I would think B, along the Amazon River. This is because of the warm climate ad lots of rainfall.
A 2kg mass moving at 1 m/s has a kinetic energy equal to...?
Answer:
kinetic energy = 1/2mv2
= 1/2 x 2 x 3^2
= 9J
Explanation:
PLEASE HELP
Which of the following is a force?
Momentum
Friction
Acceleration
Velocity
How much potential energy does a 75 kg diver have stepping off the edge of a 5 meter platform?
Answer:
3.678kJ
Explanation:
Given
mass= 75kg
height= 5 m
g= 9.81m/s^2
Required
Potential energy
PE= mgh
substitute
PE= 75*9.81*5
PE=3678.75J
PE= 3.678kJ
I need help with this. Lab: Conservation of Linear Momentum
Assignment: Lab Report Urgent!!
Explain your answers to 9a and 9b in terms of Newton's laws of motion.
Answer:i One way to solve the quadratic equation x2 = 9 is to subtract 9 from both sides to get one side equal to 0: x2 – 9 = 0. The expression on the left can be factored:
Explanation:
Tony drives his car . He drives the first 13 miles in 13 minutes. He then drives at an average speed of 68mph for 1 hour 24 minutes .
Complete question :
Tony drives his car . He drives the first 13 miles in 13 minutes. He then drives at an average speed of 68mph for 1 hour 24 minutes . Find how much petrol he uses using the information in the table.
Requires table to answer question is attached below
Answer:
2.64 gallons
Explanation:
Given that:
First 13 miles takes 13 minutes
Average rate = 13 miles / 13 minutes = 1mile/minute ; Average rate per hour = (1 mile /minute * 60) = 60 miles /hour
If average speed = 65mph or less ; 50 miles per gallon (it uses 1 gallon for 50 miles)
Hence, since first phase rate is 60 mph,; then miles per gallon is 50 miles
Therefore,gallon of petrol used for 13 miles will be :
13 miles / 50 mpg = 0.26 gallons
2nd phase:
Average rate of 68 mph for 1 hour 24 minutes (1.4 hours)
Here, miles per gallon = 40 (that is; 40 miles for 1 gallon).
Total distance covered = 68 * 1.4 = 95.2 miles
Petrol used = 95.2 miles / 40 mpg = 2.38 gallons
Hence,
Total petrol used : (0.26 + 2.38) = 2.64 gallons
What is the resistance (R) when voltage is 179V and current is 5 Amps?
Answer:
R = 35.8 Ω
Explanation:
Recall Ohm's Law:
V = I * R
then R = V / I
in our case:
R = 179 V / 5 A = 35.8 Ω
What is the frequency of a radio wave of wavelength 150 m if the velocity of radio waves in free space is 3 × 10^8 m s–¹ ?
Answer:
frequency =speed/wavelength
=(3*10^8)/150
=2×10^6
An empty glass beaker has a mass of 103 g. When filled with water, it has a total mass of 361g.
When filled with cooking oil, it has a total mass of 351 g.
The density of water is 1.00 gcm–3.
What is the density of the cooking oil?
Answer:
0.96 gcm¯³
Explanation:
From the question given above, the following data were obtained:
Mass of empty beaker = 103 g
Mass of beaker + water = 361 g
Mass of beaker + oil = 351 g
Density of water = 1 gcm¯³
Density of cooking oil =?
Next, we shall determine the mass of water. This can be obtained as follow:
Mass of empty beaker = 103 g
Mass of beaker + water = 361 g
Mass of water =?
Mass of water = (Mass of beaker + water) – (Mass of empty beaker)
Mass of water = 361 – 103
Mass of water = 258 g
Next, we shall determine the volume of the beaker. This can be obtained by calculating the volume of water in the beaker.
Density of water = 1 gcm¯³
Mass of water = 258 g
Volume of water =?
Density = mass /volume
1 = 258 / volume
Cross multiply
1 × volume = 258
Volume of water = 258 cm³
Thus the volume of the beaker is 258 cm³.
Next, we shall determine the mass of the cooking oil. This can be obtained as follow:
Mass of empty beaker = 103 g
Mass of beaker + oil = 351 g
Mass of cooking oil =?
Mass of cooking oil = (Mass of beaker + oil) – (Mass of empty beaker)
Mass of cooking oil = 351 – 103
Mass of cooking oil = 248 g
Finally, we shall determine the density of the cooking oil. This can be obtained as follow:
Mass of cooking oil = 248 g
Volume of the beaker = 258 cm³
Density of cooking oil =?
Density = mass / volume
Density = 248 / 258
Density of cooking oil = 0.96 gcm¯³
the maximum range of a projectile is 2÷√3 times its actual range what is the angle of the projection for the actual range
Answer:
The actual angle is 30°
Explanation:
Equation of projectile:y axis:[tex]v_y(t)=vo*sin(A)-g*t[/tex]
the velocity is Zero when the projectile reach in the maximum altitude:
[tex]0=vo-gt\\t=\frac{vo}{g}[/tex]
When the time is vo/g the projectile are in the middle of the range.
x axis:[tex]d_x(t)=vo*cos(A)*t\\[/tex]
R=Range
[tex]R=d_x(t=2*\frac{vo}{g})[/tex]
[tex]R=vo*cos(A)*2\frac{vo}{g} \\\\R=\frac{(vo)^{2}*2* sin(A)cos(A)}{g} \\\\R=\frac{(vo)^{2} sin(2A)}{g}[/tex]
**sin(2A)=2sin(A)cos(A)
The maximum range occurs when A=45°(because sin(90°)=1)The actual range R'=(2/√3)R:Let B the actual angle of projectile
[tex]\frac{vo^{2} }{g} =(\frac{2}{\sqrt{3} }) \frac{vo^{2} *sin(2B)}{g}\\\\1= \frac{2 }{\sqrt{3}} *sin(2B)\\\\sin(2B)=\frac{\sqrt{3}}{2}\\\\[/tex]
2B=60°
B=30°
An 10 kg mass has an applied force of magnitude 69N acting on it pushing it to move in the positive x-direction. The mass is on a flat surface that has a coefficient of kinetic (Uk) friction of 0.5.with respect to the object. What is the magnitude of the acceleration of the object?
The net force on the mass in the vertical direction is
∑ F = n - w = 0
and the net horizontal force is
∑ F = A - f = ma
where
n = magnitude of the normal force
w = mg = weight of the mass
m = 10 kg, mass of the … uh, mass
g = 9.8 m/s², mag. of acceleration due to gravity
A = 69 N, mag. of the applied force
f = mag. of kinetic friction
From the first equation, we get
n = mg = (10 kg) (9.8 m/s²) = 98 N
Then the friction force has magnitude
f = µ n = 0.5 (98 N) = 49 N
Solve the mass's acceleration in the second equation:
69 N - 49 N = (10 kg) a
a = (20 N) / (10 kg) = 2.0 m/s²
in the positive x direction.
Where does the
energy used to
complete the task
come from? What
evidence do you
have that the energy
involved in the crane'
example is different
from that in the
wind-up toy
example?
Answer:
it comes from your knowledge and the information you have to get the reason why that is the answer so you are putting together things that you already know what the new information you have
Would anyone be able to o an application of physics project for me, it has to be 500 words l m a o
A 0.02kg bullet is traveling with a speed of 300m/s when it hits a wall. Assuming it comes to rest after traveling 0.1m with constant deceleration into the wall.
1. Calculate the work done by the wall on the bullet as the bullet comes to a stop.
2. Calculate the deceleration of the bullet as it comes to a stop.
Answer:
1. W = 900 J
2. a = -450000 m/s²
Explanation:
2.
First, we calculate the deceleration of the bullet by using 3rd equation of motion:
[tex]2as = V_{f}^{2} - V_{i}^{2}\\[/tex]
where,
a = deceleration = ?
s = distance traveled = 0.1 m
Vf = Final Speed = 0 m/s (it eventually stops)
Vi = Initial Speed = 300 m/s
Therefore,
[tex]2a(0.1\ m) = (0\ m/s)^{2} - (300\ m/s)^{2}\\a = \frac{-90000\ m^{2}/s^{2}}{0.2\ m}\\\\[/tex]
a = -450000 m/s² (negative sign shows deceleration)
1.
Now, we calculate the force using Newton's Second Law:
[tex]F = ma\\F = (0.02\ kg)(-450000\ m/s^{2})\\F = - 9000\ N[/tex]
Negative sign shows decelerating force.
For work done:
[tex]Work\ Done = W = Fs\\W = (9000 N)(0.1\ m)[/tex]
W = 900 J
a 4 kg bowling ball videos rolling down a lane at bowling alley at 6 m/s when the ball strikes the pins is moving your 5.1 m/show much energy in the J is lost due to the friction?
Answer:
19.98Joules
Explanation:
Energy possessed by the body is the kinetic energy
Kinetic Energy = 1/2mv²
m is the mass
v is the velocity
For the 4kg moving at 6m/s
kE = 1/2 * 4 * 6^2
KE = 1/2 * 4 * 36
KE = 72Joules
For the 4kg moving at 5.1m/s
kE = 1/2 * 4 * 5.1^2
KE = 1/2 * 4 *26.01
KE = 52.02Joules
Amount of Energy lost = 72 - 52.02
Amount of Energy lost = 19.98Joules
Hence the amount of Energy lost is 19.98Joules
“if matthew rides south on his bicycle in a straight line for 23 mins (0.383 hr) with an average velocity of 17.5mph, how far has he ridden?
Answer:
6.7miles due south
Explanation:
Given parameters:
Time = 23min(0.383hr)
Average velocity = 17.5mph
Unknown:
How far he has ridden = ?
Solution:
To solve this problem,
Displacement = Velocity x time
Displacement = 17.5 x 0.383 = 6.7miles due south
A bus traveled 2.5 hours in 150 km. What was its average speed?
s=d/t
v=D/t
a=(v-v.)lt
Answer:
Average speed = 60km/hr
Explanation:
Given the following data;
Time = 2.5 hrs
Distance = 150km
To find the average speed;
Average speed = distance/time
Substituting into the equation, we have
Average speed = 150/2.5
Average speed = 60km/hr
How does heat transfer? (Think temperature)
Answer:
The rate at which temperature changes is proportional to the rate at which heat is transferred.
Explanation:
The temperature of a sample changes more rapidly if heat is transferred at a high rate and less rapidly if heat is transferred at a low rate
can anyone help me with this last question?
Answer:
v = 39.6 m/s (first answer option)
Explanation:
Use conservation of mechanical energy.
The starting is completely potential energy and the final is all kinetic energy:
[tex]m*g*h=\frac{1}{2}*m*v^2\\g * h=\frac{1}{2} v^2\\9.8*80=\frac{1}{2} v^2\\v^2=1568\\v\approx 39.6\,\,m/s[/tex]
which agrees with the first answer shown.
Helppp please
As the temperature of water drops, it continues to give off thermal energy until it freezes. This is an example of.
increasing thermal energy
a chemical change
an exothermic change
an endothermic change
Answer:
exothermic change hope it help
Explanation:
it is exothermic change hope it helpful
which statement best compares and contrasts two physical properties of natter
Answer:
D.
Explanation:
There are three physical properties of matter that involves solid, liquid and gas.
The last statement is correct as it says: boiling and melting points are similar as both changes the physical state of matter. But are different as boiling point changes liquid into gas for example: liquid at high boiling point changes into vapors (gas) and melting point changes solid into liquid for example: ice at high melting point changes into liquid.
Hence, the correct option is "D".
The exchange of materials between a cell and its environment takes place across cell?A. MitochondriaB. MembraneC. NucleusD. Nucleolus
Answer:
I'm not 100% sure but I think its Cell membrane
Explanation:
please, correct me if i'm wrong.
It's velocity changes, but its speed remains the same.
The
true or false
Answer:
True
Explanation:
Velocity is a vector quantity, which means that it carries both magnitude and direction. Hence when direction of a particle changes, although magnitude (speed) may remain same, it's velocity changes due to direction change. For ex. A particle is m... A particle is moving along x axis with speed 1m/s, it's velocity will be represented as 1i (i represents unit vector along x)
But if it now starts moving along y axis, it's velocity is 1j (j represents unit vector along y axis). Hence velocity changes with direction.
brainllest pls .
shows the relationships among the solid, liquid and gas states as a function of temperature and pressure.
A: phase diagram
B: heat energy diagram
C: heating curve
Answer:
Phase Diagram I Think But I Just Searched It Online
PLEASE HELP IM BEGGING YOU! What is the mass of an object that requires 100N of force to accelerate it at 5m/s2? I
Answer:
20 kg
Explanation:
The following data were obtained from the question:
Force (F) = 100 N
Acceleration (a) = 5 m/s²
Mass (m) =?
Force (F) is simply defined as the product of mass (m) and acceleration (a). Mathematically, the force (F) can be expressed as:
Force (F) = mass (m) × acceleration (a)
F = ma
With the above formula, we can simply obtain the mass of the object as follow:
Force (F) = 100 N
Acceleration (a) = 5 m/s²
Mass (m) =?
F = ma
100 = m × 5
Divide both side by 5
m = 100 / 5
m = 20 kg
Thus, the mass of the object is 20 kg.
What happens to an object's gravitational potential energy as it falls from some height?
Answer:
Decreases
Explanation:
As an object falls from some height, the gravitational potential energy of the object decreases.
Potential energy is the energy due to the position of a body.
The potential energy is mathematically expressed as:
Potential energy = mass x acceleration due to gravity x height
So, potential energy is directly proportional to mass and height.
The higher the mass and height, the more the potential energy.
A car accelerates from rest in a straight line. During the first 14s, the acceleration is uniform and the car reaches the speed of 25m/s. Calculate the acceleration of the car.
v = u + at
25 = 0 + a(14)
a(14) = 25
a = 25/14
a = 1.71 (3sf)
explanation:
u use the equation of motions
v = u + at
v is final velocity, aka 25
u is initial velocity, which is 0 as it was initially at rest
t is time, which is 14s
then u sub in the values and calculate a
900n pushes a wedge 0.10 m into a log, if the work done on the log is 50j what is the efficiency of the wedge
Answer:
100
Explanation:
mark me brainliest
Household appliances convert electricity into one or more different forms of energy. An electric fan can be described as converting electricity into :
Answer: heat energy, sound energy, and mechanical energy only
Explanation: I did the test in got it right.
The heating element in a kettle behaves like a resistor. A particular kettle needs to operate at 230 V, with a power of 1500 W. Calculate the resistance which the heating element needs to have
Answer:
R = 35.27 Ohms
Explanation:
Given the following data;
Voltage = 230V
Power = 1500W
To find the resistance, R;
Power = V²/R
Where:
V is the voltage measured in volts.
R is the resistance measured in ohms.
Substituting into the equation, we have;
1500 = 230²/R
Cross-multiplying, we have;
1500R = 52900
R = 52900/1500
R = 35.27 Ohms.
Therefore, the resistance which the heating element needs to have is 35.27 Ohms.
