch of the ride, he descends 5 meters in 12.5 seconds, while accelerating from 35 km/hr to 55 km/hr. assuming rotational kinetic energy and dissipative forces to be negligible, what average power is supplied by the gravitational force during this time?
The average power supplied by the gravitational force during this time is 21717 Watt.
The mass of the road bicycle racer riding down the highway is 75kg.
The height through which he descends is 5 meters and the time taken by it is 12.5 seconds, the initial velocity of the bicycle is 35km/h(9.7m/s) and the final velocity of the bicycle is 55 km/h(15.27m/s).
The acceleration applied due to earth on the bicycle can be found as,
V²-U² = 2aS
V is the final velocity,
U is the initial velocity,
a is the acceleration created due to earth,
s is the height of the bicycle.
Putting values,
(15.27)²-(9.7)² = 2(a)(5)
a = 13.9m/s².
Now, the work done by the earth on the bicycle is,
W = 75(13.9)(5)
W = 267712.5 Joules.
The power supplied = Work done/time
Power supplied = 21717 Watt.
So, the power supplied by earth is 21717 Watts.
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How can planetary scientists estimate the ages of the outflow channels and valley networks on mars?.
Planetary scientists estimate the ages of the outflow channels and valley networks on mars by craters
Due to impact of meteorite, volcanic activity, or an explosion , there occurs a depression at a certain area , that is called crater .
Ages of the outflow channel and valley network can be estimated by counting the number of impact craters. Because of the almost constant rate at which impacts have occurred in the solar system .
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how fast does water flow from a hole at the bottom of a very wide, 6.2- m -deep storage tank filled with water? ignore viscosity.
The speed of water flowing from a hole at the bottom of a very wide, 6.2- m -deep storage tank filled with water is 11.29 m / s
v = √ 2 g h
v = Speed of water
g = Acceleration due to gravity
h = Height
g = 9.8 m / s²
h = 6.2 m
v = √ 2 * 9.8 * 6.5
v = √ 127.4
v = 11.29 m / s
This is derived from an equation of motion,
v² = u² + 2 a s
v = Final velocity
u = Initial velocity
a = Acceleration
s = Distance
u = 0
v² = 2 a s
v = √ 2 a s
Therefore, the speed of water flowing from a hole at the bottom of a very wide, 6.2- m -deep storage tank filled with water is 11.29 m / s
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A body of mass M moving with velocity V collides head on with another body of mass 2M which is initially at rest. Determine the ratio of kinetic energy of colliding bodies before and after collision 
The ratio of kinetic energy of colliding bodies before and after collision is 9:1
What is kinetic energy?Kinetic energy refers to be the energy that an object possesses due to its motion. It is defined as the work required to accelerate a body of specified mass from rest to a specified velocity. After the body acquires this energy during acceleration, it retains this kinetic energy as long as the velocity does not change.
Kinetic energy of the body before collision (KE₁): ¹/₂ mv²
Velocity (v') after collision:
v' = [(m₁ - m₂)/(m₁ + m₂)] v
Since, m₁ = 2m
m₂ = m
Substitute the values in the formula:
v' = [m/3m]v
v' = v/3
Now, kinetic energy after collision (KE₂): ¹/₂ mv'²
= ¹/₂ m(v/3)²
= ¹/₂ m(v²/9)
Now the ratio of kinetic energies:
KE₁ / KE₂ = (¹/₂ mv²) / (¹/₂ m(v²/9))
KE₁ / KE₂ = 9/1
Or 9:1
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how much work must be done on a particle with a mass of m to accelerate it from rest to a speed of 0.089 c ? express your answer in terms of mc2 .
0.14 mc² work is done on a particle with a mass of m to accelerate it from rest to a speed of 0.089 c
Define kinetic energy.A particle or an item that is in motion has a sort of energy called kinetic energy. When an object undergoes work, which involves the transfer of energy, by exerting a net force, the object accelerates and thereby gains kinetic energy.
kinetic energy of mass particle: KE = mc²( γ- 1 )
here γ is Lorentz constant
γ = [tex]\frac{1}{\sqrt{1 - \frac{v}{c}^{2} } }[/tex]
γ = [tex]\frac{1}{\sqrt{1 - \frac{0.089c}{c}^{2} } }[/tex]
γ = 1.14
here,
particle start from rent so initial KE = 0
and final KE = mc²(1.14 - 1 )
final KE = 0.14mc²
so,
work done to increase speed of particle
W = final KE - initial KE
Work = 0.14 mc²
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A ball rolls across a table at a constant speed for 0.62 m. It then falls onto the floor. It takes the ball 0.35 seconds to cover the 0.62 m path, as shown in the drawing below. The table top is 1.2 meters above the floor. Find x the distance that the bail travels horizontally after it eaves the table top.
Answer:
Explanation:
Missing drawing!
. A stone is thrown from ground level vertically upwards with a velocity of 40 m/s.
Find the maximum height to which the stone rises and its total time of flight, neglecting
air resistance.
Explanation:
maximum height to which the stone can reach is 80 m
h=80
total distance = 2h
= 160 m
The total distance travelled by the stone would be the distance it covered while moving up and then the distance it covered while coming back down.
a resistor dissipates 1.5 w when it is connected to a battery with a potential difference of 12 v. what is the resistance of the resistor?
Answer:
96 Ω
Explanation:
Power = V^2 / R
1.5 = 12^2 / R
R = 12^2 / 1.5 = 96 Ω
when a 2.5 g penny is placed on a turntable rotating at 33 rpm (revolutions per minute), it is found that the farthest away from the center of the turntable that it can be located without slipping off is 10 cm. what is the coefficient of static friction between the penny and the surface of the turntable?
The coefficient of static friction between the penny and the durcae of the turntable is 11.9.
The mass of the penny on the turntable rotating at 33 rpm is 2.5 grams. The penny was found to be located at a distance of 10cm from the center of the turntable.
Now, friction force on the penny will be.
Fr = uW
W is the weight of the penny,
u is the coefficient of friction.
The centripetal force on the penny will be,
F = Mw²r
m is the mass of penny,
w is the angular speed,
r is the distance of the penny from the center.
Now, if the penny stops,
Fr = F
so, we can write,
uW = Mw²r
Putting values,
u(2.5 x 10) = 2.5 x (3.45)² x 0.10
u = 11.9
The value of the coefficient of static friction between the penny and the surface of the turntable is 11.9.
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A 1600kg car is traveling over a hill that has a radius of curvature of 25m. The car is slowing down as it goes over the hill. It slows down at a constant rate from a speed of 25ms to a speed of 10ms over a distance of 50m ending at the top of the hill. The net acceleration of the car at the top of the hill is most nearly.
The net acceleration of the car at the top of the hill is 6.6 m/s²
According to the question,
Mass of the car, m = 1600 Kg
Final speed of the car = 10 m/s
Distance covered by the car, d = 50 m
Radius of curvature of the hill, r = 25 m
Initial speed of the car, u = 25 m/s
The acceleration of the car is calculated by applying the third equation of motion,
v² = u² + 2as
where, v is the initial speed
u is the final speed and
a is the acceleration of the car
2as = v² - u²
a = [tex]\frac{v^{2-u^{2} } }{2a}[/tex]
a =[tex]\frac{10^{2}- 25^{2} }{2 X 50 }[/tex]
a = - 5.25 [tex]m/s^{2}[/tex]
The centripetal acceleration of the car at the top of the hill is given as,
[tex]a_{c} =\frac{v^{2} }{r\\}[/tex]
[tex]a_{c} =\frac{10^{2} }{25} \\a_{c = 4m/s^{2}[/tex]
The net acceleration of the car at the top of the hill is calculated as;
[tex]a_{net} = \sqrt{a^{2} } +a_{c^{} }[/tex]
[tex]a_{net} = \sqrt{-5.25} ^{2} - 4^{2}[/tex]
= 6.6[tex]m/s^{2}[/tex]
Thus, the net acceleration of the car at the top of the hill is 6.6 m/s²
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(q011) suppose you are studying a visible-light image of a distant galaxy, and you see a dark lane cutting across the bright disk. that dark line is most likely caused by
The reason some regions of the Milky Way's disk appear dark is because
stars in this direction are obscured by interstellar dust.
Astronomers have observed many different stars at each stage of their formation process. They have moved away from the Sun over the past 4.5 billion years. Location-to-location density variation increases as the cloud collapses. Once a protostar with a mass of less than 0.08 solar mass is formed, its internal temperature never reaches a sufficient level to initiate thermonuclear fusion. This quirky star is called a brown dwarf and sits between a planet (such as Jupiter) and a star. Coalsacks are clouds of interstellar dust about 600 light-years away that block light from the stars from reaching us. It is a type of celestial object called a dark nebula. The "inside" star that can be seen with binoculars is actually closer than the coal sack itself.
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predict how you think two inductors in series will act as an equivalent inductor. will they add together, add as 1/l or some other relationship?
The total inductance of inductors connected in series is equal to the sum of the inductances of the individual inductors.
Briefing:
The amount of voltage dropped across an inductor for a specific rate of current change through it is the undisputed indicator of inductance.
The total voltage reduced as a result of a change in current will be additive with each inductor if inductors are linked in series (sharing the same current and experiencing the same rate of change in current), resulting in a higher total voltage than either of the individual inductors alone. Greater inductance results from higher voltage at the same rate of current change.
As a result, the overall inductance of a series of inductors is greater than the sum of the inductances of each individual inductor. Similar to how series resistances are calculated, the series total inductance formula takes the same form:
L(total) = L1+L2+L3….Ln
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if the capacitor and inductor in part a are connected in an l-c circuit, what will be the resonance angular frequency of that circuit?
What is Angular frequency?
The length of time it takes an item to complete one oscillation is called the time period.The shortest angle an item makes when spinning in a circle from its starting location to its stopping position is known as the angular displacement.In other terms, you may say that it is the rate at which rotation changes or the pace at which changes in sinusoidal waves occur. It is the angular displacement of a wave element per unit of time. For instance, if you describe an object as having a high angular frequency, you are describing how quickly it turns. The size of the angular velocity is known as the angular frequency.However, it is a scalar quantity, meaning that it lacks direction.
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As you hold your leg in this position, the upper leg exerts a force on the lower leg at the knee joint. What is the magnitude of this force?
The upper leg applies the exact same amount of force on the knee as the tendon applies on the lower leg. f = 215.6 N
This is only logical as the net result of these forces is the canceling out and the leg staying stable in its position.
The magnitude of a force is how much it accelerates the object it acts on and is represented by a scalar. Size can also be viewed as a strength. Riding a bicycle is a simple example of force magnitude. It is a simple machine that converts human-supplied energy into kinetic energy.
The force exerted on the pedal results in the formation of energy. Work is done to convert this energy into kinetic energy and move the bicycle forward. Force magnitude describes the sum of all forces acting on an object. If all forces act in the same direction the force magnitude increases. If forces act on an object in different directions the magnitude of the force will decrease.
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what is the total magnification of a microscope with two lenses when one lens has a magnification of 10x, and the other lens has a magnification of 30x?
The total magnification of a microscope or set of lenses is 300x.
Magnification is the process of enlarging an object's image in relation to its size using a mirror, whether it be convex or concave.
There is no unit for magnification. The fact that it is a measurement ratio is the cause. It is the proportion of an object's size to that of an image.
Calculating the overall magnification is straightforward math once each lens's specific magnification is known. Add the combined magnification of the lenses.
Given
magnification of the first lens, l1 = 10x
magnification of the second lens, l2 = 30x
Total magnification = product of the magnification of all the lenses.
Thus, to compute the total magnification of a microscope, multiply the two lenses' magnification powers.
Consequently, the lenses' combined magnification will be - 10*30.
Thus the total magnification of a microscope or set of lenses is 300x.
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a current of 6.51 a6.51 a in a solenoid of length 11.0 cm11.0 cm creates a 0.341 t0.341 t magnetic field at the center of the solenoid. how many turns does this solenoid contain?
The number of turns this solenoid contains is 4422 turns.
The magnetic field is the location around a magnet wherein the effect of magnetism is felt. We use the magnetic subject as a device to explain how the magnetic force is distributed inside the space around and within some thing magnetic in nature.
The Earth's magnetic field does now not directly affect human health. human beings advanced to live on the earth. high altitude pilots and astronauts can experience higher degrees of radiation for the duration of magnetic storms, however, the risk is due to the radiation, no longer the magnetic area itself.
Magnetic fields are produced via transferring electric powered fees. the entirety is made up of atoms, and every atom has a nucleus fabricated from neutrons and protons with electrons that orbit around the nucleus. for the reason that orbiting electrons are tiny moving costs, a small magnetic field is created around every atom.
Calculation:-
B = uNI/L
⇒ 339 = (4pi X 10^-7)(6.71)(N)/.11
⇒ N = 4422 turns
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an object is revolving uniformly in a horizontal circle of radius 1.0 m with a speed of 1.0 m/s, calculate its centripetal acceleration. g
The centripetal acceleration is 1 m/s^2 .
Centripetal force is applied when there is a object revolving in circular path. This path is applied in the opposite direction of the center of the circular path and also this would be perpendicular to the velocity direction.
The value of centripetal force is
Fc = [tex]\frac{mv^{2} }{r}[/tex]
where m is the mass of the object
v is the velocity and r is the radius of the object.
Now as we know that
F = ma
where a is the acceleration
so we can write that
a = v^2/r
putting the values, we get
a = 1^2/1
a = 1/1
a = 1 m/s^2
Hence the centripetal acceleration is 1 m/s^2.
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a 4.50-kg object moves through a distance of 13.8 m as it slows down uniformly from 22.0 m/s to 13.5 m/s. what is the magnitude of the acceleration of the ball?
The magnitude of the acceleration of the ball is 25.3 m/s²
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
Calculation:-
v² = u² -2as
13.5² = 22² - 2a × 13.8
1182.25 - 484 = - 27.6a
698.25/27.6 = -a
a = - 25.3 m/s²
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A stone p,thrown upward with an velocity 20m/s.At the sametime and 30m vertical above, a second stone is released. After what time and at what height do they collide(g=10ms‐²)
The time and height at which they collide at 1 second and 15 m respectively when the stone is thrown upward with a velocity of 20m/s.
Let ball A be at the bottom and ball B be at the top.
Assume that you are sitting at B and watching A move.
You (B) appear to be content with yourself. However, both you (B) and A are accelerating in the same general direction. So, the acceleration of A relative to you (B) is 0.
As a result, A will appear to be approaching you uniformly moving at 20 m/s toward you.
A reaches you (B) in 1 second if the distance of 20 meters is divided by that speed.
Now that you have assumed you were stationed at B, you have thought about these motions and time. However, whichever reference frame you use, the time it takes for A to reach B shouldn't vary.
The collision between A and B occurs in 1 second.
Assuming g = 10 m/s2,
B falls freely and travels a distance of 1/2(g)([tex]1^{2}[/tex])=5.
They thus collide at a height of (20-5)m, or 15m, above the earth.
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The ability of a covalently bonded atom to attract the shared electrons is called.
Electronegativity is the capacity of a covalently connected atom to draw the shared electrons.
The capacity of an atom to draw the shared electrons from a covalent connection to itself is known as electronegativity. If the electronegativity of the linked atoms is the same, then the shared electrons will be distributed evenly. The electrons in a bond will not be distributed evenly if one of the atoms is more electronegative and hence attracts more of the bond's electrons. The more electronegative atom will "take" the electrons, resulting in two ions and an ionic connection, if the difference in electronegativity is great enough to prevent any sharing of the electrons.
Think of a tug-of-war match. The rope remains in the middle if the two teams are of equal strength. The rope is tugged in the direction of the team that is more powerful. The rope eventually ends up on the side of the stronger team if one team is much stronger than the other. If this happens, the weaker team is no longer able to hold onto the rope. Chemical bonding are comparable to this. The electrons are shared evenly if the electronegativity of the two bonding atoms is equal. The bond's electrons are more drawn to an atom if it has a higher electronegative charge. The electrons won't be shared, leading to an ionic bond, if one atom is much more electronegative than the other atom.
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if it requires 5.0 j of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be required to stretch it an additional 4.0 cm ?
2.5 J work will be required to stretch it an additional 4.0 cm.
Work done is elaborated in such a manner that it consists of each force exerted on the frame and the full displacement of the frame. This block is preceded by using a regular force F. The purpose of this pressure is to transport the body a certain distance d in an immediate course inside the path of the pressure.
The work is stated to be accomplished while force is implemented on an object's movements via a distance within the route of the utility of pressure. Scientists use the joule to measure work. One joule is the same as the paintings achieved by way of a force of one newton to move an item one meter in the path of the force.
Calculation:-
Work done is inversely proportional to the distance,
W₁/W₂ = L₂/L₁
W₂ = W₁L₁/L₂
= 5 × 2 /4
= 2.5 J
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Is rebel a synonym or antonym of the word conform
A hypothetical wave has 6. 6 j of energy. What is its hypothetical, approximate frequency?.
The approximate frequency is 9.96 × ³³ s-1
Solution:
Hypothetical wave energy = 6.6 J
Hypothetical wave frequency =?
E = HV
v = E / h
Where,
E = energy in joules
h = plank's constant & = 6.626 × 10-34 J.s
v = frequency in s-1
On substituting the values in the above formula :
v = E / h
v = 6.6 J / 6.626 × 10-34 J.s
v = 0.996 × 1034 s-1
v = 9.96 × 1033 s-1
Hence hypothetical wave frequency is = 9.96 × 10³³ s-1.
Count the markers to determine the frequency of each class. The relative frequency of a data class is the percentage of data items in that class. A joule is a unit of energy in the International System of Units. This is the work done when a force of 1 Newton displaces a mass 1 meter in the direction of the applied force.
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11 How far away does a ball land that rolls off a 2 m high table rolling at 9 m/s
a) 5.75 m
b) 10.25 m
c) 13.75 m/s
d) none of the above
*Please Show Equation*
Thank You!
Answer:
H = 1/2 g t^2 time to fall H
t = (2 H / g)^12 = (2 * 2 / 9.80)^1/2 = .639 sec
Sx = Vx * t = 9 m/s * .639 s = 5.75 m horizontal distance traveled
a ferris wheel with a radius of m is rotating at a rate of one revolution every minutes. how fast is a rider rising when his seat is m above ground level?
Using the concepts of Ferris wheel, we go that the speed of the rider is 2πm /min above ground level if a Ferris wheel with a radius of m is rotating at a rate of one revolution every minutes
The height of the rider at any time is (x + m) .
From the right triangle
sinθ = x/m ---------------(eq1)
Differentiating both sides with respect to t, we get:
d(sin)/dt= [(1/m)×(dx/dt)]
Using chain rule,
cosθ×(dθ/dt)= [(1/m)×(dx/dt)] -------------(eq 2)
When the height of the rider is 1m.
X = m - m
Then the value of x is 0.
Put the value of x in the equation (I)
Sinθ = 0/m = 0
We need to calculate the value of (dθ/dt)
A Ferris wheel makes 1 revolution per minute.
(dθ/dt)= 2π
Now, substitute the value of sinθ and (dθ/dt) in equation (II)
√1-0 x 2π= [(1/m)×(dx/dt)]
dx/dt =2πm
Hence, if a Ferris wheel with a radius of m is rotating at a rate of one revolution every minutes, the speed of rider rising when his seat is m above ground level is to be 2πm meters /sec.
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If a person is pushing against a stationary wall with a force of 20 n, what force is being exerted back on the person?.
If a person is pushing against a stationary wall with a force of 20N, then the force of same magnitude will be exerted back on to the person by the wall.
What is Force?Force is the external agent which is capable of changing an object's state of rest or motion. A force can be a push or a pull. It has both the magnitude and direction.
According to Newton's third law of motion, forces always acts in equal but opposite pairs. This law can also be defined as for every action, there is an equal but opposite reaction. It means that when a person pushes on a wall with a force of 20N, the wall pushes back on the person with a force equal in strength to the force which is exerted i.e., 20N but opposite in direction.
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if the car speeds up at a steady 1.7 m/s2 , how long after starting is the magnitude of its centripetal acceleration equal to the tangential acceleration?
Using the theories of centripetal acceleration, we got that 9.388 sec after the starting magnitude of its centripetal acceleration equal to the tangential acceleration.
We know that centripetal acceleration is given by =v²/r,
where v is the velocity along curved road and r is the radius of the curved road.
We have from the question, Acceleration (a) = 1.7m/sec²
Radius(R) = 150 m
Therefore,
a=v²/r
=>1.7=v²/150
=>v²=1.7×150
=>v²=255.0
=>v = 15.96 m/sec
Now, we know that the formula for tangential acceleration is the product of acceleration and its time ,which means
v = a x t
15.96 = 1.7 x t
t = 9.388 sec.
Hence, if the car speeds up at a steady 1.7 m/s2 , the time after starting when the magnitude of its centripetal acceleration equal to the tangential acceleration is 9.388 sec
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3. A luxury ship cruises at Miami, Florida at 150 mph and is brought to a stop uniformly by a motor
boat in 500 ft. Find the (a) acceleration and (b) the time required to stop.
Given:
a) Acceleration is calculated as 29.54 m/s^2
b) Time required to stop is calculated as 2.27 seconds
What is acceleration?The rate of change of the velocity of an object with respect to time is called as acceleration and it is a vector quantity. Acceleration is the rate at which velocity changes with time in terms of both speed and direction. An object moving in a straight line is accelerated if it's speed goes up or down.
Given, speed = 150 mph
1mph = 0.447 m/s
150mph = 67.056 m/s
and distance = 500 ft
1ft = 0.30 m
500 ft= 152.4 m
time= distance / speed
= 152.4/ 67.056
= 2.27 sec
Acceleration= velocity/ time
= 67.056/2.27
Acceleration = 29.54 m/s^2
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Brain waves that are lowest in frequency and highest in amplitude are called _____________ waves.
Brain waves that are lowest in frequency and highest in amplitude are called delta waves.
What are brain waves?Brain waves such as alpha waves or delta waves refer to the oscillations in the electrical differential of potential from different parts of the brain, which occur as a differential due to the action that an individual is making and it may indicate the brain areas working in a particular activity such as sleep.
Therefore, with this data, we can see that brain waves depend on the differential electrical potential that produces oscillations in the brain in response to the activity of different parts of our brain.
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