In the absence of air friction, an object dropped near the surface of the Earth experiences a constant acceleration
of about 9.8 m/s2
(A) speed of the object increases 9.8 m/s during each second
(B) speed of the object as it falls is 9.8 m/s
. This means that the
(C) object falls 9.8 meters during each second
(D) object falls 9.8 meters during the first second only
(E) rate of change of the displacement with respect to time for the object
In the absence of air friction, an object dropped near the surface of the Earth experiences a constant acceleration of about 9.8 m/s2, so the speed of the object increases 9.8 m/s during each second.
The speed of the object increases 9.8 m/s during each second the acceleration means the change in velocity per second.
Gravity can be explained as a force such that controls the movement of the planets such as Earth around the Sun, hold stars grouped in galaxies together, and galaxies grouped in clusters.
The gravity which is generally near the Earth's surface makes it possible for all physical objects to possess weight and experience a free fall.
Generally, the acceleration due to gravity for an object experiencing a free fall near the Earth's surface is 9.8 m/s2.
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Stretched 1 cm beyond its natural length, a rubber band exerts a restoring force of magnitude 2 newtons. Assuming that Hooke's Law applies, answer the following questions: (a) How far (in units of meters) will a force of 3 newtons stretch the rubber band? Distance stretched 8 m (b) How much work does it take to stretch the rubber band this far?
A force of 3N will stretch the rubber a distance of 0.015 m. It takes 0.045 J of work to stretch the rubber band.
What does Hooke's law mean?According to Hooke's law, the amount of force used to stretch an elastic item is proportional to that force. The object won't rebound if it is stretched too far, though. Only when an elastic object is not overextended does Hooke's Law hold true.
What are the instances of Hooke's laws in the actual world?The nature of a balloon is elastic. It expands when air molecules are blasted through it. Similar to that, it gets smaller when it is expelled. It operates according to Hooke's law because the balloon's expansion and compression depend on the force with which air is pumped into it.
From Hooke's law, as long as the elastic limit is not exceeded the extension is directly proportional to the force applied.
(a)
F = Ke
F = force
K = force constant
e = extension
So;
2 N = K(1 × 10^-2) m
K = 2 N /(1 × 10^-2) m
K = 200 N/m
Hence;
3N = 200 N/m × a
Where a is the extension in meters
a = 3N/200 N/m
a = 0.015 m
(b)
Work (w) = Force (f)×distance (a)
Work (w) = 3 N×0.015
Work (w) = 0.045 J
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true/false. derive an equation to show the relationship between the gravitational field on a planet and the acceleration when the mass or the distance is varied depending on your chosen experiment.
Equation to show the relationship between gravitational field on a planet and the acceleration when the mass or distance is varied : a = g = G * (M/r^2)
What is gravitational field?In physics, gravitational field is a model that is used to explain influences that a massive body extends into the space around itself, producing force on another massive body.
The gravitational field strength on a planet;
F = G * (Mm / r^2)
F is gravitational force, G is the gravitational constant (approximately 6.67 x 10^-11 N*(m/kg)^2), M is mass of the planet, m is mass of the object being affected by the gravitational force, and r is distance between the centers of two masses.
F/m = G * (M/r^2)
As, a = g = G * (M/r^2)
This equation shows the relationship between gravitational field on a planet and the acceleration experienced by an object due to that field. It shows that acceleration is directly proportional to mass of the planet and inversely proportional to the square of distance between the centers of the two masses.
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two stationary point charges of unknown magnitude and sign are isolated from all other charges. if the electric field strength is zero at the midpoint of the line joining them, which of the following can be concluded about the charges?
Two stationary point charges of unknown magnitude and sign are isolated from other charges. If electric field strength is zero at midpoint of line joining them, following can be concluded about charges : They are equal in magnitude but opposite in sign.
What is meant by electric field?The electric field is a vector field that describes the force experienced by a test charge placed in the field. The direction of the electric field is given by the direction of the force experienced by the test charge and its magnitude is given by the force experienced per unit charge.
Electric field at the point due to point charge ;
E = k * (q/r^2) * r_unit
where k is Coulomb's constant, q is the charge, r is the distance from the point charge, and r_unit is the unit vector pointing from the point charge to the point where the electric field is being calculated.
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Note: The question given on the portal is incomplete. Here is the complete question.
Question: Two stationary point charges of unknown magnitude and sign are isolated from all other charges. if the electric field strength is zero at the midpoint of the line joining them, which of the following can be concluded about the charges?
They are equal in magnitude but opposite in sign.
They are equal in magnitude and sign.
They are not equal in magnitude and opposite in sign
They are not equal in magnitude but same sign.
How do you use Cavalieri's principle to find volume?
According to Cavalieri's principle, if two solids are sandwiched between two parallel planes and any plane perpendicular to these planes meets them with cross-sections of equal area, the solids' volumes are also equal.
When used on increasingly intricate shapes, Cavalieri's approach demonstrates its effectiveness (or when the rectangles are allowed to become infinitely thin.) Two solids (planar figures) must have equal volumes and the same heights and areas (lengths) on every level according to a brief formulation (areas). The idea represented an early step toward what is now called the Integral Calculus.
Let's identify a relationship between the volumes of a cylinder, a cone, and a sphere as an amazing use of Cavalieri's principle.
Assume that a cylinder's height is equal to the radius of its base (r) and that the cylinder has an inscribed cone with the same base and height as the cone.
The area of the cone's cross-section at level y is equal to y², calculated from the bottom up. The area of the remaining ring (at level y) is equal to (r² - y²) because the cross-section of the cylinder, regardless of its height, equals r². This is the exact area of the cross-section of the hemisphere of radius r at level y according to the Pythagorean theorem. According to Cavalieri's principle, the cylinder's volume less the cone's volume equals the hemisphere's volume.
A cone's volume is one-third of a cylinder's volume, which is defined as Base × Height. The volume of the hemisphere is, therefore 2/3 that of the cylinder, and the volume of the entire sphere is 4/3 that of the cylinder. The latter is r³, hence the sphere's volume is 4/3 r³.
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a solid object of mass m is suspended vertically from a spring balance. the spring balance reads w when the object is in air. when the object is submerged in water while still attached to the balance, the reading on the balance is
The Archimedes principle states that when an object is submerged in a fluid, it seems to lose weight that is equal to the weight of the fluid that was displaced.
What transpires when something is immersed in water? The Archimedes principle states that when an object is submerged in a fluid, it seems to lose weight that is equal to the weight of the fluid that was displaced.The apparent weight loss is brought about by the buoyant force, which acts in an upward direction counter to the object's weight.The buoyant force is the name for the upward push that fluid-immersed objects experience.The buoyant force.A submerged item experiences fluid pressure on all sides.The upward force on the bottom surface (F2) is larger than the downward push on the top surface, though, because pressure rises with depth (P) (F1).As a result, there is constantly an upward pull from buoyancy. 'To learn more about Archimedes principle refer
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use the impulse-momentum theorem to find how long a stone falling straight down takes to increase its speed from 4.8 m/s to 12.0 m/s .
The impulse-momentum theorem states that the change in momentum of an object is equal to the impulse applied to it. The a stone falling vertically to pick up speed, going from 4.8 m/s to 12.0 m/s.
How can we calculate its speed using the impulse-momentum theorem?Δp = F * Δt
where Δp is the change in momentum, F is the net force acting on the stone, and Δt is the time interval.
Since the stone is falling vertically and only gravity is acting on it, the net force is equal to its weight, which is given by the equation:
F = m * g
where m is the mass of the stone and g is the acceleration due to gravity (9.8 m/s^2).
Now we can find the change in momentum by subtracting the initial momentum from the final momentum:
Δp = pf - pi
= (m * vf) - (m * vi)
= m * (vf - vi)
where vi and vf are the initial and final speeds (4.8 m/s and 12.0 m/s), and m is the mass of the stone.
Substituting the expressions for F and Δp into the impulse-momentum theorem, we get:
m * (vf - vi) = F * Δt
m * (12.0 - 4.8) = m * g * Δt
7.2 = 9.8 * Δt
Finally, we can solve for Δt by dividing both sides of the equation by 9.8:
Δt = 7.2 / 9.8
Δt = 0.735 seconds
So it takes the stone 0.735 seconds to increase its speed from 4.8 m/s to 12.0 m/s.
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The impulse-momentum theorem states that the change in momentum of an object is equal to the impulse applied to it. It takes the stone 0.735 seconds to increase up speed, going from [tex]4.8 m/s to 12.0 m/s.[/tex]
How can we calculate its speed using the impulse-momentum theorem?Δp = F * Δt
where Δp is the change in momentum, F is the net force acting on the stone, and Δt is the time interval.
Since the stone is falling vertically and only gravity is acting on it, the net force is equal to its weight, which is given by the equation:
F = m * g
where m is the mass of the stone and g is the acceleration due to gravity (9.8 m/s^2).
Now we can find the change in momentum by subtracting the initial momentum from the final momentum:
Δp = pf - pi
= (m * vf) - (m * vi)
= m * (vf - vi)
where vi and vf are the initial and final speeds (4.8 m/s and 12.0 m/s), and m is the mass of the stone.
Substituting the expressions for F and Δp into the impulse-momentum theorem, we get:
m * (vf - vi) = F * Δt
m * (12.0 - 4.8) = m * g * Δt
7.2 = 9.8 * Δt
Finally, we can solve for Δt by dividing both sides of the equation by 9.8:
Δt = 7.2 / 9.8
Δt = 0.735 seconds
So it takes the stone 0.735 seconds to increase its speed from 4.8 m/s to 12.0 m/s.
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Suppose that a ball is thrown vertically upward from earth with velocity v, and returns to its original height in a time t. If the value of g were reduced to g/6 (as on the moon), then t would:
If the value of g were reduced to g/6, then the equation for the time it takes for the ball to return to its original height would become t = 2v/(g/6), or t = 12v/g. Since the original equation is t = 2v/g, the new equation is 6 times greater, so the time t would be 6 times greater than before.
What would be the velocity of the ball when it returns to its original height? If the value of g were reduced to g/6, the ball would reach its original height with a velocity of 6v (where v is the initial velocity of the ball when it was thrown vertically up). The time t would also be reduced to t/6, since the acceleration of the ball is reduced to g/6. This means that the ball would take less time to reach its original height when compared to the time taken when the acceleration is equal to g. In conclusion, if the value of g were reduced to g/6, the velocity of the ball when it returns to its original height would be 6v and the time taken for the ball to reach its original height would be t/6.To learn more about velocity refer to:
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gravitational, magnetic, and electric forces can all be explained using fields. which of the following is a reason that we explain these forces using fields?
Fields provide a consistent framework for understanding and describing different types of forces, such as strength, direction, propagation, attenuation, and mathematically describing the behavior of forces.
What is gravitational force?Gravitational force is the force of attraction that exists between two objects that have mass. It is the weakest of the four fundamental forces in nature, but it is the most influential force when it comes to the large-scale structure of the universe. It is responsible for keeping planets and stars in orbit around one another, and also for the formation of galaxies and other large structures.
We explain these forces using fields because fields provide a consistent framework for understanding and describing different types of forces. Fields provide a way to represent the strength and direction of a force at any given point in space. They also provide a way to represent the interactions between different types of forces, such as how magnetic and electric fields interact to create electromagnetic forces. Furthermore, fields provide a way to represent how forces can propagate and attenuate over distances, allowing us to understand how things interact from afar. Finally, fields provide a way to mathematically describe the behavior of forces, allowing us to make predictions about how things interact in different situations.
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The complete question is: What is a reason to explain the gravitational, magnetic, and electric forces using the fields?
. An internal combustion engine has an efficiency of 20.0%. This engine is
used to deliver 6.00 × 104 J of work to the rest of the drive train. What is
total energy input of the engine?
Estimate the mass of air inside the passenger area of a CATA bus. A)100 kg B)10 kg C)1000 kg D)0.1 kg
The Correct option is D which is 0.1kg .
It can be challenging to calculate the air mass in a CATA bus's passenger compartment. It will most likely just weigh a few tenths of a kilogramme or perhaps less, which is exceedingly little.
This is because, in relation to the size of the bus itself, the volume of air inside the passenger compartment of a bus is rather low. Additionally, even a small volume of air will have a comparatively modest mass since the density of air at normal atmospheric pressure is extremely low.
The frequent interchange of air through open doors and windows would be another element that might contribute to the small mass of air inside a bus.This would mean that the air inside the bus is not stagnant and is constantly being replaced by the air outside which would lead to a decrease in mass. The answer would be D)0.1 kg
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A 2,400-kilogram car is traveling at a speed of 20. meters per second. Compared to the magnitude of the force required to stop the car in 12 seconds, the magnitude of the force required to stop the car in 6.0 seconds is (1) half as great(2) twice as great (3) the same (4) four times as great
Compared to the magnitude of force required to stop the car in 12 seconds, magnitude of the force required to stop the car in 6.0 seconds is : (3) the same.
What is meant by force?In physics, force is an influence that changes the motion of an object.
Force is : F = m * a, where m is mass of the object and a is acceleration.
Given, distance traveled is zero (the car stops), the initial velocity is 20 m/s and time is 12 seconds.
As, d = vt + (1/2)at^2
So, a = 2d/t^2 - v^2/d
a = 2*0/(12^2) - (20^2)/0 = 0 - 400/0 = undefined
a = 2*0/(6^2) - (20^2)/0 = 0 - 400/0 = undefined
As acceleration is undefined in both case, we say that the force required to stop the car in 6.0 seconds is same as force required to stop the car in 12 seconds.
So, answer is (3) the same.
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For each of the cases described below, sketch and label the total acceleration vector, the radial acceleration vector, and the tangential acceleration vector. ($a$) A car is accelerating from 55 km/h to 70 km/h as it rounds a curve of constant radius. ($b$) A car is going a constant as it rounds a curve of constant radius. ($c$) A car slows down while rounding a curve of constant radius.
These two vectors can be added to provide the net acceleration, same as in a Cartesian coordinate system.This is dispensing with the fixed X and y axis that you are used to to demonstrate this coordinate system.
How the car is accelerating as it rounds a curve?
Total acceleration vector: pointing towards the center of the curve, as the car is accelerating towards the center.
Radial acceleration vector: also pointing towards the center of the curve, as the car is accelerating towards the center.
Tangential acceleration vector: pointing parallel to the path of the car, as the car is changing direction while maintaining a constant speed.
($b$) A car is going a constant as it rounds a curve of constant radius:
Total acceleration vector: pointing towards the center of the curve, as the car is changing direction while maintaining a constant speed.
Radial acceleration vector: also pointing towards the center of the curve, as the car is changing direction while maintaining a constant speed.
Tangential acceleration vector: zero, as the car is maintaining a constant speed.
($c$) A car slows down while rounding a curve of constant radius:
Total acceleration vector: pointing towards the center of the curve, as the car is slowing down towards the center.
Radial acceleration vector: also pointing towards the center of the curve, as the car is slowing down towards the center.
Tangential acceleration vector: pointing opposite to the path of the car, as the car is slowing down while changing direction.
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A person standing at the edge of a cliff throws one ball straight up and another ball straight down, each at the same initial speed. Neglecting air resistance, which ball hits the ground below the cliff with the greater speed?
When a person standing at the edge of a cliff throws one ball straight up and another ball straight down, each at the same initial speed, neglecting air resistance, the ball that hits the ground below the cliff with the greater speed is the ball that was thrown straight up.
What is the acceleration due to gravity?The acceleration due to gravity is the acceleration that is produced in an object due to the gravitational force of the earth acting on the object.
The velocity of an object depends on the acceleration due to gravity and the height above the ground of an object as given below:
Velocity = √2gh
where;
g is the acceleration due to gravity
h is the height above the ground
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Consider the periodic waveform of Fig. 1 r(t) T DT DT 2 Figure 1: Waveform for Problem 1 Derive expressions for the DC component of this waveform, and for the magnitudes of the Fourier series harmonics. Determine the value of D which sets the magnitude of the Fourier series 3d harmonic to zero. Finally, derive an expression for the RMS value of this waveform
A wave-shaped signal is represented graphically by a waveform. Depending on the kind of wave generating input, it might be either square or sinusoidal. The characteristics that determine the wave's size and shape determine the waveform.
The required details for waveform in given paragraph
The waveform in Figure 1 is a square wave with a period T. The DC component of this waveform is the average value of the waveform over one period. It can be found by integrating the waveform over one period and dividing by the period T:
DC component = from 0 to T
The magnitude of the Fourier series harmonics can be found by using the formula for the Fourier series coefficients:
Ak = (from 0 to T)
Bk = (from 0 to T)
where k is the harmonic number, f is the fundamental frequency (1/T), and A and B are the Fourier series coefficients.
For a square wave, the odd harmonics are non-zero and the even harmonics are zero. For the 3rd harmonic, the magnitude is:
Ak = (from 0 to T)
= (from 0 to T)
= (from 0 to T)
To set the magnitude of the Fourier series 3rd harmonic to zero,
D = 0
Finally, the RMS value of the waveform can be found by using the formula:
RMS = (from 0 to T)
= (from 0 to T)
= It's important to notice that the solution and expressions given here are only valid for square waveform with a period T and amplitude D.
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4. On Earth the average atmospheric pressure at the surface is 1013254 Pa. If we assume that the radius of Earth is 6.4 x 106m and the acceleration of gravity is 9.8 m/s2, what is the mass of Earth's atmosphere? Hint: You will need to use the equations for force, pressure, and the surface area of a sphere, but you will need to analyze the units to confirm how these get combined.) Use the following values to solve this problem. 16 pts 1 atm = PEarth=101325 Pa; REarth-6,4x10ºm; g = 9.8 m/s? Ending units:
At the surface of Earth, the ambient atmospheric pressure is 1013254 Pa. The weight of the atmosphere on Earth is 5.322 * 1016 kg.
Describe pressure.The magnitude of force applied to a certain region is referred to as pressure. So either a strong force or a strong force applied over a short area can cause a lot of pressure (or do both).
Why does air pressure exist?The atoms and molecules that comprise the many layers of the atmosphere are continually moving in arbitrary directions. Despite their modest size, when they hit a surface, they apply pressure that humans perceive as a force.
atmospheric pressure = 1013254 Pa
radius of Earth = 6.4 * 10⁶ m
gravity = 9.8 m/s²
surface area of a sphere = 4π radius²
surface area of earth = 4 * 3.14 * ( 6.4 *10⁶ )²
= 5.14719 * 10¹⁴ m²
mass of the atmosphere = ( 1013254 pa * 5.14719 * 10¹⁴ m²) / 9.8
= 5322 * 10 ¹⁶ gm
= 5.322 * 10¹⁶ kg
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a rocket takes off from earth's surface, accelerating straight up at 65.2 m/s2. calculate the normal force (in n) acting on an astronaut of mass 88.4 kg, including her space suit. (assume the rocket's initial motion parallel to the y-direction. indicate the direction with the sign of your answer.)
The normal force (in n) acting on an astronaut of mass 88.4 kg, including her space suit is M=6612.32N direction upwards.
One kind of ground response force is the normal force. The entire ground response force can be broken down into two parts: a normal force perpendicular to the ground and a frictional force parallel to the ground if the person stands on a slope without sinking into the ground or sliding downhill. Another typical scenario is when an object strikes a surface at a certain speed and the surface is able to survive the impact. In this case, the normal force causes a quick deceleration, which depends on the flexibility of the surface and the object.
Given, a=65m/[tex]s^{2}[/tex]
mass=88.4Kg
from the condition ,
let M be the normal force
M=ma
M=mg+ma
M=m(g+a)
M=88.4(9.8m/[tex]s^{2}[/tex]+65m/[tex]s^{2}[/tex])
M=6612.32N direction upwards
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At a resting pulse rate of 71 beats per minute, the human heart typically pumps about 69 mL of blood per beat. Blood has a
density of 1060 kg/m³. Circulating all of the blood in the body through the heart takes about 1 min for a person at rest.
Approximately how much blood is in the body?
volume of blood in body:
On average, what mass of blood does the heart pump with each heart beat?
mass per heart beat:
m³
3
E
kg
The number of pulse beats per minute is referred to as pulse rate. A resting person's heartbeat typically ranges from 72 to 80 beats per minute.
What volume of blood does the heart pump with each heartbeat?For adults, it pumps roughly 55-80 ml (1/3 cup) and for kids, 25-85 ml (1/3 cup) of blood per beat. A typical adult heart pumps between 6,000 and 7,500 liters (1,500 and 2,000 gallons) of blood every day. About five quarts of blood circulate continuously throughout the normal adult's body.The number of pulse beats per minute is referred to as pulse rate. A resting person's heartbeat typically ranges from 72 to 80 beats per minute.For adults, it pumps roughly 55-80 ml (1/3 cup) and for kids, 25-85 ml (1/3 cup) of blood per beat. A typical adult heart pumps between 6,000 and 7,500 liters (1,500 and 2,000 gallons) of blood every day.To learn more about pulse beats refer to:
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It pumps roughly 25-85 ml of blood every beat for youngsters and 55-80 ml (1/3 cup) per beat for adults.
What mass of blood does the heart pump with each heart beat?A typical adult heart pumps between 6,000 and 7,500 liters (1,500 and 2,000 gallons) of blood each day. About five quarts of blood are present in the average adult body, and this blood is constantly circulating.Blood enters the arteries under high pressure when the ventricles constrict. The pulse is a throbbing sensation caused by the arteries' contraction and relaxation with each heartbeat. The average heartbeat is between 60 and 100 beats per minute.the volume of blood the aorta pumps out of the heart each minute. Adult males typically produce 5.6 L/min of cardiac output at rest, while women produce 10–20% less. During vigorous exercise, a person's heart rate can go up to 25 L/min.To learn more about heart beat refer to :
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scallops use muscles to close their shells. opening the shell is another story--muscles can only pull, they can't push. instead of muscles, the shell is opened by a spring, a pad of a very elastic biological material called abductin. when the shell closes, the pad compresses; a restoring force then pushes the shell back open. the energy to open the shell comes from the elastic energy that was stored when the shell was closed. (figure 1) shows smoothed data for the restoring force of an abductin pad versus the compression. when the shell closes, the pad compresses by 0.15 mmmm.
Solve by multiplying one half by the drug's 10.5 newtons per millimetre and by its square root, 0.15 millimetre.
What is opening the shell?Another issue is that muscles can only pull, not push, while opening the shell. The shell is opened by a spring, a pad made of an extremely elastic organic substance termed abduction, rather than muscles. The pad contracts as the shell closes, and a restoring force pushes the shell open again.Yes, the had compresses by 0.15 millimetre at 12.5 newtons per millimetre. Mhm. Yeah. Therefore, this one-half informed by the spring constant modified by the squared of the spaceman is the formula for plastic potential energy. After that, we solve by multiplying one half by the drug's 10.5 newtons per millimetre and by its square root, 0.15 millimetre.
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Yanni is sitting in the stands watching a football game. The quarterback runs forward toward the end zone and throws a pass straight downfield to a player for a touchdown. The quarterback ran at a speed of 8 m/s and threw the ball with a speed of 15 m/s.
Which statement is supported by this scenario?
The quarterback in this scenario ran at a speed of 8 m/s and threw the ball with a speed of 15 m/s.
Which statement support this scenario?This scenario supports the statement that the quarterback has a greater speed when throwing the ball than when running.This is likely because throwing a ball requires a different set of muscle movements and techniques than running, and the quarterback was able to generate more force when throwing the ball than when running.Additionally, throwing a ball requires different timing and coordination than running, which could also contribute to the difference in speed.It's also possible that the quarterback was able to use his forward momentum while running to add additional speed to the throw.Overall, the scenario supports the statement that the quarterback has a greater speed when throwing the ball than when running, as the 15m/s of the ball throw is greater than 8m/s of running.To learn more about quarterback run refer:
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A rigid bar has a moment of inertia of 0.8 kg m^2 and an initial angular velocity of 0 rad/s. A constant torque of 4.55 n m is applied for t = .92s, compute the final angular velocity w and the angular impulse that was applied to the rigid bar.
The final angular velocity of the rigid bar is 5.2325 rad/s.
The angular impulse that was applied to the rigid bar is 4.186 N-m-s.
What is angular velocity?As a vector number that indicates an object's angular speed or rotational speed as well as the axis around which it is spinning, angular velocity is defined as the rate of change of angular displacement.
The final angular velocity of the rigid bar = (4.55 N-m × 0.92 s)/(0.8 kg-m²)
= 5.2325 rad/s.
The angular impulse that was applied to the rigid bar = (4.55 N-m × 0.92 s)
= 4.186 N-m-s.
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Imagine, if you can, that you are traveling toward a black hole. When is time dilation likely to occur?
when you approach the event horizon
when you cross the wormhole
when you land in the singularity
when you pass the quasar
Imagine, if you are traveling toward a black hole. The time that time dilation is likely to occur is option A: when you approach the event horizon.
What is the black hole about?The event horizon is the boundary around a black hole beyond which nothing, including light, can escape. As an object approaches the event horizon, the gravitational pull becomes stronger. This causes time to slow down for the object, a phenomenon known as time dilation.
The effect becomes more pronounced as the object gets closer to the singularity, the central point of the black hole where the gravitational pull becomes infinitely strong.
Crossing a wormhole, which is a hypothetical passage through space-time connecting distant points, would also experience time dilation, but it is different than the one that occurs near a black hole.
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when the car is in the position shown, what are the directions of the centripetal force acting on the car and the velocity of the car?
The directions of the centripetal force acting on the car and the velocity of the car is east. Thus, option d is correct.
What is velocity?Velocity is a measure of the rate and direction of an object's change in position. It is a vector quantity, having both magnitude and direction. Velocity is commonly described in terms of speed, distance traveled, and direction of travel. Velocity can be calculated by dividing the displacement (change in position) by the time taken for the displacement to take place. The SI unit for velocity is meters per second (m/s).
This force is generated by the car's acceleration inwards and is responsible for the car's circular motion. The velocity of the car is the speed of the car in the direction of the circle's circumference. The magnitude of the velocity is determined by the radius of the circle and the angular velocity of the car. The magnitude of the centripetal force is equal to the weight of the car times the square of the velocity divided by the radius of the circle.
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Complete question:
A car moves with a constant speed in a clockwise direction around a circular path of radius r, as represented in the diagram When the car is in the position shown, its acceleration is directed toward the?
a. north
b. south
c. west
d. east
PLEASE HELP AND HURRY! VERY IMPORTANT TEST
1. What physical properties can cause an object to resonate?
-mass, color, and density
-shape, temperature, energy
-shape, composition, and length
-color, density, and composition
2. Which statement about resonance is correct?
-Resonance causes the amplitude of vibrations to decrease.
-Resonance causes the amplitude of vibrations to increase.
-Resonance does not affect the amplitude of vibrations.
-Resonance causes frequency to incease
3.How can you make the natural frequency of a string increase?
-decrease the tension of the string
-cut the string
-tighten the string
-loosen the string
4. A student wants to make the natural frequency of a tube increase. How can the student accomplish this?
-Decrease the length of the tube
-Change the composition of the tube
-Make holes in the tube
-Increase the length of the tube
5.Which factor determines the natural frequency of an object?
-color
-elasticity
-length
-pressure
Question:1. What physical properties can cause an object to resonate?-mass, color, and density-shape, temperature, energy-shape, composition, and length-color, density, and composition
2. Which statement about resonance is correct?-Resonance causes the amplitude of vibrations to decrease.-Resonance causes the amplitude of vibrations to increase.-Resonance does not affect the amplitude of vibrations.-Resonance causes frequency to incease3.How can you make the natural frequency of a string increase?-decrease the tension of the string-cut the string-tighten the string-loosen the string4. A student wants to make the natural frequency of a tube increase. How can the student accomplish this?-Decrease the length of the tube-Change the composition of the tube-Make holes in the tube-Increase the length of the tube5.Which factor determines the natural frequency of an object?-color-elasticity-length-pressure
Explanation:
answer is 1,2,3,4,5,
isolated spheres 1 and 2 both carry positive charge qq, but sphere 2 has more mass than sphere 1. the objects are released from rest when they are a distance dd apart and accelerate away from each other. let uu be the electric potential energy of the system of two spheres, and k1k1 and k2k2 be the kinetic energies of sphere 1 and sphere 2, respectively. which of the following pairs of energy bar charts could represent the distribution of the energies in the system when the spheres are first released and the distribution of energies when the spheres are a large distance away from each other?
The power required to move a charge in opposition to an electric field is known as electric potential energy.
What is potential energy in electric systems?
The power required to move a charge in opposition to an electric field is known as electric potential energy. A charge must be moved through a greater electric field with more energy, but it also must be moved through a weaker electric field with more energy.
Potential energy will be associated with each charged sphere's individual charge.
K! = 8πε 0 1
rsq 2
The electric field of the other sphere's potential energy contained in one object is K 2 = 4 0.
1R q 2
Consequently, the P.E. strored in the system of object at U=[2K 1 + K 2 ]= 4 0.
q 2 [ R 1 + 1 ]
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Melissa is working on the roof of her house. She drops a hammer and. Nail. Why do both hammer and nail hit the ground at the same time
Both hammer and nail hit the ground at the same time because acceleration due to gravity is same for everything on Earth surface.
What is acceleration due to gravity?The acceleration an object experiences as a result of gravitational force is known as acceleration due to gravity.
M/s² is its SI unit. Its vector nature—which includes both magnitude and direction—makes it a quantity. The unit g stands for gravitational acceleration. At sea level, the standard value of g on earth's surface is 9.8 m/s².
As acceleration due to gravity is same for everything on Earth surface, both hammer and nail hit the ground at the same time.
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Answer:
(Question) Melissa is working on the roof of her house. She drops a hammer and a nail. Why do both objects hit the ground at the same time?
(Answer) Earth’s gravity causes both objects to fall at the same rate.
(Question) Which of the following statements about gravitational mass is true?
(Answer) Gravitational acceleration is irrespective of mass.
(Question) Two objects fall from an apartment window sill at the same time. Object 1 lands on the sidewalk in 3.6 seconds. Object 2 lands on the sidewalk in 3.3 seconds. What can be concluded about the objects?
(Answer) Object 1 has more surface area than Object 2.
(Question) A company uses drones to fly food to people in regions that have experienced natural disasters. The food is packed in boxes that are attached to parachutes. How can the company change the design of its parachute to reduce the number of boxes that are damaged when they hit the ground?
(Answer) The company can design a parachute with more surface area.
(Question) Students want to design an experiment to study gravity. They decide they will drop four objects with the same mass from the top of their school’s bleachers. They will time how long each object takes to reach the ground. How can they improve confidence in the experiment’s results?
(Answer) Drop each object 10 times and use the average of each object’s fall times.
Explanation:
i just finished the quick check
Select the techniques that can be used to speed up refrigerant recovery (you may select more than one)
a. Cool the recovery cylinder
b. Recovery from both sides of the system at once
c. Use large-diameter hoses
d. Heat the refrigerant system
Amongst the refrigerant techniques given in the options, all of them are correct and can be used to speed up recovery.
A brief explanation of all the refrigerant techniques to increase the speed of recovery:
a. Cooling the recovery cylinder: This technique involves placing the recovery cylinder in a cool environment, such as a cooler or refrigerator, before beginning the recovery process. This can help to speed up the process by reducing the temperature of the refrigerant inside the cylinder, making it more dense and easier to pump out.
b. Recovery from both sides of the system at once: This technique involves connecting the recovery equipment to both the high and low side of the refrigerant system at the same time. This allows for faster recovery by allowing the refrigerant to flow in both directions simultaneously.
c. Use large-diameter hoses: Using larger diameter hoses can also help to speed up the recovery process. This is because larger hoses provide less resistance to the flow of refrigerant, allowing it to be pumped out more quickly.
d. Heating the refrigerant system: This technique involves heating the refrigerant system before beginning the recovery process. This can help to speed up the process by increasing the pressure of the refrigerant, making it easier to pump out.
All these techniques can help to speed up the refrigerant recovery process by making it easier to pump out the refrigerant, and by allowing for faster flow of the refrigerant. However, safety measures should be taken before applying these techniques, and precautions should be taken to avoid over-heating or over-cooling the system, as this can cause damage to the equipment.
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When a 1.00-kg mass is suspended from a spring, the spring stretches by .050 m. What is the spring constant and what is the period if it oscillates in simple harmonic motion?
The period if it oscillates on simple harmonic motion is determined by the value to be 0.1256 seconds.
What does harmonic motion entail?Harmonic motion is the motion that an oscillating mass undergoes when the restoring force is proportionate to the displacement but acting in the opposite direction. A sine wave with a constant magnitude and frequency can be used to illustrate harmonic motion because it is periodic. A weight bouncing on a spring is an illustration of this.
Why do harmonics exist?Harmonics are the outcome of nonlinear loads converting AC voltage level to DC. Because of nonlinear electrically controlled components like computer power supply, energy-efficient lighting, and variable-frequency drives (VFDs), harmonics enter the electrical system.
According to the given information:The force constant of the spring,
So,
K = f/x
= (1 x 10)/0.2
= 50 N/m
Now, if the mass of 1 kg is suspended by the spring, then the period of oscillation,
T = 2π√(m/k)
T = 2π√(1/50)
T = 2π * 0.02
T = 0.1256s
the value to be 0.1256 seconds.
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What is the ideal speed to take a 75 m radius curve banked at a 10.0° angle?
m/s
The ideal speed to take a 75 m radius curve banked at a 10.0° angle is 21.82 m/s.
The formula for the maximum vehicle velocity on banked roads can be used to determine the banking angle. The equation for the angle of banking, t a n = v 2/ r g, is obtained by squaring the equation on both sides and rearrangement.
The curved path's banking angle is given as
tan θ = v² / rg
Here, v is the linear speed, r is the curved path's radius, is the bank angle, and g is the acceleration brought on by gravity.
θ = 10.0°, r = 75 m, and g = 9.8 m/s2 are our values.
By replacing these numbers in the formula above, we obtain
tan 10 = v2 / 75m × 9.8m/m/s²
v² = 476.54
v = √476.54 = 21.82 m/s
Thus, 21.82 m/s is the optimal speed.
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a stone is dropped from the roof of a house. a person standing on the ground watches and times te fall of the stone with a stopwatch. if the stone takes 1.1 seconds to fall, how tall is the house using feet as your measurement
The height of the house in feet would be 19.45.
The distance in metres can be converted to feet by multiplying by 3.281 (1 m = 3.281 ft).
So the height of the house in feet =distance (in meters) × 3.281
Height of the house=1/2× 9.8×1.1²
=5.929 m
Height of the house in feet= 5.929×3.281= 19.45 feet
Please note that the result of this calculation is an approximation, and real-world factors such as air resistance may affect the actual time it takes for the stone to fall.
Acceleration due to gravity is 9.8 m/s² and time for the stone to fall is 1.1 seconds, can be used to calculate the height of the house. Calculating the distance fallen in metres, then multiplying it by 3.281 to get the distance in feet. The exact amount of time it takes for the stone to fall may vary due to external factors like air resistance.
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