In what time would a Current
Current of
IA transfer
Change of 30c
a Change

The speed of particle 1 with respect to particle 2 at 2.83 s is determined as 17.5 m/s.

The relative velocity of an object 1 relative to another object 2 is the velocity that object 1 would appear to have to an observer moving with 2.

V(1) =  3.37 m/s²  x 2.83 s

V(1) = 9.54 m/s

V(2) =  5.18 m/s²  x 2.83 s

V(2) = 14.66 m/s

V(12) = √(9.54² + 14.66²)

V(12) = 17.5 m/s

Thus, the speed of particle 1 with respect to particle 2 at 2.83 s is determined as 17.5 m/s.

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When the automobile arrives at the truck, the two distance functions are equal.

95t−0.210=75t

95t−75t=0.210

25t=0.210

t=0.210

25t=0.0084 hr = 0.504 min = 30.24 s

Light always moves in a straight line. Light in air travels at 1.0003 times the speed of light in a vacuum, slowing it from 299,792,458 metres per second to 299,702,547 metres per second.

Homepage for Einstein's Big Idea. E = mc2. It's the most famous equation in the world, "Mass multiplied by the speed of light squared equals energy." On the most fundamental level, the equation states that energy and mass (matter) are interchangeable; they are various manifestations of the same thing.

The distance a wave travels in a particular length of time, such as the number of metres per second, is referred to as its wave speed.

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Answer:

t=45.4717

Explanation:

Find the speed of the car

93km/h x 1000m/1km x 1hr/3600s =25.833

Find the speed of the truck

74km/h x 1000m/1km x 1hr/3600s=20.555

(25.833-20.555)t=240

t=45.4717

The dog has a momentum of 11.34 kg*m/s.

The correct answer is D.

Product of a particle's mass and velocity. A vector quantity, momentum has both a magnitude and a direction. The force exerted on a particle is equated to the time rate of change of momentum by Isaac Newton's second equation of motion.

The sum of the units of mass and velocity yields the unit of momentum. The momentum is expressed in kilogram meters per second (kgm/s) in SI units if the mass and velocity are both expressed in kilograms and meters per second, respectively.

P = momentum

m = mass

v = velocity

m = 18 kg

v = .63 m/s

P = m × v

P= 18 × .63

p = 11.34 kg*m/s.

The dog has a momentum of 11.34 kg*m/s.

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The complete question is -

A dog weighing 18 kg runs into a park at a velocity of .63 m/s. What is the momentum of the dog? (1 point)

A-035 kg*m/s

B-17.37 kg*m/s

C- 28.5 kg*m/s

D- 11.34 kg* m/s

Answer:

The dog has a momentum of 11.34 kg*m/s.

It takes light to travel 150,000,000 km from the Sun to Earth in 500 seconds.

Light travels quicker in a vacuum than in another medium. this is because there's no obstruction in the vacuum for the propagation of mild and accordingly, the refractive index of the vacuum is the lowest. the rate of mild in a vacuum is 3×108 ms. daylight takes approximately 8 minutes to reach the Earth. thru the vacuum of space, irrespective of what their strength is, they always travel at the rate of light.

It would not remember how fast you chase after or run closer to light, both that velocity you view it journeying at will continually be equal. The thing that shifts, in place of its velocity, can be the mild's electricity. Albert Einstein's special principle of relativity famously dictates that no regarded object can journey faster than the speed of mild in a vacuum, which is 299,792 km. This speed restriction makes it not going that human beings will ever be able to ship spacecraft to discover beyond our nearby vicinity of the Milky Way.

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Answer:

It depends on what you mean by positive and negative acceleration. However I think what most people mean by these is that positive means speeding up and negative slowing down. In this case the object’s acceleration is negative on the way up, after leaving your hand at least, and positive on the way down.

Explanation:

A projectile's horizontal velocity is constant (a never changing in value), Gravity causes a downward vertical acceleration with a magnitude of 9.8 m/s/s. A projectile's vertical velocity fluctuates by 9.8 m/s per second, A projectile's vertical motion is unrelated to its horizontal motion.

For relatively small displacements, the force of gravity has little effect on an object's horizontal motion. This indicates that while the vertical velocity is accelerating, the horizontal velocity is remaining constant. The cause is that perpendicular vectors behave differently from one another. A projectile's vertical velocity is zero at its maximum height. There is now only the horizontal velocity.

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Explanation:

an object accelerated from 20m/s to 30m/s in 2 seconds. calculate the acceleration, can be calculated in calculator

Acceleration of the bullet is -87500m/s2

The rate at which the velocity of an object varies in relation to time is known as acceleration.

Acceleration is a vector quantity and the direction of the net force applied on an item determines the direction of its acceleration.

Acceleration is the rate at which the speed and direction of a moving object vary over time. When anything moves faster or slower moving straight, it is considered to be accelerating. Even though the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects influence to the acceleration for all other motions.

Since acceleration has both a magnitude and a direction, it is considered as a vector quantity. The velocity vector change during a time interval divided by the time interval is the definition of acceleration.

The limit of the ratio of the variation in velocity during a specified time period to the time period as the time period approaches zero determines the instantaneous acceleration (at a specific time and location).

Formula:

[tex]v^2 = u^2 + 2aS[/tex]

[tex]a = (v^2 - u^2) / 2S[/tex]

[tex]a = -350^2 / 2 * 0.07[/tex]

[tex]a = -122500 / 0.14[/tex]

[tex]a = -87500 m/s^2[/tex]

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Answer:

Explanation:

The short answer is B.

Both answers are correct if you omit the concerns of the other group. The second group is primarily concerned about the effects of tidal power on the environment. They are worried about marine animals, fish, silt buildups.

Contrary to this, the first group see the need for power that is relatively clean.

That's what B points out.

The volleyball's velocity at the moment it was tossed into the air is 10.78 m/s in the upward direction.

Let us assume that the initial velocity of the volleyball at the moment it was tossed into the air is u m/s. And the maximum height attained by it is equal to h meters.

Given in the question

Time of reach Max height = 1.1 seconds

Initial velocity = u m/s

Final Velocity = 0 m/s

( As the volleyball reaches the maximum height, it momentarily stops and its velocity at that instant is zero. )

Acceleration due to gravity = a = -g = -9.8 m/s²

( As the direction of velocity and acceleration due to gravity is opposite in direction, the Upward direction is taken as positive and the downward direction is taken as negative. )

Using First equation of motion: v = u + at

Put in the value

0 = u + (-9.8)(1.1)

0 = u - 10.78

u = 10.78 m/s

Therefore, the volleyball's velocity at the moment it was tossed into the air is 10.78 m/s in the upward direction.  

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The linear velocity of the CD is 1.03 m/s.

We know that the angular velocity and the linear velocity are related by the use of the formula;

v = rω

v = velocity of the body (linear)

r = radius of the body

ω = angular velocity

Given that we have to convert from rpm to rad/s

1 RPM = 0.10472 rad/s

180 RPM =  180 RPM * 0.10472 rad/s/1 RPM

= 18.7 rad/s

We know that radius = diameter/2 = 110 millimeters/2 = 55 millimeters or 55 * 10^-3 m

Substituting values;

v = 55 * 10^-3 m *  18.7 rad/s

v = 1.03 m/s

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The magnitude of the third charge is determined as -1.37 μc.

The magnitude of the charge on q3 is calculated as follows;

F = q12 + q23 + q13

F = kq₁q₂/r₂ + kq₂q₃/r² + kq₁q₃/r²

4.2 = (9 x 10⁹ x 2 x 10⁻⁶ x 3 x 10⁻⁶)/(0.1²) + (9 x 10⁹ x 3 x 10⁻⁶q₃)/(0.2²) + (9 x 10⁹ x 2 x 10⁻⁶ x q₃)/0.3²)

4.2 = 5.4 + 675,000q₃ + 200,000q₃

-1.2 = 875,000q₃

q₃ = -1.2/875000

q₃ = -1.37 x 10⁻⁶ C

q₃ = -1.37 μC

Thus, the magnitude of the third charge is determined as -1.37 μc.

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The acceleration is 930 m/s^2 and the time taken is 0.07 s.

We know that the acceleration is the rate of change of velocity with time. We can find the acceleration in this case by the use of kinematic equations of motion as we shall demonstrate below.

Let use the formula;

v^2 = u^2 + 2as

Where

v = final velocity

u = initial velocity

a = acceleration

s = distance covered

u = 0 m/s because the motion started from rest

v^2 =  2as

a = v^2/2s

a = (61)^2/2 * 2

a = 930 m/s^2

The time taken is;

v = u + at

u = 0 m/s

v = at

t = v/a

t = 61 m/s/930 m/s^2

t = 0.07 s

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The top speed reached during the entire trip would be 45 meters/seconds because the highest ordinate of the y-axis from the graph is 45 and the entire trip would last for 6 seconds.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

As given in the problem we have to find the top speed reached during the entire trip and the total duration of the trip,

The top speed = highest ordinate for the speed time curve

The top speed reached during the entire trip would be 45 meters/seconds because the highest ordinate of the y-axis from the graph is 45 and the entire trip would last for 6 seconds.

Thus, the top speed reached during the entire trip would be  45 meters/second.

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As the height from the ground was doubled the horizontal range increases.

As we increases the height from the ground, then the time ball will remain in air, means time of flight will increase which will ultimately increase the horizontal range.

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The total distance traveled for the entire trip is 30 meters and the total time consumed in the trip would be 4 seconds so the correct answer for the second problem is 4 seconds.

Displacement describes this shift in location.

Displacement is a vector quantity.

As given in the problem we have to find out from the graph the total time consumed in the trip,

As we can observe from the graph the position of the object is changing up to 4 seconds so we can conclude that the entire trip would have taken a total of 4 seconds.

Thus, the total time of the trip would be 4 seconds.

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Answer:

Compared to the emitted frequency, the received frequency is higher during the approach, identical at the instant of passing by, and lower during the recession.

Explanation:

Answer:

1.) Lose electrons

2.) Ionic Bonding

Explanation:

Elements on the left side of the periodic table lose electrons during ionic bonding. These elements lose electrons because it is easier for them to give up a few electrons rather than to try and gain many more to achieve a full valence octet. On the other hand, the elements on the right side have close to 8 valence electrons. Therefore, they are more likely to take electrons to make up this small gap rather than give many more away.

Answer:

Option B. Burning of wood.

Energy is dissipated as heat from the lamp is

400 kw

It is given that

power of lamp = 100 kw

efficiency = 20%

time = 5 hour

We have to find the energy of lamp

Efficiency is the measure of how completely work input is connected to work output.

Efficiency = work(out)/work(in) * 100%

Efficiency of visible light = 20%

Energy converted to heat = 80%

Energy = Power * time

Energy = 100 kw x 80% x 5 = 400 kw

Hence, Energy dissipated as heat is 400 kw

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Answer:

325.125m

Explanation:

We can use the kinematics equations to solve this problem.

Given:

u = Initial Velocity = 0 m/s

v = Final Velocity = 76.5 m/s

t = 8.5 s

We can use the first kinematics equation to find the acceleration:

v = u + at

76.5 = 0 + 8.5a

a = 76.5 ÷ 8.5

[tex] = 9\frac{m}{ {s}^{2} } [/tex]

Since we now have the acceleration, we can use the third kinematics equation to find the distance travelled:

[tex]s = ut + \frac{1}{2} a {t}^{2} \\ s = (0)(8.5) + \frac{1}{2} (9) {(8.5)}^{2} \\ = 325.125m[/tex]

For a truck moving at constant speed, the distances traveled during each time period are the same.

If an object covers an equal amount of distance in equal interval of time, then the body is said to be moving at a constant speed.

Constant speed means the speed does not change at all for each second of the motion.

Speed has no direction, hence we cannot say that he direction traveled during each time period must be the same.

Thus, for a truck moving at constant speed, the distances traveled during each time period are the same.

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The rocket landed 92.45m below when it hit the ground.

When a  body is dropped from a height, its initial velocity is 0. A body executing free fall moves with constant acceleration i.e., acceleration due to gravity

Given data -

By using 2nd equation of motion:

[tex]s = ut + \frac{1}{2} at^2[/tex]

Equation of motion under gravity:

[tex]s = ut + \frac{1}{2} gt^2[/tex]

  [tex]= 0 \times 4.3 \sec + \frac{1}{2} \times 10 \times (4.3)^{2}[/tex] ( assuming g = 10 m/s²)

  [tex]= \frac{1}{2} \times 10 \times 18.49[/tex]

  = 5 × 18.49

  =  92.45 m

Thus we can conclude that the rocket landed 92.45m below when it hit the ground.

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An outline for how to approach writing your lab report is as follows

The parts

This is further explained below.

Generally, A lab report is composed of eight different components, which are as follows: the title, the abstract, the introduction, the techniques and materials, the findings, the discussion, and the conclusion.

In conclusion, It is important that the experiment is adequately described in the title of the lab report, and that the title also accurately represents the data obtained from the experiment.

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The particle’s acceleration is 0.268 m/s².

The initial velocity of the particle before 13.3 seconds is 3.56 m/s.

The time when the particle is at rest is 32.68 seconds.

The acceleration of the particle is calculated as follows;

a = Δv/Δt

a = (7.95 m/s - 4.38 m/s) / 13.3 s

a = 0.268 m/s²

u = at

u = 0.268 m/s² x 13.3 s

u = 3.56 m/s

s = ut + ¹/₂at²

0 = -4.38t + ¹/₂(0.268)t²

0.134t² = 4.38t

0.134t = 4.38

t = 32.68 seconds

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Overproduction is caused by price supports. Governments assist farmers to increase production by subsidising prices above the point at which the market clears. Farmers use more inputs per acre in order to produce more. Additionally, they compete with one another for the limited supply of farmland, driving increasing the cost of it.

Agricultural assistance is defined as the annual dollar amount of gross consumer and taxation transfers to agriculture resulting from governmental policies that support agriculture, independent of the goals or effects on the economy.

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The space shuttle will travel as far as 29400 km in 1.4 hours

Speed is the distance travelled per time taken. It is a scalar quantity.

Given that a space shuttle orbits earth at a speed of 21,000 km/hr. Since it is assumed that the shuttle is traveling on a straight path, to know how far it will travel in 1.4 hours, we will apply the speed formula.

Speed = distance / time

21000 = distance / 1.4

distance = 21000 x 1.4

distance = 29400 Km

Therefore, the space shuttle will travel as far as 29400 km in 1.4 hours

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The force needed by Princess Leia is 17.87 N.

The acceleration of Princess Leia is calculated as follows;

s = u + ¹/₂at²

where;

s = ¹/₂at²

2s = at²

a = 2s/t²

a = (2 x 10) / (7.1²)

a = 0.397 m/s²

The force needed by Princess Leia is calculated as follows;

F = ma

F = 45 x 0.397 m/s²

F = 17.87 N

Thus, the force needed by Princess Leia is 17.87 N.

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We can move away from a 6.0 × 1014 Hz light source to observe waves with a frequency of 4.0 × 1014 Hz with a speed of 0.38c.

Physics refers to the frequency as the quantity of waves passing a fixed point in a unit of time. Additionally, it is the quantity of vibrations or cycles that a body in periodic motion experiences in a certain period of time. One cycle or vibration is defined as the movement of a body in periodic motion across a sequence of occasions or locations before returning to its initial state.

According to the question,

6.0× 1014 Hz can be written as 6 A° similarly,

4.0×1014 Hz can be written as 4 A°

By using Doppler's effect, the wavelength of light will be :

[tex]\lambda\\[/tex]=[tex]\lambda[/tex]₀[tex]\sqrt{1+(v/c)/1-(v/c)}[/tex]

6.0 A°= (4.0 A°)  [tex]\sqrt{1+(v/c)/1-(v/c)}[/tex]

v=0.38c

Hence, it will move with 0.38c.

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