During autumn, what happens? (Select all that apply.)
Days become warmer and longer.
Animals prepare to survive the winter.
Some trees begin to shed their leaves.
Plants prepare to survive the winter.
During autumn, several changes occur in nature. Some of the changes that happen during this season include:Days become cooler and shorter,animals prepare to survive the winter.some trees begin to shed their leaves and plants prepare to survive winter, thus all options are correct.
1. Days become cooler and shorter: As autumn arrives, the weather gradually becomes cooler. The days also become shorter, meaning there is less sunlight each day. This decrease in daylight hours is due to the Earth's tilt on its axis as it orbits the sun.
2. Animals prepare to survive the winter: Many animals start making preparations for the upcoming winter during autumn. They may begin to store food or find sheltered places to hibernate. For example, squirrels gather and store nuts, birds migrate to warmer regions, and bears build up fat reserves for hibernation.
3. Some trees begin to shed their leaves: One of the most notable changes during autumn is the colorful transformation of tree leaves. Some trees, such as deciduous trees, shed their leaves during this season. As the days shorten and temperatures drop, the trees receive less sunlight, which triggers the production of a pigment called anthocyanin. This pigment gives leaves their vibrant red, orange, and yellow colors before they eventually fall off.
4. Plants prepare to survive the winter: Just like animals, plants also make preparations to survive the harsh conditions of winter. They may enter a state of dormancy or store energy and nutrients in their roots to survive until spring. Some plants produce seeds or fruits during autumn, ensuring their offspring can grow when conditions become favorable again.
In summary, during autumn, days become cooler and shorter, animals prepare for winter, some trees shed their leaves, and plants make preparations to survive until spring. These changes are part of the natural cycle of life and adaptation to seasonal variations.Thus, all options are correct.
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Refer to the question above to help answer this question. If the students were to redo their experiment with the water and the antiacid tablet, what would you recommend they do in order to show that the mass was conserved in that chemical reaction.
a. They should put a cover on the beaker so nothing can escape during the experiment.
b. They should use two antiacid tablets instead of one.
c. They should use more water.
d. They should get a new scale and double check their measurements.
Answer:
hrsseWFEwdS
Explanation:
Which of the following statements accurately describes a pedigree chart?
1. A pedigree chart is used to predict the genotype of offspring.
2. A pedigree chart tracks inherited traits from parents to offspring.
3. A pedigree chart predicts the percentage of offspring that will have a specific trait.
4. A pedigree chart identifies the phenotype of the organism.
Answer:
Two is your answer...
Explanation:
a train moving at a velocity of 15 m/s is accelerated to 24 m/s over a 12 second period
Answer:
o.75
Explanation:
A train moving at a velocity of 15 m/s is accelerated to 24m/s over a 12 second period, time traveled by the train is 12 seconds.
The initial velocity u of the train is 15 m/s, the final velocity v is 24 m/s, and the time t is 12 seconds. The train is undergoing uniform acceleration.
We can use the kinematic equation to relate the initial velocity, final velocity, acceleration, and time:
v = u + at
Solving for t:
[tex]\[ t = \dfrac{v - u}{a} \][/tex]
Given that a is the acceleration and is calculated as:
[tex]\[ a = \dfrac{v - u}{t} \][/tex]
Substitute the given values:
[tex]\[ a = \dfrac{24 \, \text{m/s} - 15 \, \text{m/s}}{12 \, \text{s}} \][/tex]
[tex]\[ a = \dfrac{9 \, \text{m/s}}{12 \, \text{s}} \\\\= 0.75 \, \text{m/s}^2 \][/tex]
Now substitute the calculated acceleration back into the equation for \( t \):
[tex]\[ t = \dfrac{v - u}{a} \\\\= \dfrac{24 \, \text{m/s} - 15 \, \text{m/s}}{0.75 \, \text{m/s}^2} \][/tex]
[tex]\[ t = \dfrac{9 \, \text{m/s}}{0.75 \, \text{m/s}^2} \\\\= 12 \, \text{s} \][/tex]
Thus, the time traveled by the train is 12 seconds.
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Your question seems incomplete, the probable complete question is:
A train moving at a velocity of 15 m/s is accelerated to 24m/s over a 12 second period. Determine the time travelled
