Answer: 24 sq units is the area of triangle.
Step-by-step explanation:
Given , (x1 , y1) = (-1, 1), (x2 , y2) = (3, 5) , (x3, y3) = (5, -5)
Using the Formula :
Area of triangle = [tex]\[\frac{1}{2}(x1(y2-y3) + x2(y3-y1) + x3(y1 -y2))\][/tex]
[tex]\[=\frac{1}{2}(-1(5-(-5)) + 3(-5-1) + 5(1-5)) \\=\frac{1}{2}(-10 -1 8 -20) \\=\frac{1}{2}(-48) = -24\][/tex]
Area cannot be negative. We only consider the numerical value of answer. Therefore, area of triangle = 24 sq units.
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The function f(x)= –StartRoot negative x EndRoot is shown on the graph.
The range of the required function f(x) = -√-x is all real values less than or equal to 0.
The nature of the function is imaginary because of the negative sign present inside the root. Hence the range of the function exists only and only if the function gives real values in each of its outcomes.
What are functions?Functions is the relationship between sets of values. e g y=f(x), for every value of x there is its exists in set of y. x is independent variable while Y is dependent variable.
As per question
f(x) = -√-x
clearly, for each positive real number the function becomes imaginary.
So the domain of the given function lies (-∞, 0).
and for every x in its domain function has its exists in range of all real values less than and equal to zero.
Thus, the range of the function f(x) ≤ 0.
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Math: Surface Area word problem..10 pts for your help!
The formula for the surface area N(t) of the balloon after t seconds is [tex]N(t) = \frac {64}9\pi t^2[/tex]
How to determine the surface area?We have:
[tex]S(r) = 4\pi r^2[/tex]
Also, we have:
[tex]P(t) = \frac 43t[/tex]
The above can be rewritten as:
[tex]r = \frac 43t[/tex]
Substitute [tex]r = \frac 43t[/tex] in S(r) to determine the function N(t)
[tex]S(r) = 4\pi (\frac 43t)^2[/tex]
Express as N(t)
[tex]N(t) = 4\pi (\frac 43t)^2[/tex]
Expand the exponent
[tex]N(t) = 4\pi *\frac {16}9t^2[/tex]
Evaluate the product
[tex]N(t) = \frac {64}9\pi t^2[/tex]
Hence, the formula for the surface area N(t) of the balloon after t seconds is [tex]N(t) = \frac {64}9\pi t^2[/tex]
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Please answer BOTH the questions tyyyyyysm
C and A
X = at least 45 and more
This means we need to have a full closed dot.
It's A because the question says more than 75 ft meaning only open dots.
Enter the correct answer in the box.
Function g has the same a value as function f, but its vertex is 2 units below and 3 units to the left.
f(x) = x² - 4x - 32
Write the vertex form of the equation modeling function g.
The equation in the vertex form of g(x) is:
[tex]g(x) = (x + 1)^2 - 38[/tex]
How to get the equation of function g?
We know that g(x) is a translation of 2 units below and 3 units to the left of f(x).
So first, let's rewrite f(x) to its vertex form:
[tex]f(x) = x^2 - 4x - 32[/tex]
The vertex is at:
[tex]x = -(-4)/2*1 = 2[/tex]
The y-value of the vertex is:
[tex]f(2) = 2^2 - 4*2 - 32 = -36[/tex]
Then the vertex form of f(x) is:
[tex]f(x) = (x - 2)^2 - 36[/tex]
If we move this vertex 2 units below, and 3 units to the left, then we have:
[tex]g(x) = f(x +3) - 2\\\\g(x) = (x - 2 + 3)^2 - 36 - 2\\\\g(x) = (x + 1)^2 - 38[/tex]
That is the equation for g(x) in vertex form.
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How many square feet of tile is needed for a room of 24 foot x 24 foot
Answer:576
Step-by-step explanation:
24 squared is 576
Tan + Cos / 1 + Sin = Sec
[tex]\tan x+\frac{\cos x}{1+\sin x}\\\\ =\frac{\sin x}{\cos x}+\frac{\cos x}{1+\sin x}\\\\=\frac{\sin x(1+\sin x)+\cos^{2} x}{\cos x(1+\sin x)}\\\\=\frac{\sin^{2} x+\cos^{2} x+\sin x}{\cos x(1+\sin x)}\\\\=\frac{1+\sin x}{\cos x(1+\sin x)}\\\\=\frac{1}{\cos x}\\\\=\sec x[/tex]
What is the greatest common factor of 20 and 36?
2
4
5
6
Answer:
GFC = 4
Step-by-step explanation:
Factors of 20 1 2 4 5 10 20
Factors of 36 1 2 3 4 6 9 12 18 36
Answer:4
Step-by-step explanation:nice and simple
Evaluate 3a-5b when a=-3 and b=-2
Answer: 1
Step-by-step explanation:
Substituting in the given values,
3a-5b=3(-3)-5(-2)=-9+10=
he roots of the quadratic function describing the relationship between the number of products produced and overall profit margins are x= 0 and 150. the vertex is (75, 10000).
The question was incomplete. Below you will find the missing parts of the question.
The company actually loses money on their first few products as it costs them more to make them, but once they hit ? they break even again. The worst case scenerio is that they produce ? items, as they will have a profit of ? dollars. The first root tells us that the profit will be 0 when ? products are sold.
Answer: The company actually loses money on their first few products as it costs them more to make them, but once they hit 150 they break even again. The worst case scenerio is that they produce 75 items, as they will have a profit of 10000 dollars. The first root tells us that the profit will be 0 when 0 products are sold.
Because the roots are x = 0 and 150, the vertex is (75, 10000).
So, the function is y = [tex]-\frac{10000}{5625}(x-75)^{2} +10000[/tex]
When, y = 0,
[tex]0=-\frac{10000}{5625} (x-75)^{2} +10000[/tex]
⇒ [tex]\frac{10000}{5625} (x-75)^{2}=10000[/tex]
⇒ [tex](x-75)^{2} = 10000(\frac{5625}{10000})[/tex]
⇒ [tex](x-75)^{2} = 5625[/tex]
⇒ [tex]x-75=75[/tex]
⇒ x = 150
When y=0, then x =150, their income was in balance.
When x = 75, then y=10000, they will have a profit of 10000 dollars.
The first root tells us that the profit will be 0 when 0 products are sold.
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which law would you use to simplify the expression....
Answer:
power of a power
Step-by-step explanation:
the power of a power law says that, "if a base raised to a power is being raised to another power, the exponents are multiplied and the base remains the same."
for example, for this problem, you would do:
[tex](x^4)^9\\= x^4^*^9\\= x^3^6[/tex]
How to find the a in the equation y=ax^3 + d given the two points (0,10), (2,20)
Answer:
[tex]y=\dfrac{5}{4}x^3+10[/tex]
Step-by-step explanation:
Given information:
[tex]y=ax^3+d[/tex](0, 10)(2, 20)Create two equations by substituting the given points into the given equation:
Equation 1: point (0, 10)
[tex]\implies a(0)^3+d=10[/tex]
[tex]\implies 0+d=10[/tex]
[tex]\implies d=10[/tex]
Equation 2: point (2, 20)
[tex]\implies a(2)^3+d=20[/tex]
[tex]\implies 8a+d=20[/tex]
Substitute Equation 1 into Equation 2 and solve for a:
[tex]\implies 8a+d=20[/tex]
[tex]\implies 8a+10=20[/tex]
[tex]\implies 8a+10-10=20-10[/tex]
[tex]\implies 8a=10[/tex]
[tex]\implies \dfrac{8a}{8}=\dfrac{10}{8}[/tex]
[tex]\implies a=\dfrac{10}{8}[/tex]
[tex]\implies a=\dfrac{5}{4}[/tex]
Finally, substitute the found values of a and d into the original formula:
[tex]\implies y=\dfrac{5}{4}x^3+10[/tex]
Check by substituting the x-values of the two given points into the found equation:
[tex]x=0 \implies y=\dfrac{5}{4}(0)^3+10=10 \leftarrow \textsf{correct}[/tex]
[tex]x=2 \implies y=\dfrac{5}{4}(2)^3+10=20 \leftarrow \textsf{correct}[/tex]
Put(0,10)
10=a(0)³+dd=10Now
Put again (2,20) this time
20=2³a+1010=8aa=10/8a=5/4A sample of size 400 was drawn and sample mean was found t
be 99. Test whether this sample could have come from a normal
population with mean 100 and variance 64 at 5%
significance.
Answer:
etrf4f3dvef3rf3rfr2wrgwrf2rg3rf3rgerferferfef I'm
Which of the following statements are true?
A. Both graphs have exactly one asymptote.
B. Both graphs have been shifted and flipped.
c. Both graphs are logarithmic functions.
D. Both graphs are exponential functions.
Geometry question! Please help thanks!
The measure of the angles are Z = 90, X = 90, V = 90, Y = ∠20, W = ∠8 and W = ∠20
How to solve the angles?The sum of angles on a straight line is 180 degrees.
This means that:
Z + 90 = 180
X + 90 = 180
V + 90 = 180
Solve for the variables
Z = 90;
X = 90
V = 90
Also, alternate angles are equal.
This means that:
Y = ∠20
W = ∠8
This is so because the above angles are alternate angles.
Lastly, corresponding angles are equal.
So, we have:
W = ∠20
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Abby used the law of cosines for TriangleKMN to solve for k.
k2 = 312 + 532 – 2(31)(53)cos(37°)
Triangle K N M is shown. The length of K N is 53, the length of N M is k, and the length of K M is n.
Law of cosines: a2 = b2 + c2 – 2bccos(A)
What additional information did Abby know that is not shown in the diagram?
mAngleK = 37° and n = 31
mAngleK = 37° and k = 31
mAngleN = 37° and n = 31
mAngleN = 37° and k = 31
Answer:
m∠K = 37° and n = 31
Step-by-step explanation:
A lot of math is about matching patterns. Here, the two patterns we want to match are different versions of the same Law of Cosines relation:
a² = b² +c² -2bc·cos(A)k² = 31² +53² -2·31·53·cos(37°)ComparisonComparing the two equations, we note these correspondences:
a = kb = 31c = 53A = 37°Comparing these values to the given information, we see that ...
KN = c = 53 . . . . . . . . . . matching values 53NM = a = k . . . . . . . . . . . matching values kKM = b = n = 31 . . . . . . . matching values 31∠K = ∠A = 37° . . . . . . . matching side/angle namesAbby apparently knew that ∠K = 37° and n = 31.
__
Additional comment
Side and angle naming for the Law of Sines and the Law of Cosines are as follows. The vertices of the triangle are labeled with single upper-case letters. The side opposite is labeled with the same lower-case letter, or with the two vertices at either end.
Vertex and angle K are opposite side k, also called side NM in this triangle.
Which expressions are equivalent to 9b?
Choose all answers that apply
A. b+2(b+2b)
B. 3b+b
C. 2(2b)
Answer:
A. b+2(b+2b)
b + 2b + 4b = 7b
B. 3b + b = 4b
C. 2(2b) = 4b
None of them are equal to 9b
Answer:
[tex]\fbox {None}[/tex]
Step-by-step explanation:
A
b + 2(b + 2b)b + 2(b) + 2(2b)b + 2b + 4b7bB
3b + b4bC
2(2b)4bWhat is the simplified form of StartRoot StartFraction 72 x Superscript 16 Baseline Over 50 x Superscript 36 Baseline EndFraction EndRoot? Assume x ≠ 0.
StartFraction 6 Over 5 x Superscript 10 Baseline EndFraction
StartFraction 6 Over 5 x squared EndFraction
Six-fifths x Superscript 10
Six-fifths x squared
The simplification form of the provided expression is 6/5x¹⁰ option first is correct.
What is an expression?It is defined as the combination of constants and variables with mathematical operators.
We have an expression:
[tex]\rm = \sqrt{\dfrac{72x^{16}}{50x^{36}}}[/tex]
[tex]\rm = \sqrt{\dfrac{72}{50}} \sqrt{\dfrac{x^{36}}{x^{16}}}[/tex]
[tex]\rm = \sqrt{\dfrac{36\times2}{25\times2}} \sqrt{\dfrac{x^{36}}{x^{16}}}[/tex]
[tex]\rm ={\dfrac{6x^{8}}{5x^{18}}}[/tex]
[tex]\rm ={\dfrac{6}{5x^{10}}}[/tex]
Thus, the simplification form of the provided expression is 6/5x¹⁰ option first is correct.
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Answer:
6x3
Step-by-step explanation:
Edge 2023
How do I solve for x?
Answer:
3
Step-by-step explanation:
1: Turn the mixed fraction into improper.
2: Multiply 3/5 to each side
3: The you get x = 3
You need to multiply the fraction instead of division because multiplying by the reciprocal is the same as dividing the normal fraction.
[tex]\huge\text{Hey there!}[/tex]
[tex]\mathsf{5 = 1\dfrac{2}{3}x}[/tex]
[tex]\mathsf{1\dfrac{2}{3}x = 5}[/tex]
[tex]\mathsf{\dfrac{1\times3 + 2}{3}x = 5}[/tex]
[tex]\mathsf{\dfrac{3 + 2}{3}x = 5}[/tex]
[tex]\mathsf{\dfrac{5}{3}x = 5}[/tex]
[tex]\large\textbf{MULTIPLY }\rm{\bf \dfrac{3}{5}}\large\textbf{ to BOTH SIDES}[/tex]
[tex]\mathsf{{\dfrac{3}{5}\times\dfrac{5}{3}x= \dfrac{3}{5}\times 5}}[/tex]
[tex]\large\textbf{SIMPLIFY IT!}[/tex]
[tex]\mathsf{x = \dfrac{3}{5}\times5}[/tex]
[tex]\mathsf{x = \dfrac{3}{5}\times\dfrac{5}{1}}[/tex]
[tex]\mathsf{x = \dfrac{3\times5}{5\times1}}[/tex]
[tex]\mathsf{x = \dfrac{15}{5}}[/tex]
[tex]\mathsf{x = 15\div5}[/tex]
[tex]\mathsf{x = 3}[/tex]
[tex]\huge\text{Therefore, your answer should be: \boxed{\mathsf{x = 3}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
Clarinex-D is a medication whose purpose is to reduce the symptoms associated with a variety of allergies. In clinical trials of Clarinex-D, 5% of the patients in the study experienced insomnia as a side effect. As random sample of 20 Clarinex-D users is obtained, and the number of patients who experienced insomnia is recorded. Find and interpret probability that 3 or fewer experienced insomnia as a side effect.
Using the binomial distribution, it is found that there is a 0.9842 = 98.42% probability that 3 or fewer experienced insomnia as a side effect, which means that it is a highly likely event.
What is the binomial distribution formula?The formula is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.The values of the parameters are given as follows:
n = 20, p = 0.05.
The probability that 3 or fewer experienced insomnia as a side effect is given by:
[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]
Hence:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{20,0}.(0.05)^{0}.(0.95)^{20} = 0.3585[/tex]
[tex]P(X = 1) = C_{20,1}.(0.05)^{1}.(0.95)^{19} = 0.3774[/tex]
[tex]P(X = 2) = C_{20,2}.(0.05)^{2}.(0.95)^{18} = 0.1887[/tex]
[tex]P(X = 3) = C_{20,3}.(0.05)^{3}.(0.95)^{17} = 0.0596[/tex]
Then:
[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3585 + 0.3774 + 0.1887 + 0.0596 = 0.9842[/tex]
0.9842 = 98.42% probability that 3 or fewer experienced insomnia as a side effect.
Since this probability is greater than 95%, this is a highly likely event.
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A dragon flew 300 miles from his castle to visit a friend. Flying with the wind, his trip took 2 hours. His return trip against the wind took 3 hours. What was the speed of the wind and the speed of the dragon in still air?
The speed of the wind and the speed of the dragon in still air are respectively; 142.5 mph and 7.5 mph
How to calculate the speed?The dragon flew 300 miles with the wind in two hours.
After flying against the wind for two hours, he had made 270 miles of the return trip.
Let s be the speed in still air
Let w be the speed of the wind
Thus;
(s - w) = effective speed against the wind
and
(s + w) = effective speed with the wind
We know that;
distance = time * effective speed
Thus;
2(s + w) = 300
2(s - w) = 270
This can be simplified to get;
s + w = 150 -----(1)
s - w = 135 -----(2)
Add both equations to get;
2s = 285
s = 285/2
s = 142.5 mph.
Then, plane speed in still air is;
142.5 + w = 150
w = 150 - 142.5
w = 7.5 mph is the speed of the wind
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TIME REMAINING
09:44
On a coordinate plane, a solid straight line has a positive slope and goes through (negative 3, negative 5) and (0, negative 4). Everything to the right of the line is shaded.
Which linear inequality is represented by the graph?
y ≥ One-thirdx – 4
y ≤ One-thirdx – 4
y ≤ One-thirdx + 4
y ≥ One-thirdx + 4
Since everything to the right of the line is shaded, the linear inequality which represents the graph is equal to: A. y ≥ 1/3x - 4.
How to determine the linear inequality?In order to determine the linear inequality which represents the graph, we would find the slope of the given points.
Mathematically, the slope of a straight line can be calculated by using this formula;
[tex]Slope = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}[/tex]
Substituting the given points into the formula, we have;
[tex]Slope = \frac{-4\;-\;(-5)}{0\;-\;(-3)}\\\\Slope = \frac{1}{3}[/tex]
Slope = 1/3.
From the standard equation, we have:
y - y₁ = m(x - x₁)
y - (-5) = 1/3(x - (-3))
y + 5 = 1/3x + 1
y = 1/3x + 1 - 5
y = 1/3x - 4
y ≥ 1/3x - 4.
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Find x and Y pls help
Answer:
Step-by-step explanation:
Comment
The angle supplementary to x and 3x are equal.
Supplementary angles = 180
Solution
x + 3x = 180
4x = 180 Divide by 4
4x/4 = 180/4
x = 45
The angle supplementary to x is 3x
3x = 3*45
3x = 135
This angle is vertically opposite y. Vertically opposite angles are equal. So y = 135
Answer
x = 45
y = 135
For the regions bounded by y = 6cosx and y = one fourth x squared minus 7.
Part A: Find the limits of integration. (10 points)
Part B: Write the expression representing the total area. (10 points)
Part C: Solve for the total area. (10 points)
For the regions bounded by y = 6cosx and y = one-fourth x squared minus 7, the limits of integration, the expression representing the total area, and the total area are mathematically given as
A=27.03squnit
What are the limits of integration, the expression representing the total area, and the total area.?
Generally, the equation for expression is mathematically given as
y = 6cosx
y=(1/4)x^2-7
therefore
[tex]A=\int^{b}_a (f(x)-g(x))dx[/tex]
The limits are
a=0 b=2\pi
Hence
[tex]A=\int ^{2\pi}_0 (6cosx -((1/4)x^2-7))dx\\\\solving\\\\A=\int^{2\pi}_0 (6cosx -((1/4)x^2-7))dx[/tex]
A=27.03squnit
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Which expression is equivalent to...
(08.01 MC)
Find the height of a square pyramid that has a volume of 75 cubic feet and a base length of 5 feet.
A. 5 feet
B. 9 feet
C. 25 feet
D. 45 feet
Answer:
A. 5 feet
Step-by-step explanation:
The volume of a can of Pepsi is 0.33liter. There are 12 cans in 1 carton
What is the volume of 5 cartons of Pepsi?
Answer:
19 liters 800 milliliters
Step-by-step explanation:
0.33 * 12 * 5 = 19.8 liters
Find the formula for the area of the shaded region in the figure.
x² = 4py
ہے
The formula for the area of the shaded region in the figure.
x² = 4py is mathematically given as
[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]
What is the formula for the area of the shaded region in the figure?Parameters
[tex]$x^{2}=4 p y$[/tex]
[tex]$y=h$[/tex]
[tex]\therefore x^{2}=4 p h \Rightarrow x=2 \sqrt{p h} \\[/tex]
Generally, the equation for the Area is mathematically given as
[tex]& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\[/tex]
[tex]&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]
[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]
In conclusion, the equation for the Area is
[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]
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Find the critical point for f(x)=x^2-2x+4 and determine their nature.
Select one:
O a. (3, 1) minimum point
O b. (1, 3) minimum point
O c. (1, 3) maximum point
O d. (3, 1) maximum point
How do you solve this question
[tex]a - 4 = ( \sqrt{a} - 2)( \sqrt{a} + 2)[/tex]
[tex] \frac{ \sqrt{a} - 2}{a - 4} = \frac{ \sqrt{a} - 2}{( \sqrt{a} - 2)( \sqrt{a} + 2) } = \frac{1}{ \sqrt{a} + 2 } [/tex]
Round 7,485 to the nearest hundred.
Answer:
7,500
Step-by-step explanation:
When you round you automatically round up unless told otherwise
so find the hundredth, which is 485 and you round that to 500
then put the 7 back → 7,500